Tagged Choice Counts and Actual Branch Widths
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This question bank has corresponding bilingual step-by-step derivations. Source candidate and English ai_candidate states are retained. AI review, finite computation and Lean formal proof are labelled separately.
batch-20261008-advance-20261012-r02-counting-principle-foundations · 2026-10-08 · 100 questions
This English edition is an AI candidate and does not yet have an OCME Atlas (GPT-6) Twin closure receipt.
1. Disjoint Tagged Choices and Prefix Counts
Mutually exclusive tagged categories have ordered sizes=[]. Give (total choices, each prefix’s total), retaining an empty list.
View answer and explanation
(0, [])
Add category sizes in order; no categories give total zero. This is a choice protocol, not a probability-independence assumption. The exact result, retaining the requested order, is (0, []).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-disjoint-choice-sizes · candidate
2. Disjoint Tagged Choices and Prefix Counts
Mutually exclusive tagged categories have ordered sizes=[0]. Give (total choices, each prefix’s total), retaining an empty list.
View answer and explanation
(0, [0])
Add category sizes in order; no categories give total zero. This is a choice protocol, not a probability-independence assumption. The exact result, retaining the requested order, is (0, [0]).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-disjoint-choice-sizes · candidate
3. Disjoint Tagged Choices and Prefix Counts
Mutually exclusive tagged categories have ordered sizes=[1]. Give (total choices, each prefix’s total), retaining an empty list.
View answer and explanation
(1, [1])
Add category sizes in order; no categories give total zero. This is a choice protocol, not a probability-independence assumption. The exact result, retaining the requested order, is (1, [1]).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-disjoint-choice-sizes · candidate
4. Disjoint Tagged Choices and Prefix Counts
Mutually exclusive tagged categories have ordered sizes=[2, 0, 3, 1]. Give (total choices, each prefix’s total), retaining an empty list.
View answer and explanation
(6, [2, 2, 5, 6])
Add category sizes in order; no categories give total zero. This is a choice protocol, not a probability-independence assumption. The exact result, retaining the requested order, is (6, [2, 2, 5, 6]).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-disjoint-choice-sizes · candidate
5. Disjoint Tagged Choices and Prefix Counts
Mutually exclusive tagged categories have ordered sizes=[1, 1]. Give (total choices, each prefix’s total), retaining an empty list.
View answer and explanation
(2, [1, 2])
Add category sizes in order; no categories give total zero. This is a choice protocol, not a probability-independence assumption. The exact result, retaining the requested order, is (2, [1, 2]).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-disjoint-choice-sizes · candidate
6. Disjoint Tagged Choices and Prefix Counts
Mutually exclusive tagged categories have ordered sizes=[1, 2]. Give (total choices, each prefix’s total), retaining an empty list.
View answer and explanation
(3, [1, 3])
Add category sizes in order; no categories give total zero. This is a choice protocol, not a probability-independence assumption. The exact result, retaining the requested order, is (3, [1, 3]).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-disjoint-choice-sizes · candidate
7. Disjoint Tagged Choices and Prefix Counts
Mutually exclusive tagged categories have ordered sizes=[1, 3]. Give (total choices, each prefix’s total), retaining an empty list.
View answer and explanation
(4, [1, 4])
Add category sizes in order; no categories give total zero. This is a choice protocol, not a probability-independence assumption. The exact result, retaining the requested order, is (4, [1, 4]).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-disjoint-choice-sizes · candidate
8. Disjoint Tagged Choices and Prefix Counts
Mutually exclusive tagged categories have ordered sizes=[1, 4]. Give (total choices, each prefix’s total), retaining an empty list.
View answer and explanation
(5, [1, 5])
Add category sizes in order; no categories give total zero. This is a choice protocol, not a probability-independence assumption. The exact result, retaining the requested order, is (5, [1, 5]).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-disjoint-choice-sizes · candidate
9. Disjoint Tagged Choices and Prefix Counts
Mutually exclusive tagged categories have ordered sizes=[1, 5]. Give (total choices, each prefix’s total), retaining an empty list.
View answer and explanation
(6, [1, 6])
Add category sizes in order; no categories give total zero. This is a choice protocol, not a probability-independence assumption. The exact result, retaining the requested order, is (6, [1, 6]).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-disjoint-choice-sizes · candidate
10. Disjoint Tagged Choices and Prefix Counts
Mutually exclusive tagged categories have ordered sizes=[1, 6]. Give (total choices, each prefix’s total), retaining an empty list.
View answer and explanation
(7, [1, 7])
Add category sizes in order; no categories give total zero. This is a choice protocol, not a probability-independence assumption. The exact result, retaining the requested order, is (7, [1, 7]).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-disjoint-choice-sizes · candidate
11. Disjoint Tagged Choices and Prefix Counts
Mutually exclusive tagged categories have ordered sizes=[1, 7]. Give (total choices, each prefix’s total), retaining an empty list.
View answer and explanation
(8, [1, 8])
Add category sizes in order; no categories give total zero. This is a choice protocol, not a probability-independence assumption. The exact result, retaining the requested order, is (8, [1, 8]).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-disjoint-choice-sizes · candidate
12. Disjoint Tagged Choices and Prefix Counts
Mutually exclusive tagged categories have ordered sizes=[1, 8]. Give (total choices, each prefix’s total), retaining an empty list.
View answer and explanation
(9, [1, 9])
Add category sizes in order; no categories give total zero. This is a choice protocol, not a probability-independence assumption. The exact result, retaining the requested order, is (9, [1, 9]).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-disjoint-choice-sizes · candidate
13. Disjoint Tagged Choices and Prefix Counts
Mutually exclusive tagged categories have ordered sizes=[2, 1]. Give (total choices, each prefix’s total), retaining an empty list.
View answer and explanation
(3, [2, 3])
Add category sizes in order; no categories give total zero. This is a choice protocol, not a probability-independence assumption. The exact result, retaining the requested order, is (3, [2, 3]).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-disjoint-choice-sizes · candidate
14. Disjoint Tagged Choices and Prefix Counts
Mutually exclusive tagged categories have ordered sizes=[2, 2]. Give (total choices, each prefix’s total), retaining an empty list.
View answer and explanation
(4, [2, 4])
Add category sizes in order; no categories give total zero. This is a choice protocol, not a probability-independence assumption. The exact result, retaining the requested order, is (4, [2, 4]).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-disjoint-choice-sizes · candidate
15. Disjoint Tagged Choices and Prefix Counts
Mutually exclusive tagged categories have ordered sizes=[2, 3]. Give (total choices, each prefix’s total), retaining an empty list.
View answer and explanation
(5, [2, 5])
Add category sizes in order; no categories give total zero. This is a choice protocol, not a probability-independence assumption. The exact result, retaining the requested order, is (5, [2, 5]).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-disjoint-choice-sizes · candidate
16. Disjoint Tagged Choices and Prefix Counts
Mutually exclusive tagged categories have ordered sizes=[2, 4]. Give (total choices, each prefix’s total), retaining an empty list.
View answer and explanation
(6, [2, 6])
Add category sizes in order; no categories give total zero. This is a choice protocol, not a probability-independence assumption. The exact result, retaining the requested order, is (6, [2, 6]).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-disjoint-choice-sizes · candidate
17. Disjoint Tagged Choices and Prefix Counts
Mutually exclusive tagged categories have ordered sizes=[2, 5]. Give (total choices, each prefix’s total), retaining an empty list.
View answer and explanation
(7, [2, 7])
Add category sizes in order; no categories give total zero. This is a choice protocol, not a probability-independence assumption. The exact result, retaining the requested order, is (7, [2, 7]).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-disjoint-choice-sizes · candidate
18. Disjoint Tagged Choices and Prefix Counts
Mutually exclusive tagged categories have ordered sizes=[2, 6]. Give (total choices, each prefix’s total), retaining an empty list.
View answer and explanation
(8, [2, 8])
Add category sizes in order; no categories give total zero. This is a choice protocol, not a probability-independence assumption. The exact result, retaining the requested order, is (8, [2, 8]).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-disjoint-choice-sizes · candidate
19. Disjoint Tagged Choices and Prefix Counts
Mutually exclusive tagged categories have ordered sizes=[2, 7]. Give (total choices, each prefix’s total), retaining an empty list.
View answer and explanation
(9, [2, 9])
Add category sizes in order; no categories give total zero. This is a choice protocol, not a probability-independence assumption. The exact result, retaining the requested order, is (9, [2, 9]).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-disjoint-choice-sizes · candidate
20. Disjoint Tagged Choices and Prefix Counts
Mutually exclusive tagged categories have ordered sizes=[2, 8]. Give (total choices, each prefix’s total), retaining an empty list.
View answer and explanation
(10, [2, 10])
Add category sizes in order; no categories give total zero. This is a choice protocol, not a probability-independence assumption. The exact result, retaining the requested order, is (10, [2, 10]).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-disjoint-choice-sizes · candidate
21. Disjoint Tagged Choices and Prefix Counts
Mutually exclusive tagged categories have ordered sizes=[3, 1]. Give (total choices, each prefix’s total), retaining an empty list.
View answer and explanation
(4, [3, 4])
Add category sizes in order; no categories give total zero. This is a choice protocol, not a probability-independence assumption. The exact result, retaining the requested order, is (4, [3, 4]).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-disjoint-choice-sizes · candidate
22. Disjoint Tagged Choices and Prefix Counts
Mutually exclusive tagged categories have ordered sizes=[3, 2]. Give (total choices, each prefix’s total), retaining an empty list.
View answer and explanation
(5, [3, 5])
Add category sizes in order; no categories give total zero. This is a choice protocol, not a probability-independence assumption. The exact result, retaining the requested order, is (5, [3, 5]).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-disjoint-choice-sizes · candidate
23. Disjoint Tagged Choices and Prefix Counts
Mutually exclusive tagged categories have ordered sizes=[3, 3]. Give (total choices, each prefix’s total), retaining an empty list.
View answer and explanation
(6, [3, 6])
Add category sizes in order; no categories give total zero. This is a choice protocol, not a probability-independence assumption. The exact result, retaining the requested order, is (6, [3, 6]).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-disjoint-choice-sizes · candidate
24. Disjoint Tagged Choices and Prefix Counts
Mutually exclusive tagged categories have ordered sizes=[3, 4]. Give (total choices, each prefix’s total), retaining an empty list.
View answer and explanation
(7, [3, 7])
Add category sizes in order; no categories give total zero. This is a choice protocol, not a probability-independence assumption. The exact result, retaining the requested order, is (7, [3, 7]).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-disjoint-choice-sizes · candidate
25. Disjoint Tagged Choices and Prefix Counts
Mutually exclusive tagged categories have ordered sizes=[3, 5]. Give (total choices, each prefix’s total), retaining an empty list.
View answer and explanation
(8, [3, 8])
Add category sizes in order; no categories give total zero. This is a choice protocol, not a probability-independence assumption. The exact result, retaining the requested order, is (8, [3, 8]).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-disjoint-choice-sizes · candidate
26. Full Product Choices and Prefix Counts
Ordered stage sizes=[]; every cross-stage combination is allowed. Give (full product count, each prefix product). Zero stages have one empty selection sequence.
View answer and explanation
(1, [])
Multiply successive choice counts; an empty product is one and a zero stage makes later products zero. No stochastic independence is asserted. The exact result, retaining the requested order, is (1, []).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-full-product-prefix · candidate
27. Full Product Choices and Prefix Counts
Ordered stage sizes=[0]; every cross-stage combination is allowed. Give (full product count, each prefix product). Zero stages have one empty selection sequence.
View answer and explanation
(0, [0])
Multiply successive choice counts; an empty product is one and a zero stage makes later products zero. No stochastic independence is asserted. The exact result, retaining the requested order, is (0, [0]).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-full-product-prefix · candidate
28. Full Product Choices and Prefix Counts
Ordered stage sizes=[2, 0, 3]; every cross-stage combination is allowed. Give (full product count, each prefix product). Zero stages have one empty selection sequence.
View answer and explanation
(0, [2, 0, 0])
Multiply successive choice counts; an empty product is one and a zero stage makes later products zero. No stochastic independence is asserted. The exact result, retaining the requested order, is (0, [2, 0, 0]).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-full-product-prefix · candidate
29. Full Product Choices and Prefix Counts
Ordered stage sizes=[0, 4, 5]; every cross-stage combination is allowed. Give (full product count, each prefix product). Zero stages have one empty selection sequence.
View answer and explanation
(0, [0, 0, 0])
Multiply successive choice counts; an empty product is one and a zero stage makes later products zero. No stochastic independence is asserted. The exact result, retaining the requested order, is (0, [0, 0, 0]).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-full-product-prefix · candidate
30. Full Product Choices and Prefix Counts
Ordered stage sizes=[2, 3, 0, 8]; every cross-stage combination is allowed. Give (full product count, each prefix product). Zero stages have one empty selection sequence.
View answer and explanation
(0, [2, 6, 0, 0])
Multiply successive choice counts; an empty product is one and a zero stage makes later products zero. No stochastic independence is asserted. The exact result, retaining the requested order, is (0, [2, 6, 0, 0]).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-full-product-prefix · candidate
31. Full Product Choices and Prefix Counts
Ordered stage sizes=[1, 1]; every cross-stage combination is allowed. Give (full product count, each prefix product). Zero stages have one empty selection sequence.
View answer and explanation
(1, [1, 1])
Multiply successive choice counts; an empty product is one and a zero stage makes later products zero. No stochastic independence is asserted. The exact result, retaining the requested order, is (1, [1, 1]).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-full-product-prefix · candidate
32. Full Product Choices and Prefix Counts
Ordered stage sizes=[1, 2]; every cross-stage combination is allowed. Give (full product count, each prefix product). Zero stages have one empty selection sequence.
View answer and explanation
(2, [1, 2])
Multiply successive choice counts; an empty product is one and a zero stage makes later products zero. No stochastic independence is asserted. The exact result, retaining the requested order, is (2, [1, 2]).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-full-product-prefix · candidate
33. Full Product Choices and Prefix Counts
Ordered stage sizes=[1, 3]; every cross-stage combination is allowed. Give (full product count, each prefix product). Zero stages have one empty selection sequence.
View answer and explanation
(3, [1, 3])
Multiply successive choice counts; an empty product is one and a zero stage makes later products zero. No stochastic independence is asserted. The exact result, retaining the requested order, is (3, [1, 3]).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-full-product-prefix · candidate
34. Full Product Choices and Prefix Counts
Ordered stage sizes=[1, 4]; every cross-stage combination is allowed. Give (full product count, each prefix product). Zero stages have one empty selection sequence.
View answer and explanation
(4, [1, 4])
Multiply successive choice counts; an empty product is one and a zero stage makes later products zero. No stochastic independence is asserted. The exact result, retaining the requested order, is (4, [1, 4]).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-full-product-prefix · candidate
35. Full Product Choices and Prefix Counts
Ordered stage sizes=[1, 5]; every cross-stage combination is allowed. Give (full product count, each prefix product). Zero stages have one empty selection sequence.
View answer and explanation
(5, [1, 5])
Multiply successive choice counts; an empty product is one and a zero stage makes later products zero. No stochastic independence is asserted. The exact result, retaining the requested order, is (5, [1, 5]).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-full-product-prefix · candidate
36. Full Product Choices and Prefix Counts
Ordered stage sizes=[1, 6]; every cross-stage combination is allowed. Give (full product count, each prefix product). Zero stages have one empty selection sequence.
View answer and explanation
(6, [1, 6])
Multiply successive choice counts; an empty product is one and a zero stage makes later products zero. No stochastic independence is asserted. The exact result, retaining the requested order, is (6, [1, 6]).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-full-product-prefix · candidate
37. Full Product Choices and Prefix Counts
Ordered stage sizes=[1, 7]; every cross-stage combination is allowed. Give (full product count, each prefix product). Zero stages have one empty selection sequence.
View answer and explanation
(7, [1, 7])
Multiply successive choice counts; an empty product is one and a zero stage makes later products zero. No stochastic independence is asserted. The exact result, retaining the requested order, is (7, [1, 7]).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-full-product-prefix · candidate
38. Full Product Choices and Prefix Counts
Ordered stage sizes=[1, 8]; every cross-stage combination is allowed. Give (full product count, each prefix product). Zero stages have one empty selection sequence.
View answer and explanation
(8, [1, 8])
Multiply successive choice counts; an empty product is one and a zero stage makes later products zero. No stochastic independence is asserted. The exact result, retaining the requested order, is (8, [1, 8]).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-full-product-prefix · candidate
39. Full Product Choices and Prefix Counts
Ordered stage sizes=[2, 1]; every cross-stage combination is allowed. Give (full product count, each prefix product). Zero stages have one empty selection sequence.
View answer and explanation
(2, [2, 2])
Multiply successive choice counts; an empty product is one and a zero stage makes later products zero. No stochastic independence is asserted. The exact result, retaining the requested order, is (2, [2, 2]).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-full-product-prefix · candidate
40. Full Product Choices and Prefix Counts
Ordered stage sizes=[2, 2]; every cross-stage combination is allowed. Give (full product count, each prefix product). Zero stages have one empty selection sequence.
View answer and explanation
(4, [2, 4])
Multiply successive choice counts; an empty product is one and a zero stage makes later products zero. No stochastic independence is asserted. The exact result, retaining the requested order, is (4, [2, 4]).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-full-product-prefix · candidate
41. Full Product Choices and Prefix Counts
Ordered stage sizes=[2, 3]; every cross-stage combination is allowed. Give (full product count, each prefix product). Zero stages have one empty selection sequence.
View answer and explanation
(6, [2, 6])
Multiply successive choice counts; an empty product is one and a zero stage makes later products zero. No stochastic independence is asserted. The exact result, retaining the requested order, is (6, [2, 6]).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-full-product-prefix · candidate
42. Full Product Choices and Prefix Counts
Ordered stage sizes=[2, 4]; every cross-stage combination is allowed. Give (full product count, each prefix product). Zero stages have one empty selection sequence.
View answer and explanation
(8, [2, 8])
Multiply successive choice counts; an empty product is one and a zero stage makes later products zero. No stochastic independence is asserted. The exact result, retaining the requested order, is (8, [2, 8]).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-full-product-prefix · candidate
43. Full Product Choices and Prefix Counts
Ordered stage sizes=[2, 5]; every cross-stage combination is allowed. Give (full product count, each prefix product). Zero stages have one empty selection sequence.
View answer and explanation
(10, [2, 10])
Multiply successive choice counts; an empty product is one and a zero stage makes later products zero. No stochastic independence is asserted. The exact result, retaining the requested order, is (10, [2, 10]).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-full-product-prefix · candidate
44. Full Product Choices and Prefix Counts
Ordered stage sizes=[2, 6]; every cross-stage combination is allowed. Give (full product count, each prefix product). Zero stages have one empty selection sequence.
View answer and explanation
(12, [2, 12])
Multiply successive choice counts; an empty product is one and a zero stage makes later products zero. No stochastic independence is asserted. The exact result, retaining the requested order, is (12, [2, 12]).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-full-product-prefix · candidate
45. Full Product Choices and Prefix Counts
Ordered stage sizes=[2, 7]; every cross-stage combination is allowed. Give (full product count, each prefix product). Zero stages have one empty selection sequence.
View answer and explanation
(14, [2, 14])
Multiply successive choice counts; an empty product is one and a zero stage makes later products zero. No stochastic independence is asserted. The exact result, retaining the requested order, is (14, [2, 14]).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-full-product-prefix · candidate
46. Full Product Choices and Prefix Counts
Ordered stage sizes=[2, 8]; every cross-stage combination is allowed. Give (full product count, each prefix product). Zero stages have one empty selection sequence.
View answer and explanation
(16, [2, 16])
Multiply successive choice counts; an empty product is one and a zero stage makes later products zero. No stochastic independence is asserted. The exact result, retaining the requested order, is (16, [2, 16]).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-full-product-prefix · candidate
47. Full Product Choices and Prefix Counts
Ordered stage sizes=[3, 1]; every cross-stage combination is allowed. Give (full product count, each prefix product). Zero stages have one empty selection sequence.
View answer and explanation
(3, [3, 3])
Multiply successive choice counts; an empty product is one and a zero stage makes later products zero. No stochastic independence is asserted. The exact result, retaining the requested order, is (3, [3, 3]).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-full-product-prefix · candidate
48. Full Product Choices and Prefix Counts
Ordered stage sizes=[3, 2]; every cross-stage combination is allowed. Give (full product count, each prefix product). Zero stages have one empty selection sequence.
View answer and explanation
(6, [3, 6])
Multiply successive choice counts; an empty product is one and a zero stage makes later products zero. No stochastic independence is asserted. The exact result, retaining the requested order, is (6, [3, 6]).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-full-product-prefix · candidate
49. Full Product Choices and Prefix Counts
Ordered stage sizes=[3, 3]; every cross-stage combination is allowed. Give (full product count, each prefix product). Zero stages have one empty selection sequence.
View answer and explanation
(9, [3, 9])
Multiply successive choice counts; an empty product is one and a zero stage makes later products zero. No stochastic independence is asserted. The exact result, retaining the requested order, is (9, [3, 9]).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-full-product-prefix · candidate
50. Full Product Choices and Prefix Counts
Ordered stage sizes=[3, 4]; every cross-stage combination is allowed. Give (full product count, each prefix product). Zero stages have one empty selection sequence.
View answer and explanation
(12, [3, 12])
Multiply successive choice counts; an empty product is one and a zero stage makes later products zero. No stochastic independence is asserted. The exact result, retaining the requested order, is (12, [3, 12]).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-full-product-prefix · candidate
51. Actual Branch Widths versus a Candidate Width
Ordered second-stage branch counts=[], n=0; candidate common width h=7. Give (actual total, assumed n*h total, does every branch equal h?, n*h−actual total).
View answer and explanation
(0, 0, Yes, 0)
Sum actual branches and check every width separately; equal totals do not establish equal widths. For no first-stage branches the width condition is vacuously Yes. The exact result, retaining the requested order, is (0, 0, Yes, 0).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-conditional-candidate-defect · candidate
52. Actual Branch Widths versus a Candidate Width
Ordered second-stage branch counts=[1, 3], n=2; candidate common width h=2. Give (actual total, assumed n*h total, does every branch equal h?, n*h−actual total).
View answer and explanation
(4, 4, No, 0)
Sum actual branches and check every width separately; equal totals do not establish equal widths. For no first-stage branches the width condition is vacuously Yes. The exact result, retaining the requested order, is (4, 4, No, 0).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-conditional-candidate-defect · candidate
53. Actual Branch Widths versus a Candidate Width
Ordered second-stage branch counts=[2, 2], n=2; candidate common width h=2. Give (actual total, assumed n*h total, does every branch equal h?, n*h−actual total).
View answer and explanation
(4, 4, Yes, 0)
Sum actual branches and check every width separately; equal totals do not establish equal widths. For no first-stage branches the width condition is vacuously Yes. The exact result, retaining the requested order, is (4, 4, Yes, 0).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-conditional-candidate-defect · candidate
54. Actual Branch Widths versus a Candidate Width
Ordered second-stage branch counts=[0], n=1; candidate common width h=0. Give (actual total, assumed n*h total, does every branch equal h?, n*h−actual total).
View answer and explanation
(0, 0, Yes, 0)
Sum actual branches and check every width separately; equal totals do not establish equal widths. For no first-stage branches the width condition is vacuously Yes. The exact result, retaining the requested order, is (0, 0, Yes, 0).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-conditional-candidate-defect · candidate
55. Actual Branch Widths versus a Candidate Width
Ordered second-stage branch counts=[3], n=1; candidate common width h=2. Give (actual total, assumed n*h total, does every branch equal h?, n*h−actual total).
View answer and explanation
(3, 2, No, -1)
Sum actual branches and check every width separately; equal totals do not establish equal widths. For no first-stage branches the width condition is vacuously Yes. The exact result, retaining the requested order, is (3, 2, No, -1).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-conditional-candidate-defect · candidate
56. Actual Branch Widths versus a Candidate Width
Ordered second-stage branch counts=[5, 6], n=2; candidate common width h=0. Give (actual total, assumed n*h total, does every branch equal h?, n*h−actual total).
View answer and explanation
(11, 0, No, -11)
Sum actual branches and check every width separately; equal totals do not establish equal widths. For no first-stage branches the width condition is vacuously Yes. The exact result, retaining the requested order, is (11, 0, No, -11).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-conditional-candidate-defect · candidate
57. Actual Branch Widths versus a Candidate Width
Ordered second-stage branch counts=[6, 7], n=2; candidate common width h=0. Give (actual total, assumed n*h total, does every branch equal h?, n*h−actual total).
View answer and explanation
(13, 0, No, -13)
Sum actual branches and check every width separately; equal totals do not establish equal widths. For no first-stage branches the width condition is vacuously Yes. The exact result, retaining the requested order, is (13, 0, No, -13).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-conditional-candidate-defect · candidate
58. Actual Branch Widths versus a Candidate Width
Ordered second-stage branch counts=[7, 8], n=2; candidate common width h=0. Give (actual total, assumed n*h total, does every branch equal h?, n*h−actual total).
View answer and explanation
(15, 0, No, -15)
Sum actual branches and check every width separately; equal totals do not establish equal widths. For no first-stage branches the width condition is vacuously Yes. The exact result, retaining the requested order, is (15, 0, No, -15).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-conditional-candidate-defect · candidate
59. Actual Branch Widths versus a Candidate Width
Ordered second-stage branch counts=[8, 0], n=2; candidate common width h=0. Give (actual total, assumed n*h total, does every branch equal h?, n*h−actual total).
View answer and explanation
(8, 0, No, -8)
Sum actual branches and check every width separately; equal totals do not establish equal widths. For no first-stage branches the width condition is vacuously Yes. The exact result, retaining the requested order, is (8, 0, No, -8).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-conditional-candidate-defect · candidate
60. Actual Branch Widths versus a Candidate Width
Ordered second-stage branch counts=[0, 1], n=2; candidate common width h=1. Give (actual total, assumed n*h total, does every branch equal h?, n*h−actual total).
View answer and explanation
(1, 2, No, 1)
Sum actual branches and check every width separately; equal totals do not establish equal widths. For no first-stage branches the width condition is vacuously Yes. The exact result, retaining the requested order, is (1, 2, No, 1).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-conditional-candidate-defect · candidate
61. Actual Branch Widths versus a Candidate Width
Ordered second-stage branch counts=[1, 2], n=2; candidate common width h=1. Give (actual total, assumed n*h total, does every branch equal h?, n*h−actual total).
View answer and explanation
(3, 2, No, -1)
Sum actual branches and check every width separately; equal totals do not establish equal widths. For no first-stage branches the width condition is vacuously Yes. The exact result, retaining the requested order, is (3, 2, No, -1).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-conditional-candidate-defect · candidate
62. Actual Branch Widths versus a Candidate Width
Ordered second-stage branch counts=[2, 3], n=2; candidate common width h=1. Give (actual total, assumed n*h total, does every branch equal h?, n*h−actual total).
View answer and explanation
(5, 2, No, -3)
Sum actual branches and check every width separately; equal totals do not establish equal widths. For no first-stage branches the width condition is vacuously Yes. The exact result, retaining the requested order, is (5, 2, No, -3).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-conditional-candidate-defect · candidate
63. Actual Branch Widths versus a Candidate Width
Ordered second-stage branch counts=[3, 4], n=2; candidate common width h=1. Give (actual total, assumed n*h total, does every branch equal h?, n*h−actual total).
View answer and explanation
(7, 2, No, -5)
Sum actual branches and check every width separately; equal totals do not establish equal widths. For no first-stage branches the width condition is vacuously Yes. The exact result, retaining the requested order, is (7, 2, No, -5).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-conditional-candidate-defect · candidate
64. Actual Branch Widths versus a Candidate Width
Ordered second-stage branch counts=[4, 5], n=2; candidate common width h=1. Give (actual total, assumed n*h total, does every branch equal h?, n*h−actual total).
View answer and explanation
(9, 2, No, -7)
Sum actual branches and check every width separately; equal totals do not establish equal widths. For no first-stage branches the width condition is vacuously Yes. The exact result, retaining the requested order, is (9, 2, No, -7).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-conditional-candidate-defect · candidate
65. Actual Branch Widths versus a Candidate Width
Ordered second-stage branch counts=[5, 6], n=2; candidate common width h=1. Give (actual total, assumed n*h total, does every branch equal h?, n*h−actual total).
View answer and explanation
(11, 2, No, -9)
Sum actual branches and check every width separately; equal totals do not establish equal widths. For no first-stage branches the width condition is vacuously Yes. The exact result, retaining the requested order, is (11, 2, No, -9).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-conditional-candidate-defect · candidate
66. Actual Branch Widths versus a Candidate Width
Ordered second-stage branch counts=[6, 7], n=2; candidate common width h=1. Give (actual total, assumed n*h total, does every branch equal h?, n*h−actual total).
View answer and explanation
(13, 2, No, -11)
Sum actual branches and check every width separately; equal totals do not establish equal widths. For no first-stage branches the width condition is vacuously Yes. The exact result, retaining the requested order, is (13, 2, No, -11).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-conditional-candidate-defect · candidate
67. Actual Branch Widths versus a Candidate Width
Ordered second-stage branch counts=[7, 8], n=2; candidate common width h=1. Give (actual total, assumed n*h total, does every branch equal h?, n*h−actual total).
View answer and explanation
(15, 2, No, -13)
Sum actual branches and check every width separately; equal totals do not establish equal widths. For no first-stage branches the width condition is vacuously Yes. The exact result, retaining the requested order, is (15, 2, No, -13).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-conditional-candidate-defect · candidate
68. Actual Branch Widths versus a Candidate Width
Ordered second-stage branch counts=[8, 0], n=2; candidate common width h=1. Give (actual total, assumed n*h total, does every branch equal h?, n*h−actual total).
View answer and explanation
(8, 2, No, -6)
Sum actual branches and check every width separately; equal totals do not establish equal widths. For no first-stage branches the width condition is vacuously Yes. The exact result, retaining the requested order, is (8, 2, No, -6).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-conditional-candidate-defect · candidate
69. Actual Branch Widths versus a Candidate Width
Ordered second-stage branch counts=[0, 1], n=2; candidate common width h=2. Give (actual total, assumed n*h total, does every branch equal h?, n*h−actual total).
View answer and explanation
(1, 4, No, 3)
Sum actual branches and check every width separately; equal totals do not establish equal widths. For no first-stage branches the width condition is vacuously Yes. The exact result, retaining the requested order, is (1, 4, No, 3).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-conditional-candidate-defect · candidate
70. Actual Branch Widths versus a Candidate Width
Ordered second-stage branch counts=[1, 2], n=2; candidate common width h=2. Give (actual total, assumed n*h total, does every branch equal h?, n*h−actual total).
View answer and explanation
(3, 4, No, 1)
Sum actual branches and check every width separately; equal totals do not establish equal widths. For no first-stage branches the width condition is vacuously Yes. The exact result, retaining the requested order, is (3, 4, No, 1).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-conditional-candidate-defect · candidate
71. Actual Branch Widths versus a Candidate Width
Ordered second-stage branch counts=[2, 3], n=2; candidate common width h=2. Give (actual total, assumed n*h total, does every branch equal h?, n*h−actual total).
View answer and explanation
(5, 4, No, -1)
Sum actual branches and check every width separately; equal totals do not establish equal widths. For no first-stage branches the width condition is vacuously Yes. The exact result, retaining the requested order, is (5, 4, No, -1).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-conditional-candidate-defect · candidate
72. Actual Branch Widths versus a Candidate Width
Ordered second-stage branch counts=[3, 4], n=2; candidate common width h=2. Give (actual total, assumed n*h total, does every branch equal h?, n*h−actual total).
View answer and explanation
(7, 4, No, -3)
Sum actual branches and check every width separately; equal totals do not establish equal widths. For no first-stage branches the width condition is vacuously Yes. The exact result, retaining the requested order, is (7, 4, No, -3).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-conditional-candidate-defect · candidate
73. Actual Branch Widths versus a Candidate Width
Ordered second-stage branch counts=[4, 5], n=2; candidate common width h=2. Give (actual total, assumed n*h total, does every branch equal h?, n*h−actual total).
View answer and explanation
(9, 4, No, -5)
Sum actual branches and check every width separately; equal totals do not establish equal widths. For no first-stage branches the width condition is vacuously Yes. The exact result, retaining the requested order, is (9, 4, No, -5).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-conditional-candidate-defect · candidate
74. Actual Branch Widths versus a Candidate Width
Ordered second-stage branch counts=[5, 6], n=2; candidate common width h=2. Give (actual total, assumed n*h total, does every branch equal h?, n*h−actual total).
View answer and explanation
(11, 4, No, -7)
Sum actual branches and check every width separately; equal totals do not establish equal widths. For no first-stage branches the width condition is vacuously Yes. The exact result, retaining the requested order, is (11, 4, No, -7).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-conditional-candidate-defect · candidate
75. Actual Branch Widths versus a Candidate Width
Ordered second-stage branch counts=[6, 7], n=2; candidate common width h=2. Give (actual total, assumed n*h total, does every branch equal h?, n*h−actual total).
View answer and explanation
(13, 4, No, -9)
Sum actual branches and check every width separately; equal totals do not establish equal widths. For no first-stage branches the width condition is vacuously Yes. The exact result, retaining the requested order, is (13, 4, No, -9).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-conditional-candidate-defect · candidate
76. Overlap-Corrected Finite Choice Counts
Finite integer choice sets A=[], B=[]. Give (|A|+|B|, |A∪B|, |A∩B|).
View answer and explanation
(0, 0, 0)
Enumerate actual union/intersection membership; adding both cardinalities double-counts shared choices. No probability-independence premise is involved. The exact result, retaining the requested order, is (0, 0, 0).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-overlap-correction · candidate
77. Overlap-Corrected Finite Choice Counts
Finite integer choice sets A=[0], B=[0]. Give (|A|+|B|, |A∪B|, |A∩B|).
View answer and explanation
(2, 1, 1)
Enumerate actual union/intersection membership; adding both cardinalities double-counts shared choices. No probability-independence premise is involved. The exact result, retaining the requested order, is (2, 1, 1).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-overlap-correction · candidate
78. Overlap-Corrected Finite Choice Counts
Finite integer choice sets A=[], B=[100]. Give (|A|+|B|, |A∪B|, |A∩B|).
View answer and explanation
(1, 1, 0)
Enumerate actual union/intersection membership; adding both cardinalities double-counts shared choices. No probability-independence premise is involved. The exact result, retaining the requested order, is (1, 1, 0).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-overlap-correction · candidate
79. Overlap-Corrected Finite Choice Counts
Finite integer choice sets A=[0, 1], B=[0, 1]. Give (|A|+|B|, |A∪B|, |A∩B|).
View answer and explanation
(4, 2, 2)
Enumerate actual union/intersection membership; adding both cardinalities double-counts shared choices. No probability-independence premise is involved. The exact result, retaining the requested order, is (4, 2, 2).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-overlap-correction · candidate
80. Overlap-Corrected Finite Choice Counts
Finite integer choice sets A=[0], B=[0, 100]. Give (|A|+|B|, |A∪B|, |A∩B|).
View answer and explanation
(3, 2, 1)
Enumerate actual union/intersection membership; adding both cardinalities double-counts shared choices. No probability-independence premise is involved. The exact result, retaining the requested order, is (3, 2, 1).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-overlap-correction · candidate
81. Overlap-Corrected Finite Choice Counts
Finite integer choice sets A=[], B=[100, 101]. Give (|A|+|B|, |A∪B|, |A∩B|).
View answer and explanation
(2, 2, 0)
Enumerate actual union/intersection membership; adding both cardinalities double-counts shared choices. No probability-independence premise is involved. The exact result, retaining the requested order, is (2, 2, 0).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-overlap-correction · candidate
82. Overlap-Corrected Finite Choice Counts
Finite integer choice sets A=[-1], B=[100]. Give (|A|+|B|, |A∪B|, |A∩B|).
View answer and explanation
(2, 2, 0)
Enumerate actual union/intersection membership; adding both cardinalities double-counts shared choices. No probability-independence premise is involved. The exact result, retaining the requested order, is (2, 2, 0).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-overlap-correction · candidate
83. Overlap-Corrected Finite Choice Counts
Finite integer choice sets A=[0, 1, 2], B=[0, 1, 2]. Give (|A|+|B|, |A∪B|, |A∩B|).
View answer and explanation
(6, 3, 3)
Enumerate actual union/intersection membership; adding both cardinalities double-counts shared choices. No probability-independence premise is involved. The exact result, retaining the requested order, is (6, 3, 3).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-overlap-correction · candidate
84. Overlap-Corrected Finite Choice Counts
Finite integer choice sets A=[0, 1], B=[0, 1, 100]. Give (|A|+|B|, |A∪B|, |A∩B|).
View answer and explanation
(5, 3, 2)
Enumerate actual union/intersection membership; adding both cardinalities double-counts shared choices. No probability-independence premise is involved. The exact result, retaining the requested order, is (5, 3, 2).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-overlap-correction · candidate
85. Overlap-Corrected Finite Choice Counts
Finite integer choice sets A=[0], B=[0, 100, 101]. Give (|A|+|B|, |A∪B|, |A∩B|).
View answer and explanation
(4, 3, 1)
Enumerate actual union/intersection membership; adding both cardinalities double-counts shared choices. No probability-independence premise is involved. The exact result, retaining the requested order, is (4, 3, 1).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-overlap-correction · candidate
86. Overlap-Corrected Finite Choice Counts
Finite integer choice sets A=[], B=[100, 101, 102]. Give (|A|+|B|, |A∪B|, |A∩B|).
View answer and explanation
(3, 3, 0)
Enumerate actual union/intersection membership; adding both cardinalities double-counts shared choices. No probability-independence premise is involved. The exact result, retaining the requested order, is (3, 3, 0).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-overlap-correction · candidate
87. Overlap-Corrected Finite Choice Counts
Finite integer choice sets A=[0, -1], B=[0, 100]. Give (|A|+|B|, |A∪B|, |A∩B|).
View answer and explanation
(4, 3, 1)
Enumerate actual union/intersection membership; adding both cardinalities double-counts shared choices. No probability-independence premise is involved. The exact result, retaining the requested order, is (4, 3, 1).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-overlap-correction · candidate
88. Overlap-Corrected Finite Choice Counts
Finite integer choice sets A=[-1], B=[100, 101]. Give (|A|+|B|, |A∪B|, |A∩B|).
View answer and explanation
(3, 3, 0)
Enumerate actual union/intersection membership; adding both cardinalities double-counts shared choices. No probability-independence premise is involved. The exact result, retaining the requested order, is (3, 3, 0).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-overlap-correction · candidate
89. Overlap-Corrected Finite Choice Counts
Finite integer choice sets A=[0, 1, 2, 3], B=[0, 1, 2, 3]. Give (|A|+|B|, |A∪B|, |A∩B|).
View answer and explanation
(8, 4, 4)
Enumerate actual union/intersection membership; adding both cardinalities double-counts shared choices. No probability-independence premise is involved. The exact result, retaining the requested order, is (8, 4, 4).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-overlap-correction · candidate
90. Overlap-Corrected Finite Choice Counts
Finite integer choice sets A=[0, 1, 2], B=[0, 1, 2, 100]. Give (|A|+|B|, |A∪B|, |A∩B|).
View answer and explanation
(7, 4, 3)
Enumerate actual union/intersection membership; adding both cardinalities double-counts shared choices. No probability-independence premise is involved. The exact result, retaining the requested order, is (7, 4, 3).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-overlap-correction · candidate
91. Overlap-Corrected Finite Choice Counts
Finite integer choice sets A=[0, 1], B=[0, 1, 100, 101]. Give (|A|+|B|, |A∪B|, |A∩B|).
View answer and explanation
(6, 4, 2)
Enumerate actual union/intersection membership; adding both cardinalities double-counts shared choices. No probability-independence premise is involved. The exact result, retaining the requested order, is (6, 4, 2).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-overlap-correction · candidate
92. Overlap-Corrected Finite Choice Counts
Finite integer choice sets A=[0], B=[0, 100, 101, 102]. Give (|A|+|B|, |A∪B|, |A∩B|).
View answer and explanation
(5, 4, 1)
Enumerate actual union/intersection membership; adding both cardinalities double-counts shared choices. No probability-independence premise is involved. The exact result, retaining the requested order, is (5, 4, 1).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-overlap-correction · candidate
93. Overlap-Corrected Finite Choice Counts
Finite integer choice sets A=[], B=[100, 101, 102, 103]. Give (|A|+|B|, |A∪B|, |A∩B|).
View answer and explanation
(4, 4, 0)
Enumerate actual union/intersection membership; adding both cardinalities double-counts shared choices. No probability-independence premise is involved. The exact result, retaining the requested order, is (4, 4, 0).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-overlap-correction · candidate
94. Overlap-Corrected Finite Choice Counts
Finite integer choice sets A=[0, 1, -1], B=[0, 1, 100]. Give (|A|+|B|, |A∪B|, |A∩B|).
View answer and explanation
(6, 4, 2)
Enumerate actual union/intersection membership; adding both cardinalities double-counts shared choices. No probability-independence premise is involved. The exact result, retaining the requested order, is (6, 4, 2).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-overlap-correction · candidate
95. Overlap-Corrected Finite Choice Counts
Finite integer choice sets A=[0, -1], B=[0, 100, 101]. Give (|A|+|B|, |A∪B|, |A∩B|).
View answer and explanation
(5, 4, 1)
Enumerate actual union/intersection membership; adding both cardinalities double-counts shared choices. No probability-independence premise is involved. The exact result, retaining the requested order, is (5, 4, 1).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-overlap-correction · candidate
96. Overlap-Corrected Finite Choice Counts
Finite integer choice sets A=[-1], B=[100, 101, 102]. Give (|A|+|B|, |A∪B|, |A∩B|).
View answer and explanation
(4, 4, 0)
Enumerate actual union/intersection membership; adding both cardinalities double-counts shared choices. No probability-independence premise is involved. The exact result, retaining the requested order, is (4, 4, 0).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-overlap-correction · candidate
97. Overlap-Corrected Finite Choice Counts
Finite integer choice sets A=[-2, -1], B=[100, 101]. Give (|A|+|B|, |A∪B|, |A∩B|).
View answer and explanation
(4, 4, 0)
Enumerate actual union/intersection membership; adding both cardinalities double-counts shared choices. No probability-independence premise is involved. The exact result, retaining the requested order, is (4, 4, 0).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-overlap-correction · candidate
98. Overlap-Corrected Finite Choice Counts
Finite integer choice sets A=[0, 1, 2, 3, 4], B=[0, 1, 2, 3, 4]. Give (|A|+|B|, |A∪B|, |A∩B|).
View answer and explanation
(10, 5, 5)
Enumerate actual union/intersection membership; adding both cardinalities double-counts shared choices. No probability-independence premise is involved. The exact result, retaining the requested order, is (10, 5, 5).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-overlap-correction · candidate
99. Overlap-Corrected Finite Choice Counts
Finite integer choice sets A=[0, 1, 2, 3], B=[0, 1, 2, 3, 100]. Give (|A|+|B|, |A∪B|, |A∩B|).
View answer and explanation
(9, 5, 4)
Enumerate actual union/intersection membership; adding both cardinalities double-counts shared choices. No probability-independence premise is involved. The exact result, retaining the requested order, is (9, 5, 4).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-overlap-correction · candidate
100. Overlap-Corrected Finite Choice Counts
Finite integer choice sets A=[0, 1, 2], B=[0, 1, 2, 100, 101]. Give (|A|+|B|, |A∪B|, |A∩B|).
View answer and explanation
(8, 5, 3)
Enumerate actual union/intersection membership; adding both cardinalities double-counts shared choices. No probability-independence premise is involved. The exact result, retaining the requested order, is (8, 5, 3).
Reviewed step-by-step derivation
Basic counting principles · qf-density12-counting-overlap-correction · candidate
Canonical question JSONL · English JSONL · Validation report