Tracing 1011 through a complete DFA On this page Goal and scope Givens and symbols Rules and sources Main derivation Substeps and lemmas Reverse audits Error controls and negative controls Result and limitations Verification and source binding ← Guide index · Original MKO
This is an owner-adopted natural-language teaching guide. Finite/arithmetic checks are not universal proofs; no Lean was run, and review scope is recorded per revision. Original source status labels are retained as historical data. Formulas retain exact TeX; no new semantic AST is invented.
derivation-mko-finite-automaton-01 · ocme-new142-reader-adoption-20261021
Goal and scope The specified DFA rejects 1011 and accepts epsilon.
A full deterministic total Q-by-alphabet table and finite-word traces, not language equivalence from examples.
Givens and symbols G1 — Q={E,O}, alphabet={0,1}, start=E, finals={E}; delta(E,0)=E,delta(E,1)=O,delta(O,0)=O,delta(O,1)=E; word=1011.\delta^* — iterated transition on a wordi — number of consumed symbolsRules and sources Some rule statements have reader clarifications in this revision: they are paraphrases, not verbatim quotations. Referenced original source bytes and hashes are unchanged.
calc · prerequisite — Assume finite sets, finite strings and indices, stepwise function updates and induction on natural numbers; epsilon denotes the length-zero word.mko_definition · cited — Completely check that each Q×Sigma input has exactly one valid output, then trace each complete finite word in order. The empty word is accepted exactly when the initial state is accepting. One finite trace does not establish language equivalence or regularity of an unspecified target language. · mko-finite-automatonMain derivation S01 · implies Before
Q=\{E,O\},\quad\Sigma=\{0,1\} After
\begin{array}{c|cc}\delta&0&1\\\hline E&E&O\\O&O&E\end{array} Conditions: none
Rule: calc · Uses: G1
Leaf basis: calc
Each of the four state-symbol pairs has exactly one output in Q, completely checking totality and determinism.
S02 · implies Before
w=1011,\quad q_0=E After
(q,i)=(E,0) Conditions: none
Rule: calc · Uses: G1, S01
Leaf basis: calc
Initialize at the unique start; position zero means no symbol has been read.
S03 · implies Before
(E,0),\quad w_1=1 After
(O,1) Conditions: none
Rule: calc · Uses: G1, S01, S02
Leaf basis: calc
Reading the first 1 uses delta(E,1)=O and advances position by one.
S04 · implies Before
(O,1),\quad w_2=0 After
(O,2) Conditions: none
Rule: calc · Uses: G1, S01, S03
Leaf basis: calc
The second symbol 0 keeps O unchanged while still consuming that symbol.
S05 · implies Before
(O,2),\quad w_3=1 After
(E,3) Conditions: none
Rule: calc · Uses: G1, S01, S04
Leaf basis: calc
The third symbol 1 returns to E, with one final 1 still unread.
S06 · implies Before
(E,3),\quad w_4=1 After
(O,4),\quad4=|w| Conditions: none
Rule: calc · Uses: G1, S01, S05
Leaf basis: calc
The final 1 sends E to O, consuming all four symbols in order.
S07 · implies Before
\delta^*(E,1011)=O,\quad F=\{E\} After
O\notin F\Rightarrow1011\text{ rejected} Conditions: none
Rule: mko_definition · Uses: G1, S06
Leaf basis: mko_definition
The unique complete run ends outside the final set, rejecting this word.
S08 · implies Before
w=\varepsilon,\quad|w|=0 After
\delta^*(E,\varepsilon)=E\in F\Rightarrow\varepsilon\text{ accepted} Conditions: none
Rule: calc · Uses: G1, S01, S07
Leaf basis: calc
The empty word makes no transition, so the start is final and epsilon is accepted.
Substeps and lemmas No substeps in this guide.
Reverse audits S08 · premise_audit · G1, S01, S07 — No epsilon edge is added; an empty word differs from an epsilon transition.S07 · premise_audit · G1, S06 — This certifies the specified word, not equivalence with an arbitrary target language.S06 · premise_audit · G1, S01, S05 — One cannot stop at E in S05 and discard the last symbol.S05 · premise_audit · G1, S01, S04 — Reaching a final state midway does not yet accept the whole word.S04 · premise_audit · G1, S01, S03 — An unchanged state is not an epsilon move; the position advances from 1 to 2.S03 · premise_audit · G1, S01, S02 — There is only one successor; remaining at E is not a choice.S02 · premise_audit · G1, S01 — An accepting start does not allow ignoring the remaining nonempty input.S01 · premise_audit · G1 — There is no epsilon transition or multivalued cell.Error controls and negative controls Total table All four state-symbol cells need one legal output.
Consume all input Check acceptance only after position equals word length.
An intermediate E accepts 1011. → reject — The final 1 remains; the full terminal state is O. An unchanged state on 0 consumes no input. → reject — Every DFA input transition consumes one symbol and advances position. Accepting epsilon requires an epsilon transition. → reject — The empty word takes no edge and start E is final. Result and limitations The specified DFA rejects 1011 and accepts epsilon.
Verification and source binding 0 declared checks for this guide; only the listed expressions are covered.
source commit: b1b2f1dcf8c50d67a93fe52d95f8eef7b3abba9f adopted source SHA-256: c631c60e2976f05f20ff82cd04318bc5c870bf60c51efcfb4bf34202ec0524b1 original source SHA-256: 1b4e2cc34b16b6214d69dfde3f776b2089abe1dec7d7ab3534bf2cf53e8d3aae Lean: NOT_RUN · independent AI: SCOPED_LEAD_AND_BILINGUAL_CONTEXT_REVIEW Same-source full JSON (formulas, ASTs, controls and revision log)