Topology-Relative Boundaries, Complements and Empty/Whole Sets

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This question bank has corresponding bilingual step-by-step derivations. Source candidate and English ai_candidate states are retained. AI review, finite computation and Lean formal proof are labelled separately.

batch-20261014-advance-20261102-r04-topological-boundary-foundations · 2026-10-14 · 100 questions

This English edition is an AI candidate and does not yet have an OCME Atlas (GPT-6) Twin closure receipt.

1. Boundary Is Closure Minus Interior in the Same Topology

Use the complete finite topology=[[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. Subset=[1, 2]. Give (subset,closure,interior,boundary), with resulting subsets in increasing carrier order.

View answer and explanation

([1, 2], [1, 2, 3, 4], [], [1, 2, 3, 4])

Intersect all closed supersets to get closure and unite all open subsets to get interior, then subtract the interior from the closure. A picture cannot replace these topology-relative constructions. The exact result, retaining the requested order, is ([1, 2], [1, 2, 3, 4], [], [1, 2, 3, 4]).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-exact · candidate

2. Boundary Is Closure Minus Interior in the Same Topology

Use the complete finite topology=[[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 4], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. Subset=[1, 2]. Give (subset,closure,interior,boundary), with resulting subsets in increasing carrier order.

View answer and explanation

([1, 2], [1, 2, 3, 4], [], [1, 2, 3, 4])

Intersect all closed supersets to get closure and unite all open subsets to get interior, then subtract the interior from the closure. A picture cannot replace these topology-relative constructions. The exact result, retaining the requested order, is ([1, 2], [1, 2, 3, 4], [], [1, 2, 3, 4]).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-exact · candidate

3. Boundary Is Closure Minus Interior in the Same Topology

Use the complete finite topology=[[], [0], [0, 1], [0, 1, 3], [0, 1, 2, 3], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. Subset=[1, 3]. Give (subset,closure,interior,boundary), with resulting subsets in increasing carrier order.

View answer and explanation

([1, 3], [1, 2, 3, 4], [], [1, 2, 3, 4])

Intersect all closed supersets to get closure and unite all open subsets to get interior, then subtract the interior from the closure. A picture cannot replace these topology-relative constructions. The exact result, retaining the requested order, is ([1, 3], [1, 2, 3, 4], [], [1, 2, 3, 4]).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-exact · candidate

4. Boundary Is Closure Minus Interior in the Same Topology

Use the complete finite topology=[[], [0], [0, 1], [0, 1, 3], [0, 1, 3, 4], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. Subset=[1, 3]. Give (subset,closure,interior,boundary), with resulting subsets in increasing carrier order.

View answer and explanation

([1, 3], [1, 2, 3, 4], [], [1, 2, 3, 4])

Intersect all closed supersets to get closure and unite all open subsets to get interior, then subtract the interior from the closure. A picture cannot replace these topology-relative constructions. The exact result, retaining the requested order, is ([1, 3], [1, 2, 3, 4], [], [1, 2, 3, 4]).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-exact · candidate

5. Boundary Is Closure Minus Interior in the Same Topology

Use the complete finite topology=[[], [0], [0, 1], [0, 1, 4], [0, 1, 2, 4], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. Subset=[1, 4]. Give (subset,closure,interior,boundary), with resulting subsets in increasing carrier order.

View answer and explanation

([1, 4], [1, 2, 3, 4], [], [1, 2, 3, 4])

Intersect all closed supersets to get closure and unite all open subsets to get interior, then subtract the interior from the closure. A picture cannot replace these topology-relative constructions. The exact result, retaining the requested order, is ([1, 4], [1, 2, 3, 4], [], [1, 2, 3, 4]).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-exact · candidate

6. Boundary Is Closure Minus Interior in the Same Topology

Use the complete finite topology=[[], [0], [0, 1], [0, 1, 4], [0, 1, 3, 4], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. Subset=[1, 4]. Give (subset,closure,interior,boundary), with resulting subsets in increasing carrier order.

View answer and explanation

([1, 4], [1, 2, 3, 4], [], [1, 2, 3, 4])

Intersect all closed supersets to get closure and unite all open subsets to get interior, then subtract the interior from the closure. A picture cannot replace these topology-relative constructions. The exact result, retaining the requested order, is ([1, 4], [1, 2, 3, 4], [], [1, 2, 3, 4]).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-exact · candidate

7. Boundary Is Closure Minus Interior in the Same Topology

Use the complete finite topology=[[], [0], [0, 2], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. Subset=[1, 2]. Give (subset,closure,interior,boundary), with resulting subsets in increasing carrier order.

View answer and explanation

([1, 2], [1, 2, 3, 4], [], [1, 2, 3, 4])

Intersect all closed supersets to get closure and unite all open subsets to get interior, then subtract the interior from the closure. A picture cannot replace these topology-relative constructions. The exact result, retaining the requested order, is ([1, 2], [1, 2, 3, 4], [], [1, 2, 3, 4]).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-exact · candidate

8. Boundary Is Closure Minus Interior in the Same Topology

Use the complete finite topology=[[], [0], [0, 2], [0, 1, 2], [0, 1, 2, 4], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. Subset=[1, 2]. Give (subset,closure,interior,boundary), with resulting subsets in increasing carrier order.

View answer and explanation

([1, 2], [1, 2, 3, 4], [], [1, 2, 3, 4])

Intersect all closed supersets to get closure and unite all open subsets to get interior, then subtract the interior from the closure. A picture cannot replace these topology-relative constructions. The exact result, retaining the requested order, is ([1, 2], [1, 2, 3, 4], [], [1, 2, 3, 4]).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-exact · candidate

9. Boundary Is Closure Minus Interior in the Same Topology

Use the complete finite topology=[[], [0], [0, 2], [0, 2, 3], [0, 1, 2, 3], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. Subset=[2, 3]. Give (subset,closure,interior,boundary), with resulting subsets in increasing carrier order.

View answer and explanation

([2, 3], [1, 2, 3, 4], [], [1, 2, 3, 4])

Intersect all closed supersets to get closure and unite all open subsets to get interior, then subtract the interior from the closure. A picture cannot replace these topology-relative constructions. The exact result, retaining the requested order, is ([2, 3], [1, 2, 3, 4], [], [1, 2, 3, 4]).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-exact · candidate

10. Boundary Is Closure Minus Interior in the Same Topology

Use the complete finite topology=[[], [0], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. Subset=[2, 3]. Give (subset,closure,interior,boundary), with resulting subsets in increasing carrier order.

View answer and explanation

([2, 3], [1, 2, 3, 4], [], [1, 2, 3, 4])

Intersect all closed supersets to get closure and unite all open subsets to get interior, then subtract the interior from the closure. A picture cannot replace these topology-relative constructions. The exact result, retaining the requested order, is ([2, 3], [1, 2, 3, 4], [], [1, 2, 3, 4]).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-exact · candidate

11. Boundary Is Closure Minus Interior in the Same Topology

Use the complete finite topology=[[], [0], [0, 2], [0, 2, 4], [0, 1, 2, 4], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. Subset=[2, 4]. Give (subset,closure,interior,boundary), with resulting subsets in increasing carrier order.

View answer and explanation

([2, 4], [1, 2, 3, 4], [], [1, 2, 3, 4])

Intersect all closed supersets to get closure and unite all open subsets to get interior, then subtract the interior from the closure. A picture cannot replace these topology-relative constructions. The exact result, retaining the requested order, is ([2, 4], [1, 2, 3, 4], [], [1, 2, 3, 4]).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-exact · candidate

12. Boundary Is Closure Minus Interior in the Same Topology

Use the complete finite topology=[[], [0], [0, 2], [0, 2, 4], [0, 2, 3, 4], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. Subset=[2, 4]. Give (subset,closure,interior,boundary), with resulting subsets in increasing carrier order.

View answer and explanation

([2, 4], [1, 2, 3, 4], [], [1, 2, 3, 4])

Intersect all closed supersets to get closure and unite all open subsets to get interior, then subtract the interior from the closure. A picture cannot replace these topology-relative constructions. The exact result, retaining the requested order, is ([2, 4], [1, 2, 3, 4], [], [1, 2, 3, 4]).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-exact · candidate

13. Boundary Is Closure Minus Interior in the Same Topology

Use the complete finite topology=[[], [0], [0, 3], [0, 1, 3], [0, 1, 2, 3], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. Subset=[1, 3]. Give (subset,closure,interior,boundary), with resulting subsets in increasing carrier order.

View answer and explanation

([1, 3], [1, 2, 3, 4], [], [1, 2, 3, 4])

Intersect all closed supersets to get closure and unite all open subsets to get interior, then subtract the interior from the closure. A picture cannot replace these topology-relative constructions. The exact result, retaining the requested order, is ([1, 3], [1, 2, 3, 4], [], [1, 2, 3, 4]).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-exact · candidate

14. Boundary Is Closure Minus Interior in the Same Topology

Use the complete finite topology=[[], [0], [0, 3], [0, 1, 3], [0, 1, 3, 4], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. Subset=[1, 3]. Give (subset,closure,interior,boundary), with resulting subsets in increasing carrier order.

View answer and explanation

([1, 3], [1, 2, 3, 4], [], [1, 2, 3, 4])

Intersect all closed supersets to get closure and unite all open subsets to get interior, then subtract the interior from the closure. A picture cannot replace these topology-relative constructions. The exact result, retaining the requested order, is ([1, 3], [1, 2, 3, 4], [], [1, 2, 3, 4]).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-exact · candidate

15. Boundary Is Closure Minus Interior in the Same Topology

Use the complete finite topology=[[], [0], [0, 3], [0, 2, 3], [0, 1, 2, 3], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. Subset=[2, 3]. Give (subset,closure,interior,boundary), with resulting subsets in increasing carrier order.

View answer and explanation

([2, 3], [1, 2, 3, 4], [], [1, 2, 3, 4])

Intersect all closed supersets to get closure and unite all open subsets to get interior, then subtract the interior from the closure. A picture cannot replace these topology-relative constructions. The exact result, retaining the requested order, is ([2, 3], [1, 2, 3, 4], [], [1, 2, 3, 4]).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-exact · candidate

16. Boundary Is Closure Minus Interior in the Same Topology

Use the complete finite topology=[[], [0], [0, 3], [0, 2, 3], [0, 2, 3, 4], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. Subset=[2, 3]. Give (subset,closure,interior,boundary), with resulting subsets in increasing carrier order.

View answer and explanation

([2, 3], [1, 2, 3, 4], [], [1, 2, 3, 4])

Intersect all closed supersets to get closure and unite all open subsets to get interior, then subtract the interior from the closure. A picture cannot replace these topology-relative constructions. The exact result, retaining the requested order, is ([2, 3], [1, 2, 3, 4], [], [1, 2, 3, 4]).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-exact · candidate

17. Boundary Is Closure Minus Interior in the Same Topology

Use the complete finite topology=[[], [0], [0, 3], [0, 3, 4], [0, 1, 3, 4], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. Subset=[3, 4]. Give (subset,closure,interior,boundary), with resulting subsets in increasing carrier order.

View answer and explanation

([3, 4], [1, 2, 3, 4], [], [1, 2, 3, 4])

Intersect all closed supersets to get closure and unite all open subsets to get interior, then subtract the interior from the closure. A picture cannot replace these topology-relative constructions. The exact result, retaining the requested order, is ([3, 4], [1, 2, 3, 4], [], [1, 2, 3, 4]).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-exact · candidate

18. Boundary Is Closure Minus Interior in the Same Topology

Use the complete finite topology=[[], [0], [0, 3], [0, 3, 4], [0, 2, 3, 4], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. Subset=[3, 4]. Give (subset,closure,interior,boundary), with resulting subsets in increasing carrier order.

View answer and explanation

([3, 4], [1, 2, 3, 4], [], [1, 2, 3, 4])

Intersect all closed supersets to get closure and unite all open subsets to get interior, then subtract the interior from the closure. A picture cannot replace these topology-relative constructions. The exact result, retaining the requested order, is ([3, 4], [1, 2, 3, 4], [], [1, 2, 3, 4]).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-exact · candidate

19. Boundary Is Closure Minus Interior in the Same Topology

Use the complete finite topology=[[], [0], [0, 4], [0, 1, 4], [0, 1, 2, 4], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. Subset=[1, 4]. Give (subset,closure,interior,boundary), with resulting subsets in increasing carrier order.

View answer and explanation

([1, 4], [1, 2, 3, 4], [], [1, 2, 3, 4])

Intersect all closed supersets to get closure and unite all open subsets to get interior, then subtract the interior from the closure. A picture cannot replace these topology-relative constructions. The exact result, retaining the requested order, is ([1, 4], [1, 2, 3, 4], [], [1, 2, 3, 4]).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-exact · candidate

20. Boundary Is Closure Minus Interior in the Same Topology

Use the complete finite topology=[[], [0], [0, 4], [0, 1, 4], [0, 1, 3, 4], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. Subset=[1, 4]. Give (subset,closure,interior,boundary), with resulting subsets in increasing carrier order.

View answer and explanation

([1, 4], [1, 2, 3, 4], [], [1, 2, 3, 4])

Intersect all closed supersets to get closure and unite all open subsets to get interior, then subtract the interior from the closure. A picture cannot replace these topology-relative constructions. The exact result, retaining the requested order, is ([1, 4], [1, 2, 3, 4], [], [1, 2, 3, 4]).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-exact · candidate

21. Boundary Is Closure Minus Interior in the Same Topology

Use the complete finite topology=[[], [0], [0, 4], [0, 2, 4], [0, 1, 2, 4], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. Subset=[2, 4]. Give (subset,closure,interior,boundary), with resulting subsets in increasing carrier order.

View answer and explanation

([2, 4], [1, 2, 3, 4], [], [1, 2, 3, 4])

Intersect all closed supersets to get closure and unite all open subsets to get interior, then subtract the interior from the closure. A picture cannot replace these topology-relative constructions. The exact result, retaining the requested order, is ([2, 4], [1, 2, 3, 4], [], [1, 2, 3, 4]).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-exact · candidate

22. Boundary Is Closure Minus Interior in the Same Topology

Use the complete finite topology=[[], [0], [0, 4], [0, 2, 4], [0, 2, 3, 4], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. Subset=[2, 4]. Give (subset,closure,interior,boundary), with resulting subsets in increasing carrier order.

View answer and explanation

([2, 4], [1, 2, 3, 4], [], [1, 2, 3, 4])

Intersect all closed supersets to get closure and unite all open subsets to get interior, then subtract the interior from the closure. A picture cannot replace these topology-relative constructions. The exact result, retaining the requested order, is ([2, 4], [1, 2, 3, 4], [], [1, 2, 3, 4]).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-exact · candidate

23. Boundary Is Closure Minus Interior in the Same Topology

Use the complete finite topology=[[], [0], [0, 4], [0, 3, 4], [0, 1, 3, 4], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. Subset=[3, 4]. Give (subset,closure,interior,boundary), with resulting subsets in increasing carrier order.

View answer and explanation

([3, 4], [1, 2, 3, 4], [], [1, 2, 3, 4])

Intersect all closed supersets to get closure and unite all open subsets to get interior, then subtract the interior from the closure. A picture cannot replace these topology-relative constructions. The exact result, retaining the requested order, is ([3, 4], [1, 2, 3, 4], [], [1, 2, 3, 4]).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-exact · candidate

24. Boundary Is Closure Minus Interior in the Same Topology

Use the complete finite topology=[[], [0], [0, 4], [0, 3, 4], [0, 2, 3, 4], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. Subset=[3, 4]. Give (subset,closure,interior,boundary), with resulting subsets in increasing carrier order.

View answer and explanation

([3, 4], [1, 2, 3, 4], [], [1, 2, 3, 4])

Intersect all closed supersets to get closure and unite all open subsets to get interior, then subtract the interior from the closure. A picture cannot replace these topology-relative constructions. The exact result, retaining the requested order, is ([3, 4], [1, 2, 3, 4], [], [1, 2, 3, 4]).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-exact · candidate

25. Boundary Is Closure Minus Interior in the Same Topology

Use the complete finite topology=[[], [1], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. Subset=[0, 2]. Give (subset,closure,interior,boundary), with resulting subsets in increasing carrier order.

View answer and explanation

([0, 2], [0, 2, 3, 4], [], [0, 2, 3, 4])

Intersect all closed supersets to get closure and unite all open subsets to get interior, then subtract the interior from the closure. A picture cannot replace these topology-relative constructions. The exact result, retaining the requested order, is ([0, 2], [0, 2, 3, 4], [], [0, 2, 3, 4]).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-exact · candidate

26. Boundary Membership Is Not Just Membership in the Original Set

Use the complete finite topology=[[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. Subset=[1, 2], point=0. Give (point,boundary,in_boundary?,topology_relative_boundary).

View answer and explanation

(0, [1, 2, 3, 4], No, topology_relative_boundary)

Compute the complete topology-relative boundary first, then test the point. Do not infer boundary status from an unstated metric or a drawing. The exact result, retaining the requested order, is (0, [1, 2, 3, 4], No, topology_relative_boundary).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-membership · candidate

27. Boundary Membership Is Not Just Membership in the Original Set

Use the complete finite topology=[[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 4], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. Subset=[1, 2], point=1. Give (point,boundary,in_boundary?,topology_relative_boundary).

View answer and explanation

(1, [1, 2, 3, 4], Yes, topology_relative_boundary)

Compute the complete topology-relative boundary first, then test the point. Do not infer boundary status from an unstated metric or a drawing. The exact result, retaining the requested order, is (1, [1, 2, 3, 4], Yes, topology_relative_boundary).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-membership · candidate

28. Boundary Membership Is Not Just Membership in the Original Set

Use the complete finite topology=[[], [0], [0, 1], [0, 1, 3], [0, 1, 2, 3], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. Subset=[1, 3], point=3. Give (point,boundary,in_boundary?,topology_relative_boundary).

View answer and explanation

(3, [1, 2, 3, 4], Yes, topology_relative_boundary)

Compute the complete topology-relative boundary first, then test the point. Do not infer boundary status from an unstated metric or a drawing. The exact result, retaining the requested order, is (3, [1, 2, 3, 4], Yes, topology_relative_boundary).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-membership · candidate

29. Boundary Membership Is Not Just Membership in the Original Set

Use the complete finite topology=[[], [0], [0, 1], [0, 1, 3], [0, 1, 3, 4], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. Subset=[1, 3], point=4. Give (point,boundary,in_boundary?,topology_relative_boundary).

View answer and explanation

(4, [1, 2, 3, 4], Yes, topology_relative_boundary)

Compute the complete topology-relative boundary first, then test the point. Do not infer boundary status from an unstated metric or a drawing. The exact result, retaining the requested order, is (4, [1, 2, 3, 4], Yes, topology_relative_boundary).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-membership · candidate

30. Boundary Membership Is Not Just Membership in the Original Set

Use the complete finite topology=[[], [0], [0, 1], [0, 1, 4], [0, 1, 2, 4], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. Subset=[1, 4], point=3. Give (point,boundary,in_boundary?,topology_relative_boundary).

View answer and explanation

(3, [1, 2, 3, 4], Yes, topology_relative_boundary)

Compute the complete topology-relative boundary first, then test the point. Do not infer boundary status from an unstated metric or a drawing. The exact result, retaining the requested order, is (3, [1, 2, 3, 4], Yes, topology_relative_boundary).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-membership · candidate

31. Boundary Membership Is Not Just Membership in the Original Set

Use the complete finite topology=[[], [0], [0, 1], [0, 1, 4], [0, 1, 3, 4], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. Subset=[1, 4], point=0. Give (point,boundary,in_boundary?,topology_relative_boundary).

View answer and explanation

(0, [1, 2, 3, 4], No, topology_relative_boundary)

Compute the complete topology-relative boundary first, then test the point. Do not infer boundary status from an unstated metric or a drawing. The exact result, retaining the requested order, is (0, [1, 2, 3, 4], No, topology_relative_boundary).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-membership · candidate

32. Boundary Membership Is Not Just Membership in the Original Set

Use the complete finite topology=[[], [0], [0, 2], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. Subset=[1, 2], point=2. Give (point,boundary,in_boundary?,topology_relative_boundary).

View answer and explanation

(2, [1, 2, 3, 4], Yes, topology_relative_boundary)

Compute the complete topology-relative boundary first, then test the point. Do not infer boundary status from an unstated metric or a drawing. The exact result, retaining the requested order, is (2, [1, 2, 3, 4], Yes, topology_relative_boundary).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-membership · candidate

33. Boundary Membership Is Not Just Membership in the Original Set

Use the complete finite topology=[[], [0], [0, 2], [0, 1, 2], [0, 1, 2, 4], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. Subset=[1, 2], point=1. Give (point,boundary,in_boundary?,topology_relative_boundary).

View answer and explanation

(1, [1, 2, 3, 4], Yes, topology_relative_boundary)

Compute the complete topology-relative boundary first, then test the point. Do not infer boundary status from an unstated metric or a drawing. The exact result, retaining the requested order, is (1, [1, 2, 3, 4], Yes, topology_relative_boundary).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-membership · candidate

34. Boundary Membership Is Not Just Membership in the Original Set

Use the complete finite topology=[[], [0], [0, 2], [0, 2, 3], [0, 1, 2, 3], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. Subset=[2, 3], point=1. Give (point,boundary,in_boundary?,topology_relative_boundary).

View answer and explanation

(1, [1, 2, 3, 4], Yes, topology_relative_boundary)

Compute the complete topology-relative boundary first, then test the point. Do not infer boundary status from an unstated metric or a drawing. The exact result, retaining the requested order, is (1, [1, 2, 3, 4], Yes, topology_relative_boundary).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-membership · candidate

35. Boundary Membership Is Not Just Membership in the Original Set

Use the complete finite topology=[[], [0], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. Subset=[2, 3], point=1. Give (point,boundary,in_boundary?,topology_relative_boundary).

View answer and explanation

(1, [1, 2, 3, 4], Yes, topology_relative_boundary)

Compute the complete topology-relative boundary first, then test the point. Do not infer boundary status from an unstated metric or a drawing. The exact result, retaining the requested order, is (1, [1, 2, 3, 4], Yes, topology_relative_boundary).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-membership · candidate

36. Boundary Membership Is Not Just Membership in the Original Set

Use the complete finite topology=[[], [0], [0, 2], [0, 2, 4], [0, 1, 2, 4], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. Subset=[2, 4], point=0. Give (point,boundary,in_boundary?,topology_relative_boundary).

View answer and explanation

(0, [1, 2, 3, 4], No, topology_relative_boundary)

Compute the complete topology-relative boundary first, then test the point. Do not infer boundary status from an unstated metric or a drawing. The exact result, retaining the requested order, is (0, [1, 2, 3, 4], No, topology_relative_boundary).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-membership · candidate

37. Boundary Membership Is Not Just Membership in the Original Set

Use the complete finite topology=[[], [0], [0, 2], [0, 2, 4], [0, 2, 3, 4], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. Subset=[2, 4], point=2. Give (point,boundary,in_boundary?,topology_relative_boundary).

View answer and explanation

(2, [1, 2, 3, 4], Yes, topology_relative_boundary)

Compute the complete topology-relative boundary first, then test the point. Do not infer boundary status from an unstated metric or a drawing. The exact result, retaining the requested order, is (2, [1, 2, 3, 4], Yes, topology_relative_boundary).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-membership · candidate

38. Boundary Membership Is Not Just Membership in the Original Set

Use the complete finite topology=[[], [0], [0, 3], [0, 1, 3], [0, 1, 2, 3], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. Subset=[1, 3], point=1. Give (point,boundary,in_boundary?,topology_relative_boundary).

View answer and explanation

(1, [1, 2, 3, 4], Yes, topology_relative_boundary)

Compute the complete topology-relative boundary first, then test the point. Do not infer boundary status from an unstated metric or a drawing. The exact result, retaining the requested order, is (1, [1, 2, 3, 4], Yes, topology_relative_boundary).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-membership · candidate

39. Boundary Membership Is Not Just Membership in the Original Set

Use the complete finite topology=[[], [0], [0, 3], [0, 1, 3], [0, 1, 3, 4], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. Subset=[1, 3], point=4. Give (point,boundary,in_boundary?,topology_relative_boundary).

View answer and explanation

(4, [1, 2, 3, 4], Yes, topology_relative_boundary)

Compute the complete topology-relative boundary first, then test the point. Do not infer boundary status from an unstated metric or a drawing. The exact result, retaining the requested order, is (4, [1, 2, 3, 4], Yes, topology_relative_boundary).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-membership · candidate

40. Boundary Membership Is Not Just Membership in the Original Set

Use the complete finite topology=[[], [0], [0, 3], [0, 2, 3], [0, 1, 2, 3], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. Subset=[2, 3], point=4. Give (point,boundary,in_boundary?,topology_relative_boundary).

View answer and explanation

(4, [1, 2, 3, 4], Yes, topology_relative_boundary)

Compute the complete topology-relative boundary first, then test the point. Do not infer boundary status from an unstated metric or a drawing. The exact result, retaining the requested order, is (4, [1, 2, 3, 4], Yes, topology_relative_boundary).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-membership · candidate

41. Boundary Membership Is Not Just Membership in the Original Set

Use the complete finite topology=[[], [0], [0, 3], [0, 2, 3], [0, 2, 3, 4], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. Subset=[2, 3], point=0. Give (point,boundary,in_boundary?,topology_relative_boundary).

View answer and explanation

(0, [1, 2, 3, 4], No, topology_relative_boundary)

Compute the complete topology-relative boundary first, then test the point. Do not infer boundary status from an unstated metric or a drawing. The exact result, retaining the requested order, is (0, [1, 2, 3, 4], No, topology_relative_boundary).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-membership · candidate

42. Boundary Membership Is Not Just Membership in the Original Set

Use the complete finite topology=[[], [0], [0, 3], [0, 3, 4], [0, 1, 3, 4], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. Subset=[3, 4], point=3. Give (point,boundary,in_boundary?,topology_relative_boundary).

View answer and explanation

(3, [1, 2, 3, 4], Yes, topology_relative_boundary)

Compute the complete topology-relative boundary first, then test the point. Do not infer boundary status from an unstated metric or a drawing. The exact result, retaining the requested order, is (3, [1, 2, 3, 4], Yes, topology_relative_boundary).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-membership · candidate

43. Boundary Membership Is Not Just Membership in the Original Set

Use the complete finite topology=[[], [0], [0, 3], [0, 3, 4], [0, 2, 3, 4], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. Subset=[3, 4], point=4. Give (point,boundary,in_boundary?,topology_relative_boundary).

View answer and explanation

(4, [1, 2, 3, 4], Yes, topology_relative_boundary)

Compute the complete topology-relative boundary first, then test the point. Do not infer boundary status from an unstated metric or a drawing. The exact result, retaining the requested order, is (4, [1, 2, 3, 4], Yes, topology_relative_boundary).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-membership · candidate

44. Boundary Membership Is Not Just Membership in the Original Set

Use the complete finite topology=[[], [0], [0, 4], [0, 1, 4], [0, 1, 2, 4], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. Subset=[1, 4], point=2. Give (point,boundary,in_boundary?,topology_relative_boundary).

View answer and explanation

(2, [1, 2, 3, 4], Yes, topology_relative_boundary)

Compute the complete topology-relative boundary first, then test the point. Do not infer boundary status from an unstated metric or a drawing. The exact result, retaining the requested order, is (2, [1, 2, 3, 4], Yes, topology_relative_boundary).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-membership · candidate

45. Boundary Membership Is Not Just Membership in the Original Set

Use the complete finite topology=[[], [0], [0, 4], [0, 1, 4], [0, 1, 3, 4], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. Subset=[1, 4], point=2. Give (point,boundary,in_boundary?,topology_relative_boundary).

View answer and explanation

(2, [1, 2, 3, 4], Yes, topology_relative_boundary)

Compute the complete topology-relative boundary first, then test the point. Do not infer boundary status from an unstated metric or a drawing. The exact result, retaining the requested order, is (2, [1, 2, 3, 4], Yes, topology_relative_boundary).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-membership · candidate

46. Boundary Membership Is Not Just Membership in the Original Set

Use the complete finite topology=[[], [0], [0, 4], [0, 2, 4], [0, 1, 2, 4], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. Subset=[2, 4], point=0. Give (point,boundary,in_boundary?,topology_relative_boundary).

View answer and explanation

(0, [1, 2, 3, 4], No, topology_relative_boundary)

Compute the complete topology-relative boundary first, then test the point. Do not infer boundary status from an unstated metric or a drawing. The exact result, retaining the requested order, is (0, [1, 2, 3, 4], No, topology_relative_boundary).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-membership · candidate

47. Boundary Membership Is Not Just Membership in the Original Set

Use the complete finite topology=[[], [0], [0, 4], [0, 2, 4], [0, 2, 3, 4], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. Subset=[2, 4], point=4. Give (point,boundary,in_boundary?,topology_relative_boundary).

View answer and explanation

(4, [1, 2, 3, 4], Yes, topology_relative_boundary)

Compute the complete topology-relative boundary first, then test the point. Do not infer boundary status from an unstated metric or a drawing. The exact result, retaining the requested order, is (4, [1, 2, 3, 4], Yes, topology_relative_boundary).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-membership · candidate

48. Boundary Membership Is Not Just Membership in the Original Set

Use the complete finite topology=[[], [0], [0, 4], [0, 3, 4], [0, 1, 3, 4], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. Subset=[3, 4], point=3. Give (point,boundary,in_boundary?,topology_relative_boundary).

View answer and explanation

(3, [1, 2, 3, 4], Yes, topology_relative_boundary)

Compute the complete topology-relative boundary first, then test the point. Do not infer boundary status from an unstated metric or a drawing. The exact result, retaining the requested order, is (3, [1, 2, 3, 4], Yes, topology_relative_boundary).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-membership · candidate

49. Boundary Membership Is Not Just Membership in the Original Set

Use the complete finite topology=[[], [0], [0, 4], [0, 3, 4], [0, 2, 3, 4], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. Subset=[3, 4], point=2. Give (point,boundary,in_boundary?,topology_relative_boundary).

View answer and explanation

(2, [1, 2, 3, 4], Yes, topology_relative_boundary)

Compute the complete topology-relative boundary first, then test the point. Do not infer boundary status from an unstated metric or a drawing. The exact result, retaining the requested order, is (2, [1, 2, 3, 4], Yes, topology_relative_boundary).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-membership · candidate

50. Boundary Membership Is Not Just Membership in the Original Set

Use the complete finite topology=[[], [1], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. Subset=[0, 2], point=4. Give (point,boundary,in_boundary?,topology_relative_boundary).

View answer and explanation

(4, [0, 2, 3, 4], Yes, topology_relative_boundary)

Compute the complete topology-relative boundary first, then test the point. Do not infer boundary status from an unstated metric or a drawing. The exact result, retaining the requested order, is (4, [0, 2, 3, 4], Yes, topology_relative_boundary).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-membership · candidate

51. A Set and Its Complement Have the Same Topological Boundary

Use the complete finite topology=[[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. Subset=[1, 2]. Give (subset,complement,boundary_a,boundary_complement,equal?).

View answer and explanation

([1, 2], [0, 3, 4], [1, 2, 3, 4], [1, 2, 3, 4], Yes)

Form the complement in the same carrier and independently compute both closure-minus-interior boundaries. Their equality concerns this same topology, not two different ambient spaces. The exact result, retaining the requested order, is ([1, 2], [0, 3, 4], [1, 2, 3, 4], [1, 2, 3, 4], Yes).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-complement-invariance · candidate

52. A Set and Its Complement Have the Same Topological Boundary

Use the complete finite topology=[[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 4], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. Subset=[1, 2]. Give (subset,complement,boundary_a,boundary_complement,equal?).

View answer and explanation

([1, 2], [0, 3, 4], [1, 2, 3, 4], [1, 2, 3, 4], Yes)

Form the complement in the same carrier and independently compute both closure-minus-interior boundaries. Their equality concerns this same topology, not two different ambient spaces. The exact result, retaining the requested order, is ([1, 2], [0, 3, 4], [1, 2, 3, 4], [1, 2, 3, 4], Yes).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-complement-invariance · candidate

53. A Set and Its Complement Have the Same Topological Boundary

Use the complete finite topology=[[], [0], [0, 1], [0, 1, 3], [0, 1, 2, 3], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. Subset=[1, 3]. Give (subset,complement,boundary_a,boundary_complement,equal?).

View answer and explanation

([1, 3], [0, 2, 4], [1, 2, 3, 4], [1, 2, 3, 4], Yes)

Form the complement in the same carrier and independently compute both closure-minus-interior boundaries. Their equality concerns this same topology, not two different ambient spaces. The exact result, retaining the requested order, is ([1, 3], [0, 2, 4], [1, 2, 3, 4], [1, 2, 3, 4], Yes).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-complement-invariance · candidate

54. A Set and Its Complement Have the Same Topological Boundary

Use the complete finite topology=[[], [0], [0, 1], [0, 1, 3], [0, 1, 3, 4], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. Subset=[1, 3]. Give (subset,complement,boundary_a,boundary_complement,equal?).

View answer and explanation

([1, 3], [0, 2, 4], [1, 2, 3, 4], [1, 2, 3, 4], Yes)

Form the complement in the same carrier and independently compute both closure-minus-interior boundaries. Their equality concerns this same topology, not two different ambient spaces. The exact result, retaining the requested order, is ([1, 3], [0, 2, 4], [1, 2, 3, 4], [1, 2, 3, 4], Yes).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-complement-invariance · candidate

55. A Set and Its Complement Have the Same Topological Boundary

Use the complete finite topology=[[], [0], [0, 1], [0, 1, 4], [0, 1, 2, 4], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. Subset=[1, 4]. Give (subset,complement,boundary_a,boundary_complement,equal?).

View answer and explanation

([1, 4], [0, 2, 3], [1, 2, 3, 4], [1, 2, 3, 4], Yes)

Form the complement in the same carrier and independently compute both closure-minus-interior boundaries. Their equality concerns this same topology, not two different ambient spaces. The exact result, retaining the requested order, is ([1, 4], [0, 2, 3], [1, 2, 3, 4], [1, 2, 3, 4], Yes).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-complement-invariance · candidate

56. A Set and Its Complement Have the Same Topological Boundary

Use the complete finite topology=[[], [0], [0, 1], [0, 1, 4], [0, 1, 3, 4], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. Subset=[1, 4]. Give (subset,complement,boundary_a,boundary_complement,equal?).

View answer and explanation

([1, 4], [0, 2, 3], [1, 2, 3, 4], [1, 2, 3, 4], Yes)

Form the complement in the same carrier and independently compute both closure-minus-interior boundaries. Their equality concerns this same topology, not two different ambient spaces. The exact result, retaining the requested order, is ([1, 4], [0, 2, 3], [1, 2, 3, 4], [1, 2, 3, 4], Yes).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-complement-invariance · candidate

57. A Set and Its Complement Have the Same Topological Boundary

Use the complete finite topology=[[], [0], [0, 2], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. Subset=[1, 2]. Give (subset,complement,boundary_a,boundary_complement,equal?).

View answer and explanation

([1, 2], [0, 3, 4], [1, 2, 3, 4], [1, 2, 3, 4], Yes)

Form the complement in the same carrier and independently compute both closure-minus-interior boundaries. Their equality concerns this same topology, not two different ambient spaces. The exact result, retaining the requested order, is ([1, 2], [0, 3, 4], [1, 2, 3, 4], [1, 2, 3, 4], Yes).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-complement-invariance · candidate

58. A Set and Its Complement Have the Same Topological Boundary

Use the complete finite topology=[[], [0], [0, 2], [0, 1, 2], [0, 1, 2, 4], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. Subset=[1, 2]. Give (subset,complement,boundary_a,boundary_complement,equal?).

View answer and explanation

([1, 2], [0, 3, 4], [1, 2, 3, 4], [1, 2, 3, 4], Yes)

Form the complement in the same carrier and independently compute both closure-minus-interior boundaries. Their equality concerns this same topology, not two different ambient spaces. The exact result, retaining the requested order, is ([1, 2], [0, 3, 4], [1, 2, 3, 4], [1, 2, 3, 4], Yes).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-complement-invariance · candidate

59. A Set and Its Complement Have the Same Topological Boundary

Use the complete finite topology=[[], [0], [0, 2], [0, 2, 3], [0, 1, 2, 3], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. Subset=[2, 3]. Give (subset,complement,boundary_a,boundary_complement,equal?).

View answer and explanation

([2, 3], [0, 1, 4], [1, 2, 3, 4], [1, 2, 3, 4], Yes)

Form the complement in the same carrier and independently compute both closure-minus-interior boundaries. Their equality concerns this same topology, not two different ambient spaces. The exact result, retaining the requested order, is ([2, 3], [0, 1, 4], [1, 2, 3, 4], [1, 2, 3, 4], Yes).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-complement-invariance · candidate

60. A Set and Its Complement Have the Same Topological Boundary

Use the complete finite topology=[[], [0], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. Subset=[2, 3]. Give (subset,complement,boundary_a,boundary_complement,equal?).

View answer and explanation

([2, 3], [0, 1, 4], [1, 2, 3, 4], [1, 2, 3, 4], Yes)

Form the complement in the same carrier and independently compute both closure-minus-interior boundaries. Their equality concerns this same topology, not two different ambient spaces. The exact result, retaining the requested order, is ([2, 3], [0, 1, 4], [1, 2, 3, 4], [1, 2, 3, 4], Yes).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-complement-invariance · candidate

61. A Set and Its Complement Have the Same Topological Boundary

Use the complete finite topology=[[], [0], [0, 2], [0, 2, 4], [0, 1, 2, 4], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. Subset=[2, 4]. Give (subset,complement,boundary_a,boundary_complement,equal?).

View answer and explanation

([2, 4], [0, 1, 3], [1, 2, 3, 4], [1, 2, 3, 4], Yes)

Form the complement in the same carrier and independently compute both closure-minus-interior boundaries. Their equality concerns this same topology, not two different ambient spaces. The exact result, retaining the requested order, is ([2, 4], [0, 1, 3], [1, 2, 3, 4], [1, 2, 3, 4], Yes).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-complement-invariance · candidate

62. A Set and Its Complement Have the Same Topological Boundary

Use the complete finite topology=[[], [0], [0, 2], [0, 2, 4], [0, 2, 3, 4], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. Subset=[2, 4]. Give (subset,complement,boundary_a,boundary_complement,equal?).

View answer and explanation

([2, 4], [0, 1, 3], [1, 2, 3, 4], [1, 2, 3, 4], Yes)

Form the complement in the same carrier and independently compute both closure-minus-interior boundaries. Their equality concerns this same topology, not two different ambient spaces. The exact result, retaining the requested order, is ([2, 4], [0, 1, 3], [1, 2, 3, 4], [1, 2, 3, 4], Yes).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-complement-invariance · candidate

63. A Set and Its Complement Have the Same Topological Boundary

Use the complete finite topology=[[], [0], [0, 3], [0, 1, 3], [0, 1, 2, 3], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. Subset=[1, 3]. Give (subset,complement,boundary_a,boundary_complement,equal?).

View answer and explanation

([1, 3], [0, 2, 4], [1, 2, 3, 4], [1, 2, 3, 4], Yes)

Form the complement in the same carrier and independently compute both closure-minus-interior boundaries. Their equality concerns this same topology, not two different ambient spaces. The exact result, retaining the requested order, is ([1, 3], [0, 2, 4], [1, 2, 3, 4], [1, 2, 3, 4], Yes).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-complement-invariance · candidate

64. A Set and Its Complement Have the Same Topological Boundary

Use the complete finite topology=[[], [0], [0, 3], [0, 1, 3], [0, 1, 3, 4], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. Subset=[1, 3]. Give (subset,complement,boundary_a,boundary_complement,equal?).

View answer and explanation

([1, 3], [0, 2, 4], [1, 2, 3, 4], [1, 2, 3, 4], Yes)

Form the complement in the same carrier and independently compute both closure-minus-interior boundaries. Their equality concerns this same topology, not two different ambient spaces. The exact result, retaining the requested order, is ([1, 3], [0, 2, 4], [1, 2, 3, 4], [1, 2, 3, 4], Yes).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-complement-invariance · candidate

65. A Set and Its Complement Have the Same Topological Boundary

Use the complete finite topology=[[], [0], [0, 3], [0, 2, 3], [0, 1, 2, 3], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. Subset=[2, 3]. Give (subset,complement,boundary_a,boundary_complement,equal?).

View answer and explanation

([2, 3], [0, 1, 4], [1, 2, 3, 4], [1, 2, 3, 4], Yes)

Form the complement in the same carrier and independently compute both closure-minus-interior boundaries. Their equality concerns this same topology, not two different ambient spaces. The exact result, retaining the requested order, is ([2, 3], [0, 1, 4], [1, 2, 3, 4], [1, 2, 3, 4], Yes).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-complement-invariance · candidate

66. A Set and Its Complement Have the Same Topological Boundary

Use the complete finite topology=[[], [0], [0, 3], [0, 2, 3], [0, 2, 3, 4], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. Subset=[2, 3]. Give (subset,complement,boundary_a,boundary_complement,equal?).

View answer and explanation

([2, 3], [0, 1, 4], [1, 2, 3, 4], [1, 2, 3, 4], Yes)

Form the complement in the same carrier and independently compute both closure-minus-interior boundaries. Their equality concerns this same topology, not two different ambient spaces. The exact result, retaining the requested order, is ([2, 3], [0, 1, 4], [1, 2, 3, 4], [1, 2, 3, 4], Yes).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-complement-invariance · candidate

67. A Set and Its Complement Have the Same Topological Boundary

Use the complete finite topology=[[], [0], [0, 3], [0, 3, 4], [0, 1, 3, 4], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. Subset=[3, 4]. Give (subset,complement,boundary_a,boundary_complement,equal?).

View answer and explanation

([3, 4], [0, 1, 2], [1, 2, 3, 4], [1, 2, 3, 4], Yes)

Form the complement in the same carrier and independently compute both closure-minus-interior boundaries. Their equality concerns this same topology, not two different ambient spaces. The exact result, retaining the requested order, is ([3, 4], [0, 1, 2], [1, 2, 3, 4], [1, 2, 3, 4], Yes).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-complement-invariance · candidate

68. A Set and Its Complement Have the Same Topological Boundary

Use the complete finite topology=[[], [0], [0, 3], [0, 3, 4], [0, 2, 3, 4], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. Subset=[3, 4]. Give (subset,complement,boundary_a,boundary_complement,equal?).

View answer and explanation

([3, 4], [0, 1, 2], [1, 2, 3, 4], [1, 2, 3, 4], Yes)

Form the complement in the same carrier and independently compute both closure-minus-interior boundaries. Their equality concerns this same topology, not two different ambient spaces. The exact result, retaining the requested order, is ([3, 4], [0, 1, 2], [1, 2, 3, 4], [1, 2, 3, 4], Yes).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-complement-invariance · candidate

69. A Set and Its Complement Have the Same Topological Boundary

Use the complete finite topology=[[], [0], [0, 4], [0, 1, 4], [0, 1, 2, 4], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. Subset=[1, 4]. Give (subset,complement,boundary_a,boundary_complement,equal?).

View answer and explanation

([1, 4], [0, 2, 3], [1, 2, 3, 4], [1, 2, 3, 4], Yes)

Form the complement in the same carrier and independently compute both closure-minus-interior boundaries. Their equality concerns this same topology, not two different ambient spaces. The exact result, retaining the requested order, is ([1, 4], [0, 2, 3], [1, 2, 3, 4], [1, 2, 3, 4], Yes).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-complement-invariance · candidate

70. A Set and Its Complement Have the Same Topological Boundary

Use the complete finite topology=[[], [0], [0, 4], [0, 1, 4], [0, 1, 3, 4], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. Subset=[1, 4]. Give (subset,complement,boundary_a,boundary_complement,equal?).

View answer and explanation

([1, 4], [0, 2, 3], [1, 2, 3, 4], [1, 2, 3, 4], Yes)

Form the complement in the same carrier and independently compute both closure-minus-interior boundaries. Their equality concerns this same topology, not two different ambient spaces. The exact result, retaining the requested order, is ([1, 4], [0, 2, 3], [1, 2, 3, 4], [1, 2, 3, 4], Yes).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-complement-invariance · candidate

71. A Set and Its Complement Have the Same Topological Boundary

Use the complete finite topology=[[], [0], [0, 4], [0, 2, 4], [0, 1, 2, 4], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. Subset=[2, 4]. Give (subset,complement,boundary_a,boundary_complement,equal?).

View answer and explanation

([2, 4], [0, 1, 3], [1, 2, 3, 4], [1, 2, 3, 4], Yes)

Form the complement in the same carrier and independently compute both closure-minus-interior boundaries. Their equality concerns this same topology, not two different ambient spaces. The exact result, retaining the requested order, is ([2, 4], [0, 1, 3], [1, 2, 3, 4], [1, 2, 3, 4], Yes).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-complement-invariance · candidate

72. A Set and Its Complement Have the Same Topological Boundary

Use the complete finite topology=[[], [0], [0, 4], [0, 2, 4], [0, 2, 3, 4], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. Subset=[2, 4]. Give (subset,complement,boundary_a,boundary_complement,equal?).

View answer and explanation

([2, 4], [0, 1, 3], [1, 2, 3, 4], [1, 2, 3, 4], Yes)

Form the complement in the same carrier and independently compute both closure-minus-interior boundaries. Their equality concerns this same topology, not two different ambient spaces. The exact result, retaining the requested order, is ([2, 4], [0, 1, 3], [1, 2, 3, 4], [1, 2, 3, 4], Yes).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-complement-invariance · candidate

73. A Set and Its Complement Have the Same Topological Boundary

Use the complete finite topology=[[], [0], [0, 4], [0, 3, 4], [0, 1, 3, 4], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. Subset=[3, 4]. Give (subset,complement,boundary_a,boundary_complement,equal?).

View answer and explanation

([3, 4], [0, 1, 2], [1, 2, 3, 4], [1, 2, 3, 4], Yes)

Form the complement in the same carrier and independently compute both closure-minus-interior boundaries. Their equality concerns this same topology, not two different ambient spaces. The exact result, retaining the requested order, is ([3, 4], [0, 1, 2], [1, 2, 3, 4], [1, 2, 3, 4], Yes).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-complement-invariance · candidate

74. A Set and Its Complement Have the Same Topological Boundary

Use the complete finite topology=[[], [0], [0, 4], [0, 3, 4], [0, 2, 3, 4], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. Subset=[3, 4]. Give (subset,complement,boundary_a,boundary_complement,equal?).

View answer and explanation

([3, 4], [0, 1, 2], [1, 2, 3, 4], [1, 2, 3, 4], Yes)

Form the complement in the same carrier and independently compute both closure-minus-interior boundaries. Their equality concerns this same topology, not two different ambient spaces. The exact result, retaining the requested order, is ([3, 4], [0, 1, 2], [1, 2, 3, 4], [1, 2, 3, 4], Yes).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-complement-invariance · candidate

75. A Set and Its Complement Have the Same Topological Boundary

Use the complete finite topology=[[], [1], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. Subset=[0, 2]. Give (subset,complement,boundary_a,boundary_complement,equal?).

View answer and explanation

([0, 2], [1, 3, 4], [0, 2, 3, 4], [0, 2, 3, 4], Yes)

Form the complement in the same carrier and independently compute both closure-minus-interior boundaries. Their equality concerns this same topology, not two different ambient spaces. The exact result, retaining the requested order, is ([0, 2], [1, 3, 4], [0, 2, 3, 4], [0, 2, 3, 4], Yes).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-complement-invariance · candidate

76. Empty and Whole Sets Both Have Empty Boundary

Use the complete finite topology=[[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. which=empty, restricted to empty or whole. Give (which,subset,boundary,empty?).

View answer and explanation

(empty, [], [], Yes)

Use the indicated empty subset or complete carrier. Both are open and closed in this topology, so closure minus interior is empty. The exact result, retaining the requested order, is (empty, [], [], Yes).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-empty-whole · candidate

77. Empty and Whole Sets Both Have Empty Boundary

Use the complete finite topology=[[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 4], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. which=whole, restricted to empty or whole. Give (which,subset,boundary,empty?).

View answer and explanation

(whole, [0, 1, 2, 3, 4], [], Yes)

Use the indicated empty subset or complete carrier. Both are open and closed in this topology, so closure minus interior is empty. The exact result, retaining the requested order, is (whole, [0, 1, 2, 3, 4], [], Yes).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-empty-whole · candidate

78. Empty and Whole Sets Both Have Empty Boundary

Use the complete finite topology=[[], [0], [0, 1], [0, 1, 3], [0, 1, 2, 3], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. which=empty, restricted to empty or whole. Give (which,subset,boundary,empty?).

View answer and explanation

(empty, [], [], Yes)

Use the indicated empty subset or complete carrier. Both are open and closed in this topology, so closure minus interior is empty. The exact result, retaining the requested order, is (empty, [], [], Yes).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-empty-whole · candidate

79. Empty and Whole Sets Both Have Empty Boundary

Use the complete finite topology=[[], [0], [0, 1], [0, 1, 3], [0, 1, 3, 4], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. which=whole, restricted to empty or whole. Give (which,subset,boundary,empty?).

View answer and explanation

(whole, [0, 1, 2, 3, 4], [], Yes)

Use the indicated empty subset or complete carrier. Both are open and closed in this topology, so closure minus interior is empty. The exact result, retaining the requested order, is (whole, [0, 1, 2, 3, 4], [], Yes).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-empty-whole · candidate

80. Empty and Whole Sets Both Have Empty Boundary

Use the complete finite topology=[[], [0], [0, 1], [0, 1, 4], [0, 1, 2, 4], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. which=empty, restricted to empty or whole. Give (which,subset,boundary,empty?).

View answer and explanation

(empty, [], [], Yes)

Use the indicated empty subset or complete carrier. Both are open and closed in this topology, so closure minus interior is empty. The exact result, retaining the requested order, is (empty, [], [], Yes).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-empty-whole · candidate

81. Empty and Whole Sets Both Have Empty Boundary

Use the complete finite topology=[[], [0], [0, 1], [0, 1, 4], [0, 1, 3, 4], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. which=whole, restricted to empty or whole. Give (which,subset,boundary,empty?).

View answer and explanation

(whole, [0, 1, 2, 3, 4], [], Yes)

Use the indicated empty subset or complete carrier. Both are open and closed in this topology, so closure minus interior is empty. The exact result, retaining the requested order, is (whole, [0, 1, 2, 3, 4], [], Yes).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-empty-whole · candidate

82. Empty and Whole Sets Both Have Empty Boundary

Use the complete finite topology=[[], [0], [0, 2], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. which=empty, restricted to empty or whole. Give (which,subset,boundary,empty?).

View answer and explanation

(empty, [], [], Yes)

Use the indicated empty subset or complete carrier. Both are open and closed in this topology, so closure minus interior is empty. The exact result, retaining the requested order, is (empty, [], [], Yes).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-empty-whole · candidate

83. Empty and Whole Sets Both Have Empty Boundary

Use the complete finite topology=[[], [0], [0, 2], [0, 1, 2], [0, 1, 2, 4], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. which=whole, restricted to empty or whole. Give (which,subset,boundary,empty?).

View answer and explanation

(whole, [0, 1, 2, 3, 4], [], Yes)

Use the indicated empty subset or complete carrier. Both are open and closed in this topology, so closure minus interior is empty. The exact result, retaining the requested order, is (whole, [0, 1, 2, 3, 4], [], Yes).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-empty-whole · candidate

84. Empty and Whole Sets Both Have Empty Boundary

Use the complete finite topology=[[], [0], [0, 2], [0, 2, 3], [0, 1, 2, 3], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. which=empty, restricted to empty or whole. Give (which,subset,boundary,empty?).

View answer and explanation

(empty, [], [], Yes)

Use the indicated empty subset or complete carrier. Both are open and closed in this topology, so closure minus interior is empty. The exact result, retaining the requested order, is (empty, [], [], Yes).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-empty-whole · candidate

85. Empty and Whole Sets Both Have Empty Boundary

Use the complete finite topology=[[], [0], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. which=whole, restricted to empty or whole. Give (which,subset,boundary,empty?).

View answer and explanation

(whole, [0, 1, 2, 3, 4], [], Yes)

Use the indicated empty subset or complete carrier. Both are open and closed in this topology, so closure minus interior is empty. The exact result, retaining the requested order, is (whole, [0, 1, 2, 3, 4], [], Yes).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-empty-whole · candidate

86. Empty and Whole Sets Both Have Empty Boundary

Use the complete finite topology=[[], [0], [0, 2], [0, 2, 4], [0, 1, 2, 4], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. which=empty, restricted to empty or whole. Give (which,subset,boundary,empty?).

View answer and explanation

(empty, [], [], Yes)

Use the indicated empty subset or complete carrier. Both are open and closed in this topology, so closure minus interior is empty. The exact result, retaining the requested order, is (empty, [], [], Yes).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-empty-whole · candidate

87. Empty and Whole Sets Both Have Empty Boundary

Use the complete finite topology=[[], [0], [0, 2], [0, 2, 4], [0, 2, 3, 4], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. which=whole, restricted to empty or whole. Give (which,subset,boundary,empty?).

View answer and explanation

(whole, [0, 1, 2, 3, 4], [], Yes)

Use the indicated empty subset or complete carrier. Both are open and closed in this topology, so closure minus interior is empty. The exact result, retaining the requested order, is (whole, [0, 1, 2, 3, 4], [], Yes).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-empty-whole · candidate

88. Empty and Whole Sets Both Have Empty Boundary

Use the complete finite topology=[[], [0], [0, 3], [0, 1, 3], [0, 1, 2, 3], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. which=empty, restricted to empty or whole. Give (which,subset,boundary,empty?).

View answer and explanation

(empty, [], [], Yes)

Use the indicated empty subset or complete carrier. Both are open and closed in this topology, so closure minus interior is empty. The exact result, retaining the requested order, is (empty, [], [], Yes).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-empty-whole · candidate

89. Empty and Whole Sets Both Have Empty Boundary

Use the complete finite topology=[[], [0], [0, 3], [0, 1, 3], [0, 1, 3, 4], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. which=whole, restricted to empty or whole. Give (which,subset,boundary,empty?).

View answer and explanation

(whole, [0, 1, 2, 3, 4], [], Yes)

Use the indicated empty subset or complete carrier. Both are open and closed in this topology, so closure minus interior is empty. The exact result, retaining the requested order, is (whole, [0, 1, 2, 3, 4], [], Yes).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-empty-whole · candidate

90. Empty and Whole Sets Both Have Empty Boundary

Use the complete finite topology=[[], [0], [0, 3], [0, 2, 3], [0, 1, 2, 3], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. which=empty, restricted to empty or whole. Give (which,subset,boundary,empty?).

View answer and explanation

(empty, [], [], Yes)

Use the indicated empty subset or complete carrier. Both are open and closed in this topology, so closure minus interior is empty. The exact result, retaining the requested order, is (empty, [], [], Yes).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-empty-whole · candidate

91. Empty and Whole Sets Both Have Empty Boundary

Use the complete finite topology=[[], [0], [0, 3], [0, 2, 3], [0, 2, 3, 4], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. which=whole, restricted to empty or whole. Give (which,subset,boundary,empty?).

View answer and explanation

(whole, [0, 1, 2, 3, 4], [], Yes)

Use the indicated empty subset or complete carrier. Both are open and closed in this topology, so closure minus interior is empty. The exact result, retaining the requested order, is (whole, [0, 1, 2, 3, 4], [], Yes).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-empty-whole · candidate

92. Empty and Whole Sets Both Have Empty Boundary

Use the complete finite topology=[[], [0], [0, 3], [0, 3, 4], [0, 1, 3, 4], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. which=empty, restricted to empty or whole. Give (which,subset,boundary,empty?).

View answer and explanation

(empty, [], [], Yes)

Use the indicated empty subset or complete carrier. Both are open and closed in this topology, so closure minus interior is empty. The exact result, retaining the requested order, is (empty, [], [], Yes).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-empty-whole · candidate

93. Empty and Whole Sets Both Have Empty Boundary

Use the complete finite topology=[[], [0], [0, 3], [0, 3, 4], [0, 2, 3, 4], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. which=whole, restricted to empty or whole. Give (which,subset,boundary,empty?).

View answer and explanation

(whole, [0, 1, 2, 3, 4], [], Yes)

Use the indicated empty subset or complete carrier. Both are open and closed in this topology, so closure minus interior is empty. The exact result, retaining the requested order, is (whole, [0, 1, 2, 3, 4], [], Yes).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-empty-whole · candidate

94. Empty and Whole Sets Both Have Empty Boundary

Use the complete finite topology=[[], [0], [0, 4], [0, 1, 4], [0, 1, 2, 4], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. which=empty, restricted to empty or whole. Give (which,subset,boundary,empty?).

View answer and explanation

(empty, [], [], Yes)

Use the indicated empty subset or complete carrier. Both are open and closed in this topology, so closure minus interior is empty. The exact result, retaining the requested order, is (empty, [], [], Yes).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-empty-whole · candidate

95. Empty and Whole Sets Both Have Empty Boundary

Use the complete finite topology=[[], [0], [0, 4], [0, 1, 4], [0, 1, 3, 4], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. which=whole, restricted to empty or whole. Give (which,subset,boundary,empty?).

View answer and explanation

(whole, [0, 1, 2, 3, 4], [], Yes)

Use the indicated empty subset or complete carrier. Both are open and closed in this topology, so closure minus interior is empty. The exact result, retaining the requested order, is (whole, [0, 1, 2, 3, 4], [], Yes).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-empty-whole · candidate

96. Empty and Whole Sets Both Have Empty Boundary

Use the complete finite topology=[[], [0], [0, 4], [0, 2, 4], [0, 1, 2, 4], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. which=empty, restricted to empty or whole. Give (which,subset,boundary,empty?).

View answer and explanation

(empty, [], [], Yes)

Use the indicated empty subset or complete carrier. Both are open and closed in this topology, so closure minus interior is empty. The exact result, retaining the requested order, is (empty, [], [], Yes).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-empty-whole · candidate

97. Empty and Whole Sets Both Have Empty Boundary

Use the complete finite topology=[[], [0], [0, 4], [0, 2, 4], [0, 2, 3, 4], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. which=whole, restricted to empty or whole. Give (which,subset,boundary,empty?).

View answer and explanation

(whole, [0, 1, 2, 3, 4], [], Yes)

Use the indicated empty subset or complete carrier. Both are open and closed in this topology, so closure minus interior is empty. The exact result, retaining the requested order, is (whole, [0, 1, 2, 3, 4], [], Yes).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-empty-whole · candidate

98. Empty and Whole Sets Both Have Empty Boundary

Use the complete finite topology=[[], [0], [0, 4], [0, 3, 4], [0, 1, 3, 4], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. which=empty, restricted to empty or whole. Give (which,subset,boundary,empty?).

View answer and explanation

(empty, [], [], Yes)

Use the indicated empty subset or complete carrier. Both are open and closed in this topology, so closure minus interior is empty. The exact result, retaining the requested order, is (empty, [], [], Yes).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-empty-whole · candidate

99. Empty and Whole Sets Both Have Empty Boundary

Use the complete finite topology=[[], [0], [0, 4], [0, 3, 4], [0, 2, 3, 4], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. which=whole, restricted to empty or whole. Give (which,subset,boundary,empty?).

View answer and explanation

(whole, [0, 1, 2, 3, 4], [], Yes)

Use the indicated empty subset or complete carrier. Both are open and closed in this topology, so closure minus interior is empty. The exact result, retaining the requested order, is (whole, [0, 1, 2, 3, 4], [], Yes).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-empty-whole · candidate

100. Empty and Whole Sets Both Have Empty Boundary

Use the complete finite topology=[[], [1], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4]] on the same carrier Fin(5)={0,…,4}. Each subset is an increasing duplicate-free carrier list. Validate the unique empty/whole opens and all finite union/intersection closure obligations first. All complements, closed sets, closures, interiors and boundaries refer to this same carrier/topology; no metric or visual boundary is silently supplied. which=empty, restricted to empty or whole. Give (which,subset,boundary,empty?).

View answer and explanation

(empty, [], [], Yes)

Use the indicated empty subset or complete carrier. Both are open and closed in this topology, so closure minus interior is empty. The exact result, retaining the requested order, is (empty, [], [], Yes).

Reviewed step-by-step derivation

Topological boundary · qf-mod33-boundary-empty-whole · candidate

Canonical question JSONL · English JSONL · Validation report