S01 · implies
Before
N=\{S\},\quad\Sigma=\{a,b\}After
N\cap\Sigma=\varnothing,\quad S\in N
Conditions: none
Rule: calc · Uses: G1
Leaf basis: calc
Both alphabets are finite, internally distinct and disjoint, with a nonterminal start.
derivation-mko-context-free-grammar-01 · ocme-new142-reader-adoption-20261021
The grammar S to aSb or epsilon has finite derivation witnesses for aaabbb and epsilon.
Grammar qualification and specified-word membership are separate; no regularity or CFG-PDA equivalence claim.
calcG1 — N={S}, terminals {a,b}, start S; all productions are S to aSb and S to epsilon; epsilon is the empty rhs.N,\Sigma — nonterminal and terminal setsP — complete production setcalc · prerequisite — Assume finite sets, finite strings and indices, stepwise function updates and induction on natural numbers; epsilon denotes the length-zero word.mko_definition · cited — Each right side is a finite string over terminal and nonterminal symbols, with the epsilon convention explicit. A derivation is a finite production sequence. The generated language contains only terminal-only words derivable from the start. The empty language is not a language containing epsilon. A derivation witness proves membership, but bounded-search failure does not prove nonmembership. Unambiguity, regularity and CFG-PDA equivalence do not follow automatically. · mko-context-free-grammarBefore
N=\{S\},\quad\Sigma=\{a,b\}After
N\cap\Sigma=\varnothing,\quad S\in N
Conditions: none
Rule: calc · Uses: G1
Leaf basis: calc
Both alphabets are finite, internally distinct and disjoint, with a nonterminal start.
Before
P=\{S\to aSb,\ S\to\varepsilon\}After
\text{each lhs is one nonterminal; every rhs symbol is legal}Conditions: none
Rule: calc · Uses: G1, S01
Leaf basis: calc
Both left sides are the single nonterminal S; aSb uses legal symbols and epsilon is a length-zero string, not another character.
Before
S
After
aSb
Conditions: none
Rule: calc · Uses: G1, S02
Leaf basis: calc
Apply S to aSb at the start, leaving one S.
Before
aSb
After
aaSbb
Conditions: none
Rule: calc · Uses: G1, S02, S03
Leaf basis: calc
Replace only the central S, preserving the surrounding terminals' order.
Before
aaSbb
After
aaaSbbb
Conditions: none
Rule: calc · Uses: G1, S02, S04
Leaf basis: calc
Use the same production again to create a third a,b pair.
Before
aaaSbbb
After
aaabbb
Conditions: none
Rule: calc · Uses: G1, S02, S05
Leaf basis: calc
Use S to epsilon to remove the sole S without deleting or reordering terminals.
Before
S\Rightarrow aSb\Rightarrow aaSbb\Rightarrow aaaSbbb\Rightarrow aaabbb
After
aaabbb\in L(G)
Conditions: none
Rule: mko_definition · Uses: G1, S03, S04, S05, S06
Leaf basis: mko_definition
Four legal production steps end at a terminal-only word, certifying membership.
Before
S\Rightarrow\varepsilon
After
\varepsilon\in L(G),\quad L(G)\ne\varnothing
Conditions: none
Rule: calc · Uses: G1, S02, S07
Leaf basis: calc
The empty production gives another finite witness; a language containing epsilon is not empty.
Before
\text{search depth }2After
aaabbb\text{ not found by depth 2, but has the depth-4 witness above}Conditions: none
Rule: calc · Uses: G1, S03, S04, S05, S06, S07
Leaf basis: calc
A too-shallow search does not prove nonmembership, as the exact depth-four witness shows.
No substeps in this guide.
S09 · premise_audit · G1, S03, S04, S05, S06, S07 — The grammar's explicit witness suffices without invoking CFG-PDA equivalence.S08 · premise_audit · G1, S02, S07 — Epsilon is an element of the language, whereas the empty language has no elements.S07 · premise_audit · G1, S03, S04, S05, S06 — This witness certifies this word only, not unambiguity.S06 · premise_audit · G1, S02, S05 — An epsilon replacement has length zero and does not output a letter called epsilon.S05 · premise_audit · G1, S02, S04 — Each step rewrites the actual single S rather than replacing an arbitrary whole word.S04 · premise_audit · G1, S02, S03 — A previously produced terminal a cannot be rewritten as S.S03 · premise_audit · G1, S02 — A nonterminal remains, so this is not a terminal-only endpoint.S02 · premise_audit · G1, S01 — Grammar qualification does not imply every word is derivable.S01 · premise_audit · G1 — S is not terminal; a sentential form containing S is not a terminal word.A sentential form containing S is not an accepted terminal word.
Rewrite only a valid lhs occurrence and preserve other symbols' order.
reject — It still contains nonterminal S.reject — Epsilon is already an element, and aaabbb is another.reject — The explicit depth-four derivation certifies membership.The grammar S to aSb or epsilon has finite derivation witnesses for aaabbb and epsilon.
0 declared checks for this guide; only the listed expressions are covered.
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