S01 · implies
Before
x\in X
After
2\mid x-x=0
Conditions: none
Rule: calc · Uses: G1
Leaf basis: calc
Every element relates to itself, proving reflexivity.
derivation-mko-quotient-set-01 · ocme-new142-reader-adoption-20261021
X/R={{0,2},{1,3}}, and projection values are whole classes.
A complete finite carrier and parity equivalence; no automatically inherited operation.
calcG1 — X={0,1,2,3}; xRy exactly when 2 divides x-y.E,O — even and odd classes\pi — canonical projectioncalc · prerequisite — Assume integer divisibility laws, extensional set equality and the definition of a function.mko_definition · cited — X/R is the set of all distinct equivalence classes, not a set of selected representatives. The classes cover X and are pairwise disjoint. The canonical projection sends each element to its class. Any quotient operation still needs a separate proof of independence from representative choice. · mko-quotient-setBefore
x\in X
After
2\mid x-x=0
Conditions: none
Rule: calc · Uses: G1
Leaf basis: calc
Every element relates to itself, proving reflexivity.
Before
2\mid x-y
After
2\mid y-x=-(x-y)
Conditions: none
Rule: calc · Uses: G1
Leaf basis: calc
Negation preserves divisibility, so the relation is symmetric.
Before
2\mid x-y,\quad2\mid y-z
After
2\mid x-z=(x-y)+(y-z)
Conditions: none
Rule: calc · Uses: G1, S01, S02
Leaf basis: calc
A sum of two even integers is even, proving transitivity and completing equivalence qualification.
Before
[x]=\{y\in X:2\mid y-x\}After
[0]=[2]=\{0,2\}Conditions: none
Rule: calc · Uses: G1, S03
Leaf basis: calc
Checking all four differences with 0 and 2 gives the complete even class {0,2}.
Before
[1],\ [3]
After
[1]=[3]=\{1,3\}Conditions: none
Rule: calc · Uses: G1, S03
Leaf basis: calc
The complete odd class is {1,3}; classes of all four elements have now been computed.
Before
\{[0],[1],[2],[3]\}After
X/R=\{\{0,2\},\{1,3\}\}Conditions: none
Rule: mko_definition · Uses: G1, S04, S05
Leaf basis: mko_definition
Normalize each class as its sorted element set and deduplicate, leaving two quotient elements.
Before
E=\{0,2\},\quad O=\{1,3\}After
E\cup O=X,\quad E\cap O=\varnothing
Conditions: none
Rule: calc · Uses: G1, S06
Leaf basis: calc
The two explicit classes cover all four elements and are disjoint, giving a partition.
Before
\pi:X\to X/R
After
\pi(0)=E,\ \pi(1)=O,\ \pi(2)=E,\ \pi(3)=O
Conditions: none
Rule: calc · Uses: G1, S06, S07
Leaf basis: calc
The full projection sends every element to its unique whole class and hits every quotient element.
No substeps in this guide.
S08 · premise_audit · G1, S06, S07 — Outputs are E or O, not numbers 0 or 1; no new quotient operation has been declared.S07 · premise_audit · G1, S06 — Both classes are nonempty; coverage and disjointness are checked, not merely the number of classes.S06 · premise_audit · G1, S04, S05 — Deduplication removes repeated classes, not distinct elements within a class; {0,1} is only a representative set.S05 · premise_audit · G1, S03 — 1 and 3 relate to each other but not to 0 or 2, so no class is missing.S04 · premise_audit · G1, S03 — Do not retain only representative 0; 2 belongs to the same class, not another quotient element.S03 · premise_audit · G1, S01, S02 — x,y,z must all lie in the same carrier X.S02 · premise_audit · G1 — Negating again recovers x-y, so no direction is lost.S01 · premise_audit · G1 — The formula covers all four elements without choosing representatives.The codomain of pi is the set of classes, not selected representatives.
To define f([x])=g(x), verify xRy implies g(x)=g(y).
reject — 0 and 1 can be representatives, but the quotient elements are sets E and O.reject — Both classes are exactly {0,2}.reject — f(x)=x differs on 0 and 2, so it cannot define a single value f([0]).X/R={{0,2},{1,3}}, and projection values are whole classes.
0 declared checks for this guide; only the listed expressions are covered.
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