{
  "schema_version": "ocme-reviewed-question-reader-v1",
  "question_id": "q-20261014-advance-20261031-r04-finite-quotient-ring-0070",
  "pilot_number": "R0030-15970",
  "number": 15970,
  "family_id": "qf-mod31-quotring-multiply",
  "title": {
    "zh-Hant": "第 15970 題：有限商環",
    "en": "Question 15970: Quotient Multiplication Must Respect the Same Ideal"
  },
  "original_question": {
    "schema_version": "ocme-question-v0.1",
    "id": "q-20261014-advance-20261031-r04-finite-quotient-ring-0070",
    "batch_id": "batch-20261014-advance-20261031-r04-finite-quotient-ring-foundations",
    "language": "zh-Hant",
    "source_mko_ids": [
      "mko-finite-quotient-ring"
    ],
    "title_zh": "有限商環",
    "stem_zh": "Z_n與proper雙邊理想的全部加法cosets。操作=quotring-multiply；資料={\"n\":30,\"d\":6,\"a\":19,\"b\":9}。請依 [class_a,class_b,parent_result,result_class,law] 欄序回答。",
    "answer": {
      "kind": "expression",
      "value": "(1, 3, 21, 3, [a][b]=[ab])",
      "explanation_zh": "Wave4收束核對=(1, 3, 21, 3, [a][b]=[ab])；依完整明示資料重算；加法與乘法皆須與代表元選擇無關；排除I=R的zero ring且不宣稱商環為域。"
    },
    "difficulty": {
      "band": "undergraduate_core",
      "level": 3,
      "skills": [
        "有限商環"
      ]
    },
    "variant": {
      "family_id": "qf-mod31-quotring-multiply",
      "seed": 202610314070,
      "parameters": {
        "n": 30,
        "d": 6,
        "a": 19,
        "b": 9,
        "domain": "Exact_quotient_of_Zn_by_proper_ideal",
        "operation": "quotring-multiply",
        "semantic_template": "qf-mod31-quotring-multiply/{\"a\":19,\"b\":9,\"d\":6,\"n\":30}"
      }
    },
    "verification": {
      "status": "candidate",
      "checks": [
        "producer_exact_finite_model",
        "producer_source_snapshot_check",
        "producer_substantive_template_deduplication",
        "producer_json_schema"
      ],
      "warning_zh": "候選須由主端獨立重算；不構成人工審定、一般不可數性／色數最優性／更強機率收斂／商域、optional stopping、Lean或形式Evidence。"
    },
    "provenance": {
      "generator_role": "question_producer",
      "generator_model": "model_unknown",
      "generated_at": "2026-10-14",
      "contract_version": "ocme-question-factory-v0.1"
    }
  },
  "original_english_edition": {
    "schema_version": "ocme-question-localization-v0.1",
    "question_id": "q-20261014-advance-20261031-r04-finite-quotient-ring-0070",
    "batch_id": "batch-20261014-advance-20261031-r04-finite-quotient-ring-foundations",
    "locale": "en",
    "translation_state": "ai_candidate",
    "source": {
      "question_sha256": "e684506a9b4733b2fc66f77f451eab8d382974e2fc14d96e49edf1ded500e478",
      "family_id": "qf-mod31-quotring-multiply",
      "seed": 202610314070,
      "semantic_template": "qf-mod31-quotring-multiply/{\"a\":19,\"b\":9,\"d\":6,\"n\":30}"
    },
    "fields": {
      "title": "Quotient Multiplication Must Respect the Same Ideal",
      "stem": "Use the parent ring Z_30 with residues 0 through 29 and the proper two-sided ideal I of multiples of d=6, where 2≤d≤n and d divides n. Its cosets are residue classes modulo d, ordered by representatives 0 through d−1 with increasing members. The d=n zero ideal is allowed; d=1 gives I=R and is excluded by the project's 1≠0 convention. Retain parent arithmetic modulo n separately from the quotient class label modulo d. No field conclusion follows. Parent representatives a=19, b=9. Give (class_a,class_b,parent_result,result_class,[a][b]=[ab]).",
      "answer": {
        "kind": "expression",
        "value": "(1, 3, 21, 3, [a][b]=[ab])",
        "explanation": "Compute a*b modulo n and then its class modulo d. The two-sided ideal premise makes multiplication well-defined; arbitrary equivalence classes do not automatically inherit it. The exact result, retaining the requested order, is (1, 3, 21, 3, [a][b]=[ab])."
      },
      "skills": [
        "Quotient Multiplication Must Respect the Same Ideal"
      ],
      "verification_warning": "This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."
    }
  },
  "givens": [
    {
      "id": "G001",
      "text": {
        "zh-Hant": "Z_n與proper雙邊理想的全部加法cosets。操作=quotring-multiply；資料={\"n\":30,\"d\":6,\"a\":19,\"b\":9}。請依 [class_a,class_b,parent_result,result_class,law] 欄序回答。",
        "en": "Use the parent ring Z_30 with residues 0 through 29 and the proper two-sided ideal I of multiples of d=6, where 2≤d≤n and d divides n. Its cosets are residue classes modulo d, ordered by representatives 0 through d−1 with increasing members. The d=n zero ideal is allowed; d=1 gives I=R and is excluded by the project's 1≠0 convention. Retain parent arithmetic modulo n separately from the quotient class label modulo d. No field conclusion follows. Parent representatives a=19, b=9. Give (class_a,class_b,parent_result,result_class,[a][b]=[ab])."
      }
    }
  ],
  "steps": [
    {
      "id": "S001",
      "uses": [
        "G001"
      ],
      "before": "quotient ring parent modulus divided by ideal generator := div(30, 6)",
      "after": "quotient ring parent modulus divided by ideal generator = 5",
      "relation": "calculation",
      "rule_id": "exact_rational_arithmetic",
      "conditions": [],
      "explanation": {
        "zh-Hant": "依原始角色及已核中間量精確計算，保留索引、符號、分母與運算所在載體。",
        "en": "Compute exactly from original roles and established intermediates,retaining indices,signs,denominators and the operation's carrier."
      },
      "reverse_audit": {
        "kind": "premise_and_result_audit",
        "explanation": {
          "zh-Hant": "以精確有理數重算 quotient ring parent modulus divided by ideal generator，不以小數近似替代。",
          "en": "Recompute quotient ring parent modulus divided by ideal generator with exact rational arithmetic, not rounded decimals."
        }
      },
      "arithmetic": {
        "operation": "div",
        "inputs": [
          "30",
          "6"
        ],
        "output": "5",
        "label": "quotient ring parent modulus divided by ideal generator"
      }
    },
    {
      "id": "S002",
      "uses": [
        "G001",
        "S001"
      ],
      "before": "same declared parent Z_30;generator d=6;n/d=5;ideal multiples=[0, 6, 12, 18, 24]",
      "after": "I=kernel of residue map Z_30 to Z_6;proper two-sided ideal=是;zero ideal allowed when d=n",
      "relation": "implies",
      "rule_id": "quotient_ring_actual_parent_proper_two_sided_ideal",
      "conditions": [],
      "explanation": {
        "zh-Hant": "因d整除n，整數代表改加n仍不改mod d，π:Z_n→Z_d良定且保加乘。核I由d倍數組成，加法差封閉且左右乘任意母環元素仍在I。d≥2使1不在I，故proper；d=n可得零理想，不把它排除。",
        "en": "Since d divides n,changing an integer representative by n does not change mod d.The map π:Z_n→Z_d is well-defined and preserves addition and multiplication.Its kernel consists of multiples of d,closed under differences and multiplication on either side by parent elements.With d≥2 it excludes1 and is proper;d=n gives the allowed zero ideal."
      },
      "reverse_audit": {
        "kind": "premise_and_result_audit",
        "explanation": {
          "zh-Hant": "回到原始資料與本步條件核對，不把單向推論誤稱等價。",
          "en": "Check against the original data and this step's premises; a one-way implication is not an equivalence."
        }
      },
      "arithmetic": null
    },
    {
      "id": "S003",
      "uses": [
        "G001",
        "S002"
      ],
      "before": "complete parent residues=[0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29];same ideal I=[0, 6, 12, 18, 24]",
      "after": "all additive cosets in representative order0..d-1=[[0, 6, 12, 18, 24], [1, 7, 13, 19, 25], [2, 8, 14, 20, 26], [3, 9, 15, 21, 27], [4, 10, 16, 22, 28], [5, 11, 17, 23, 29]];quotient size=6;no field conclusion",
      "relation": "implies",
      "rule_id": "quotient_ring_full_cosets_not_representative_carrier",
      "conditions": [],
      "explanation": {
        "zh-Hant": "每個加法coset列全體同餘mod d的母環元素，按代表0..d−1排序；它們互斥且覆蓋Z_n。商元素是整類，輸出class標籤只是索引，不因有限商環就宣稱域。",
        "en": "List every parent element congruent mod d in each additive coset,ordered by representatives0 through d−1.They are disjoint and cover Z_n.Quotient elements are whole cosets;class labels are indices only,and a finite quotient ring is not automatically a field."
      },
      "reverse_audit": {
        "kind": "premise_and_result_audit",
        "explanation": {
          "zh-Hant": "回到原始資料與本步條件核對，不把單向推論誤稱等價。",
          "en": "Check against the original data and this step's premises; a one-way implication is not an equivalence."
        }
      },
      "arithmetic": null
    },
    {
      "id": "S004",
      "uses": [
        "G001",
        "S003"
      ],
      "before": "first input coset exact quotient fraction := div(19, 6)",
      "after": "first input coset exact quotient fraction = 19/6",
      "relation": "calculation",
      "rule_id": "exact_rational_arithmetic",
      "conditions": [],
      "explanation": {
        "zh-Hant": "依原始角色及已核中間量精確計算，保留索引、符號、分母與運算所在載體。",
        "en": "Compute exactly from original roles and established intermediates,retaining indices,signs,denominators and the operation's carrier."
      },
      "reverse_audit": {
        "kind": "premise_and_result_audit",
        "explanation": {
          "zh-Hant": "以精確有理數重算 first input coset exact quotient fraction，不以小數近似替代。",
          "en": "Recompute first input coset exact quotient fraction with exact rational arithmetic, not rounded decimals."
        }
      },
      "arithmetic": {
        "operation": "div",
        "inputs": [
          "19",
          "6"
        ],
        "output": "19/6",
        "label": "first input coset exact quotient fraction"
      }
    },
    {
      "id": "S005",
      "uses": [
        "G001",
        "S004"
      ],
      "before": "first input coset:integer value=19;positive modulus=6;exact ratio=19/6",
      "after": "floor quotient=3;quotient<=ratio<quotient+1",
      "relation": "implies",
      "rule_id": "modular_Euclidean_floor_not_rational_division_result",
      "conditions": [],
      "explanation": {
        "zh-Hant": "先取有理商再取向下整數商q，不能把有理除法本身當餘數；正模數下q≤value/m<q+1，故後續減去qm得到0至m−1。",
        "en": "Take the exact rational quotient and its floor q,not the rational division result as a residue.With positive modulus,q≤value/m<q+1,so subtraction of qm yields a residue from0 through m−1."
      },
      "reverse_audit": {
        "kind": "premise_and_result_audit",
        "explanation": {
          "zh-Hant": "回到原始資料與本步條件核對，不把單向推論誤稱等價。",
          "en": "Check against the original data and this step's premises; a one-way implication is not an equivalence."
        }
      },
      "arithmetic": null
    },
    {
      "id": "S006",
      "uses": [
        "G001",
        "S005"
      ],
      "before": "first input coset quotient multiple := mul(3, 6)",
      "after": "first input coset quotient multiple = 18",
      "relation": "calculation",
      "rule_id": "exact_rational_arithmetic",
      "conditions": [],
      "explanation": {
        "zh-Hant": "依原始角色及已核中間量精確計算，保留索引、符號、分母與運算所在載體。",
        "en": "Compute exactly from original roles and established intermediates,retaining indices,signs,denominators and the operation's carrier."
      },
      "reverse_audit": {
        "kind": "premise_and_result_audit",
        "explanation": {
          "zh-Hant": "以精確有理數重算 first input coset quotient multiple，不以小數近似替代。",
          "en": "Recompute first input coset quotient multiple with exact rational arithmetic, not rounded decimals."
        }
      },
      "arithmetic": {
        "operation": "mul",
        "inputs": [
          "3",
          "6"
        ],
        "output": "18",
        "label": "first input coset quotient multiple"
      }
    },
    {
      "id": "S007",
      "uses": [
        "G001",
        "S006"
      ],
      "before": "first input coset canonical nonnegative residue := sub(19, 18)",
      "after": "first input coset canonical nonnegative residue = 1",
      "relation": "calculation",
      "rule_id": "exact_rational_arithmetic",
      "conditions": [],
      "explanation": {
        "zh-Hant": "依原始角色及已核中間量精確計算，保留索引、符號、分母與運算所在載體。",
        "en": "Compute exactly from original roles and established intermediates,retaining indices,signs,denominators and the operation's carrier."
      },
      "reverse_audit": {
        "kind": "premise_and_result_audit",
        "explanation": {
          "zh-Hant": "以精確有理數重算 first input coset canonical nonnegative residue，不以小數近似替代。",
          "en": "Recompute first input coset canonical nonnegative residue with exact rational arithmetic, not rounded decimals."
        }
      },
      "arithmetic": {
        "operation": "sub",
        "inputs": [
          "19",
          "18"
        ],
        "output": "1",
        "label": "first input coset canonical nonnegative residue"
      }
    },
    {
      "id": "S008",
      "uses": [
        "G001",
        "S007"
      ],
      "before": "second input coset exact quotient fraction := div(9, 6)",
      "after": "second input coset exact quotient fraction = 3/2",
      "relation": "calculation",
      "rule_id": "exact_rational_arithmetic",
      "conditions": [],
      "explanation": {
        "zh-Hant": "依原始角色及已核中間量精確計算，保留索引、符號、分母與運算所在載體。",
        "en": "Compute exactly from original roles and established intermediates,retaining indices,signs,denominators and the operation's carrier."
      },
      "reverse_audit": {
        "kind": "premise_and_result_audit",
        "explanation": {
          "zh-Hant": "以精確有理數重算 second input coset exact quotient fraction，不以小數近似替代。",
          "en": "Recompute second input coset exact quotient fraction with exact rational arithmetic, not rounded decimals."
        }
      },
      "arithmetic": {
        "operation": "div",
        "inputs": [
          "9",
          "6"
        ],
        "output": "3/2",
        "label": "second input coset exact quotient fraction"
      }
    },
    {
      "id": "S009",
      "uses": [
        "G001",
        "S008"
      ],
      "before": "second input coset:integer value=9;positive modulus=6;exact ratio=3/2",
      "after": "floor quotient=1;quotient<=ratio<quotient+1",
      "relation": "implies",
      "rule_id": "modular_Euclidean_floor_not_rational_division_result",
      "conditions": [],
      "explanation": {
        "zh-Hant": "先取有理商再取向下整數商q，不能把有理除法本身當餘數；正模數下q≤value/m<q+1，故後續減去qm得到0至m−1。",
        "en": "Take the exact rational quotient and its floor q,not the rational division result as a residue.With positive modulus,q≤value/m<q+1,so subtraction of qm yields a residue from0 through m−1."
      },
      "reverse_audit": {
        "kind": "premise_and_result_audit",
        "explanation": {
          "zh-Hant": "回到原始資料與本步條件核對，不把單向推論誤稱等價。",
          "en": "Check against the original data and this step's premises; a one-way implication is not an equivalence."
        }
      },
      "arithmetic": null
    },
    {
      "id": "S010",
      "uses": [
        "G001",
        "S009"
      ],
      "before": "second input coset quotient multiple := mul(1, 6)",
      "after": "second input coset quotient multiple = 6",
      "relation": "calculation",
      "rule_id": "exact_rational_arithmetic",
      "conditions": [],
      "explanation": {
        "zh-Hant": "依原始角色及已核中間量精確計算，保留索引、符號、分母與運算所在載體。",
        "en": "Compute exactly from original roles and established intermediates,retaining indices,signs,denominators and the operation's carrier."
      },
      "reverse_audit": {
        "kind": "premise_and_result_audit",
        "explanation": {
          "zh-Hant": "以精確有理數重算 second input coset quotient multiple，不以小數近似替代。",
          "en": "Recompute second input coset quotient multiple with exact rational arithmetic, not rounded decimals."
        }
      },
      "arithmetic": {
        "operation": "mul",
        "inputs": [
          "1",
          "6"
        ],
        "output": "6",
        "label": "second input coset quotient multiple"
      }
    },
    {
      "id": "S011",
      "uses": [
        "G001",
        "S010"
      ],
      "before": "second input coset canonical nonnegative residue := sub(9, 6)",
      "after": "second input coset canonical nonnegative residue = 3",
      "relation": "calculation",
      "rule_id": "exact_rational_arithmetic",
      "conditions": [],
      "explanation": {
        "zh-Hant": "依原始角色及已核中間量精確計算，保留索引、符號、分母與運算所在載體。",
        "en": "Compute exactly from original roles and established intermediates,retaining indices,signs,denominators and the operation's carrier."
      },
      "reverse_audit": {
        "kind": "premise_and_result_audit",
        "explanation": {
          "zh-Hant": "以精確有理數重算 second input coset canonical nonnegative residue，不以小數近似替代。",
          "en": "Recompute second input coset canonical nonnegative residue with exact rational arithmetic, not rounded decimals."
        }
      },
      "arithmetic": {
        "operation": "sub",
        "inputs": [
          "9",
          "6"
        ],
        "output": "3",
        "label": "second input coset canonical nonnegative residue"
      }
    },
    {
      "id": "S012",
      "uses": [
        "G001",
        "S011"
      ],
      "before": "selected quotient operation integer multiplication := mul(19, 9)",
      "after": "selected quotient operation integer multiplication = 171",
      "relation": "calculation",
      "rule_id": "exact_rational_arithmetic",
      "conditions": [],
      "explanation": {
        "zh-Hant": "依原始角色及已核中間量精確計算，保留索引、符號、分母與運算所在載體。",
        "en": "Compute exactly from original roles and established intermediates,retaining indices,signs,denominators and the operation's carrier."
      },
      "reverse_audit": {
        "kind": "premise_and_result_audit",
        "explanation": {
          "zh-Hant": "以精確有理數重算 selected quotient operation integer multiplication，不以小數近似替代。",
          "en": "Recompute selected quotient operation integer multiplication with exact rational arithmetic, not rounded decimals."
        }
      },
      "arithmetic": {
        "operation": "mul",
        "inputs": [
          "19",
          "9"
        ],
        "output": "171",
        "label": "selected quotient operation integer multiplication"
      }
    },
    {
      "id": "S013",
      "uses": [
        "G001",
        "S012"
      ],
      "before": "selected quotient operation parent mod n exact quotient fraction := div(171, 30)",
      "after": "selected quotient operation parent mod n exact quotient fraction = 57/10",
      "relation": "calculation",
      "rule_id": "exact_rational_arithmetic",
      "conditions": [],
      "explanation": {
        "zh-Hant": "依原始角色及已核中間量精確計算，保留索引、符號、分母與運算所在載體。",
        "en": "Compute exactly from original roles and established intermediates,retaining indices,signs,denominators and the operation's carrier."
      },
      "reverse_audit": {
        "kind": "premise_and_result_audit",
        "explanation": {
          "zh-Hant": "以精確有理數重算 selected quotient operation parent mod n exact quotient fraction，不以小數近似替代。",
          "en": "Recompute selected quotient operation parent mod n exact quotient fraction with exact rational arithmetic, not rounded decimals."
        }
      },
      "arithmetic": {
        "operation": "div",
        "inputs": [
          "171",
          "30"
        ],
        "output": "57/10",
        "label": "selected quotient operation parent mod n exact quotient fraction"
      }
    },
    {
      "id": "S014",
      "uses": [
        "G001",
        "S013"
      ],
      "before": "selected quotient operation parent mod n:integer value=171;positive modulus=30;exact ratio=57/10",
      "after": "floor quotient=5;quotient<=ratio<quotient+1",
      "relation": "implies",
      "rule_id": "modular_Euclidean_floor_not_rational_division_result",
      "conditions": [],
      "explanation": {
        "zh-Hant": "先取有理商再取向下整數商q，不能把有理除法本身當餘數；正模數下q≤value/m<q+1，故後續減去qm得到0至m−1。",
        "en": "Take the exact rational quotient and its floor q,not the rational division result as a residue.With positive modulus,q≤value/m<q+1,so subtraction of qm yields a residue from0 through m−1."
      },
      "reverse_audit": {
        "kind": "premise_and_result_audit",
        "explanation": {
          "zh-Hant": "回到原始資料與本步條件核對，不把單向推論誤稱等價。",
          "en": "Check against the original data and this step's premises; a one-way implication is not an equivalence."
        }
      },
      "arithmetic": null
    },
    {
      "id": "S015",
      "uses": [
        "G001",
        "S014"
      ],
      "before": "selected quotient operation parent mod n quotient multiple := mul(5, 30)",
      "after": "selected quotient operation parent mod n quotient multiple = 150",
      "relation": "calculation",
      "rule_id": "exact_rational_arithmetic",
      "conditions": [],
      "explanation": {
        "zh-Hant": "依原始角色及已核中間量精確計算，保留索引、符號、分母與運算所在載體。",
        "en": "Compute exactly from original roles and established intermediates,retaining indices,signs,denominators and the operation's carrier."
      },
      "reverse_audit": {
        "kind": "premise_and_result_audit",
        "explanation": {
          "zh-Hant": "以精確有理數重算 selected quotient operation parent mod n quotient multiple，不以小數近似替代。",
          "en": "Recompute selected quotient operation parent mod n quotient multiple with exact rational arithmetic, not rounded decimals."
        }
      },
      "arithmetic": {
        "operation": "mul",
        "inputs": [
          "5",
          "30"
        ],
        "output": "150",
        "label": "selected quotient operation parent mod n quotient multiple"
      }
    },
    {
      "id": "S016",
      "uses": [
        "G001",
        "S015"
      ],
      "before": "selected quotient operation parent mod n canonical nonnegative residue := sub(171, 150)",
      "after": "selected quotient operation parent mod n canonical nonnegative residue = 21",
      "relation": "calculation",
      "rule_id": "exact_rational_arithmetic",
      "conditions": [],
      "explanation": {
        "zh-Hant": "依原始角色及已核中間量精確計算，保留索引、符號、分母與運算所在載體。",
        "en": "Compute exactly from original roles and established intermediates,retaining indices,signs,denominators and the operation's carrier."
      },
      "reverse_audit": {
        "kind": "premise_and_result_audit",
        "explanation": {
          "zh-Hant": "以精確有理數重算 selected quotient operation parent mod n canonical nonnegative residue，不以小數近似替代。",
          "en": "Recompute selected quotient operation parent mod n canonical nonnegative residue with exact rational arithmetic, not rounded decimals."
        }
      },
      "arithmetic": {
        "operation": "sub",
        "inputs": [
          "171",
          "150"
        ],
        "output": "21",
        "label": "selected quotient operation parent mod n canonical nonnegative residue"
      }
    },
    {
      "id": "S017",
      "uses": [
        "G001",
        "S016"
      ],
      "before": "selected quotient operation quotient class mod d exact quotient fraction := div(21, 6)",
      "after": "selected quotient operation quotient class mod d exact quotient fraction = 7/2",
      "relation": "calculation",
      "rule_id": "exact_rational_arithmetic",
      "conditions": [],
      "explanation": {
        "zh-Hant": "依原始角色及已核中間量精確計算，保留索引、符號、分母與運算所在載體。",
        "en": "Compute exactly from original roles and established intermediates,retaining indices,signs,denominators and the operation's carrier."
      },
      "reverse_audit": {
        "kind": "premise_and_result_audit",
        "explanation": {
          "zh-Hant": "以精確有理數重算 selected quotient operation quotient class mod d exact quotient fraction，不以小數近似替代。",
          "en": "Recompute selected quotient operation quotient class mod d exact quotient fraction with exact rational arithmetic, not rounded decimals."
        }
      },
      "arithmetic": {
        "operation": "div",
        "inputs": [
          "21",
          "6"
        ],
        "output": "7/2",
        "label": "selected quotient operation quotient class mod d exact quotient fraction"
      }
    },
    {
      "id": "S018",
      "uses": [
        "G001",
        "S017"
      ],
      "before": "selected quotient operation quotient class mod d:integer value=21;positive modulus=6;exact ratio=7/2",
      "after": "floor quotient=3;quotient<=ratio<quotient+1",
      "relation": "implies",
      "rule_id": "modular_Euclidean_floor_not_rational_division_result",
      "conditions": [],
      "explanation": {
        "zh-Hant": "先取有理商再取向下整數商q，不能把有理除法本身當餘數；正模數下q≤value/m<q+1，故後續減去qm得到0至m−1。",
        "en": "Take the exact rational quotient and its floor q,not the rational division result as a residue.With positive modulus,q≤value/m<q+1,so subtraction of qm yields a residue from0 through m−1."
      },
      "reverse_audit": {
        "kind": "premise_and_result_audit",
        "explanation": {
          "zh-Hant": "回到原始資料與本步條件核對，不把單向推論誤稱等價。",
          "en": "Check against the original data and this step's premises; a one-way implication is not an equivalence."
        }
      },
      "arithmetic": null
    },
    {
      "id": "S019",
      "uses": [
        "G001",
        "S018"
      ],
      "before": "selected quotient operation quotient class mod d quotient multiple := mul(3, 6)",
      "after": "selected quotient operation quotient class mod d quotient multiple = 18",
      "relation": "calculation",
      "rule_id": "exact_rational_arithmetic",
      "conditions": [],
      "explanation": {
        "zh-Hant": "依原始角色及已核中間量精確計算，保留索引、符號、分母與運算所在載體。",
        "en": "Compute exactly from original roles and established intermediates,retaining indices,signs,denominators and the operation's carrier."
      },
      "reverse_audit": {
        "kind": "premise_and_result_audit",
        "explanation": {
          "zh-Hant": "以精確有理數重算 selected quotient operation quotient class mod d quotient multiple，不以小數近似替代。",
          "en": "Recompute selected quotient operation quotient class mod d quotient multiple with exact rational arithmetic, not rounded decimals."
        }
      },
      "arithmetic": {
        "operation": "mul",
        "inputs": [
          "3",
          "6"
        ],
        "output": "18",
        "label": "selected quotient operation quotient class mod d quotient multiple"
      }
    },
    {
      "id": "S020",
      "uses": [
        "G001",
        "S019"
      ],
      "before": "selected quotient operation quotient class mod d canonical nonnegative residue := sub(21, 18)",
      "after": "selected quotient operation quotient class mod d canonical nonnegative residue = 3",
      "relation": "calculation",
      "rule_id": "exact_rational_arithmetic",
      "conditions": [],
      "explanation": {
        "zh-Hant": "依原始角色及已核中間量精確計算，保留索引、符號、分母與運算所在載體。",
        "en": "Compute exactly from original roles and established intermediates,retaining indices,signs,denominators and the operation's carrier."
      },
      "reverse_audit": {
        "kind": "premise_and_result_audit",
        "explanation": {
          "zh-Hant": "以精確有理數重算 selected quotient operation quotient class mod d canonical nonnegative residue，不以小數近似替代。",
          "en": "Recompute selected quotient operation quotient class mod d canonical nonnegative residue with exact rational arithmetic, not rounded decimals."
        }
      },
      "arithmetic": {
        "operation": "sub",
        "inputs": [
          "21",
          "18"
        ],
        "output": "3",
        "label": "selected quotient operation quotient class mod d canonical nonnegative residue"
      }
    },
    {
      "id": "S021",
      "uses": [
        "G001",
        "S020"
      ],
      "before": "selected quotient operation:original parent representatives=[19, 9];integer result=171;parent modulus=30",
      "after": "parent result=21;quotient class label=3;class modulus=6",
      "relation": "implies",
      "rule_id": "quotient_operation_parent_result_separate_from_class",
      "conditions": [],
      "explanation": {
        "zh-Hant": "先在指定母環mod n運算，再取mod d的商類；兩層欄位可能不同，不可跳成同一個餘數，也不能把標籤當商元素全體內容。",
        "en": "Operate in the specified parent modulo n,then take the quotient class modulo d.These fields can differ;do not conflate their residues or confuse a class label with its full coset."
      },
      "reverse_audit": {
        "kind": "premise_and_result_audit",
        "explanation": {
          "zh-Hant": "回到原始資料與本步條件核對，不把單向推論誤稱等價。",
          "en": "Check against the original data and this step's premises; a one-way implication is not an equivalence."
        }
      },
      "arithmetic": null
    },
    {
      "id": "S022",
      "uses": [
        "G001",
        "S021"
      ],
      "before": "same parent Z_30;same proper two-sided ideal I=[0, 6, 12, 18, 24];input class labels=[1, 3]",
      "after": "quotient operation law=[a][b]=[ab];result class label=3",
      "relation": "implies",
      "rule_id": "quotient_ring_operation_uses_ideal_not_arbitrary_equivalence",
      "conditions": [],
      "explanation": {
        "zh-Hant": "加法陪集來自加法子群；乘法亦須兩側理想吸收才能與代表無關。本題在已核同一理想下用這條法則，不由任意商集合自動引入運算。",
        "en": "Additive cosets use the additive subgroup,but multiplication also requires the two-sided ideal absorption for representative independence.Apply the law under this same qualified ideal,not to arbitrary quotient sets."
      },
      "reverse_audit": {
        "kind": "premise_and_result_audit",
        "explanation": {
          "zh-Hant": "回到原始資料與本步條件核對，不把單向推論誤稱等價。",
          "en": "Check against the original data and this step's premises; a one-way implication is not an equivalence."
        }
      },
      "arithmetic": null
    }
  ],
  "math_model": {
    "result": [
      1,
      3,
      21,
      3,
      "[a][b]=[ab]"
    ]
  },
  "conclusion": {
    "canonical_value": "(1, 3, 21, 3, [a][b]=[ab])",
    "explanation": {
      "zh-Hant": "依上列完整代值及條件核對得到原題答案；原題編號、格式與狀態保持不變。",
      "en": "The full substitutions and premise checks give the original answer; source identity,format and status are unchanged."
    }
  },
  "definition_note": {
    "zh-Hant": "沿用原題明示的論域、假設與來源 MKO 定義。本題已完成第二對話數理與中英語義覆核，並由原始參數逐題獨立重算模型、答案與每個算術步驟；原題仍為 candidate。",
    "en": "Use the original question domain, assumptions and cited MKO definitions. This item has second-context mathematical and bilingual review, with the model, answer and every arithmetic step independently recomputed from the original parameters; the source question remains a candidate."
  },
  "source": {
    "input_commit": "0f7be61e2c22317a4075561dc822c87d881a50db",
    "question_binding": {
      "batch_id": "batch-20261014-advance-20261031-r04-finite-quotient-ring-foundations",
      "batch_path": "public/data/questions/batches/batch-20261014-advance-20261031-r04-finite-quotient-ring-foundations/questions.jsonl",
      "batch_sha256": "990159f2eda0c7cd420834e0b7b4b5b70e6cde01e33924c6340b2b0b90b0d4f8",
      "original_line": 70,
      "original_line_sha256": "c8e7bd11686f8e2e9bba3674b92dc5ebbe148937cbf8e7462d4198ee0ed7a8c2",
      "question_compact_sha256": "e684506a9b4733b2fc66f77f451eab8d382974e2fc14d96e49edf1ded500e478",
      "english_row_compact_sha256": "e31f182ade5cf5c178cf6b2d4c7e72e7237bf7d52821473f91ac0f064c0305b2",
      "english_manifest_path": "public/data/i18n/editions/batch-20261014-advance-20261031-r04-finite-quotient-ring-foundations.en.json",
      "english_rows_path": "public/data/i18n/questions/batch-20261014-advance-20261031-r04-finite-quotient-ring-foundations.en.jsonl"
    },
    "mko_bindings": {
      "mko-finite-quotient-ring": {
        "sha256": "8c2b45b38428b422d01b869c06eaca3a0db6e14e6fafc691ef583d4614d39216",
        "english_sha256": "b144945c75f4a276442029de263e7ef036043832247b0b951049af0cc80623fa",
        "original_path": "public/data/mko/finite-quotient-ring.json",
        "english_path": "public/data/i18n/editions/mko-finite-quotient-ring.en.json"
      }
    },
    "selected_manifest_sha256": "5233edba9654a6cffd8b6b2d83c932f82ded15f9c0b7c733bd049943e672acff",
    "selected_part_sha256": "d85118d74859ec7e59736714f767732c6ec092eaa0bf5279abeb28e4a628e3c3",
    "original_candidate_sha256": "44803e6670adcecffa46a7c8a80ef7c62c9ab33552f34ab1b611ad2dca76bc48",
    "original_candidate_line_sha256": "44803e6670adcecffa46a7c8a80ef7c62c9ab33552f34ab1b611ad2dca76bc48"
  },
  "historical_source_state": {
    "review_state": {
      "derivation": "candidate_authored_and_locally_checked",
      "source_question_state": "candidate",
      "independent_AI_or_human_review": "NOT_PERFORMED",
      "formalization": "not_formalized",
      "Lean": "NOT_RUN"
    },
    "scope_note": {
      "zh-Hant": "來源綁定教學推導候選；精確核對不等於獨立AI／人工審查或一般形式證明。原題、答案、MKO、公式、AST與歷史不變。",
      "en": "Source-bound pedagogical derivation candidate.Exact checking is not independent AI/human review or general formal proof.Original questions,answers,MKOs,formulas,ASTs and history remain unchanged."
    },
    "label": "Frozen producer metadata; current per-question review is separate below."
  },
  "revision": {
    "id": "review-20261026-007-p31",
    "review_date": "2026-10-26",
    "owner_authorized_reader_publication": true,
    "scope": "One hundred sixty family prototypes and their mathematical/bilingual reasoning variants, stems, boundary statements and every distinct explanation shape were reviewed in a context independent of the producer; parameter substitutions, source bindings, full math models, both answer strings and every arithmetic step were independently reconstructed per question from the original parameters only, with negative controls. This grouped method does not claim a separate literal AI reading of every repeated sentence or an extra AI voter.",
    "review_receipts": {
      "semantic_review_sha256": "73bc08066ffb1a81eacb2d4e288d03f522aeefd3949fa0d97da41b484ed737bc",
      "question_first_witness_sha256": "ac120452a208b257b8270f38351a09dcd832cdbc8d9db6b69933f83e43cc9336"
    },
    "status": "second_context_reviewed",
    "mathematical_semantics": true,
    "bilingual_semantics": true,
    "steps_reviewed": 22,
    "method": "family_template_semantic_review_plus_independent_per_instance_reconstruction",
    "exact_question_first_check": {
      "model_sha256": "59b24a491d8ef06dbad19d23c879bc052a27fdc5626516352fce9aef83071b9e",
      "arithmetic_steps": 14
    },
    "uses_answer_as_premise": false,
    "human_review": "NOT_PERFORMED",
    "formalization": "not_formalized",
    "Lean": "NOT_RUN",
    "Canonical_truth_promotion": false,
    "authority": "Owner-authorized reviewed reader publication; original question/candidate states remain historical and unchanged."
  }
}
