S01 · implies
Before
n>1,\quad d=\min\{m>1:m\mid n\}After
d\text{ prime}Conditions: none
Rule: calc · Uses: G1
Leaf basis: calc
If d=uv with 1<u<d, then u divides n, contradicting minimality; hence the least nonunit divisor is prime.
derivation-mko-unique-prime-factorization-01 · ocme-new142-reader-adoption-20261021
Every positive integer n>1 has a unique prime multiset; 360=2^3*3^2*5, with signs and units separate.
Existence and uniqueness by strong induction and an explicit Bezout prerequisite, then complete trial division for 360.
calcG1 — The theorem domain is integers n>1; the example is 360; factor order is ignored but multiplicity retained.p_i,q_j — prime factors with multiplicityr,s — finite factor countscalc · prerequisite — Assume exact integer arithmetic, division with remainder, and definitions of divisibility and gcd; every congruence has an explicit modulus. Also assume well-founded/strong induction on positive integers and the Bezout identity for coprime integers.mko_definition · cited — Separate existence from uniqueness. Induction/well-founded reasoning gives existence, with complete bounded trial-division instances as computational companions. Uniqueness keeps the Euclid-lemma witness p|ab implies p|a or p|b, not just a few matching outputs. General factorizations may contain several distinct primes. Separate a negative sign, units±1 with the empty prime product and zero, which has no such factorization. · mko-unique-prime-factorizationBefore
n>1,\quad d=\min\{m>1:m\mid n\}After
d\text{ prime}Conditions: none
Rule: calc · Uses: G1
Leaf basis: calc
If d=uv with 1<u<d, then u divides n, contradicting minimality; hence the least nonunit divisor is prime.
Before
n=dq,\quad d\text{ prime},\quad1\le q<nAfter
q=1\Rightarrow n=d;\quad q>1\Rightarrow q\text{ has prime factors by induction}Conditions: none
Rule: calc · Uses: G1, S01
Leaf basis: calc
The quotient is smaller than n; strong induction factors q and adjoining d proves existence, with n=2 covered by q=1.
Before
p\text{ prime},\quad p\mid ab,\quad p\nmid aAfter
\gcd(p,a)=1\Rightarrow\exists u,v:\ up+va=1
Conditions: none
Rule: calc · Uses: G1
Leaf basis: calc
The only positive divisors of p are 1,p; since p does not divide a, they are coprime and the stated Bezout prerequisite applies.
Before
up+va=1,\quad p\mid ab
After
b=upb+vab\Rightarrow p\mid b
Conditions: none
Rule: calc · Uses: G1, S03
Leaf basis: calc
After multiplication by b, both terms are divisible by p, proving Euclid's lemma.
Before
\prod_{i=1}^{r}p_i=\prod_{j=1}^{s}q_j,\quad p_i,q_j\text{ prime}After
p_1\mid\prod_{j=1}^{s}q_j\Rightarrow\exists j:\ p_1\mid q_j\Rightarrow p_1=q_jConditions: none
Rule: calc · Uses: G1, S04
Leaf basis: calc
Finite-product induction using Euclid's lemma makes p1 equal to one prime on the right.
Before
p_1=q_j\ne0
After
\text{cancel }p_1\text{ and induct on }r+s\Rightarrow\{p_i\}_{\rm multiset}=\{q_j\}_{\rm multiset}Conditions: none
Rule: calc · Uses: G1, S02, S05
Leaf basis: calc
Cancel the nonzero prime and decrease the total factor count until empty product 1; a nonempty prime product is at least 2 and cannot equal 1.
Before
360
After
360=2\cdot180=2^2\cdot90=2^3\cdot45=2^3\cdot3\cdot15=2^3\cdot3^2\cdot5
Conditions: none
Rule: calc · Uses: G1, S01, S02
Leaf basis: calc
Extract 2 three times and 3 twice, leaving 5. Primes 2,3 qualify, and testing 2 suffices for remaining 5 since 3^2>5.
Before
2^3\cdot3^2\cdot5=360
After
360\text{ has multiset }\{2,2,2,3,3,5\}\text{ uniquely}Conditions: none
Rule: mko_definition · Uses: G1, S06, S07
Leaf basis: mko_definition
Recheck the exact product; the uniqueness argument ensures any other prime list differs only in order.
Before
-360,\quad1,\quad-1,\quad0
After
-360=-(2^3 3^2 5),\quad\pm1\text{ use empty prime product};\quad0\text{ excluded}Conditions: none
Rule: calc · Uses: G1, S06, S08
Leaf basis: calc
A negative sign is a unit factor; ±1 use empty prime product 1, and zero is outside the n>1 factorization domain.
No substeps in this guide.
S09 · premise_audit · G1, S06, S08 — Every prime divides zero, so it cannot have a finite unique prime multiset.S08 · premise_audit · G1, S06, S07 — A single prime-power expression is insufficient because this example has three distinct primes.S07 · premise_audit · G1, S01, S02 — The remaining 5 is not an unchecked composite; trial division reaches the square-root boundary.S06 · premise_audit · G1, S02, S05 — Uniqueness retains multiplicities while ignoring order, and distinguishes empty from nonempty endpoints.S05 · premise_audit · G1, S04 — This handles arbitrary finite prime factorizations, not merely two computed outputs.S04 · premise_audit · G1, S03 — The case p dividing a is immediate; composite p does not ensure the preceding coprimality.S03 · premise_audit · G1 — This identifies the actual Bezout dependency rather than assuming the Euclid lemma being proved.S02 · premise_audit · G1, S01 — Induction uses only smaller positive integers, not the same n.S01 · premise_audit · G1 — The divisor set is nonempty because n itself belongs; well-foundedness supplies its minimum.Strong induction gives existence; Euclid's lemma and cancellation give uniqueness.
Compare prime multisets, not only distinct-prime sets.
reject — The right side is 120, missing a factor 3.reject — 4 divides 2*2 but neither factor 2.reject — The empty product is 1, not zero.Every positive integer n>1 has a unique prime multiset; 360=2^3*3^2*5, with signs and units separate.
1 declared checks for this guide; only the listed expressions are covered.
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