Tagged Choice Counts and Actual Branch Widths

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This question bank has corresponding bilingual step-by-step derivations. Source candidate and English ai_candidate states are retained. AI review, finite computation and Lean formal proof are labelled separately.

batch-20261008-advance-20261012-r02-counting-principle-foundations · 2026-10-08 · 100 questions

This English edition is an AI candidate and does not yet have an OCME Atlas (GPT-6) Twin closure receipt.

1. Disjoint Tagged Choices and Prefix Counts

Mutually exclusive tagged categories have ordered sizes=[]. Give (total choices, each prefix’s total), retaining an empty list.

View answer and explanation

(0, [])

Add category sizes in order; no categories give total zero. This is a choice protocol, not a probability-independence assumption. The exact result, retaining the requested order, is (0, []).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-disjoint-choice-sizes · candidate

2. Disjoint Tagged Choices and Prefix Counts

Mutually exclusive tagged categories have ordered sizes=[0]. Give (total choices, each prefix’s total), retaining an empty list.

View answer and explanation

(0, [0])

Add category sizes in order; no categories give total zero. This is a choice protocol, not a probability-independence assumption. The exact result, retaining the requested order, is (0, [0]).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-disjoint-choice-sizes · candidate

3. Disjoint Tagged Choices and Prefix Counts

Mutually exclusive tagged categories have ordered sizes=[1]. Give (total choices, each prefix’s total), retaining an empty list.

View answer and explanation

(1, [1])

Add category sizes in order; no categories give total zero. This is a choice protocol, not a probability-independence assumption. The exact result, retaining the requested order, is (1, [1]).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-disjoint-choice-sizes · candidate

4. Disjoint Tagged Choices and Prefix Counts

Mutually exclusive tagged categories have ordered sizes=[2, 0, 3, 1]. Give (total choices, each prefix’s total), retaining an empty list.

View answer and explanation

(6, [2, 2, 5, 6])

Add category sizes in order; no categories give total zero. This is a choice protocol, not a probability-independence assumption. The exact result, retaining the requested order, is (6, [2, 2, 5, 6]).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-disjoint-choice-sizes · candidate

5. Disjoint Tagged Choices and Prefix Counts

Mutually exclusive tagged categories have ordered sizes=[1, 1]. Give (total choices, each prefix’s total), retaining an empty list.

View answer and explanation

(2, [1, 2])

Add category sizes in order; no categories give total zero. This is a choice protocol, not a probability-independence assumption. The exact result, retaining the requested order, is (2, [1, 2]).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-disjoint-choice-sizes · candidate

6. Disjoint Tagged Choices and Prefix Counts

Mutually exclusive tagged categories have ordered sizes=[1, 2]. Give (total choices, each prefix’s total), retaining an empty list.

View answer and explanation

(3, [1, 3])

Add category sizes in order; no categories give total zero. This is a choice protocol, not a probability-independence assumption. The exact result, retaining the requested order, is (3, [1, 3]).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-disjoint-choice-sizes · candidate

7. Disjoint Tagged Choices and Prefix Counts

Mutually exclusive tagged categories have ordered sizes=[1, 3]. Give (total choices, each prefix’s total), retaining an empty list.

View answer and explanation

(4, [1, 4])

Add category sizes in order; no categories give total zero. This is a choice protocol, not a probability-independence assumption. The exact result, retaining the requested order, is (4, [1, 4]).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-disjoint-choice-sizes · candidate

8. Disjoint Tagged Choices and Prefix Counts

Mutually exclusive tagged categories have ordered sizes=[1, 4]. Give (total choices, each prefix’s total), retaining an empty list.

View answer and explanation

(5, [1, 5])

Add category sizes in order; no categories give total zero. This is a choice protocol, not a probability-independence assumption. The exact result, retaining the requested order, is (5, [1, 5]).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-disjoint-choice-sizes · candidate

9. Disjoint Tagged Choices and Prefix Counts

Mutually exclusive tagged categories have ordered sizes=[1, 5]. Give (total choices, each prefix’s total), retaining an empty list.

View answer and explanation

(6, [1, 6])

Add category sizes in order; no categories give total zero. This is a choice protocol, not a probability-independence assumption. The exact result, retaining the requested order, is (6, [1, 6]).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-disjoint-choice-sizes · candidate

10. Disjoint Tagged Choices and Prefix Counts

Mutually exclusive tagged categories have ordered sizes=[1, 6]. Give (total choices, each prefix’s total), retaining an empty list.

View answer and explanation

(7, [1, 7])

Add category sizes in order; no categories give total zero. This is a choice protocol, not a probability-independence assumption. The exact result, retaining the requested order, is (7, [1, 7]).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-disjoint-choice-sizes · candidate

11. Disjoint Tagged Choices and Prefix Counts

Mutually exclusive tagged categories have ordered sizes=[1, 7]. Give (total choices, each prefix’s total), retaining an empty list.

View answer and explanation

(8, [1, 8])

Add category sizes in order; no categories give total zero. This is a choice protocol, not a probability-independence assumption. The exact result, retaining the requested order, is (8, [1, 8]).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-disjoint-choice-sizes · candidate

12. Disjoint Tagged Choices and Prefix Counts

Mutually exclusive tagged categories have ordered sizes=[1, 8]. Give (total choices, each prefix’s total), retaining an empty list.

View answer and explanation

(9, [1, 9])

Add category sizes in order; no categories give total zero. This is a choice protocol, not a probability-independence assumption. The exact result, retaining the requested order, is (9, [1, 9]).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-disjoint-choice-sizes · candidate

13. Disjoint Tagged Choices and Prefix Counts

Mutually exclusive tagged categories have ordered sizes=[2, 1]. Give (total choices, each prefix’s total), retaining an empty list.

View answer and explanation

(3, [2, 3])

Add category sizes in order; no categories give total zero. This is a choice protocol, not a probability-independence assumption. The exact result, retaining the requested order, is (3, [2, 3]).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-disjoint-choice-sizes · candidate

14. Disjoint Tagged Choices and Prefix Counts

Mutually exclusive tagged categories have ordered sizes=[2, 2]. Give (total choices, each prefix’s total), retaining an empty list.

View answer and explanation

(4, [2, 4])

Add category sizes in order; no categories give total zero. This is a choice protocol, not a probability-independence assumption. The exact result, retaining the requested order, is (4, [2, 4]).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-disjoint-choice-sizes · candidate

15. Disjoint Tagged Choices and Prefix Counts

Mutually exclusive tagged categories have ordered sizes=[2, 3]. Give (total choices, each prefix’s total), retaining an empty list.

View answer and explanation

(5, [2, 5])

Add category sizes in order; no categories give total zero. This is a choice protocol, not a probability-independence assumption. The exact result, retaining the requested order, is (5, [2, 5]).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-disjoint-choice-sizes · candidate

16. Disjoint Tagged Choices and Prefix Counts

Mutually exclusive tagged categories have ordered sizes=[2, 4]. Give (total choices, each prefix’s total), retaining an empty list.

View answer and explanation

(6, [2, 6])

Add category sizes in order; no categories give total zero. This is a choice protocol, not a probability-independence assumption. The exact result, retaining the requested order, is (6, [2, 6]).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-disjoint-choice-sizes · candidate

17. Disjoint Tagged Choices and Prefix Counts

Mutually exclusive tagged categories have ordered sizes=[2, 5]. Give (total choices, each prefix’s total), retaining an empty list.

View answer and explanation

(7, [2, 7])

Add category sizes in order; no categories give total zero. This is a choice protocol, not a probability-independence assumption. The exact result, retaining the requested order, is (7, [2, 7]).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-disjoint-choice-sizes · candidate

18. Disjoint Tagged Choices and Prefix Counts

Mutually exclusive tagged categories have ordered sizes=[2, 6]. Give (total choices, each prefix’s total), retaining an empty list.

View answer and explanation

(8, [2, 8])

Add category sizes in order; no categories give total zero. This is a choice protocol, not a probability-independence assumption. The exact result, retaining the requested order, is (8, [2, 8]).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-disjoint-choice-sizes · candidate

19. Disjoint Tagged Choices and Prefix Counts

Mutually exclusive tagged categories have ordered sizes=[2, 7]. Give (total choices, each prefix’s total), retaining an empty list.

View answer and explanation

(9, [2, 9])

Add category sizes in order; no categories give total zero. This is a choice protocol, not a probability-independence assumption. The exact result, retaining the requested order, is (9, [2, 9]).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-disjoint-choice-sizes · candidate

20. Disjoint Tagged Choices and Prefix Counts

Mutually exclusive tagged categories have ordered sizes=[2, 8]. Give (total choices, each prefix’s total), retaining an empty list.

View answer and explanation

(10, [2, 10])

Add category sizes in order; no categories give total zero. This is a choice protocol, not a probability-independence assumption. The exact result, retaining the requested order, is (10, [2, 10]).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-disjoint-choice-sizes · candidate

21. Disjoint Tagged Choices and Prefix Counts

Mutually exclusive tagged categories have ordered sizes=[3, 1]. Give (total choices, each prefix’s total), retaining an empty list.

View answer and explanation

(4, [3, 4])

Add category sizes in order; no categories give total zero. This is a choice protocol, not a probability-independence assumption. The exact result, retaining the requested order, is (4, [3, 4]).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-disjoint-choice-sizes · candidate

22. Disjoint Tagged Choices and Prefix Counts

Mutually exclusive tagged categories have ordered sizes=[3, 2]. Give (total choices, each prefix’s total), retaining an empty list.

View answer and explanation

(5, [3, 5])

Add category sizes in order; no categories give total zero. This is a choice protocol, not a probability-independence assumption. The exact result, retaining the requested order, is (5, [3, 5]).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-disjoint-choice-sizes · candidate

23. Disjoint Tagged Choices and Prefix Counts

Mutually exclusive tagged categories have ordered sizes=[3, 3]. Give (total choices, each prefix’s total), retaining an empty list.

View answer and explanation

(6, [3, 6])

Add category sizes in order; no categories give total zero. This is a choice protocol, not a probability-independence assumption. The exact result, retaining the requested order, is (6, [3, 6]).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-disjoint-choice-sizes · candidate

24. Disjoint Tagged Choices and Prefix Counts

Mutually exclusive tagged categories have ordered sizes=[3, 4]. Give (total choices, each prefix’s total), retaining an empty list.

View answer and explanation

(7, [3, 7])

Add category sizes in order; no categories give total zero. This is a choice protocol, not a probability-independence assumption. The exact result, retaining the requested order, is (7, [3, 7]).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-disjoint-choice-sizes · candidate

25. Disjoint Tagged Choices and Prefix Counts

Mutually exclusive tagged categories have ordered sizes=[3, 5]. Give (total choices, each prefix’s total), retaining an empty list.

View answer and explanation

(8, [3, 8])

Add category sizes in order; no categories give total zero. This is a choice protocol, not a probability-independence assumption. The exact result, retaining the requested order, is (8, [3, 8]).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-disjoint-choice-sizes · candidate

26. Full Product Choices and Prefix Counts

Ordered stage sizes=[]; every cross-stage combination is allowed. Give (full product count, each prefix product). Zero stages have one empty selection sequence.

View answer and explanation

(1, [])

Multiply successive choice counts; an empty product is one and a zero stage makes later products zero. No stochastic independence is asserted. The exact result, retaining the requested order, is (1, []).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-full-product-prefix · candidate

27. Full Product Choices and Prefix Counts

Ordered stage sizes=[0]; every cross-stage combination is allowed. Give (full product count, each prefix product). Zero stages have one empty selection sequence.

View answer and explanation

(0, [0])

Multiply successive choice counts; an empty product is one and a zero stage makes later products zero. No stochastic independence is asserted. The exact result, retaining the requested order, is (0, [0]).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-full-product-prefix · candidate

28. Full Product Choices and Prefix Counts

Ordered stage sizes=[2, 0, 3]; every cross-stage combination is allowed. Give (full product count, each prefix product). Zero stages have one empty selection sequence.

View answer and explanation

(0, [2, 0, 0])

Multiply successive choice counts; an empty product is one and a zero stage makes later products zero. No stochastic independence is asserted. The exact result, retaining the requested order, is (0, [2, 0, 0]).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-full-product-prefix · candidate

29. Full Product Choices and Prefix Counts

Ordered stage sizes=[0, 4, 5]; every cross-stage combination is allowed. Give (full product count, each prefix product). Zero stages have one empty selection sequence.

View answer and explanation

(0, [0, 0, 0])

Multiply successive choice counts; an empty product is one and a zero stage makes later products zero. No stochastic independence is asserted. The exact result, retaining the requested order, is (0, [0, 0, 0]).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-full-product-prefix · candidate

30. Full Product Choices and Prefix Counts

Ordered stage sizes=[2, 3, 0, 8]; every cross-stage combination is allowed. Give (full product count, each prefix product). Zero stages have one empty selection sequence.

View answer and explanation

(0, [2, 6, 0, 0])

Multiply successive choice counts; an empty product is one and a zero stage makes later products zero. No stochastic independence is asserted. The exact result, retaining the requested order, is (0, [2, 6, 0, 0]).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-full-product-prefix · candidate

31. Full Product Choices and Prefix Counts

Ordered stage sizes=[1, 1]; every cross-stage combination is allowed. Give (full product count, each prefix product). Zero stages have one empty selection sequence.

View answer and explanation

(1, [1, 1])

Multiply successive choice counts; an empty product is one and a zero stage makes later products zero. No stochastic independence is asserted. The exact result, retaining the requested order, is (1, [1, 1]).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-full-product-prefix · candidate

32. Full Product Choices and Prefix Counts

Ordered stage sizes=[1, 2]; every cross-stage combination is allowed. Give (full product count, each prefix product). Zero stages have one empty selection sequence.

View answer and explanation

(2, [1, 2])

Multiply successive choice counts; an empty product is one and a zero stage makes later products zero. No stochastic independence is asserted. The exact result, retaining the requested order, is (2, [1, 2]).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-full-product-prefix · candidate

33. Full Product Choices and Prefix Counts

Ordered stage sizes=[1, 3]; every cross-stage combination is allowed. Give (full product count, each prefix product). Zero stages have one empty selection sequence.

View answer and explanation

(3, [1, 3])

Multiply successive choice counts; an empty product is one and a zero stage makes later products zero. No stochastic independence is asserted. The exact result, retaining the requested order, is (3, [1, 3]).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-full-product-prefix · candidate

34. Full Product Choices and Prefix Counts

Ordered stage sizes=[1, 4]; every cross-stage combination is allowed. Give (full product count, each prefix product). Zero stages have one empty selection sequence.

View answer and explanation

(4, [1, 4])

Multiply successive choice counts; an empty product is one and a zero stage makes later products zero. No stochastic independence is asserted. The exact result, retaining the requested order, is (4, [1, 4]).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-full-product-prefix · candidate

35. Full Product Choices and Prefix Counts

Ordered stage sizes=[1, 5]; every cross-stage combination is allowed. Give (full product count, each prefix product). Zero stages have one empty selection sequence.

View answer and explanation

(5, [1, 5])

Multiply successive choice counts; an empty product is one and a zero stage makes later products zero. No stochastic independence is asserted. The exact result, retaining the requested order, is (5, [1, 5]).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-full-product-prefix · candidate

36. Full Product Choices and Prefix Counts

Ordered stage sizes=[1, 6]; every cross-stage combination is allowed. Give (full product count, each prefix product). Zero stages have one empty selection sequence.

View answer and explanation

(6, [1, 6])

Multiply successive choice counts; an empty product is one and a zero stage makes later products zero. No stochastic independence is asserted. The exact result, retaining the requested order, is (6, [1, 6]).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-full-product-prefix · candidate

37. Full Product Choices and Prefix Counts

Ordered stage sizes=[1, 7]; every cross-stage combination is allowed. Give (full product count, each prefix product). Zero stages have one empty selection sequence.

View answer and explanation

(7, [1, 7])

Multiply successive choice counts; an empty product is one and a zero stage makes later products zero. No stochastic independence is asserted. The exact result, retaining the requested order, is (7, [1, 7]).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-full-product-prefix · candidate

38. Full Product Choices and Prefix Counts

Ordered stage sizes=[1, 8]; every cross-stage combination is allowed. Give (full product count, each prefix product). Zero stages have one empty selection sequence.

View answer and explanation

(8, [1, 8])

Multiply successive choice counts; an empty product is one and a zero stage makes later products zero. No stochastic independence is asserted. The exact result, retaining the requested order, is (8, [1, 8]).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-full-product-prefix · candidate

39. Full Product Choices and Prefix Counts

Ordered stage sizes=[2, 1]; every cross-stage combination is allowed. Give (full product count, each prefix product). Zero stages have one empty selection sequence.

View answer and explanation

(2, [2, 2])

Multiply successive choice counts; an empty product is one and a zero stage makes later products zero. No stochastic independence is asserted. The exact result, retaining the requested order, is (2, [2, 2]).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-full-product-prefix · candidate

40. Full Product Choices and Prefix Counts

Ordered stage sizes=[2, 2]; every cross-stage combination is allowed. Give (full product count, each prefix product). Zero stages have one empty selection sequence.

View answer and explanation

(4, [2, 4])

Multiply successive choice counts; an empty product is one and a zero stage makes later products zero. No stochastic independence is asserted. The exact result, retaining the requested order, is (4, [2, 4]).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-full-product-prefix · candidate

41. Full Product Choices and Prefix Counts

Ordered stage sizes=[2, 3]; every cross-stage combination is allowed. Give (full product count, each prefix product). Zero stages have one empty selection sequence.

View answer and explanation

(6, [2, 6])

Multiply successive choice counts; an empty product is one and a zero stage makes later products zero. No stochastic independence is asserted. The exact result, retaining the requested order, is (6, [2, 6]).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-full-product-prefix · candidate

42. Full Product Choices and Prefix Counts

Ordered stage sizes=[2, 4]; every cross-stage combination is allowed. Give (full product count, each prefix product). Zero stages have one empty selection sequence.

View answer and explanation

(8, [2, 8])

Multiply successive choice counts; an empty product is one and a zero stage makes later products zero. No stochastic independence is asserted. The exact result, retaining the requested order, is (8, [2, 8]).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-full-product-prefix · candidate

43. Full Product Choices and Prefix Counts

Ordered stage sizes=[2, 5]; every cross-stage combination is allowed. Give (full product count, each prefix product). Zero stages have one empty selection sequence.

View answer and explanation

(10, [2, 10])

Multiply successive choice counts; an empty product is one and a zero stage makes later products zero. No stochastic independence is asserted. The exact result, retaining the requested order, is (10, [2, 10]).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-full-product-prefix · candidate

44. Full Product Choices and Prefix Counts

Ordered stage sizes=[2, 6]; every cross-stage combination is allowed. Give (full product count, each prefix product). Zero stages have one empty selection sequence.

View answer and explanation

(12, [2, 12])

Multiply successive choice counts; an empty product is one and a zero stage makes later products zero. No stochastic independence is asserted. The exact result, retaining the requested order, is (12, [2, 12]).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-full-product-prefix · candidate

45. Full Product Choices and Prefix Counts

Ordered stage sizes=[2, 7]; every cross-stage combination is allowed. Give (full product count, each prefix product). Zero stages have one empty selection sequence.

View answer and explanation

(14, [2, 14])

Multiply successive choice counts; an empty product is one and a zero stage makes later products zero. No stochastic independence is asserted. The exact result, retaining the requested order, is (14, [2, 14]).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-full-product-prefix · candidate

46. Full Product Choices and Prefix Counts

Ordered stage sizes=[2, 8]; every cross-stage combination is allowed. Give (full product count, each prefix product). Zero stages have one empty selection sequence.

View answer and explanation

(16, [2, 16])

Multiply successive choice counts; an empty product is one and a zero stage makes later products zero. No stochastic independence is asserted. The exact result, retaining the requested order, is (16, [2, 16]).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-full-product-prefix · candidate

47. Full Product Choices and Prefix Counts

Ordered stage sizes=[3, 1]; every cross-stage combination is allowed. Give (full product count, each prefix product). Zero stages have one empty selection sequence.

View answer and explanation

(3, [3, 3])

Multiply successive choice counts; an empty product is one and a zero stage makes later products zero. No stochastic independence is asserted. The exact result, retaining the requested order, is (3, [3, 3]).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-full-product-prefix · candidate

48. Full Product Choices and Prefix Counts

Ordered stage sizes=[3, 2]; every cross-stage combination is allowed. Give (full product count, each prefix product). Zero stages have one empty selection sequence.

View answer and explanation

(6, [3, 6])

Multiply successive choice counts; an empty product is one and a zero stage makes later products zero. No stochastic independence is asserted. The exact result, retaining the requested order, is (6, [3, 6]).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-full-product-prefix · candidate

49. Full Product Choices and Prefix Counts

Ordered stage sizes=[3, 3]; every cross-stage combination is allowed. Give (full product count, each prefix product). Zero stages have one empty selection sequence.

View answer and explanation

(9, [3, 9])

Multiply successive choice counts; an empty product is one and a zero stage makes later products zero. No stochastic independence is asserted. The exact result, retaining the requested order, is (9, [3, 9]).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-full-product-prefix · candidate

50. Full Product Choices and Prefix Counts

Ordered stage sizes=[3, 4]; every cross-stage combination is allowed. Give (full product count, each prefix product). Zero stages have one empty selection sequence.

View answer and explanation

(12, [3, 12])

Multiply successive choice counts; an empty product is one and a zero stage makes later products zero. No stochastic independence is asserted. The exact result, retaining the requested order, is (12, [3, 12]).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-full-product-prefix · candidate

51. Actual Branch Widths versus a Candidate Width

Ordered second-stage branch counts=[], n=0; candidate common width h=7. Give (actual total, assumed n*h total, does every branch equal h?, n*h−actual total).

View answer and explanation

(0, 0, Yes, 0)

Sum actual branches and check every width separately; equal totals do not establish equal widths. For no first-stage branches the width condition is vacuously Yes. The exact result, retaining the requested order, is (0, 0, Yes, 0).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-conditional-candidate-defect · candidate

52. Actual Branch Widths versus a Candidate Width

Ordered second-stage branch counts=[1, 3], n=2; candidate common width h=2. Give (actual total, assumed n*h total, does every branch equal h?, n*h−actual total).

View answer and explanation

(4, 4, No, 0)

Sum actual branches and check every width separately; equal totals do not establish equal widths. For no first-stage branches the width condition is vacuously Yes. The exact result, retaining the requested order, is (4, 4, No, 0).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-conditional-candidate-defect · candidate

53. Actual Branch Widths versus a Candidate Width

Ordered second-stage branch counts=[2, 2], n=2; candidate common width h=2. Give (actual total, assumed n*h total, does every branch equal h?, n*h−actual total).

View answer and explanation

(4, 4, Yes, 0)

Sum actual branches and check every width separately; equal totals do not establish equal widths. For no first-stage branches the width condition is vacuously Yes. The exact result, retaining the requested order, is (4, 4, Yes, 0).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-conditional-candidate-defect · candidate

54. Actual Branch Widths versus a Candidate Width

Ordered second-stage branch counts=[0], n=1; candidate common width h=0. Give (actual total, assumed n*h total, does every branch equal h?, n*h−actual total).

View answer and explanation

(0, 0, Yes, 0)

Sum actual branches and check every width separately; equal totals do not establish equal widths. For no first-stage branches the width condition is vacuously Yes. The exact result, retaining the requested order, is (0, 0, Yes, 0).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-conditional-candidate-defect · candidate

55. Actual Branch Widths versus a Candidate Width

Ordered second-stage branch counts=[3], n=1; candidate common width h=2. Give (actual total, assumed n*h total, does every branch equal h?, n*h−actual total).

View answer and explanation

(3, 2, No, -1)

Sum actual branches and check every width separately; equal totals do not establish equal widths. For no first-stage branches the width condition is vacuously Yes. The exact result, retaining the requested order, is (3, 2, No, -1).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-conditional-candidate-defect · candidate

56. Actual Branch Widths versus a Candidate Width

Ordered second-stage branch counts=[5, 6], n=2; candidate common width h=0. Give (actual total, assumed n*h total, does every branch equal h?, n*h−actual total).

View answer and explanation

(11, 0, No, -11)

Sum actual branches and check every width separately; equal totals do not establish equal widths. For no first-stage branches the width condition is vacuously Yes. The exact result, retaining the requested order, is (11, 0, No, -11).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-conditional-candidate-defect · candidate

57. Actual Branch Widths versus a Candidate Width

Ordered second-stage branch counts=[6, 7], n=2; candidate common width h=0. Give (actual total, assumed n*h total, does every branch equal h?, n*h−actual total).

View answer and explanation

(13, 0, No, -13)

Sum actual branches and check every width separately; equal totals do not establish equal widths. For no first-stage branches the width condition is vacuously Yes. The exact result, retaining the requested order, is (13, 0, No, -13).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-conditional-candidate-defect · candidate

58. Actual Branch Widths versus a Candidate Width

Ordered second-stage branch counts=[7, 8], n=2; candidate common width h=0. Give (actual total, assumed n*h total, does every branch equal h?, n*h−actual total).

View answer and explanation

(15, 0, No, -15)

Sum actual branches and check every width separately; equal totals do not establish equal widths. For no first-stage branches the width condition is vacuously Yes. The exact result, retaining the requested order, is (15, 0, No, -15).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-conditional-candidate-defect · candidate

59. Actual Branch Widths versus a Candidate Width

Ordered second-stage branch counts=[8, 0], n=2; candidate common width h=0. Give (actual total, assumed n*h total, does every branch equal h?, n*h−actual total).

View answer and explanation

(8, 0, No, -8)

Sum actual branches and check every width separately; equal totals do not establish equal widths. For no first-stage branches the width condition is vacuously Yes. The exact result, retaining the requested order, is (8, 0, No, -8).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-conditional-candidate-defect · candidate

60. Actual Branch Widths versus a Candidate Width

Ordered second-stage branch counts=[0, 1], n=2; candidate common width h=1. Give (actual total, assumed n*h total, does every branch equal h?, n*h−actual total).

View answer and explanation

(1, 2, No, 1)

Sum actual branches and check every width separately; equal totals do not establish equal widths. For no first-stage branches the width condition is vacuously Yes. The exact result, retaining the requested order, is (1, 2, No, 1).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-conditional-candidate-defect · candidate

61. Actual Branch Widths versus a Candidate Width

Ordered second-stage branch counts=[1, 2], n=2; candidate common width h=1. Give (actual total, assumed n*h total, does every branch equal h?, n*h−actual total).

View answer and explanation

(3, 2, No, -1)

Sum actual branches and check every width separately; equal totals do not establish equal widths. For no first-stage branches the width condition is vacuously Yes. The exact result, retaining the requested order, is (3, 2, No, -1).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-conditional-candidate-defect · candidate

62. Actual Branch Widths versus a Candidate Width

Ordered second-stage branch counts=[2, 3], n=2; candidate common width h=1. Give (actual total, assumed n*h total, does every branch equal h?, n*h−actual total).

View answer and explanation

(5, 2, No, -3)

Sum actual branches and check every width separately; equal totals do not establish equal widths. For no first-stage branches the width condition is vacuously Yes. The exact result, retaining the requested order, is (5, 2, No, -3).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-conditional-candidate-defect · candidate

63. Actual Branch Widths versus a Candidate Width

Ordered second-stage branch counts=[3, 4], n=2; candidate common width h=1. Give (actual total, assumed n*h total, does every branch equal h?, n*h−actual total).

View answer and explanation

(7, 2, No, -5)

Sum actual branches and check every width separately; equal totals do not establish equal widths. For no first-stage branches the width condition is vacuously Yes. The exact result, retaining the requested order, is (7, 2, No, -5).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-conditional-candidate-defect · candidate

64. Actual Branch Widths versus a Candidate Width

Ordered second-stage branch counts=[4, 5], n=2; candidate common width h=1. Give (actual total, assumed n*h total, does every branch equal h?, n*h−actual total).

View answer and explanation

(9, 2, No, -7)

Sum actual branches and check every width separately; equal totals do not establish equal widths. For no first-stage branches the width condition is vacuously Yes. The exact result, retaining the requested order, is (9, 2, No, -7).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-conditional-candidate-defect · candidate

65. Actual Branch Widths versus a Candidate Width

Ordered second-stage branch counts=[5, 6], n=2; candidate common width h=1. Give (actual total, assumed n*h total, does every branch equal h?, n*h−actual total).

View answer and explanation

(11, 2, No, -9)

Sum actual branches and check every width separately; equal totals do not establish equal widths. For no first-stage branches the width condition is vacuously Yes. The exact result, retaining the requested order, is (11, 2, No, -9).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-conditional-candidate-defect · candidate

66. Actual Branch Widths versus a Candidate Width

Ordered second-stage branch counts=[6, 7], n=2; candidate common width h=1. Give (actual total, assumed n*h total, does every branch equal h?, n*h−actual total).

View answer and explanation

(13, 2, No, -11)

Sum actual branches and check every width separately; equal totals do not establish equal widths. For no first-stage branches the width condition is vacuously Yes. The exact result, retaining the requested order, is (13, 2, No, -11).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-conditional-candidate-defect · candidate

67. Actual Branch Widths versus a Candidate Width

Ordered second-stage branch counts=[7, 8], n=2; candidate common width h=1. Give (actual total, assumed n*h total, does every branch equal h?, n*h−actual total).

View answer and explanation

(15, 2, No, -13)

Sum actual branches and check every width separately; equal totals do not establish equal widths. For no first-stage branches the width condition is vacuously Yes. The exact result, retaining the requested order, is (15, 2, No, -13).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-conditional-candidate-defect · candidate

68. Actual Branch Widths versus a Candidate Width

Ordered second-stage branch counts=[8, 0], n=2; candidate common width h=1. Give (actual total, assumed n*h total, does every branch equal h?, n*h−actual total).

View answer and explanation

(8, 2, No, -6)

Sum actual branches and check every width separately; equal totals do not establish equal widths. For no first-stage branches the width condition is vacuously Yes. The exact result, retaining the requested order, is (8, 2, No, -6).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-conditional-candidate-defect · candidate

69. Actual Branch Widths versus a Candidate Width

Ordered second-stage branch counts=[0, 1], n=2; candidate common width h=2. Give (actual total, assumed n*h total, does every branch equal h?, n*h−actual total).

View answer and explanation

(1, 4, No, 3)

Sum actual branches and check every width separately; equal totals do not establish equal widths. For no first-stage branches the width condition is vacuously Yes. The exact result, retaining the requested order, is (1, 4, No, 3).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-conditional-candidate-defect · candidate

70. Actual Branch Widths versus a Candidate Width

Ordered second-stage branch counts=[1, 2], n=2; candidate common width h=2. Give (actual total, assumed n*h total, does every branch equal h?, n*h−actual total).

View answer and explanation

(3, 4, No, 1)

Sum actual branches and check every width separately; equal totals do not establish equal widths. For no first-stage branches the width condition is vacuously Yes. The exact result, retaining the requested order, is (3, 4, No, 1).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-conditional-candidate-defect · candidate

71. Actual Branch Widths versus a Candidate Width

Ordered second-stage branch counts=[2, 3], n=2; candidate common width h=2. Give (actual total, assumed n*h total, does every branch equal h?, n*h−actual total).

View answer and explanation

(5, 4, No, -1)

Sum actual branches and check every width separately; equal totals do not establish equal widths. For no first-stage branches the width condition is vacuously Yes. The exact result, retaining the requested order, is (5, 4, No, -1).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-conditional-candidate-defect · candidate

72. Actual Branch Widths versus a Candidate Width

Ordered second-stage branch counts=[3, 4], n=2; candidate common width h=2. Give (actual total, assumed n*h total, does every branch equal h?, n*h−actual total).

View answer and explanation

(7, 4, No, -3)

Sum actual branches and check every width separately; equal totals do not establish equal widths. For no first-stage branches the width condition is vacuously Yes. The exact result, retaining the requested order, is (7, 4, No, -3).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-conditional-candidate-defect · candidate

73. Actual Branch Widths versus a Candidate Width

Ordered second-stage branch counts=[4, 5], n=2; candidate common width h=2. Give (actual total, assumed n*h total, does every branch equal h?, n*h−actual total).

View answer and explanation

(9, 4, No, -5)

Sum actual branches and check every width separately; equal totals do not establish equal widths. For no first-stage branches the width condition is vacuously Yes. The exact result, retaining the requested order, is (9, 4, No, -5).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-conditional-candidate-defect · candidate

74. Actual Branch Widths versus a Candidate Width

Ordered second-stage branch counts=[5, 6], n=2; candidate common width h=2. Give (actual total, assumed n*h total, does every branch equal h?, n*h−actual total).

View answer and explanation

(11, 4, No, -7)

Sum actual branches and check every width separately; equal totals do not establish equal widths. For no first-stage branches the width condition is vacuously Yes. The exact result, retaining the requested order, is (11, 4, No, -7).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-conditional-candidate-defect · candidate

75. Actual Branch Widths versus a Candidate Width

Ordered second-stage branch counts=[6, 7], n=2; candidate common width h=2. Give (actual total, assumed n*h total, does every branch equal h?, n*h−actual total).

View answer and explanation

(13, 4, No, -9)

Sum actual branches and check every width separately; equal totals do not establish equal widths. For no first-stage branches the width condition is vacuously Yes. The exact result, retaining the requested order, is (13, 4, No, -9).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-conditional-candidate-defect · candidate

76. Overlap-Corrected Finite Choice Counts

Finite integer choice sets A=[], B=[]. Give (|A|+|B|, |A∪B|, |A∩B|).

View answer and explanation

(0, 0, 0)

Enumerate actual union/intersection membership; adding both cardinalities double-counts shared choices. No probability-independence premise is involved. The exact result, retaining the requested order, is (0, 0, 0).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-overlap-correction · candidate

77. Overlap-Corrected Finite Choice Counts

Finite integer choice sets A=[0], B=[0]. Give (|A|+|B|, |A∪B|, |A∩B|).

View answer and explanation

(2, 1, 1)

Enumerate actual union/intersection membership; adding both cardinalities double-counts shared choices. No probability-independence premise is involved. The exact result, retaining the requested order, is (2, 1, 1).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-overlap-correction · candidate

78. Overlap-Corrected Finite Choice Counts

Finite integer choice sets A=[], B=[100]. Give (|A|+|B|, |A∪B|, |A∩B|).

View answer and explanation

(1, 1, 0)

Enumerate actual union/intersection membership; adding both cardinalities double-counts shared choices. No probability-independence premise is involved. The exact result, retaining the requested order, is (1, 1, 0).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-overlap-correction · candidate

79. Overlap-Corrected Finite Choice Counts

Finite integer choice sets A=[0, 1], B=[0, 1]. Give (|A|+|B|, |A∪B|, |A∩B|).

View answer and explanation

(4, 2, 2)

Enumerate actual union/intersection membership; adding both cardinalities double-counts shared choices. No probability-independence premise is involved. The exact result, retaining the requested order, is (4, 2, 2).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-overlap-correction · candidate

80. Overlap-Corrected Finite Choice Counts

Finite integer choice sets A=[0], B=[0, 100]. Give (|A|+|B|, |A∪B|, |A∩B|).

View answer and explanation

(3, 2, 1)

Enumerate actual union/intersection membership; adding both cardinalities double-counts shared choices. No probability-independence premise is involved. The exact result, retaining the requested order, is (3, 2, 1).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-overlap-correction · candidate

81. Overlap-Corrected Finite Choice Counts

Finite integer choice sets A=[], B=[100, 101]. Give (|A|+|B|, |A∪B|, |A∩B|).

View answer and explanation

(2, 2, 0)

Enumerate actual union/intersection membership; adding both cardinalities double-counts shared choices. No probability-independence premise is involved. The exact result, retaining the requested order, is (2, 2, 0).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-overlap-correction · candidate

82. Overlap-Corrected Finite Choice Counts

Finite integer choice sets A=[-1], B=[100]. Give (|A|+|B|, |A∪B|, |A∩B|).

View answer and explanation

(2, 2, 0)

Enumerate actual union/intersection membership; adding both cardinalities double-counts shared choices. No probability-independence premise is involved. The exact result, retaining the requested order, is (2, 2, 0).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-overlap-correction · candidate

83. Overlap-Corrected Finite Choice Counts

Finite integer choice sets A=[0, 1, 2], B=[0, 1, 2]. Give (|A|+|B|, |A∪B|, |A∩B|).

View answer and explanation

(6, 3, 3)

Enumerate actual union/intersection membership; adding both cardinalities double-counts shared choices. No probability-independence premise is involved. The exact result, retaining the requested order, is (6, 3, 3).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-overlap-correction · candidate

84. Overlap-Corrected Finite Choice Counts

Finite integer choice sets A=[0, 1], B=[0, 1, 100]. Give (|A|+|B|, |A∪B|, |A∩B|).

View answer and explanation

(5, 3, 2)

Enumerate actual union/intersection membership; adding both cardinalities double-counts shared choices. No probability-independence premise is involved. The exact result, retaining the requested order, is (5, 3, 2).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-overlap-correction · candidate

85. Overlap-Corrected Finite Choice Counts

Finite integer choice sets A=[0], B=[0, 100, 101]. Give (|A|+|B|, |A∪B|, |A∩B|).

View answer and explanation

(4, 3, 1)

Enumerate actual union/intersection membership; adding both cardinalities double-counts shared choices. No probability-independence premise is involved. The exact result, retaining the requested order, is (4, 3, 1).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-overlap-correction · candidate

86. Overlap-Corrected Finite Choice Counts

Finite integer choice sets A=[], B=[100, 101, 102]. Give (|A|+|B|, |A∪B|, |A∩B|).

View answer and explanation

(3, 3, 0)

Enumerate actual union/intersection membership; adding both cardinalities double-counts shared choices. No probability-independence premise is involved. The exact result, retaining the requested order, is (3, 3, 0).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-overlap-correction · candidate

87. Overlap-Corrected Finite Choice Counts

Finite integer choice sets A=[0, -1], B=[0, 100]. Give (|A|+|B|, |A∪B|, |A∩B|).

View answer and explanation

(4, 3, 1)

Enumerate actual union/intersection membership; adding both cardinalities double-counts shared choices. No probability-independence premise is involved. The exact result, retaining the requested order, is (4, 3, 1).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-overlap-correction · candidate

88. Overlap-Corrected Finite Choice Counts

Finite integer choice sets A=[-1], B=[100, 101]. Give (|A|+|B|, |A∪B|, |A∩B|).

View answer and explanation

(3, 3, 0)

Enumerate actual union/intersection membership; adding both cardinalities double-counts shared choices. No probability-independence premise is involved. The exact result, retaining the requested order, is (3, 3, 0).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-overlap-correction · candidate

89. Overlap-Corrected Finite Choice Counts

Finite integer choice sets A=[0, 1, 2, 3], B=[0, 1, 2, 3]. Give (|A|+|B|, |A∪B|, |A∩B|).

View answer and explanation

(8, 4, 4)

Enumerate actual union/intersection membership; adding both cardinalities double-counts shared choices. No probability-independence premise is involved. The exact result, retaining the requested order, is (8, 4, 4).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-overlap-correction · candidate

90. Overlap-Corrected Finite Choice Counts

Finite integer choice sets A=[0, 1, 2], B=[0, 1, 2, 100]. Give (|A|+|B|, |A∪B|, |A∩B|).

View answer and explanation

(7, 4, 3)

Enumerate actual union/intersection membership; adding both cardinalities double-counts shared choices. No probability-independence premise is involved. The exact result, retaining the requested order, is (7, 4, 3).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-overlap-correction · candidate

91. Overlap-Corrected Finite Choice Counts

Finite integer choice sets A=[0, 1], B=[0, 1, 100, 101]. Give (|A|+|B|, |A∪B|, |A∩B|).

View answer and explanation

(6, 4, 2)

Enumerate actual union/intersection membership; adding both cardinalities double-counts shared choices. No probability-independence premise is involved. The exact result, retaining the requested order, is (6, 4, 2).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-overlap-correction · candidate

92. Overlap-Corrected Finite Choice Counts

Finite integer choice sets A=[0], B=[0, 100, 101, 102]. Give (|A|+|B|, |A∪B|, |A∩B|).

View answer and explanation

(5, 4, 1)

Enumerate actual union/intersection membership; adding both cardinalities double-counts shared choices. No probability-independence premise is involved. The exact result, retaining the requested order, is (5, 4, 1).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-overlap-correction · candidate

93. Overlap-Corrected Finite Choice Counts

Finite integer choice sets A=[], B=[100, 101, 102, 103]. Give (|A|+|B|, |A∪B|, |A∩B|).

View answer and explanation

(4, 4, 0)

Enumerate actual union/intersection membership; adding both cardinalities double-counts shared choices. No probability-independence premise is involved. The exact result, retaining the requested order, is (4, 4, 0).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-overlap-correction · candidate

94. Overlap-Corrected Finite Choice Counts

Finite integer choice sets A=[0, 1, -1], B=[0, 1, 100]. Give (|A|+|B|, |A∪B|, |A∩B|).

View answer and explanation

(6, 4, 2)

Enumerate actual union/intersection membership; adding both cardinalities double-counts shared choices. No probability-independence premise is involved. The exact result, retaining the requested order, is (6, 4, 2).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-overlap-correction · candidate

95. Overlap-Corrected Finite Choice Counts

Finite integer choice sets A=[0, -1], B=[0, 100, 101]. Give (|A|+|B|, |A∪B|, |A∩B|).

View answer and explanation

(5, 4, 1)

Enumerate actual union/intersection membership; adding both cardinalities double-counts shared choices. No probability-independence premise is involved. The exact result, retaining the requested order, is (5, 4, 1).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-overlap-correction · candidate

96. Overlap-Corrected Finite Choice Counts

Finite integer choice sets A=[-1], B=[100, 101, 102]. Give (|A|+|B|, |A∪B|, |A∩B|).

View answer and explanation

(4, 4, 0)

Enumerate actual union/intersection membership; adding both cardinalities double-counts shared choices. No probability-independence premise is involved. The exact result, retaining the requested order, is (4, 4, 0).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-overlap-correction · candidate

97. Overlap-Corrected Finite Choice Counts

Finite integer choice sets A=[-2, -1], B=[100, 101]. Give (|A|+|B|, |A∪B|, |A∩B|).

View answer and explanation

(4, 4, 0)

Enumerate actual union/intersection membership; adding both cardinalities double-counts shared choices. No probability-independence premise is involved. The exact result, retaining the requested order, is (4, 4, 0).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-overlap-correction · candidate

98. Overlap-Corrected Finite Choice Counts

Finite integer choice sets A=[0, 1, 2, 3, 4], B=[0, 1, 2, 3, 4]. Give (|A|+|B|, |A∪B|, |A∩B|).

View answer and explanation

(10, 5, 5)

Enumerate actual union/intersection membership; adding both cardinalities double-counts shared choices. No probability-independence premise is involved. The exact result, retaining the requested order, is (10, 5, 5).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-overlap-correction · candidate

99. Overlap-Corrected Finite Choice Counts

Finite integer choice sets A=[0, 1, 2, 3], B=[0, 1, 2, 3, 100]. Give (|A|+|B|, |A∪B|, |A∩B|).

View answer and explanation

(9, 5, 4)

Enumerate actual union/intersection membership; adding both cardinalities double-counts shared choices. No probability-independence premise is involved. The exact result, retaining the requested order, is (9, 5, 4).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-overlap-correction · candidate

100. Overlap-Corrected Finite Choice Counts

Finite integer choice sets A=[0, 1, 2], B=[0, 1, 2, 100, 101]. Give (|A|+|B|, |A∪B|, |A∩B|).

View answer and explanation

(8, 5, 3)

Enumerate actual union/intersection membership; adding both cardinalities double-counts shared choices. No probability-independence premise is involved. The exact result, retaining the requested order, is (8, 5, 3).

Reviewed step-by-step derivation

Basic counting principles · qf-density12-counting-overlap-correction · candidate

Canonical question JSONL · English JSONL · Validation report