{
  "schema_version": "ocme-reviewed-question-reader-v1",
  "question_id": "q-20261014-advance-20261107-r02-supremum-and-infimum-0070",
  "pilot_number": "R0040-20545",
  "number": 20545,
  "family_id": "qf-mod38-supinf-lower-bound-greatestness",
  "title": {
    "zh-Hant": "第 20545 題：上確界與下確界",
    "en": "Question 20545: A Lower Bound Still Needs Greatestness to Be the Infimum"
  },
  "original_question": {
    "schema_version": "ocme-question-v0.1",
    "id": "q-20261014-advance-20261107-r02-supremum-and-infimum-0070",
    "batch_id": "batch-20261014-advance-20261107-r02-supremum-and-infimum-foundations",
    "language": "zh-Hant",
    "source_mko_ids": [
      "mko-supremum-and-infimum"
    ],
    "title_zh": "上確界與下確界",
    "stem_zh": "非空且相應有界的實值集合或明示有界開區間。操作=supinf-lower-bound-greatestness；資料={\"values\":[[20,21],[-21,22],[41,23]],\"candidate\":[-21,22]}。請依 exact_ordered_tuple_declared_by_interface 欄序回答。",
    "answer": {
      "kind": "expression",
      "value": "(-21/22, 是, -21/22, 是, lower_bound_and_greatestness_are_separate)",
      "explanation_zh": "Wave6根層核對=(-21/22, 是, -21/22, 是, lower_bound_and_greatestness_are_separate)；依完整明示資料獨立重算；sup同時是上界與最小上界，inf對偶；兩項責任不可省略；sup與inf不必屬於集合，只有取到時才是maximum或minimum；空集與無界集另處理。"
    },
    "difficulty": {
      "band": "undergraduate_core",
      "level": 3,
      "skills": [
        "上確界與下確界"
      ]
    },
    "variant": {
      "family_id": "qf-mod38-supinf-lower-bound-greatestness",
      "seed": 202611072070,
      "parameters": {
        "values": [
          [
            20,
            21
          ],
          [
            -21,
            22
          ],
          [
            41,
            23
          ]
        ],
        "candidate": [
          -21,
          22
        ],
        "domain": "Exact_bounded_real_set_extrema",
        "operation": "supinf-lower-bound-greatestness",
        "semantic_template": "qf-mod38-supinf-lower-bound-greatestness/{\"candidate\":[-21,22],\"values\":[[20,21],[-21,22],[41,23]]}"
      }
    },
    "verification": {
      "status": "candidate",
      "checks": [
        "producer_exact_finite_or_symbolic_model",
        "producer_source_snapshot_check",
        "producer_substantive_template_deduplication",
        "producer_json_schema"
      ],
      "warning_zh": "候選須主端重算；不構成人工審定、有限sample群作用、sup等於max、basis等於subbasis、signed Markov、pigeonhole converse、nonunit Euler、finite-prefix subsequence、Lean或Evidence。"
    },
    "provenance": {
      "generator_role": "question_producer",
      "generator_model": "model_unknown",
      "generated_at": "2026-10-14",
      "contract_version": "ocme-question-factory-v0.1"
    }
  },
  "original_english_edition": {
    "schema_version": "ocme-question-localization-v0.1",
    "question_id": "q-20261014-advance-20261107-r02-supremum-and-infimum-0070",
    "batch_id": "batch-20261014-advance-20261107-r02-supremum-and-infimum-foundations",
    "locale": "en",
    "translation_state": "ai_candidate",
    "source": {
      "question_sha256": "311fc4a80ebed541c1f4f1de56289b0bbc63eafb9cabcebed0dfa14d59e3d491",
      "family_id": "qf-mod38-supinf-lower-bound-greatestness",
      "seed": 202611072070,
      "semantic_template": "qf-mod38-supinf-lower-bound-greatestness/{\"candidate\":[-21,22],\"values\":[[20,21],[-21,22],[41,23]]}"
    },
    "fields": {
      "title": "A Lower Bound Still Needs Greatestness to Be the Infimum",
      "stem": "The ordered rational values=[20/21, -21/22, 41/23] denote a complete nonempty finite real set. Duplicate listed values do not change its bounds; retain supplied order in the output. Empty, unbounded and extended-real sets are outside this slice. Candidate=-21/22. Give (candidate, is_lower_bound, infimum, equals_infimum, boundary).",
      "answer": {
        "kind": "expression",
        "value": "(-21/22, Yes, -21/22, Yes, lower_bound_and_greatestness_are_separate)",
        "explanation": "Check every value is at least the candidate, then separately compare it with the exact infimum. A smaller lower bound is not the greatest lower bound. The exact result, retaining the requested order, is (-21/22, Yes, -21/22, Yes, lower_bound_and_greatestness_are_separate)."
      },
      "skills": [
        "A Lower Bound Still Needs Greatestness to Be the Infimum"
      ],
      "verification_warning": "This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."
    }
  },
  "givens": [
    {
      "id": "G001",
      "text": {
        "zh-Hant": "非空且相應有界的實值集合或明示有界開區間。操作=supinf-lower-bound-greatestness；資料={\"values\":[[20,21],[-21,22],[41,23]],\"candidate\":[-21,22]}。請依 exact_ordered_tuple_declared_by_interface 欄序回答。",
        "en": "The ordered rational values=[20/21, -21/22, 41/23] denote a complete nonempty finite real set. Duplicate listed values do not change its bounds; retain supplied order in the output. Empty, unbounded and extended-real sets are outside this slice. Candidate=-21/22. Give (candidate, is_lower_bound, infimum, equals_infimum, boundary)."
      }
    }
  ],
  "steps": [
    {
      "id": "S001",
      "uses": [
        "G001"
      ],
      "before": "source operation=supinf-lower-bound-greatestness;original snapshot and mathematics retained",
      "after": "explicit ordered source output fields=[candidate, is_lower_bound, infimum, equals_infimum, boundary]",
      "relation": "implies",
      "rule_id": "source_ordered_interface_explicit_without_javascript",
      "conditions": [],
      "explanation": {
        "zh-Hant": "原題快照保留歷史介面標記；本頁直接列來源欄位順序，不需JavaScript或外部表。標籤不自動是數學證據，No保持來源的聲稱範圍。",
        "en": "Keep the historical interface marker in the original snapshot while listing source fields here without JavaScript or external lookup.Labels are not mathematical evidence,and No retains its source claim scope."
      },
      "reverse_audit": {
        "kind": "premise_and_result_audit",
        "explanation": {
          "zh-Hant": "回到原始資料與本步條件核對，不把單向推論誤稱等價。",
          "en": "Check against the original data and this step's premises; a one-way implication is not an equivalence."
        }
      },
      "arithmetic": null
    },
    {
      "id": "S002",
      "uses": [
        "G001",
        "S001"
      ],
      "before": "ORIGINAL complete ordered nonempty finite real-value list=[20/21, -21/22, 41/23]",
      "after": "initialize upper/lower extremum candidates at ORIGINAL first value;duplicates retained and do not change set bounds",
      "relation": "implies",
      "rule_id": "supinf_complete_nonempty_finite_set_not_samples_or_sorting",
      "conditions": [],
      "explanation": {
        "zh-Hant": "這是完整有限集合的給定列表，不是未知集合的有限取樣。重複值可出現但不改sup/inf，輸出仍按原順序保留，不先排序資料。",
        "en": "This is the supplied complete finite set list,not a sample of an unspecified set.Duplicates do not alter bounds but remain in original output order;do not sort the data first."
      },
      "reverse_audit": {
        "kind": "premise_and_result_audit",
        "explanation": {
          "zh-Hant": "回到原始資料與本步條件核對，不把單向推論誤稱等價。",
          "en": "Check against the original data and this step's premises; a one-way implication is not an equivalence."
        }
      },
      "arithmetic": null
    },
    {
      "id": "S003",
      "uses": [
        "G001",
        "S002"
      ],
      "before": "supinf original value1 minus previous maximum := sub(-21/22, 20/21)",
      "after": "supinf original value1 minus previous maximum = -881/462",
      "relation": "calculation",
      "rule_id": "exact_rational_arithmetic",
      "conditions": [],
      "explanation": {
        "zh-Hant": "依原始角色及已核中間量精確代值，保留原索引、集合位置、方向、正負號與適用條件。",
        "en": "Substitute original roles and established intermediates exactly,retaining indices,set positions,orientation,signs and applicability conditions."
      },
      "reverse_audit": {
        "kind": "premise_and_result_audit",
        "explanation": {
          "zh-Hant": "以精確有理數重算 supinf original value1 minus previous maximum，不以小數近似替代。",
          "en": "Recompute supinf original value1 minus previous maximum with exact rational arithmetic, not rounded decimals."
        }
      },
      "arithmetic": {
        "operation": "sub",
        "inputs": [
          "-21/22",
          "20/21"
        ],
        "output": "-881/462",
        "label": "supinf original value1 minus previous maximum"
      }
    },
    {
      "id": "S004",
      "uses": [
        "G001",
        "S003"
      ],
      "before": "supinf original value1 minus previous minimum := sub(-21/22, 20/21)",
      "after": "supinf original value1 minus previous minimum = -881/462",
      "relation": "calculation",
      "rule_id": "exact_rational_arithmetic",
      "conditions": [],
      "explanation": {
        "zh-Hant": "依原始角色及已核中間量精確代值，保留原索引、集合位置、方向、正負號與適用條件。",
        "en": "Substitute original roles and established intermediates exactly,retaining indices,set positions,orientation,signs and applicability conditions."
      },
      "reverse_audit": {
        "kind": "premise_and_result_audit",
        "explanation": {
          "zh-Hant": "以精確有理數重算 supinf original value1 minus previous minimum，不以小數近似替代。",
          "en": "Recompute supinf original value1 minus previous minimum with exact rational arithmetic, not rounded decimals."
        }
      },
      "arithmetic": {
        "operation": "sub",
        "inputs": [
          "-21/22",
          "20/21"
        ],
        "output": "-881/462",
        "label": "supinf original value1 minus previous minimum"
      }
    },
    {
      "id": "S005",
      "uses": [
        "G001",
        "S004"
      ],
      "before": "ORIGINAL next index=1;value=-21/22;previous extremum values=[20/21, 20/21];differences=[-881/462, -881/462]",
      "after": "prefix maximum=20/21 attained at original index0;prefix minimum=-21/22 attained at original index1",
      "relation": "implies",
      "rule_id": "supinf_every_value_extremum_prefix_invariant",
      "conditions": [],
      "explanation": {
        "zh-Hant": "逐全部原值比較保prefix最大／最小不變式，只在嚴格變大／變小時改witness；沒有漏掉的原值。",
        "en": "Compare every original value,preserving prefix maximum/minimum invariants and updating witnesses only for strict improvement.No original value is omitted."
      },
      "reverse_audit": {
        "kind": "premise_and_result_audit",
        "explanation": {
          "zh-Hant": "回到原始資料與本步條件核對，不把單向推論誤稱等價。",
          "en": "Check against the original data and this step's premises; a one-way implication is not an equivalence."
        }
      },
      "arithmetic": null
    },
    {
      "id": "S006",
      "uses": [
        "G001",
        "S005"
      ],
      "before": "supinf original value2 minus previous maximum := sub(41/23, 20/21)",
      "after": "supinf original value2 minus previous maximum = 401/483",
      "relation": "calculation",
      "rule_id": "exact_rational_arithmetic",
      "conditions": [],
      "explanation": {
        "zh-Hant": "依原始角色及已核中間量精確代值，保留原索引、集合位置、方向、正負號與適用條件。",
        "en": "Substitute original roles and established intermediates exactly,retaining indices,set positions,orientation,signs and applicability conditions."
      },
      "reverse_audit": {
        "kind": "premise_and_result_audit",
        "explanation": {
          "zh-Hant": "以精確有理數重算 supinf original value2 minus previous maximum，不以小數近似替代。",
          "en": "Recompute supinf original value2 minus previous maximum with exact rational arithmetic, not rounded decimals."
        }
      },
      "arithmetic": {
        "operation": "sub",
        "inputs": [
          "41/23",
          "20/21"
        ],
        "output": "401/483",
        "label": "supinf original value2 minus previous maximum"
      }
    },
    {
      "id": "S007",
      "uses": [
        "G001",
        "S006"
      ],
      "before": "supinf original value2 minus previous minimum := sub(41/23, -21/22)",
      "after": "supinf original value2 minus previous minimum = 1385/506",
      "relation": "calculation",
      "rule_id": "exact_rational_arithmetic",
      "conditions": [],
      "explanation": {
        "zh-Hant": "依原始角色及已核中間量精確代值，保留原索引、集合位置、方向、正負號與適用條件。",
        "en": "Substitute original roles and established intermediates exactly,retaining indices,set positions,orientation,signs and applicability conditions."
      },
      "reverse_audit": {
        "kind": "premise_and_result_audit",
        "explanation": {
          "zh-Hant": "以精確有理數重算 supinf original value2 minus previous minimum，不以小數近似替代。",
          "en": "Recompute supinf original value2 minus previous minimum with exact rational arithmetic, not rounded decimals."
        }
      },
      "arithmetic": {
        "operation": "sub",
        "inputs": [
          "41/23",
          "-21/22"
        ],
        "output": "1385/506",
        "label": "supinf original value2 minus previous minimum"
      }
    },
    {
      "id": "S008",
      "uses": [
        "G001",
        "S007"
      ],
      "before": "ORIGINAL next index=2;value=41/23;previous extremum values=[20/21, -21/22];differences=[401/483, 1385/506]",
      "after": "prefix maximum=41/23 attained at original index2;prefix minimum=-21/22 attained at original index1",
      "relation": "implies",
      "rule_id": "supinf_every_value_extremum_prefix_invariant",
      "conditions": [],
      "explanation": {
        "zh-Hant": "逐全部原值比較保prefix最大／最小不變式，只在嚴格變大／變小時改witness；沒有漏掉的原值。",
        "en": "Compare every original value,preserving prefix maximum/minimum invariants and updating witnesses only for strict improvement.No original value is omitted."
      },
      "reverse_audit": {
        "kind": "premise_and_result_audit",
        "explanation": {
          "zh-Hant": "回到原始資料與本步條件核對，不把單向推論誤稱等價。",
          "en": "Check against the original data and this step's premises; a one-way implication is not an equivalence."
        }
      },
      "arithmetic": null
    },
    {
      "id": "S009",
      "uses": [
        "G001",
        "S008"
      ],
      "before": "ALL original values processed;actual maximum witness=[2, 41/23];actual minimum witness=[1, -21/22]",
      "after": "EVERY listed value between-21/22 and41/23;ANY upper bound must>=actual maximum in the set;ANY lower bound must<=actual minimum;sup=41/23,inf=-21/22,BOTH attained",
      "relation": "implies",
      "rule_id": "supinf_bounds_and_least_greatest_by_actual_attaining_points",
      "conditions": [],
      "explanation": {
        "zh-Hant": "最大點本身屬集合，故任何上界都不能比它小；最小點亦迫任何下界不能更大。這同時證bound與leastness／greatestness，有限非空才有此取到性，不外推一般有界集合。",
        "en": "Because the maximum is itself in the set,no upper bound can be smaller;the minimum similarly bounds every lower bound above.This proves both bounding and leastness/greatestness.Attainment uses finiteness and nonemptiness and is not inferred for arbitrary bounded sets."
      },
      "reverse_audit": {
        "kind": "premise_and_result_audit",
        "explanation": {
          "zh-Hant": "回到原始資料與本步條件核對，不把單向推論誤稱等價。",
          "en": "Check against the original data and this step's premises; a one-way implication is not an equivalence."
        }
      },
      "arithmetic": null
    },
    {
      "id": "S010",
      "uses": [
        "G001",
        "S009"
      ],
      "before": "supinf candidate bound test original value0 := sub(20/21, -21/22)",
      "after": "supinf candidate bound test original value0 = 881/462",
      "relation": "calculation",
      "rule_id": "exact_rational_arithmetic",
      "conditions": [],
      "explanation": {
        "zh-Hant": "依原始角色及已核中間量精確代值，保留原索引、集合位置、方向、正負號與適用條件。",
        "en": "Substitute original roles and established intermediates exactly,retaining indices,set positions,orientation,signs and applicability conditions."
      },
      "reverse_audit": {
        "kind": "premise_and_result_audit",
        "explanation": {
          "zh-Hant": "以精確有理數重算 supinf candidate bound test original value0，不以小數近似替代。",
          "en": "Recompute supinf candidate bound test original value0 with exact rational arithmetic, not rounded decimals."
        }
      },
      "arithmetic": {
        "operation": "sub",
        "inputs": [
          "20/21",
          "-21/22"
        ],
        "output": "881/462",
        "label": "supinf candidate bound test original value0"
      }
    },
    {
      "id": "S011",
      "uses": [
        "G001",
        "S010"
      ],
      "before": "supinf candidate bound test original value1 := sub(-21/22, -21/22)",
      "after": "supinf candidate bound test original value1 = 0",
      "relation": "calculation",
      "rule_id": "exact_rational_arithmetic",
      "conditions": [],
      "explanation": {
        "zh-Hant": "依原始角色及已核中間量精確代值，保留原索引、集合位置、方向、正負號與適用條件。",
        "en": "Substitute original roles and established intermediates exactly,retaining indices,set positions,orientation,signs and applicability conditions."
      },
      "reverse_audit": {
        "kind": "premise_and_result_audit",
        "explanation": {
          "zh-Hant": "以精確有理數重算 supinf candidate bound test original value1，不以小數近似替代。",
          "en": "Recompute supinf candidate bound test original value1 with exact rational arithmetic, not rounded decimals."
        }
      },
      "arithmetic": {
        "operation": "sub",
        "inputs": [
          "-21/22",
          "-21/22"
        ],
        "output": "0",
        "label": "supinf candidate bound test original value1"
      }
    },
    {
      "id": "S012",
      "uses": [
        "G001",
        "S011"
      ],
      "before": "supinf candidate bound test original value2 := sub(41/23, -21/22)",
      "after": "supinf candidate bound test original value2 = 1385/506",
      "relation": "calculation",
      "rule_id": "exact_rational_arithmetic",
      "conditions": [],
      "explanation": {
        "zh-Hant": "依原始角色及已核中間量精確代值，保留原索引、集合位置、方向、正負號與適用條件。",
        "en": "Substitute original roles and established intermediates exactly,retaining indices,set positions,orientation,signs and applicability conditions."
      },
      "reverse_audit": {
        "kind": "premise_and_result_audit",
        "explanation": {
          "zh-Hant": "以精確有理數重算 supinf candidate bound test original value2，不以小數近似替代。",
          "en": "Recompute supinf candidate bound test original value2 with exact rational arithmetic, not rounded decimals."
        }
      },
      "arithmetic": {
        "operation": "sub",
        "inputs": [
          "41/23",
          "-21/22"
        ],
        "output": "1385/506",
        "label": "supinf candidate bound test original value2"
      }
    },
    {
      "id": "S013",
      "uses": [
        "G001",
        "S012"
      ],
      "before": "ORIGINAL candidate=-21/22;lower-bound flags for EVERY original value=[是, 是, 是];separate actual extremum=-21/22",
      "after": "candidate is bound=是;candidate equals INF=是;a loose bound and a failed candidate are not the extremum",
      "relation": "implies",
      "rule_id": "supinf_candidate_bound_and_least_greatest_separate_flags",
      "conditions": [],
      "explanation": {
        "zh-Hant": "候選bound要逐值全稱核；等於已證sup／inf才是相應最緊界。失敗只否決此candidate，不表示集合無界；鬆界通過也不等於最小上界／最大下界。",
        "en": "Audit the candidate against every value.Equality with the established sup/inf gives the tight bound.A failed candidate does not make the set unbounded,and a loose passing bound is not the least upper/greatest lower bound."
      },
      "reverse_audit": {
        "kind": "premise_and_result_audit",
        "explanation": {
          "zh-Hant": "回到原始資料與本步條件核對，不把單向推論誤稱等價。",
          "en": "Check against the original data and this step's premises; a one-way implication is not an equivalence."
        }
      },
      "arithmetic": null
    }
  ],
  "math_model": {
    "result": [
      "-21/22",
      true,
      "-21/22",
      true,
      "lower_bound_and_greatestness_are_separate"
    ]
  },
  "conclusion": {
    "canonical_value": "(-21/22, 是, -21/22, 是, lower_bound_and_greatestness_are_separate)",
    "explanation": {
      "zh-Hant": "依上列完整代值及條件核對得到原題答案；原題編號、格式與狀態保持不變。",
      "en": "The full substitutions and premise checks give the original answer; source identity,format and status are unchanged."
    }
  },
  "definition_note": {
    "zh-Hant": "沿用原題明示的論域、假設與來源 MKO 定義。本題已完成第二對話數理與中英語義覆核，並由原始參數逐題獨立重算模型、答案與每個算術步驟；原題仍為 candidate。",
    "en": "Use the original question domain, assumptions and cited MKO definitions. This item has second-context mathematical and bilingual review, with the model, answer and every arithmetic step independently recomputed from the original parameters; the source question remains a candidate."
  },
  "source": {
    "input_commit": "0f7be61e2c22317a4075561dc822c87d881a50db",
    "question_binding": {
      "batch_id": "batch-20261014-advance-20261107-r02-supremum-and-infimum-foundations",
      "batch_path": "public/data/questions/batches/batch-20261014-advance-20261107-r02-supremum-and-infimum-foundations/questions.jsonl",
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