{
  "schema_version": "ocme-reviewed-question-reader-v1",
  "question_id": "q-20261007-advance-20261008-r01-sequence-limit-0008",
  "pilot_number": "R0056-28758",
  "number": 28758,
  "family_id": "qf-sequence-limit-reciprocal-value",
  "title": {
    "zh-Hant": "第 28758 題：明示倒數尾的數列極限",
    "en": "Question 28758: Limit of an Explicit Reciprocal-Tail Sequence"
  },
  "original_question": {
    "schema_version": "ocme-question-v0.1",
    "id": "q-20261007-advance-20261008-r01-sequence-limit-0008",
    "batch_id": "batch-20261007-advance-20261008-r01-sequence-limit-foundations",
    "language": "zh-Hant",
    "source_mko_ids": [
      "mko-sequence-limit"
    ],
    "title_zh": "明示倒數尾的數列極限",
    "stem_zh": "從0起算實數列 a_n=-5+(-8)/(n+3)，n∈N0，d≥1。求數列極限。",
    "answer": {
      "kind": "short_text",
      "value": "-5",
      "explanation_zh": "極限L=-5。此模型的倒數尾趨於零，極限為指定 L；不是以有限項抽樣建立任意數列的普遍證明。"
    },
    "difficulty": {
      "band": "undergraduate_core",
      "level": 1,
      "skills": [
        "明示倒數尾的數列極限"
      ]
    },
    "variant": {
      "family_id": "qf-sequence-limit-reciprocal-value",
      "seed": 202610081008,
      "parameters": {
        "L": -5,
        "c": -8,
        "d": 3,
        "operation": "reciprocal_sequence_limit",
        "domain": "naturals_from_zero",
        "semantic_template": "qf-sequence-limit-reciprocal-value/{\"inputs\":[\"-5\"],\"operation\":\"reciprocal_sequence_limit\"}"
      }
    },
    "verification": {
      "status": "candidate",
      "checks": [
        "producer_exact_integer_rational_arithmetic",
        "producer_finite_enumeration",
        "producer_source_snapshot_check",
        "producer_substantive_template_deduplication",
        "producer_json_schema"
      ],
      "warning_zh": "僅為產生端候選及自檢；主端須另做獨立驗收，不構成人工審定、普遍證明或形式 Evidence。"
    },
    "provenance": {
      "generator_role": "question_producer",
      "generator_model": "model_unknown",
      "generated_at": "2026-10-07",
      "contract_version": "ocme-question-factory-v0.1"
    }
  },
  "original_english_edition": {
    "schema_version": "ocme-question-localization-v0.1",
    "question_id": "q-20261007-advance-20261008-r01-sequence-limit-0008",
    "batch_id": "batch-20261007-advance-20261008-r01-sequence-limit-foundations",
    "locale": "en",
    "translation_state": "ai_candidate",
    "source": {
      "question_sha256": "655e207480cdd020ce5c750a9b073ddd77981431ac0ff6b1b869ce270170329c",
      "family_id": "qf-sequence-limit-reciprocal-value",
      "seed": 202610081008,
      "semantic_template": "qf-sequence-limit-reciprocal-value/{\"inputs\":[\"-5\"],\"operation\":\"reciprocal_sequence_limit\"}"
    },
    "fields": {
      "title": "Limit of an Explicit Reciprocal-Tail Sequence",
      "stem": "On natural indices starting at zero, u(n)=(-5)+(-8)/(n+3), with d≥1. Find the declared reciprocal-tail limit.",
      "answer": {
        "kind": "short_text",
        "value": "-5",
        "explanation": "The reciprocal error tends to zero in this model, leaving L=-5, including c=0. This is not an inference about an arbitrary sequence from finitely many terms."
      },
      "skills": [
        "Limit of an Explicit Reciprocal-Tail Sequence"
      ],
      "verification_warning": "This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."
    }
  },
  "givens": [
    {
      "id": "G001",
      "text": {
        "zh-Hant": "從0起算實數列 a_n=-5+(-8)/(n+3)，n∈N0，d≥1。求數列極限。",
        "en": "On natural indices starting at zero, u(n)=(-5)+(-8)/(n+3), with d≥1. Find the declared reciprocal-tail limit."
      }
    }
  ],
  "steps": [
    {
      "id": "S001",
      "uses": [
        "G001"
      ],
      "before": "source roles = [qf-sequence-limit-reciprocal-value, reciprocal_sequence_limit]",
      "after": "derived = [limit_from_whole_reciprocal_sequence_law]",
      "relation": "implies",
      "rule_id": "R56_source_answer_role_and_EXACT_family_interface",
      "conditions": [],
      "explanation": {
        "zh-Hant": "本題輸出依原scalar／set／是非／fraction角色；有理數整數保留/1。不加未宣告domain，不改中英來源、公式或題目。",
        "en": "Use the declared scalar/set/Yes-No/fraction answer role;integer fractions retain/1.Do not add an undeclared domain or change original bilingual data,formulas or questions."
      },
      "reverse_audit": {
        "kind": "premise_and_result_audit",
        "explanation": {
          "zh-Hant": "反向逐項代回原始資料與本步條件；保持索引、符號、嚴格／非嚴格邊界，不能用正確答案代替推導責任。這是候選教學與精確核對，非形式證明或發布資格。",
          "en": "Reverse-check EACH original datum and premise,retaining indices,signs and strict/non-strict boundaries.A correct final answer cannot replace the derivation obligations.This is candidate teaching/exact checking,not formal proof or publication clearance."
        }
      },
      "arithmetic": null
    },
    {
      "id": "S002",
      "uses": [
        "G001",
        "S001"
      ],
      "before": "source roles = [-8, 3, naturals_from_zero]",
      "after": "derived = [8, u(n)=L+c/(n+d), |u(n)-L|=|c|/(n+d)]",
      "relation": "implies",
      "rule_id": "Sequence_WHOLE_law_and_positive_increasing_denominator",
      "conditions": [],
      "explanation": {
        "zh-Hant": "題設給所有自然數n>=0的完整law，d>0使n+d正且隨n增大。取絕對值先消L再得誤差，不從有限prefix猜limit；error／cutoff題的L只是任意固定實數，非新增參數。",
        "en": "The premise is the WHOLE law for every n>=0,not a finite prefix.With d>0,the denominator is positive and increasing.Subtract L before taking the absolute value.In error/cutoff tasks L is an arbitrary fixed real,not an invented input parameter."
      },
      "reverse_audit": {
        "kind": "premise_and_result_audit",
        "explanation": {
          "zh-Hant": "反向逐項代回原始資料與本步條件；保持索引、符號、嚴格／非嚴格邊界，不能用正確答案代替推導責任。這是候選教學與精確核對，非形式證明或發布資格。",
          "en": "Reverse-check EACH original datum and premise,retaining indices,signs and strict/non-strict boundaries.A correct final answer cannot replace the derivation obligations.This is candidate teaching/exact checking,not formal proof or publication clearance."
        }
      },
      "arithmetic": null
    },
    {
      "id": "S003",
      "uses": [
        "G001",
        "S002"
      ],
      "before": "source roles = [-5, -8, 3]",
      "after": "derived = [-5, N=max(0,floor(|c|/epsilon)-d+1), for all n>=N: |u(n)-L|<epsilon]",
      "relation": "implies",
      "rule_id": "Sequence_limit_EVERY_epsilon_has_a_whole_tail",
      "conditions": [],
      "explanation": {
        "zh-Hant": "任意epsilon>0，以N=max(0,floor(|c|/epsilon)-d+1)得N+d>|c|/epsilon，所有n>=N同樣滿足誤差<epsilon；c=0時可N=0。因此limit正是給定L，不把某個取樣項當limit。",
        "en": "For ANY epsilon>0 choose N=max(0,floor(|c|/epsilon)-d+1).Then n+d>|c|/epsilon for EVERY n>=N,so the error is strictly below epsilon.For c=0,N=0 suffices.Thus the limit is the GIVEN L,not a sampled term."
      },
      "reverse_audit": {
        "kind": "premise_and_result_audit",
        "explanation": {
          "zh-Hant": "反向逐項代回原始資料與本步條件；保持索引、符號、嚴格／非嚴格邊界，不能用正確答案代替推導責任。這是候選教學與精確核對，非形式證明或發布資格。",
          "en": "Reverse-check EACH original datum and premise,retaining indices,signs and strict/non-strict boundaries.A correct final answer cannot replace the derivation obligations.This is candidate teaching/exact checking,not formal proof or publication clearance."
        }
      },
      "arithmetic": null
    }
  ],
  "math_model": {
    "result": "-5"
  },
  "conclusion": {
    "canonical_value": "-5",
    "explanation": {
      "zh-Hant": "依上列完整代值及條件核對得到原題答案；原題編號、格式與狀態保持不變。",
      "en": "The full substitutions and premise checks give the original answer; source identity,format and status are unchanged."
    }
  },
  "definition_note": {
    "zh-Hant": "沿用原題明示的論域、假設與來源 MKO 定義。本題已完成第二對話數理與中英語義覆核，並由原始參數逐題獨立重算模型、答案與每個算術步驟；原題仍為 candidate。",
    "en": "Use the original question domain, assumptions and cited MKO definitions. This item has second-context mathematical and bilingual review, with the model, answer and every arithmetic step independently recomputed from the original parameters; the source question remains a candidate."
  },
  "source": {
    "input_commit": "0f7be61e2c22317a4075561dc822c87d881a50db",
    "question_binding": {
      "batch_id": "batch-20261007-advance-20261008-r01-sequence-limit-foundations",
      "batch_path": "public/data/questions/batches/batch-20261007-advance-20261008-r01-sequence-limit-foundations/questions.jsonl",
      "batch_sha256": "124ae93c1492492eb4f3fc0395814be15a2792916927f6f1ab8aaa2eadb2c2b1",
      "original_line": 8,
      "original_line_sha256": "b2fc3e10c2962dac3a3f19ee61055b0929f49f0ee7c34c0e196bc6a9fd00c06f",
      "question_compact_sha256": "655e207480cdd020ce5c750a9b073ddd77981431ac0ff6b1b869ce270170329c",
      "english_row_compact_sha256": "588fe3afba128e483ed159c6ecf132252c22774a9f87a37952fa57fe7bb53246",
      "english_manifest_path": "public/data/i18n/editions/batch-20261007-advance-20261008-r01-sequence-limit-foundations.en.json",
      "english_rows_path": "public/data/i18n/questions/batch-20261007-advance-20261008-r01-sequence-limit-foundations.en.jsonl"
    },
    "mko_bindings": {
      "mko-sequence-limit": {
        "sha256": "3018ee44ad1a41db719f4c5275fd215d436e1dc4e73fdc44993604a211486fff",
        "english_sha256": "ee964b7eba696e940cf9793cbba93912244a2bd9ed11ec3f4e647fafa8fd38ae",
        "original_path": "public/data/mko/sequence-limit.json",
        "english_path": "public/data/i18n/editions/mko-sequence-limit.en.json"
      }
    },
    "selected_manifest_sha256": "5233edba9654a6cffd8b6b2d83c932f82ded15f9c0b7c733bd049943e672acff",
    "selected_part_sha256": "e340023047850507ee3fe2ae1466d606cfcbd26849aa3bb168d53248f38097e5",
    "original_candidate_sha256": "1c92b219bb6a4952e7fbd452403fd7ac90fdd01f7c05145d5c24ecf57483b883",
    "original_candidate_line_sha256": "1c92b219bb6a4952e7fbd452403fd7ac90fdd01f7c05145d5c24ecf57483b883"
  },
  "historical_source_state": {
    "review_state": {
      "derivation": "candidate_authored_and_locally_checked",
      "source_question_state": "candidate",
      "independent_AI_or_human_review": "NOT_PERFORMED",
      "formalization": "not_formalized",
      "Lean": "NOT_RUN"
    },
    "scope_note": {
      "zh-Hant": "來源綁定教學推導候選；精確核對不等於獨立AI／人工審查或一般形式證明。原題、答案、MKO、公式、AST與歷史不變。",
      "en": "Source-bound pedagogical derivation candidate.Exact checking is not independent AI/human review or general formal proof.Original questions,answers,MKOs,formulas,ASTs and history remain unchanged."
    },
    "label": "Frozen producer metadata; current per-question review is separate below."
  },
  "revision": {
    "id": "review-20261026-010-p57",
    "review_date": "2026-10-26",
    "owner_authorized_reader_publication": true,
    "scope": "One hundred sixty family prototypes and their mathematical/bilingual reasoning variants, stems, boundary statements and every distinct explanation shape were reviewed in a context independent of the producer; parameter substitutions, source bindings, full math models, both answer strings and every arithmetic step were independently reconstructed per question from the original parameters only, with negative controls. This grouped method does not claim a separate literal AI reading of every repeated sentence or an extra AI voter.",
    "review_receipts": {
      "semantic_review_sha256": "8bbda4edbed7078634ae88342998c79bcfb95de96187fac119c3b08e0adb0bc8",
      "question_first_witness_sha256": "3edafa72d63d16a22414892b55806430e0a25b15b926d04f312550179607759f"
    },
    "status": "second_context_reviewed",
    "mathematical_semantics": true,
    "bilingual_semantics": true,
    "steps_reviewed": 3,
    "method": "family_template_semantic_review_plus_independent_per_instance_reconstruction",
    "exact_question_first_check": {
      "model_sha256": "995e467ea05904b35e74312ccc88a1eaa03c3a1b81e85ed5335cfd4daa85b078",
      "arithmetic_steps": 0
    },
    "uses_answer_as_premise": false,
    "human_review": "NOT_PERFORMED",
    "formalization": "not_formalized",
    "Lean": "NOT_RUN",
    "Canonical_truth_promotion": false,
    "authority": "Owner-authorized reviewed reader publication; original question/candidate states remain historical and unchanged."
  }
}
