{
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  "question_id": "q-20261014-advance-20261112-r05-power-series-radius-of-convergence-0005",
  "pilot_number": "R0046-23830",
  "number": 23830,
  "family_id": "qf-mod43-radius-geometric-exact",
  "title": {
    "zh-Hant": "第 23830 題：冪級數收斂半徑",
    "en": "Question 23830: A Whole Geometric Coefficient Law Gives an Exact Radius"
  },
  "original_question": {
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    "id": "q-20261014-advance-20261112-r05-power-series-radius-of-convergence-0005",
    "batch_id": "batch-20261014-advance-20261112-r05-power-series-radius-of-convergence-foundations",
    "language": "zh-Hant",
    "source_mko_ids": [
      "mko-power-series-radius-of-convergence"
    ],
    "title_zh": "冪級數收斂半徑",
    "stem_zh": "明示對每個n>=0有效的完整coefficient law、center與extended radius。操作=radius-geometric-exact；資料={\"coefficient_ratio\":[5,6],\"center\":-8}。請依 exact_ordered_tuple_declared_by_interface 欄序回答。",
    "answer": {
      "kind": "expression",
      "value": "(a_n=(5/6)^n_for_every_n>=0, -8, 6/5, absolute_convergence_inside, divergence_outside, endpoints_require_separate_audit)",
      "explanation_zh": "Wave6第六層核對=(a_n=(5/6)^n_for_every_n>=0, -8, 6/5, absolute_convergence_inside, divergence_outside, endpoints_require_separate_audit)；依完整明示資料獨立重算；geometric採a_n=q^n；endpoint採a_n=R^(-n)/(n+1)^p；prefix boundary明示共同zero prefix及兩條完整geometric tail laws；inside絕對收斂、outside發散而endpoints逐案判定；R=0與R=infinity均合法，有限prefix不能決定radius。"
    },
    "difficulty": {
      "band": "undergraduate_core",
      "level": 1,
      "skills": [
        "冪級數收斂半徑"
      ]
    },
    "variant": {
      "family_id": "qf-mod43-radius-geometric-exact",
      "seed": 202611125005,
      "parameters": {
        "coefficient_ratio": [
          5,
          6
        ],
        "center": -8,
        "domain": "Exact_power_series_radius",
        "operation": "radius-geometric-exact",
        "semantic_template": "qf-mod43-radius-geometric-exact/{\"center\":-8,\"coefficient_ratio\":[5,6]}"
      }
    },
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      "warning_zh": "候選須主端重算；不構成人工審定、一般定理的有限枚舉替代、未宣告瑕積分、未明示係數律、Euler criterion循環、有限word等價、Lean或Evidence。"
    },
    "provenance": {
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      "generated_at": "2026-10-14",
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    "question_id": "q-20261014-advance-20261112-r05-power-series-radius-of-convergence-0005",
    "batch_id": "batch-20261014-advance-20261112-r05-power-series-radius-of-convergence-foundations",
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      "family_id": "qf-mod43-radius-geometric-exact",
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      "semantic_template": "qf-mod43-radius-geometric-exact/{\"center\":-8,\"coefficient_ratio\":[5,6]}"
    },
    "fields": {
      "title": "A Whole Geometric Coefficient Law Gives an Exact Radius",
      "stem": "Use a_n=(5/6)^n for every n≥0, positive ratio q=5/6, and center c=-8. Give (coefficient_law, center, radius, interior_status, exterior_status, boundary).",
      "answer": {
        "kind": "expression",
        "value": "(a_n=(5/6)^n_for_every_n>=0, -8, 6/5, absolute_convergence_inside, divergence_outside, endpoints_require_separate_audit)",
        "explanation": "For sum a_n*(x−c)^n the radius is1/q. Interior absolute convergence and exterior divergence are distinct from endpoints, which need a separate audit. A finite coefficient sample is not the complete law. The exact result, retaining the requested order, is (a_n=(5/6)^n_for_every_n>=0, -8, 6/5, absolute_convergence_inside, divergence_outside, endpoints_require_separate_audit)."
      },
      "skills": [
        "A Whole Geometric Coefficient Law Gives an Exact Radius"
      ],
      "verification_warning": "This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."
    }
  },
  "givens": [
    {
      "id": "G001",
      "text": {
        "zh-Hant": "明示對每個n>=0有效的完整coefficient law、center與extended radius。操作=radius-geometric-exact；資料={\"coefficient_ratio\":[5,6],\"center\":-8}。請依 exact_ordered_tuple_declared_by_interface 欄序回答。",
        "en": "Use a_n=(5/6)^n for every n≥0, positive ratio q=5/6, and center c=-8. Give (coefficient_law, center, radius, interior_status, exterior_status, boundary)."
      }
    }
  ],
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    {
      "id": "S001",
      "uses": [
        "G001"
      ],
      "before": "source operation=radius-geometric-exact;original snapshot and mathematics retained",
      "after": "explicit ordered source output fields=[coefficient_law, center, radius, interior_status, exterior_status, boundary]",
      "relation": "implies",
      "rule_id": "source_ordered_interface_explicit_without_javascript",
      "conditions": [],
      "explanation": {
        "zh-Hant": "保留原題介面快照，本頁直接列來源欄序，不需JavaScript。radius由原mode選6／11欄，不補欄；No與實際否定依來源責任分清。",
        "en": "Keep the source snapshot while listing ordered fields without JavaScript.Radius uses its original mode to select6 or11 fields without padding;distinguish nonclaims from actual negations."
      },
      "reverse_audit": {
        "kind": "premise_and_result_audit",
        "explanation": {
          "zh-Hant": "回到原始資料與本步條件核對，不把單向推論誤稱等價。",
          "en": "Check against the original data and this step's premises; a one-way implication is not an equivalence."
        }
      },
      "arithmetic": null
    },
    {
      "id": "S002",
      "uses": [
        "G001",
        "S001"
      ],
      "before": "Radius ORIGINAL positive coefficient-ratio reciprocal := div(1, 5/6)",
      "after": "Radius ORIGINAL positive coefficient-ratio reciprocal = 6/5",
      "relation": "calculation",
      "rule_id": "exact_rational_arithmetic",
      "conditions": [],
      "explanation": {
        "zh-Hant": "依原始角色與已證中間量精確代值，不用浮點近似，也不把有限測試冒充全稱極限。",
        "en": "Substitute original roles and established intermediates exactly,without floats or treating finite tests as universal limits."
      },
      "reverse_audit": {
        "kind": "premise_and_result_audit",
        "explanation": {
          "zh-Hant": "以精確有理數重算 Radius ORIGINAL positive coefficient-ratio reciprocal，不以小數近似替代。",
          "en": "Recompute Radius ORIGINAL positive coefficient-ratio reciprocal with exact rational arithmetic, not rounded decimals."
        }
      },
      "arithmetic": {
        "operation": "div",
        "inputs": [
          "1",
          "5/6"
        ],
        "output": "6/5",
        "label": "Radius ORIGINAL positive coefficient-ratio reciprocal"
      }
    },
    {
      "id": "S003",
      "uses": [
        "G001",
        "S002"
      ],
      "before": "ORIGINAL WHOLE a_n=(5/6)^n for EVERY n>=0;center=-8;positive q=5/6",
      "after": "absolute geometric term ratio=q*|x-center|;less than1 gives absolute convergence,greater than1 makes terms not tend0;exact radius1/q=6/5",
      "relation": "implies",
      "rule_id": "radius_WHOLE_geometric_inside_outside_not_finite_coefficients",
      "conditions": [],
      "explanation": {
        "zh-Hant": "使用全部n的係數law，不把幾個a_n當無窮證書；interior／exterior分開，endpoint性質另核，radius本身不取代兩端結論。",
        "en": "Use the law for every n,not a handful of coefficients.Keep interior and exterior separate and audit endpoints separately;a radius does not replace endpoint conclusions."
      },
      "reverse_audit": {
        "kind": "premise_and_result_audit",
        "explanation": {
          "zh-Hant": "回到原始資料與本步條件核對，不把單向推論誤稱等價。",
          "en": "Check against the original data and this step's premises; a one-way implication is not an equivalence."
        }
      },
      "arithmetic": null
    }
  ],
  "math_model": {
    "result": [
      "a_n=(5/6)^n_for_every_n>=0",
      "-8",
      "6/5",
      "absolute_convergence_inside",
      "divergence_outside",
      "endpoints_require_separate_audit"
    ]
  },
  "conclusion": {
    "canonical_value": "(a_n=(5/6)^n_for_every_n>=0, -8, 6/5, absolute_convergence_inside, divergence_outside, endpoints_require_separate_audit)",
    "explanation": {
      "zh-Hant": "依上列完整代值及條件核對得到原題答案；原題編號、格式與狀態保持不變。",
      "en": "The full substitutions and premise checks give the original answer; source identity,format and status are unchanged."
    }
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    "zh-Hant": "沿用原題明示的論域、假設與來源 MKO 定義。本題已完成第二對話數理與中英語義覆核，並由原始參數逐題獨立重算模型、答案與每個算術步驟；原題仍為 candidate。",
    "en": "Use the original question domain, assumptions and cited MKO definitions. This item has second-context mathematical and bilingual review, with the model, answer and every arithmetic step independently recomputed from the original parameters; the source question remains a candidate."
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