{
  "schema_version":"ocme-learning-path-registry-v0.1",
  "paths":[
    {
      "schema_version":"ocme-learning-path-v0.1",
      "id":"path-geometry-foundations",
      "title_zh":"幾何基礎到畢達哥拉斯定理",
      "audience":["general_learner","upper_secondary"],
      "goal_zh":"由點、線、面的基礎語言，經三角形、角、長度與直角三角形進入畢達哥拉斯定理。",
      "nodes":[
        {"object_id":"mko-point-line-plane","position":1,"requirement":"required","rationale_zh":"先區分幾何位置、延伸對象與圖示。"},
        {"object_id":"mko-triangle","position":2,"requirement":"required","rationale_zh":"由三個相異不共線點建立三角形、頂點與邊。"},
        {"object_id":"mko-angle","position":2,"requirement":"required","rationale_zh":"建立共同端點兩射線與角量的語言。"},
        {"object_id":"mko-euclidean-length","position":2,"requirement":"required","rationale_zh":"平行建立邊長與距離的意義。"},
        {"object_id":"mko-right-triangle","position":3,"requirement":"required","rationale_zh":"再以直角與邊確定定理適用的幾何對象。"},
        {"object_id":"mko-euclid-pythagorean-theorem","position":4,"requirement":"required","rationale_zh":"最後理解平方關係與證明。"}
      ],
      "edges":[
        {"from":"mko-point-line-plane","to":"mko-triangle","relation":"required_before"},
        {"from":"mko-point-line-plane","to":"mko-angle","relation":"required_before"},
        {"from":"mko-point-line-plane","to":"mko-euclidean-length","relation":"recommended_before"},
        {"from":"mko-angle","to":"mko-right-triangle","relation":"required_before"},
        {"from":"mko-triangle","to":"mko-right-triangle","relation":"required_before"},
        {"from":"mko-euclidean-length","to":"mko-right-triangle","relation":"recommended_before"},
        {"from":"mko-right-triangle","to":"mko-euclid-pythagorean-theorem","relation":"required_before"}
      ],
      "review":{"status":"candidate","reviewer":"Codex local AI","version":2}
    },
    {
      "schema_version":"ocme-learning-path-v0.1",
      "id":"path-function-to-limits",
      "title_zh":"集合、函數到趨近關係",
      "audience":["upper_secondary","undergraduate"],
      "goal_zh":"建立集合隸屬、總函數與趨近語義的基礎鏈。",
      "nodes":[
        {"object_id":"mko-set-membership","position":1,"requirement":"required","rationale_zh":"建立元素與集合之間的基本關係。"},
        {"object_id":"mko-function-mapping","position":2,"requirement":"required","rationale_zh":"理解定義域到陪域的總函數。"},
        {"object_id":"mko-tends-to-relation","position":3,"requirement":"required","rationale_zh":"在函數關係上引入趨近與濾子核心。"}
      ],
      "edges":[
        {"from":"mko-set-membership","to":"mko-function-mapping","relation":"recommended_before"},
        {"from":"mko-function-mapping","to":"mko-tends-to-relation","relation":"required_before"}
      ],
      "review":{"status":"reviewed","reviewer":"Neo.K / Aletheia","version":1}
    },
    {
      "schema_version":"ocme-learning-path-v0.1",
      "id":"path-modern-general-literacy",
      "title_zh":"現代通識數學樣本路徑",
      "audience":["general_learner"],
      "goal_zh":"以六個現有物件示範通識入口的多分支學習方式。",
      "nodes":[
        {"object_id":"mko-set-membership","position":1,"requirement":"required","rationale_zh":"先接觸現代數學常用的集合語言。"},
        {"object_id":"mko-function-mapping","position":2,"requirement":"required","rationale_zh":"建立函數作為映射的基本概念。"},
        {"object_id":"mko-euclidean-length","position":2,"requirement":"optional","rationale_zh":"平行進入幾何量與距離。"},
        {"object_id":"mko-right-triangle","position":3,"requirement":"optional","rationale_zh":"由長度進入直角幾何。"},
        {"object_id":"mko-euclid-pythagorean-theorem","position":4,"requirement":"optional","rationale_zh":"觀察幾何、代數與證明的連接。"},
        {"object_id":"mko-tends-to-relation","position":4,"requirement":"optional","rationale_zh":"由函數進入分析中的趨近語義。"}
      ],
      "edges":[
        {"from":"mko-set-membership","to":"mko-function-mapping","relation":"recommended_before"},
        {"from":"mko-euclidean-length","to":"mko-right-triangle","relation":"recommended_before"},
        {"from":"mko-right-triangle","to":"mko-euclid-pythagorean-theorem","relation":"recommended_before"},
        {"from":"mko-function-mapping","to":"mko-tends-to-relation","relation":"recommended_before"}
      ],
      "review":{"status":"reviewed","reviewer":"Neo.K / Aletheia","version":1}
    },
    {
      "schema_version":"ocme-learning-path-v0.1",
      "id":"path-formalized-mathematics-entry",
      "title_zh":"形式化數學入門樣本",
      "audience":["undergraduate","formalizer"],
      "goal_zh":"從集合與函數語義進入 Lean／Mathlib 的精確聲明與證據物件。",
      "nodes":[
        {"object_id":"mko-set-membership","position":1,"requirement":"required","rationale_zh":"對齊 Set 作為謂詞的形式語義。"},
        {"object_id":"mko-function-mapping","position":2,"requirement":"required","rationale_zh":"對齊總函數型別與唯一輸出。"},
        {"object_id":"mko-tends-to-relation","position":3,"requirement":"required","rationale_zh":"理解 Filter.Tendsto 的形式核心。"},
        {"object_id":"mko-euclid-pythagorean-theorem","position":4,"requirement":"optional","rationale_zh":"觀察百科語義到向量及邊長模型的形式橋。"}
      ],
      "edges":[
        {"from":"mko-set-membership","to":"mko-function-mapping","relation":"required_before"},
        {"from":"mko-function-mapping","to":"mko-tends-to-relation","relation":"required_before"}
      ],
      "review":{"status":"reviewed","reviewer":"Neo.K / Aletheia","version":1}
    },
    {
      "schema_version":"ocme-learning-path-v0.1",
      "id":"path-proof-and-evidence-literacy",
      "title_zh":"證明與證據素養",
      "audience":["general_learner","undergraduate"],
      "goal_zh":"先辨識證明義務，再區分人工證明、有限計算證據與精確形式證明。",
      "nodes":[
        {"object_id":"mko-proof","position":1,"requirement":"required","rationale_zh":"先建立前提、推理、結論與非證明證據的區分。"},
        {"object_id":"mko-euclid-pythagorean-theorem","position":2,"requirement":"required","rationale_zh":"同一物件同時具有人工、Python、FELRA 與 Lean 證據。"},
        {"object_id":"mko-right-triangle","position":3,"requirement":"optional","rationale_zh":"比較定義物件與定理物件的證據需求。"},
        {"object_id":"mko-tends-to-relation","position":3,"requirement":"optional","rationale_zh":"比較形式核心與完整分析語義的邊界。"}
      ],
      "edges":[
        {"from":"mko-proof","to":"mko-euclid-pythagorean-theorem","relation":"recommended_before"},
        {"from":"mko-euclid-pythagorean-theorem","to":"mko-right-triangle","relation":"extends"},
        {"from":"mko-euclid-pythagorean-theorem","to":"mko-tends-to-relation","relation":"alternative_entry"}
      ],
      "review":{"status":"reviewed","reviewer":"Neo.K / Aletheia","version":1}
    },
    {
      "schema_version":"ocme-learning-path-v0.1",
      "id":"path-foundational-language-candidate",
      "title_zh":"數學基礎語言候選路徑",
      "audience":["general_learner","upper_secondary"],
      "goal_zh":"從計數的具體語言前進到集合、命題與邏輯連接詞，建立閱讀後續數學物件所需的基礎語言。",
      "nodes":[
        {"object_id":"mko-natural-number","position":1,"requirement":"required","rationale_zh":"先用熟悉的計數對象建立數學概念與符號的區分。"},
        {"object_id":"mko-set","position":2,"requirement":"required","rationale_zh":"再以集合整理對象、元素與整體之間的語言。"},
        {"object_id":"mko-proposition","position":3,"requirement":"required","rationale_zh":"引入可被斷言、判定與證明的數學陳述。"},
        {"object_id":"mko-logical-connectives","position":4,"requirement":"required","rationale_zh":"用否定、合取、析取、蘊涵與雙條件組合命題。"},
        {"object_id":"mko-proof","position":5,"requirement":"required","rationale_zh":"以明示前提與合法推理建立結論。"}
      ],
      "edges":[
        {"from":"mko-natural-number","to":"mko-set","relation":"recommended_before"},
        {"from":"mko-set","to":"mko-proposition","relation":"recommended_before"},
        {"from":"mko-proposition","to":"mko-logical-connectives","relation":"required_before"},
        {"from":"mko-logical-connectives","to":"mko-proof","relation":"required_before"}
      ],
      "review":{"status":"candidate","reviewer":"Codex local AI","version":2}
    },
    {
      "schema_version":"ocme-learning-path-v0.1",
      "id":"path-domain-coverage-wave-one",
      "title_zh":"第一波領域覆蓋基礎",
      "audience":["general_learner","upper_secondary"],
      "goal_zh":"由自然數、集合與命題分支進入算術、方程、機率、歸納、階乘與基本組合計數。",
      "nodes":[
        {"object_id":"mko-natural-number","position":1,"requirement":"required","rationale_zh":"提供算術、歸納與有限計數的自然數基礎。"},
        {"object_id":"mko-set","position":1,"requirement":"required","rationale_zh":"提供樣本空間作為結果集合的基礎。"},
        {"object_id":"mko-proposition","position":1,"requirement":"required","rationale_zh":"提供歸納法所處理命題族的邏輯基礎。"},
        {"object_id":"mko-arithmetic-operations","position":2,"requirement":"required","rationale_zh":"解鎖代數表達與基本計數中的數量組合。"},
        {"object_id":"mko-sample-space","position":2,"requirement":"optional","rationale_zh":"從集合語言進入機率統計的結果論域。"},
        {"object_id":"mko-mathematical-induction","position":2,"requirement":"optional","rationale_zh":"從自然數與命題進入結構化證明方法。"},
        {"object_id":"mko-variable-expression","position":3,"requirement":"optional","rationale_zh":"從算術運算進入含變數的代數表達。"},
        {"object_id":"mko-equation","position":4,"requirement":"optional","rationale_zh":"由表達式進入等式、解集與代入驗證。"},
        {"object_id":"mko-linear-equation","position":5,"requirement":"optional","rationale_zh":"以非零一次係數收斂到唯一解與退化分類。"},
        {"object_id":"mko-counting-principle","position":3,"requirement":"optional","rationale_zh":"以自然數與算術運算組合有限選擇數量。"},
        {"object_id":"mko-factorial","position":3,"requirement":"optional","rationale_zh":"以自然數乘法與後繼遞迴建立有限乘積。"}
      ],
      "edges":[
        {"from":"mko-natural-number","to":"mko-arithmetic-operations","relation":"required_before"},
        {"from":"mko-arithmetic-operations","to":"mko-variable-expression","relation":"required_before"},
        {"from":"mko-variable-expression","to":"mko-equation","relation":"required_before"},
        {"from":"mko-equation","to":"mko-linear-equation","relation":"required_before"},
        {"from":"mko-set","to":"mko-sample-space","relation":"required_before"},
        {"from":"mko-natural-number","to":"mko-mathematical-induction","relation":"required_before"},
        {"from":"mko-proposition","to":"mko-mathematical-induction","relation":"required_before"},
        {"from":"mko-natural-number","to":"mko-counting-principle","relation":"required_before"},
        {"from":"mko-arithmetic-operations","to":"mko-counting-principle","relation":"required_before"},
        {"from":"mko-natural-number","to":"mko-factorial","relation":"required_before"},
        {"from":"mko-arithmetic-operations","to":"mko-factorial","relation":"required_before"}
      ],
      "review":{"status":"candidate","reviewer":"Codex local AI","version":1}
    },
    {
      "schema_version":"ocme-learning-path-v0.1",
      "id":"path-set-language-to-topology-candidate",
      "title_zh":"集合語言到拓撲前置候選路徑",
      "audience":["upper_secondary","undergraduate"],
      "goal_zh":"從集合、元素隸屬、子集合與基本集合運算建立閱讀拓撲空間定義所需的集合語言。",
      "nodes":[
        {"object_id":"mko-set","position":1,"requirement":"required","rationale_zh":"先確立集合是由隸屬條件刻畫的對象。"},
        {"object_id":"mko-set-membership","position":2,"requirement":"required","rationale_zh":"再以元素是否屬於集合表達運算定義。"},
        {"object_id":"mko-subset","position":3,"requirement":"required","rationale_zh":"由逐元素隸屬建立集合之間的包含關係。"},
        {"object_id":"mko-set-operations","position":3,"requirement":"required","rationale_zh":"平行建立聯集、交集、差集與相對補集。"}
      ],
      "edges":[
        {"from":"mko-set","to":"mko-set-membership","relation":"recommended_before"},
        {"from":"mko-set-membership","to":"mko-subset","relation":"required_before"},
        {"from":"mko-set-membership","to":"mko-set-operations","relation":"required_before"}
      ],
      "review":{"status":"candidate","reviewer":"Codex local AI","version":1}
    },
    {
      "schema_version":"ocme-learning-path-v0.1",
      "id":"path-probability-events-candidate",
      "title_zh":"樣本空間到事件候選路徑",
      "audience":["upper_secondary","undergraduate"],
      "goal_zh":"由集合語言與樣本空間建立事件作為結果子集合的精確邊界。",
      "nodes":[
        {"object_id":"mko-set","position":1,"requirement":"required","rationale_zh":"先建立集合語言。"},
        {"object_id":"mko-set-membership","position":2,"requirement":"required","rationale_zh":"區分結果元素與結果集合。"},
        {"object_id":"mko-subset","position":3,"requirement":"required","rationale_zh":"建立集合之間的包含關係。"},
        {"object_id":"mko-sample-space","position":3,"requirement":"required","rationale_zh":"指定試驗的全部可能結果。"},
        {"object_id":"mko-event","position":4,"requirement":"required","rationale_zh":"把事件定位為樣本空間中的結果集合。"}
      ],
      "edges":[
        {"from":"mko-set","to":"mko-set-membership","relation":"required_before"},
        {"from":"mko-set-membership","to":"mko-subset","relation":"required_before"},
        {"from":"mko-set","to":"mko-sample-space","relation":"required_before"},
        {"from":"mko-subset","to":"mko-event","relation":"required_before"},
        {"from":"mko-sample-space","to":"mko-event","relation":"required_before"}
      ],
      "review":{"status":"candidate","reviewer":"Codex local AI","version":1}
    },
    {
      "schema_version":"ocme-learning-path-v0.1",
      "id":"path-number-system-extension-candidate",
      "title_zh":"自然數、整數、有理數、實數到絕對值候選路徑",
      "audience":["general_learner","lower_secondary"],
      "goal_zh":"由計數用的自然數進入整數與有理數，以完備化語言建立實數入口，再用絕對值表達數線距離。",
      "nodes":[
        {"object_id":"mko-natural-number","position":1,"requirement":"required","rationale_zh":"先建立自然數與零的慣例。"},
        {"object_id":"mko-integer","position":2,"requirement":"required","rationale_zh":"加入負方向形成整數。"},
        {"object_id":"mko-rational-number","position":3,"requirement":"required","rationale_zh":"以兩個整數之比建立有理數，並排除零分母。"},
        {"object_id":"mko-real-number","position":4,"requirement":"required","rationale_zh":"由有理數嵌入與完備化進入實數系。"},
        {"object_id":"mko-absolute-value","position":5,"requirement":"optional","rationale_zh":"以分段函數表示實數到零的非負距離。"}
      ],
      "edges":[
        {"from":"mko-natural-number","to":"mko-integer","relation":"required_before"},
        {"from":"mko-integer","to":"mko-rational-number","relation":"required_before"},
        {"from":"mko-rational-number","to":"mko-real-number","relation":"required_before"},
        {"from":"mko-real-number","to":"mko-absolute-value","relation":"required_before"}
      ],
      "review":{"status":"candidate","reviewer":"Codex local AI","version":3}
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}
