Main derivation
S01 · definition
Before
\angle AOC,\ \angle COB,\ \angle BOD,\ \angle DOA
After
\alpha=m\angle AOC,\ \beta=m\angle COB,\ \gamma=m\angle BOD,\ \delta=m\angle DOA
Conditions: none
Rule: def_intro · Uses: G1, G2
Leaf basis: def_intro + mko_angle_def
Name the measures of the four angles with vertex O. By the MKO, the size of an angle is the opening between its sides, independent of how long the rays are drawn. ∠AOC and ∠BOD are one pair of vertical angles (OA is opposite to OB and OC is opposite to OD); ∠COB and ∠DOA are the other pair.
S02 · theorem_application
Before
A\text{-}O\text{-}B,\ C\notin\overleftrightarrow{AB}After
\alpha+\beta=180
Conditions: O\ \text{between}\ A,B; C\notin\overleftrightarrow{AB}
Rule: linear_pair · Uses: S01, G2
Leaf basis: linear_pair
Apply the linear pair postulate to line AB and the point C (X=C): m∠AOC+m∠COB=180°, that is α+β=180. Both hypotheses of the postulate, O between A and B and C not on line AB, come from G2.
S03 · theorem_application
Before
C\text{-}O\text{-}D,\ B\notin\overleftrightarrow{CD}After
\beta+\gamma=180
Conditions: O\ \text{between}\ C,D; B\notin\overleftrightarrow{CD}
Rule: linear_pair · Uses: S01, G2
Leaf basis: linear_pair + angle_symmetric
Apply the linear pair postulate to line CD and the point B (the postulate's A, B become C, D, and X=B): m∠COB+m∠BOD=180°, that is β+γ=180.
S04 · implies
Before
\alpha+\beta=180,\ \beta+\gamma=180
After
\alpha+\beta=\gamma+\beta
Conditions: none
Rule: eq_refl_symm_trans · Uses: S02, S03
Leaf basis: eq_refl_symm_trans + add_comm
Both right sides are 180, so symmetry and transitivity of equality give α+β=β+γ; commutativity of addition rewrites this as α+β=γ+β, with the common term β in the same place on both sides.
S05 · equivalent
Before
\alpha+\beta=\gamma+\beta
After
\alpha=\gamma
Conditions: none
Rule: L_cancel · Uses: S04
Leaf basis: eq_congruence + add_assoc + add_inverse + add_zero
By Lemma L_cancel (u=α, v=γ, w=β) cancel β from both sides to get α=γ, that is m∠AOC=m∠BOD.
S06 · theorem_application
Before
A\text{-}O\text{-}B,\ D\notin\overleftrightarrow{AB}After
\delta+\gamma=180
Conditions: O\ \text{between}\ A,B; D\notin\overleftrightarrow{AB}
Rule: linear_pair · Uses: S01, G2
Leaf basis: linear_pair + angle_symmetric
Apply the linear pair postulate to line AB and the point D (X=D): m∠AOD+m∠DOB=180°. By angle_symmetric, m∠AOD=m∠DOA=δ and m∠DOB=m∠BOD=γ, so δ+γ=180.
S07 · implies
Before
\beta+\gamma=180,\ \delta+\gamma=180
After
\beta+\gamma=\delta+\gamma
Conditions: none
Rule: eq_refl_symm_trans · Uses: S03, S06
Leaf basis: eq_refl_symm_trans
Both right sides are 180, so symmetry and transitivity of equality give β+γ=δ+γ.
S08 · equivalent
Before
\beta+\gamma=\delta+\gamma
After
\beta=\delta
Conditions: none
Rule: L_cancel · Uses: S07
Leaf basis: eq_congruence + add_assoc + add_inverse + add_zero
By Lemma L_cancel (w=γ) cancel γ to get β=δ, that is m∠COB=m∠DOA.
S09 · implies
Before
\alpha=\gamma,\ \beta=\delta
After
m\angle AOC=m\angle BOD,\ m\angle COB=m\angle DOA
Conditions: none
Rule: def_unfold · Uses: S05, S08
Leaf basis: def_unfold + and_intro_elim
Unfold the names back to the angles: both pairs of vertical angles are equal. The proof used no particular measure and no measurement of a figure, so it holds for every configuration satisfying G2.
S10 · implies
Before
\alpha=35
After
\beta=145,\ \gamma=35,\ \delta=145
Conditions: none
Rule: eq_congruence · Uses: G3, S02, S05, S08
Leaf basis: eq_congruence + eq_replace + numeric_evaluation
Substitute α=35: from S02, β=180−35=145; from S05, γ=α=35; from S08, δ=β=145. Check: 35+145=180.
Error controls and negative controls
Measuring a figure is not a proof
The MKO notes the common mistake of guessing measures from a sketch. Measuring ∠AOC and ∠BOD as apparently equal in one drawing supports only that drawing, with measurement error; the proof here uses only the incidence data of G2 and the linear pair postulate, so it covers every configuration satisfying G2.
Adjacent angles are not always supplementary
The linear pair postulate needs A, O, B collinear with O in the middle. If three rays from O point in the directions 0°, 50° and 120°, the two adjacent angles are 50° and 70°, summing to 120°, not 180°. That is why S02, S03 and S06 must cite 'O between the two points' from G2.
Supplementary angles need not be adjacent
The MKO explains that being supplementary depends only on the measures summing to 180° and does not require the angles to be adjacent. This proof uses the special adjacent case of a linear pair to obtain supplementary angles; conversely, supplementary angles need not form a linear pair.
- ∠AOC and ∠COB share the side OC, so m∠AOC+m∠COB=180° →
reject — A, O, B must also be collinear with O in the middle; rays at 0°, 50° and 120° give 50°+70°=120°. - Vertical angles are equal, so adjacent angles are equal too →
reject — With α=35 we get β=145, so adjacent angles differ. - Supplementary angles must be adjacent in the figure →
reject — Angles of 30° and 150° may lie in different figures; their measures sum to 180°, so they are supplementary (MKO). - In a drawing ∠AOC measures about the same as ∠BOD, so the vertical-angle theorem is proved →
reject — One measurement supports only that drawing, with error, and does not cover all configurations.