{
  "schema_version": "ocme-reviewed-question-reader-v1",
  "question_id": "q-20261009-advance-20261013-r01-pythagorean-theorem-0011",
  "pilot_number": "R0011-06361",
  "number": 6361,
  "family_id": "qf-density13-pythagorean-leg-square-sum",
  "title": {
    "zh-Hant": "第 6361 題：正股的有序平方與斜邊平方",
    "en": "Question 6361: Ordered Leg Squares and Hypotenuse Square"
  },
  "original_question": {
    "schema_version": "ocme-question-v0.1",
    "id": "q-20261009-advance-20261013-r01-pythagorean-theorem-0011",
    "batch_id": "batch-20261009-advance-20261013-r01-pythagorean-theorem-foundations",
    "language": "zh-Hant",
    "source_mko_ids": [
      "mko-euclid-pythagorean-theorem"
    ],
    "title_zh": "正股的有序平方與斜邊平方",
    "stem_zh": "歐氏直角邊長模型；正股長，a=12、b=5。依序求 (a², b², a²+b²)，最後欄是模型的斜邊平方，不交換股序。",
    "answer": {
      "kind": "expression",
      "value": "(144, 25, 169)",
      "explanation_zh": "股平方與斜邊平方=(144, 25, 169)。分別平方兩正股再加總；有限邊長檢查非新普遍證明，未完成任意仿射橋接。"
    },
    "difficulty": {
      "band": "upper_secondary",
      "level": 2,
      "skills": [
        "正股的有序平方與斜邊平方"
      ]
    },
    "variant": {
      "family_id": "qf-density13-pythagorean-leg-square-sum",
      "seed": 202610131011,
      "parameters": {
        "a": 12,
        "b": 5,
        "geometry": "euclidean_right_side_model",
        "operation": "density13_pythagorean_leg_square_sum",
        "domain": "positive_integer_right_side_protocol",
        "semantic_template": "qf-density13-pythagorean-leg-square-sum/[\"144\",\"25\"]"
      }
    },
    "verification": {
      "status": "candidate",
      "checks": [
        "producer_exact_integer_rational_arithmetic",
        "producer_finite_enumeration",
        "producer_source_snapshot_check",
        "producer_substantive_template_deduplication",
        "producer_json_schema"
      ],
      "warning_zh": "僅為產生端候選及自檢；主端須另做獨立驗收，不構成人工審定、普遍證明或形式 Evidence。"
    },
    "provenance": {
      "generator_role": "question_producer",
      "generator_model": "model_unknown",
      "generated_at": "2026-10-09",
      "contract_version": "ocme-question-factory-v0.1"
    }
  },
  "original_english_edition": {
    "schema_version": "ocme-question-localization-v0.1",
    "question_id": "q-20261009-advance-20261013-r01-pythagorean-theorem-0011",
    "batch_id": "batch-20261009-advance-20261013-r01-pythagorean-theorem-foundations",
    "locale": "en",
    "translation_state": "ai_candidate",
    "source": {
      "question_sha256": "7d424475036149c1345d9c0ba7b5c05ea0fe813684aadd77394e65d0bcabed76",
      "family_id": "qf-density13-pythagorean-leg-square-sum",
      "seed": 202610131011,
      "semantic_template": "qf-density13-pythagorean-leg-square-sum/[\"144\",\"25\"]"
    },
    "fields": {
      "title": "Ordered Leg Squares and Hypotenuse Square",
      "stem": "Use a Euclidean right-triangle side-length model with strictly positive integer legs. a=12, b=5. Give (a², b², a²+b²), retaining leg order; the last field is the model’s hypotenuse square.",
      "answer": {
        "kind": "expression",
        "value": "(144, 25, 169)",
        "explanation": "Square both positive legs separately and add; this finite side model is not a new universal proof or a completed affine geometry bridge. The exact result, retaining the requested order, is (144, 25, 169)."
      },
      "skills": [
        "Ordered Leg Squares and Hypotenuse Square"
      ],
      "verification_warning": "This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."
    }
  },
  "givens": [
    {
      "id": "G001",
      "text": {
        "zh-Hant": "歐氏直角邊長模型；正股長，a=12、b=5。依序求 (a², b², a²+b²)，最後欄是模型的斜邊平方，不交換股序。",
        "en": "Use a Euclidean right-triangle side-length model with strictly positive integer legs. a=12, b=5. Give (a², b², a²+b²), retaining leg order; the last field is the model’s hypotenuse square."
      }
    }
  ],
  "steps": [
    {
      "id": "S001",
      "uses": [
        "G001"
      ],
      "before": "Euclidean right-side model;positive leg a=12",
      "after": "use the supplied right-angle premise:a²+b²=c²",
      "relation": "implies",
      "rule_id": "pythagorean_right_side_premise",
      "conditions": [],
      "explanation": {
        "zh-Hant": "使用已宣告的歐氏直角邊長模型及正股長前提；此有限數值核對不是畢氏定理的新普遍證明，也不建立任意仿射幾何橋接。",
        "en": "Use the declared Euclidean right-side model with positive legs.This finite numerical check is not a new universal proof of the Pythagorean theorem or an arbitrary affine-geometric bridge."
      },
      "reverse_audit": {
        "kind": "premise_and_result_audit",
        "explanation": {
          "zh-Hant": "回到原始資料與本步條件核對，不把單向推論誤稱等價。",
          "en": "Check against the original data and this step's premises; a one-way implication is not an equivalence."
        }
      },
      "arithmetic": null
    },
    {
      "id": "S002",
      "uses": [
        "G001",
        "S001"
      ],
      "before": "known leg a squared := square(12)",
      "after": "known leg a squared = 144",
      "relation": "calculation",
      "rule_id": "exact_rational_arithmetic",
      "conditions": [],
      "explanation": {
        "zh-Hant": "先完整平方已知正股長a。",
        "en": "Square the complete known positive leg a."
      },
      "reverse_audit": {
        "kind": "premise_and_result_audit",
        "explanation": {
          "zh-Hant": "以精確有理數重算 known leg a squared，不以小數近似替代。",
          "en": "Recompute known leg a squared with exact rational arithmetic, not rounded decimals."
        }
      },
      "arithmetic": {
        "operation": "square",
        "inputs": [
          "12"
        ],
        "output": "144",
        "label": "known leg a squared"
      }
    },
    {
      "id": "S003",
      "uses": [
        "G001",
        "S002"
      ],
      "before": "leg b squared := square(5)",
      "after": "leg b squared = 25",
      "relation": "calculation",
      "rule_id": "exact_rational_arithmetic",
      "conditions": [],
      "explanation": {
        "zh-Hant": "另一正股長b獨立平方。",
        "en": "Square the other positive leg b separately."
      },
      "reverse_audit": {
        "kind": "premise_and_result_audit",
        "explanation": {
          "zh-Hant": "以精確有理數重算 leg b squared，不以小數近似替代。",
          "en": "Recompute leg b squared with exact rational arithmetic, not rounded decimals."
        }
      },
      "arithmetic": {
        "operation": "square",
        "inputs": [
          "5"
        ],
        "output": "25",
        "label": "leg b squared"
      }
    },
    {
      "id": "S004",
      "uses": [
        "G001",
        "S003"
      ],
      "before": "sum of leg squares := sum(144, 25)",
      "after": "sum of leg squares = 169",
      "relation": "calculation",
      "rule_id": "exact_rational_arithmetic",
      "conditions": [],
      "explanation": {
        "zh-Hant": "股平方相加是模型中的斜邊平方，不是斜邊本身。",
        "en": "The sum of leg squares is the model's squared hypotenuse,not the hypotenuse itself."
      },
      "reverse_audit": {
        "kind": "premise_and_result_audit",
        "explanation": {
          "zh-Hant": "以精確有理數重算 sum of leg squares，不以小數近似替代。",
          "en": "Recompute sum of leg squares with exact rational arithmetic, not rounded decimals."
        }
      },
      "arithmetic": {
        "operation": "sum",
        "inputs": [
          "144",
          "25"
        ],
        "output": "169",
        "label": "sum of leg squares"
      }
    }
  ],
  "math_model": {
    "result": [
      "144",
      "25",
      "169"
    ]
  },
  "conclusion": {
    "canonical_value": "(144, 25, 169)",
    "explanation": {
      "zh-Hant": "依上列完整代值及條件核對得到原題答案；原題編號、格式與狀態保持不變。",
      "en": "The full substitutions and premise checks give the original answer; source identity,format and status are unchanged."
    }
  },
  "definition_note": {
    "zh-Hant": "沿用原題明示的論域、假設與來源 MKO 定義。本題已完成第二對話數理與中英語義覆核，並由原始參數逐題獨立重算模型、答案與每個算術步驟；原題仍為 candidate。",
    "en": "Use the original question domain, assumptions and cited MKO definitions. This item has second-context mathematical and bilingual review, with the model, answer and every arithmetic step independently recomputed from the original parameters; the source question remains a candidate."
  },
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      "english_manifest_path": "public/data/i18n/editions/batch-20261009-advance-20261013-r01-pythagorean-theorem-foundations.en.json",
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      "formalization": "not_formalized",
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      "en": "Source-bound pedagogical derivation candidate.Exact checking is not independent AI/human review or general formal proof.Original questions,answers,MKOs,formulas,ASTs and history remain unchanged."
    },
    "label": "Frozen producer metadata; current per-question review is separate below."
  },
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    "review_date": "2026-10-26",
    "owner_authorized_reader_publication": true,
    "scope": "One hundred sixty family prototypes and their mathematical/bilingual reasoning variants, stems, boundary statements and every distinct explanation shape were reviewed in a context independent of the producer; parameter substitutions, source bindings, full math models, both answer strings and every arithmetic step were independently reconstructed per question from the original parameters only, with negative controls. This grouped method does not claim a separate literal AI reading of every repeated sentence or an extra AI voter.",
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}
