{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0001","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"69abf5f81af43b21b6e265ceccafa497f17e2895eb6acf941d514cd0a2f9f3e2","family_id":"qf-mod30-convprob-deviation-probability","seed":202610307001,"semantic_template":"qf-mod30-convprob-deviation-probability/{\"n\":1,\"numerator\":1,\"shift\":2}"},"fields":{"title":"Evaluate the Deviation Profile Only at a Valid Probability Index","stem":"Use the declared rational deviation-probability tail p_n=1/(n+2) on nonnegative integer indices where this value belongs to[0,1], starting no earlier than max(0,numerator-shift). The common probability space and infinite-process interpretation remain declared premises, not constructions inferred from finitely many numbers. Keep exact reduced rational outputs with positive denominators, omitting /1 for integers. Evaluate index n=1. Give (numerator,shift,n,deviation_probability).","answer":{"kind":"expression","value":"(1, 2, 1, 1/3)","explanation":"The supplied index must lie in the declared probability domain. Evaluate the exact rational value without clipping it to1, renormalizing it or silently shifting the index. One value does not establish convergence for every epsilon. The exact result, retaining the requested order, is (1, 2, 1, 1/3)."},"skills":["Evaluate the Deviation Profile Only at a Valid Probability Index"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0002","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"7a3056094e8b794292020b5f70a24857f70b040dd05662bbf1c42a77614b5467","family_id":"qf-mod30-convprob-deviation-probability","seed":202610307002,"semantic_template":"qf-mod30-convprob-deviation-probability/{\"n\":2,\"numerator\":2,\"shift\":3}"},"fields":{"title":"Evaluate the Deviation Profile Only at a Valid Probability Index","stem":"Use the declared rational deviation-probability tail p_n=2/(n+3) on nonnegative integer indices where this value belongs to[0,1], starting no earlier than max(0,numerator-shift). The common probability space and infinite-process interpretation remain declared premises, not constructions inferred from finitely many numbers. Keep exact reduced rational outputs with positive denominators, omitting /1 for integers. Evaluate index n=2. Give (numerator,shift,n,deviation_probability).","answer":{"kind":"expression","value":"(2, 3, 2, 2/5)","explanation":"The supplied index must lie in the declared probability domain. Evaluate the exact rational value without clipping it to1, renormalizing it or silently shifting the index. One value does not establish convergence for every epsilon. The exact result, retaining the requested order, is (2, 3, 2, 2/5)."},"skills":["Evaluate the Deviation Profile Only at a Valid Probability Index"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0003","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"093e4f00a89eb386217f0bd55735696a7dcb321eb60df05b60171d707f3716a4","family_id":"qf-mod30-convprob-deviation-probability","seed":202610307003,"semantic_template":"qf-mod30-convprob-deviation-probability/{\"n\":3,\"numerator\":3,\"shift\":4}"},"fields":{"title":"Evaluate the Deviation Profile Only at a Valid Probability Index","stem":"Use the declared rational deviation-probability tail p_n=3/(n+4) on nonnegative integer indices where this value belongs to[0,1], starting no earlier than max(0,numerator-shift). The common probability space and infinite-process interpretation remain declared premises, not constructions inferred from finitely many numbers. Keep exact reduced rational outputs with positive denominators, omitting /1 for integers. Evaluate index n=3. Give (numerator,shift,n,deviation_probability).","answer":{"kind":"expression","value":"(3, 4, 3, 3/7)","explanation":"The supplied index must lie in the declared probability domain. Evaluate the exact rational value without clipping it to1, renormalizing it or silently shifting the index. One value does not establish convergence for every epsilon. The exact result, retaining the requested order, is (3, 4, 3, 3/7)."},"skills":["Evaluate the Deviation Profile Only at a Valid Probability Index"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0004","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"257c790a3a22b34d2664c08e9b1794e12b5ffe529634020526900f92790250fe","family_id":"qf-mod30-convprob-deviation-probability","seed":202610307004,"semantic_template":"qf-mod30-convprob-deviation-probability/{\"n\":4,\"numerator\":4,\"shift\":5}"},"fields":{"title":"Evaluate the Deviation Profile Only at a Valid Probability Index","stem":"Use the declared rational deviation-probability tail p_n=4/(n+5) on nonnegative integer indices where this value belongs to[0,1], starting no earlier than max(0,numerator-shift). The common probability space and infinite-process interpretation remain declared premises, not constructions inferred from finitely many numbers. Keep exact reduced rational outputs with positive denominators, omitting /1 for integers. Evaluate index n=4. Give (numerator,shift,n,deviation_probability).","answer":{"kind":"expression","value":"(4, 5, 4, 4/9)","explanation":"The supplied index must lie in the declared probability domain. Evaluate the exact rational value without clipping it to1, renormalizing it or silently shifting the index. One value does not establish convergence for every epsilon. The exact result, retaining the requested order, is (4, 5, 4, 4/9)."},"skills":["Evaluate the Deviation Profile Only at a Valid Probability Index"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0005","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"26bcd63524fa2661add4ec65d6c4a6d6fe8723ceb55e9c15f951787b62e1b305","family_id":"qf-mod30-convprob-deviation-probability","seed":202610307005,"semantic_template":"qf-mod30-convprob-deviation-probability/{\"n\":5,\"numerator\":5,\"shift\":6}"},"fields":{"title":"Evaluate the Deviation Profile Only at a Valid Probability Index","stem":"Use the declared rational deviation-probability tail p_n=5/(n+6) on nonnegative integer indices where this value belongs to[0,1], starting no earlier than max(0,numerator-shift). The common probability space and infinite-process interpretation remain declared premises, not constructions inferred from finitely many numbers. Keep exact reduced rational outputs with positive denominators, omitting /1 for integers. Evaluate index n=5. Give (numerator,shift,n,deviation_probability).","answer":{"kind":"expression","value":"(5, 6, 5, 5/11)","explanation":"The supplied index must lie in the declared probability domain. Evaluate the exact rational value without clipping it to1, renormalizing it or silently shifting the index. One value does not establish convergence for every epsilon. The exact result, retaining the requested order, is (5, 6, 5, 5/11)."},"skills":["Evaluate the Deviation Profile Only at a Valid Probability Index"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0006","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"957c4d7c33cf9621521b91e52ec1aaf9473e33dd54ffc3c5e7896d29a4fb846b","family_id":"qf-mod30-convprob-deviation-probability","seed":202610307006,"semantic_template":"qf-mod30-convprob-deviation-probability/{\"n\":6,\"numerator\":1,\"shift\":7}"},"fields":{"title":"Evaluate the Deviation Profile Only at a Valid Probability Index","stem":"Use the declared rational deviation-probability tail p_n=1/(n+7) on nonnegative integer indices where this value belongs to[0,1], starting no earlier than max(0,numerator-shift). The common probability space and infinite-process interpretation remain declared premises, not constructions inferred from finitely many numbers. Keep exact reduced rational outputs with positive denominators, omitting /1 for integers. Evaluate index n=6. Give (numerator,shift,n,deviation_probability).","answer":{"kind":"expression","value":"(1, 7, 6, 1/13)","explanation":"The supplied index must lie in the declared probability domain. Evaluate the exact rational value without clipping it to1, renormalizing it or silently shifting the index. One value does not establish convergence for every epsilon. The exact result, retaining the requested order, is (1, 7, 6, 1/13)."},"skills":["Evaluate the Deviation Profile Only at a Valid Probability Index"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0007","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"9e239f437917438747262cf83b59978c4de001a280ca81be8300390c5fe8b34c","family_id":"qf-mod30-convprob-deviation-probability","seed":202610307007,"semantic_template":"qf-mod30-convprob-deviation-probability/{\"n\":7,\"numerator\":2,\"shift\":8}"},"fields":{"title":"Evaluate the Deviation Profile Only at a Valid Probability Index","stem":"Use the declared rational deviation-probability tail p_n=2/(n+8) on nonnegative integer indices where this value belongs to[0,1], starting no earlier than max(0,numerator-shift). The common probability space and infinite-process interpretation remain declared premises, not constructions inferred from finitely many numbers. Keep exact reduced rational outputs with positive denominators, omitting /1 for integers. Evaluate index n=7. Give (numerator,shift,n,deviation_probability).","answer":{"kind":"expression","value":"(2, 8, 7, 2/15)","explanation":"The supplied index must lie in the declared probability domain. Evaluate the exact rational value without clipping it to1, renormalizing it or silently shifting the index. One value does not establish convergence for every epsilon. The exact result, retaining the requested order, is (2, 8, 7, 2/15)."},"skills":["Evaluate the Deviation Profile Only at a Valid Probability Index"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0008","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"d3442e89b8d95d366303ac0ac0e16023ea576a47239d5482f1fb9032e06b3a37","family_id":"qf-mod30-convprob-deviation-probability","seed":202610307008,"semantic_template":"qf-mod30-convprob-deviation-probability/{\"n\":8,\"numerator\":3,\"shift\":2}"},"fields":{"title":"Evaluate the Deviation Profile Only at a Valid Probability Index","stem":"Use the declared rational deviation-probability tail p_n=3/(n+2) on nonnegative integer indices where this value belongs to[0,1], starting no earlier than max(0,numerator-shift). The common probability space and infinite-process interpretation remain declared premises, not constructions inferred from finitely many numbers. Keep exact reduced rational outputs with positive denominators, omitting /1 for integers. Evaluate index n=8. Give (numerator,shift,n,deviation_probability).","answer":{"kind":"expression","value":"(3, 2, 8, 3/10)","explanation":"The supplied index must lie in the declared probability domain. Evaluate the exact rational value without clipping it to1, renormalizing it or silently shifting the index. One value does not establish convergence for every epsilon. The exact result, retaining the requested order, is (3, 2, 8, 3/10)."},"skills":["Evaluate the Deviation Profile Only at a Valid Probability Index"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0009","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"20b6bf728d7d0d0810ea09456b6365a254812c5ee670b7d0540c3de15ddac3b9","family_id":"qf-mod30-convprob-deviation-probability","seed":202610307009,"semantic_template":"qf-mod30-convprob-deviation-probability/{\"n\":9,\"numerator\":4,\"shift\":3}"},"fields":{"title":"Evaluate the Deviation Profile Only at a Valid Probability Index","stem":"Use the declared rational deviation-probability tail p_n=4/(n+3) on nonnegative integer indices where this value belongs to[0,1], starting no earlier than max(0,numerator-shift). The common probability space and infinite-process interpretation remain declared premises, not constructions inferred from finitely many numbers. Keep exact reduced rational outputs with positive denominators, omitting /1 for integers. Evaluate index n=9. Give (numerator,shift,n,deviation_probability).","answer":{"kind":"expression","value":"(4, 3, 9, 1/3)","explanation":"The supplied index must lie in the declared probability domain. Evaluate the exact rational value without clipping it to1, renormalizing it or silently shifting the index. One value does not establish convergence for every epsilon. The exact result, retaining the requested order, is (4, 3, 9, 1/3)."},"skills":["Evaluate the Deviation Profile Only at a Valid Probability Index"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0010","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"ee51c842586c9cf0be8c4bc18861e16cb64ed7342a4999706f93c6e2e757c296","family_id":"qf-mod30-convprob-deviation-probability","seed":202610307010,"semantic_template":"qf-mod30-convprob-deviation-probability/{\"n\":10,\"numerator\":5,\"shift\":4}"},"fields":{"title":"Evaluate the Deviation Profile Only at a Valid Probability Index","stem":"Use the declared rational deviation-probability tail p_n=5/(n+4) on nonnegative integer indices where this value belongs to[0,1], starting no earlier than max(0,numerator-shift). The common probability space and infinite-process interpretation remain declared premises, not constructions inferred from finitely many numbers. Keep exact reduced rational outputs with positive denominators, omitting /1 for integers. Evaluate index n=10. Give (numerator,shift,n,deviation_probability).","answer":{"kind":"expression","value":"(5, 4, 10, 5/14)","explanation":"The supplied index must lie in the declared probability domain. Evaluate the exact rational value without clipping it to1, renormalizing it or silently shifting the index. One value does not establish convergence for every epsilon. The exact result, retaining the requested order, is (5, 4, 10, 5/14)."},"skills":["Evaluate the Deviation Profile Only at a Valid Probability Index"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0011","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"33e435d2c128d86a78e17178c8aa067ac8bf557bf170911896da8ec7b1abcb30","family_id":"qf-mod30-convprob-deviation-probability","seed":202610307011,"semantic_template":"qf-mod30-convprob-deviation-probability/{\"n\":11,\"numerator\":1,\"shift\":5}"},"fields":{"title":"Evaluate the Deviation Profile Only at a Valid Probability Index","stem":"Use the declared rational deviation-probability tail p_n=1/(n+5) on nonnegative integer indices where this value belongs to[0,1], starting no earlier than max(0,numerator-shift). The common probability space and infinite-process interpretation remain declared premises, not constructions inferred from finitely many numbers. Keep exact reduced rational outputs with positive denominators, omitting /1 for integers. Evaluate index n=11. Give (numerator,shift,n,deviation_probability).","answer":{"kind":"expression","value":"(1, 5, 11, 1/16)","explanation":"The supplied index must lie in the declared probability domain. Evaluate the exact rational value without clipping it to1, renormalizing it or silently shifting the index. One value does not establish convergence for every epsilon. The exact result, retaining the requested order, is (1, 5, 11, 1/16)."},"skills":["Evaluate the Deviation Profile Only at a Valid Probability Index"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0012","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"9b4da8183649ad982877262b1e7ea020ef2f94de482cc94ff626fa54a1db6f4b","family_id":"qf-mod30-convprob-deviation-probability","seed":202610307012,"semantic_template":"qf-mod30-convprob-deviation-probability/{\"n\":12,\"numerator\":2,\"shift\":6}"},"fields":{"title":"Evaluate the Deviation Profile Only at a Valid Probability Index","stem":"Use the declared rational deviation-probability tail p_n=2/(n+6) on nonnegative integer indices where this value belongs to[0,1], starting no earlier than max(0,numerator-shift). The common probability space and infinite-process interpretation remain declared premises, not constructions inferred from finitely many numbers. Keep exact reduced rational outputs with positive denominators, omitting /1 for integers. Evaluate index n=12. Give (numerator,shift,n,deviation_probability).","answer":{"kind":"expression","value":"(2, 6, 12, 1/9)","explanation":"The supplied index must lie in the declared probability domain. Evaluate the exact rational value without clipping it to1, renormalizing it or silently shifting the index. One value does not establish convergence for every epsilon. The exact result, retaining the requested order, is (2, 6, 12, 1/9)."},"skills":["Evaluate the Deviation Profile Only at a Valid Probability Index"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0013","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"faed14f5fe2230baaadb9bafc2e60874ad2bdaff21eac4d1d081f184344d1416","family_id":"qf-mod30-convprob-deviation-probability","seed":202610307013,"semantic_template":"qf-mod30-convprob-deviation-probability/{\"n\":13,\"numerator\":3,\"shift\":7}"},"fields":{"title":"Evaluate the Deviation Profile Only at a Valid Probability Index","stem":"Use the declared rational deviation-probability tail p_n=3/(n+7) on nonnegative integer indices where this value belongs to[0,1], starting no earlier than max(0,numerator-shift). The common probability space and infinite-process interpretation remain declared premises, not constructions inferred from finitely many numbers. Keep exact reduced rational outputs with positive denominators, omitting /1 for integers. Evaluate index n=13. Give (numerator,shift,n,deviation_probability).","answer":{"kind":"expression","value":"(3, 7, 13, 3/20)","explanation":"The supplied index must lie in the declared probability domain. Evaluate the exact rational value without clipping it to1, renormalizing it or silently shifting the index. One value does not establish convergence for every epsilon. The exact result, retaining the requested order, is (3, 7, 13, 3/20)."},"skills":["Evaluate the Deviation Profile Only at a Valid Probability Index"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0014","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"060304176890018434afcb6a9ec72a6a61bc32797e4c28808abea8f1a80c0a91","family_id":"qf-mod30-convprob-deviation-probability","seed":202610307014,"semantic_template":"qf-mod30-convprob-deviation-probability/{\"n\":14,\"numerator\":4,\"shift\":8}"},"fields":{"title":"Evaluate the Deviation Profile Only at a Valid Probability Index","stem":"Use the declared rational deviation-probability tail p_n=4/(n+8) on nonnegative integer indices where this value belongs to[0,1], starting no earlier than max(0,numerator-shift). The common probability space and infinite-process interpretation remain declared premises, not constructions inferred from finitely many numbers. Keep exact reduced rational outputs with positive denominators, omitting /1 for integers. Evaluate index n=14. Give (numerator,shift,n,deviation_probability).","answer":{"kind":"expression","value":"(4, 8, 14, 2/11)","explanation":"The supplied index must lie in the declared probability domain. Evaluate the exact rational value without clipping it to1, renormalizing it or silently shifting the index. One value does not establish convergence for every epsilon. The exact result, retaining the requested order, is (4, 8, 14, 2/11)."},"skills":["Evaluate the Deviation Profile Only at a Valid Probability Index"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0015","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"40d9f3e9679676fb61d85738b9b50859694a0604b209107f1091ab3212f4172d","family_id":"qf-mod30-convprob-deviation-probability","seed":202610307015,"semantic_template":"qf-mod30-convprob-deviation-probability/{\"n\":15,\"numerator\":5,\"shift\":2}"},"fields":{"title":"Evaluate the Deviation Profile Only at a Valid Probability Index","stem":"Use the declared rational deviation-probability tail p_n=5/(n+2) on nonnegative integer indices where this value belongs to[0,1], starting no earlier than max(0,numerator-shift). The common probability space and infinite-process interpretation remain declared premises, not constructions inferred from finitely many numbers. Keep exact reduced rational outputs with positive denominators, omitting /1 for integers. Evaluate index n=15. Give (numerator,shift,n,deviation_probability).","answer":{"kind":"expression","value":"(5, 2, 15, 5/17)","explanation":"The supplied index must lie in the declared probability domain. Evaluate the exact rational value without clipping it to1, renormalizing it or silently shifting the index. One value does not establish convergence for every epsilon. The exact result, retaining the requested order, is (5, 2, 15, 5/17)."},"skills":["Evaluate the Deviation Profile Only at a Valid Probability Index"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0016","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"0ecd89e616b4d5fb82d955cdcb00b96fb1d0058d0981f1d941a669235cf84400","family_id":"qf-mod30-convprob-deviation-probability","seed":202610307016,"semantic_template":"qf-mod30-convprob-deviation-probability/{\"n\":16,\"numerator\":1,\"shift\":3}"},"fields":{"title":"Evaluate the Deviation Profile Only at a Valid Probability Index","stem":"Use the declared rational deviation-probability tail p_n=1/(n+3) on nonnegative integer indices where this value belongs to[0,1], starting no earlier than max(0,numerator-shift). The common probability space and infinite-process interpretation remain declared premises, not constructions inferred from finitely many numbers. Keep exact reduced rational outputs with positive denominators, omitting /1 for integers. Evaluate index n=16. Give (numerator,shift,n,deviation_probability).","answer":{"kind":"expression","value":"(1, 3, 16, 1/19)","explanation":"The supplied index must lie in the declared probability domain. Evaluate the exact rational value without clipping it to1, renormalizing it or silently shifting the index. One value does not establish convergence for every epsilon. The exact result, retaining the requested order, is (1, 3, 16, 1/19)."},"skills":["Evaluate the Deviation Profile Only at a Valid Probability Index"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0017","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"b5d6543c6a682baf172ca4a276d39e607d8504b0da73db5256aa6b6a05363381","family_id":"qf-mod30-convprob-deviation-probability","seed":202610307017,"semantic_template":"qf-mod30-convprob-deviation-probability/{\"n\":17,\"numerator\":2,\"shift\":4}"},"fields":{"title":"Evaluate the Deviation Profile Only at a Valid Probability Index","stem":"Use the declared rational deviation-probability tail p_n=2/(n+4) on nonnegative integer indices where this value belongs to[0,1], starting no earlier than max(0,numerator-shift). The common probability space and infinite-process interpretation remain declared premises, not constructions inferred from finitely many numbers. Keep exact reduced rational outputs with positive denominators, omitting /1 for integers. Evaluate index n=17. Give (numerator,shift,n,deviation_probability).","answer":{"kind":"expression","value":"(2, 4, 17, 2/21)","explanation":"The supplied index must lie in the declared probability domain. Evaluate the exact rational value without clipping it to1, renormalizing it or silently shifting the index. One value does not establish convergence for every epsilon. The exact result, retaining the requested order, is (2, 4, 17, 2/21)."},"skills":["Evaluate the Deviation Profile Only at a Valid Probability Index"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0018","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"6dadd7cb3a87168a5020cca7022d903d50007db183e0b26ba9ae8c5fe00e8bb4","family_id":"qf-mod30-convprob-deviation-probability","seed":202610307018,"semantic_template":"qf-mod30-convprob-deviation-probability/{\"n\":18,\"numerator\":3,\"shift\":5}"},"fields":{"title":"Evaluate the Deviation Profile Only at a Valid Probability Index","stem":"Use the declared rational deviation-probability tail p_n=3/(n+5) on nonnegative integer indices where this value belongs to[0,1], starting no earlier than max(0,numerator-shift). The common probability space and infinite-process interpretation remain declared premises, not constructions inferred from finitely many numbers. Keep exact reduced rational outputs with positive denominators, omitting /1 for integers. Evaluate index n=18. Give (numerator,shift,n,deviation_probability).","answer":{"kind":"expression","value":"(3, 5, 18, 3/23)","explanation":"The supplied index must lie in the declared probability domain. Evaluate the exact rational value without clipping it to1, renormalizing it or silently shifting the index. One value does not establish convergence for every epsilon. The exact result, retaining the requested order, is (3, 5, 18, 3/23)."},"skills":["Evaluate the Deviation Profile Only at a Valid Probability Index"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0019","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"1fd0d9f0cd316ca187e38dbb9bc7de8539be890332cd49fa3a58188bc5f90f5c","family_id":"qf-mod30-convprob-deviation-probability","seed":202610307019,"semantic_template":"qf-mod30-convprob-deviation-probability/{\"n\":19,\"numerator\":4,\"shift\":6}"},"fields":{"title":"Evaluate the Deviation Profile Only at a Valid Probability Index","stem":"Use the declared rational deviation-probability tail p_n=4/(n+6) on nonnegative integer indices where this value belongs to[0,1], starting no earlier than max(0,numerator-shift). The common probability space and infinite-process interpretation remain declared premises, not constructions inferred from finitely many numbers. Keep exact reduced rational outputs with positive denominators, omitting /1 for integers. Evaluate index n=19. Give (numerator,shift,n,deviation_probability).","answer":{"kind":"expression","value":"(4, 6, 19, 4/25)","explanation":"The supplied index must lie in the declared probability domain. Evaluate the exact rational value without clipping it to1, renormalizing it or silently shifting the index. One value does not establish convergence for every epsilon. The exact result, retaining the requested order, is (4, 6, 19, 4/25)."},"skills":["Evaluate the Deviation Profile Only at a Valid Probability Index"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0020","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"0305fe6348dd9a72d3880e448522a6911fcaa5ec6170e00c69a40f5ab7ff9b7f","family_id":"qf-mod30-convprob-deviation-probability","seed":202610307020,"semantic_template":"qf-mod30-convprob-deviation-probability/{\"n\":20,\"numerator\":5,\"shift\":7}"},"fields":{"title":"Evaluate the Deviation Profile Only at a Valid Probability Index","stem":"Use the declared rational deviation-probability tail p_n=5/(n+7) on nonnegative integer indices where this value belongs to[0,1], starting no earlier than max(0,numerator-shift). The common probability space and infinite-process interpretation remain declared premises, not constructions inferred from finitely many numbers. Keep exact reduced rational outputs with positive denominators, omitting /1 for integers. Evaluate index n=20. Give (numerator,shift,n,deviation_probability).","answer":{"kind":"expression","value":"(5, 7, 20, 5/27)","explanation":"The supplied index must lie in the declared probability domain. Evaluate the exact rational value without clipping it to1, renormalizing it or silently shifting the index. One value does not establish convergence for every epsilon. The exact result, retaining the requested order, is (5, 7, 20, 5/27)."},"skills":["Evaluate the Deviation Profile Only at a Valid Probability Index"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0021","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"4c16caa2e4790579e7ca9df410c3cb9e47dfc02ff86dfc5a94a7194ef3f89329","family_id":"qf-mod30-convprob-deviation-probability","seed":202610307021,"semantic_template":"qf-mod30-convprob-deviation-probability/{\"n\":21,\"numerator\":1,\"shift\":8}"},"fields":{"title":"Evaluate the Deviation Profile Only at a Valid Probability Index","stem":"Use the declared rational deviation-probability tail p_n=1/(n+8) on nonnegative integer indices where this value belongs to[0,1], starting no earlier than max(0,numerator-shift). The common probability space and infinite-process interpretation remain declared premises, not constructions inferred from finitely many numbers. Keep exact reduced rational outputs with positive denominators, omitting /1 for integers. Evaluate index n=21. Give (numerator,shift,n,deviation_probability).","answer":{"kind":"expression","value":"(1, 8, 21, 1/29)","explanation":"The supplied index must lie in the declared probability domain. Evaluate the exact rational value without clipping it to1, renormalizing it or silently shifting the index. One value does not establish convergence for every epsilon. The exact result, retaining the requested order, is (1, 8, 21, 1/29)."},"skills":["Evaluate the Deviation Profile Only at a Valid Probability Index"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0022","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"f88baf64c66724c67a5beee29b39754241c945beaf0ca7a4fb72df5b22ab5104","family_id":"qf-mod30-convprob-deviation-probability","seed":202610307022,"semantic_template":"qf-mod30-convprob-deviation-probability/{\"n\":22,\"numerator\":2,\"shift\":2}"},"fields":{"title":"Evaluate the Deviation Profile Only at a Valid Probability Index","stem":"Use the declared rational deviation-probability tail p_n=2/(n+2) on nonnegative integer indices where this value belongs to[0,1], starting no earlier than max(0,numerator-shift). The common probability space and infinite-process interpretation remain declared premises, not constructions inferred from finitely many numbers. Keep exact reduced rational outputs with positive denominators, omitting /1 for integers. Evaluate index n=22. Give (numerator,shift,n,deviation_probability).","answer":{"kind":"expression","value":"(2, 2, 22, 1/12)","explanation":"The supplied index must lie in the declared probability domain. Evaluate the exact rational value without clipping it to1, renormalizing it or silently shifting the index. One value does not establish convergence for every epsilon. The exact result, retaining the requested order, is (2, 2, 22, 1/12)."},"skills":["Evaluate the Deviation Profile Only at a Valid Probability Index"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0023","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"4905707f3edfef4fb8c860639222d253e9426cdc6b84b71c748e14f55d44f156","family_id":"qf-mod30-convprob-deviation-probability","seed":202610307023,"semantic_template":"qf-mod30-convprob-deviation-probability/{\"n\":23,\"numerator\":3,\"shift\":3}"},"fields":{"title":"Evaluate the Deviation Profile Only at a Valid Probability Index","stem":"Use the declared rational deviation-probability tail p_n=3/(n+3) on nonnegative integer indices where this value belongs to[0,1], starting no earlier than max(0,numerator-shift). The common probability space and infinite-process interpretation remain declared premises, not constructions inferred from finitely many numbers. Keep exact reduced rational outputs with positive denominators, omitting /1 for integers. Evaluate index n=23. Give (numerator,shift,n,deviation_probability).","answer":{"kind":"expression","value":"(3, 3, 23, 3/26)","explanation":"The supplied index must lie in the declared probability domain. Evaluate the exact rational value without clipping it to1, renormalizing it or silently shifting the index. One value does not establish convergence for every epsilon. The exact result, retaining the requested order, is (3, 3, 23, 3/26)."},"skills":["Evaluate the Deviation Profile Only at a Valid Probability Index"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0024","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"45176f49a87f28ccf5971aff7ef20d76616a305dd732ce59adbb19d12cd358bf","family_id":"qf-mod30-convprob-deviation-probability","seed":202610307024,"semantic_template":"qf-mod30-convprob-deviation-probability/{\"n\":24,\"numerator\":4,\"shift\":4}"},"fields":{"title":"Evaluate the Deviation Profile Only at a Valid Probability Index","stem":"Use the declared rational deviation-probability tail p_n=4/(n+4) on nonnegative integer indices where this value belongs to[0,1], starting no earlier than max(0,numerator-shift). The common probability space and infinite-process interpretation remain declared premises, not constructions inferred from finitely many numbers. Keep exact reduced rational outputs with positive denominators, omitting /1 for integers. Evaluate index n=24. Give (numerator,shift,n,deviation_probability).","answer":{"kind":"expression","value":"(4, 4, 24, 1/7)","explanation":"The supplied index must lie in the declared probability domain. Evaluate the exact rational value without clipping it to1, renormalizing it or silently shifting the index. One value does not establish convergence for every epsilon. The exact result, retaining the requested order, is (4, 4, 24, 1/7)."},"skills":["Evaluate the Deviation Profile Only at a Valid Probability Index"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0025","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"bde2dcc23d916c4ee169fda2958d1af3a123a3518e94d256277c058837a146ad","family_id":"qf-mod30-convprob-deviation-probability","seed":202610307025,"semantic_template":"qf-mod30-convprob-deviation-probability/{\"n\":25,\"numerator\":5,\"shift\":5}"},"fields":{"title":"Evaluate the Deviation Profile Only at a Valid Probability Index","stem":"Use the declared rational deviation-probability tail p_n=5/(n+5) on nonnegative integer indices where this value belongs to[0,1], starting no earlier than max(0,numerator-shift). The common probability space and infinite-process interpretation remain declared premises, not constructions inferred from finitely many numbers. Keep exact reduced rational outputs with positive denominators, omitting /1 for integers. Evaluate index n=25. Give (numerator,shift,n,deviation_probability).","answer":{"kind":"expression","value":"(5, 5, 25, 1/6)","explanation":"The supplied index must lie in the declared probability domain. Evaluate the exact rational value without clipping it to1, renormalizing it or silently shifting the index. One value does not establish convergence for every epsilon. The exact result, retaining the requested order, is (5, 5, 25, 1/6)."},"skills":["Evaluate the Deviation Profile Only at a Valid Probability Index"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0026","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"af12ef7a0094653dd95eadeae278d66fd0cf6351a2c3ac134271751c18874072","family_id":"qf-mod30-convprob-epsilon-witness","seed":202610307026,"semantic_template":"qf-mod30-convprob-epsilon-witness/{\"delta\":[1,10],\"numerator\":1,\"shift\":2}"},"fields":{"title":"A Strict Rational Tail Cutoff Is Different from a Finite Prefix","stem":"Use the declared rational deviation-probability tail p_n=1/(n+2) on nonnegative integer indices where this value belongs to[0,1], starting no earlier than max(0,numerator-shift). The common probability space and infinite-process interpretation remain declared premises, not constructions inferred from finitely many numbers. Keep exact reduced rational outputs with positive denominators, omitting /1 for integers. Use positive target delta=1/10. Give (numerator,shift,delta,minimal_nonnegative_N,bound_at_N,strict_tail?,forall_n_ge_N_tail_bound).","answer":{"kind":"expression","value":"(1, 2, 1/10, 9, 1/11, Yes, forall_n_ge_N_tail_bound)","explanation":"Solve the strict inequality c/(N+s)<delta with the least nonnegative integer N. The returned N must also belong to the valid probability domain. Increasing positive denominators then give the bound for every later index, conditionally on the declared deviation profile; no sampled prefix or infinite-process construction is substituted. The exact result, retaining the requested order, is (1, 2, 1/10, 9, 1/11, Yes, forall_n_ge_N_tail_bound)."},"skills":["A Strict Rational Tail Cutoff Is Different from a Finite Prefix"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0027","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"e157010189347b6899ac8625cebe199a7d12c8b04f375a2ed258036eef296887","family_id":"qf-mod30-convprob-epsilon-witness","seed":202610307027,"semantic_template":"qf-mod30-convprob-epsilon-witness/{\"delta\":[1,11],\"numerator\":2,\"shift\":3}"},"fields":{"title":"A Strict Rational Tail Cutoff Is Different from a Finite Prefix","stem":"Use the declared rational deviation-probability tail p_n=2/(n+3) on nonnegative integer indices where this value belongs to[0,1], starting no earlier than max(0,numerator-shift). The common probability space and infinite-process interpretation remain declared premises, not constructions inferred from finitely many numbers. Keep exact reduced rational outputs with positive denominators, omitting /1 for integers. Use positive target delta=1/11. Give (numerator,shift,delta,minimal_nonnegative_N,bound_at_N,strict_tail?,forall_n_ge_N_tail_bound).","answer":{"kind":"expression","value":"(2, 3, 1/11, 20, 2/23, Yes, forall_n_ge_N_tail_bound)","explanation":"Solve the strict inequality c/(N+s)<delta with the least nonnegative integer N. The returned N must also belong to the valid probability domain. Increasing positive denominators then give the bound for every later index, conditionally on the declared deviation profile; no sampled prefix or infinite-process construction is substituted. The exact result, retaining the requested order, is (2, 3, 1/11, 20, 2/23, Yes, forall_n_ge_N_tail_bound)."},"skills":["A Strict Rational Tail Cutoff Is Different from a Finite Prefix"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0028","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"ffa0215b615756e16f634c79317892e0f80b8c34b6cf0310e9690f7cf7b116cb","family_id":"qf-mod30-convprob-epsilon-witness","seed":202610307028,"semantic_template":"qf-mod30-convprob-epsilon-witness/{\"delta\":[1,12],\"numerator\":3,\"shift\":4}"},"fields":{"title":"A Strict Rational Tail Cutoff Is Different from a Finite Prefix","stem":"Use the declared rational deviation-probability tail p_n=3/(n+4) on nonnegative integer indices where this value belongs to[0,1], starting no earlier than max(0,numerator-shift). The common probability space and infinite-process interpretation remain declared premises, not constructions inferred from finitely many numbers. Keep exact reduced rational outputs with positive denominators, omitting /1 for integers. Use positive target delta=1/12. Give (numerator,shift,delta,minimal_nonnegative_N,bound_at_N,strict_tail?,forall_n_ge_N_tail_bound).","answer":{"kind":"expression","value":"(3, 4, 1/12, 33, 3/37, Yes, forall_n_ge_N_tail_bound)","explanation":"Solve the strict inequality c/(N+s)<delta with the least nonnegative integer N. The returned N must also belong to the valid probability domain. Increasing positive denominators then give the bound for every later index, conditionally on the declared deviation profile; no sampled prefix or infinite-process construction is substituted. The exact result, retaining the requested order, is (3, 4, 1/12, 33, 3/37, Yes, forall_n_ge_N_tail_bound)."},"skills":["A Strict Rational Tail Cutoff Is Different from a Finite Prefix"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0029","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"e2868bd4867b13187e43f180325d24170fab3c8ae001918bad8c16aa41392126","family_id":"qf-mod30-convprob-epsilon-witness","seed":202610307029,"semantic_template":"qf-mod30-convprob-epsilon-witness/{\"delta\":[1,13],\"numerator\":4,\"shift\":5}"},"fields":{"title":"A Strict Rational Tail Cutoff Is Different from a Finite Prefix","stem":"Use the declared rational deviation-probability tail p_n=4/(n+5) on nonnegative integer indices where this value belongs to[0,1], starting no earlier than max(0,numerator-shift). The common probability space and infinite-process interpretation remain declared premises, not constructions inferred from finitely many numbers. Keep exact reduced rational outputs with positive denominators, omitting /1 for integers. Use positive target delta=1/13. Give (numerator,shift,delta,minimal_nonnegative_N,bound_at_N,strict_tail?,forall_n_ge_N_tail_bound).","answer":{"kind":"expression","value":"(4, 5, 1/13, 48, 4/53, Yes, forall_n_ge_N_tail_bound)","explanation":"Solve the strict inequality c/(N+s)<delta with the least nonnegative integer N. The returned N must also belong to the valid probability domain. Increasing positive denominators then give the bound for every later index, conditionally on the declared deviation profile; no sampled prefix or infinite-process construction is substituted. The exact result, retaining the requested order, is (4, 5, 1/13, 48, 4/53, Yes, forall_n_ge_N_tail_bound)."},"skills":["A Strict Rational Tail Cutoff Is Different from a Finite Prefix"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0030","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"3dd8033f8550ea96b6f8b2041628d5ad097441c478bf5fd29282399793e10cd6","family_id":"qf-mod30-convprob-epsilon-witness","seed":202610307030,"semantic_template":"qf-mod30-convprob-epsilon-witness/{\"delta\":[1,14],\"numerator\":5,\"shift\":6}"},"fields":{"title":"A Strict Rational Tail Cutoff Is Different from a Finite Prefix","stem":"Use the declared rational deviation-probability tail p_n=5/(n+6) on nonnegative integer indices where this value belongs to[0,1], starting no earlier than max(0,numerator-shift). The common probability space and infinite-process interpretation remain declared premises, not constructions inferred from finitely many numbers. Keep exact reduced rational outputs with positive denominators, omitting /1 for integers. Use positive target delta=1/14. Give (numerator,shift,delta,minimal_nonnegative_N,bound_at_N,strict_tail?,forall_n_ge_N_tail_bound).","answer":{"kind":"expression","value":"(5, 6, 1/14, 65, 5/71, Yes, forall_n_ge_N_tail_bound)","explanation":"Solve the strict inequality c/(N+s)<delta with the least nonnegative integer N. The returned N must also belong to the valid probability domain. Increasing positive denominators then give the bound for every later index, conditionally on the declared deviation profile; no sampled prefix or infinite-process construction is substituted. The exact result, retaining the requested order, is (5, 6, 1/14, 65, 5/71, Yes, forall_n_ge_N_tail_bound)."},"skills":["A Strict Rational Tail Cutoff Is Different from a Finite Prefix"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0031","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"8751cd725bead8dedcdb05a6bd09c2e65f4f948c1d5d44d5546b21e073f54b19","family_id":"qf-mod30-convprob-epsilon-witness","seed":202610307031,"semantic_template":"qf-mod30-convprob-epsilon-witness/{\"delta\":[1,15],\"numerator\":1,\"shift\":7}"},"fields":{"title":"A Strict Rational Tail Cutoff Is Different from a Finite Prefix","stem":"Use the declared rational deviation-probability tail p_n=1/(n+7) on nonnegative integer indices where this value belongs to[0,1], starting no earlier than max(0,numerator-shift). The common probability space and infinite-process interpretation remain declared premises, not constructions inferred from finitely many numbers. Keep exact reduced rational outputs with positive denominators, omitting /1 for integers. Use positive target delta=1/15. Give (numerator,shift,delta,minimal_nonnegative_N,bound_at_N,strict_tail?,forall_n_ge_N_tail_bound).","answer":{"kind":"expression","value":"(1, 7, 1/15, 9, 1/16, Yes, forall_n_ge_N_tail_bound)","explanation":"Solve the strict inequality c/(N+s)<delta with the least nonnegative integer N. The returned N must also belong to the valid probability domain. Increasing positive denominators then give the bound for every later index, conditionally on the declared deviation profile; no sampled prefix or infinite-process construction is substituted. The exact result, retaining the requested order, is (1, 7, 1/15, 9, 1/16, Yes, forall_n_ge_N_tail_bound)."},"skills":["A Strict Rational Tail Cutoff Is Different from a Finite Prefix"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0032","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"62fc4467b05df02e8c5fbc842585a6313f4431eacdd677763aa48977cf375066","family_id":"qf-mod30-convprob-epsilon-witness","seed":202610307032,"semantic_template":"qf-mod30-convprob-epsilon-witness/{\"delta\":[1,16],\"numerator\":2,\"shift\":8}"},"fields":{"title":"A Strict Rational Tail Cutoff Is Different from a Finite Prefix","stem":"Use the declared rational deviation-probability tail p_n=2/(n+8) on nonnegative integer indices where this value belongs to[0,1], starting no earlier than max(0,numerator-shift). The common probability space and infinite-process interpretation remain declared premises, not constructions inferred from finitely many numbers. Keep exact reduced rational outputs with positive denominators, omitting /1 for integers. Use positive target delta=1/16. Give (numerator,shift,delta,minimal_nonnegative_N,bound_at_N,strict_tail?,forall_n_ge_N_tail_bound).","answer":{"kind":"expression","value":"(2, 8, 1/16, 25, 2/33, Yes, forall_n_ge_N_tail_bound)","explanation":"Solve the strict inequality c/(N+s)<delta with the least nonnegative integer N. The returned N must also belong to the valid probability domain. Increasing positive denominators then give the bound for every later index, conditionally on the declared deviation profile; no sampled prefix or infinite-process construction is substituted. The exact result, retaining the requested order, is (2, 8, 1/16, 25, 2/33, Yes, forall_n_ge_N_tail_bound)."},"skills":["A Strict Rational Tail Cutoff Is Different from a Finite Prefix"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0033","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"0de187493b4d741dffc48a689563c660b68779e97fadc72c89a1f59383863414","family_id":"qf-mod30-convprob-epsilon-witness","seed":202610307033,"semantic_template":"qf-mod30-convprob-epsilon-witness/{\"delta\":[1,17],\"numerator\":3,\"shift\":2}"},"fields":{"title":"A Strict Rational Tail Cutoff Is Different from a Finite Prefix","stem":"Use the declared rational deviation-probability tail p_n=3/(n+2) on nonnegative integer indices where this value belongs to[0,1], starting no earlier than max(0,numerator-shift). The common probability space and infinite-process interpretation remain declared premises, not constructions inferred from finitely many numbers. Keep exact reduced rational outputs with positive denominators, omitting /1 for integers. Use positive target delta=1/17. Give (numerator,shift,delta,minimal_nonnegative_N,bound_at_N,strict_tail?,forall_n_ge_N_tail_bound).","answer":{"kind":"expression","value":"(3, 2, 1/17, 50, 3/52, Yes, forall_n_ge_N_tail_bound)","explanation":"Solve the strict inequality c/(N+s)<delta with the least nonnegative integer N. The returned N must also belong to the valid probability domain. Increasing positive denominators then give the bound for every later index, conditionally on the declared deviation profile; no sampled prefix or infinite-process construction is substituted. The exact result, retaining the requested order, is (3, 2, 1/17, 50, 3/52, Yes, forall_n_ge_N_tail_bound)."},"skills":["A Strict Rational Tail Cutoff Is Different from a Finite Prefix"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0034","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"af783d1c1b62a08002c2d0573c73fbaf92499099556ecc5dea25783a67e2151e","family_id":"qf-mod30-convprob-epsilon-witness","seed":202610307034,"semantic_template":"qf-mod30-convprob-epsilon-witness/{\"delta\":[1,18],\"numerator\":4,\"shift\":3}"},"fields":{"title":"A Strict Rational Tail Cutoff Is Different from a Finite Prefix","stem":"Use the declared rational deviation-probability tail p_n=4/(n+3) on nonnegative integer indices where this value belongs to[0,1], starting no earlier than max(0,numerator-shift). The common probability space and infinite-process interpretation remain declared premises, not constructions inferred from finitely many numbers. Keep exact reduced rational outputs with positive denominators, omitting /1 for integers. Use positive target delta=1/18. Give (numerator,shift,delta,minimal_nonnegative_N,bound_at_N,strict_tail?,forall_n_ge_N_tail_bound).","answer":{"kind":"expression","value":"(4, 3, 1/18, 70, 4/73, Yes, forall_n_ge_N_tail_bound)","explanation":"Solve the strict inequality c/(N+s)<delta with the least nonnegative integer N. The returned N must also belong to the valid probability domain. Increasing positive denominators then give the bound for every later index, conditionally on the declared deviation profile; no sampled prefix or infinite-process construction is substituted. The exact result, retaining the requested order, is (4, 3, 1/18, 70, 4/73, Yes, forall_n_ge_N_tail_bound)."},"skills":["A Strict Rational Tail Cutoff Is Different from a Finite Prefix"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0035","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"7074a67e6d185ea86dc6ace6d6b87c479326ac2e80323b8e029ca4cf4b91bf94","family_id":"qf-mod30-convprob-epsilon-witness","seed":202610307035,"semantic_template":"qf-mod30-convprob-epsilon-witness/{\"delta\":[1,19],\"numerator\":5,\"shift\":4}"},"fields":{"title":"A Strict Rational Tail Cutoff Is Different from a Finite Prefix","stem":"Use the declared rational deviation-probability tail p_n=5/(n+4) on nonnegative integer indices where this value belongs to[0,1], starting no earlier than max(0,numerator-shift). The common probability space and infinite-process interpretation remain declared premises, not constructions inferred from finitely many numbers. Keep exact reduced rational outputs with positive denominators, omitting /1 for integers. Use positive target delta=1/19. Give (numerator,shift,delta,minimal_nonnegative_N,bound_at_N,strict_tail?,forall_n_ge_N_tail_bound).","answer":{"kind":"expression","value":"(5, 4, 1/19, 92, 5/96, Yes, forall_n_ge_N_tail_bound)","explanation":"Solve the strict inequality c/(N+s)<delta with the least nonnegative integer N. The returned N must also belong to the valid probability domain. Increasing positive denominators then give the bound for every later index, conditionally on the declared deviation profile; no sampled prefix or infinite-process construction is substituted. The exact result, retaining the requested order, is (5, 4, 1/19, 92, 5/96, Yes, forall_n_ge_N_tail_bound)."},"skills":["A Strict Rational Tail Cutoff Is Different from a Finite Prefix"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0036","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"6f67e463de5e32f3641e885843e7d681fa0a5e15a978c4b6f57b59cbaeebd72b","family_id":"qf-mod30-convprob-epsilon-witness","seed":202610307036,"semantic_template":"qf-mod30-convprob-epsilon-witness/{\"delta\":[1,20],\"numerator\":1,\"shift\":5}"},"fields":{"title":"A Strict Rational Tail Cutoff Is Different from a Finite Prefix","stem":"Use the declared rational deviation-probability tail p_n=1/(n+5) on nonnegative integer indices where this value belongs to[0,1], starting no earlier than max(0,numerator-shift). The common probability space and infinite-process interpretation remain declared premises, not constructions inferred from finitely many numbers. Keep exact reduced rational outputs with positive denominators, omitting /1 for integers. Use positive target delta=1/20. Give (numerator,shift,delta,minimal_nonnegative_N,bound_at_N,strict_tail?,forall_n_ge_N_tail_bound).","answer":{"kind":"expression","value":"(1, 5, 1/20, 16, 1/21, Yes, forall_n_ge_N_tail_bound)","explanation":"Solve the strict inequality c/(N+s)<delta with the least nonnegative integer N. The returned N must also belong to the valid probability domain. Increasing positive denominators then give the bound for every later index, conditionally on the declared deviation profile; no sampled prefix or infinite-process construction is substituted. The exact result, retaining the requested order, is (1, 5, 1/20, 16, 1/21, Yes, forall_n_ge_N_tail_bound)."},"skills":["A Strict Rational Tail Cutoff Is Different from a Finite Prefix"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0037","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"cfe5e303d608be464def3c69fc34f78970711a80fef3a401a847c497811e1f99","family_id":"qf-mod30-convprob-epsilon-witness","seed":202610307037,"semantic_template":"qf-mod30-convprob-epsilon-witness/{\"delta\":[1,21],\"numerator\":2,\"shift\":6}"},"fields":{"title":"A Strict Rational Tail Cutoff Is Different from a Finite Prefix","stem":"Use the declared rational deviation-probability tail p_n=2/(n+6) on nonnegative integer indices where this value belongs to[0,1], starting no earlier than max(0,numerator-shift). The common probability space and infinite-process interpretation remain declared premises, not constructions inferred from finitely many numbers. Keep exact reduced rational outputs with positive denominators, omitting /1 for integers. Use positive target delta=1/21. Give (numerator,shift,delta,minimal_nonnegative_N,bound_at_N,strict_tail?,forall_n_ge_N_tail_bound).","answer":{"kind":"expression","value":"(2, 6, 1/21, 37, 2/43, Yes, forall_n_ge_N_tail_bound)","explanation":"Solve the strict inequality c/(N+s)<delta with the least nonnegative integer N. The returned N must also belong to the valid probability domain. Increasing positive denominators then give the bound for every later index, conditionally on the declared deviation profile; no sampled prefix or infinite-process construction is substituted. The exact result, retaining the requested order, is (2, 6, 1/21, 37, 2/43, Yes, forall_n_ge_N_tail_bound)."},"skills":["A Strict Rational Tail Cutoff Is Different from a Finite Prefix"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0038","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"f7cd298e0de8862499a0c711d5e66c1b51711d3974d493c0fcb9d941539812ba","family_id":"qf-mod30-convprob-epsilon-witness","seed":202610307038,"semantic_template":"qf-mod30-convprob-epsilon-witness/{\"delta\":[1,22],\"numerator\":3,\"shift\":7}"},"fields":{"title":"A Strict Rational Tail Cutoff Is Different from a Finite Prefix","stem":"Use the declared rational deviation-probability tail p_n=3/(n+7) on nonnegative integer indices where this value belongs to[0,1], starting no earlier than max(0,numerator-shift). The common probability space and infinite-process interpretation remain declared premises, not constructions inferred from finitely many numbers. Keep exact reduced rational outputs with positive denominators, omitting /1 for integers. Use positive target delta=1/22. Give (numerator,shift,delta,minimal_nonnegative_N,bound_at_N,strict_tail?,forall_n_ge_N_tail_bound).","answer":{"kind":"expression","value":"(3, 7, 1/22, 60, 3/67, Yes, forall_n_ge_N_tail_bound)","explanation":"Solve the strict inequality c/(N+s)<delta with the least nonnegative integer N. The returned N must also belong to the valid probability domain. Increasing positive denominators then give the bound for every later index, conditionally on the declared deviation profile; no sampled prefix or infinite-process construction is substituted. The exact result, retaining the requested order, is (3, 7, 1/22, 60, 3/67, Yes, forall_n_ge_N_tail_bound)."},"skills":["A Strict Rational Tail Cutoff Is Different from a Finite Prefix"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0039","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"31107fbcee8e68e3dc4103b95b8be4095f941339ccfc64875c03076f00f8567d","family_id":"qf-mod30-convprob-epsilon-witness","seed":202610307039,"semantic_template":"qf-mod30-convprob-epsilon-witness/{\"delta\":[1,23],\"numerator\":4,\"shift\":8}"},"fields":{"title":"A Strict Rational Tail Cutoff Is Different from a Finite Prefix","stem":"Use the declared rational deviation-probability tail p_n=4/(n+8) on nonnegative integer indices where this value belongs to[0,1], starting no earlier than max(0,numerator-shift). The common probability space and infinite-process interpretation remain declared premises, not constructions inferred from finitely many numbers. Keep exact reduced rational outputs with positive denominators, omitting /1 for integers. Use positive target delta=1/23. Give (numerator,shift,delta,minimal_nonnegative_N,bound_at_N,strict_tail?,forall_n_ge_N_tail_bound).","answer":{"kind":"expression","value":"(4, 8, 1/23, 85, 4/93, Yes, forall_n_ge_N_tail_bound)","explanation":"Solve the strict inequality c/(N+s)<delta with the least nonnegative integer N. The returned N must also belong to the valid probability domain. Increasing positive denominators then give the bound for every later index, conditionally on the declared deviation profile; no sampled prefix or infinite-process construction is substituted. The exact result, retaining the requested order, is (4, 8, 1/23, 85, 4/93, Yes, forall_n_ge_N_tail_bound)."},"skills":["A Strict Rational Tail Cutoff Is Different from a Finite Prefix"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0040","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"e228e8c60eac3f310099abd69e96c20563af387dd013d753be3c40b0e4506772","family_id":"qf-mod30-convprob-epsilon-witness","seed":202610307040,"semantic_template":"qf-mod30-convprob-epsilon-witness/{\"delta\":[1,24],\"numerator\":5,\"shift\":2}"},"fields":{"title":"A Strict Rational Tail Cutoff Is Different from a Finite Prefix","stem":"Use the declared rational deviation-probability tail p_n=5/(n+2) on nonnegative integer indices where this value belongs to[0,1], starting no earlier than max(0,numerator-shift). The common probability space and infinite-process interpretation remain declared premises, not constructions inferred from finitely many numbers. Keep exact reduced rational outputs with positive denominators, omitting /1 for integers. Use positive target delta=1/24. Give (numerator,shift,delta,minimal_nonnegative_N,bound_at_N,strict_tail?,forall_n_ge_N_tail_bound).","answer":{"kind":"expression","value":"(5, 2, 1/24, 119, 5/121, Yes, forall_n_ge_N_tail_bound)","explanation":"Solve the strict inequality c/(N+s)<delta with the least nonnegative integer N. The returned N must also belong to the valid probability domain. Increasing positive denominators then give the bound for every later index, conditionally on the declared deviation profile; no sampled prefix or infinite-process construction is substituted. The exact result, retaining the requested order, is (5, 2, 1/24, 119, 5/121, Yes, forall_n_ge_N_tail_bound)."},"skills":["A Strict Rational Tail Cutoff Is Different from a Finite Prefix"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0041","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"8fc570f67834d3495c6e5339670042351c8f204f63ba8465f631f84a6221e83d","family_id":"qf-mod30-convprob-epsilon-witness","seed":202610307041,"semantic_template":"qf-mod30-convprob-epsilon-witness/{\"delta\":[1,25],\"numerator\":1,\"shift\":3}"},"fields":{"title":"A Strict Rational Tail Cutoff Is Different from a Finite Prefix","stem":"Use the declared rational deviation-probability tail p_n=1/(n+3) on nonnegative integer indices where this value belongs to[0,1], starting no earlier than max(0,numerator-shift). The common probability space and infinite-process interpretation remain declared premises, not constructions inferred from finitely many numbers. Keep exact reduced rational outputs with positive denominators, omitting /1 for integers. Use positive target delta=1/25. Give (numerator,shift,delta,minimal_nonnegative_N,bound_at_N,strict_tail?,forall_n_ge_N_tail_bound).","answer":{"kind":"expression","value":"(1, 3, 1/25, 23, 1/26, Yes, forall_n_ge_N_tail_bound)","explanation":"Solve the strict inequality c/(N+s)<delta with the least nonnegative integer N. The returned N must also belong to the valid probability domain. Increasing positive denominators then give the bound for every later index, conditionally on the declared deviation profile; no sampled prefix or infinite-process construction is substituted. The exact result, retaining the requested order, is (1, 3, 1/25, 23, 1/26, Yes, forall_n_ge_N_tail_bound)."},"skills":["A Strict Rational Tail Cutoff Is Different from a Finite Prefix"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0042","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"dc20c03ae7865138e6bb9cb2258f205ec17ab67de51c1c1bc9ce9dc215933d86","family_id":"qf-mod30-convprob-epsilon-witness","seed":202610307042,"semantic_template":"qf-mod30-convprob-epsilon-witness/{\"delta\":[1,26],\"numerator\":2,\"shift\":4}"},"fields":{"title":"A Strict Rational Tail Cutoff Is Different from a Finite Prefix","stem":"Use the declared rational deviation-probability tail p_n=2/(n+4) on nonnegative integer indices where this value belongs to[0,1], starting no earlier than max(0,numerator-shift). The common probability space and infinite-process interpretation remain declared premises, not constructions inferred from finitely many numbers. Keep exact reduced rational outputs with positive denominators, omitting /1 for integers. Use positive target delta=1/26. Give (numerator,shift,delta,minimal_nonnegative_N,bound_at_N,strict_tail?,forall_n_ge_N_tail_bound).","answer":{"kind":"expression","value":"(2, 4, 1/26, 49, 2/53, Yes, forall_n_ge_N_tail_bound)","explanation":"Solve the strict inequality c/(N+s)<delta with the least nonnegative integer N. The returned N must also belong to the valid probability domain. Increasing positive denominators then give the bound for every later index, conditionally on the declared deviation profile; no sampled prefix or infinite-process construction is substituted. The exact result, retaining the requested order, is (2, 4, 1/26, 49, 2/53, Yes, forall_n_ge_N_tail_bound)."},"skills":["A Strict Rational Tail Cutoff Is Different from a Finite Prefix"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0043","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"24d67cb60c530ff0ac09080906f7ce971441610720de617371a0774302ccbe62","family_id":"qf-mod30-convprob-epsilon-witness","seed":202610307043,"semantic_template":"qf-mod30-convprob-epsilon-witness/{\"delta\":[1,27],\"numerator\":3,\"shift\":5}"},"fields":{"title":"A Strict Rational Tail Cutoff Is Different from a Finite Prefix","stem":"Use the declared rational deviation-probability tail p_n=3/(n+5) on nonnegative integer indices where this value belongs to[0,1], starting no earlier than max(0,numerator-shift). The common probability space and infinite-process interpretation remain declared premises, not constructions inferred from finitely many numbers. Keep exact reduced rational outputs with positive denominators, omitting /1 for integers. Use positive target delta=1/27. Give (numerator,shift,delta,minimal_nonnegative_N,bound_at_N,strict_tail?,forall_n_ge_N_tail_bound).","answer":{"kind":"expression","value":"(3, 5, 1/27, 77, 3/82, Yes, forall_n_ge_N_tail_bound)","explanation":"Solve the strict inequality c/(N+s)<delta with the least nonnegative integer N. The returned N must also belong to the valid probability domain. Increasing positive denominators then give the bound for every later index, conditionally on the declared deviation profile; no sampled prefix or infinite-process construction is substituted. The exact result, retaining the requested order, is (3, 5, 1/27, 77, 3/82, Yes, forall_n_ge_N_tail_bound)."},"skills":["A Strict Rational Tail Cutoff Is Different from a Finite Prefix"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0044","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"cb4dad13a82b91c458c74eea7e29003bb275a1e03df79d39d7d77e17a1387471","family_id":"qf-mod30-convprob-epsilon-witness","seed":202610307044,"semantic_template":"qf-mod30-convprob-epsilon-witness/{\"delta\":[1,28],\"numerator\":4,\"shift\":6}"},"fields":{"title":"A Strict Rational Tail Cutoff Is Different from a Finite Prefix","stem":"Use the declared rational deviation-probability tail p_n=4/(n+6) on nonnegative integer indices where this value belongs to[0,1], starting no earlier than max(0,numerator-shift). The common probability space and infinite-process interpretation remain declared premises, not constructions inferred from finitely many numbers. Keep exact reduced rational outputs with positive denominators, omitting /1 for integers. Use positive target delta=1/28. Give (numerator,shift,delta,minimal_nonnegative_N,bound_at_N,strict_tail?,forall_n_ge_N_tail_bound).","answer":{"kind":"expression","value":"(4, 6, 1/28, 107, 4/113, Yes, forall_n_ge_N_tail_bound)","explanation":"Solve the strict inequality c/(N+s)<delta with the least nonnegative integer N. The returned N must also belong to the valid probability domain. Increasing positive denominators then give the bound for every later index, conditionally on the declared deviation profile; no sampled prefix or infinite-process construction is substituted. The exact result, retaining the requested order, is (4, 6, 1/28, 107, 4/113, Yes, forall_n_ge_N_tail_bound)."},"skills":["A Strict Rational Tail Cutoff Is Different from a Finite Prefix"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0045","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"4cf39f5c01cced0431ec4f9063aba8603cbe0315ea569f809d56cdaac6b72327","family_id":"qf-mod30-convprob-epsilon-witness","seed":202610307045,"semantic_template":"qf-mod30-convprob-epsilon-witness/{\"delta\":[1,29],\"numerator\":5,\"shift\":7}"},"fields":{"title":"A Strict Rational Tail Cutoff Is Different from a Finite Prefix","stem":"Use the declared rational deviation-probability tail p_n=5/(n+7) on nonnegative integer indices where this value belongs to[0,1], starting no earlier than max(0,numerator-shift). The common probability space and infinite-process interpretation remain declared premises, not constructions inferred from finitely many numbers. Keep exact reduced rational outputs with positive denominators, omitting /1 for integers. Use positive target delta=1/29. Give (numerator,shift,delta,minimal_nonnegative_N,bound_at_N,strict_tail?,forall_n_ge_N_tail_bound).","answer":{"kind":"expression","value":"(5, 7, 1/29, 139, 5/146, Yes, forall_n_ge_N_tail_bound)","explanation":"Solve the strict inequality c/(N+s)<delta with the least nonnegative integer N. The returned N must also belong to the valid probability domain. Increasing positive denominators then give the bound for every later index, conditionally on the declared deviation profile; no sampled prefix or infinite-process construction is substituted. The exact result, retaining the requested order, is (5, 7, 1/29, 139, 5/146, Yes, forall_n_ge_N_tail_bound)."},"skills":["A Strict Rational Tail Cutoff Is Different from a Finite Prefix"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0046","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"7a6d495b3711992c1a352e0ffc37f0f2a310623ab5ec6100c62777b656f38717","family_id":"qf-mod30-convprob-epsilon-witness","seed":202610307046,"semantic_template":"qf-mod30-convprob-epsilon-witness/{\"delta\":[1,30],\"numerator\":1,\"shift\":8}"},"fields":{"title":"A Strict Rational Tail Cutoff Is Different from a Finite Prefix","stem":"Use the declared rational deviation-probability tail p_n=1/(n+8) on nonnegative integer indices where this value belongs to[0,1], starting no earlier than max(0,numerator-shift). The common probability space and infinite-process interpretation remain declared premises, not constructions inferred from finitely many numbers. Keep exact reduced rational outputs with positive denominators, omitting /1 for integers. Use positive target delta=1/30. Give (numerator,shift,delta,minimal_nonnegative_N,bound_at_N,strict_tail?,forall_n_ge_N_tail_bound).","answer":{"kind":"expression","value":"(1, 8, 1/30, 23, 1/31, Yes, forall_n_ge_N_tail_bound)","explanation":"Solve the strict inequality c/(N+s)<delta with the least nonnegative integer N. The returned N must also belong to the valid probability domain. Increasing positive denominators then give the bound for every later index, conditionally on the declared deviation profile; no sampled prefix or infinite-process construction is substituted. The exact result, retaining the requested order, is (1, 8, 1/30, 23, 1/31, Yes, forall_n_ge_N_tail_bound)."},"skills":["A Strict Rational Tail Cutoff Is Different from a Finite Prefix"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0047","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"62aaae6d800439067d598fbc9a86fe439cafe95c66cf78f55d5bb6ebee0d1a96","family_id":"qf-mod30-convprob-epsilon-witness","seed":202610307047,"semantic_template":"qf-mod30-convprob-epsilon-witness/{\"delta\":[1,31],\"numerator\":2,\"shift\":2}"},"fields":{"title":"A Strict Rational Tail Cutoff Is Different from a Finite Prefix","stem":"Use the declared rational deviation-probability tail p_n=2/(n+2) on nonnegative integer indices where this value belongs to[0,1], starting no earlier than max(0,numerator-shift). The common probability space and infinite-process interpretation remain declared premises, not constructions inferred from finitely many numbers. Keep exact reduced rational outputs with positive denominators, omitting /1 for integers. Use positive target delta=1/31. Give (numerator,shift,delta,minimal_nonnegative_N,bound_at_N,strict_tail?,forall_n_ge_N_tail_bound).","answer":{"kind":"expression","value":"(2, 2, 1/31, 61, 2/63, Yes, forall_n_ge_N_tail_bound)","explanation":"Solve the strict inequality c/(N+s)<delta with the least nonnegative integer N. The returned N must also belong to the valid probability domain. Increasing positive denominators then give the bound for every later index, conditionally on the declared deviation profile; no sampled prefix or infinite-process construction is substituted. The exact result, retaining the requested order, is (2, 2, 1/31, 61, 2/63, Yes, forall_n_ge_N_tail_bound)."},"skills":["A Strict Rational Tail Cutoff Is Different from a Finite Prefix"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0048","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"052cce1860c14ff5b0b70f52c1c3b9113c7b3441744098509fefcdd138043442","family_id":"qf-mod30-convprob-epsilon-witness","seed":202610307048,"semantic_template":"qf-mod30-convprob-epsilon-witness/{\"delta\":[1,32],\"numerator\":3,\"shift\":3}"},"fields":{"title":"A Strict Rational Tail Cutoff Is Different from a Finite Prefix","stem":"Use the declared rational deviation-probability tail p_n=3/(n+3) on nonnegative integer indices where this value belongs to[0,1], starting no earlier than max(0,numerator-shift). The common probability space and infinite-process interpretation remain declared premises, not constructions inferred from finitely many numbers. Keep exact reduced rational outputs with positive denominators, omitting /1 for integers. Use positive target delta=1/32. Give (numerator,shift,delta,minimal_nonnegative_N,bound_at_N,strict_tail?,forall_n_ge_N_tail_bound).","answer":{"kind":"expression","value":"(3, 3, 1/32, 94, 3/97, Yes, forall_n_ge_N_tail_bound)","explanation":"Solve the strict inequality c/(N+s)<delta with the least nonnegative integer N. The returned N must also belong to the valid probability domain. Increasing positive denominators then give the bound for every later index, conditionally on the declared deviation profile; no sampled prefix or infinite-process construction is substituted. The exact result, retaining the requested order, is (3, 3, 1/32, 94, 3/97, Yes, forall_n_ge_N_tail_bound)."},"skills":["A Strict Rational Tail Cutoff Is Different from a Finite Prefix"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0049","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"75b6343fb9350ad759554dfc905e2dde148d2a661b4d309ca6efcfd452b458ad","family_id":"qf-mod30-convprob-epsilon-witness","seed":202610307049,"semantic_template":"qf-mod30-convprob-epsilon-witness/{\"delta\":[1,33],\"numerator\":4,\"shift\":4}"},"fields":{"title":"A Strict Rational Tail Cutoff Is Different from a Finite Prefix","stem":"Use the declared rational deviation-probability tail p_n=4/(n+4) on nonnegative integer indices where this value belongs to[0,1], starting no earlier than max(0,numerator-shift). The common probability space and infinite-process interpretation remain declared premises, not constructions inferred from finitely many numbers. Keep exact reduced rational outputs with positive denominators, omitting /1 for integers. Use positive target delta=1/33. Give (numerator,shift,delta,minimal_nonnegative_N,bound_at_N,strict_tail?,forall_n_ge_N_tail_bound).","answer":{"kind":"expression","value":"(4, 4, 1/33, 129, 4/133, Yes, forall_n_ge_N_tail_bound)","explanation":"Solve the strict inequality c/(N+s)<delta with the least nonnegative integer N. The returned N must also belong to the valid probability domain. Increasing positive denominators then give the bound for every later index, conditionally on the declared deviation profile; no sampled prefix or infinite-process construction is substituted. The exact result, retaining the requested order, is (4, 4, 1/33, 129, 4/133, Yes, forall_n_ge_N_tail_bound)."},"skills":["A Strict Rational Tail Cutoff Is Different from a Finite Prefix"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0050","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"37a2eb671b9c16a4ad16447ef3bd3fb161960a2b5d2a4a2b10e2f07aa70d0511","family_id":"qf-mod30-convprob-epsilon-witness","seed":202610307050,"semantic_template":"qf-mod30-convprob-epsilon-witness/{\"delta\":[1,34],\"numerator\":5,\"shift\":5}"},"fields":{"title":"A Strict Rational Tail Cutoff Is Different from a Finite Prefix","stem":"Use the declared rational deviation-probability tail p_n=5/(n+5) on nonnegative integer indices where this value belongs to[0,1], starting no earlier than max(0,numerator-shift). The common probability space and infinite-process interpretation remain declared premises, not constructions inferred from finitely many numbers. Keep exact reduced rational outputs with positive denominators, omitting /1 for integers. Use positive target delta=1/34. Give (numerator,shift,delta,minimal_nonnegative_N,bound_at_N,strict_tail?,forall_n_ge_N_tail_bound).","answer":{"kind":"expression","value":"(5, 5, 1/34, 166, 5/171, Yes, forall_n_ge_N_tail_bound)","explanation":"Solve the strict inequality c/(N+s)<delta with the least nonnegative integer N. The returned N must also belong to the valid probability domain. Increasing positive denominators then give the bound for every later index, conditionally on the declared deviation profile; no sampled prefix or infinite-process construction is substituted. The exact result, retaining the requested order, is (5, 5, 1/34, 166, 5/171, Yes, forall_n_ge_N_tail_bound)."},"skills":["A Strict Rational Tail Cutoff Is Different from a Finite Prefix"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0051","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"cd2c6727ede0ee9bc93c03fb16ae6a4c5ccb644e91340fa2f203758513b2dc6b","family_id":"qf-mod30-convprob-finite-prefix-boundary","seed":202610307051,"semantic_template":"qf-mod30-convprob-finite-prefix-boundary/{\"numerator\":1,\"prefix_length\":1,\"shift\":2}"},"fields":{"title":"A Valid Zero-Indexed Probability Prefix Is Still Not a Convergence Certificate","stem":"Use only the explicitly supplied finite list p_n=1/(n+2) for n=0 through prefix_length-1, with prefix_length=1. Every listed entry must be in [0,1]. The formula describes these finitely specified entries only: no continuation beyond this finite prefix, infinite-process construction or full forall-epsilon tail premise is supplied. Keep exact reduced rational outputs with positive denominators, omitting /1 for integers. Give (numerator,shift,prefix_length,probability_values,sufficient?,finite_prefix_not_convergence_certificate).","answer":{"kind":"expression","value":"(1, 2, 1, [1/2], No, finite_prefix_not_convergence_certificate)","explanation":"List c/(n+s) for every integer0 through prefix_length-1 in order, without clipping or dropping an invalid leading value. The sufficiency flag is No: finitely many correct decreasing values alone do not establish the universal tail obligation. The exact result, retaining the requested order, is (1, 2, 1, [1/2], No, finite_prefix_not_convergence_certificate)."},"skills":["A Valid Zero-Indexed Probability Prefix Is Still Not a Convergence Certificate"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0052","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"3be2cbad947ad76df34df02edab2d27de27abc4f2a3486491d7407f0c31eb009","family_id":"qf-mod30-convprob-finite-prefix-boundary","seed":202610307052,"semantic_template":"qf-mod30-convprob-finite-prefix-boundary/{\"numerator\":2,\"prefix_length\":2,\"shift\":3}"},"fields":{"title":"A Valid Zero-Indexed Probability Prefix Is Still Not a Convergence Certificate","stem":"Use only the explicitly supplied finite list p_n=2/(n+3) for n=0 through prefix_length-1, with prefix_length=2. Every listed entry must be in [0,1]. The formula describes these finitely specified entries only: no continuation beyond this finite prefix, infinite-process construction or full forall-epsilon tail premise is supplied. Keep exact reduced rational outputs with positive denominators, omitting /1 for integers. Give (numerator,shift,prefix_length,probability_values,sufficient?,finite_prefix_not_convergence_certificate).","answer":{"kind":"expression","value":"(2, 3, 2, [2/3, 1/2], No, finite_prefix_not_convergence_certificate)","explanation":"List c/(n+s) for every integer0 through prefix_length-1 in order, without clipping or dropping an invalid leading value. The sufficiency flag is No: finitely many correct decreasing values alone do not establish the universal tail obligation. The exact result, retaining the requested order, is (2, 3, 2, [2/3, 1/2], No, finite_prefix_not_convergence_certificate)."},"skills":["A Valid Zero-Indexed Probability Prefix Is Still Not a Convergence Certificate"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0053","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"2158f875dd9989e4efc8e7a4b58261754cab0e96424f93adbb163934958c9fc3","family_id":"qf-mod30-convprob-finite-prefix-boundary","seed":202610307053,"semantic_template":"qf-mod30-convprob-finite-prefix-boundary/{\"numerator\":3,\"prefix_length\":3,\"shift\":4}"},"fields":{"title":"A Valid Zero-Indexed Probability Prefix Is Still Not a Convergence Certificate","stem":"Use only the explicitly supplied finite list p_n=3/(n+4) for n=0 through prefix_length-1, with prefix_length=3. Every listed entry must be in [0,1]. The formula describes these finitely specified entries only: no continuation beyond this finite prefix, infinite-process construction or full forall-epsilon tail premise is supplied. Keep exact reduced rational outputs with positive denominators, omitting /1 for integers. Give (numerator,shift,prefix_length,probability_values,sufficient?,finite_prefix_not_convergence_certificate).","answer":{"kind":"expression","value":"(3, 4, 3, [3/4, 3/5, 1/2], No, finite_prefix_not_convergence_certificate)","explanation":"List c/(n+s) for every integer0 through prefix_length-1 in order, without clipping or dropping an invalid leading value. The sufficiency flag is No: finitely many correct decreasing values alone do not establish the universal tail obligation. The exact result, retaining the requested order, is (3, 4, 3, [3/4, 3/5, 1/2], No, finite_prefix_not_convergence_certificate)."},"skills":["A Valid Zero-Indexed Probability Prefix Is Still Not a Convergence Certificate"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0054","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"ff1bcbf53fd51d4d2ebdca2c0048bee168abe2ec6d9ecc9d86556d37591d57cf","family_id":"qf-mod30-convprob-finite-prefix-boundary","seed":202610307054,"semantic_template":"qf-mod30-convprob-finite-prefix-boundary/{\"numerator\":4,\"prefix_length\":4,\"shift\":5}"},"fields":{"title":"A Valid Zero-Indexed Probability Prefix Is Still Not a Convergence Certificate","stem":"Use only the explicitly supplied finite list p_n=4/(n+5) for n=0 through prefix_length-1, with prefix_length=4. Every listed entry must be in [0,1]. The formula describes these finitely specified entries only: no continuation beyond this finite prefix, infinite-process construction or full forall-epsilon tail premise is supplied. Keep exact reduced rational outputs with positive denominators, omitting /1 for integers. Give (numerator,shift,prefix_length,probability_values,sufficient?,finite_prefix_not_convergence_certificate).","answer":{"kind":"expression","value":"(4, 5, 4, [4/5, 2/3, 4/7, 1/2], No, finite_prefix_not_convergence_certificate)","explanation":"List c/(n+s) for every integer0 through prefix_length-1 in order, without clipping or dropping an invalid leading value. The sufficiency flag is No: finitely many correct decreasing values alone do not establish the universal tail obligation. The exact result, retaining the requested order, is (4, 5, 4, [4/5, 2/3, 4/7, 1/2], No, finite_prefix_not_convergence_certificate)."},"skills":["A Valid Zero-Indexed Probability Prefix Is Still Not a Convergence Certificate"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0055","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"170fb96ecb8e94ccbfbd82a92d33a20e574d59b79fcceef308001e1940ab33d2","family_id":"qf-mod30-convprob-finite-prefix-boundary","seed":202610307055,"semantic_template":"qf-mod30-convprob-finite-prefix-boundary/{\"numerator\":5,\"prefix_length\":5,\"shift\":6}"},"fields":{"title":"A Valid Zero-Indexed Probability Prefix Is Still Not a Convergence Certificate","stem":"Use only the explicitly supplied finite list p_n=5/(n+6) for n=0 through prefix_length-1, with prefix_length=5. Every listed entry must be in [0,1]. The formula describes these finitely specified entries only: no continuation beyond this finite prefix, infinite-process construction or full forall-epsilon tail premise is supplied. Keep exact reduced rational outputs with positive denominators, omitting /1 for integers. Give (numerator,shift,prefix_length,probability_values,sufficient?,finite_prefix_not_convergence_certificate).","answer":{"kind":"expression","value":"(5, 6, 5, [5/6, 5/7, 5/8, 5/9, 1/2], No, finite_prefix_not_convergence_certificate)","explanation":"List c/(n+s) for every integer0 through prefix_length-1 in order, without clipping or dropping an invalid leading value. The sufficiency flag is No: finitely many correct decreasing values alone do not establish the universal tail obligation. The exact result, retaining the requested order, is (5, 6, 5, [5/6, 5/7, 5/8, 5/9, 1/2], No, finite_prefix_not_convergence_certificate)."},"skills":["A Valid Zero-Indexed Probability Prefix Is Still Not a Convergence Certificate"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0056","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"e23ef78a7c78b13472e6c4b61e9f2feb45e46d66a7b5027e115563512c6a0a5e","family_id":"qf-mod30-convprob-finite-prefix-boundary","seed":202610307056,"semantic_template":"qf-mod30-convprob-finite-prefix-boundary/{\"numerator\":1,\"prefix_length\":6,\"shift\":7}"},"fields":{"title":"A Valid Zero-Indexed Probability Prefix Is Still Not a Convergence Certificate","stem":"Use only the explicitly supplied finite list p_n=1/(n+7) for n=0 through prefix_length-1, with prefix_length=6. Every listed entry must be in [0,1]. The formula describes these finitely specified entries only: no continuation beyond this finite prefix, infinite-process construction or full forall-epsilon tail premise is supplied. Keep exact reduced rational outputs with positive denominators, omitting /1 for integers. Give (numerator,shift,prefix_length,probability_values,sufficient?,finite_prefix_not_convergence_certificate).","answer":{"kind":"expression","value":"(1, 7, 6, [1/7, 1/8, 1/9, 1/10, 1/11, 1/12], No, finite_prefix_not_convergence_certificate)","explanation":"List c/(n+s) for every integer0 through prefix_length-1 in order, without clipping or dropping an invalid leading value. The sufficiency flag is No: finitely many correct decreasing values alone do not establish the universal tail obligation. The exact result, retaining the requested order, is (1, 7, 6, [1/7, 1/8, 1/9, 1/10, 1/11, 1/12], No, finite_prefix_not_convergence_certificate)."},"skills":["A Valid Zero-Indexed Probability Prefix Is Still Not a Convergence Certificate"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0057","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"95203d9a00ace8605a6cfe61fb1e0082ce45234598ef45906697af0194afcde7","family_id":"qf-mod30-convprob-finite-prefix-boundary","seed":202610307057,"semantic_template":"qf-mod30-convprob-finite-prefix-boundary/{\"numerator\":2,\"prefix_length\":7,\"shift\":8}"},"fields":{"title":"A Valid Zero-Indexed Probability Prefix Is Still Not a Convergence Certificate","stem":"Use only the explicitly supplied finite list p_n=2/(n+8) for n=0 through prefix_length-1, with prefix_length=7. Every listed entry must be in [0,1]. The formula describes these finitely specified entries only: no continuation beyond this finite prefix, infinite-process construction or full forall-epsilon tail premise is supplied. Keep exact reduced rational outputs with positive denominators, omitting /1 for integers. Give (numerator,shift,prefix_length,probability_values,sufficient?,finite_prefix_not_convergence_certificate).","answer":{"kind":"expression","value":"(2, 8, 7, [1/4, 2/9, 1/5, 2/11, 1/6, 2/13, 1/7], No, finite_prefix_not_convergence_certificate)","explanation":"List c/(n+s) for every integer0 through prefix_length-1 in order, without clipping or dropping an invalid leading value. The sufficiency flag is No: finitely many correct decreasing values alone do not establish the universal tail obligation. The exact result, retaining the requested order, is (2, 8, 7, [1/4, 2/9, 1/5, 2/11, 1/6, 2/13, 1/7], No, finite_prefix_not_convergence_certificate)."},"skills":["A Valid Zero-Indexed Probability Prefix Is Still Not a Convergence Certificate"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0058","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"95fe3ea6509392cb7e723573fafcbf4d5f8bd530022eeafd4179849b83f01a83","family_id":"qf-mod30-convprob-finite-prefix-boundary","seed":202610307058,"semantic_template":"qf-mod30-convprob-finite-prefix-boundary/{\"numerator\":3,\"prefix_length\":8,\"shift\":3}"},"fields":{"title":"A Valid Zero-Indexed Probability Prefix Is Still Not a Convergence Certificate","stem":"Use only the explicitly supplied finite list p_n=3/(n+3) for n=0 through prefix_length-1, with prefix_length=8. Every listed entry must be in [0,1]. The formula describes these finitely specified entries only: no continuation beyond this finite prefix, infinite-process construction or full forall-epsilon tail premise is supplied. Keep exact reduced rational outputs with positive denominators, omitting /1 for integers. Give (numerator,shift,prefix_length,probability_values,sufficient?,finite_prefix_not_convergence_certificate).","answer":{"kind":"expression","value":"(3, 3, 8, [1, 3/4, 3/5, 1/2, 3/7, 3/8, 1/3, 3/10], No, finite_prefix_not_convergence_certificate)","explanation":"List c/(n+s) for every integer0 through prefix_length-1 in order, without clipping or dropping an invalid leading value. The sufficiency flag is No: finitely many correct decreasing values alone do not establish the universal tail obligation. The exact result, retaining the requested order, is (3, 3, 8, [1, 3/4, 3/5, 1/2, 3/7, 3/8, 1/3, 3/10], No, finite_prefix_not_convergence_certificate)."},"skills":["A Valid Zero-Indexed Probability Prefix Is Still Not a Convergence Certificate"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0059","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"7d24afbda475d8c446e7630cda8de0abd683b6ceeffb1888b506d9632f73191e","family_id":"qf-mod30-convprob-finite-prefix-boundary","seed":202610307059,"semantic_template":"qf-mod30-convprob-finite-prefix-boundary/{\"numerator\":4,\"prefix_length\":9,\"shift\":4}"},"fields":{"title":"A Valid Zero-Indexed Probability Prefix Is Still Not a Convergence Certificate","stem":"Use only the explicitly supplied finite list p_n=4/(n+4) for n=0 through prefix_length-1, with prefix_length=9. Every listed entry must be in [0,1]. The formula describes these finitely specified entries only: no continuation beyond this finite prefix, infinite-process construction or full forall-epsilon tail premise is supplied. Keep exact reduced rational outputs with positive denominators, omitting /1 for integers. Give (numerator,shift,prefix_length,probability_values,sufficient?,finite_prefix_not_convergence_certificate).","answer":{"kind":"expression","value":"(4, 4, 9, [1, 4/5, 2/3, 4/7, 1/2, 4/9, 2/5, 4/11, 1/3], No, finite_prefix_not_convergence_certificate)","explanation":"List c/(n+s) for every integer0 through prefix_length-1 in order, without clipping or dropping an invalid leading value. The sufficiency flag is No: finitely many correct decreasing values alone do not establish the universal tail obligation. The exact result, retaining the requested order, is (4, 4, 9, [1, 4/5, 2/3, 4/7, 1/2, 4/9, 2/5, 4/11, 1/3], No, finite_prefix_not_convergence_certificate)."},"skills":["A Valid Zero-Indexed Probability Prefix Is Still Not a Convergence Certificate"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0060","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"7f205126b7ba16de72e197d830e16fdff325de676cc60a543947a74b56537e90","family_id":"qf-mod30-convprob-finite-prefix-boundary","seed":202610307060,"semantic_template":"qf-mod30-convprob-finite-prefix-boundary/{\"numerator\":5,\"prefix_length\":10,\"shift\":5}"},"fields":{"title":"A Valid Zero-Indexed Probability Prefix Is Still Not a Convergence Certificate","stem":"Use only the explicitly supplied finite list p_n=5/(n+5) for n=0 through prefix_length-1, with prefix_length=10. Every listed entry must be in [0,1]. The formula describes these finitely specified entries only: no continuation beyond this finite prefix, infinite-process construction or full forall-epsilon tail premise is supplied. Keep exact reduced rational outputs with positive denominators, omitting /1 for integers. Give (numerator,shift,prefix_length,probability_values,sufficient?,finite_prefix_not_convergence_certificate).","answer":{"kind":"expression","value":"(5, 5, 10, [1, 5/6, 5/7, 5/8, 5/9, 1/2, 5/11, 5/12, 5/13, 5/14], No, finite_prefix_not_convergence_certificate)","explanation":"List c/(n+s) for every integer0 through prefix_length-1 in order, without clipping or dropping an invalid leading value. The sufficiency flag is No: finitely many correct decreasing values alone do not establish the universal tail obligation. The exact result, retaining the requested order, is (5, 5, 10, [1, 5/6, 5/7, 5/8, 5/9, 1/2, 5/11, 5/12, 5/13, 5/14], No, finite_prefix_not_convergence_certificate)."},"skills":["A Valid Zero-Indexed Probability Prefix Is Still Not a Convergence Certificate"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0061","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"443106cc36d3972f630969fb71fbedb4b774b45e8f60ef7fbc9aebff44aac5d4","family_id":"qf-mod30-convprob-finite-prefix-boundary","seed":202610307061,"semantic_template":"qf-mod30-convprob-finite-prefix-boundary/{\"numerator\":1,\"prefix_length\":11,\"shift\":5}"},"fields":{"title":"A Valid Zero-Indexed Probability Prefix Is Still Not a Convergence Certificate","stem":"Use only the explicitly supplied finite list p_n=1/(n+5) for n=0 through prefix_length-1, with prefix_length=11. Every listed entry must be in [0,1]. The formula describes these finitely specified entries only: no continuation beyond this finite prefix, infinite-process construction or full forall-epsilon tail premise is supplied. Keep exact reduced rational outputs with positive denominators, omitting /1 for integers. Give (numerator,shift,prefix_length,probability_values,sufficient?,finite_prefix_not_convergence_certificate).","answer":{"kind":"expression","value":"(1, 5, 11, [1/5, 1/6, 1/7, 1/8, 1/9, 1/10, 1/11, 1/12, 1/13, 1/14, 1/15], No, finite_prefix_not_convergence_certificate)","explanation":"List c/(n+s) for every integer0 through prefix_length-1 in order, without clipping or dropping an invalid leading value. The sufficiency flag is No: finitely many correct decreasing values alone do not establish the universal tail obligation. The exact result, retaining the requested order, is (1, 5, 11, [1/5, 1/6, 1/7, 1/8, 1/9, 1/10, 1/11, 1/12, 1/13, 1/14, 1/15], No, finite_prefix_not_convergence_certificate)."},"skills":["A Valid Zero-Indexed Probability Prefix Is Still Not a Convergence Certificate"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0062","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"acd44acb7818a7b8234541920ae03041fc19e7c13b7534e4c15f707f83b7b864","family_id":"qf-mod30-convprob-finite-prefix-boundary","seed":202610307062,"semantic_template":"qf-mod30-convprob-finite-prefix-boundary/{\"numerator\":2,\"prefix_length\":12,\"shift\":6}"},"fields":{"title":"A Valid Zero-Indexed Probability Prefix Is Still Not a Convergence Certificate","stem":"Use only the explicitly supplied finite list p_n=2/(n+6) for n=0 through prefix_length-1, with prefix_length=12. Every listed entry must be in [0,1]. The formula describes these finitely specified entries only: no continuation beyond this finite prefix, infinite-process construction or full forall-epsilon tail premise is supplied. Keep exact reduced rational outputs with positive denominators, omitting /1 for integers. Give (numerator,shift,prefix_length,probability_values,sufficient?,finite_prefix_not_convergence_certificate).","answer":{"kind":"expression","value":"(2, 6, 12, [1/3, 2/7, 1/4, 2/9, 1/5, 2/11, 1/6, 2/13, 1/7, 2/15, 1/8, 2/17], No, finite_prefix_not_convergence_certificate)","explanation":"List c/(n+s) for every integer0 through prefix_length-1 in order, without clipping or dropping an invalid leading value. The sufficiency flag is No: finitely many correct decreasing values alone do not establish the universal tail obligation. The exact result, retaining the requested order, is (2, 6, 12, [1/3, 2/7, 1/4, 2/9, 1/5, 2/11, 1/6, 2/13, 1/7, 2/15, 1/8, 2/17], No, finite_prefix_not_convergence_certificate)."},"skills":["A Valid Zero-Indexed Probability Prefix Is Still Not a Convergence Certificate"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0063","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"de438882ce98d750e197b0ce0584f20e787f84542b87d7342a6e4e469041102b","family_id":"qf-mod30-convprob-finite-prefix-boundary","seed":202610307063,"semantic_template":"qf-mod30-convprob-finite-prefix-boundary/{\"numerator\":3,\"prefix_length\":13,\"shift\":7}"},"fields":{"title":"A Valid Zero-Indexed Probability Prefix Is Still Not a Convergence Certificate","stem":"Use only the explicitly supplied finite list p_n=3/(n+7) for n=0 through prefix_length-1, with prefix_length=13. Every listed entry must be in [0,1]. The formula describes these finitely specified entries only: no continuation beyond this finite prefix, infinite-process construction or full forall-epsilon tail premise is supplied. Keep exact reduced rational outputs with positive denominators, omitting /1 for integers. Give (numerator,shift,prefix_length,probability_values,sufficient?,finite_prefix_not_convergence_certificate).","answer":{"kind":"expression","value":"(3, 7, 13, [3/7, 3/8, 1/3, 3/10, 3/11, 1/4, 3/13, 3/14, 1/5, 3/16, 3/17, 1/6, 3/19], No, finite_prefix_not_convergence_certificate)","explanation":"List c/(n+s) for every integer0 through prefix_length-1 in order, without clipping or dropping an invalid leading value. The sufficiency flag is No: finitely many correct decreasing values alone do not establish the universal tail obligation. The exact result, retaining the requested order, is (3, 7, 13, [3/7, 3/8, 1/3, 3/10, 3/11, 1/4, 3/13, 3/14, 1/5, 3/16, 3/17, 1/6, 3/19], No, finite_prefix_not_convergence_certificate)."},"skills":["A Valid Zero-Indexed Probability Prefix Is Still Not a Convergence Certificate"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0064","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"514808df2c0725145439a10badba92c162aa2b831838c2f8dcdde51cf3c8acb6","family_id":"qf-mod30-convprob-finite-prefix-boundary","seed":202610307064,"semantic_template":"qf-mod30-convprob-finite-prefix-boundary/{\"numerator\":4,\"prefix_length\":14,\"shift\":8}"},"fields":{"title":"A Valid Zero-Indexed Probability Prefix Is Still Not a Convergence Certificate","stem":"Use only the explicitly supplied finite list p_n=4/(n+8) for n=0 through prefix_length-1, with prefix_length=14. Every listed entry must be in [0,1]. The formula describes these finitely specified entries only: no continuation beyond this finite prefix, infinite-process construction or full forall-epsilon tail premise is supplied. Keep exact reduced rational outputs with positive denominators, omitting /1 for integers. Give (numerator,shift,prefix_length,probability_values,sufficient?,finite_prefix_not_convergence_certificate).","answer":{"kind":"expression","value":"(4, 8, 14, [1/2, 4/9, 2/5, 4/11, 1/3, 4/13, 2/7, 4/15, 1/4, 4/17, 2/9, 4/19, 1/5, 4/21], No, finite_prefix_not_convergence_certificate)","explanation":"List c/(n+s) for every integer0 through prefix_length-1 in order, without clipping or dropping an invalid leading value. The sufficiency flag is No: finitely many correct decreasing values alone do not establish the universal tail obligation. The exact result, retaining the requested order, is (4, 8, 14, [1/2, 4/9, 2/5, 4/11, 1/3, 4/13, 2/7, 4/15, 1/4, 4/17, 2/9, 4/19, 1/5, 4/21], No, finite_prefix_not_convergence_certificate)."},"skills":["A Valid Zero-Indexed Probability Prefix Is Still Not a Convergence Certificate"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0065","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"ae142f30467de6e83a406de6ba79f33ea315cd408305ca0d9b0ab05c776804e5","family_id":"qf-mod30-convprob-finite-prefix-boundary","seed":202610307065,"semantic_template":"qf-mod30-convprob-finite-prefix-boundary/{\"numerator\":5,\"prefix_length\":15,\"shift\":5}"},"fields":{"title":"A Valid Zero-Indexed Probability Prefix Is Still Not a Convergence Certificate","stem":"Use only the explicitly supplied finite list p_n=5/(n+5) for n=0 through prefix_length-1, with prefix_length=15. Every listed entry must be in [0,1]. The formula describes these finitely specified entries only: no continuation beyond this finite prefix, infinite-process construction or full forall-epsilon tail premise is supplied. Keep exact reduced rational outputs with positive denominators, omitting /1 for integers. Give (numerator,shift,prefix_length,probability_values,sufficient?,finite_prefix_not_convergence_certificate).","answer":{"kind":"expression","value":"(5, 5, 15, [1, 5/6, 5/7, 5/8, 5/9, 1/2, 5/11, 5/12, 5/13, 5/14, 1/3, 5/16, 5/17, 5/18, 5/19], No, finite_prefix_not_convergence_certificate)","explanation":"List c/(n+s) for every integer0 through prefix_length-1 in order, without clipping or dropping an invalid leading value. The sufficiency flag is No: finitely many correct decreasing values alone do not establish the universal tail obligation. The exact result, retaining the requested order, is (5, 5, 15, [1, 5/6, 5/7, 5/8, 5/9, 1/2, 5/11, 5/12, 5/13, 5/14, 1/3, 5/16, 5/17, 5/18, 5/19], No, finite_prefix_not_convergence_certificate)."},"skills":["A Valid Zero-Indexed Probability Prefix Is Still Not a Convergence Certificate"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0066","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"921021c9ba4ebbc9453e56963b0ad66460cafa846968924079572f95fc0f5660","family_id":"qf-mod30-convprob-finite-prefix-boundary","seed":202610307066,"semantic_template":"qf-mod30-convprob-finite-prefix-boundary/{\"numerator\":1,\"prefix_length\":16,\"shift\":3}"},"fields":{"title":"A Valid Zero-Indexed Probability Prefix Is Still Not a Convergence Certificate","stem":"Use only the explicitly supplied finite list p_n=1/(n+3) for n=0 through prefix_length-1, with prefix_length=16. Every listed entry must be in [0,1]. The formula describes these finitely specified entries only: no continuation beyond this finite prefix, infinite-process construction or full forall-epsilon tail premise is supplied. Keep exact reduced rational outputs with positive denominators, omitting /1 for integers. Give (numerator,shift,prefix_length,probability_values,sufficient?,finite_prefix_not_convergence_certificate).","answer":{"kind":"expression","value":"(1, 3, 16, [1/3, 1/4, 1/5, 1/6, 1/7, 1/8, 1/9, 1/10, 1/11, 1/12, 1/13, 1/14, 1/15, 1/16, 1/17, 1/18], No, finite_prefix_not_convergence_certificate)","explanation":"List c/(n+s) for every integer0 through prefix_length-1 in order, without clipping or dropping an invalid leading value. The sufficiency flag is No: finitely many correct decreasing values alone do not establish the universal tail obligation. The exact result, retaining the requested order, is (1, 3, 16, [1/3, 1/4, 1/5, 1/6, 1/7, 1/8, 1/9, 1/10, 1/11, 1/12, 1/13, 1/14, 1/15, 1/16, 1/17, 1/18], No, finite_prefix_not_convergence_certificate)."},"skills":["A Valid Zero-Indexed Probability Prefix Is Still Not a Convergence Certificate"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0067","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"a62e54d5854a131d8fb9c4cbdc696a4b00c84b5fedc43dcfcfb2dd0eccd42784","family_id":"qf-mod30-convprob-finite-prefix-boundary","seed":202610307067,"semantic_template":"qf-mod30-convprob-finite-prefix-boundary/{\"numerator\":2,\"prefix_length\":17,\"shift\":4}"},"fields":{"title":"A Valid Zero-Indexed Probability Prefix Is Still Not a Convergence Certificate","stem":"Use only the explicitly supplied finite list p_n=2/(n+4) for n=0 through prefix_length-1, with prefix_length=17. Every listed entry must be in [0,1]. The formula describes these finitely specified entries only: no continuation beyond this finite prefix, infinite-process construction or full forall-epsilon tail premise is supplied. Keep exact reduced rational outputs with positive denominators, omitting /1 for integers. Give (numerator,shift,prefix_length,probability_values,sufficient?,finite_prefix_not_convergence_certificate).","answer":{"kind":"expression","value":"(2, 4, 17, [1/2, 2/5, 1/3, 2/7, 1/4, 2/9, 1/5, 2/11, 1/6, 2/13, 1/7, 2/15, 1/8, 2/17, 1/9, 2/19, 1/10], No, finite_prefix_not_convergence_certificate)","explanation":"List c/(n+s) for every integer0 through prefix_length-1 in order, without clipping or dropping an invalid leading value. The sufficiency flag is No: finitely many correct decreasing values alone do not establish the universal tail obligation. The exact result, retaining the requested order, is (2, 4, 17, [1/2, 2/5, 1/3, 2/7, 1/4, 2/9, 1/5, 2/11, 1/6, 2/13, 1/7, 2/15, 1/8, 2/17, 1/9, 2/19, 1/10], No, finite_prefix_not_convergence_certificate)."},"skills":["A Valid Zero-Indexed Probability Prefix Is Still Not a Convergence Certificate"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0068","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"35afd96064116c9a05370a51aa14ca5985eb1655e2b1ee96a93594c009d919e7","family_id":"qf-mod30-convprob-finite-prefix-boundary","seed":202610307068,"semantic_template":"qf-mod30-convprob-finite-prefix-boundary/{\"numerator\":3,\"prefix_length\":18,\"shift\":5}"},"fields":{"title":"A Valid Zero-Indexed Probability Prefix Is Still Not a Convergence Certificate","stem":"Use only the explicitly supplied finite list p_n=3/(n+5) for n=0 through prefix_length-1, with prefix_length=18. Every listed entry must be in [0,1]. The formula describes these finitely specified entries only: no continuation beyond this finite prefix, infinite-process construction or full forall-epsilon tail premise is supplied. Keep exact reduced rational outputs with positive denominators, omitting /1 for integers. Give (numerator,shift,prefix_length,probability_values,sufficient?,finite_prefix_not_convergence_certificate).","answer":{"kind":"expression","value":"(3, 5, 18, [3/5, 1/2, 3/7, 3/8, 1/3, 3/10, 3/11, 1/4, 3/13, 3/14, 1/5, 3/16, 3/17, 1/6, 3/19, 3/20, 1/7, 3/22], No, finite_prefix_not_convergence_certificate)","explanation":"List c/(n+s) for every integer0 through prefix_length-1 in order, without clipping or dropping an invalid leading value. The sufficiency flag is No: finitely many correct decreasing values alone do not establish the universal tail obligation. The exact result, retaining the requested order, is (3, 5, 18, [3/5, 1/2, 3/7, 3/8, 1/3, 3/10, 3/11, 1/4, 3/13, 3/14, 1/5, 3/16, 3/17, 1/6, 3/19, 3/20, 1/7, 3/22], No, finite_prefix_not_convergence_certificate)."},"skills":["A Valid Zero-Indexed Probability Prefix Is Still Not a Convergence Certificate"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0069","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"eb4ea764cd54da38747c41c897d3cee7de51a7608aefd8ad5cd5a7ca487ec866","family_id":"qf-mod30-convprob-finite-prefix-boundary","seed":202610307069,"semantic_template":"qf-mod30-convprob-finite-prefix-boundary/{\"numerator\":4,\"prefix_length\":19,\"shift\":6}"},"fields":{"title":"A Valid Zero-Indexed Probability Prefix Is Still Not a Convergence Certificate","stem":"Use only the explicitly supplied finite list p_n=4/(n+6) for n=0 through prefix_length-1, with prefix_length=19. Every listed entry must be in [0,1]. The formula describes these finitely specified entries only: no continuation beyond this finite prefix, infinite-process construction or full forall-epsilon tail premise is supplied. Keep exact reduced rational outputs with positive denominators, omitting /1 for integers. Give (numerator,shift,prefix_length,probability_values,sufficient?,finite_prefix_not_convergence_certificate).","answer":{"kind":"expression","value":"(4, 6, 19, [2/3, 4/7, 1/2, 4/9, 2/5, 4/11, 1/3, 4/13, 2/7, 4/15, 1/4, 4/17, 2/9, 4/19, 1/5, 4/21, 2/11, 4/23, 1/6], No, finite_prefix_not_convergence_certificate)","explanation":"List c/(n+s) for every integer0 through prefix_length-1 in order, without clipping or dropping an invalid leading value. The sufficiency flag is No: finitely many correct decreasing values alone do not establish the universal tail obligation. The exact result, retaining the requested order, is (4, 6, 19, [2/3, 4/7, 1/2, 4/9, 2/5, 4/11, 1/3, 4/13, 2/7, 4/15, 1/4, 4/17, 2/9, 4/19, 1/5, 4/21, 2/11, 4/23, 1/6], No, finite_prefix_not_convergence_certificate)."},"skills":["A Valid Zero-Indexed Probability Prefix Is Still Not a Convergence Certificate"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0070","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"e4ce6fe0379427ed45cf4c0f0b9bbf14557c62c69978a9dfb519748f8b287005","family_id":"qf-mod30-convprob-finite-prefix-boundary","seed":202610307070,"semantic_template":"qf-mod30-convprob-finite-prefix-boundary/{\"numerator\":5,\"prefix_length\":20,\"shift\":7}"},"fields":{"title":"A Valid Zero-Indexed Probability Prefix Is Still Not a Convergence Certificate","stem":"Use only the explicitly supplied finite list p_n=5/(n+7) for n=0 through prefix_length-1, with prefix_length=20. Every listed entry must be in [0,1]. The formula describes these finitely specified entries only: no continuation beyond this finite prefix, infinite-process construction or full forall-epsilon tail premise is supplied. Keep exact reduced rational outputs with positive denominators, omitting /1 for integers. Give (numerator,shift,prefix_length,probability_values,sufficient?,finite_prefix_not_convergence_certificate).","answer":{"kind":"expression","value":"(5, 7, 20, [5/7, 5/8, 5/9, 1/2, 5/11, 5/12, 5/13, 5/14, 1/3, 5/16, 5/17, 5/18, 5/19, 1/4, 5/21, 5/22, 5/23, 5/24, 1/5, 5/26], No, finite_prefix_not_convergence_certificate)","explanation":"List c/(n+s) for every integer0 through prefix_length-1 in order, without clipping or dropping an invalid leading value. The sufficiency flag is No: finitely many correct decreasing values alone do not establish the universal tail obligation. The exact result, retaining the requested order, is (5, 7, 20, [5/7, 5/8, 5/9, 1/2, 5/11, 5/12, 5/13, 5/14, 1/3, 5/16, 5/17, 5/18, 5/19, 1/4, 5/21, 5/22, 5/23, 5/24, 1/5, 5/26], No, finite_prefix_not_convergence_certificate)."},"skills":["A Valid Zero-Indexed Probability Prefix Is Still Not a Convergence Certificate"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0071","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"8817de706d3ca95904acb8f2ab1c09e4f4e92b70ce961fa79367f03637cb31a9","family_id":"qf-mod30-convprob-finite-prefix-boundary","seed":202610307071,"semantic_template":"qf-mod30-convprob-finite-prefix-boundary/{\"numerator\":1,\"prefix_length\":21,\"shift\":8}"},"fields":{"title":"A Valid Zero-Indexed Probability Prefix Is Still Not a Convergence Certificate","stem":"Use only the explicitly supplied finite list p_n=1/(n+8) for n=0 through prefix_length-1, with prefix_length=21. Every listed entry must be in [0,1]. The formula describes these finitely specified entries only: no continuation beyond this finite prefix, infinite-process construction or full forall-epsilon tail premise is supplied. Keep exact reduced rational outputs with positive denominators, omitting /1 for integers. Give (numerator,shift,prefix_length,probability_values,sufficient?,finite_prefix_not_convergence_certificate).","answer":{"kind":"expression","value":"(1, 8, 21, [1/8, 1/9, 1/10, 1/11, 1/12, 1/13, 1/14, 1/15, 1/16, 1/17, 1/18, 1/19, 1/20, 1/21, 1/22, 1/23, 1/24, 1/25, 1/26, 1/27, 1/28], No, finite_prefix_not_convergence_certificate)","explanation":"List c/(n+s) for every integer0 through prefix_length-1 in order, without clipping or dropping an invalid leading value. The sufficiency flag is No: finitely many correct decreasing values alone do not establish the universal tail obligation. The exact result, retaining the requested order, is (1, 8, 21, [1/8, 1/9, 1/10, 1/11, 1/12, 1/13, 1/14, 1/15, 1/16, 1/17, 1/18, 1/19, 1/20, 1/21, 1/22, 1/23, 1/24, 1/25, 1/26, 1/27, 1/28], No, finite_prefix_not_convergence_certificate)."},"skills":["A Valid Zero-Indexed Probability Prefix Is Still Not a Convergence Certificate"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0072","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"2298687545e5cd111ab3c41e1b91ea4c372211d386838e1ee5da59e870c1282f","family_id":"qf-mod30-convprob-finite-prefix-boundary","seed":202610307072,"semantic_template":"qf-mod30-convprob-finite-prefix-boundary/{\"numerator\":2,\"prefix_length\":22,\"shift\":2}"},"fields":{"title":"A Valid Zero-Indexed Probability Prefix Is Still Not a Convergence Certificate","stem":"Use only the explicitly supplied finite list p_n=2/(n+2) for n=0 through prefix_length-1, with prefix_length=22. Every listed entry must be in [0,1]. The formula describes these finitely specified entries only: no continuation beyond this finite prefix, infinite-process construction or full forall-epsilon tail premise is supplied. Keep exact reduced rational outputs with positive denominators, omitting /1 for integers. Give (numerator,shift,prefix_length,probability_values,sufficient?,finite_prefix_not_convergence_certificate).","answer":{"kind":"expression","value":"(2, 2, 22, [1, 2/3, 1/2, 2/5, 1/3, 2/7, 1/4, 2/9, 1/5, 2/11, 1/6, 2/13, 1/7, 2/15, 1/8, 2/17, 1/9, 2/19, 1/10, 2/21, 1/11, 2/23], No, finite_prefix_not_convergence_certificate)","explanation":"List c/(n+s) for every integer0 through prefix_length-1 in order, without clipping or dropping an invalid leading value. The sufficiency flag is No: finitely many correct decreasing values alone do not establish the universal tail obligation. The exact result, retaining the requested order, is (2, 2, 22, [1, 2/3, 1/2, 2/5, 1/3, 2/7, 1/4, 2/9, 1/5, 2/11, 1/6, 2/13, 1/7, 2/15, 1/8, 2/17, 1/9, 2/19, 1/10, 2/21, 1/11, 2/23], No, finite_prefix_not_convergence_certificate)."},"skills":["A Valid Zero-Indexed Probability Prefix Is Still Not a Convergence Certificate"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0073","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"f4501fe7e2fb9a162e836e647bc0679ce351944efb3a8b1792162f45a8cf1de9","family_id":"qf-mod30-convprob-finite-prefix-boundary","seed":202610307073,"semantic_template":"qf-mod30-convprob-finite-prefix-boundary/{\"numerator\":3,\"prefix_length\":23,\"shift\":3}"},"fields":{"title":"A Valid Zero-Indexed Probability Prefix Is Still Not a Convergence Certificate","stem":"Use only the explicitly supplied finite list p_n=3/(n+3) for n=0 through prefix_length-1, with prefix_length=23. Every listed entry must be in [0,1]. The formula describes these finitely specified entries only: no continuation beyond this finite prefix, infinite-process construction or full forall-epsilon tail premise is supplied. Keep exact reduced rational outputs with positive denominators, omitting /1 for integers. Give (numerator,shift,prefix_length,probability_values,sufficient?,finite_prefix_not_convergence_certificate).","answer":{"kind":"expression","value":"(3, 3, 23, [1, 3/4, 3/5, 1/2, 3/7, 3/8, 1/3, 3/10, 3/11, 1/4, 3/13, 3/14, 1/5, 3/16, 3/17, 1/6, 3/19, 3/20, 1/7, 3/22, 3/23, 1/8, 3/25], No, finite_prefix_not_convergence_certificate)","explanation":"List c/(n+s) for every integer0 through prefix_length-1 in order, without clipping or dropping an invalid leading value. The sufficiency flag is No: finitely many correct decreasing values alone do not establish the universal tail obligation. The exact result, retaining the requested order, is (3, 3, 23, [1, 3/4, 3/5, 1/2, 3/7, 3/8, 1/3, 3/10, 3/11, 1/4, 3/13, 3/14, 1/5, 3/16, 3/17, 1/6, 3/19, 3/20, 1/7, 3/22, 3/23, 1/8, 3/25], No, finite_prefix_not_convergence_certificate)."},"skills":["A Valid Zero-Indexed Probability Prefix Is Still Not a Convergence Certificate"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0074","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"126fc2a645675373b0562691d7f24929e8dfa47a85da5c839abcd8d497adeb39","family_id":"qf-mod30-convprob-finite-prefix-boundary","seed":202610307074,"semantic_template":"qf-mod30-convprob-finite-prefix-boundary/{\"numerator\":4,\"prefix_length\":24,\"shift\":4}"},"fields":{"title":"A Valid Zero-Indexed Probability Prefix Is Still Not a Convergence Certificate","stem":"Use only the explicitly supplied finite list p_n=4/(n+4) for n=0 through prefix_length-1, with prefix_length=24. Every listed entry must be in [0,1]. The formula describes these finitely specified entries only: no continuation beyond this finite prefix, infinite-process construction or full forall-epsilon tail premise is supplied. Keep exact reduced rational outputs with positive denominators, omitting /1 for integers. Give (numerator,shift,prefix_length,probability_values,sufficient?,finite_prefix_not_convergence_certificate).","answer":{"kind":"expression","value":"(4, 4, 24, [1, 4/5, 2/3, 4/7, 1/2, 4/9, 2/5, 4/11, 1/3, 4/13, 2/7, 4/15, 1/4, 4/17, 2/9, 4/19, 1/5, 4/21, 2/11, 4/23, 1/6, 4/25, 2/13, 4/27], No, finite_prefix_not_convergence_certificate)","explanation":"List c/(n+s) for every integer0 through prefix_length-1 in order, without clipping or dropping an invalid leading value. The sufficiency flag is No: finitely many correct decreasing values alone do not establish the universal tail obligation. The exact result, retaining the requested order, is (4, 4, 24, [1, 4/5, 2/3, 4/7, 1/2, 4/9, 2/5, 4/11, 1/3, 4/13, 2/7, 4/15, 1/4, 4/17, 2/9, 4/19, 1/5, 4/21, 2/11, 4/23, 1/6, 4/25, 2/13, 4/27], No, finite_prefix_not_convergence_certificate)."},"skills":["A Valid Zero-Indexed Probability Prefix Is Still Not a Convergence Certificate"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0075","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"6647616680f8d3771babf880f347bbfa521c0cc7388d1390a4955b43521f0630","family_id":"qf-mod30-convprob-finite-prefix-boundary","seed":202610307075,"semantic_template":"qf-mod30-convprob-finite-prefix-boundary/{\"numerator\":5,\"prefix_length\":25,\"shift\":5}"},"fields":{"title":"A Valid Zero-Indexed Probability Prefix Is Still Not a Convergence Certificate","stem":"Use only the explicitly supplied finite list p_n=5/(n+5) for n=0 through prefix_length-1, with prefix_length=25. Every listed entry must be in [0,1]. The formula describes these finitely specified entries only: no continuation beyond this finite prefix, infinite-process construction or full forall-epsilon tail premise is supplied. Keep exact reduced rational outputs with positive denominators, omitting /1 for integers. Give (numerator,shift,prefix_length,probability_values,sufficient?,finite_prefix_not_convergence_certificate).","answer":{"kind":"expression","value":"(5, 5, 25, [1, 5/6, 5/7, 5/8, 5/9, 1/2, 5/11, 5/12, 5/13, 5/14, 1/3, 5/16, 5/17, 5/18, 5/19, 1/4, 5/21, 5/22, 5/23, 5/24, 1/5, 5/26, 5/27, 5/28, 5/29], No, finite_prefix_not_convergence_certificate)","explanation":"List c/(n+s) for every integer0 through prefix_length-1 in order, without clipping or dropping an invalid leading value. The sufficiency flag is No: finitely many correct decreasing values alone do not establish the universal tail obligation. The exact result, retaining the requested order, is (5, 5, 25, [1, 5/6, 5/7, 5/8, 5/9, 1/2, 5/11, 5/12, 5/13, 5/14, 1/3, 5/16, 5/17, 5/18, 5/19, 1/4, 5/21, 5/22, 5/23, 5/24, 1/5, 5/26, 5/27, 5/28, 5/29], No, finite_prefix_not_convergence_certificate)."},"skills":["A Valid Zero-Indexed Probability Prefix Is Still Not a Convergence Certificate"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0076","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"0a0b38a493b27503b4bd824ac8b0a299f061d9df81c4638ee2dbee0bc3dc8c31","family_id":"qf-mod30-convprob-eventual-equality","seed":202610307076,"semantic_template":"qf-mod30-convprob-eventual-equality/{\"n\":0,\"settling_index\":1}"},"fields":{"title":"Eventual Equality Supplies a Conditional Universal-Tail Certificate","stem":"On the declared common probability space assume X_n=X almost surely for every n≥settling_index=1; inspect n=0. Give (settling_index,n,zero_probability_status,certificate?,eventual_equality_universal_tail_certificate).","answer":{"kind":"expression","value":"(1, 0, not_yet_zero, Yes, eventual_equality_universal_tail_certificate)","explanation":"At or beyond the settling index the deviation probability is0 for every positive epsilon. Earlier not_yet_zero means this certificate has not yet supplied a zero value; it does not independently establish a positive deviation probability. The final Yes is the conditional eventual-equality tail certificate, not a proof from this single inspected index. The exact result, retaining the requested order, is (1, 0, not_yet_zero, Yes, eventual_equality_universal_tail_certificate)."},"skills":["Eventual Equality Supplies a Conditional Universal-Tail Certificate"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0077","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"a33876dac0ba6b573c98c09b2da1fd838b79a6a09f50c920dfb217c45c09b4e2","family_id":"qf-mod30-convprob-eventual-equality","seed":202610307077,"semantic_template":"qf-mod30-convprob-eventual-equality/{\"n\":1,\"settling_index\":2}"},"fields":{"title":"Eventual Equality Supplies a Conditional Universal-Tail Certificate","stem":"On the declared common probability space assume X_n=X almost surely for every n≥settling_index=2; inspect n=1. Give (settling_index,n,zero_probability_status,certificate?,eventual_equality_universal_tail_certificate).","answer":{"kind":"expression","value":"(2, 1, not_yet_zero, Yes, eventual_equality_universal_tail_certificate)","explanation":"At or beyond the settling index the deviation probability is0 for every positive epsilon. Earlier not_yet_zero means this certificate has not yet supplied a zero value; it does not independently establish a positive deviation probability. The final Yes is the conditional eventual-equality tail certificate, not a proof from this single inspected index. The exact result, retaining the requested order, is (2, 1, not_yet_zero, Yes, eventual_equality_universal_tail_certificate)."},"skills":["Eventual Equality Supplies a Conditional Universal-Tail Certificate"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0078","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"e5d9104c2e9696fc4e3c0ca84a297c780e079ffe3e24d19ec948a6c7c6e3a171","family_id":"qf-mod30-convprob-eventual-equality","seed":202610307078,"semantic_template":"qf-mod30-convprob-eventual-equality/{\"n\":2,\"settling_index\":3}"},"fields":{"title":"Eventual Equality Supplies a Conditional Universal-Tail Certificate","stem":"On the declared common probability space assume X_n=X almost surely for every n≥settling_index=3; inspect n=2. Give (settling_index,n,zero_probability_status,certificate?,eventual_equality_universal_tail_certificate).","answer":{"kind":"expression","value":"(3, 2, not_yet_zero, Yes, eventual_equality_universal_tail_certificate)","explanation":"At or beyond the settling index the deviation probability is0 for every positive epsilon. Earlier not_yet_zero means this certificate has not yet supplied a zero value; it does not independently establish a positive deviation probability. The final Yes is the conditional eventual-equality tail certificate, not a proof from this single inspected index. The exact result, retaining the requested order, is (3, 2, not_yet_zero, Yes, eventual_equality_universal_tail_certificate)."},"skills":["Eventual Equality Supplies a Conditional Universal-Tail Certificate"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0079","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"9700366a38e1fb0f7433d1a57f481be0f7090cc928e4f07366c1c2937149b155","family_id":"qf-mod30-convprob-eventual-equality","seed":202610307079,"semantic_template":"qf-mod30-convprob-eventual-equality/{\"n\":4,\"settling_index\":4}"},"fields":{"title":"Eventual Equality Supplies a Conditional Universal-Tail Certificate","stem":"On the declared common probability space assume X_n=X almost surely for every n≥settling_index=4; inspect n=4. Give (settling_index,n,zero_probability_status,certificate?,eventual_equality_universal_tail_certificate).","answer":{"kind":"expression","value":"(4, 4, 0, Yes, eventual_equality_universal_tail_certificate)","explanation":"At or beyond the settling index the deviation probability is0 for every positive epsilon. Earlier not_yet_zero means this certificate has not yet supplied a zero value; it does not independently establish a positive deviation probability. The final Yes is the conditional eventual-equality tail certificate, not a proof from this single inspected index. The exact result, retaining the requested order, is (4, 4, 0, Yes, eventual_equality_universal_tail_certificate)."},"skills":["Eventual Equality Supplies a Conditional Universal-Tail Certificate"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0080","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"13082904fa8fd251d8be95645f6a48f6e413af7724ab8aab0dd3002ec5d31906","family_id":"qf-mod30-convprob-eventual-equality","seed":202610307080,"semantic_template":"qf-mod30-convprob-eventual-equality/{\"n\":5,\"settling_index\":5}"},"fields":{"title":"Eventual Equality Supplies a Conditional Universal-Tail Certificate","stem":"On the declared common probability space assume X_n=X almost surely for every n≥settling_index=5; inspect n=5. Give (settling_index,n,zero_probability_status,certificate?,eventual_equality_universal_tail_certificate).","answer":{"kind":"expression","value":"(5, 5, 0, Yes, eventual_equality_universal_tail_certificate)","explanation":"At or beyond the settling index the deviation probability is0 for every positive epsilon. Earlier not_yet_zero means this certificate has not yet supplied a zero value; it does not independently establish a positive deviation probability. The final Yes is the conditional eventual-equality tail certificate, not a proof from this single inspected index. The exact result, retaining the requested order, is (5, 5, 0, Yes, eventual_equality_universal_tail_certificate)."},"skills":["Eventual Equality Supplies a Conditional Universal-Tail Certificate"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0081","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"ab5f3d6911513367b37cea43235958c7e27ee8ab85d0527224204020a1137936","family_id":"qf-mod30-convprob-eventual-equality","seed":202610307081,"semantic_template":"qf-mod30-convprob-eventual-equality/{\"n\":6,\"settling_index\":6}"},"fields":{"title":"Eventual Equality Supplies a Conditional Universal-Tail Certificate","stem":"On the declared common probability space assume X_n=X almost surely for every n≥settling_index=6; inspect n=6. Give (settling_index,n,zero_probability_status,certificate?,eventual_equality_universal_tail_certificate).","answer":{"kind":"expression","value":"(6, 6, 0, Yes, eventual_equality_universal_tail_certificate)","explanation":"At or beyond the settling index the deviation probability is0 for every positive epsilon. Earlier not_yet_zero means this certificate has not yet supplied a zero value; it does not independently establish a positive deviation probability. The final Yes is the conditional eventual-equality tail certificate, not a proof from this single inspected index. The exact result, retaining the requested order, is (6, 6, 0, Yes, eventual_equality_universal_tail_certificate)."},"skills":["Eventual Equality Supplies a Conditional Universal-Tail Certificate"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0082","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"30dbf8f608e22cad8ef1c6384f1cf58c304ef9b1860d2e8ccc59dec78a70b798","family_id":"qf-mod30-convprob-eventual-equality","seed":202610307082,"semantic_template":"qf-mod30-convprob-eventual-equality/{\"n\":8,\"settling_index\":7}"},"fields":{"title":"Eventual Equality Supplies a Conditional Universal-Tail Certificate","stem":"On the declared common probability space assume X_n=X almost surely for every n≥settling_index=7; inspect n=8. Give (settling_index,n,zero_probability_status,certificate?,eventual_equality_universal_tail_certificate).","answer":{"kind":"expression","value":"(7, 8, 0, Yes, eventual_equality_universal_tail_certificate)","explanation":"At or beyond the settling index the deviation probability is0 for every positive epsilon. Earlier not_yet_zero means this certificate has not yet supplied a zero value; it does not independently establish a positive deviation probability. The final Yes is the conditional eventual-equality tail certificate, not a proof from this single inspected index. The exact result, retaining the requested order, is (7, 8, 0, Yes, eventual_equality_universal_tail_certificate)."},"skills":["Eventual Equality Supplies a Conditional Universal-Tail Certificate"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0083","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"d94af7c659fa427e76e6f423a8a8582331c7503bb714e0e2d6e9a1391f54f200","family_id":"qf-mod30-convprob-eventual-equality","seed":202610307083,"semantic_template":"qf-mod30-convprob-eventual-equality/{\"n\":9,\"settling_index\":8}"},"fields":{"title":"Eventual Equality Supplies a Conditional Universal-Tail Certificate","stem":"On the declared common probability space assume X_n=X almost surely for every n≥settling_index=8; inspect n=9. Give (settling_index,n,zero_probability_status,certificate?,eventual_equality_universal_tail_certificate).","answer":{"kind":"expression","value":"(8, 9, 0, Yes, eventual_equality_universal_tail_certificate)","explanation":"At or beyond the settling index the deviation probability is0 for every positive epsilon. Earlier not_yet_zero means this certificate has not yet supplied a zero value; it does not independently establish a positive deviation probability. The final Yes is the conditional eventual-equality tail certificate, not a proof from this single inspected index. The exact result, retaining the requested order, is (8, 9, 0, Yes, eventual_equality_universal_tail_certificate)."},"skills":["Eventual Equality Supplies a Conditional Universal-Tail Certificate"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0084","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"a2289bce65373c569551a1e181a078daf767a9778ed63fdf378b531ed25e6fae","family_id":"qf-mod30-convprob-eventual-equality","seed":202610307084,"semantic_template":"qf-mod30-convprob-eventual-equality/{\"n\":10,\"settling_index\":9}"},"fields":{"title":"Eventual Equality Supplies a Conditional Universal-Tail Certificate","stem":"On the declared common probability space assume X_n=X almost surely for every n≥settling_index=9; inspect n=10. Give (settling_index,n,zero_probability_status,certificate?,eventual_equality_universal_tail_certificate).","answer":{"kind":"expression","value":"(9, 10, 0, Yes, eventual_equality_universal_tail_certificate)","explanation":"At or beyond the settling index the deviation probability is0 for every positive epsilon. Earlier not_yet_zero means this certificate has not yet supplied a zero value; it does not independently establish a positive deviation probability. The final Yes is the conditional eventual-equality tail certificate, not a proof from this single inspected index. The exact result, retaining the requested order, is (9, 10, 0, Yes, eventual_equality_universal_tail_certificate)."},"skills":["Eventual Equality Supplies a Conditional Universal-Tail Certificate"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0085","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"a5cc1c49ac35aa6e701f6b55d756dd5abb990296a59602292c8761686aeb299b","family_id":"qf-mod30-convprob-eventual-equality","seed":202610307085,"semantic_template":"qf-mod30-convprob-eventual-equality/{\"n\":12,\"settling_index\":10}"},"fields":{"title":"Eventual Equality Supplies a Conditional Universal-Tail Certificate","stem":"On the declared common probability space assume X_n=X almost surely for every n≥settling_index=10; inspect n=12. Give (settling_index,n,zero_probability_status,certificate?,eventual_equality_universal_tail_certificate).","answer":{"kind":"expression","value":"(10, 12, 0, Yes, eventual_equality_universal_tail_certificate)","explanation":"At or beyond the settling index the deviation probability is0 for every positive epsilon. Earlier not_yet_zero means this certificate has not yet supplied a zero value; it does not independently establish a positive deviation probability. The final Yes is the conditional eventual-equality tail certificate, not a proof from this single inspected index. The exact result, retaining the requested order, is (10, 12, 0, Yes, eventual_equality_universal_tail_certificate)."},"skills":["Eventual Equality Supplies a Conditional Universal-Tail Certificate"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0086","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"8a18b241830f42b409152436e72527d8e91b5b058fb611a97b3b7b80cc74c7c1","family_id":"qf-mod30-convprob-eventual-equality","seed":202610307086,"semantic_template":"qf-mod30-convprob-eventual-equality/{\"n\":13,\"settling_index\":11}"},"fields":{"title":"Eventual Equality Supplies a Conditional Universal-Tail Certificate","stem":"On the declared common probability space assume X_n=X almost surely for every n≥settling_index=11; inspect n=13. Give (settling_index,n,zero_probability_status,certificate?,eventual_equality_universal_tail_certificate).","answer":{"kind":"expression","value":"(11, 13, 0, Yes, eventual_equality_universal_tail_certificate)","explanation":"At or beyond the settling index the deviation probability is0 for every positive epsilon. Earlier not_yet_zero means this certificate has not yet supplied a zero value; it does not independently establish a positive deviation probability. The final Yes is the conditional eventual-equality tail certificate, not a proof from this single inspected index. The exact result, retaining the requested order, is (11, 13, 0, Yes, eventual_equality_universal_tail_certificate)."},"skills":["Eventual Equality Supplies a Conditional Universal-Tail Certificate"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0087","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"8ba17074aac0f9ec8f2ae35427ad7a8e3bb1625d6e02907d14ee8b35cc1ebd04","family_id":"qf-mod30-convprob-eventual-equality","seed":202610307087,"semantic_template":"qf-mod30-convprob-eventual-equality/{\"n\":14,\"settling_index\":12}"},"fields":{"title":"Eventual Equality Supplies a Conditional Universal-Tail Certificate","stem":"On the declared common probability space assume X_n=X almost surely for every n≥settling_index=12; inspect n=14. Give (settling_index,n,zero_probability_status,certificate?,eventual_equality_universal_tail_certificate).","answer":{"kind":"expression","value":"(12, 14, 0, Yes, eventual_equality_universal_tail_certificate)","explanation":"At or beyond the settling index the deviation probability is0 for every positive epsilon. Earlier not_yet_zero means this certificate has not yet supplied a zero value; it does not independently establish a positive deviation probability. The final Yes is the conditional eventual-equality tail certificate, not a proof from this single inspected index. The exact result, retaining the requested order, is (12, 14, 0, Yes, eventual_equality_universal_tail_certificate)."},"skills":["Eventual Equality Supplies a Conditional Universal-Tail Certificate"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0088","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"d5ecb83ab06217ad9d62ca12d53f4973202106df500e1067e5f887f7cac21868","family_id":"qf-mod30-convprob-eventual-equality","seed":202610307088,"semantic_template":"qf-mod30-convprob-eventual-equality/{\"n\":16,\"settling_index\":13}"},"fields":{"title":"Eventual Equality Supplies a Conditional Universal-Tail Certificate","stem":"On the declared common probability space assume X_n=X almost surely for every n≥settling_index=13; inspect n=16. Give (settling_index,n,zero_probability_status,certificate?,eventual_equality_universal_tail_certificate).","answer":{"kind":"expression","value":"(13, 16, 0, Yes, eventual_equality_universal_tail_certificate)","explanation":"At or beyond the settling index the deviation probability is0 for every positive epsilon. Earlier not_yet_zero means this certificate has not yet supplied a zero value; it does not independently establish a positive deviation probability. The final Yes is the conditional eventual-equality tail certificate, not a proof from this single inspected index. The exact result, retaining the requested order, is (13, 16, 0, Yes, eventual_equality_universal_tail_certificate)."},"skills":["Eventual Equality Supplies a Conditional Universal-Tail Certificate"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0089","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"508f70f77edfa774cbf0bd83d954b6190075e0ac62a26830f2967aec1ad46376","family_id":"qf-mod30-convprob-eventual-equality","seed":202610307089,"semantic_template":"qf-mod30-convprob-eventual-equality/{\"n\":17,\"settling_index\":14}"},"fields":{"title":"Eventual Equality Supplies a Conditional Universal-Tail Certificate","stem":"On the declared common probability space assume X_n=X almost surely for every n≥settling_index=14; inspect n=17. Give (settling_index,n,zero_probability_status,certificate?,eventual_equality_universal_tail_certificate).","answer":{"kind":"expression","value":"(14, 17, 0, Yes, eventual_equality_universal_tail_certificate)","explanation":"At or beyond the settling index the deviation probability is0 for every positive epsilon. Earlier not_yet_zero means this certificate has not yet supplied a zero value; it does not independently establish a positive deviation probability. The final Yes is the conditional eventual-equality tail certificate, not a proof from this single inspected index. The exact result, retaining the requested order, is (14, 17, 0, Yes, eventual_equality_universal_tail_certificate)."},"skills":["Eventual Equality Supplies a Conditional Universal-Tail Certificate"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0090","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"a4837a22ed239d0c3cc22fcd4fe1de58fb7d021dfce0da8c0bd14d46f257f22b","family_id":"qf-mod30-convprob-eventual-equality","seed":202610307090,"semantic_template":"qf-mod30-convprob-eventual-equality/{\"n\":18,\"settling_index\":15}"},"fields":{"title":"Eventual Equality Supplies a Conditional Universal-Tail Certificate","stem":"On the declared common probability space assume X_n=X almost surely for every n≥settling_index=15; inspect n=18. Give (settling_index,n,zero_probability_status,certificate?,eventual_equality_universal_tail_certificate).","answer":{"kind":"expression","value":"(15, 18, 0, Yes, eventual_equality_universal_tail_certificate)","explanation":"At or beyond the settling index the deviation probability is0 for every positive epsilon. Earlier not_yet_zero means this certificate has not yet supplied a zero value; it does not independently establish a positive deviation probability. The final Yes is the conditional eventual-equality tail certificate, not a proof from this single inspected index. The exact result, retaining the requested order, is (15, 18, 0, Yes, eventual_equality_universal_tail_certificate)."},"skills":["Eventual Equality Supplies a Conditional Universal-Tail Certificate"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0091","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"53ddc282b2e6a300555cbbfd4489c387f1f51acfa8a0345d31e697210e4c6cca","family_id":"qf-mod30-convprob-eventual-equality","seed":202610307091,"semantic_template":"qf-mod30-convprob-eventual-equality/{\"n\":20,\"settling_index\":16}"},"fields":{"title":"Eventual Equality Supplies a Conditional Universal-Tail Certificate","stem":"On the declared common probability space assume X_n=X almost surely for every n≥settling_index=16; inspect n=20. Give (settling_index,n,zero_probability_status,certificate?,eventual_equality_universal_tail_certificate).","answer":{"kind":"expression","value":"(16, 20, 0, Yes, eventual_equality_universal_tail_certificate)","explanation":"At or beyond the settling index the deviation probability is0 for every positive epsilon. Earlier not_yet_zero means this certificate has not yet supplied a zero value; it does not independently establish a positive deviation probability. The final Yes is the conditional eventual-equality tail certificate, not a proof from this single inspected index. The exact result, retaining the requested order, is (16, 20, 0, Yes, eventual_equality_universal_tail_certificate)."},"skills":["Eventual Equality Supplies a Conditional Universal-Tail Certificate"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0092","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"b820ac930823e1a1e6a6aeab8a91461049ce5ef3731907f0fc4102b2d708dfe6","family_id":"qf-mod30-convprob-eventual-equality","seed":202610307092,"semantic_template":"qf-mod30-convprob-eventual-equality/{\"n\":21,\"settling_index\":17}"},"fields":{"title":"Eventual Equality Supplies a Conditional Universal-Tail Certificate","stem":"On the declared common probability space assume X_n=X almost surely for every n≥settling_index=17; inspect n=21. Give (settling_index,n,zero_probability_status,certificate?,eventual_equality_universal_tail_certificate).","answer":{"kind":"expression","value":"(17, 21, 0, Yes, eventual_equality_universal_tail_certificate)","explanation":"At or beyond the settling index the deviation probability is0 for every positive epsilon. Earlier not_yet_zero means this certificate has not yet supplied a zero value; it does not independently establish a positive deviation probability. The final Yes is the conditional eventual-equality tail certificate, not a proof from this single inspected index. The exact result, retaining the requested order, is (17, 21, 0, Yes, eventual_equality_universal_tail_certificate)."},"skills":["Eventual Equality Supplies a Conditional Universal-Tail Certificate"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0093","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"fcf6ea3b3f0bfad85457e6bd4015d2350cd1332e719ccfaf92c6abe2cb5779d6","family_id":"qf-mod30-convprob-eventual-equality","seed":202610307093,"semantic_template":"qf-mod30-convprob-eventual-equality/{\"n\":22,\"settling_index\":18}"},"fields":{"title":"Eventual Equality Supplies a Conditional Universal-Tail Certificate","stem":"On the declared common probability space assume X_n=X almost surely for every n≥settling_index=18; inspect n=22. Give (settling_index,n,zero_probability_status,certificate?,eventual_equality_universal_tail_certificate).","answer":{"kind":"expression","value":"(18, 22, 0, Yes, eventual_equality_universal_tail_certificate)","explanation":"At or beyond the settling index the deviation probability is0 for every positive epsilon. Earlier not_yet_zero means this certificate has not yet supplied a zero value; it does not independently establish a positive deviation probability. The final Yes is the conditional eventual-equality tail certificate, not a proof from this single inspected index. The exact result, retaining the requested order, is (18, 22, 0, Yes, eventual_equality_universal_tail_certificate)."},"skills":["Eventual Equality Supplies a Conditional Universal-Tail Certificate"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0094","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"9c9e6fe20561e56ca309c2a69bafd41437d957b55f73c78067dce04fbf2b6548","family_id":"qf-mod30-convprob-eventual-equality","seed":202610307094,"semantic_template":"qf-mod30-convprob-eventual-equality/{\"n\":24,\"settling_index\":19}"},"fields":{"title":"Eventual Equality Supplies a Conditional Universal-Tail Certificate","stem":"On the declared common probability space assume X_n=X almost surely for every n≥settling_index=19; inspect n=24. Give (settling_index,n,zero_probability_status,certificate?,eventual_equality_universal_tail_certificate).","answer":{"kind":"expression","value":"(19, 24, 0, Yes, eventual_equality_universal_tail_certificate)","explanation":"At or beyond the settling index the deviation probability is0 for every positive epsilon. Earlier not_yet_zero means this certificate has not yet supplied a zero value; it does not independently establish a positive deviation probability. The final Yes is the conditional eventual-equality tail certificate, not a proof from this single inspected index. The exact result, retaining the requested order, is (19, 24, 0, Yes, eventual_equality_universal_tail_certificate)."},"skills":["Eventual Equality Supplies a Conditional Universal-Tail Certificate"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0095","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"7f3253de86070ded023005736927fad7a952a1a2e2f45b8bff9d65588900d0f2","family_id":"qf-mod30-convprob-eventual-equality","seed":202610307095,"semantic_template":"qf-mod30-convprob-eventual-equality/{\"n\":25,\"settling_index\":20}"},"fields":{"title":"Eventual Equality Supplies a Conditional Universal-Tail Certificate","stem":"On the declared common probability space assume X_n=X almost surely for every n≥settling_index=20; inspect n=25. Give (settling_index,n,zero_probability_status,certificate?,eventual_equality_universal_tail_certificate).","answer":{"kind":"expression","value":"(20, 25, 0, Yes, eventual_equality_universal_tail_certificate)","explanation":"At or beyond the settling index the deviation probability is0 for every positive epsilon. Earlier not_yet_zero means this certificate has not yet supplied a zero value; it does not independently establish a positive deviation probability. The final Yes is the conditional eventual-equality tail certificate, not a proof from this single inspected index. The exact result, retaining the requested order, is (20, 25, 0, Yes, eventual_equality_universal_tail_certificate)."},"skills":["Eventual Equality Supplies a Conditional Universal-Tail Certificate"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0096","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"d1f764ee7c89fb7cbc8d098e8226997219283b0c36d5e746594bfc28c8809edc","family_id":"qf-mod30-convprob-eventual-equality","seed":202610307096,"semantic_template":"qf-mod30-convprob-eventual-equality/{\"n\":26,\"settling_index\":21}"},"fields":{"title":"Eventual Equality Supplies a Conditional Universal-Tail Certificate","stem":"On the declared common probability space assume X_n=X almost surely for every n≥settling_index=21; inspect n=26. Give (settling_index,n,zero_probability_status,certificate?,eventual_equality_universal_tail_certificate).","answer":{"kind":"expression","value":"(21, 26, 0, Yes, eventual_equality_universal_tail_certificate)","explanation":"At or beyond the settling index the deviation probability is0 for every positive epsilon. Earlier not_yet_zero means this certificate has not yet supplied a zero value; it does not independently establish a positive deviation probability. The final Yes is the conditional eventual-equality tail certificate, not a proof from this single inspected index. The exact result, retaining the requested order, is (21, 26, 0, Yes, eventual_equality_universal_tail_certificate)."},"skills":["Eventual Equality Supplies a Conditional Universal-Tail Certificate"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0097","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"1d37d9bd1f910fb54745854811f5e74df653f119d0832090391b1e518b8d6a72","family_id":"qf-mod30-convprob-eventual-equality","seed":202610307097,"semantic_template":"qf-mod30-convprob-eventual-equality/{\"n\":28,\"settling_index\":22}"},"fields":{"title":"Eventual Equality Supplies a Conditional Universal-Tail Certificate","stem":"On the declared common probability space assume X_n=X almost surely for every n≥settling_index=22; inspect n=28. Give (settling_index,n,zero_probability_status,certificate?,eventual_equality_universal_tail_certificate).","answer":{"kind":"expression","value":"(22, 28, 0, Yes, eventual_equality_universal_tail_certificate)","explanation":"At or beyond the settling index the deviation probability is0 for every positive epsilon. Earlier not_yet_zero means this certificate has not yet supplied a zero value; it does not independently establish a positive deviation probability. The final Yes is the conditional eventual-equality tail certificate, not a proof from this single inspected index. The exact result, retaining the requested order, is (22, 28, 0, Yes, eventual_equality_universal_tail_certificate)."},"skills":["Eventual Equality Supplies a Conditional Universal-Tail Certificate"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0098","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"eaea21bcf8fa748e304fe378b1ad5f811a5253f2bac1697ebe2fb7ea3555a4c1","family_id":"qf-mod30-convprob-eventual-equality","seed":202610307098,"semantic_template":"qf-mod30-convprob-eventual-equality/{\"n\":29,\"settling_index\":23}"},"fields":{"title":"Eventual Equality Supplies a Conditional Universal-Tail Certificate","stem":"On the declared common probability space assume X_n=X almost surely for every n≥settling_index=23; inspect n=29. Give (settling_index,n,zero_probability_status,certificate?,eventual_equality_universal_tail_certificate).","answer":{"kind":"expression","value":"(23, 29, 0, Yes, eventual_equality_universal_tail_certificate)","explanation":"At or beyond the settling index the deviation probability is0 for every positive epsilon. Earlier not_yet_zero means this certificate has not yet supplied a zero value; it does not independently establish a positive deviation probability. The final Yes is the conditional eventual-equality tail certificate, not a proof from this single inspected index. The exact result, retaining the requested order, is (23, 29, 0, Yes, eventual_equality_universal_tail_certificate)."},"skills":["Eventual Equality Supplies a Conditional Universal-Tail Certificate"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0099","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"e8549d8f23067a3ae953bb99eaa9ddb31f685f85de33132b5c1f94efb9911b2d","family_id":"qf-mod30-convprob-eventual-equality","seed":202610307099,"semantic_template":"qf-mod30-convprob-eventual-equality/{\"n\":30,\"settling_index\":24}"},"fields":{"title":"Eventual Equality Supplies a Conditional Universal-Tail Certificate","stem":"On the declared common probability space assume X_n=X almost surely for every n≥settling_index=24; inspect n=30. Give (settling_index,n,zero_probability_status,certificate?,eventual_equality_universal_tail_certificate).","answer":{"kind":"expression","value":"(24, 30, 0, Yes, eventual_equality_universal_tail_certificate)","explanation":"At or beyond the settling index the deviation probability is0 for every positive epsilon. Earlier not_yet_zero means this certificate has not yet supplied a zero value; it does not independently establish a positive deviation probability. The final Yes is the conditional eventual-equality tail certificate, not a proof from this single inspected index. The exact result, retaining the requested order, is (24, 30, 0, Yes, eventual_equality_universal_tail_certificate)."},"skills":["Eventual Equality Supplies a Conditional Universal-Tail Certificate"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
{"schema_version":"ocme-question-localization-v0.1","question_id":"q-20261014-advance-20261030-r07-convergence-in-probability-0100","batch_id":"batch-20261014-advance-20261030-r07-convergence-in-probability-foundations","locale":"en","translation_state":"ai_candidate","source":{"question_sha256":"17c16bd6ba65cc1a65940168eb37d14fe52330d0530add18f32b8e1b9b10dce2","family_id":"qf-mod30-convprob-eventual-equality","seed":202610307100,"semantic_template":"qf-mod30-convprob-eventual-equality/{\"n\":32,\"settling_index\":25}"},"fields":{"title":"Eventual Equality Supplies a Conditional Universal-Tail Certificate","stem":"On the declared common probability space assume X_n=X almost surely for every n≥settling_index=25; inspect n=32. Give (settling_index,n,zero_probability_status,certificate?,eventual_equality_universal_tail_certificate).","answer":{"kind":"expression","value":"(25, 32, 0, Yes, eventual_equality_universal_tail_certificate)","explanation":"At or beyond the settling index the deviation probability is0 for every positive epsilon. Earlier not_yet_zero means this certificate has not yet supplied a zero value; it does not independently establish a positive deviation probability. The final Yes is the conditional eventual-equality tail certificate, not a proof from this single inspected index. The exact result, retaining the requested order, is (25, 32, 0, Yes, eventual_equality_universal_tail_certificate)."},"skills":["Eventual Equality Supplies a Conditional Universal-Tail Certificate"],"verification_warning":"This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."}}
