{"schema_version":"ocme-site-results-v1","locale":"en","page_type":"derivations","facts":{"questions":36000,"reviewed":36000,"display_candidates":0,"knowledge":302,"guides":299,"paths":59,"batches":360,"families":1441,"atlas":302,"core":80,"evidence":9,"formal_evidence":5,"formal_subjects":4,"lean_files":6,"lean_toolchain":"leanprover/lean4:v4.30.0","question_state":"candidate","english_state":"ai_candidate","question_Lean":"NOT_RUN","canonical_truth_promotion":false},"filters":{"q":"mko-numerical-approximation-error"},"kind":"guides","total":1,"pages":1,"page":1,"entries":[{"id":"derivation-mko-numerical-approximation-error-01","title":{"zh-Hant":"數值近似與誤差：以 0.33 近似 1/3 的絕對誤差、相對誤差與容許範圍","en":"Numerical approximation and error: absolute error, relative error and tolerance for 0.33 approximating 1/3"},"summary":{"zh-Hant":"以精確有理數計算：近似值 a=33/100 相對參照值 x=1/3 的絕對誤差與相對誤差；判定 a 是否在容許誤差 τ₁=1/250、τ₂=1/400、τ₃=1/300 之內（τ₃ 為端點情形）；證明 |a−x|≤τ ⇔ x−τ≤a≤x+τ；比較放大 1000 倍後的誤差；說明參照值為 0 時相對誤差沒有定義，以及誤差數值本身不能說明誤差來源。","en":"Using exact rationals: compute the absolute and relative error of the approximation a=33/100 to the reference x=1/3; decide whether a is within the tolerances τ₁=1/250, τ₂=1/400 and τ₃=1/300 (τ₃ is the endpoint case); prove |a−x|≤τ ⇔ x−τ≤a≤x+τ; compare the errors after scaling by 1000; explain why relative error is undefined for a zero reference and why an error value alone does not reveal the source of the error."},"mko_ids":["mko-numerical-approximation-error"]}],"title":"Concept derivation guides"}