{
  "schema_version": "ocme-reviewed-question-reader-v1",
  "question_id": "q-20261015-advance-20261116-r07-multiplicative-order-mod-n-0022",
  "pilot_number": "R0066-33822",
  "number": 33822,
  "family_id": "qf-mod47-morder-qualification",
  "title": {
    "zh-Hant": "第 33822 題：模n乘法階",
    "en": "Question 33822: Normalize and Qualify a Unit before Defining Multiplicative Order"
  },
  "original_question": {
    "schema_version": "ocme-question-v0.1",
    "id": "q-20261015-advance-20261116-r07-multiplicative-order-mod-n-0022",
    "batch_id": "batch-20261015-advance-20261116-r07-multiplicative-order-mod-n-foundations",
    "language": "zh-Hant",
    "source_mko_ids": [
      "mko-multiplicative-order-mod-n"
    ],
    "title_zh": "模n乘法階",
    "stem_zh": "n>=2、normalized coprime residue與first positive power return責任。操作=morder-qualification；資料={\"n\":24,\"a\":5}。請依 exact_ordered_tuple_declared_by_interface 欄序回答。",
    "answer": {
      "kind": "expression",
      "value": "(24, 5, 5, 1, 8, 是, unit_mod_n_qualified)",
      "explanation_zh": "Wave6第十層核對=(24, 5, 5, 1, 8, 是, unit_mod_n_qualified)；依完整明示資料獨立重算；complete power table與phi enumeration核order divides phi；noncoprime/invalid modulus undefined；不宣稱order=phi、primitive root或additive order。"
    },
    "difficulty": {
      "band": "undergraduate_core",
      "level": 3,
      "skills": [
        "模n乘法階"
      ]
    },
    "variant": {
      "family_id": "qf-mod47-morder-qualification",
      "seed": 202611167022,
      "parameters": {
        "n": 24,
        "a": 5,
        "domain": "Exact_multiplicative_order_mod_n",
        "operation": "morder-qualification",
        "semantic_template": "qf-mod47-morder-qualification/{\"a\":[5,1],\"n\":24}"
      }
    },
    "verification": {
      "status": "candidate",
      "checks": [
        "producer_exact_finite_or_symbolic_model",
        "producer_source_snapshot_check",
        "producer_substantive_template_deduplication",
        "producer_json_schema"
      ],
      "warning_zh": "候選須主端重算；不構成人工審定、一般Banach／IVT／Taylor證明、MLE漸近性、factorization theorem、一般DAG iff或primitive-root主張、Lean或Evidence。"
    },
    "provenance": {
      "generator_role": "question_producer",
      "generator_model": "model_unknown",
      "generated_at": "2026-10-15",
      "contract_version": "ocme-question-factory-v0.1"
    }
  },
  "original_english_edition": {
    "schema_version": "ocme-question-localization-v0.1",
    "question_id": "q-20261015-advance-20261116-r07-multiplicative-order-mod-n-0022",
    "batch_id": "batch-20261015-advance-20261116-r07-multiplicative-order-mod-n-foundations",
    "locale": "en",
    "translation_state": "ai_candidate",
    "source": {
      "question_sha256": "9877fc10baaa792c759fc4e8d7ef0f4f86e6353294e716fdf7c974ef19e11787",
      "family_id": "qf-mod47-morder-qualification",
      "seed": 202611167022,
      "semantic_template": "qf-mod47-morder-qualification/{\"a\":[5,1],\"n\":24}"
    },
    "fields": {
      "title": "Normalize and Qualify a Unit before Defining Multiplicative Order",
      "stem": "Use exact modulus n=24 and integer a=5. First require n≥2 and normalize a modulo n into the canonical nonnegative residue, then require gcd(a,n)=1. The order is the least positive return exponent, not any return. Give (n, a, normalized_residue, gcd, phi, unit_qualified, certificate).",
      "answer": {
        "kind": "expression",
        "value": "(24, 5, 5, 1, 8, Yes, unit_mod_n_qualified)",
        "explanation": "Retain gcd and phi(n) from the complete unit residue carrier. Euler theorem supplies the return bound for a unit, not a claim that its order always equals phi(n) or that it is a primitive root. The exact result, retaining the requested order, is (24, 5, 5, 1, 8, Yes, unit_mod_n_qualified)."
      },
      "skills": [
        "Normalize and Qualify a Unit before Defining Multiplicative Order"
      ],
      "verification_warning": "This is a candidate exercise. Mechanical recomputation checks only the stated conditions and this instance; it is neither a formal proof nor human review."
    }
  },
  "givens": [
    {
      "id": "G001",
      "text": {
        "zh-Hant": "n>=2、normalized coprime residue與first positive power return責任。操作=morder-qualification；資料={\"n\":24,\"a\":5}。請依 exact_ordered_tuple_declared_by_interface 欄序回答。",
        "en": "Use exact modulus n=24 and integer a=5. First require n≥2 and normalize a modulo n into the canonical nonnegative residue, then require gcd(a,n)=1. The order is the least positive return exponent, not any return. Give (n, a, normalized_residue, gcd, phi, unit_qualified, certificate)."
      }
    }
  ],
  "steps": [
    {
      "id": "S001",
      "uses": [
        "G001"
      ],
      "before": "source roles = [qf-mod47-morder-qualification, [a, domain, n, operation]]",
      "after": "derived = [morder-qualification, Exact_multiplicative_order_mod_n]",
      "relation": "implies",
      "rule_id": "R66_EXACT_source_bank_keys_local_operation_domain",
      "conditions": [],
      "explanation": {
        "zh-Hant": "原bank的operation是LOCAL hyphen，keys與domain各自精確匹配。欄位順序及數字/Boolean/字串角色依來源，所有有理數文字整數省略/1；不改原題與英文、MKO、AST或狀態。",
        "en": "THIS source uses LOCAL-hyphen operations with exact keys/domain.Keep source field order and numeric/Boolean/string roles;integer rational texts omit/1.Original questions,English,MKOs,ASTs and statuses remain unchanged."
      },
      "reverse_audit": {
        "kind": "premise_and_result_audit",
        "explanation": {
          "zh-Hant": "反向核對本步原始角色、完整前提與欄序；只接受這些條件下的結論，不把單向結論還原為唯一前提，也不把有限核對稱一般形式證明。",
          "en": "Reverse-audit THIS step against its ORIGINAL ordered roles and complete premises.Accept the conclusion only under these conditions;do not invert a one-way implication or call a finite check a general formal proof."
        }
      },
      "arithmetic": null
    },
    {
      "id": "S002",
      "uses": [
        "G001",
        "S001"
      ],
      "before": "source roles = [ORIGINAL representative, 5, 24]",
      "after": "derived = [0, 5]",
      "relation": "implies",
      "rule_id": "Finite_MOD_euclidean_quotient_remainder",
      "conditions": [],
      "explanation": {
        "zh-Hant": "以整數Euclidean division核value=n*quotient+remainder與0≤remainder<n，負代表元也正規化；不是浮點餘數。",
        "en": "Use integer Euclidean division: value=n*quotient+remainder with0≤remainder<n.Normalize negative representatives too;do not use floating remainders."
      },
      "reverse_audit": {
        "kind": "premise_and_result_audit",
        "explanation": {
          "zh-Hant": "反向核對本步原始角色、完整前提與欄序；只接受這些條件下的結論，不把單向結論還原為唯一前提，也不把有限核對稱一般形式證明。",
          "en": "Reverse-audit THIS step against its ORIGINAL ordered roles and complete premises.Accept the conclusion only under these conditions;do not invert a one-way implication or call a finite check a general formal proof."
        }
      },
      "arithmetic": null
    },
    {
      "id": "S003",
      "uses": [
        "G001",
        "S002"
      ],
      "before": "source roles = [24, 5, 5, 1]",
      "after": "derived = [[1, 5, 7, 11, 13, 17, 19, 23], 8]",
      "relation": "implies",
      "rule_id": "Order_ALL_residues_UNIT_gcd_and_complete_phi_carrier",
      "conditions": [],
      "explanation": {
        "zh-Hant": "先n≥2，正規化到0..n−1並驗gcd=1；完整列所有與n互質的residue得phi(n)，不可拿n−1代替一般phi，也不把nonunit定義為某個數值階。",
        "en": "FIRST require n≥2,normalize into0..n−1 and qualify gcd1.Enumerate ALL unit residues to obtain phi(n);do not replace general phi with n−1 or assign a numeric order to a nonunit."
      },
      "reverse_audit": {
        "kind": "premise_and_result_audit",
        "explanation": {
          "zh-Hant": "反向核對本步原始角色、完整前提與欄序；只接受這些條件下的結論，不把單向結論還原為唯一前提，也不把有限核對稱一般形式證明。",
          "en": "Reverse-audit THIS step against its ORIGINAL ordered roles and complete premises.Accept the conclusion only under these conditions;do not invert a one-way implication or call a finite check a general formal proof."
        }
      },
      "arithmetic": null
    },
    {
      "id": "S004",
      "uses": [
        "G001",
        "S003"
      ],
      "before": "Order ORIGINAL previous residue times unit exponent1 := mul(1, 5)",
      "after": "Order ORIGINAL previous residue times unit exponent1 = 5",
      "relation": "calculation",
      "rule_id": "exact_rational_arithmetic",
      "conditions": [],
      "explanation": {
        "zh-Hant": "按本步原操作數與次序精確運算；來源有理數的pre-reduction界另行保留，不用浮點或偷偷跨bank放寬。",
        "en": "Calculate exactly from THIS step’s ORIGINAL ordered operands.Retain the SOURCE rational pre-reduction envelope separately;do not use floating values or silently widen a different bank."
      },
      "reverse_audit": {
        "kind": "premise_and_result_audit",
        "explanation": {
          "zh-Hant": "以精確有理數重算 Order ORIGINAL previous residue times unit exponent1，不以小數近似替代。",
          "en": "Recompute Order ORIGINAL previous residue times unit exponent1 with exact rational arithmetic, not rounded decimals."
        }
      },
      "arithmetic": {
        "operation": "mul",
        "inputs": [
          "1",
          "5"
        ],
        "output": "5",
        "label": "Order ORIGINAL previous residue times unit exponent1"
      }
    },
    {
      "id": "S005",
      "uses": [
        "G001",
        "S004"
      ],
      "before": "source roles = [first-return exponent1, 5, 24]",
      "after": "derived = [0, 5]",
      "relation": "implies",
      "rule_id": "Finite_MOD_euclidean_quotient_remainder",
      "conditions": [],
      "explanation": {
        "zh-Hant": "以整數Euclidean division核value=n*quotient+remainder與0≤remainder<n，負代表元也正規化；不是浮點餘數。",
        "en": "Use integer Euclidean division: value=n*quotient+remainder with0≤remainder<n.Normalize negative representatives too;do not use floating remainders."
      },
      "reverse_audit": {
        "kind": "premise_and_result_audit",
        "explanation": {
          "zh-Hant": "反向核對本步原始角色、完整前提與欄序；只接受這些條件下的結論，不把單向結論還原為唯一前提，也不把有限核對稱一般形式證明。",
          "en": "Reverse-audit THIS step against its ORIGINAL ordered roles and complete premises.Accept the conclusion only under these conditions;do not invert a one-way implication or call a finite check a general formal proof."
        }
      },
      "arithmetic": null
    },
    {
      "id": "S006",
      "uses": [
        "G001",
        "S005"
      ],
      "before": "Order ORIGINAL previous residue times unit exponent2 := mul(5, 5)",
      "after": "Order ORIGINAL previous residue times unit exponent2 = 25",
      "relation": "calculation",
      "rule_id": "exact_rational_arithmetic",
      "conditions": [],
      "explanation": {
        "zh-Hant": "按本步原操作數與次序精確運算；來源有理數的pre-reduction界另行保留，不用浮點或偷偷跨bank放寬。",
        "en": "Calculate exactly from THIS step’s ORIGINAL ordered operands.Retain the SOURCE rational pre-reduction envelope separately;do not use floating values or silently widen a different bank."
      },
      "reverse_audit": {
        "kind": "premise_and_result_audit",
        "explanation": {
          "zh-Hant": "以精確有理數重算 Order ORIGINAL previous residue times unit exponent2，不以小數近似替代。",
          "en": "Recompute Order ORIGINAL previous residue times unit exponent2 with exact rational arithmetic, not rounded decimals."
        }
      },
      "arithmetic": {
        "operation": "mul",
        "inputs": [
          "5",
          "5"
        ],
        "output": "25",
        "label": "Order ORIGINAL previous residue times unit exponent2"
      }
    },
    {
      "id": "S007",
      "uses": [
        "G001",
        "S006"
      ],
      "before": "source roles = [first-return exponent2, 25, 24]",
      "after": "derived = [1, 1]",
      "relation": "implies",
      "rule_id": "Finite_MOD_euclidean_quotient_remainder",
      "conditions": [],
      "explanation": {
        "zh-Hant": "以整數Euclidean division核value=n*quotient+remainder與0≤remainder<n，負代表元也正規化；不是浮點餘數。",
        "en": "Use integer Euclidean division: value=n*quotient+remainder with0≤remainder<n.Normalize negative representatives too;do not use floating remainders."
      },
      "reverse_audit": {
        "kind": "premise_and_result_audit",
        "explanation": {
          "zh-Hant": "反向核對本步原始角色、完整前提與欄序；只接受這些條件下的結論，不把單向結論還原為唯一前提，也不把有限核對稱一般形式證明。",
          "en": "Reverse-audit THIS step against its ORIGINAL ordered roles and complete premises.Accept the conclusion only under these conditions;do not invert a one-way implication or call a finite check a general formal proof."
        }
      },
      "arithmetic": null
    },
    {
      "id": "S008",
      "uses": [
        "G001",
        "S007"
      ],
      "before": "source roles = [24, 5, 8]",
      "after": "derived = [[[1, 5], [2, 1]], 2]",
      "relation": "implies",
      "rule_id": "Order_SOURCE_UNUSED_qualification_return_table_still_checked",
      "conditions": [],
      "explanation": {
        "zh-Hant": "來源即使qualification只輸出gcd/phi，也先計first-return完整prefix；保留此unused計算責任。從正指數1開始且之前不回1；不宣稱階必等phi或primitive root/加法階。",
        "en": "The SOURCE computes the complete first-return prefix EVEN when qualification outputs only gcd/phi.Retain this UNUSED computation obligation.Start at POSITIVE exponent1 with no earlier return.Do not claim order=phi,a primitive root or additive order."
      },
      "reverse_audit": {
        "kind": "premise_and_result_audit",
        "explanation": {
          "zh-Hant": "反向核對本步原始角色、完整前提與欄序；只接受這些條件下的結論，不把單向結論還原為唯一前提，也不把有限核對稱一般形式證明。",
          "en": "Reverse-audit THIS step against its ORIGINAL ordered roles and complete premises.Accept the conclusion only under these conditions;do not invert a one-way implication or call a finite check a general formal proof."
        }
      },
      "arithmetic": null
    }
  ],
  "math_model": {
    "result": [
      24,
      5,
      5,
      1,
      8,
      true,
      "unit_mod_n_qualified"
    ]
  },
  "conclusion": {
    "canonical_value": "(24, 5, 5, 1, 8, 是, unit_mod_n_qualified)",
    "explanation": {
      "zh-Hant": "依上列完整代值及條件核對得到原題答案；原題編號、格式與狀態保持不變。",
      "en": "The full substitutions and premise checks give the original answer; source identity,format and status are unchanged."
    }
  },
  "definition_note": {
    "zh-Hant": "沿用原題明示的論域、假設與來源 MKO 定義。本題已完成第二對話數理與中英語義覆核，並由原始參數逐題獨立重算模型、答案與每個算術步驟；原題仍為 candidate。",
    "en": "Use the original question domain, assumptions and cited MKO definitions. This item has second-context mathematical and bilingual review, with the model, answer and every arithmetic step independently recomputed from the original parameters; the source question remains a candidate."
  },
  "source": {
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      "english_manifest_path": "public/data/i18n/editions/batch-20261015-advance-20261116-r07-multiplicative-order-mod-n-foundations.en.json",
      "english_rows_path": "public/data/i18n/questions/batch-20261015-advance-20261116-r07-multiplicative-order-mod-n-foundations.en.jsonl"
    },
    "mko_bindings": {
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        "original_path": "public/data/mko/multiplicative-order-mod-n.json",
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    "selected_manifest_sha256": "5233edba9654a6cffd8b6b2d83c932f82ded15f9c0b7c733bd049943e672acff",
    "selected_part_sha256": "df58fcce25614251047f7c41d31ff93b5bfec19cd9bbcaa5fbb42a4daceb0310",
    "original_candidate_sha256": "2fba639fc4096300af933e2b473d283384e24df3708a88119cee9c6254d5daf8",
    "original_candidate_line_sha256": "2fba639fc4096300af933e2b473d283384e24df3708a88119cee9c6254d5daf8",
    "mko_binding_revision": {
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      "derivation": "candidate_authored_and_locally_checked",
      "source_question_state": "candidate",
      "independent_AI_or_human_review": "NOT_PERFORMED",
      "formalization": "not_formalized",
      "Lean": "NOT_RUN"
    },
    "scope_note": {
      "zh-Hant": "來源綁定教學推導候選；精確核對不等於獨立AI／人工審查或一般形式證明。原題、答案、MKO、公式、AST與歷史不變。",
      "en": "Source-bound pedagogical derivation candidate.Exact checking is not independent AI/human review or general formal proof.Original questions,answers,MKOs,formulas,ASTs and history remain unchanged."
    },
    "label": "Frozen producer metadata; current per-question review is separate below."
  },
  "revision": {
    "id": "review-20261026-012-p67",
    "review_date": "2026-10-26",
    "owner_authorized_reader_publication": true,
    "scope": "One hundred sixty family prototypes and their mathematical/bilingual reasoning variants, stems, boundary statements and every distinct explanation shape were reviewed in a context independent of the producer; parameter substitutions, source bindings, full math models, both answer strings and every arithmetic step were independently reconstructed per question from the original parameters only, with negative controls. This grouped method does not claim a separate literal AI reading of every repeated sentence or an extra AI voter.",
    "review_receipts": {
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      "question_first_witness_sha256": "d9bd3a1940da8a73f790ee3fe460c9a8523791bdbe72c8e0304e3740b66710cc"
    },
    "status": "second_context_reviewed",
    "mathematical_semantics": true,
    "bilingual_semantics": true,
    "steps_reviewed": 8,
    "method": "family_template_semantic_review_plus_independent_per_instance_reconstruction",
    "exact_question_first_check": {
      "model_sha256": "d06e084aa48b797343914e8d48fc424e159276c3c93059d357d900816183437e",
      "arithmetic_steps": 2
    },
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    "human_review": "NOT_PERFORMED",
    "formalization": "not_formalized",
    "Lean": "NOT_RUN",
    "Canonical_truth_promotion": false,
    "authority": "Owner-authorized reviewed reader publication; original question/candidate states remain historical and unchanged."
  }
}
