# Finite Tail Audits, Infinite Cauchy Witnesses and Alternating Counterexamples

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This question bank has corresponding bilingual step-by-step derivations. Source candidate and English ai_candidate states are retained. AI review, finite computation and Lean formal proof are labelled separately.

batch-20261013-advance-20261026-r03-cauchy-sequence-foundations · 2026-10-13 · 100 questions

This English edition is an AI candidate and does not yet have an OCME Atlas (GPT-6) Twin closure receipt.



## 1. A Finite Tail Audit Cannot Establish General Cauchy Behavior

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. Recorded rational sequence=[1/2, 1/3, 1/4, 1/5, 1/6], epsilon=1/3, cutoff N=0; only listed zero-based indices are available. Give (normalized sequence,epsilon,N,all bad [m,n,distance] records in ordered-index order,finite_tail_pass?,general Cauchy established by this audit?,finite-tail-insufficient-for-general-Cauchy). A bad distance is at least epsilon. Use exact reduced rational outputs with positive denominators; omit /1 for integers.

View answer and explanation([1/2, 1/3, 1/4, 1/5, 1/6], 1/3, 0, [[0, 4, 1/3], [4, 0, 1/3]], No, No, finite-tail-insufficient-for-general-Cauchy)

Enumerate every ordered pair of listed indices at or beyond N. An empty tail passes vacuously. The general_cauchy No means not established by this finite audit, not a proof that every infinite continuation is non-Cauchy. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is ([1/2, 1/3, 1/4, 1/5, 1/6], 1/3, 0, [[0, 4, 1/3], [4, 0, 1/3]], No, No, finite-tail-insufficient-for-general-Cauchy).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0001/)

Cauchy sequence · qf-mod26-cauchy-finite-tail-audit · candidate





## 2. A Finite Tail Audit Cannot Establish General Cauchy Behavior

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. Recorded rational sequence=[1/3, 1/4, 1/5, 1/6, 1/7], epsilon=1/4, cutoff N=1; only listed zero-based indices are available. Give (normalized sequence,epsilon,N,all bad [m,n,distance] records in ordered-index order,finite_tail_pass?,general Cauchy established by this audit?,finite-tail-insufficient-for-general-Cauchy). A bad distance is at least epsilon. Use exact reduced rational outputs with positive denominators; omit /1 for integers.

View answer and explanation([1/3, 1/4, 1/5, 1/6, 1/7], 1/4, 1, [], Yes, No, finite-tail-insufficient-for-general-Cauchy)

Enumerate every ordered pair of listed indices at or beyond N. An empty tail passes vacuously. The general_cauchy No means not established by this finite audit, not a proof that every infinite continuation is non-Cauchy. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is ([1/3, 1/4, 1/5, 1/6, 1/7], 1/4, 1, [], Yes, No, finite-tail-insufficient-for-general-Cauchy).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0002/)

Cauchy sequence · qf-mod26-cauchy-finite-tail-audit · candidate





## 3. A Finite Tail Audit Cannot Establish General Cauchy Behavior

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. Recorded rational sequence=[1/4, 1/5, 1/6, 1/7, 1/8], epsilon=1/5, cutoff N=2; only listed zero-based indices are available. Give (normalized sequence,epsilon,N,all bad [m,n,distance] records in ordered-index order,finite_tail_pass?,general Cauchy established by this audit?,finite-tail-insufficient-for-general-Cauchy). A bad distance is at least epsilon. Use exact reduced rational outputs with positive denominators; omit /1 for integers.

View answer and explanation([1/4, 1/5, 1/6, 1/7, 1/8], 1/5, 2, [], Yes, No, finite-tail-insufficient-for-general-Cauchy)

Enumerate every ordered pair of listed indices at or beyond N. An empty tail passes vacuously. The general_cauchy No means not established by this finite audit, not a proof that every infinite continuation is non-Cauchy. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is ([1/4, 1/5, 1/6, 1/7, 1/8], 1/5, 2, [], Yes, No, finite-tail-insufficient-for-general-Cauchy).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0003/)

Cauchy sequence · qf-mod26-cauchy-finite-tail-audit · candidate





## 4. A Finite Tail Audit Cannot Establish General Cauchy Behavior

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. Recorded rational sequence=[1/5, 1/6, 1/7, 1/8, 1/9], epsilon=1/6, cutoff N=0; only listed zero-based indices are available. Give (normalized sequence,epsilon,N,all bad [m,n,distance] records in ordered-index order,finite_tail_pass?,general Cauchy established by this audit?,finite-tail-insufficient-for-general-Cauchy). A bad distance is at least epsilon. Use exact reduced rational outputs with positive denominators; omit /1 for integers.

View answer and explanation([1/5, 1/6, 1/7, 1/8, 1/9], 1/6, 0, [], Yes, No, finite-tail-insufficient-for-general-Cauchy)

Enumerate every ordered pair of listed indices at or beyond N. An empty tail passes vacuously. The general_cauchy No means not established by this finite audit, not a proof that every infinite continuation is non-Cauchy. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is ([1/5, 1/6, 1/7, 1/8, 1/9], 1/6, 0, [], Yes, No, finite-tail-insufficient-for-general-Cauchy).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0004/)

Cauchy sequence · qf-mod26-cauchy-finite-tail-audit · candidate





## 5. A Finite Tail Audit Cannot Establish General Cauchy Behavior

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. Recorded rational sequence=[1/6, 1/7, 1/8, 1/9, 1/10], epsilon=1/7, cutoff N=1; only listed zero-based indices are available. Give (normalized sequence,epsilon,N,all bad [m,n,distance] records in ordered-index order,finite_tail_pass?,general Cauchy established by this audit?,finite-tail-insufficient-for-general-Cauchy). A bad distance is at least epsilon. Use exact reduced rational outputs with positive denominators; omit /1 for integers.

View answer and explanation([1/6, 1/7, 1/8, 1/9, 1/10], 1/7, 1, [], Yes, No, finite-tail-insufficient-for-general-Cauchy)

Enumerate every ordered pair of listed indices at or beyond N. An empty tail passes vacuously. The general_cauchy No means not established by this finite audit, not a proof that every infinite continuation is non-Cauchy. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is ([1/6, 1/7, 1/8, 1/9, 1/10], 1/7, 1, [], Yes, No, finite-tail-insufficient-for-general-Cauchy).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0005/)

Cauchy sequence · qf-mod26-cauchy-finite-tail-audit · candidate





## 6. A Finite Tail Audit Cannot Establish General Cauchy Behavior

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. Recorded rational sequence=[1/7, 1/8, 1/9, 1/10, 1/11], epsilon=1/3, cutoff N=2; only listed zero-based indices are available. Give (normalized sequence,epsilon,N,all bad [m,n,distance] records in ordered-index order,finite_tail_pass?,general Cauchy established by this audit?,finite-tail-insufficient-for-general-Cauchy). A bad distance is at least epsilon. Use exact reduced rational outputs with positive denominators; omit /1 for integers.

View answer and explanation([1/7, 1/8, 1/9, 1/10, 1/11], 1/3, 2, [], Yes, No, finite-tail-insufficient-for-general-Cauchy)

Enumerate every ordered pair of listed indices at or beyond N. An empty tail passes vacuously. The general_cauchy No means not established by this finite audit, not a proof that every infinite continuation is non-Cauchy. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is ([1/7, 1/8, 1/9, 1/10, 1/11], 1/3, 2, [], Yes, No, finite-tail-insufficient-for-general-Cauchy).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0006/)

Cauchy sequence · qf-mod26-cauchy-finite-tail-audit · candidate





## 7. A Finite Tail Audit Cannot Establish General Cauchy Behavior

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. Recorded rational sequence=[1/8, 1/9, 1/10, 1/11, 1/12], epsilon=1/4, cutoff N=0; only listed zero-based indices are available. Give (normalized sequence,epsilon,N,all bad [m,n,distance] records in ordered-index order,finite_tail_pass?,general Cauchy established by this audit?,finite-tail-insufficient-for-general-Cauchy). A bad distance is at least epsilon. Use exact reduced rational outputs with positive denominators; omit /1 for integers.

View answer and explanation([1/8, 1/9, 1/10, 1/11, 1/12], 1/4, 0, [], Yes, No, finite-tail-insufficient-for-general-Cauchy)

Enumerate every ordered pair of listed indices at or beyond N. An empty tail passes vacuously. The general_cauchy No means not established by this finite audit, not a proof that every infinite continuation is non-Cauchy. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is ([1/8, 1/9, 1/10, 1/11, 1/12], 1/4, 0, [], Yes, No, finite-tail-insufficient-for-general-Cauchy).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0007/)

Cauchy sequence · qf-mod26-cauchy-finite-tail-audit · candidate





## 8. A Finite Tail Audit Cannot Establish General Cauchy Behavior

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. Recorded rational sequence=[1/9, 1/10, 1/11, 1/12, 1/13], epsilon=1/5, cutoff N=1; only listed zero-based indices are available. Give (normalized sequence,epsilon,N,all bad [m,n,distance] records in ordered-index order,finite_tail_pass?,general Cauchy established by this audit?,finite-tail-insufficient-for-general-Cauchy). A bad distance is at least epsilon. Use exact reduced rational outputs with positive denominators; omit /1 for integers.

View answer and explanation([1/9, 1/10, 1/11, 1/12, 1/13], 1/5, 1, [], Yes, No, finite-tail-insufficient-for-general-Cauchy)

Enumerate every ordered pair of listed indices at or beyond N. An empty tail passes vacuously. The general_cauchy No means not established by this finite audit, not a proof that every infinite continuation is non-Cauchy. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is ([1/9, 1/10, 1/11, 1/12, 1/13], 1/5, 1, [], Yes, No, finite-tail-insufficient-for-general-Cauchy).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0008/)

Cauchy sequence · qf-mod26-cauchy-finite-tail-audit · candidate





## 9. A Finite Tail Audit Cannot Establish General Cauchy Behavior

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. Recorded rational sequence=[1/10, 1/11, 1/12, 1/13, 1/14], epsilon=1/6, cutoff N=2; only listed zero-based indices are available. Give (normalized sequence,epsilon,N,all bad [m,n,distance] records in ordered-index order,finite_tail_pass?,general Cauchy established by this audit?,finite-tail-insufficient-for-general-Cauchy). A bad distance is at least epsilon. Use exact reduced rational outputs with positive denominators; omit /1 for integers.

View answer and explanation([1/10, 1/11, 1/12, 1/13, 1/14], 1/6, 2, [], Yes, No, finite-tail-insufficient-for-general-Cauchy)

Enumerate every ordered pair of listed indices at or beyond N. An empty tail passes vacuously. The general_cauchy No means not established by this finite audit, not a proof that every infinite continuation is non-Cauchy. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is ([1/10, 1/11, 1/12, 1/13, 1/14], 1/6, 2, [], Yes, No, finite-tail-insufficient-for-general-Cauchy).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0009/)

Cauchy sequence · qf-mod26-cauchy-finite-tail-audit · candidate





## 10. A Finite Tail Audit Cannot Establish General Cauchy Behavior

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. Recorded rational sequence=[1/11, 1/12, 1/13, 1/14, 1/15], epsilon=1/7, cutoff N=0; only listed zero-based indices are available. Give (normalized sequence,epsilon,N,all bad [m,n,distance] records in ordered-index order,finite_tail_pass?,general Cauchy established by this audit?,finite-tail-insufficient-for-general-Cauchy). A bad distance is at least epsilon. Use exact reduced rational outputs with positive denominators; omit /1 for integers.

View answer and explanation([1/11, 1/12, 1/13, 1/14, 1/15], 1/7, 0, [], Yes, No, finite-tail-insufficient-for-general-Cauchy)

Enumerate every ordered pair of listed indices at or beyond N. An empty tail passes vacuously. The general_cauchy No means not established by this finite audit, not a proof that every infinite continuation is non-Cauchy. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is ([1/11, 1/12, 1/13, 1/14, 1/15], 1/7, 0, [], Yes, No, finite-tail-insufficient-for-general-Cauchy).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0010/)

Cauchy sequence · qf-mod26-cauchy-finite-tail-audit · candidate





## 11. A Finite Tail Audit Cannot Establish General Cauchy Behavior

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. Recorded rational sequence=[1/12, 1/13, 1/14, 1/15, 1/16], epsilon=1/3, cutoff N=1; only listed zero-based indices are available. Give (normalized sequence,epsilon,N,all bad [m,n,distance] records in ordered-index order,finite_tail_pass?,general Cauchy established by this audit?,finite-tail-insufficient-for-general-Cauchy). A bad distance is at least epsilon. Use exact reduced rational outputs with positive denominators; omit /1 for integers.

View answer and explanation([1/12, 1/13, 1/14, 1/15, 1/16], 1/3, 1, [], Yes, No, finite-tail-insufficient-for-general-Cauchy)

Enumerate every ordered pair of listed indices at or beyond N. An empty tail passes vacuously. The general_cauchy No means not established by this finite audit, not a proof that every infinite continuation is non-Cauchy. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is ([1/12, 1/13, 1/14, 1/15, 1/16], 1/3, 1, [], Yes, No, finite-tail-insufficient-for-general-Cauchy).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0011/)

Cauchy sequence · qf-mod26-cauchy-finite-tail-audit · candidate





## 12. A Finite Tail Audit Cannot Establish General Cauchy Behavior

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. Recorded rational sequence=[1/13, 1/14, 1/15, 1/16, 1/17], epsilon=1/4, cutoff N=2; only listed zero-based indices are available. Give (normalized sequence,epsilon,N,all bad [m,n,distance] records in ordered-index order,finite_tail_pass?,general Cauchy established by this audit?,finite-tail-insufficient-for-general-Cauchy). A bad distance is at least epsilon. Use exact reduced rational outputs with positive denominators; omit /1 for integers.

View answer and explanation([1/13, 1/14, 1/15, 1/16, 1/17], 1/4, 2, [], Yes, No, finite-tail-insufficient-for-general-Cauchy)

Enumerate every ordered pair of listed indices at or beyond N. An empty tail passes vacuously. The general_cauchy No means not established by this finite audit, not a proof that every infinite continuation is non-Cauchy. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is ([1/13, 1/14, 1/15, 1/16, 1/17], 1/4, 2, [], Yes, No, finite-tail-insufficient-for-general-Cauchy).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0012/)

Cauchy sequence · qf-mod26-cauchy-finite-tail-audit · candidate





## 13. A Finite Tail Audit Cannot Establish General Cauchy Behavior

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. Recorded rational sequence=[1/14, 1/15, 1/16, 1/17, 1/18], epsilon=1/5, cutoff N=0; only listed zero-based indices are available. Give (normalized sequence,epsilon,N,all bad [m,n,distance] records in ordered-index order,finite_tail_pass?,general Cauchy established by this audit?,finite-tail-insufficient-for-general-Cauchy). A bad distance is at least epsilon. Use exact reduced rational outputs with positive denominators; omit /1 for integers.

View answer and explanation([1/14, 1/15, 1/16, 1/17, 1/18], 1/5, 0, [], Yes, No, finite-tail-insufficient-for-general-Cauchy)

Enumerate every ordered pair of listed indices at or beyond N. An empty tail passes vacuously. The general_cauchy No means not established by this finite audit, not a proof that every infinite continuation is non-Cauchy. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is ([1/14, 1/15, 1/16, 1/17, 1/18], 1/5, 0, [], Yes, No, finite-tail-insufficient-for-general-Cauchy).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0013/)

Cauchy sequence · qf-mod26-cauchy-finite-tail-audit · candidate





## 14. A Finite Tail Audit Cannot Establish General Cauchy Behavior

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. Recorded rational sequence=[1/15, 1/16, 1/17, 1/18, 1/19], epsilon=1/6, cutoff N=1; only listed zero-based indices are available. Give (normalized sequence,epsilon,N,all bad [m,n,distance] records in ordered-index order,finite_tail_pass?,general Cauchy established by this audit?,finite-tail-insufficient-for-general-Cauchy). A bad distance is at least epsilon. Use exact reduced rational outputs with positive denominators; omit /1 for integers.

View answer and explanation([1/15, 1/16, 1/17, 1/18, 1/19], 1/6, 1, [], Yes, No, finite-tail-insufficient-for-general-Cauchy)

Enumerate every ordered pair of listed indices at or beyond N. An empty tail passes vacuously. The general_cauchy No means not established by this finite audit, not a proof that every infinite continuation is non-Cauchy. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is ([1/15, 1/16, 1/17, 1/18, 1/19], 1/6, 1, [], Yes, No, finite-tail-insufficient-for-general-Cauchy).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0014/)

Cauchy sequence · qf-mod26-cauchy-finite-tail-audit · candidate





## 15. A Finite Tail Audit Cannot Establish General Cauchy Behavior

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. Recorded rational sequence=[1/16, 1/17, 1/18, 1/19, 1/20], epsilon=1/7, cutoff N=2; only listed zero-based indices are available. Give (normalized sequence,epsilon,N,all bad [m,n,distance] records in ordered-index order,finite_tail_pass?,general Cauchy established by this audit?,finite-tail-insufficient-for-general-Cauchy). A bad distance is at least epsilon. Use exact reduced rational outputs with positive denominators; omit /1 for integers.

View answer and explanation([1/16, 1/17, 1/18, 1/19, 1/20], 1/7, 2, [], Yes, No, finite-tail-insufficient-for-general-Cauchy)

Enumerate every ordered pair of listed indices at or beyond N. An empty tail passes vacuously. The general_cauchy No means not established by this finite audit, not a proof that every infinite continuation is non-Cauchy. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is ([1/16, 1/17, 1/18, 1/19, 1/20], 1/7, 2, [], Yes, No, finite-tail-insufficient-for-general-Cauchy).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0015/)

Cauchy sequence · qf-mod26-cauchy-finite-tail-audit · candidate





## 16. A Finite Tail Audit Cannot Establish General Cauchy Behavior

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. Recorded rational sequence=[1/17, 1/18, 1/19, 1/20, 1/21], epsilon=1/3, cutoff N=0; only listed zero-based indices are available. Give (normalized sequence,epsilon,N,all bad [m,n,distance] records in ordered-index order,finite_tail_pass?,general Cauchy established by this audit?,finite-tail-insufficient-for-general-Cauchy). A bad distance is at least epsilon. Use exact reduced rational outputs with positive denominators; omit /1 for integers.

View answer and explanation([1/17, 1/18, 1/19, 1/20, 1/21], 1/3, 0, [], Yes, No, finite-tail-insufficient-for-general-Cauchy)

Enumerate every ordered pair of listed indices at or beyond N. An empty tail passes vacuously. The general_cauchy No means not established by this finite audit, not a proof that every infinite continuation is non-Cauchy. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is ([1/17, 1/18, 1/19, 1/20, 1/21], 1/3, 0, [], Yes, No, finite-tail-insufficient-for-general-Cauchy).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0016/)

Cauchy sequence · qf-mod26-cauchy-finite-tail-audit · candidate





## 17. A Finite Tail Audit Cannot Establish General Cauchy Behavior

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. Recorded rational sequence=[1/18, 1/19, 1/20, 1/21, 1/22], epsilon=1/4, cutoff N=1; only listed zero-based indices are available. Give (normalized sequence,epsilon,N,all bad [m,n,distance] records in ordered-index order,finite_tail_pass?,general Cauchy established by this audit?,finite-tail-insufficient-for-general-Cauchy). A bad distance is at least epsilon. Use exact reduced rational outputs with positive denominators; omit /1 for integers.

View answer and explanation([1/18, 1/19, 1/20, 1/21, 1/22], 1/4, 1, [], Yes, No, finite-tail-insufficient-for-general-Cauchy)

Enumerate every ordered pair of listed indices at or beyond N. An empty tail passes vacuously. The general_cauchy No means not established by this finite audit, not a proof that every infinite continuation is non-Cauchy. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is ([1/18, 1/19, 1/20, 1/21, 1/22], 1/4, 1, [], Yes, No, finite-tail-insufficient-for-general-Cauchy).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0017/)

Cauchy sequence · qf-mod26-cauchy-finite-tail-audit · candidate





## 18. A Finite Tail Audit Cannot Establish General Cauchy Behavior

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. Recorded rational sequence=[1/19, 1/20, 1/21, 1/22, 1/23], epsilon=1/5, cutoff N=2; only listed zero-based indices are available. Give (normalized sequence,epsilon,N,all bad [m,n,distance] records in ordered-index order,finite_tail_pass?,general Cauchy established by this audit?,finite-tail-insufficient-for-general-Cauchy). A bad distance is at least epsilon. Use exact reduced rational outputs with positive denominators; omit /1 for integers.

View answer and explanation([1/19, 1/20, 1/21, 1/22, 1/23], 1/5, 2, [], Yes, No, finite-tail-insufficient-for-general-Cauchy)

Enumerate every ordered pair of listed indices at or beyond N. An empty tail passes vacuously. The general_cauchy No means not established by this finite audit, not a proof that every infinite continuation is non-Cauchy. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is ([1/19, 1/20, 1/21, 1/22, 1/23], 1/5, 2, [], Yes, No, finite-tail-insufficient-for-general-Cauchy).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0018/)

Cauchy sequence · qf-mod26-cauchy-finite-tail-audit · candidate





## 19. A Finite Tail Audit Cannot Establish General Cauchy Behavior

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. Recorded rational sequence=[1/20, 1/21, 1/22, 1/23, 1/24], epsilon=1/6, cutoff N=0; only listed zero-based indices are available. Give (normalized sequence,epsilon,N,all bad [m,n,distance] records in ordered-index order,finite_tail_pass?,general Cauchy established by this audit?,finite-tail-insufficient-for-general-Cauchy). A bad distance is at least epsilon. Use exact reduced rational outputs with positive denominators; omit /1 for integers.

View answer and explanation([1/20, 1/21, 1/22, 1/23, 1/24], 1/6, 0, [], Yes, No, finite-tail-insufficient-for-general-Cauchy)

Enumerate every ordered pair of listed indices at or beyond N. An empty tail passes vacuously. The general_cauchy No means not established by this finite audit, not a proof that every infinite continuation is non-Cauchy. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is ([1/20, 1/21, 1/22, 1/23, 1/24], 1/6, 0, [], Yes, No, finite-tail-insufficient-for-general-Cauchy).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0019/)

Cauchy sequence · qf-mod26-cauchy-finite-tail-audit · candidate





## 20. A Finite Tail Audit Cannot Establish General Cauchy Behavior

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. Recorded rational sequence=[1/21, 1/22, 1/23, 1/24, 1/25], epsilon=1/7, cutoff N=1; only listed zero-based indices are available. Give (normalized sequence,epsilon,N,all bad [m,n,distance] records in ordered-index order,finite_tail_pass?,general Cauchy established by this audit?,finite-tail-insufficient-for-general-Cauchy). A bad distance is at least epsilon. Use exact reduced rational outputs with positive denominators; omit /1 for integers.

View answer and explanation([1/21, 1/22, 1/23, 1/24, 1/25], 1/7, 1, [], Yes, No, finite-tail-insufficient-for-general-Cauchy)

Enumerate every ordered pair of listed indices at or beyond N. An empty tail passes vacuously. The general_cauchy No means not established by this finite audit, not a proof that every infinite continuation is non-Cauchy. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is ([1/21, 1/22, 1/23, 1/24, 1/25], 1/7, 1, [], Yes, No, finite-tail-insufficient-for-general-Cauchy).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0020/)

Cauchy sequence · qf-mod26-cauchy-finite-tail-audit · candidate





## 21. A Finite Tail Audit Cannot Establish General Cauchy Behavior

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. Recorded rational sequence=[1/22, 1/23, 1/24, 1/25, 1/26], epsilon=1/3, cutoff N=2; only listed zero-based indices are available. Give (normalized sequence,epsilon,N,all bad [m,n,distance] records in ordered-index order,finite_tail_pass?,general Cauchy established by this audit?,finite-tail-insufficient-for-general-Cauchy). A bad distance is at least epsilon. Use exact reduced rational outputs with positive denominators; omit /1 for integers.

View answer and explanation([1/22, 1/23, 1/24, 1/25, 1/26], 1/3, 2, [], Yes, No, finite-tail-insufficient-for-general-Cauchy)

Enumerate every ordered pair of listed indices at or beyond N. An empty tail passes vacuously. The general_cauchy No means not established by this finite audit, not a proof that every infinite continuation is non-Cauchy. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is ([1/22, 1/23, 1/24, 1/25, 1/26], 1/3, 2, [], Yes, No, finite-tail-insufficient-for-general-Cauchy).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0021/)

Cauchy sequence · qf-mod26-cauchy-finite-tail-audit · candidate





## 22. A Finite Tail Audit Cannot Establish General Cauchy Behavior

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. Recorded rational sequence=[1/23, 1/24, 1/25, 1/26, 1/27], epsilon=1/4, cutoff N=0; only listed zero-based indices are available. Give (normalized sequence,epsilon,N,all bad [m,n,distance] records in ordered-index order,finite_tail_pass?,general Cauchy established by this audit?,finite-tail-insufficient-for-general-Cauchy). A bad distance is at least epsilon. Use exact reduced rational outputs with positive denominators; omit /1 for integers.

View answer and explanation([1/23, 1/24, 1/25, 1/26, 1/27], 1/4, 0, [], Yes, No, finite-tail-insufficient-for-general-Cauchy)

Enumerate every ordered pair of listed indices at or beyond N. An empty tail passes vacuously. The general_cauchy No means not established by this finite audit, not a proof that every infinite continuation is non-Cauchy. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is ([1/23, 1/24, 1/25, 1/26, 1/27], 1/4, 0, [], Yes, No, finite-tail-insufficient-for-general-Cauchy).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0022/)

Cauchy sequence · qf-mod26-cauchy-finite-tail-audit · candidate





## 23. A Finite Tail Audit Cannot Establish General Cauchy Behavior

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. Recorded rational sequence=[1/24, 1/25, 1/26, 1/27, 1/28], epsilon=1/5, cutoff N=1; only listed zero-based indices are available. Give (normalized sequence,epsilon,N,all bad [m,n,distance] records in ordered-index order,finite_tail_pass?,general Cauchy established by this audit?,finite-tail-insufficient-for-general-Cauchy). A bad distance is at least epsilon. Use exact reduced rational outputs with positive denominators; omit /1 for integers.

View answer and explanation([1/24, 1/25, 1/26, 1/27, 1/28], 1/5, 1, [], Yes, No, finite-tail-insufficient-for-general-Cauchy)

Enumerate every ordered pair of listed indices at or beyond N. An empty tail passes vacuously. The general_cauchy No means not established by this finite audit, not a proof that every infinite continuation is non-Cauchy. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is ([1/24, 1/25, 1/26, 1/27, 1/28], 1/5, 1, [], Yes, No, finite-tail-insufficient-for-general-Cauchy).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0023/)

Cauchy sequence · qf-mod26-cauchy-finite-tail-audit · candidate





## 24. A Finite Tail Audit Cannot Establish General Cauchy Behavior

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. Recorded rational sequence=[1/25, 1/26, 1/27, 1/28, 1/29], epsilon=1/6, cutoff N=2; only listed zero-based indices are available. Give (normalized sequence,epsilon,N,all bad [m,n,distance] records in ordered-index order,finite_tail_pass?,general Cauchy established by this audit?,finite-tail-insufficient-for-general-Cauchy). A bad distance is at least epsilon. Use exact reduced rational outputs with positive denominators; omit /1 for integers.

View answer and explanation([1/25, 1/26, 1/27, 1/28, 1/29], 1/6, 2, [], Yes, No, finite-tail-insufficient-for-general-Cauchy)

Enumerate every ordered pair of listed indices at or beyond N. An empty tail passes vacuously. The general_cauchy No means not established by this finite audit, not a proof that every infinite continuation is non-Cauchy. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is ([1/25, 1/26, 1/27, 1/28, 1/29], 1/6, 2, [], Yes, No, finite-tail-insufficient-for-general-Cauchy).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0024/)

Cauchy sequence · qf-mod26-cauchy-finite-tail-audit · candidate





## 25. A Finite Tail Audit Cannot Establish General Cauchy Behavior

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. Recorded rational sequence=[1/26, 1/27, 1/28, 1/29, 1/30], epsilon=1/7, cutoff N=0; only listed zero-based indices are available. Give (normalized sequence,epsilon,N,all bad [m,n,distance] records in ordered-index order,finite_tail_pass?,general Cauchy established by this audit?,finite-tail-insufficient-for-general-Cauchy). A bad distance is at least epsilon. Use exact reduced rational outputs with positive denominators; omit /1 for integers.

View answer and explanation([1/26, 1/27, 1/28, 1/29, 1/30], 1/7, 0, [], Yes, No, finite-tail-insufficient-for-general-Cauchy)

Enumerate every ordered pair of listed indices at or beyond N. An empty tail passes vacuously. The general_cauchy No means not established by this finite audit, not a proof that every infinite continuation is non-Cauchy. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is ([1/26, 1/27, 1/28, 1/29, 1/30], 1/7, 0, [], Yes, No, finite-tail-insufficient-for-general-Cauchy).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0025/)

Cauchy sequence · qf-mod26-cauchy-finite-tail-audit · candidate





## 26. An Explicit Infinite Constant Tail Supplies a Cauchy Witness

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. The infinite real sequence has finite prefix=[-12/1, 1/2, -3/1] followed forever by tail=-5/1. Give (normalized prefix,tail,N,witness,cauchy?). Use exact reduced rational outputs with positive denominators; omit /1 for integers.

View answer and explanation([-12, 1/2, -3], -5, 3, for any epsilon>0 choose N=prefix length, Yes)

For any positive epsilon choose N equal to the prefix length. Every pair of terms at or beyond N is identical, so its distance is zero. This uses the declared infinite model rather than a finite sample. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is ([-12, 1/2, -3], -5, 3, for any epsilon>0 choose N=prefix length, Yes).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0026/)

Cauchy sequence · qf-mod26-cauchy-ultimately-constant-certificate · candidate





## 27. An Explicit Infinite Constant Tail Supplies a Cauchy Witness

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. The infinite real sequence has finite prefix=[-11/1, 2/2, -2/2] followed forever by tail=-4/2. Give (normalized prefix,tail,N,witness,cauchy?). Use exact reduced rational outputs with positive denominators; omit /1 for integers.

View answer and explanation([-11, 1, -1], -2, 3, for any epsilon>0 choose N=prefix length, Yes)

For any positive epsilon choose N equal to the prefix length. Every pair of terms at or beyond N is identical, so its distance is zero. This uses the declared infinite model rather than a finite sample. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is ([-11, 1, -1], -2, 3, for any epsilon>0 choose N=prefix length, Yes).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0027/)

Cauchy sequence · qf-mod26-cauchy-ultimately-constant-certificate · candidate





## 28. An Explicit Infinite Constant Tail Supplies a Cauchy Witness

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. The infinite real sequence has finite prefix=[-10/1, 3/2, -1/3] followed forever by tail=-3/3. Give (normalized prefix,tail,N,witness,cauchy?). Use exact reduced rational outputs with positive denominators; omit /1 for integers.

View answer and explanation([-10, 3/2, -1/3], -1, 3, for any epsilon>0 choose N=prefix length, Yes)

For any positive epsilon choose N equal to the prefix length. Every pair of terms at or beyond N is identical, so its distance is zero. This uses the declared infinite model rather than a finite sample. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is ([-10, 3/2, -1/3], -1, 3, for any epsilon>0 choose N=prefix length, Yes).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0028/)

Cauchy sequence · qf-mod26-cauchy-ultimately-constant-certificate · candidate





## 29. An Explicit Infinite Constant Tail Supplies a Cauchy Witness

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. The infinite real sequence has finite prefix=[-9/1, 4/2, 0/4] followed forever by tail=-2/4. Give (normalized prefix,tail,N,witness,cauchy?). Use exact reduced rational outputs with positive denominators; omit /1 for integers.

View answer and explanation([-9, 2, 0], -1/2, 3, for any epsilon>0 choose N=prefix length, Yes)

For any positive epsilon choose N equal to the prefix length. Every pair of terms at or beyond N is identical, so its distance is zero. This uses the declared infinite model rather than a finite sample. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is ([-9, 2, 0], -1/2, 3, for any epsilon>0 choose N=prefix length, Yes).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0029/)

Cauchy sequence · qf-mod26-cauchy-ultimately-constant-certificate · candidate





## 30. An Explicit Infinite Constant Tail Supplies a Cauchy Witness

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. The infinite real sequence has finite prefix=[-8/1, 5/2, 1/5] followed forever by tail=-1/5. Give (normalized prefix,tail,N,witness,cauchy?). Use exact reduced rational outputs with positive denominators; omit /1 for integers.

View answer and explanation([-8, 5/2, 1/5], -1/5, 3, for any epsilon>0 choose N=prefix length, Yes)

For any positive epsilon choose N equal to the prefix length. Every pair of terms at or beyond N is identical, so its distance is zero. This uses the declared infinite model rather than a finite sample. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is ([-8, 5/2, 1/5], -1/5, 3, for any epsilon>0 choose N=prefix length, Yes).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0030/)

Cauchy sequence · qf-mod26-cauchy-ultimately-constant-certificate · candidate





## 31. An Explicit Infinite Constant Tail Supplies a Cauchy Witness

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. The infinite real sequence has finite prefix=[-7/1, 6/2, 2/1] followed forever by tail=0/6. Give (normalized prefix,tail,N,witness,cauchy?). Use exact reduced rational outputs with positive denominators; omit /1 for integers.

View answer and explanation([-7, 3, 2], 0, 3, for any epsilon>0 choose N=prefix length, Yes)

For any positive epsilon choose N equal to the prefix length. Every pair of terms at or beyond N is identical, so its distance is zero. This uses the declared infinite model rather than a finite sample. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is ([-7, 3, 2], 0, 3, for any epsilon>0 choose N=prefix length, Yes).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0031/)

Cauchy sequence · qf-mod26-cauchy-ultimately-constant-certificate · candidate





## 32. An Explicit Infinite Constant Tail Supplies a Cauchy Witness

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. The infinite real sequence has finite prefix=[-6/1, 7/2, 3/2] followed forever by tail=1/7. Give (normalized prefix,tail,N,witness,cauchy?). Use exact reduced rational outputs with positive denominators; omit /1 for integers.

View answer and explanation([-6, 7/2, 3/2], 1/7, 3, for any epsilon>0 choose N=prefix length, Yes)

For any positive epsilon choose N equal to the prefix length. Every pair of terms at or beyond N is identical, so its distance is zero. This uses the declared infinite model rather than a finite sample. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is ([-6, 7/2, 3/2], 1/7, 3, for any epsilon>0 choose N=prefix length, Yes).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0032/)

Cauchy sequence · qf-mod26-cauchy-ultimately-constant-certificate · candidate





## 33. An Explicit Infinite Constant Tail Supplies a Cauchy Witness

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. The infinite real sequence has finite prefix=[-5/1, 8/2, -3/3] followed forever by tail=2/1. Give (normalized prefix,tail,N,witness,cauchy?). Use exact reduced rational outputs with positive denominators; omit /1 for integers.

View answer and explanation([-5, 4, -1], 2, 3, for any epsilon>0 choose N=prefix length, Yes)

For any positive epsilon choose N equal to the prefix length. Every pair of terms at or beyond N is identical, so its distance is zero. This uses the declared infinite model rather than a finite sample. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is ([-5, 4, -1], 2, 3, for any epsilon>0 choose N=prefix length, Yes).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0033/)

Cauchy sequence · qf-mod26-cauchy-ultimately-constant-certificate · candidate





## 34. An Explicit Infinite Constant Tail Supplies a Cauchy Witness

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. The infinite real sequence has finite prefix=[-4/1, 9/2, -2/4] followed forever by tail=3/2. Give (normalized prefix,tail,N,witness,cauchy?). Use exact reduced rational outputs with positive denominators; omit /1 for integers.

View answer and explanation([-4, 9/2, -1/2], 3/2, 3, for any epsilon>0 choose N=prefix length, Yes)

For any positive epsilon choose N equal to the prefix length. Every pair of terms at or beyond N is identical, so its distance is zero. This uses the declared infinite model rather than a finite sample. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is ([-4, 9/2, -1/2], 3/2, 3, for any epsilon>0 choose N=prefix length, Yes).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0034/)

Cauchy sequence · qf-mod26-cauchy-ultimately-constant-certificate · candidate





## 35. An Explicit Infinite Constant Tail Supplies a Cauchy Witness

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. The infinite real sequence has finite prefix=[-3/1, 10/2, -1/5] followed forever by tail=4/3. Give (normalized prefix,tail,N,witness,cauchy?). Use exact reduced rational outputs with positive denominators; omit /1 for integers.

View answer and explanation([-3, 5, -1/5], 4/3, 3, for any epsilon>0 choose N=prefix length, Yes)

For any positive epsilon choose N equal to the prefix length. Every pair of terms at or beyond N is identical, so its distance is zero. This uses the declared infinite model rather than a finite sample. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is ([-3, 5, -1/5], 4/3, 3, for any epsilon>0 choose N=prefix length, Yes).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0035/)

Cauchy sequence · qf-mod26-cauchy-ultimately-constant-certificate · candidate





## 36. An Explicit Infinite Constant Tail Supplies a Cauchy Witness

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. The infinite real sequence has finite prefix=[-2/1, 11/2, 0/1] followed forever by tail=5/4. Give (normalized prefix,tail,N,witness,cauchy?). Use exact reduced rational outputs with positive denominators; omit /1 for integers.

View answer and explanation([-2, 11/2, 0], 5/4, 3, for any epsilon>0 choose N=prefix length, Yes)

For any positive epsilon choose N equal to the prefix length. Every pair of terms at or beyond N is identical, so its distance is zero. This uses the declared infinite model rather than a finite sample. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is ([-2, 11/2, 0], 5/4, 3, for any epsilon>0 choose N=prefix length, Yes).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0036/)

Cauchy sequence · qf-mod26-cauchy-ultimately-constant-certificate · candidate





## 37. An Explicit Infinite Constant Tail Supplies a Cauchy Witness

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. The infinite real sequence has finite prefix=[-1/1, 12/2, 1/2] followed forever by tail=-5/5. Give (normalized prefix,tail,N,witness,cauchy?). Use exact reduced rational outputs with positive denominators; omit /1 for integers.

View answer and explanation([-1, 6, 1/2], -1, 3, for any epsilon>0 choose N=prefix length, Yes)

For any positive epsilon choose N equal to the prefix length. Every pair of terms at or beyond N is identical, so its distance is zero. This uses the declared infinite model rather than a finite sample. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is ([-1, 6, 1/2], -1, 3, for any epsilon>0 choose N=prefix length, Yes).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0037/)

Cauchy sequence · qf-mod26-cauchy-ultimately-constant-certificate · candidate





## 38. An Explicit Infinite Constant Tail Supplies a Cauchy Witness

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. The infinite real sequence has finite prefix=[0/1, 13/2, 2/3] followed forever by tail=-4/6. Give (normalized prefix,tail,N,witness,cauchy?). Use exact reduced rational outputs with positive denominators; omit /1 for integers.

View answer and explanation([0, 13/2, 2/3], -2/3, 3, for any epsilon>0 choose N=prefix length, Yes)

For any positive epsilon choose N equal to the prefix length. Every pair of terms at or beyond N is identical, so its distance is zero. This uses the declared infinite model rather than a finite sample. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is ([0, 13/2, 2/3], -2/3, 3, for any epsilon>0 choose N=prefix length, Yes).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0038/)

Cauchy sequence · qf-mod26-cauchy-ultimately-constant-certificate · candidate





## 39. An Explicit Infinite Constant Tail Supplies a Cauchy Witness

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. The infinite real sequence has finite prefix=[1/1, 14/2, 3/4] followed forever by tail=-3/7. Give (normalized prefix,tail,N,witness,cauchy?). Use exact reduced rational outputs with positive denominators; omit /1 for integers.

View answer and explanation([1, 7, 3/4], -3/7, 3, for any epsilon>0 choose N=prefix length, Yes)

For any positive epsilon choose N equal to the prefix length. Every pair of terms at or beyond N is identical, so its distance is zero. This uses the declared infinite model rather than a finite sample. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is ([1, 7, 3/4], -3/7, 3, for any epsilon>0 choose N=prefix length, Yes).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0039/)

Cauchy sequence · qf-mod26-cauchy-ultimately-constant-certificate · candidate





## 40. An Explicit Infinite Constant Tail Supplies a Cauchy Witness

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. The infinite real sequence has finite prefix=[2/1, 15/2, -3/5] followed forever by tail=-2/1. Give (normalized prefix,tail,N,witness,cauchy?). Use exact reduced rational outputs with positive denominators; omit /1 for integers.

View answer and explanation([2, 15/2, -3/5], -2, 3, for any epsilon>0 choose N=prefix length, Yes)

For any positive epsilon choose N equal to the prefix length. Every pair of terms at or beyond N is identical, so its distance is zero. This uses the declared infinite model rather than a finite sample. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is ([2, 15/2, -3/5], -2, 3, for any epsilon>0 choose N=prefix length, Yes).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0040/)

Cauchy sequence · qf-mod26-cauchy-ultimately-constant-certificate · candidate





## 41. An Explicit Infinite Constant Tail Supplies a Cauchy Witness

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. The infinite real sequence has finite prefix=[3/1, 16/2, -2/1] followed forever by tail=-1/2. Give (normalized prefix,tail,N,witness,cauchy?). Use exact reduced rational outputs with positive denominators; omit /1 for integers.

View answer and explanation([3, 8, -2], -1/2, 3, for any epsilon>0 choose N=prefix length, Yes)

For any positive epsilon choose N equal to the prefix length. Every pair of terms at or beyond N is identical, so its distance is zero. This uses the declared infinite model rather than a finite sample. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is ([3, 8, -2], -1/2, 3, for any epsilon>0 choose N=prefix length, Yes).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0041/)

Cauchy sequence · qf-mod26-cauchy-ultimately-constant-certificate · candidate





## 42. An Explicit Infinite Constant Tail Supplies a Cauchy Witness

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. The infinite real sequence has finite prefix=[4/1, 17/2, -1/2] followed forever by tail=0/3. Give (normalized prefix,tail,N,witness,cauchy?). Use exact reduced rational outputs with positive denominators; omit /1 for integers.

View answer and explanation([4, 17/2, -1/2], 0, 3, for any epsilon>0 choose N=prefix length, Yes)

For any positive epsilon choose N equal to the prefix length. Every pair of terms at or beyond N is identical, so its distance is zero. This uses the declared infinite model rather than a finite sample. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is ([4, 17/2, -1/2], 0, 3, for any epsilon>0 choose N=prefix length, Yes).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0042/)

Cauchy sequence · qf-mod26-cauchy-ultimately-constant-certificate · candidate





## 43. An Explicit Infinite Constant Tail Supplies a Cauchy Witness

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. The infinite real sequence has finite prefix=[5/1, 18/2, 0/3] followed forever by tail=1/4. Give (normalized prefix,tail,N,witness,cauchy?). Use exact reduced rational outputs with positive denominators; omit /1 for integers.

View answer and explanation([5, 9, 0], 1/4, 3, for any epsilon>0 choose N=prefix length, Yes)

For any positive epsilon choose N equal to the prefix length. Every pair of terms at or beyond N is identical, so its distance is zero. This uses the declared infinite model rather than a finite sample. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is ([5, 9, 0], 1/4, 3, for any epsilon>0 choose N=prefix length, Yes).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0043/)

Cauchy sequence · qf-mod26-cauchy-ultimately-constant-certificate · candidate





## 44. An Explicit Infinite Constant Tail Supplies a Cauchy Witness

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. The infinite real sequence has finite prefix=[6/1, 19/2, 1/4] followed forever by tail=2/5. Give (normalized prefix,tail,N,witness,cauchy?). Use exact reduced rational outputs with positive denominators; omit /1 for integers.

View answer and explanation([6, 19/2, 1/4], 2/5, 3, for any epsilon>0 choose N=prefix length, Yes)

For any positive epsilon choose N equal to the prefix length. Every pair of terms at or beyond N is identical, so its distance is zero. This uses the declared infinite model rather than a finite sample. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is ([6, 19/2, 1/4], 2/5, 3, for any epsilon>0 choose N=prefix length, Yes).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0044/)

Cauchy sequence · qf-mod26-cauchy-ultimately-constant-certificate · candidate





## 45. An Explicit Infinite Constant Tail Supplies a Cauchy Witness

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. The infinite real sequence has finite prefix=[7/1, 20/2, 2/5] followed forever by tail=3/6. Give (normalized prefix,tail,N,witness,cauchy?). Use exact reduced rational outputs with positive denominators; omit /1 for integers.

View answer and explanation([7, 10, 2/5], 1/2, 3, for any epsilon>0 choose N=prefix length, Yes)

For any positive epsilon choose N equal to the prefix length. Every pair of terms at or beyond N is identical, so its distance is zero. This uses the declared infinite model rather than a finite sample. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is ([7, 10, 2/5], 1/2, 3, for any epsilon>0 choose N=prefix length, Yes).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0045/)

Cauchy sequence · qf-mod26-cauchy-ultimately-constant-certificate · candidate





## 46. An Explicit Infinite Constant Tail Supplies a Cauchy Witness

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. The infinite real sequence has finite prefix=[8/1, 21/2, 3/1] followed forever by tail=4/7. Give (normalized prefix,tail,N,witness,cauchy?). Use exact reduced rational outputs with positive denominators; omit /1 for integers.

View answer and explanation([8, 21/2, 3], 4/7, 3, for any epsilon>0 choose N=prefix length, Yes)

For any positive epsilon choose N equal to the prefix length. Every pair of terms at or beyond N is identical, so its distance is zero. This uses the declared infinite model rather than a finite sample. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is ([8, 21/2, 3], 4/7, 3, for any epsilon>0 choose N=prefix length, Yes).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0046/)

Cauchy sequence · qf-mod26-cauchy-ultimately-constant-certificate · candidate





## 47. An Explicit Infinite Constant Tail Supplies a Cauchy Witness

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. The infinite real sequence has finite prefix=[9/1, 22/2, -3/2] followed forever by tail=5/1. Give (normalized prefix,tail,N,witness,cauchy?). Use exact reduced rational outputs with positive denominators; omit /1 for integers.

View answer and explanation([9, 11, -3/2], 5, 3, for any epsilon>0 choose N=prefix length, Yes)

For any positive epsilon choose N equal to the prefix length. Every pair of terms at or beyond N is identical, so its distance is zero. This uses the declared infinite model rather than a finite sample. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is ([9, 11, -3/2], 5, 3, for any epsilon>0 choose N=prefix length, Yes).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0047/)

Cauchy sequence · qf-mod26-cauchy-ultimately-constant-certificate · candidate





## 48. An Explicit Infinite Constant Tail Supplies a Cauchy Witness

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. The infinite real sequence has finite prefix=[10/1, 23/2, -2/3] followed forever by tail=-5/2. Give (normalized prefix,tail,N,witness,cauchy?). Use exact reduced rational outputs with positive denominators; omit /1 for integers.

View answer and explanation([10, 23/2, -2/3], -5/2, 3, for any epsilon>0 choose N=prefix length, Yes)

For any positive epsilon choose N equal to the prefix length. Every pair of terms at or beyond N is identical, so its distance is zero. This uses the declared infinite model rather than a finite sample. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is ([10, 23/2, -2/3], -5/2, 3, for any epsilon>0 choose N=prefix length, Yes).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0048/)

Cauchy sequence · qf-mod26-cauchy-ultimately-constant-certificate · candidate





## 49. An Explicit Infinite Constant Tail Supplies a Cauchy Witness

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. The infinite real sequence has finite prefix=[11/1, 24/2, -1/4] followed forever by tail=-4/3. Give (normalized prefix,tail,N,witness,cauchy?). Use exact reduced rational outputs with positive denominators; omit /1 for integers.

View answer and explanation([11, 12, -1/4], -4/3, 3, for any epsilon>0 choose N=prefix length, Yes)

For any positive epsilon choose N equal to the prefix length. Every pair of terms at or beyond N is identical, so its distance is zero. This uses the declared infinite model rather than a finite sample. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is ([11, 12, -1/4], -4/3, 3, for any epsilon>0 choose N=prefix length, Yes).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0049/)

Cauchy sequence · qf-mod26-cauchy-ultimately-constant-certificate · candidate





## 50. An Explicit Infinite Constant Tail Supplies a Cauchy Witness

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. The infinite real sequence has finite prefix=[12/1, 25/2, 0/5] followed forever by tail=-3/4. Give (normalized prefix,tail,N,witness,cauchy?). Use exact reduced rational outputs with positive denominators; omit /1 for integers.

View answer and explanation([12, 25/2, 0], -3/4, 3, for any epsilon>0 choose N=prefix length, Yes)

For any positive epsilon choose N equal to the prefix length. Every pair of terms at or beyond N is identical, so its distance is zero. This uses the declared infinite model rather than a finite sample. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is ([12, 25/2, 0], -3/4, 3, for any epsilon>0 choose N=prefix length, Yes).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0050/)

Cauchy sequence · qf-mod26-cauchy-ultimately-constant-certificate · candidate





## 51. A Strict Reciprocal Bound for the Selected Epsilon

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. The infinite model is x_n=1/(n+shift), with shift=1, epsilon=1/3. Give (shift,epsilon,least nonnegative N with 1/(N+shift)<epsilon,bound,m,n>=N implies distance<=1/(N+shift)<epsilon,cauchy_for_epsilon?). Use exact reduced rational outputs with positive denominators; omit /1 for integers.

View answer and explanation(1, 1/3, 3, 1/4, m,n>=N implies distance<=1/(N+shift)<epsilon, Yes)

Retain the strict inequality when choosing N. For every two later indices the reciprocal terms lie between zero and the stated upper bound, so their distance is at most that bound. The output certifies this chosen epsilon and the explicit model, not an arbitrary sequence. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is (1, 1/3, 3, 1/4, m,n>=N implies distance<=1/(N+shift)<epsilon, Yes).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0051/)

Cauchy sequence · qf-mod26-cauchy-reciprocal-epsilon-witness · candidate





## 52. A Strict Reciprocal Bound for the Selected Epsilon

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. The infinite model is x_n=1/(n+shift), with shift=2, epsilon=1/4. Give (shift,epsilon,least nonnegative N with 1/(N+shift)<epsilon,bound,m,n>=N implies distance<=1/(N+shift)<epsilon,cauchy_for_epsilon?). Use exact reduced rational outputs with positive denominators; omit /1 for integers.

View answer and explanation(2, 1/4, 3, 1/5, m,n>=N implies distance<=1/(N+shift)<epsilon, Yes)

Retain the strict inequality when choosing N. For every two later indices the reciprocal terms lie between zero and the stated upper bound, so their distance is at most that bound. The output certifies this chosen epsilon and the explicit model, not an arbitrary sequence. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is (2, 1/4, 3, 1/5, m,n>=N implies distance<=1/(N+shift)<epsilon, Yes).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0052/)

Cauchy sequence · qf-mod26-cauchy-reciprocal-epsilon-witness · candidate





## 53. A Strict Reciprocal Bound for the Selected Epsilon

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. The infinite model is x_n=1/(n+shift), with shift=3, epsilon=1/5. Give (shift,epsilon,least nonnegative N with 1/(N+shift)<epsilon,bound,m,n>=N implies distance<=1/(N+shift)<epsilon,cauchy_for_epsilon?). Use exact reduced rational outputs with positive denominators; omit /1 for integers.

View answer and explanation(3, 1/5, 3, 1/6, m,n>=N implies distance<=1/(N+shift)<epsilon, Yes)

Retain the strict inequality when choosing N. For every two later indices the reciprocal terms lie between zero and the stated upper bound, so their distance is at most that bound. The output certifies this chosen epsilon and the explicit model, not an arbitrary sequence. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is (3, 1/5, 3, 1/6, m,n>=N implies distance<=1/(N+shift)<epsilon, Yes).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0053/)

Cauchy sequence · qf-mod26-cauchy-reciprocal-epsilon-witness · candidate





## 54. A Strict Reciprocal Bound for the Selected Epsilon

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. The infinite model is x_n=1/(n+shift), with shift=4, epsilon=1/6. Give (shift,epsilon,least nonnegative N with 1/(N+shift)<epsilon,bound,m,n>=N implies distance<=1/(N+shift)<epsilon,cauchy_for_epsilon?). Use exact reduced rational outputs with positive denominators; omit /1 for integers.

View answer and explanation(4, 1/6, 3, 1/7, m,n>=N implies distance<=1/(N+shift)<epsilon, Yes)

Retain the strict inequality when choosing N. For every two later indices the reciprocal terms lie between zero and the stated upper bound, so their distance is at most that bound. The output certifies this chosen epsilon and the explicit model, not an arbitrary sequence. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is (4, 1/6, 3, 1/7, m,n>=N implies distance<=1/(N+shift)<epsilon, Yes).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0054/)

Cauchy sequence · qf-mod26-cauchy-reciprocal-epsilon-witness · candidate





## 55. A Strict Reciprocal Bound for the Selected Epsilon

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. The infinite model is x_n=1/(n+shift), with shift=5, epsilon=1/7. Give (shift,epsilon,least nonnegative N with 1/(N+shift)<epsilon,bound,m,n>=N implies distance<=1/(N+shift)<epsilon,cauchy_for_epsilon?). Use exact reduced rational outputs with positive denominators; omit /1 for integers.

View answer and explanation(5, 1/7, 3, 1/8, m,n>=N implies distance<=1/(N+shift)<epsilon, Yes)

Retain the strict inequality when choosing N. For every two later indices the reciprocal terms lie between zero and the stated upper bound, so their distance is at most that bound. The output certifies this chosen epsilon and the explicit model, not an arbitrary sequence. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is (5, 1/7, 3, 1/8, m,n>=N implies distance<=1/(N+shift)<epsilon, Yes).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0055/)

Cauchy sequence · qf-mod26-cauchy-reciprocal-epsilon-witness · candidate





## 56. A Strict Reciprocal Bound for the Selected Epsilon

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. The infinite model is x_n=1/(n+shift), with shift=6, epsilon=1/8. Give (shift,epsilon,least nonnegative N with 1/(N+shift)<epsilon,bound,m,n>=N implies distance<=1/(N+shift)<epsilon,cauchy_for_epsilon?). Use exact reduced rational outputs with positive denominators; omit /1 for integers.

View answer and explanation(6, 1/8, 3, 1/9, m,n>=N implies distance<=1/(N+shift)<epsilon, Yes)

Retain the strict inequality when choosing N. For every two later indices the reciprocal terms lie between zero and the stated upper bound, so their distance is at most that bound. The output certifies this chosen epsilon and the explicit model, not an arbitrary sequence. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is (6, 1/8, 3, 1/9, m,n>=N implies distance<=1/(N+shift)<epsilon, Yes).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0056/)

Cauchy sequence · qf-mod26-cauchy-reciprocal-epsilon-witness · candidate





## 57. A Strict Reciprocal Bound for the Selected Epsilon

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. The infinite model is x_n=1/(n+shift), with shift=7, epsilon=1/9. Give (shift,epsilon,least nonnegative N with 1/(N+shift)<epsilon,bound,m,n>=N implies distance<=1/(N+shift)<epsilon,cauchy_for_epsilon?). Use exact reduced rational outputs with positive denominators; omit /1 for integers.

View answer and explanation(7, 1/9, 3, 1/10, m,n>=N implies distance<=1/(N+shift)<epsilon, Yes)

Retain the strict inequality when choosing N. For every two later indices the reciprocal terms lie between zero and the stated upper bound, so their distance is at most that bound. The output certifies this chosen epsilon and the explicit model, not an arbitrary sequence. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is (7, 1/9, 3, 1/10, m,n>=N implies distance<=1/(N+shift)<epsilon, Yes).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0057/)

Cauchy sequence · qf-mod26-cauchy-reciprocal-epsilon-witness · candidate





## 58. A Strict Reciprocal Bound for the Selected Epsilon

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. The infinite model is x_n=1/(n+shift), with shift=8, epsilon=1/10. Give (shift,epsilon,least nonnegative N with 1/(N+shift)<epsilon,bound,m,n>=N implies distance<=1/(N+shift)<epsilon,cauchy_for_epsilon?). Use exact reduced rational outputs with positive denominators; omit /1 for integers.

View answer and explanation(8, 1/10, 3, 1/11, m,n>=N implies distance<=1/(N+shift)<epsilon, Yes)

Retain the strict inequality when choosing N. For every two later indices the reciprocal terms lie between zero and the stated upper bound, so their distance is at most that bound. The output certifies this chosen epsilon and the explicit model, not an arbitrary sequence. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is (8, 1/10, 3, 1/11, m,n>=N implies distance<=1/(N+shift)<epsilon, Yes).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0058/)

Cauchy sequence · qf-mod26-cauchy-reciprocal-epsilon-witness · candidate





## 59. A Strict Reciprocal Bound for the Selected Epsilon

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. The infinite model is x_n=1/(n+shift), with shift=9, epsilon=1/11. Give (shift,epsilon,least nonnegative N with 1/(N+shift)<epsilon,bound,m,n>=N implies distance<=1/(N+shift)<epsilon,cauchy_for_epsilon?). Use exact reduced rational outputs with positive denominators; omit /1 for integers.

View answer and explanation(9, 1/11, 3, 1/12, m,n>=N implies distance<=1/(N+shift)<epsilon, Yes)

Retain the strict inequality when choosing N. For every two later indices the reciprocal terms lie between zero and the stated upper bound, so their distance is at most that bound. The output certifies this chosen epsilon and the explicit model, not an arbitrary sequence. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is (9, 1/11, 3, 1/12, m,n>=N implies distance<=1/(N+shift)<epsilon, Yes).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0059/)

Cauchy sequence · qf-mod26-cauchy-reciprocal-epsilon-witness · candidate





## 60. A Strict Reciprocal Bound for the Selected Epsilon

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. The infinite model is x_n=1/(n+shift), with shift=10, epsilon=1/12. Give (shift,epsilon,least nonnegative N with 1/(N+shift)<epsilon,bound,m,n>=N implies distance<=1/(N+shift)<epsilon,cauchy_for_epsilon?). Use exact reduced rational outputs with positive denominators; omit /1 for integers.

View answer and explanation(10, 1/12, 3, 1/13, m,n>=N implies distance<=1/(N+shift)<epsilon, Yes)

Retain the strict inequality when choosing N. For every two later indices the reciprocal terms lie between zero and the stated upper bound, so their distance is at most that bound. The output certifies this chosen epsilon and the explicit model, not an arbitrary sequence. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is (10, 1/12, 3, 1/13, m,n>=N implies distance<=1/(N+shift)<epsilon, Yes).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0060/)

Cauchy sequence · qf-mod26-cauchy-reciprocal-epsilon-witness · candidate





## 61. A Strict Reciprocal Bound for the Selected Epsilon

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. The infinite model is x_n=1/(n+shift), with shift=11, epsilon=1/13. Give (shift,epsilon,least nonnegative N with 1/(N+shift)<epsilon,bound,m,n>=N implies distance<=1/(N+shift)<epsilon,cauchy_for_epsilon?). Use exact reduced rational outputs with positive denominators; omit /1 for integers.

View answer and explanation(11, 1/13, 3, 1/14, m,n>=N implies distance<=1/(N+shift)<epsilon, Yes)

Retain the strict inequality when choosing N. For every two later indices the reciprocal terms lie between zero and the stated upper bound, so their distance is at most that bound. The output certifies this chosen epsilon and the explicit model, not an arbitrary sequence. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is (11, 1/13, 3, 1/14, m,n>=N implies distance<=1/(N+shift)<epsilon, Yes).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0061/)

Cauchy sequence · qf-mod26-cauchy-reciprocal-epsilon-witness · candidate





## 62. A Strict Reciprocal Bound for the Selected Epsilon

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. The infinite model is x_n=1/(n+shift), with shift=12, epsilon=1/14. Give (shift,epsilon,least nonnegative N with 1/(N+shift)<epsilon,bound,m,n>=N implies distance<=1/(N+shift)<epsilon,cauchy_for_epsilon?). Use exact reduced rational outputs with positive denominators; omit /1 for integers.

View answer and explanation(12, 1/14, 3, 1/15, m,n>=N implies distance<=1/(N+shift)<epsilon, Yes)

Retain the strict inequality when choosing N. For every two later indices the reciprocal terms lie between zero and the stated upper bound, so their distance is at most that bound. The output certifies this chosen epsilon and the explicit model, not an arbitrary sequence. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is (12, 1/14, 3, 1/15, m,n>=N implies distance<=1/(N+shift)<epsilon, Yes).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0062/)

Cauchy sequence · qf-mod26-cauchy-reciprocal-epsilon-witness · candidate





## 63. A Strict Reciprocal Bound for the Selected Epsilon

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. The infinite model is x_n=1/(n+shift), with shift=13, epsilon=1/15. Give (shift,epsilon,least nonnegative N with 1/(N+shift)<epsilon,bound,m,n>=N implies distance<=1/(N+shift)<epsilon,cauchy_for_epsilon?). Use exact reduced rational outputs with positive denominators; omit /1 for integers.

View answer and explanation(13, 1/15, 3, 1/16, m,n>=N implies distance<=1/(N+shift)<epsilon, Yes)

Retain the strict inequality when choosing N. For every two later indices the reciprocal terms lie between zero and the stated upper bound, so their distance is at most that bound. The output certifies this chosen epsilon and the explicit model, not an arbitrary sequence. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is (13, 1/15, 3, 1/16, m,n>=N implies distance<=1/(N+shift)<epsilon, Yes).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0063/)

Cauchy sequence · qf-mod26-cauchy-reciprocal-epsilon-witness · candidate





## 64. A Strict Reciprocal Bound for the Selected Epsilon

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. The infinite model is x_n=1/(n+shift), with shift=14, epsilon=1/16. Give (shift,epsilon,least nonnegative N with 1/(N+shift)<epsilon,bound,m,n>=N implies distance<=1/(N+shift)<epsilon,cauchy_for_epsilon?). Use exact reduced rational outputs with positive denominators; omit /1 for integers.

View answer and explanation(14, 1/16, 3, 1/17, m,n>=N implies distance<=1/(N+shift)<epsilon, Yes)

Retain the strict inequality when choosing N. For every two later indices the reciprocal terms lie between zero and the stated upper bound, so their distance is at most that bound. The output certifies this chosen epsilon and the explicit model, not an arbitrary sequence. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is (14, 1/16, 3, 1/17, m,n>=N implies distance<=1/(N+shift)<epsilon, Yes).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0064/)

Cauchy sequence · qf-mod26-cauchy-reciprocal-epsilon-witness · candidate





## 65. A Strict Reciprocal Bound for the Selected Epsilon

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. The infinite model is x_n=1/(n+shift), with shift=15, epsilon=1/17. Give (shift,epsilon,least nonnegative N with 1/(N+shift)<epsilon,bound,m,n>=N implies distance<=1/(N+shift)<epsilon,cauchy_for_epsilon?). Use exact reduced rational outputs with positive denominators; omit /1 for integers.

View answer and explanation(15, 1/17, 3, 1/18, m,n>=N implies distance<=1/(N+shift)<epsilon, Yes)

Retain the strict inequality when choosing N. For every two later indices the reciprocal terms lie between zero and the stated upper bound, so their distance is at most that bound. The output certifies this chosen epsilon and the explicit model, not an arbitrary sequence. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is (15, 1/17, 3, 1/18, m,n>=N implies distance<=1/(N+shift)<epsilon, Yes).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0065/)

Cauchy sequence · qf-mod26-cauchy-reciprocal-epsilon-witness · candidate





## 66. A Strict Reciprocal Bound for the Selected Epsilon

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. The infinite model is x_n=1/(n+shift), with shift=16, epsilon=1/18. Give (shift,epsilon,least nonnegative N with 1/(N+shift)<epsilon,bound,m,n>=N implies distance<=1/(N+shift)<epsilon,cauchy_for_epsilon?). Use exact reduced rational outputs with positive denominators; omit /1 for integers.

View answer and explanation(16, 1/18, 3, 1/19, m,n>=N implies distance<=1/(N+shift)<epsilon, Yes)

Retain the strict inequality when choosing N. For every two later indices the reciprocal terms lie between zero and the stated upper bound, so their distance is at most that bound. The output certifies this chosen epsilon and the explicit model, not an arbitrary sequence. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is (16, 1/18, 3, 1/19, m,n>=N implies distance<=1/(N+shift)<epsilon, Yes).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0066/)

Cauchy sequence · qf-mod26-cauchy-reciprocal-epsilon-witness · candidate





## 67. A Strict Reciprocal Bound for the Selected Epsilon

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. The infinite model is x_n=1/(n+shift), with shift=17, epsilon=1/19. Give (shift,epsilon,least nonnegative N with 1/(N+shift)<epsilon,bound,m,n>=N implies distance<=1/(N+shift)<epsilon,cauchy_for_epsilon?). Use exact reduced rational outputs with positive denominators; omit /1 for integers.

View answer and explanation(17, 1/19, 3, 1/20, m,n>=N implies distance<=1/(N+shift)<epsilon, Yes)

Retain the strict inequality when choosing N. For every two later indices the reciprocal terms lie between zero and the stated upper bound, so their distance is at most that bound. The output certifies this chosen epsilon and the explicit model, not an arbitrary sequence. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is (17, 1/19, 3, 1/20, m,n>=N implies distance<=1/(N+shift)<epsilon, Yes).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0067/)

Cauchy sequence · qf-mod26-cauchy-reciprocal-epsilon-witness · candidate





## 68. A Strict Reciprocal Bound for the Selected Epsilon

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. The infinite model is x_n=1/(n+shift), with shift=18, epsilon=1/20. Give (shift,epsilon,least nonnegative N with 1/(N+shift)<epsilon,bound,m,n>=N implies distance<=1/(N+shift)<epsilon,cauchy_for_epsilon?). Use exact reduced rational outputs with positive denominators; omit /1 for integers.

View answer and explanation(18, 1/20, 3, 1/21, m,n>=N implies distance<=1/(N+shift)<epsilon, Yes)

Retain the strict inequality when choosing N. For every two later indices the reciprocal terms lie between zero and the stated upper bound, so their distance is at most that bound. The output certifies this chosen epsilon and the explicit model, not an arbitrary sequence. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is (18, 1/20, 3, 1/21, m,n>=N implies distance<=1/(N+shift)<epsilon, Yes).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0068/)

Cauchy sequence · qf-mod26-cauchy-reciprocal-epsilon-witness · candidate





## 69. A Strict Reciprocal Bound for the Selected Epsilon

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. The infinite model is x_n=1/(n+shift), with shift=19, epsilon=1/21. Give (shift,epsilon,least nonnegative N with 1/(N+shift)<epsilon,bound,m,n>=N implies distance<=1/(N+shift)<epsilon,cauchy_for_epsilon?). Use exact reduced rational outputs with positive denominators; omit /1 for integers.

View answer and explanation(19, 1/21, 3, 1/22, m,n>=N implies distance<=1/(N+shift)<epsilon, Yes)

Retain the strict inequality when choosing N. For every two later indices the reciprocal terms lie between zero and the stated upper bound, so their distance is at most that bound. The output certifies this chosen epsilon and the explicit model, not an arbitrary sequence. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is (19, 1/21, 3, 1/22, m,n>=N implies distance<=1/(N+shift)<epsilon, Yes).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0069/)

Cauchy sequence · qf-mod26-cauchy-reciprocal-epsilon-witness · candidate





## 70. A Strict Reciprocal Bound for the Selected Epsilon

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. The infinite model is x_n=1/(n+shift), with shift=20, epsilon=1/22. Give (shift,epsilon,least nonnegative N with 1/(N+shift)<epsilon,bound,m,n>=N implies distance<=1/(N+shift)<epsilon,cauchy_for_epsilon?). Use exact reduced rational outputs with positive denominators; omit /1 for integers.

View answer and explanation(20, 1/22, 3, 1/23, m,n>=N implies distance<=1/(N+shift)<epsilon, Yes)

Retain the strict inequality when choosing N. For every two later indices the reciprocal terms lie between zero and the stated upper bound, so their distance is at most that bound. The output certifies this chosen epsilon and the explicit model, not an arbitrary sequence. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is (20, 1/22, 3, 1/23, m,n>=N implies distance<=1/(N+shift)<epsilon, Yes).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0070/)

Cauchy sequence · qf-mod26-cauchy-reciprocal-epsilon-witness · candidate





## 71. A Strict Reciprocal Bound for the Selected Epsilon

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. The infinite model is x_n=1/(n+shift), with shift=21, epsilon=1/23. Give (shift,epsilon,least nonnegative N with 1/(N+shift)<epsilon,bound,m,n>=N implies distance<=1/(N+shift)<epsilon,cauchy_for_epsilon?). Use exact reduced rational outputs with positive denominators; omit /1 for integers.

View answer and explanation(21, 1/23, 3, 1/24, m,n>=N implies distance<=1/(N+shift)<epsilon, Yes)

Retain the strict inequality when choosing N. For every two later indices the reciprocal terms lie between zero and the stated upper bound, so their distance is at most that bound. The output certifies this chosen epsilon and the explicit model, not an arbitrary sequence. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is (21, 1/23, 3, 1/24, m,n>=N implies distance<=1/(N+shift)<epsilon, Yes).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0071/)

Cauchy sequence · qf-mod26-cauchy-reciprocal-epsilon-witness · candidate





## 72. A Strict Reciprocal Bound for the Selected Epsilon

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. The infinite model is x_n=1/(n+shift), with shift=22, epsilon=1/24. Give (shift,epsilon,least nonnegative N with 1/(N+shift)<epsilon,bound,m,n>=N implies distance<=1/(N+shift)<epsilon,cauchy_for_epsilon?). Use exact reduced rational outputs with positive denominators; omit /1 for integers.

View answer and explanation(22, 1/24, 3, 1/25, m,n>=N implies distance<=1/(N+shift)<epsilon, Yes)

Retain the strict inequality when choosing N. For every two later indices the reciprocal terms lie between zero and the stated upper bound, so their distance is at most that bound. The output certifies this chosen epsilon and the explicit model, not an arbitrary sequence. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is (22, 1/24, 3, 1/25, m,n>=N implies distance<=1/(N+shift)<epsilon, Yes).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0072/)

Cauchy sequence · qf-mod26-cauchy-reciprocal-epsilon-witness · candidate





## 73. A Strict Reciprocal Bound for the Selected Epsilon

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. The infinite model is x_n=1/(n+shift), with shift=23, epsilon=1/25. Give (shift,epsilon,least nonnegative N with 1/(N+shift)<epsilon,bound,m,n>=N implies distance<=1/(N+shift)<epsilon,cauchy_for_epsilon?). Use exact reduced rational outputs with positive denominators; omit /1 for integers.

View answer and explanation(23, 1/25, 3, 1/26, m,n>=N implies distance<=1/(N+shift)<epsilon, Yes)

Retain the strict inequality when choosing N. For every two later indices the reciprocal terms lie between zero and the stated upper bound, so their distance is at most that bound. The output certifies this chosen epsilon and the explicit model, not an arbitrary sequence. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is (23, 1/25, 3, 1/26, m,n>=N implies distance<=1/(N+shift)<epsilon, Yes).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0073/)

Cauchy sequence · qf-mod26-cauchy-reciprocal-epsilon-witness · candidate





## 74. A Strict Reciprocal Bound for the Selected Epsilon

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. The infinite model is x_n=1/(n+shift), with shift=24, epsilon=1/26. Give (shift,epsilon,least nonnegative N with 1/(N+shift)<epsilon,bound,m,n>=N implies distance<=1/(N+shift)<epsilon,cauchy_for_epsilon?). Use exact reduced rational outputs with positive denominators; omit /1 for integers.

View answer and explanation(24, 1/26, 3, 1/27, m,n>=N implies distance<=1/(N+shift)<epsilon, Yes)

Retain the strict inequality when choosing N. For every two later indices the reciprocal terms lie between zero and the stated upper bound, so their distance is at most that bound. The output certifies this chosen epsilon and the explicit model, not an arbitrary sequence. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is (24, 1/26, 3, 1/27, m,n>=N implies distance<=1/(N+shift)<epsilon, Yes).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0074/)

Cauchy sequence · qf-mod26-cauchy-reciprocal-epsilon-witness · candidate





## 75. A Strict Reciprocal Bound for the Selected Epsilon

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. The infinite model is x_n=1/(n+shift), with shift=25, epsilon=1/27. Give (shift,epsilon,least nonnegative N with 1/(N+shift)<epsilon,bound,m,n>=N implies distance<=1/(N+shift)<epsilon,cauchy_for_epsilon?). Use exact reduced rational outputs with positive denominators; omit /1 for integers.

View answer and explanation(25, 1/27, 3, 1/28, m,n>=N implies distance<=1/(N+shift)<epsilon, Yes)

Retain the strict inequality when choosing N. For every two later indices the reciprocal terms lie between zero and the stated upper bound, so their distance is at most that bound. The output certifies this chosen epsilon and the explicit model, not an arbitrary sequence. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is (25, 1/27, 3, 1/28, m,n>=N implies distance<=1/(N+shift)<epsilon, Yes).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0075/)

Cauchy sequence · qf-mod26-cauchy-reciprocal-epsilon-witness · candidate





## 76. Adjacent Opposite Terms Refute Cauchy Behavior

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. The infinite sequence alternates between amplitude and its negative, with positive amplitude=1; arbitrary proposed cutoff N=1. Give [amplitude,N,next_index,epsilon,distance,counterexample,cauchy] as a tuple. Use next_index=N+1 and epsilon=amplitude. The final No is the Cauchy flag, not the negated property.

View answer and explanation(1, 1, 2, 1, 2, Yes, No)

The adjacent terms at N and N+1 are both beyond the cutoff and have distance twice the amplitude, hence fail the strict epsilon bound. The same construction works for every N at one fixed positive epsilon: counterexample=Yes and cauchy=No. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is (1, 1, 2, 1, 2, Yes, No).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0076/)

Cauchy sequence · qf-mod26-cauchy-alternating-counterexample · candidate





## 77. Adjacent Opposite Terms Refute Cauchy Behavior

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. The infinite sequence alternates between amplitude and its negative, with positive amplitude=2; arbitrary proposed cutoff N=3. Give [amplitude,N,next_index,epsilon,distance,counterexample,cauchy] as a tuple. Use next_index=N+1 and epsilon=amplitude. The final No is the Cauchy flag, not the negated property.

View answer and explanation(2, 3, 4, 2, 4, Yes, No)

The adjacent terms at N and N+1 are both beyond the cutoff and have distance twice the amplitude, hence fail the strict epsilon bound. The same construction works for every N at one fixed positive epsilon: counterexample=Yes and cauchy=No. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is (2, 3, 4, 2, 4, Yes, No).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0077/)

Cauchy sequence · qf-mod26-cauchy-alternating-counterexample · candidate





## 78. Adjacent Opposite Terms Refute Cauchy Behavior

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. The infinite sequence alternates between amplitude and its negative, with positive amplitude=3; arbitrary proposed cutoff N=5. Give [amplitude,N,next_index,epsilon,distance,counterexample,cauchy] as a tuple. Use next_index=N+1 and epsilon=amplitude. The final No is the Cauchy flag, not the negated property.

View answer and explanation(3, 5, 6, 3, 6, Yes, No)

The adjacent terms at N and N+1 are both beyond the cutoff and have distance twice the amplitude, hence fail the strict epsilon bound. The same construction works for every N at one fixed positive epsilon: counterexample=Yes and cauchy=No. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is (3, 5, 6, 3, 6, Yes, No).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0078/)

Cauchy sequence · qf-mod26-cauchy-alternating-counterexample · candidate





## 79. Adjacent Opposite Terms Refute Cauchy Behavior

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. The infinite sequence alternates between amplitude and its negative, with positive amplitude=4; arbitrary proposed cutoff N=7. Give [amplitude,N,next_index,epsilon,distance,counterexample,cauchy] as a tuple. Use next_index=N+1 and epsilon=amplitude. The final No is the Cauchy flag, not the negated property.

View answer and explanation(4, 7, 8, 4, 8, Yes, No)

The adjacent terms at N and N+1 are both beyond the cutoff and have distance twice the amplitude, hence fail the strict epsilon bound. The same construction works for every N at one fixed positive epsilon: counterexample=Yes and cauchy=No. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is (4, 7, 8, 4, 8, Yes, No).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0079/)

Cauchy sequence · qf-mod26-cauchy-alternating-counterexample · candidate





## 80. Adjacent Opposite Terms Refute Cauchy Behavior

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. The infinite sequence alternates between amplitude and its negative, with positive amplitude=5; arbitrary proposed cutoff N=9. Give [amplitude,N,next_index,epsilon,distance,counterexample,cauchy] as a tuple. Use next_index=N+1 and epsilon=amplitude. The final No is the Cauchy flag, not the negated property.

View answer and explanation(5, 9, 10, 5, 10, Yes, No)

The adjacent terms at N and N+1 are both beyond the cutoff and have distance twice the amplitude, hence fail the strict epsilon bound. The same construction works for every N at one fixed positive epsilon: counterexample=Yes and cauchy=No. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is (5, 9, 10, 5, 10, Yes, No).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0080/)

Cauchy sequence · qf-mod26-cauchy-alternating-counterexample · candidate





## 81. Adjacent Opposite Terms Refute Cauchy Behavior

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. The infinite sequence alternates between amplitude and its negative, with positive amplitude=6; arbitrary proposed cutoff N=11. Give [amplitude,N,next_index,epsilon,distance,counterexample,cauchy] as a tuple. Use next_index=N+1 and epsilon=amplitude. The final No is the Cauchy flag, not the negated property.

View answer and explanation(6, 11, 12, 6, 12, Yes, No)

The adjacent terms at N and N+1 are both beyond the cutoff and have distance twice the amplitude, hence fail the strict epsilon bound. The same construction works for every N at one fixed positive epsilon: counterexample=Yes and cauchy=No. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is (6, 11, 12, 6, 12, Yes, No).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0081/)

Cauchy sequence · qf-mod26-cauchy-alternating-counterexample · candidate





## 82. Adjacent Opposite Terms Refute Cauchy Behavior

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. The infinite sequence alternates between amplitude and its negative, with positive amplitude=7; arbitrary proposed cutoff N=13. Give [amplitude,N,next_index,epsilon,distance,counterexample,cauchy] as a tuple. Use next_index=N+1 and epsilon=amplitude. The final No is the Cauchy flag, not the negated property.

View answer and explanation(7, 13, 14, 7, 14, Yes, No)

The adjacent terms at N and N+1 are both beyond the cutoff and have distance twice the amplitude, hence fail the strict epsilon bound. The same construction works for every N at one fixed positive epsilon: counterexample=Yes and cauchy=No. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is (7, 13, 14, 7, 14, Yes, No).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0082/)

Cauchy sequence · qf-mod26-cauchy-alternating-counterexample · candidate





## 83. Adjacent Opposite Terms Refute Cauchy Behavior

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. The infinite sequence alternates between amplitude and its negative, with positive amplitude=8; arbitrary proposed cutoff N=15. Give [amplitude,N,next_index,epsilon,distance,counterexample,cauchy] as a tuple. Use next_index=N+1 and epsilon=amplitude. The final No is the Cauchy flag, not the negated property.

View answer and explanation(8, 15, 16, 8, 16, Yes, No)

The adjacent terms at N and N+1 are both beyond the cutoff and have distance twice the amplitude, hence fail the strict epsilon bound. The same construction works for every N at one fixed positive epsilon: counterexample=Yes and cauchy=No. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is (8, 15, 16, 8, 16, Yes, No).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0083/)

Cauchy sequence · qf-mod26-cauchy-alternating-counterexample · candidate





## 84. Adjacent Opposite Terms Refute Cauchy Behavior

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. The infinite sequence alternates between amplitude and its negative, with positive amplitude=9; arbitrary proposed cutoff N=17. Give [amplitude,N,next_index,epsilon,distance,counterexample,cauchy] as a tuple. Use next_index=N+1 and epsilon=amplitude. The final No is the Cauchy flag, not the negated property.

View answer and explanation(9, 17, 18, 9, 18, Yes, No)

The adjacent terms at N and N+1 are both beyond the cutoff and have distance twice the amplitude, hence fail the strict epsilon bound. The same construction works for every N at one fixed positive epsilon: counterexample=Yes and cauchy=No. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is (9, 17, 18, 9, 18, Yes, No).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0084/)

Cauchy sequence · qf-mod26-cauchy-alternating-counterexample · candidate





## 85. Adjacent Opposite Terms Refute Cauchy Behavior

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. The infinite sequence alternates between amplitude and its negative, with positive amplitude=10; arbitrary proposed cutoff N=19. Give [amplitude,N,next_index,epsilon,distance,counterexample,cauchy] as a tuple. Use next_index=N+1 and epsilon=amplitude. The final No is the Cauchy flag, not the negated property.

View answer and explanation(10, 19, 20, 10, 20, Yes, No)

The adjacent terms at N and N+1 are both beyond the cutoff and have distance twice the amplitude, hence fail the strict epsilon bound. The same construction works for every N at one fixed positive epsilon: counterexample=Yes and cauchy=No. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is (10, 19, 20, 10, 20, Yes, No).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0085/)

Cauchy sequence · qf-mod26-cauchy-alternating-counterexample · candidate





## 86. Adjacent Opposite Terms Refute Cauchy Behavior

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. The infinite sequence alternates between amplitude and its negative, with positive amplitude=11; arbitrary proposed cutoff N=21. Give [amplitude,N,next_index,epsilon,distance,counterexample,cauchy] as a tuple. Use next_index=N+1 and epsilon=amplitude. The final No is the Cauchy flag, not the negated property.

View answer and explanation(11, 21, 22, 11, 22, Yes, No)

The adjacent terms at N and N+1 are both beyond the cutoff and have distance twice the amplitude, hence fail the strict epsilon bound. The same construction works for every N at one fixed positive epsilon: counterexample=Yes and cauchy=No. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is (11, 21, 22, 11, 22, Yes, No).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0086/)

Cauchy sequence · qf-mod26-cauchy-alternating-counterexample · candidate





## 87. Adjacent Opposite Terms Refute Cauchy Behavior

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. The infinite sequence alternates between amplitude and its negative, with positive amplitude=12; arbitrary proposed cutoff N=23. Give [amplitude,N,next_index,epsilon,distance,counterexample,cauchy] as a tuple. Use next_index=N+1 and epsilon=amplitude. The final No is the Cauchy flag, not the negated property.

View answer and explanation(12, 23, 24, 12, 24, Yes, No)

The adjacent terms at N and N+1 are both beyond the cutoff and have distance twice the amplitude, hence fail the strict epsilon bound. The same construction works for every N at one fixed positive epsilon: counterexample=Yes and cauchy=No. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is (12, 23, 24, 12, 24, Yes, No).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0087/)

Cauchy sequence · qf-mod26-cauchy-alternating-counterexample · candidate





## 88. Adjacent Opposite Terms Refute Cauchy Behavior

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. The infinite sequence alternates between amplitude and its negative, with positive amplitude=13; arbitrary proposed cutoff N=25. Give [amplitude,N,next_index,epsilon,distance,counterexample,cauchy] as a tuple. Use next_index=N+1 and epsilon=amplitude. The final No is the Cauchy flag, not the negated property.

View answer and explanation(13, 25, 26, 13, 26, Yes, No)

The adjacent terms at N and N+1 are both beyond the cutoff and have distance twice the amplitude, hence fail the strict epsilon bound. The same construction works for every N at one fixed positive epsilon: counterexample=Yes and cauchy=No. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is (13, 25, 26, 13, 26, Yes, No).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0088/)

Cauchy sequence · qf-mod26-cauchy-alternating-counterexample · candidate





## 89. Adjacent Opposite Terms Refute Cauchy Behavior

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. The infinite sequence alternates between amplitude and its negative, with positive amplitude=14; arbitrary proposed cutoff N=27. Give [amplitude,N,next_index,epsilon,distance,counterexample,cauchy] as a tuple. Use next_index=N+1 and epsilon=amplitude. The final No is the Cauchy flag, not the negated property.

View answer and explanation(14, 27, 28, 14, 28, Yes, No)

The adjacent terms at N and N+1 are both beyond the cutoff and have distance twice the amplitude, hence fail the strict epsilon bound. The same construction works for every N at one fixed positive epsilon: counterexample=Yes and cauchy=No. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is (14, 27, 28, 14, 28, Yes, No).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0089/)

Cauchy sequence · qf-mod26-cauchy-alternating-counterexample · candidate





## 90. Adjacent Opposite Terms Refute Cauchy Behavior

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. The infinite sequence alternates between amplitude and its negative, with positive amplitude=15; arbitrary proposed cutoff N=29. Give [amplitude,N,next_index,epsilon,distance,counterexample,cauchy] as a tuple. Use next_index=N+1 and epsilon=amplitude. The final No is the Cauchy flag, not the negated property.

View answer and explanation(15, 29, 30, 15, 30, Yes, No)

The adjacent terms at N and N+1 are both beyond the cutoff and have distance twice the amplitude, hence fail the strict epsilon bound. The same construction works for every N at one fixed positive epsilon: counterexample=Yes and cauchy=No. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is (15, 29, 30, 15, 30, Yes, No).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0090/)

Cauchy sequence · qf-mod26-cauchy-alternating-counterexample · candidate





## 91. Adjacent Opposite Terms Refute Cauchy Behavior

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. The infinite sequence alternates between amplitude and its negative, with positive amplitude=16; arbitrary proposed cutoff N=31. Give [amplitude,N,next_index,epsilon,distance,counterexample,cauchy] as a tuple. Use next_index=N+1 and epsilon=amplitude. The final No is the Cauchy flag, not the negated property.

View answer and explanation(16, 31, 32, 16, 32, Yes, No)

The adjacent terms at N and N+1 are both beyond the cutoff and have distance twice the amplitude, hence fail the strict epsilon bound. The same construction works for every N at one fixed positive epsilon: counterexample=Yes and cauchy=No. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is (16, 31, 32, 16, 32, Yes, No).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0091/)

Cauchy sequence · qf-mod26-cauchy-alternating-counterexample · candidate





## 92. Adjacent Opposite Terms Refute Cauchy Behavior

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. The infinite sequence alternates between amplitude and its negative, with positive amplitude=17; arbitrary proposed cutoff N=33. Give [amplitude,N,next_index,epsilon,distance,counterexample,cauchy] as a tuple. Use next_index=N+1 and epsilon=amplitude. The final No is the Cauchy flag, not the negated property.

View answer and explanation(17, 33, 34, 17, 34, Yes, No)

The adjacent terms at N and N+1 are both beyond the cutoff and have distance twice the amplitude, hence fail the strict epsilon bound. The same construction works for every N at one fixed positive epsilon: counterexample=Yes and cauchy=No. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is (17, 33, 34, 17, 34, Yes, No).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0092/)

Cauchy sequence · qf-mod26-cauchy-alternating-counterexample · candidate





## 93. Adjacent Opposite Terms Refute Cauchy Behavior

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. The infinite sequence alternates between amplitude and its negative, with positive amplitude=18; arbitrary proposed cutoff N=35. Give [amplitude,N,next_index,epsilon,distance,counterexample,cauchy] as a tuple. Use next_index=N+1 and epsilon=amplitude. The final No is the Cauchy flag, not the negated property.

View answer and explanation(18, 35, 36, 18, 36, Yes, No)

The adjacent terms at N and N+1 are both beyond the cutoff and have distance twice the amplitude, hence fail the strict epsilon bound. The same construction works for every N at one fixed positive epsilon: counterexample=Yes and cauchy=No. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is (18, 35, 36, 18, 36, Yes, No).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0093/)

Cauchy sequence · qf-mod26-cauchy-alternating-counterexample · candidate





## 94. Adjacent Opposite Terms Refute Cauchy Behavior

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. The infinite sequence alternates between amplitude and its negative, with positive amplitude=19; arbitrary proposed cutoff N=37. Give [amplitude,N,next_index,epsilon,distance,counterexample,cauchy] as a tuple. Use next_index=N+1 and epsilon=amplitude. The final No is the Cauchy flag, not the negated property.

View answer and explanation(19, 37, 38, 19, 38, Yes, No)

The adjacent terms at N and N+1 are both beyond the cutoff and have distance twice the amplitude, hence fail the strict epsilon bound. The same construction works for every N at one fixed positive epsilon: counterexample=Yes and cauchy=No. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is (19, 37, 38, 19, 38, Yes, No).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0094/)

Cauchy sequence · qf-mod26-cauchy-alternating-counterexample · candidate





## 95. Adjacent Opposite Terms Refute Cauchy Behavior

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. The infinite sequence alternates between amplitude and its negative, with positive amplitude=20; arbitrary proposed cutoff N=39. Give [amplitude,N,next_index,epsilon,distance,counterexample,cauchy] as a tuple. Use next_index=N+1 and epsilon=amplitude. The final No is the Cauchy flag, not the negated property.

View answer and explanation(20, 39, 40, 20, 40, Yes, No)

The adjacent terms at N and N+1 are both beyond the cutoff and have distance twice the amplitude, hence fail the strict epsilon bound. The same construction works for every N at one fixed positive epsilon: counterexample=Yes and cauchy=No. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is (20, 39, 40, 20, 40, Yes, No).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0095/)

Cauchy sequence · qf-mod26-cauchy-alternating-counterexample · candidate





## 96. Adjacent Opposite Terms Refute Cauchy Behavior

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. The infinite sequence alternates between amplitude and its negative, with positive amplitude=21; arbitrary proposed cutoff N=41. Give [amplitude,N,next_index,epsilon,distance,counterexample,cauchy] as a tuple. Use next_index=N+1 and epsilon=amplitude. The final No is the Cauchy flag, not the negated property.

View answer and explanation(21, 41, 42, 21, 42, Yes, No)

The adjacent terms at N and N+1 are both beyond the cutoff and have distance twice the amplitude, hence fail the strict epsilon bound. The same construction works for every N at one fixed positive epsilon: counterexample=Yes and cauchy=No. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is (21, 41, 42, 21, 42, Yes, No).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0096/)

Cauchy sequence · qf-mod26-cauchy-alternating-counterexample · candidate





## 97. Adjacent Opposite Terms Refute Cauchy Behavior

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. The infinite sequence alternates between amplitude and its negative, with positive amplitude=22; arbitrary proposed cutoff N=43. Give [amplitude,N,next_index,epsilon,distance,counterexample,cauchy] as a tuple. Use next_index=N+1 and epsilon=amplitude. The final No is the Cauchy flag, not the negated property.

View answer and explanation(22, 43, 44, 22, 44, Yes, No)

The adjacent terms at N and N+1 are both beyond the cutoff and have distance twice the amplitude, hence fail the strict epsilon bound. The same construction works for every N at one fixed positive epsilon: counterexample=Yes and cauchy=No. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is (22, 43, 44, 22, 44, Yes, No).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0097/)

Cauchy sequence · qf-mod26-cauchy-alternating-counterexample · candidate





## 98. Adjacent Opposite Terms Refute Cauchy Behavior

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. The infinite sequence alternates between amplitude and its negative, with positive amplitude=23; arbitrary proposed cutoff N=45. Give [amplitude,N,next_index,epsilon,distance,counterexample,cauchy] as a tuple. Use next_index=N+1 and epsilon=amplitude. The final No is the Cauchy flag, not the negated property.

View answer and explanation(23, 45, 46, 23, 46, Yes, No)

The adjacent terms at N and N+1 are both beyond the cutoff and have distance twice the amplitude, hence fail the strict epsilon bound. The same construction works for every N at one fixed positive epsilon: counterexample=Yes and cauchy=No. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is (23, 45, 46, 23, 46, Yes, No).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0098/)

Cauchy sequence · qf-mod26-cauchy-alternating-counterexample · candidate





## 99. Adjacent Opposite Terms Refute Cauchy Behavior

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. The infinite sequence alternates between amplitude and its negative, with positive amplitude=24; arbitrary proposed cutoff N=47. Give [amplitude,N,next_index,epsilon,distance,counterexample,cauchy] as a tuple. Use next_index=N+1 and epsilon=amplitude. The final No is the Cauchy flag, not the negated property.

View answer and explanation(24, 47, 48, 24, 48, Yes, No)

The adjacent terms at N and N+1 are both beyond the cutoff and have distance twice the amplitude, hence fail the strict epsilon bound. The same construction works for every N at one fixed positive epsilon: counterexample=Yes and cauchy=No. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is (24, 47, 48, 24, 48, Yes, No).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0099/)

Cauchy sequence · qf-mod26-cauchy-alternating-counterexample · candidate





## 100. Adjacent Opposite Terms Refute Cauchy Behavior

Keep the quantifier order: for every epsilon>0 there exists N such that for all m,n≥N, d(x_m,x_n)<epsilon. No limit or completeness premise is assumed. A finite recorded tail alone does not prove this infinite statement. The infinite sequence alternates between amplitude and its negative, with positive amplitude=25; arbitrary proposed cutoff N=49. Give [amplitude,N,next_index,epsilon,distance,counterexample,cauchy] as a tuple. Use next_index=N+1 and epsilon=amplitude. The final No is the Cauchy flag, not the negated property.

View answer and explanation(25, 49, 50, 25, 50, Yes, No)

The adjacent terms at N and N+1 are both beyond the cutoff and have distance twice the amplitude, hence fail the strict epsilon bound. The same construction works for every N at one fixed positive epsilon: counterexample=Yes and cauchy=No. An exact finite or explicitly certified slice does not automatically establish a general infinite theorem. The exact result, retaining the requested order, is (25, 49, 50, 25, 50, Yes, No).



[Reviewed step-by-step derivation](https://ocme.evemisslab.com/en/questions/q-20261013-advance-20261026-r03-cauchy-sequence-0100/)

Cauchy sequence · qf-mod26-cauchy-alternating-counterexample · candidate



[Canonical question JSONL](https://ocme.evemisslab.com/data/questions/errata/ocme-source-label-cauchy-20261015/questions.jsonl) · [English JSONL](https://ocme.evemisslab.com/data/i18n/questions/batch-20261013-advance-20261026-r03-cauchy-sequence-foundations.en.jsonl) · [Validation report](https://ocme.evemisslab.com/data/questions/errata/ocme-source-label-cauchy-20261015/validation-report.json)


