{
  "schema_version": "ocme-reviewed-question-reader-v1",
  "question_id": "q-20261015-advance-20261116-r01-contraction-mapping-theorem-0060",
  "pilot_number": "R0051-26235",
  "number": 26235,
  "family_id": "qf-mod47-contract-fixed-point-bound",
  "title": {
    "zh-Hant": "第 26235 題：壓縮映射定理",
    "en": "Question 26235: The Geometric Tail Bound Controls the Exact Picard Error"
  },
  "original_question": {
    "schema_version": "ocme-question-v0.1",
    "id": "q-20261015-advance-20261116-r01-contraction-mapping-theorem-0060",
    "batch_id": "batch-20261015-advance-20261116-r01-contraction-mapping-theorem-foundations",
    "language": "zh-Hant",
    "source_mko_ids": [
      "mko-contraction-mapping-theorem"
    ],
    "title_zh": "壓縮映射定理",
    "stem_zh": "完整metric、total self-map與forall-pairs q<1 contraction責任。操作=contract-fixed-point-bound；資料={\"metric\":[[0,10,30],[10,0,20],[30,20,0]],\"mapping\":[0,0,1],\"q\":[1,2],\"start\":2,\"steps\":6}。請依 exact_ordered_tuple_declared_by_interface 欄序回答。",
    "answer": {
      "kind": "expression",
      "value": "([2, 1, 0, 0, 0, 0, 0], 0, 0, 5/8, 是, d_xn_fixed_le_qn_over_one_minus_q_times_d_x1_x0)",
      "explanation_zh": "Wave6第十層核對=([2, 1, 0, 0, 0, 0, 0], 0, 0, 5/8, 是, d_xn_fixed_le_qn_over_one_minus_q_times_d_x1_x0)；依完整明示資料獨立重算；Picard orbit、unique fixed point與geometric tail bound使用exact arithmetic；q=1、非self-map、noncomplete或sampled-pairs不足；finite model不取代一般定理。"
    },
    "difficulty": {
      "band": "undergraduate_core",
      "level": 2,
      "skills": [
        "壓縮映射定理"
      ]
    },
    "variant": {
      "family_id": "qf-mod47-contract-fixed-point-bound",
      "seed": 202611161060,
      "parameters": {
        "metric": [
          [
            0,
            10,
            30
          ],
          [
            10,
            0,
            20
          ],
          [
            30,
            20,
            0
          ]
        ],
        "mapping": [
          0,
          0,
          1
        ],
        "q": [
          1,
          2
        ],
        "start": 2,
        "steps": 6,
        "domain": "Exact_finite_contraction_mapping",
        "operation": "contract-fixed-point-bound",
        "semantic_template": "qf-mod47-contract-fixed-point-bound/{\"mapping\":[0,0,1],\"metric\":[[[0,1],[10,1],[30,1]],[[10,1],[0,1],[20,1]],[[30,1],[20,1],[0,1]]],\"q\":[1,2],\"start\":2,\"steps\":6}"
      }
    },
    "verification": {
      "status": "candidate",
      "checks": [
        "producer_exact_finite_or_symbolic_model",
        "producer_source_snapshot_check",
        "producer_substantive_template_deduplication",
        "producer_json_schema"
      ],
      "warning_zh": "候選須主端重算；不構成人工審定、一般Banach／IVT／Taylor證明、MLE漸近性、factorization theorem、一般DAG iff或primitive-root主張、Lean或Evidence。"
    },
    "provenance": {
      "generator_role": "question_producer",
      "generator_model": "model_unknown",
      "generated_at": "2026-10-15",
      "contract_version": "ocme-question-factory-v0.1"
    }
  },
  "original_english_edition": {
    "schema_version": "ocme-question-localization-v0.1",
    "question_id": "q-20261015-advance-20261116-r01-contraction-mapping-theorem-0060",
    "batch_id": "batch-20261015-advance-20261116-r01-contraction-mapping-theorem-foundations",
    "locale": "en",
    "translation_state": "ai_candidate",
    "source": {
      "question_sha256": "8af47539ee1b36f93cda57a3cfca21155c75a7d304ff8259ad0c835892eca6de",
      "family_id": "qf-mod47-contract-fixed-point-bound",
      "seed": 202611161060,
      "semantic_template": "qf-mod47-contract-fixed-point-bound/{\"mapping\":[0,0,1],\"metric\":[[[0,1],[10,1],[30,1]],[[10,1],[0,1],[20,1]],[[30,1],[20,1],[0,1]]],\"q\":[1,2],\"start\":2,\"steps\":6}"
    },
    "fields": {
      "title": "The Geometric Tail Bound Controls the Exact Picard Error",
      "stem": "Use the complete exact metric matrix=[[0, 10, 30], [10, 0, 20], [30, 20, 0]], aligned mapping=[0, 0, 1] and q=1/2. Qualify nonnegativity, separation, symmetry and every triangle, the entire self-map and every ordered contraction pair. A finite metric space is complete. Start=2, steps=6. Give (orbit, fixed_point, actual_error, geometric_bound, bound_holds, certificate).",
      "answer": {
        "kind": "expression",
        "value": "([2, 1, 0, 0, 0, 0, 0], 0, 0, 5/8, Yes, d_xn_fixed_le_qn_over_one_minus_q_times_d_x1_x0)",
        "explanation": "Compare actual distance d(x_n,x*) with q^n/(1−q)*d(x_1,x_0). Keep n=0 and q=0 conventions explicit through exact finite arithmetic. The unique fixed point and full contraction premises precede this bound. The exact result, retaining the requested order, is ([2, 1, 0, 0, 0, 0, 0], 0, 0, 5/8, Yes, d_xn_fixed_le_qn_over_one_minus_q_times_d_x1_x0)."
      },
      "skills": [
        "The Geometric Tail Bound Controls the Exact Picard Error"
      ],
      "verification_warning": "This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."
    }
  },
  "givens": [
    {
      "id": "G001",
      "text": {
        "zh-Hant": "完整metric、total self-map與forall-pairs q<1 contraction責任。操作=contract-fixed-point-bound；資料={\"metric\":[[0,10,30],[10,0,20],[30,20,0]],\"mapping\":[0,0,1],\"q\":[1,2],\"start\":2,\"steps\":6}。請依 exact_ordered_tuple_declared_by_interface 欄序回答。",
        "en": "Use the complete exact metric matrix=[[0, 10, 30], [10, 0, 20], [30, 20, 0]], aligned mapping=[0, 0, 1] and q=1/2. Qualify nonnegativity, separation, symmetry and every triangle, the entire self-map and every ordered contraction pair. A finite metric space is complete. Start=2, steps=6. Give (orbit, fixed_point, actual_error, geometric_bound, bound_holds, certificate)."
      }
    }
  ],
  "steps": [
    {
      "id": "S001",
      "uses": [
        "G001"
      ],
      "before": "source roles = [contract-fixed-point-bound]",
      "after": "derived = [[orbit, fixed_point, actual_error, geometric_bound, bound_holds, certificate]]",
      "relation": "implies",
      "rule_id": "source_ordered_fields_without_JS",
      "conditions": [],
      "explanation": {
        "zh-Hant": "本頁直接列完整來源欄序，不需JavaScript；contract的6/4/6/6與IVT的8/7/8由原mode選，不補欄也不由答案形狀猜。",
        "en": "List the full source field order without JavaScript.Original modes select contract6/4/6/6 and IVT8/7/8 roles,without padding or answer-shape inference."
      },
      "reverse_audit": {
        "kind": "premise_and_result_audit",
        "explanation": {
          "zh-Hant": "回到原始資料與本步條件核對，不把單向推論誤稱等價。",
          "en": "Check against the original data and this step's premises; a one-way implication is not an equivalence."
        }
      },
      "arithmetic": null
    },
    {
      "id": "S002",
      "uses": [
        "G001",
        "S001"
      ],
      "before": "source roles = [[[0, 10, 30], [10, 0, 20], [30, 20, 0]]]",
      "after": "derived = [3, 是, 是, 是, [[0, 0, 0, 0, 0, 是], [0, 0, 1, 10, 10, 是], [0, 0, 2, 30, 30, 是], [0, 1, 0, 0, 20, 是], [0, 1, 1, 10, 10, 是], [0, 1, 2, 30, 30, 是], [0, 2, 0, 0, 60, 是], [0, 2, 1, 10, 50, 是], [0, 2, 2, 30, 30, 是], [1, 0, 0, 10, 10, 是], [1, 0, 1, 0, 20, 是], [1, 0, 2, 20, 40, 是], [1, 1, 0, 10, 10, 是], [1, 1, 1, 0, 0, 是], [1, 1, 2, 20, 20, 是], [1, 2, 0, 10, 50, 是], [1, 2, 1, 0, 40, 是], [1, 2, 2, 20, 20, 是], [2, 0, 0, 30, 30, 是], [2, 0, 1, 20, 40, 是], [2, 0, 2, 0, 60, 是], [2, 1, 0, 30, 30, 是], [2, 1, 1, 20, 20, 是], [2, 1, 2, 0, 40, 是], [2, 2, 0, 30, 30, 是], [2, 2, 1, 20, 20, 是], [2, 2, 2, 0, 0, 是]], 是]",
      "relation": "implies",
      "rule_id": "Contraction_COMPLETE_metric_axioms_ALL_triangles_finite_completeness",
      "conditions": [],
      "explanation": {
        "zh-Hant": "逐全部三元組核triangle，不由samples推metric。非空有限metric必complete：singleton顯然，否則取最小正距離delta，Cauchy尾段距離<delta便全相同，故極限仍在X。",
        "en": "Check every triangle triple,not sampled metric behavior.A nonempty finite metric is complete:trivial for a singleton;otherwise the minimum positive distance delta forces a Cauchy tail with distances<delta to be constant,with limit in X."
      },
      "reverse_audit": {
        "kind": "premise_and_result_audit",
        "explanation": {
          "zh-Hant": "回到原始資料與本步條件核對，不把單向推論誤稱等價。",
          "en": "Check against the original data and this step's premises; a one-way implication is not an equivalence."
        }
      },
      "arithmetic": null
    },
    {
      "id": "S003",
      "uses": [
        "G001",
        "S002"
      ],
      "before": "Contraction ORIGINAL pair0,0 q times distance := mul(1/2, 0)",
      "after": "Contraction ORIGINAL pair0,0 q times distance = 0",
      "relation": "calculation",
      "rule_id": "exact_rational_arithmetic",
      "conditions": [],
      "explanation": {
        "zh-Hant": "依原始角色與已證中間量精確代值，不用近似；額外教學恆等式不另縮限原題域。",
        "en": "Substitute original roles and established intermediates exactly,without rounding;extra teaching identities do not restrict the source domain."
      },
      "reverse_audit": {
        "kind": "premise_and_result_audit",
        "explanation": {
          "zh-Hant": "以精確有理數重算 Contraction ORIGINAL pair0,0 q times distance，不以小數近似替代。",
          "en": "Recompute Contraction ORIGINAL pair0,0 q times distance with exact rational arithmetic, not rounded decimals."
        }
      },
      "arithmetic": {
        "operation": "mul",
        "inputs": [
          "1/2",
          "0"
        ],
        "output": "0",
        "label": "Contraction ORIGINAL pair0,0 q times distance"
      }
    },
    {
      "id": "S004",
      "uses": [
        "G001",
        "S003"
      ],
      "before": "Contraction ORIGINAL pair0,1 q times distance := mul(1/2, 10)",
      "after": "Contraction ORIGINAL pair0,1 q times distance = 5",
      "relation": "calculation",
      "rule_id": "exact_rational_arithmetic",
      "conditions": [],
      "explanation": {
        "zh-Hant": "依原始角色與已證中間量精確代值，不用近似；額外教學恆等式不另縮限原題域。",
        "en": "Substitute original roles and established intermediates exactly,without rounding;extra teaching identities do not restrict the source domain."
      },
      "reverse_audit": {
        "kind": "premise_and_result_audit",
        "explanation": {
          "zh-Hant": "以精確有理數重算 Contraction ORIGINAL pair0,1 q times distance，不以小數近似替代。",
          "en": "Recompute Contraction ORIGINAL pair0,1 q times distance with exact rational arithmetic, not rounded decimals."
        }
      },
      "arithmetic": {
        "operation": "mul",
        "inputs": [
          "1/2",
          "10"
        ],
        "output": "5",
        "label": "Contraction ORIGINAL pair0,1 q times distance"
      }
    },
    {
      "id": "S005",
      "uses": [
        "G001",
        "S004"
      ],
      "before": "Contraction ORIGINAL pair0,2 q times distance := mul(1/2, 30)",
      "after": "Contraction ORIGINAL pair0,2 q times distance = 15",
      "relation": "calculation",
      "rule_id": "exact_rational_arithmetic",
      "conditions": [],
      "explanation": {
        "zh-Hant": "依原始角色與已證中間量精確代值，不用近似；額外教學恆等式不另縮限原題域。",
        "en": "Substitute original roles and established intermediates exactly,without rounding;extra teaching identities do not restrict the source domain."
      },
      "reverse_audit": {
        "kind": "premise_and_result_audit",
        "explanation": {
          "zh-Hant": "以精確有理數重算 Contraction ORIGINAL pair0,2 q times distance，不以小數近似替代。",
          "en": "Recompute Contraction ORIGINAL pair0,2 q times distance with exact rational arithmetic, not rounded decimals."
        }
      },
      "arithmetic": {
        "operation": "mul",
        "inputs": [
          "1/2",
          "30"
        ],
        "output": "15",
        "label": "Contraction ORIGINAL pair0,2 q times distance"
      }
    },
    {
      "id": "S006",
      "uses": [
        "G001",
        "S005"
      ],
      "before": "Contraction ORIGINAL pair1,0 q times distance := mul(1/2, 10)",
      "after": "Contraction ORIGINAL pair1,0 q times distance = 5",
      "relation": "calculation",
      "rule_id": "exact_rational_arithmetic",
      "conditions": [],
      "explanation": {
        "zh-Hant": "依原始角色與已證中間量精確代值，不用近似；額外教學恆等式不另縮限原題域。",
        "en": "Substitute original roles and established intermediates exactly,without rounding;extra teaching identities do not restrict the source domain."
      },
      "reverse_audit": {
        "kind": "premise_and_result_audit",
        "explanation": {
          "zh-Hant": "以精確有理數重算 Contraction ORIGINAL pair1,0 q times distance，不以小數近似替代。",
          "en": "Recompute Contraction ORIGINAL pair1,0 q times distance with exact rational arithmetic, not rounded decimals."
        }
      },
      "arithmetic": {
        "operation": "mul",
        "inputs": [
          "1/2",
          "10"
        ],
        "output": "5",
        "label": "Contraction ORIGINAL pair1,0 q times distance"
      }
    },
    {
      "id": "S007",
      "uses": [
        "G001",
        "S006"
      ],
      "before": "Contraction ORIGINAL pair1,1 q times distance := mul(1/2, 0)",
      "after": "Contraction ORIGINAL pair1,1 q times distance = 0",
      "relation": "calculation",
      "rule_id": "exact_rational_arithmetic",
      "conditions": [],
      "explanation": {
        "zh-Hant": "依原始角色與已證中間量精確代值，不用近似；額外教學恆等式不另縮限原題域。",
        "en": "Substitute original roles and established intermediates exactly,without rounding;extra teaching identities do not restrict the source domain."
      },
      "reverse_audit": {
        "kind": "premise_and_result_audit",
        "explanation": {
          "zh-Hant": "以精確有理數重算 Contraction ORIGINAL pair1,1 q times distance，不以小數近似替代。",
          "en": "Recompute Contraction ORIGINAL pair1,1 q times distance with exact rational arithmetic, not rounded decimals."
        }
      },
      "arithmetic": {
        "operation": "mul",
        "inputs": [
          "1/2",
          "0"
        ],
        "output": "0",
        "label": "Contraction ORIGINAL pair1,1 q times distance"
      }
    },
    {
      "id": "S008",
      "uses": [
        "G001",
        "S007"
      ],
      "before": "Contraction ORIGINAL pair1,2 q times distance := mul(1/2, 20)",
      "after": "Contraction ORIGINAL pair1,2 q times distance = 10",
      "relation": "calculation",
      "rule_id": "exact_rational_arithmetic",
      "conditions": [],
      "explanation": {
        "zh-Hant": "依原始角色與已證中間量精確代值，不用近似；額外教學恆等式不另縮限原題域。",
        "en": "Substitute original roles and established intermediates exactly,without rounding;extra teaching identities do not restrict the source domain."
      },
      "reverse_audit": {
        "kind": "premise_and_result_audit",
        "explanation": {
          "zh-Hant": "以精確有理數重算 Contraction ORIGINAL pair1,2 q times distance，不以小數近似替代。",
          "en": "Recompute Contraction ORIGINAL pair1,2 q times distance with exact rational arithmetic, not rounded decimals."
        }
      },
      "arithmetic": {
        "operation": "mul",
        "inputs": [
          "1/2",
          "20"
        ],
        "output": "10",
        "label": "Contraction ORIGINAL pair1,2 q times distance"
      }
    },
    {
      "id": "S009",
      "uses": [
        "G001",
        "S008"
      ],
      "before": "Contraction ORIGINAL pair2,0 q times distance := mul(1/2, 30)",
      "after": "Contraction ORIGINAL pair2,0 q times distance = 15",
      "relation": "calculation",
      "rule_id": "exact_rational_arithmetic",
      "conditions": [],
      "explanation": {
        "zh-Hant": "依原始角色與已證中間量精確代值，不用近似；額外教學恆等式不另縮限原題域。",
        "en": "Substitute original roles and established intermediates exactly,without rounding;extra teaching identities do not restrict the source domain."
      },
      "reverse_audit": {
        "kind": "premise_and_result_audit",
        "explanation": {
          "zh-Hant": "以精確有理數重算 Contraction ORIGINAL pair2,0 q times distance，不以小數近似替代。",
          "en": "Recompute Contraction ORIGINAL pair2,0 q times distance with exact rational arithmetic, not rounded decimals."
        }
      },
      "arithmetic": {
        "operation": "mul",
        "inputs": [
          "1/2",
          "30"
        ],
        "output": "15",
        "label": "Contraction ORIGINAL pair2,0 q times distance"
      }
    },
    {
      "id": "S010",
      "uses": [
        "G001",
        "S009"
      ],
      "before": "Contraction ORIGINAL pair2,1 q times distance := mul(1/2, 20)",
      "after": "Contraction ORIGINAL pair2,1 q times distance = 10",
      "relation": "calculation",
      "rule_id": "exact_rational_arithmetic",
      "conditions": [],
      "explanation": {
        "zh-Hant": "依原始角色與已證中間量精確代值，不用近似；額外教學恆等式不另縮限原題域。",
        "en": "Substitute original roles and established intermediates exactly,without rounding;extra teaching identities do not restrict the source domain."
      },
      "reverse_audit": {
        "kind": "premise_and_result_audit",
        "explanation": {
          "zh-Hant": "以精確有理數重算 Contraction ORIGINAL pair2,1 q times distance，不以小數近似替代。",
          "en": "Recompute Contraction ORIGINAL pair2,1 q times distance with exact rational arithmetic, not rounded decimals."
        }
      },
      "arithmetic": {
        "operation": "mul",
        "inputs": [
          "1/2",
          "20"
        ],
        "output": "10",
        "label": "Contraction ORIGINAL pair2,1 q times distance"
      }
    },
    {
      "id": "S011",
      "uses": [
        "G001",
        "S010"
      ],
      "before": "Contraction ORIGINAL pair2,2 q times distance := mul(1/2, 0)",
      "after": "Contraction ORIGINAL pair2,2 q times distance = 0",
      "relation": "calculation",
      "rule_id": "exact_rational_arithmetic",
      "conditions": [],
      "explanation": {
        "zh-Hant": "依原始角色與已證中間量精確代值，不用近似；額外教學恆等式不另縮限原題域。",
        "en": "Substitute original roles and established intermediates exactly,without rounding;extra teaching identities do not restrict the source domain."
      },
      "reverse_audit": {
        "kind": "premise_and_result_audit",
        "explanation": {
          "zh-Hant": "以精確有理數重算 Contraction ORIGINAL pair2,2 q times distance，不以小數近似替代。",
          "en": "Recompute Contraction ORIGINAL pair2,2 q times distance with exact rational arithmetic, not rounded decimals."
        }
      },
      "arithmetic": {
        "operation": "mul",
        "inputs": [
          "1/2",
          "0"
        ],
        "output": "0",
        "label": "Contraction ORIGINAL pair2,2 q times distance"
      }
    },
    {
      "id": "S012",
      "uses": [
        "G001",
        "S011"
      ],
      "before": "source roles = [[0, 0, 1], 1/2, [[0, 10, 30], [10, 0, 20], [30, 20, 0]]]",
      "after": "derived = [是, 是, [[0, 0, 0, 0, 是], [0, 1, 0, 5, 是], [0, 2, 10, 15, 是], [1, 0, 0, 5, 是], [1, 1, 0, 0, 是], [1, 2, 10, 10, 是], [2, 0, 10, 15, 是], [2, 1, 10, 10, 是], [2, 2, 0, 0, 是]], 是, [0]]",
      "relation": "implies",
      "rule_id": "Contraction_selfmap_q_range_ALL_ordered_pairs_separate",
      "conditions": [],
      "explanation": {
        "zh-Hant": "self-map、0<=q<1與全部pair inequalities分開。nonself時source pairrows空；q失格但self時仍列實際全pair結果，不由array長度或抽樣判global。",
        "en": "Separate self-map,0<=q<1 and all pair inequalities.Nonself maps have empty source pair rows;self maps retain actual pair results even when q-range fails.Array length or samples do not prove global contraction."
      },
      "reverse_audit": {
        "kind": "premise_and_result_audit",
        "explanation": {
          "zh-Hant": "回到原始資料與本步條件核對，不把單向推論誤稱等價。",
          "en": "Check against the original data and this step's premises; a one-way implication is not an equivalence."
        }
      },
      "arithmetic": null
    },
    {
      "id": "S013",
      "uses": [
        "G001",
        "S012"
      ],
      "before": "source roles = [0, 2, [0, 0, 1]]",
      "after": "derived = [1, 10]",
      "relation": "implies",
      "rule_id": "Contraction_EACH_Picard_iterate_original_total_map",
      "conditions": [],
      "explanation": {
        "zh-Hant": "按同一完整map取下一步，保start與每次iterate，不由短prefix猜fixed point。",
        "en": "Apply the same complete map at every step,retaining the start and all iterates rather than guessing a fixed point from a short prefix."
      },
      "reverse_audit": {
        "kind": "premise_and_result_audit",
        "explanation": {
          "zh-Hant": "回到原始資料與本步條件核對，不把單向推論誤稱等價。",
          "en": "Check against the original data and this step's premises; a one-way implication is not an equivalence."
        }
      },
      "arithmetic": null
    },
    {
      "id": "S014",
      "uses": [
        "G001",
        "S013"
      ],
      "before": "source roles = [1, 1, [0, 0, 1]]",
      "after": "derived = [0, 0]",
      "relation": "implies",
      "rule_id": "Contraction_EACH_Picard_iterate_original_total_map",
      "conditions": [],
      "explanation": {
        "zh-Hant": "按同一完整map取下一步，保start與每次iterate，不由短prefix猜fixed point。",
        "en": "Apply the same complete map at every step,retaining the start and all iterates rather than guessing a fixed point from a short prefix."
      },
      "reverse_audit": {
        "kind": "premise_and_result_audit",
        "explanation": {
          "zh-Hant": "回到原始資料與本步條件核對，不把單向推論誤稱等價。",
          "en": "Check against the original data and this step's premises; a one-way implication is not an equivalence."
        }
      },
      "arithmetic": null
    },
    {
      "id": "S015",
      "uses": [
        "G001",
        "S014"
      ],
      "before": "source roles = [2, 0, [0, 0, 1]]",
      "after": "derived = [0, 0]",
      "relation": "implies",
      "rule_id": "Contraction_EACH_Picard_iterate_original_total_map",
      "conditions": [],
      "explanation": {
        "zh-Hant": "按同一完整map取下一步，保start與每次iterate，不由短prefix猜fixed point。",
        "en": "Apply the same complete map at every step,retaining the start and all iterates rather than guessing a fixed point from a short prefix."
      },
      "reverse_audit": {
        "kind": "premise_and_result_audit",
        "explanation": {
          "zh-Hant": "回到原始資料與本步條件核對，不把單向推論誤稱等價。",
          "en": "Check against the original data and this step's premises; a one-way implication is not an equivalence."
        }
      },
      "arithmetic": null
    },
    {
      "id": "S016",
      "uses": [
        "G001",
        "S015"
      ],
      "before": "source roles = [3, 0, [0, 0, 1]]",
      "after": "derived = [0, 0]",
      "relation": "implies",
      "rule_id": "Contraction_EACH_Picard_iterate_original_total_map",
      "conditions": [],
      "explanation": {
        "zh-Hant": "按同一完整map取下一步，保start與每次iterate，不由短prefix猜fixed point。",
        "en": "Apply the same complete map at every step,retaining the start and all iterates rather than guessing a fixed point from a short prefix."
      },
      "reverse_audit": {
        "kind": "premise_and_result_audit",
        "explanation": {
          "zh-Hant": "回到原始資料與本步條件核對，不把單向推論誤稱等價。",
          "en": "Check against the original data and this step's premises; a one-way implication is not an equivalence."
        }
      },
      "arithmetic": null
    },
    {
      "id": "S017",
      "uses": [
        "G001",
        "S016"
      ],
      "before": "source roles = [4, 0, [0, 0, 1]]",
      "after": "derived = [0, 0]",
      "relation": "implies",
      "rule_id": "Contraction_EACH_Picard_iterate_original_total_map",
      "conditions": [],
      "explanation": {
        "zh-Hant": "按同一完整map取下一步，保start與每次iterate，不由短prefix猜fixed point。",
        "en": "Apply the same complete map at every step,retaining the start and all iterates rather than guessing a fixed point from a short prefix."
      },
      "reverse_audit": {
        "kind": "premise_and_result_audit",
        "explanation": {
          "zh-Hant": "回到原始資料與本步條件核對，不把單向推論誤稱等價。",
          "en": "Check against the original data and this step's premises; a one-way implication is not an equivalence."
        }
      },
      "arithmetic": null
    },
    {
      "id": "S018",
      "uses": [
        "G001",
        "S017"
      ],
      "before": "source roles = [5, 0, [0, 0, 1]]",
      "after": "derived = [0, 0]",
      "relation": "implies",
      "rule_id": "Contraction_EACH_Picard_iterate_original_total_map",
      "conditions": [],
      "explanation": {
        "zh-Hant": "按同一完整map取下一步，保start與每次iterate，不由短prefix猜fixed point。",
        "en": "Apply the same complete map at every step,retaining the start and all iterates rather than guessing a fixed point from a short prefix."
      },
      "reverse_audit": {
        "kind": "premise_and_result_audit",
        "explanation": {
          "zh-Hant": "回到原始資料與本步條件核對，不把單向推論誤稱等價。",
          "en": "Check against the original data and this step's premises; a one-way implication is not an equivalence."
        }
      },
      "arithmetic": null
    },
    {
      "id": "S019",
      "uses": [
        "G001",
        "S018"
      ],
      "before": "source roles = [1/2, [0], 2, [2, 1, 0, 0, 0, 0, 0]]",
      "after": "derived = [[30, 10, 0, 0, 0, 0, 0], d(x_(n+k),x_n)<=q^n*(1-q^k)/(1-q)*d(x1,x0), complete limit fixed;two fixed points obey(1-q)d<=0 hence coincide]",
      "relation": "implies",
      "rule_id": "Contraction_GENERAL_geometric_tail_complete_limit_and_unique_fixed",
      "conditions": [],
      "explanation": {
        "zh-Hant": "相鄰距離逐步<=q次前距，triangle把有限尾和成geometric bound，使Picard為Cauchy；completeness給極限，Lipschitz continuity使極限fixed。任兩fixed距離<=q倍自身，q<1迫距離0，故唯一。這是一般教學理由，不把finite orbit當一般定理形式證明。",
        "en": "Successive distances shrink by q;the triangle inequality sums the finite geometric tail,making Picard Cauchy.Completeness gives a limit and Lipschitz continuity makes it fixed.Two fixed points satisfy distance<=q*distance,so q<1 forces equality.This pedagogical argument does not label a finite orbit a general formal proof."
      },
      "reverse_audit": {
        "kind": "premise_and_result_audit",
        "explanation": {
          "zh-Hant": "回到原始資料與本步條件核對，不把單向推論誤稱等價。",
          "en": "Check against the original data and this step's premises; a one-way implication is not an equivalence."
        }
      },
      "arithmetic": null
    },
    {
      "id": "S020",
      "uses": [
        "G001",
        "S019"
      ],
      "before": "(1/2)^6",
      "after": "Contraction ORIGINAL q powerN = 1/64",
      "relation": "implies",
      "rule_id": "integer_power",
      "conditions": [],
      "explanation": {
        "zh-Hant": "以非負整數次有限乘積精確計算，零次為多項式中的乘法單位元。",
        "en": "Evaluate the finite nonnegative-integer power exactly; exponent0 uses the polynomial multiplicative identity."
      },
      "reverse_audit": {
        "kind": "premise_and_result_audit",
        "explanation": {
          "zh-Hant": "回到原始資料與本步條件核對，不把單向推論誤稱等價。",
          "en": "Check against the original data and this step's premises; a one-way implication is not an equivalence."
        }
      },
      "arithmetic": {
        "operation": "integer_power",
        "inputs": [
          "1/2",
          "6"
        ],
        "output": "1/64",
        "label": "Contraction ORIGINAL q powerN"
      }
    },
    {
      "id": "S021",
      "uses": [
        "G001",
        "S020"
      ],
      "before": "Contraction strict one minus q := sub(1, 1/2)",
      "after": "Contraction strict one minus q = 1/2",
      "relation": "calculation",
      "rule_id": "exact_rational_arithmetic",
      "conditions": [],
      "explanation": {
        "zh-Hant": "依原始角色與已證中間量精確代值，不用近似；額外教學恆等式不另縮限原題域。",
        "en": "Substitute original roles and established intermediates exactly,without rounding;extra teaching identities do not restrict the source domain."
      },
      "reverse_audit": {
        "kind": "premise_and_result_audit",
        "explanation": {
          "zh-Hant": "以精確有理數重算 Contraction strict one minus q，不以小數近似替代。",
          "en": "Recompute Contraction strict one minus q with exact rational arithmetic, not rounded decimals."
        }
      },
      "arithmetic": {
        "operation": "sub",
        "inputs": [
          "1",
          "1/2"
        ],
        "output": "1/2",
        "label": "Contraction strict one minus q"
      }
    },
    {
      "id": "S022",
      "uses": [
        "G001",
        "S021"
      ],
      "before": "Contraction geometric tail factor := div(1/64, 1/2)",
      "after": "Contraction geometric tail factor = 1/32",
      "relation": "calculation",
      "rule_id": "exact_rational_arithmetic",
      "conditions": [],
      "explanation": {
        "zh-Hant": "依原始角色與已證中間量精確代值，不用近似；額外教學恆等式不另縮限原題域。",
        "en": "Substitute original roles and established intermediates exactly,without rounding;extra teaching identities do not restrict the source domain."
      },
      "reverse_audit": {
        "kind": "premise_and_result_audit",
        "explanation": {
          "zh-Hant": "以精確有理數重算 Contraction geometric tail factor，不以小數近似替代。",
          "en": "Recompute Contraction geometric tail factor with exact rational arithmetic, not rounded decimals."
        }
      },
      "arithmetic": {
        "operation": "div",
        "inputs": [
          "1/64",
          "1/2"
        ],
        "output": "1/32",
        "label": "Contraction geometric tail factor"
      }
    },
    {
      "id": "S023",
      "uses": [
        "G001",
        "S022"
      ],
      "before": "Contraction factor times ORIGINAL first-step distance := mul(1/32, 20)",
      "after": "Contraction factor times ORIGINAL first-step distance = 5/8",
      "relation": "calculation",
      "rule_id": "exact_rational_arithmetic",
      "conditions": [],
      "explanation": {
        "zh-Hant": "依原始角色與已證中間量精確代值，不用近似；額外教學恆等式不另縮限原題域。",
        "en": "Substitute original roles and established intermediates exactly,without rounding;extra teaching identities do not restrict the source domain."
      },
      "reverse_audit": {
        "kind": "premise_and_result_audit",
        "explanation": {
          "zh-Hant": "以精確有理數重算 Contraction factor times ORIGINAL first-step distance，不以小數近似替代。",
          "en": "Recompute Contraction factor times ORIGINAL first-step distance with exact rational arithmetic, not rounded decimals."
        }
      },
      "arithmetic": {
        "operation": "mul",
        "inputs": [
          "1/32",
          "20"
        ],
        "output": "5/8",
        "label": "Contraction factor times ORIGINAL first-step distance"
      }
    },
    {
      "id": "S024",
      "uses": [
        "G001",
        "S023"
      ],
      "before": "source roles = [6, 1/2, [2, 1, 0, 0, 0, 0, 0], 0, 20]",
      "after": "derived = [0, 5/8, 是]",
      "relation": "implies",
      "rule_id": "Contraction_actual_error_bound_N0_q0_profile_NOT_shortcircuited",
      "conditions": [],
      "explanation": {
        "zh-Hant": "取尾長k→infinity得a posteriori界；N0時q^0空乘積1，即使q0。原source先算power／division再乘first distance，不因distance0跳過profile。",
        "en": "Let tail length tend to infinity to obtain the error bound.At N0,q^0 is the empty product1,including q0.The source computes powers/division before multiplying first distance;zero distance does not bypass its numeric profile."
      },
      "reverse_audit": {
        "kind": "premise_and_result_audit",
        "explanation": {
          "zh-Hant": "回到原始資料與本步條件核對，不把單向推論誤稱等價。",
          "en": "Check against the original data and this step's premises; a one-way implication is not an equivalence."
        }
      },
      "arithmetic": null
    }
  ],
  "math_model": {
    "result": [
      [
        2,
        1,
        0,
        0,
        0,
        0,
        0
      ],
      0,
      "0",
      "5/8",
      true,
      "d_xn_fixed_le_qn_over_one_minus_q_times_d_x1_x0"
    ]
  },
  "conclusion": {
    "canonical_value": "([2, 1, 0, 0, 0, 0, 0], 0, 0, 5/8, 是, d_xn_fixed_le_qn_over_one_minus_q_times_d_x1_x0)",
    "explanation": {
      "zh-Hant": "依上列完整代值及條件核對得到原題答案；原題編號、格式與狀態保持不變。",
      "en": "The full substitutions and premise checks give the original answer; source identity,format and status are unchanged."
    }
  },
  "definition_note": {
    "zh-Hant": "沿用原題明示的論域、假設與來源 MKO 定義。本題已完成第二對話數理與中英語義覆核，並由原始參數逐題獨立重算模型、答案與每個算術步驟；原題仍為 candidate。",
    "en": "Use the original question domain, assumptions and cited MKO definitions. This item has second-context mathematical and bilingual review, with the model, answer and every arithmetic step independently recomputed from the original parameters; the source question remains a candidate."
  },
  "source": {
    "input_commit": "0f7be61e2c22317a4075561dc822c87d881a50db",
    "question_binding": {
      "batch_id": "batch-20261015-advance-20261116-r01-contraction-mapping-theorem-foundations",
      "batch_path": "public/data/questions/batches/batch-20261015-advance-20261116-r01-contraction-mapping-theorem-foundations/questions.jsonl",
      "batch_sha256": "268af34d2f0ede8f2948e060f19a97e857bedbcdc7359cad296d6741ee95280f",
      "original_line": 60,
      "original_line_sha256": "150000a78e3438fd80758a908a658b1848daf6ce22849935f257bfe63d7d2dec",
      "question_compact_sha256": "8af47539ee1b36f93cda57a3cfca21155c75a7d304ff8259ad0c835892eca6de",
      "english_row_compact_sha256": "187d149d7bd2739a0e273e98cc7fc97d9ac39dbec6b8f8e76d240b1a6e9f7b78",
      "english_manifest_path": "public/data/i18n/editions/batch-20261015-advance-20261116-r01-contraction-mapping-theorem-foundations.en.json",
      "english_rows_path": "public/data/i18n/questions/batch-20261015-advance-20261116-r01-contraction-mapping-theorem-foundations.en.jsonl"
    },
    "mko_bindings": {
      "mko-contraction-mapping-theorem": {
        "sha256": "ab6943f2789918c758734f9dd379c1ca82efe2111e3e7b2f6cd5c3be1eb4db5d",
        "english_sha256": "f40dc82c772b380f05cbd256c6019c0825fda576fd85a8614c86e43cdb7cb080",
        "original_path": "public/data/mko/contraction-mapping-theorem.json",
        "english_path": "public/data/i18n/editions/mko-contraction-mapping-theorem.en.json"
      }
    },
    "selected_manifest_sha256": "5233edba9654a6cffd8b6b2d83c932f82ded15f9c0b7c733bd049943e672acff",
    "selected_part_sha256": "74f6f34e0a695e06f9d836b5f5c677f9f716d2291c75c8f2f5b809ff0935bcff",
    "original_candidate_sha256": "26d2ac1d94d9208f80f8a51cbc0f2ad29c82fa7021b30f25d0bc4cd6a55f529d",
    "original_candidate_line_sha256": "26d2ac1d94d9208f80f8a51cbc0f2ad29c82fa7021b30f25d0bc4cd6a55f529d"
  },
  "historical_source_state": {
    "review_state": {
      "derivation": "candidate_authored_and_locally_checked",
      "source_question_state": "candidate",
      "independent_AI_or_human_review": "NOT_PERFORMED",
      "formalization": "not_formalized",
      "Lean": "NOT_RUN"
    },
    "scope_note": {
      "zh-Hant": "來源綁定教學推導候選；精確核對不等於獨立AI／人工審查或一般形式證明。原題、答案、MKO、公式、AST與歷史不變。",
      "en": "Source-bound pedagogical derivation candidate.Exact checking is not independent AI/human review or general formal proof.Original questions,answers,MKOs,formulas,ASTs and history remain unchanged."
    },
    "label": "Frozen producer metadata; current per-question review is separate below."
  },
  "revision": {
    "id": "review-20261026-010-p52",
    "review_date": "2026-10-26",
    "owner_authorized_reader_publication": true,
    "scope": "One hundred sixty family prototypes and their mathematical/bilingual reasoning variants, stems, boundary statements and every distinct explanation shape were reviewed in a context independent of the producer; parameter substitutions, source bindings, full math models, both answer strings and every arithmetic step were independently reconstructed per question from the original parameters only, with negative controls. This grouped method does not claim a separate literal AI reading of every repeated sentence or an extra AI voter.",
    "review_receipts": {
      "semantic_review_sha256": "90df1e889242e9afdf01e068788ee8500ef366ffcfc0496e30a6800de32631c3",
      "question_first_witness_sha256": "ae1e849608590ca856c9f3b6911ba58e3bf53c608eb7369606192a770f48bd5c"
    },
    "status": "second_context_reviewed",
    "mathematical_semantics": true,
    "bilingual_semantics": true,
    "steps_reviewed": 24,
    "method": "family_template_semantic_review_plus_independent_per_instance_reconstruction",
    "exact_question_first_check": {
      "model_sha256": "dcb28ebba195c8a00e3df27516f8ff99ca38075d34dc74ed71dbef4a2632a1cb",
      "arithmetic_steps": 13
    },
    "uses_answer_as_premise": false,
    "human_review": "NOT_PERFORMED",
    "formalization": "not_formalized",
    "Lean": "NOT_RUN",
    "Canonical_truth_promotion": false,
    "authority": "Owner-authorized reviewed reader publication; original question/candidate states remain historical and unchanged."
  }
}
