{
  "schema_version": "ocme-reviewed-question-reader-v1",
  "question_id": "q-20261013-advance-20261018-r02-natural-divisibility-0096",
  "pilot_number": "R0016-08846",
  "number": 8846,
  "family_id": "qf-ext18-divisibility-transitivity",
  "title": {
    "zh-Hant": "第 8846 題：自然數整除與零邊界",
    "en": "Question 8846: Compose Two Given Natural Divisibility Witnesses"
  },
  "original_question": {
    "schema_version": "ocme-question-v0.1",
    "id": "q-20261013-advance-20261018-r02-natural-divisibility-0096",
    "batch_id": "batch-20261013-advance-20261018-r02-natural-divisibility-foundations",
    "language": "zh-Hant",
    "source_mko_ids": [
      "mko-natural-divisibility"
    ],
    "title_zh": "自然數整除與零邊界",
    "stem_zh": "自然數包含0。操作=divisibility-transitivity；資料={\"a\":2,\"k\":0,\"l\":4}。請依 [a,b,c,k,l,k*l,a_divides_c] 的欄序回答。",
    "answer": {
      "kind": "expression",
      "value": "(2, 0, 0, 0, 4, 0, 是)",
      "explanation_zh": "擴展基礎核對=(2, 0, 0, 0, 4, 0, 是)；依完整明示資料逐欄精確重算；有限／合成資料核對不是一般形式證明；0∣b當且僅當b=0；a∣0對所有自然數a成立。"
    },
    "difficulty": {
      "band": "upper_secondary",
      "level": 3,
      "skills": [
        "自然數整除與零邊界"
      ]
    },
    "variant": {
      "family_id": "qf-ext18-divisibility-transitivity",
      "seed": 202610182096,
      "parameters": {
        "a": 2,
        "k": 0,
        "l": 4,
        "domain": "Nat_divisibility",
        "operation": "divisibility-transitivity",
        "semantic_template": "qf-ext18-divisibility-transitivity/{\"a\":2,\"k\":0,\"l\":4}"
      }
    },
    "verification": {
      "status": "candidate",
      "checks": [
        "producer_exact_finite_arithmetic",
        "producer_source_snapshot_check",
        "producer_substantive_template_deduplication",
        "producer_json_schema"
      ],
      "warning_zh": "僅為產生端候選及自檢；主端須另做驗收，不構成人工審定、普遍證明、Lean執行或形式Evidence。"
    },
    "provenance": {
      "generator_role": "question_producer",
      "generator_model": "model_unknown",
      "generated_at": "2026-10-13",
      "contract_version": "ocme-question-factory-v0.1"
    }
  },
  "original_english_edition": {
    "schema_version": "ocme-question-localization-v0.1",
    "question_id": "q-20261013-advance-20261018-r02-natural-divisibility-0096",
    "batch_id": "batch-20261013-advance-20261018-r02-natural-divisibility-foundations",
    "locale": "en",
    "translation_state": "ai_candidate",
    "source": {
      "question_sha256": "1da0c82ada31da5a9cd8ff0f78f02ac552fd689489bf726238fc5d04f6c9bfa5",
      "family_id": "qf-ext18-divisibility-transitivity",
      "seed": 202610182096,
      "semantic_template": "qf-ext18-divisibility-transitivity/{\"a\":2,\"k\":0,\"l\":4}"
    },
    "fields": {
      "title": "Compose Two Given Natural Divisibility Witnesses",
      "stem": "Natural numbers include 0. Every a divides 0; 0 divides b exactly when b=0. Divisibility witnesses are natural-number multipliers, not approximate quotients. a=2, k=0, l=4; define b=a*k and c=b*l. Give (a, b, c, k, l, k*l, a divides c?).",
      "answer": {
        "kind": "expression",
        "value": "(2, 0, 0, 0, 4, 0, Yes)",
        "explanation": "Multiply the explicit witnesses in the given order and check the resulting exact equality, including zero cases. Exact finite/synthetic checks are not new general formal Evidence. The exact result, retaining the requested order, is (2, 0, 0, 0, 4, 0, Yes)."
      },
      "skills": [
        "Compose Two Given Natural Divisibility Witnesses"
      ],
      "verification_warning": "This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."
    }
  },
  "givens": [
    {
      "id": "G001",
      "text": {
        "zh-Hant": "自然數包含0。操作=divisibility-transitivity；資料={\"a\":2,\"k\":0,\"l\":4}。請依 [a,b,c,k,l,k*l,a_divides_c] 的欄序回答。",
        "en": "Natural numbers include 0. Every a divides 0; 0 divides b exactly when b=0. Divisibility witnesses are natural-number multipliers, not approximate quotients. a=2, k=0, l=4; define b=a*k and c=b*l. Give (a, b, c, k, l, k*l, a divides c?)."
      }
    }
  ],
  "steps": [
    {
      "id": "S001",
      "uses": [
        "G001"
      ],
      "before": "natural numbers include0;b is divisible by a iff b=a*k for some natural k",
      "after": "0 divides only0;every natural divides0",
      "relation": "implies",
      "rule_id": "natural_divisibility_zero_scope",
      "conditions": [],
      "explanation": {
        "zh-Hant": "整除是存在乘數的關係，不先假定除數正或非零；a∣0包含a=0。正因數清單另排除0，兩個問題不混用。",
        "en": "Divisibility is an existential multiplier relation without presuming a positive or nonzero divisor.Every natural,including0,divides0.A positive-divisor inventory separately excludes0."
      },
      "reverse_audit": {
        "kind": "premise_and_result_audit",
        "explanation": {
          "zh-Hant": "回到原始資料與本步條件核對，不把單向推論誤稱等價。",
          "en": "Check against the original data and this step's premises; a one-way implication is not an equivalence."
        }
      },
      "arithmetic": null
    },
    {
      "id": "S002",
      "uses": [
        "G001",
        "S001"
      ],
      "before": "first multiple b=a*k := mul(2, 0)",
      "after": "first multiple b=a*k = 0",
      "relation": "calculation",
      "rule_id": "exact_rational_arithmetic",
      "conditions": [],
      "explanation": {
        "zh-Hant": "依本步的原始操作數與運算順序精確計算；除法前須先核分母非零。",
        "en": "Evaluate exactly with this step's source operands and operation order.Check a denominator is nonzero before division."
      },
      "reverse_audit": {
        "kind": "premise_and_result_audit",
        "explanation": {
          "zh-Hant": "以精確有理數重算 first multiple b=a*k，不以小數近似替代。",
          "en": "Recompute first multiple b=a*k with exact rational arithmetic, not rounded decimals."
        }
      },
      "arithmetic": {
        "operation": "mul",
        "inputs": [
          "2",
          "0"
        ],
        "output": "0",
        "label": "first multiple b=a*k"
      }
    },
    {
      "id": "S003",
      "uses": [
        "G001",
        "S002"
      ],
      "before": "second multiple c=b*l := mul(0, 4)",
      "after": "second multiple c=b*l = 0",
      "relation": "calculation",
      "rule_id": "exact_rational_arithmetic",
      "conditions": [],
      "explanation": {
        "zh-Hant": "依本步的原始操作數與運算順序精確計算；除法前須先核分母非零。",
        "en": "Evaluate exactly with this step's source operands and operation order.Check a denominator is nonzero before division."
      },
      "reverse_audit": {
        "kind": "premise_and_result_audit",
        "explanation": {
          "zh-Hant": "以精確有理數重算 second multiple c=b*l，不以小數近似替代。",
          "en": "Recompute second multiple c=b*l with exact rational arithmetic, not rounded decimals."
        }
      },
      "arithmetic": {
        "operation": "mul",
        "inputs": [
          "0",
          "4"
        ],
        "output": "0",
        "label": "second multiple c=b*l"
      }
    },
    {
      "id": "S004",
      "uses": [
        "G001",
        "S003"
      ],
      "before": "composed multiplier k*l := mul(0, 4)",
      "after": "composed multiplier k*l = 0",
      "relation": "calculation",
      "rule_id": "exact_rational_arithmetic",
      "conditions": [],
      "explanation": {
        "zh-Hant": "依本步的原始操作數與運算順序精確計算；除法前須先核分母非零。",
        "en": "Evaluate exactly with this step's source operands and operation order.Check a denominator is nonzero before division."
      },
      "reverse_audit": {
        "kind": "premise_and_result_audit",
        "explanation": {
          "zh-Hant": "以精確有理數重算 composed multiplier k*l，不以小數近似替代。",
          "en": "Recompute composed multiplier k*l with exact rational arithmetic, not rounded decimals."
        }
      },
      "arithmetic": {
        "operation": "mul",
        "inputs": [
          "0",
          "4"
        ],
        "output": "0",
        "label": "composed multiplier k*l"
      }
    },
    {
      "id": "S005",
      "uses": [
        "G001",
        "S004"
      ],
      "before": "a times composed multiplier := mul(2, 0)",
      "after": "a times composed multiplier = 0",
      "relation": "calculation",
      "rule_id": "exact_rational_arithmetic",
      "conditions": [],
      "explanation": {
        "zh-Hant": "依本步的原始操作數與運算順序精確計算；除法前須先核分母非零。",
        "en": "Evaluate exactly with this step's source operands and operation order.Check a denominator is nonzero before division."
      },
      "reverse_audit": {
        "kind": "premise_and_result_audit",
        "explanation": {
          "zh-Hant": "以精確有理數重算 a times composed multiplier，不以小數近似替代。",
          "en": "Recompute a times composed multiplier with exact rational arithmetic, not rounded decimals."
        }
      },
      "arithmetic": {
        "operation": "mul",
        "inputs": [
          "2",
          "0"
        ],
        "output": "0",
        "label": "a times composed multiplier"
      }
    },
    {
      "id": "S006",
      "uses": [
        "G001",
        "S005"
      ],
      "before": "composed divisibility:divide natural 0 by positive 2",
      "after": "0=0·2+0",
      "relation": "implies",
      "rule_id": "natural_euclidean_division_witness",
      "conditions": [],
      "explanation": {
        "zh-Hant": "正除數給唯一商餘，餘數滿足0≤r<divisor；這個完整等式同時核商與餘數，不作除以0。",
        "en": "A positive divisor gives a unique quotient/remainder with0≤r<divisor.The full equality audits both values without division by zero."
      },
      "reverse_audit": {
        "kind": "premise_and_result_audit",
        "explanation": {
          "zh-Hant": "回到原始資料與本步條件核對，不把單向推論誤稱等價。",
          "en": "Check against the original data and this step's premises; a one-way implication is not an equivalence."
        }
      },
      "arithmetic": {
        "operation": "euclidean_division",
        "inputs": [
          "0",
          "2",
          "0"
        ],
        "output": "0",
        "label": "composed divisibility"
      }
    },
    {
      "id": "S007",
      "uses": [
        "G001",
        "S006"
      ],
      "before": "composed divisibility:a=2;b=0;quotient=0;remainder=0",
      "after": "divides=是;witness/status=0",
      "relation": "implies",
      "rule_id": "positive_divisor_remainder_criterion",
      "conditions": [],
      "explanation": {
        "zh-Hant": "正a下，餘數0時商就是自然乘數見證；非零餘數由商餘唯一性排除整除，不把截斷商當見證。",
        "en": "For positive a,a zero remainder makes the quotient a natural multiplier witness.A nonzero remainder rules out divisibility by uniqueness;the truncated quotient is not a witness."
      },
      "reverse_audit": {
        "kind": "premise_and_result_audit",
        "explanation": {
          "zh-Hant": "回到原始資料與本步條件核對，不把單向推論誤稱等價。",
          "en": "Check against the original data and this step's premises; a one-way implication is not an equivalence."
        }
      },
      "arithmetic": null
    },
    {
      "id": "S008",
      "uses": [
        "G001",
        "S007"
      ],
      "before": "b=a*k=0;c=b*l=0;k*l=0",
      "after": "c=a*(k*l)=0;a divides c=是",
      "relation": "implies",
      "rule_id": "divisibility_compose_given_witnesses",
      "conditions": [],
      "explanation": {
        "zh-Hant": "把兩個實際見證相乘，用乘法結合律得到c=a*(k*l)；零乘數與零a都不需取消或除法。",
        "en": "Compose the two supplied witnesses by multiplication and associativity to get c=a*(k*l).Zero multipliers and a=0 require neither cancellation nor division."
      },
      "reverse_audit": {
        "kind": "premise_and_result_audit",
        "explanation": {
          "zh-Hant": "回到原始資料與本步條件核對，不把單向推論誤稱等價。",
          "en": "Check against the original data and this step's premises; a one-way implication is not an equivalence."
        }
      },
      "arithmetic": null
    }
  ],
  "math_model": {
    "result": [
      2,
      "0",
      "0",
      0,
      4,
      "0",
      true
    ]
  },
  "conclusion": {
    "canonical_value": "(2, 0, 0, 0, 4, 0, 是)",
    "explanation": {
      "zh-Hant": "依上列完整代值及條件核對得到原題答案；原題編號、格式與狀態保持不變。",
      "en": "The full substitutions and premise checks give the original answer; source identity,format and status are unchanged."
    }
  },
  "definition_note": {
    "zh-Hant": "沿用原題明示的論域、假設與來源 MKO 定義。本題已完成第二對話數理與中英語義覆核，並由原始參數逐題獨立重算模型、答案與每個算術步驟；原題仍為 candidate。",
    "en": "Use the original question domain, assumptions and cited MKO definitions. This item has second-context mathematical and bilingual review, with the model, answer and every arithmetic step independently recomputed from the original parameters; the source question remains a candidate."
  },
  "source": {
    "input_commit": "0f7be61e2c22317a4075561dc822c87d881a50db",
    "question_binding": {
      "batch_id": "batch-20261013-advance-20261018-r02-natural-divisibility-foundations",
      "batch_path": "public/data/questions/batches/batch-20261013-advance-20261018-r02-natural-divisibility-foundations/questions.jsonl",
      "batch_sha256": "85abf07ffd0c46a8235728cd1ab694010d535a2683ea0040042f9de7a1360357",
      "original_line": 96,
      "original_line_sha256": "682661e11c1f22e33b9a63f7e260ab01164b81605d99bab1e437f311a355b64d",
      "question_compact_sha256": "1da0c82ada31da5a9cd8ff0f78f02ac552fd689489bf726238fc5d04f6c9bfa5",
      "english_row_compact_sha256": "ac8b01855fd5aa6819738550c0b8c98e9b899032989e4665fcc17ac79a96599c",
      "english_manifest_path": "public/data/i18n/editions/batch-20261013-advance-20261018-r02-natural-divisibility-foundations.en.json",
      "english_rows_path": "public/data/i18n/questions/batch-20261013-advance-20261018-r02-natural-divisibility-foundations.en.jsonl"
    },
    "mko_bindings": {
      "mko-natural-divisibility": {
        "sha256": "2e5d00faa3ae3031b2cb2a650b12db0ab8e8aa1b59a7ea6b2350f49a792758d7",
        "english_sha256": "acae542d73cc84e0fd3fd3443b35f99bca7758dce17f8b8ab65ee9957193e395",
        "original_path": "public/data/mko/natural-divisibility.json",
        "english_path": "public/data/i18n/editions/mko-natural-divisibility.en.json"
      }
    },
    "selected_manifest_sha256": "5233edba9654a6cffd8b6b2d83c932f82ded15f9c0b7c733bd049943e672acff",
    "selected_part_sha256": "8e8954cf690c44da1ec1efa08994a485c73ca8706b7865d854e3f2cdfd4ca89f",
    "original_candidate_sha256": "75f6b713cdea4cb450d124eebf704377bcb93b69865e9be7b9fa17d3f56a6baa",
    "original_candidate_line_sha256": "75f6b713cdea4cb450d124eebf704377bcb93b69865e9be7b9fa17d3f56a6baa"
  },
  "historical_source_state": {
    "review_state": {
      "derivation": "candidate_authored_and_locally_checked",
      "source_question_state": "candidate",
      "independent_AI_or_human_review": "NOT_PERFORMED",
      "formalization": "not_formalized",
      "Lean": "NOT_RUN"
    },
    "scope_note": {
      "zh-Hant": "來源綁定教學推導候選；精確核對不等於獨立AI／人工審查或一般形式證明。原題、答案、MKO、公式、AST與歷史不變。",
      "en": "Source-bound pedagogical derivation candidate.Exact checking is not independent AI/human review or general formal proof.Original questions,answers,MKOs,formulas,ASTs and history remain unchanged."
    },
    "label": "Frozen producer metadata; current per-question review is separate below."
  },
  "revision": {
    "id": "review-20261026-005-p17",
    "review_date": "2026-10-26",
    "owner_authorized_reader_publication": true,
    "scope": "One hundred sixty family prototypes and their mathematical/bilingual reasoning variants, stems, boundary statements and every distinct explanation shape were reviewed in a context independent of the producer; parameter substitutions, source bindings, full math models, both answer strings and every arithmetic step were independently reconstructed per question from the original parameters only, with negative controls. This grouped method does not claim a separate literal AI reading of every repeated sentence or an extra AI voter.",
    "review_receipts": {
      "semantic_review_sha256": "00fcddb10a9fb0f56697308976a52e68e2537472bd8e68ecbe96d3c4553f4ad2",
      "question_first_witness_sha256": "198e04380b2d32aef2375b07ca0df1f8afa454d1184993173fad8a3c9187a3d1"
    },
    "status": "second_context_reviewed",
    "mathematical_semantics": true,
    "bilingual_semantics": true,
    "steps_reviewed": 8,
    "method": "family_template_semantic_review_plus_independent_per_instance_reconstruction",
    "exact_question_first_check": {
      "model_sha256": "d5783fda1b33765bc3801d632fdfc79263cb889f8729b61a2467344dec544c98",
      "arithmetic_steps": 5
    },
    "uses_answer_as_premise": false,
    "human_review": "NOT_PERFORMED",
    "formalization": "not_formalized",
    "Lean": "NOT_RUN",
    "Canonical_truth_promotion": false,
    "authority": "Owner-authorized reviewed reader publication; original question/candidate states remain historical and unchanged."
  }
}
