{
  "schema_version": "ocme-reviewed-question-reader-v1",
  "question_id": "q-20261014-advance-20261112-r05-power-series-radius-of-convergence-0081",
  "pilot_number": "R0046-23881",
  "number": 23881,
  "family_id": "qf-mod43-radius-zero-infinity-prefix-boundary",
  "title": {
    "zh-Hant": "第 23881 題：冪級數收斂半徑",
    "en": "Question 23881: Whole Factorial Laws and Complete Shared-Prefix Tails Keep Their Different Radii"
  },
  "original_question": {
    "schema_version": "ocme-question-v0.1",
    "id": "q-20261014-advance-20261112-r05-power-series-radius-of-convergence-0081",
    "batch_id": "batch-20261014-advance-20261112-r05-power-series-radius-of-convergence-foundations",
    "language": "zh-Hant",
    "source_mko_ids": [
      "mko-power-series-radius-of-convergence"
    ],
    "title_zh": "冪級數收斂半徑",
    "stem_zh": "明示對每個n>=0有效的完整coefficient law、center與extended radius。操作=radius-zero-infinity-prefix-boundary；資料={\"mode\":\"finite_prefix\",\"scale\":6,\"prefix_length\":2,\"first_ratio\":[1,2],\"second_ratio\":[1,4]}。請依 exact_ordered_tuple_declared_by_interface 欄序回答。",
    "answer": {
      "kind": "expression",
      "value": "(finite_prefix, 6, 2, [0, 0, 0], a_n=0_for_n<=2;a_n=6*(1/2)^(n-3)_for_n>2, b_n=0_for_n<=2;b_n=6*(1/4)^(n-3)_for_n>2, 2, 4, 是, 是, two_complete_laws_share_every_coefficient_through_the_prefix_and_have_different_radii)",
      "explanation_zh": "Wave6第六層核對=(finite_prefix, 6, 2, [0, 0, 0], a_n=0_for_n<=2;a_n=6*(1/2)^(n-3)_for_n>2, b_n=0_for_n<=2;b_n=6*(1/4)^(n-3)_for_n>2, 2, 4, 是, 是, two_complete_laws_share_every_coefficient_through_the_prefix_and_have_different_radii)；依完整明示資料獨立重算；geometric採a_n=q^n；endpoint採a_n=R^(-n)/(n+1)^p；prefix boundary明示共同zero prefix及兩條完整geometric tail laws；inside絕對收斂、outside發散而endpoints逐案判定；R=0與R=infinity均合法，有限prefix不能決定radius。"
    },
    "difficulty": {
      "band": "undergraduate_core",
      "level": 1,
      "skills": [
        "冪級數收斂半徑"
      ]
    },
    "variant": {
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      "parameters": {
        "mode": "finite_prefix",
        "scale": 6,
        "prefix_length": 2,
        "first_ratio": [
          1,
          2
        ],
        "second_ratio": [
          1,
          4
        ],
        "domain": "Exact_power_series_radius",
        "operation": "radius-zero-infinity-prefix-boundary",
        "semantic_template": "qf-mod43-radius-zero-infinity-prefix-boundary/{\"first_ratio\":[1,2],\"mode\":\"finite_prefix\",\"prefix_length\":2,\"scale\":6,\"second_ratio\":[1,4]}"
      }
    },
    "verification": {
      "status": "candidate",
      "checks": [
        "producer_exact_finite_or_symbolic_model",
        "producer_source_snapshot_check",
        "producer_substantive_template_deduplication",
        "producer_json_schema"
      ],
      "warning_zh": "候選須主端重算；不構成人工審定、一般定理的有限枚舉替代、未宣告瑕積分、未明示係數律、Euler criterion循環、有限word等價、Lean或Evidence。"
    },
    "provenance": {
      "generator_role": "question_producer",
      "generator_model": "model_unknown",
      "generated_at": "2026-10-14",
      "contract_version": "ocme-question-factory-v0.1"
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    "question_id": "q-20261014-advance-20261112-r05-power-series-radius-of-convergence-0081",
    "batch_id": "batch-20261014-advance-20261112-r05-power-series-radius-of-convergence-foundations",
    "locale": "en",
    "translation_state": "ai_candidate",
    "source": {
      "question_sha256": "8a4b41e59c78875f4a01a5252877c78822a4b3bd1f1f9ff6e3f0de38ec7c616b",
      "family_id": "qf-mod43-radius-zero-infinity-prefix-boundary",
      "seed": 202611125081,
      "semantic_template": "qf-mod43-radius-zero-infinity-prefix-boundary/{\"first_ratio\":[1,2],\"mode\":\"finite_prefix\",\"prefix_length\":2,\"scale\":6,\"second_ratio\":[1,4]}"
    },
    "fields": {
      "title": "Whole Factorial Laws and Complete Shared-Prefix Tails Keep Their Different Radii",
      "stem": "Use mode=finite_prefix, positive scale=6, source prefix_length=2, first_ratio=1/2, second_ratio=1/4. zero_radius/infinite_radius require the canonical unused-field sentinels prefix0 and ratios1. Give (mode, scale, prefix_last_index, common_zero_prefix, first_complete_law, second_complete_law, first_radius, second_radius, same_prefix, different_radii, certificate).",
      "answer": {
        "kind": "expression",
        "value": "(finite_prefix, 6, 2, [0, 0, 0], a_n=0_for_n<=2;a_n=6*(1/2)^(n-3)_for_n>2, b_n=0_for_n<=2;b_n=6*(1/4)^(n-3)_for_n>2, 2, 4, Yes, Yes, two_complete_laws_share_every_coefficient_through_the_prefix_and_have_different_radii)",
        "explanation": "zero_radius declares a_n=scale*n! for every n≥0 and R=0; infinite_radius declares a_n=scale/n! and R=infinity. finite_prefix uses N=source prefix_length as the last shared zero index, so there are N+1 zeros; subsequent coefficients are scale*q_1^(n−N−1) or scale*q_2^(n−N−1), with positive unequal q values and radii1/q_1,1/q_2. Use the explicit mode-selected6 or11 fields without padding or answer-shape inference. The exact result, retaining the requested order, is (finite_prefix, 6, 2, [0, 0, 0], a_n=0_for_n<=2;a_n=6*(1/2)^(n-3)_for_n>2, b_n=0_for_n<=2;b_n=6*(1/4)^(n-3)_for_n>2, 2, 4, Yes, Yes, two_complete_laws_share_every_coefficient_through_the_prefix_and_have_different_radii)."
      },
      "skills": [
        "Whole Factorial Laws and Complete Shared-Prefix Tails Keep Their Different Radii"
      ],
      "verification_warning": "This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."
    }
  },
  "givens": [
    {
      "id": "G001",
      "text": {
        "zh-Hant": "明示對每個n>=0有效的完整coefficient law、center與extended radius。操作=radius-zero-infinity-prefix-boundary；資料={\"mode\":\"finite_prefix\",\"scale\":6,\"prefix_length\":2,\"first_ratio\":[1,2],\"second_ratio\":[1,4]}。請依 exact_ordered_tuple_declared_by_interface 欄序回答。",
        "en": "Use mode=finite_prefix, positive scale=6, source prefix_length=2, first_ratio=1/2, second_ratio=1/4. zero_radius/infinite_radius require the canonical unused-field sentinels prefix0 and ratios1. Give (mode, scale, prefix_last_index, common_zero_prefix, first_complete_law, second_complete_law, first_radius, second_radius, same_prefix, different_radii, certificate)."
      }
    }
  ],
  "steps": [
    {
      "id": "S001",
      "uses": [
        "G001"
      ],
      "before": "source operation=radius-zero-infinity-prefix-boundary;original snapshot and mathematics retained",
      "after": "explicit ordered source output fields=[mode, scale, prefix_last_index, common_zero_prefix, first_complete_law, second_complete_law, first_radius, second_radius, same_prefix, different_radii, certificate]",
      "relation": "implies",
      "rule_id": "source_ordered_interface_explicit_without_javascript",
      "conditions": [],
      "explanation": {
        "zh-Hant": "保留原題介面快照，本頁直接列來源欄序，不需JavaScript。radius由原mode選6／11欄，不補欄；No與實際否定依來源責任分清。",
        "en": "Keep the source snapshot while listing ordered fields without JavaScript.Radius uses its original mode to select6 or11 fields without padding;distinguish nonclaims from actual negations."
      },
      "reverse_audit": {
        "kind": "premise_and_result_audit",
        "explanation": {
          "zh-Hant": "回到原始資料與本步條件核對，不把單向推論誤稱等價。",
          "en": "Check against the original data and this step's premises; a one-way implication is not an equivalence."
        }
      },
      "arithmetic": null
    },
    {
      "id": "S002",
      "uses": [
        "G001",
        "S001"
      ],
      "before": "Radius ORIGINAL first complete-tail reciprocal := div(1, 1/2)",
      "after": "Radius ORIGINAL first complete-tail reciprocal = 2",
      "relation": "calculation",
      "rule_id": "exact_rational_arithmetic",
      "conditions": [],
      "explanation": {
        "zh-Hant": "依原始角色與已證中間量精確代值，不用浮點近似，也不把有限測試冒充全稱極限。",
        "en": "Substitute original roles and established intermediates exactly,without floats or treating finite tests as universal limits."
      },
      "reverse_audit": {
        "kind": "premise_and_result_audit",
        "explanation": {
          "zh-Hant": "以精確有理數重算 Radius ORIGINAL first complete-tail reciprocal，不以小數近似替代。",
          "en": "Recompute Radius ORIGINAL first complete-tail reciprocal with exact rational arithmetic, not rounded decimals."
        }
      },
      "arithmetic": {
        "operation": "div",
        "inputs": [
          "1",
          "1/2"
        ],
        "output": "2",
        "label": "Radius ORIGINAL first complete-tail reciprocal"
      }
    },
    {
      "id": "S003",
      "uses": [
        "G001",
        "S002"
      ],
      "before": "Radius ORIGINAL second complete-tail reciprocal := div(1, 1/4)",
      "after": "Radius ORIGINAL second complete-tail reciprocal = 4",
      "relation": "calculation",
      "rule_id": "exact_rational_arithmetic",
      "conditions": [],
      "explanation": {
        "zh-Hant": "依原始角色與已證中間量精確代值，不用浮點近似，也不把有限測試冒充全稱極限。",
        "en": "Substitute original roles and established intermediates exactly,without floats or treating finite tests as universal limits."
      },
      "reverse_audit": {
        "kind": "premise_and_result_audit",
        "explanation": {
          "zh-Hant": "以精確有理數重算 Radius ORIGINAL second complete-tail reciprocal，不以小數近似替代。",
          "en": "Recompute Radius ORIGINAL second complete-tail reciprocal with exact rational arithmetic, not rounded decimals."
        }
      },
      "arithmetic": {
        "operation": "div",
        "inputs": [
          "1",
          "1/4"
        ],
        "output": "4",
        "label": "Radius ORIGINAL second complete-tail reciprocal"
      }
    },
    {
      "id": "S004",
      "uses": [
        "G001",
        "S003"
      ],
      "before": "ORIGINAL prefix_length parameter N=2;positive scale=6;distinct positive tail ratios=[1/2, 1/4]",
      "after": "COMMON zero coefficients at ALL n0..N=[0, 0, 0];there are N+1=3 zeros;for n>N laws are scale*q^(n-N-1),first tail term scale;radii=[2, 4] DIFFER",
      "relation": "implies",
      "rule_id": "radius_SHARED_prefix_LAST_index_Nplus1_not_lengthN",
      "conditions": [],
      "explanation": {
        "zh-Hant": "source參數是共同zero prefix的最後index，不是列表長度。兩條完整尾律的ratio分別q1、q2，有限修改／位移不改radius；不由共同有限prefix決定無窮tail。",
        "en": "The source parameter is the last shared zero index,not list length.The complete tails have ratios q1 and q2;finite changes/shifts do not change radius.The common finite prefix does not determine an infinite tail."
      },
      "reverse_audit": {
        "kind": "premise_and_result_audit",
        "explanation": {
          "zh-Hant": "回到原始資料與本步條件核對，不把單向推論誤稱等價。",
          "en": "Check against the original data and this step's premises; a one-way implication is not an equivalence."
        }
      },
      "arithmetic": null
    }
  ],
  "math_model": {
    "result": [
      "finite_prefix",
      6,
      2,
      [
        0,
        0,
        0
      ],
      "a_n=0_for_n<=2;a_n=6*(1/2)^(n-3)_for_n>2",
      "b_n=0_for_n<=2;b_n=6*(1/4)^(n-3)_for_n>2",
      "2",
      "4",
      true,
      true,
      "two_complete_laws_share_every_coefficient_through_the_prefix_and_have_different_radii"
    ]
  },
  "conclusion": {
    "canonical_value": "(finite_prefix, 6, 2, [0, 0, 0], a_n=0_for_n<=2;a_n=6*(1/2)^(n-3)_for_n>2, b_n=0_for_n<=2;b_n=6*(1/4)^(n-3)_for_n>2, 2, 4, 是, 是, two_complete_laws_share_every_coefficient_through_the_prefix_and_have_different_radii)",
    "explanation": {
      "zh-Hant": "依上列完整代值及條件核對得到原題答案；原題編號、格式與狀態保持不變。",
      "en": "The full substitutions and premise checks give the original answer; source identity,format and status are unchanged."
    }
  },
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    "zh-Hant": "沿用原題明示的論域、假設與來源 MKO 定義。本題已完成第二對話數理與中英語義覆核，並由原始參數逐題獨立重算模型、答案與每個算術步驟；原題仍為 candidate。",
    "en": "Use the original question domain, assumptions and cited MKO definitions. This item has second-context mathematical and bilingual review, with the model, answer and every arithmetic step independently recomputed from the original parameters; the source question remains a candidate."
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