Complete Point Stabilizers, Subgroup Closure and Membership Boundaries

This batch has passed Schema, deduplication, source-snapshot, and independent-answer recomputation checks; it is still not marked as human-reviewed.

This question bank has corresponding bilingual step-by-step derivations. Source candidate and English ai_candidate states are retained. AI review, finite computation and Lean formal proof are labelled separately.

batch-20261014-advance-20261109-r01-finite-group-stabilizer-foundations · 2026-10-14 · 100 questions

This English edition is an AI candidate and does not yet have an OCME Atlas (GPT-6) Twin closure receipt.

Field order uses a source-bound presentation supplement; canonical JSONL and mathematical answers are unchanged.

Field-order and source-binding data

1. The Point Stabilizer Enumerates Every Fixing Group Element

Use complete group table=[[0, 1], [1, 0]], identity=0, point carrier Fin(2)={0,…,1} and total action_table=[[0, 1], [1, 0]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=0. Give (point, stabilizer, stabilizer_order, full_enumeration_certificate, certificate).

View answer and explanation

(0, [0], 1, Yes, all_group_elements_checked)

Enumerate every g with g*x=x and retain them in group-index order. The result is a subgroup of G, not the orbit in the point carrier or merely one fixed-element witness. The exact result, retaining the requested order, is (0, [0], 1, Yes, all_group_elements_checked).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-stabilizer-of-point · candidate

2. The Point Stabilizer Enumerates Every Fixing Group Element

Use complete group table=[[0, 1, 2], [1, 2, 0], [2, 0, 1]], identity=0, point carrier Fin(3)={0,…,2} and total action_table=[[0, 1, 2], [1, 2, 0], [2, 0, 1]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=1. Give (point, stabilizer, stabilizer_order, full_enumeration_certificate, certificate).

View answer and explanation

(1, [0], 1, Yes, all_group_elements_checked)

Enumerate every g with g*x=x and retain them in group-index order. The result is a subgroup of G, not the orbit in the point carrier or merely one fixed-element witness. The exact result, retaining the requested order, is (1, [0], 1, Yes, all_group_elements_checked).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-stabilizer-of-point · candidate

3. The Point Stabilizer Enumerates Every Fixing Group Element

Use complete group table=[[0, 1, 2, 3], [1, 2, 3, 0], [2, 3, 0, 1], [3, 0, 1, 2]], identity=0, point carrier Fin(4)={0,…,3} and total action_table=[[0, 1, 2, 3], [1, 2, 3, 0], [2, 3, 0, 1], [3, 0, 1, 2]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=2. Give (point, stabilizer, stabilizer_order, full_enumeration_certificate, certificate).

View answer and explanation

(2, [0], 1, Yes, all_group_elements_checked)

Enumerate every g with g*x=x and retain them in group-index order. The result is a subgroup of G, not the orbit in the point carrier or merely one fixed-element witness. The exact result, retaining the requested order, is (2, [0], 1, Yes, all_group_elements_checked).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-stabilizer-of-point · candidate

4. The Point Stabilizer Enumerates Every Fixing Group Element

Use complete group table=[[0, 1, 2, 3, 4], [1, 2, 3, 4, 0], [2, 3, 4, 0, 1], [3, 4, 0, 1, 2], [4, 0, 1, 2, 3]], identity=0, point carrier Fin(5)={0,…,4} and total action_table=[[0, 1, 2, 3, 4], [1, 2, 3, 4, 0], [2, 3, 4, 0, 1], [3, 4, 0, 1, 2], [4, 0, 1, 2, 3]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=3. Give (point, stabilizer, stabilizer_order, full_enumeration_certificate, certificate).

View answer and explanation

(3, [0], 1, Yes, all_group_elements_checked)

Enumerate every g with g*x=x and retain them in group-index order. The result is a subgroup of G, not the orbit in the point carrier or merely one fixed-element witness. The exact result, retaining the requested order, is (3, [0], 1, Yes, all_group_elements_checked).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-stabilizer-of-point · candidate

5. The Point Stabilizer Enumerates Every Fixing Group Element

Use complete group table=[[0, 1, 2, 3, 4, 5], [1, 2, 3, 4, 5, 0], [2, 3, 4, 5, 0, 1], [3, 4, 5, 0, 1, 2], [4, 5, 0, 1, 2, 3], [5, 0, 1, 2, 3, 4]], identity=0, point carrier Fin(6)={0,…,5} and total action_table=[[0, 1, 2, 3, 4, 5], [1, 2, 3, 4, 5, 0], [2, 3, 4, 5, 0, 1], [3, 4, 5, 0, 1, 2], [4, 5, 0, 1, 2, 3], [5, 0, 1, 2, 3, 4]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=4. Give (point, stabilizer, stabilizer_order, full_enumeration_certificate, certificate).

View answer and explanation

(4, [0], 1, Yes, all_group_elements_checked)

Enumerate every g with g*x=x and retain them in group-index order. The result is a subgroup of G, not the orbit in the point carrier or merely one fixed-element witness. The exact result, retaining the requested order, is (4, [0], 1, Yes, all_group_elements_checked).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-stabilizer-of-point · candidate

6. The Point Stabilizer Enumerates Every Fixing Group Element

Use complete group table=[[0, 1], [1, 0]], identity=0, point carrier Fin(3)={0,…,2} and total action_table=[[0, 1, 2], [1, 0, 2]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=2. Give (point, stabilizer, stabilizer_order, full_enumeration_certificate, certificate).

View answer and explanation

(2, [0, 1], 2, Yes, all_group_elements_checked)

Enumerate every g with g*x=x and retain them in group-index order. The result is a subgroup of G, not the orbit in the point carrier or merely one fixed-element witness. The exact result, retaining the requested order, is (2, [0, 1], 2, Yes, all_group_elements_checked).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-stabilizer-of-point · candidate

7. The Point Stabilizer Enumerates Every Fixing Group Element

Use complete group table=[[0, 1, 2], [1, 2, 0], [2, 0, 1]], identity=0, point carrier Fin(4)={0,…,3} and total action_table=[[0, 1, 2, 3], [1, 2, 0, 3], [2, 0, 1, 3]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=2. Give (point, stabilizer, stabilizer_order, full_enumeration_certificate, certificate).

View answer and explanation

(2, [0], 1, Yes, all_group_elements_checked)

Enumerate every g with g*x=x and retain them in group-index order. The result is a subgroup of G, not the orbit in the point carrier or merely one fixed-element witness. The exact result, retaining the requested order, is (2, [0], 1, Yes, all_group_elements_checked).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-stabilizer-of-point · candidate

8. The Point Stabilizer Enumerates Every Fixing Group Element

Use complete group table=[[0, 1, 2, 3], [1, 2, 3, 0], [2, 3, 0, 1], [3, 0, 1, 2]], identity=0, point carrier Fin(5)={0,…,4} and total action_table=[[0, 1, 2, 3, 4], [1, 2, 3, 0, 4], [2, 3, 0, 1, 4], [3, 0, 1, 2, 4]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=2. Give (point, stabilizer, stabilizer_order, full_enumeration_certificate, certificate).

View answer and explanation

(2, [0], 1, Yes, all_group_elements_checked)

Enumerate every g with g*x=x and retain them in group-index order. The result is a subgroup of G, not the orbit in the point carrier or merely one fixed-element witness. The exact result, retaining the requested order, is (2, [0], 1, Yes, all_group_elements_checked).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-stabilizer-of-point · candidate

9. The Point Stabilizer Enumerates Every Fixing Group Element

Use complete group table=[[0, 1, 2, 3, 4], [1, 2, 3, 4, 0], [2, 3, 4, 0, 1], [3, 4, 0, 1, 2], [4, 0, 1, 2, 3]], identity=0, point carrier Fin(6)={0,…,5} and total action_table=[[0, 1, 2, 3, 4, 5], [1, 2, 3, 4, 0, 5], [2, 3, 4, 0, 1, 5], [3, 4, 0, 1, 2, 5], [4, 0, 1, 2, 3, 5]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=2. Give (point, stabilizer, stabilizer_order, full_enumeration_certificate, certificate).

View answer and explanation

(2, [0], 1, Yes, all_group_elements_checked)

Enumerate every g with g*x=x and retain them in group-index order. The result is a subgroup of G, not the orbit in the point carrier or merely one fixed-element witness. The exact result, retaining the requested order, is (2, [0], 1, Yes, all_group_elements_checked).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-stabilizer-of-point · candidate

10. The Point Stabilizer Enumerates Every Fixing Group Element

Use complete group table=[[0, 1, 2, 3, 4, 5], [1, 2, 3, 4, 5, 0], [2, 3, 4, 5, 0, 1], [3, 4, 5, 0, 1, 2], [4, 5, 0, 1, 2, 3], [5, 0, 1, 2, 3, 4]], identity=0, point carrier Fin(7)={0,…,6} and total action_table=[[0, 1, 2, 3, 4, 5, 6], [1, 2, 3, 4, 5, 0, 6], [2, 3, 4, 5, 0, 1, 6], [3, 4, 5, 0, 1, 2, 6], [4, 5, 0, 1, 2, 3, 6], [5, 0, 1, 2, 3, 4, 6]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=2. Give (point, stabilizer, stabilizer_order, full_enumeration_certificate, certificate).

View answer and explanation

(2, [0], 1, Yes, all_group_elements_checked)

Enumerate every g with g*x=x and retain them in group-index order. The result is a subgroup of G, not the orbit in the point carrier or merely one fixed-element witness. The exact result, retaining the requested order, is (2, [0], 1, Yes, all_group_elements_checked).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-stabilizer-of-point · candidate

11. The Point Stabilizer Enumerates Every Fixing Group Element

Use complete group table=[[0, 1], [1, 0]], identity=0, point carrier Fin(4)={0,…,3} and total action_table=[[0, 1, 2, 3], [1, 0, 2, 3]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=2. Give (point, stabilizer, stabilizer_order, full_enumeration_certificate, certificate).

View answer and explanation

(2, [0, 1], 2, Yes, all_group_elements_checked)

Enumerate every g with g*x=x and retain them in group-index order. The result is a subgroup of G, not the orbit in the point carrier or merely one fixed-element witness. The exact result, retaining the requested order, is (2, [0, 1], 2, Yes, all_group_elements_checked).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-stabilizer-of-point · candidate

12. The Point Stabilizer Enumerates Every Fixing Group Element

Use complete group table=[[0, 1, 2], [1, 2, 0], [2, 0, 1]], identity=0, point carrier Fin(5)={0,…,4} and total action_table=[[0, 1, 2, 3, 4], [1, 2, 0, 3, 4], [2, 0, 1, 3, 4]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=1. Give (point, stabilizer, stabilizer_order, full_enumeration_certificate, certificate).

View answer and explanation

(1, [0], 1, Yes, all_group_elements_checked)

Enumerate every g with g*x=x and retain them in group-index order. The result is a subgroup of G, not the orbit in the point carrier or merely one fixed-element witness. The exact result, retaining the requested order, is (1, [0], 1, Yes, all_group_elements_checked).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-stabilizer-of-point · candidate

13. The Point Stabilizer Enumerates Every Fixing Group Element

Use complete group table=[[0, 1, 2, 3], [1, 2, 3, 0], [2, 3, 0, 1], [3, 0, 1, 2]], identity=0, point carrier Fin(6)={0,…,5} and total action_table=[[0, 1, 2, 3, 4, 5], [1, 2, 3, 0, 4, 5], [2, 3, 0, 1, 4, 5], [3, 0, 1, 2, 4, 5]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=0. Give (point, stabilizer, stabilizer_order, full_enumeration_certificate, certificate).

View answer and explanation

(0, [0], 1, Yes, all_group_elements_checked)

Enumerate every g with g*x=x and retain them in group-index order. The result is a subgroup of G, not the orbit in the point carrier or merely one fixed-element witness. The exact result, retaining the requested order, is (0, [0], 1, Yes, all_group_elements_checked).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-stabilizer-of-point · candidate

14. The Point Stabilizer Enumerates Every Fixing Group Element

Use complete group table=[[0, 1, 2, 3, 4], [1, 2, 3, 4, 0], [2, 3, 4, 0, 1], [3, 4, 0, 1, 2], [4, 0, 1, 2, 3]], identity=0, point carrier Fin(7)={0,…,6} and total action_table=[[0, 1, 2, 3, 4, 5, 6], [1, 2, 3, 4, 0, 5, 6], [2, 3, 4, 0, 1, 5, 6], [3, 4, 0, 1, 2, 5, 6], [4, 0, 1, 2, 3, 5, 6]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=6. Give (point, stabilizer, stabilizer_order, full_enumeration_certificate, certificate).

View answer and explanation

(6, [0, 1, 2, 3, 4], 5, Yes, all_group_elements_checked)

Enumerate every g with g*x=x and retain them in group-index order. The result is a subgroup of G, not the orbit in the point carrier or merely one fixed-element witness. The exact result, retaining the requested order, is (6, [0, 1, 2, 3, 4], 5, Yes, all_group_elements_checked).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-stabilizer-of-point · candidate

15. The Point Stabilizer Enumerates Every Fixing Group Element

Use complete group table=[[0, 1, 2, 3, 4, 5], [1, 2, 3, 4, 5, 0], [2, 3, 4, 5, 0, 1], [3, 4, 5, 0, 1, 2], [4, 5, 0, 1, 2, 3], [5, 0, 1, 2, 3, 4]], identity=0, point carrier Fin(8)={0,…,7} and total action_table=[[0, 1, 2, 3, 4, 5, 6, 7], [1, 2, 3, 4, 5, 0, 6, 7], [2, 3, 4, 5, 0, 1, 6, 7], [3, 4, 5, 0, 1, 2, 6, 7], [4, 5, 0, 1, 2, 3, 6, 7], [5, 0, 1, 2, 3, 4, 6, 7]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=6. Give (point, stabilizer, stabilizer_order, full_enumeration_certificate, certificate).

View answer and explanation

(6, [0, 1, 2, 3, 4, 5], 6, Yes, all_group_elements_checked)

Enumerate every g with g*x=x and retain them in group-index order. The result is a subgroup of G, not the orbit in the point carrier or merely one fixed-element witness. The exact result, retaining the requested order, is (6, [0, 1, 2, 3, 4, 5], 6, Yes, all_group_elements_checked).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-stabilizer-of-point · candidate

16. The Point Stabilizer Enumerates Every Fixing Group Element

Use complete group table=[[0, 1], [1, 0]], identity=0, point carrier Fin(5)={0,…,4} and total action_table=[[0, 1, 2, 3, 4], [1, 0, 2, 3, 4]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=0. Give (point, stabilizer, stabilizer_order, full_enumeration_certificate, certificate).

View answer and explanation

(0, [0], 1, Yes, all_group_elements_checked)

Enumerate every g with g*x=x and retain them in group-index order. The result is a subgroup of G, not the orbit in the point carrier or merely one fixed-element witness. The exact result, retaining the requested order, is (0, [0], 1, Yes, all_group_elements_checked).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-stabilizer-of-point · candidate

17. The Point Stabilizer Enumerates Every Fixing Group Element

Use complete group table=[[0, 1, 2], [1, 2, 0], [2, 0, 1]], identity=0, point carrier Fin(6)={0,…,5} and total action_table=[[0, 1, 2, 3, 4, 5], [1, 2, 0, 3, 4, 5], [2, 0, 1, 3, 4, 5]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=4. Give (point, stabilizer, stabilizer_order, full_enumeration_certificate, certificate).

View answer and explanation

(4, [0, 1, 2], 3, Yes, all_group_elements_checked)

Enumerate every g with g*x=x and retain them in group-index order. The result is a subgroup of G, not the orbit in the point carrier or merely one fixed-element witness. The exact result, retaining the requested order, is (4, [0, 1, 2], 3, Yes, all_group_elements_checked).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-stabilizer-of-point · candidate

18. The Point Stabilizer Enumerates Every Fixing Group Element

Use complete group table=[[0, 1, 2, 3], [1, 2, 3, 0], [2, 3, 0, 1], [3, 0, 1, 2]], identity=0, point carrier Fin(7)={0,…,6} and total action_table=[[0, 1, 2, 3, 4, 5, 6], [1, 2, 3, 0, 4, 5, 6], [2, 3, 0, 1, 4, 5, 6], [3, 0, 1, 2, 4, 5, 6]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=3. Give (point, stabilizer, stabilizer_order, full_enumeration_certificate, certificate).

View answer and explanation

(3, [0], 1, Yes, all_group_elements_checked)

Enumerate every g with g*x=x and retain them in group-index order. The result is a subgroup of G, not the orbit in the point carrier or merely one fixed-element witness. The exact result, retaining the requested order, is (3, [0], 1, Yes, all_group_elements_checked).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-stabilizer-of-point · candidate

19. The Point Stabilizer Enumerates Every Fixing Group Element

Use complete group table=[[0, 1, 2, 3, 4], [1, 2, 3, 4, 0], [2, 3, 4, 0, 1], [3, 4, 0, 1, 2], [4, 0, 1, 2, 3]], identity=0, point carrier Fin(8)={0,…,7} and total action_table=[[0, 1, 2, 3, 4, 5, 6, 7], [1, 2, 3, 4, 0, 5, 6, 7], [2, 3, 4, 0, 1, 5, 6, 7], [3, 4, 0, 1, 2, 5, 6, 7], [4, 0, 1, 2, 3, 5, 6, 7]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=2. Give (point, stabilizer, stabilizer_order, full_enumeration_certificate, certificate).

View answer and explanation

(2, [0], 1, Yes, all_group_elements_checked)

Enumerate every g with g*x=x and retain them in group-index order. The result is a subgroup of G, not the orbit in the point carrier or merely one fixed-element witness. The exact result, retaining the requested order, is (2, [0], 1, Yes, all_group_elements_checked).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-stabilizer-of-point · candidate

20. The Point Stabilizer Enumerates Every Fixing Group Element

Use complete group table=[[0, 1, 2, 3, 4, 5], [1, 2, 3, 4, 5, 0], [2, 3, 4, 5, 0, 1], [3, 4, 5, 0, 1, 2], [4, 5, 0, 1, 2, 3], [5, 0, 1, 2, 3, 4]], identity=0, point carrier Fin(9)={0,…,8} and total action_table=[[0, 1, 2, 3, 4, 5, 6, 7, 8], [1, 2, 3, 4, 5, 0, 6, 7, 8], [2, 3, 4, 5, 0, 1, 6, 7, 8], [3, 4, 5, 0, 1, 2, 6, 7, 8], [4, 5, 0, 1, 2, 3, 6, 7, 8], [5, 0, 1, 2, 3, 4, 6, 7, 8]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=1. Give (point, stabilizer, stabilizer_order, full_enumeration_certificate, certificate).

View answer and explanation

(1, [0], 1, Yes, all_group_elements_checked)

Enumerate every g with g*x=x and retain them in group-index order. The result is a subgroup of G, not the orbit in the point carrier or merely one fixed-element witness. The exact result, retaining the requested order, is (1, [0], 1, Yes, all_group_elements_checked).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-stabilizer-of-point · candidate

21. The Point Stabilizer Enumerates Every Fixing Group Element

Use complete group table=[[0, 1], [1, 0]], identity=0, point carrier Fin(6)={0,…,5} and total action_table=[[0, 1, 2, 3, 4, 5], [1, 0, 2, 3, 4, 5]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=2. Give (point, stabilizer, stabilizer_order, full_enumeration_certificate, certificate).

View answer and explanation

(2, [0, 1], 2, Yes, all_group_elements_checked)

Enumerate every g with g*x=x and retain them in group-index order. The result is a subgroup of G, not the orbit in the point carrier or merely one fixed-element witness. The exact result, retaining the requested order, is (2, [0, 1], 2, Yes, all_group_elements_checked).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-stabilizer-of-point · candidate

22. The Point Stabilizer Enumerates Every Fixing Group Element

Use complete group table=[[0, 1, 2], [1, 2, 0], [2, 0, 1]], identity=0, point carrier Fin(7)={0,…,6} and total action_table=[[0, 1, 2, 3, 4, 5, 6], [1, 2, 0, 3, 4, 5, 6], [2, 0, 1, 3, 4, 5, 6]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=0. Give (point, stabilizer, stabilizer_order, full_enumeration_certificate, certificate).

View answer and explanation

(0, [0], 1, Yes, all_group_elements_checked)

Enumerate every g with g*x=x and retain them in group-index order. The result is a subgroup of G, not the orbit in the point carrier or merely one fixed-element witness. The exact result, retaining the requested order, is (0, [0], 1, Yes, all_group_elements_checked).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-stabilizer-of-point · candidate

23. The Point Stabilizer Enumerates Every Fixing Group Element

Use complete group table=[[0, 1, 2, 3], [1, 2, 3, 0], [2, 3, 0, 1], [3, 0, 1, 2]], identity=0, point carrier Fin(8)={0,…,7} and total action_table=[[0, 1, 2, 3, 4, 5, 6, 7], [1, 2, 3, 0, 4, 5, 6, 7], [2, 3, 0, 1, 4, 5, 6, 7], [3, 0, 1, 2, 4, 5, 6, 7]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=6. Give (point, stabilizer, stabilizer_order, full_enumeration_certificate, certificate).

View answer and explanation

(6, [0, 1, 2, 3], 4, Yes, all_group_elements_checked)

Enumerate every g with g*x=x and retain them in group-index order. The result is a subgroup of G, not the orbit in the point carrier or merely one fixed-element witness. The exact result, retaining the requested order, is (6, [0, 1, 2, 3], 4, Yes, all_group_elements_checked).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-stabilizer-of-point · candidate

24. The Point Stabilizer Enumerates Every Fixing Group Element

Use complete group table=[[0, 1, 2, 3, 4], [1, 2, 3, 4, 0], [2, 3, 4, 0, 1], [3, 4, 0, 1, 2], [4, 0, 1, 2, 3]], identity=0, point carrier Fin(9)={0,…,8} and total action_table=[[0, 1, 2, 3, 4, 5, 6, 7, 8], [1, 2, 3, 4, 0, 5, 6, 7, 8], [2, 3, 4, 0, 1, 5, 6, 7, 8], [3, 4, 0, 1, 2, 5, 6, 7, 8], [4, 0, 1, 2, 3, 5, 6, 7, 8]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=5. Give (point, stabilizer, stabilizer_order, full_enumeration_certificate, certificate).

View answer and explanation

(5, [0, 1, 2, 3, 4], 5, Yes, all_group_elements_checked)

Enumerate every g with g*x=x and retain them in group-index order. The result is a subgroup of G, not the orbit in the point carrier or merely one fixed-element witness. The exact result, retaining the requested order, is (5, [0, 1, 2, 3, 4], 5, Yes, all_group_elements_checked).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-stabilizer-of-point · candidate

25. The Point Stabilizer Enumerates Every Fixing Group Element

Use complete group table=[[0, 1, 2, 3, 4, 5], [1, 2, 3, 4, 5, 0], [2, 3, 4, 5, 0, 1], [3, 4, 5, 0, 1, 2], [4, 5, 0, 1, 2, 3], [5, 0, 1, 2, 3, 4]], identity=0, point carrier Fin(10)={0,…,9} and total action_table=[[0, 1, 2, 3, 4, 5, 6, 7, 8, 9], [1, 2, 3, 4, 5, 0, 6, 7, 8, 9], [2, 3, 4, 5, 0, 1, 6, 7, 8, 9], [3, 4, 5, 0, 1, 2, 6, 7, 8, 9], [4, 5, 0, 1, 2, 3, 6, 7, 8, 9], [5, 0, 1, 2, 3, 4, 6, 7, 8, 9]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=4. Give (point, stabilizer, stabilizer_order, full_enumeration_certificate, certificate).

View answer and explanation

(4, [0], 1, Yes, all_group_elements_checked)

Enumerate every g with g*x=x and retain them in group-index order. The result is a subgroup of G, not the orbit in the point carrier or merely one fixed-element witness. The exact result, retaining the requested order, is (4, [0], 1, Yes, all_group_elements_checked).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-stabilizer-of-point · candidate

26. Identity, Product and Inverse Closure Certify the Full Stabilizer

Use complete group table=[[0, 1], [1, 0]], identity=0, point carrier Fin(2)={0,…,1} and total action_table=[[0, 1], [1, 0]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=0. Give (stabilizer, identity, contains_identity, product_closed, inverse_closed, subgroup, certificate).

View answer and explanation

([0], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure)

First compute the entire stabilizer, then separately check identity membership, every product of its members and the inverse of every member using the same group table. All three obligations supply the subgroup flag. The exact result, retaining the requested order, is ([0], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-subgroup-certificate · candidate

27. Identity, Product and Inverse Closure Certify the Full Stabilizer

Use complete group table=[[0, 1, 2], [1, 2, 0], [2, 0, 1]], identity=0, point carrier Fin(3)={0,…,2} and total action_table=[[0, 1, 2], [1, 2, 0], [2, 0, 1]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=1. Give (stabilizer, identity, contains_identity, product_closed, inverse_closed, subgroup, certificate).

View answer and explanation

([0], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure)

First compute the entire stabilizer, then separately check identity membership, every product of its members and the inverse of every member using the same group table. All three obligations supply the subgroup flag. The exact result, retaining the requested order, is ([0], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-subgroup-certificate · candidate

28. Identity, Product and Inverse Closure Certify the Full Stabilizer

Use complete group table=[[0, 1, 2, 3], [1, 2, 3, 0], [2, 3, 0, 1], [3, 0, 1, 2]], identity=0, point carrier Fin(4)={0,…,3} and total action_table=[[0, 1, 2, 3], [1, 2, 3, 0], [2, 3, 0, 1], [3, 0, 1, 2]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=2. Give (stabilizer, identity, contains_identity, product_closed, inverse_closed, subgroup, certificate).

View answer and explanation

([0], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure)

First compute the entire stabilizer, then separately check identity membership, every product of its members and the inverse of every member using the same group table. All three obligations supply the subgroup flag. The exact result, retaining the requested order, is ([0], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-subgroup-certificate · candidate

29. Identity, Product and Inverse Closure Certify the Full Stabilizer

Use complete group table=[[0, 1, 2, 3, 4], [1, 2, 3, 4, 0], [2, 3, 4, 0, 1], [3, 4, 0, 1, 2], [4, 0, 1, 2, 3]], identity=0, point carrier Fin(5)={0,…,4} and total action_table=[[0, 1, 2, 3, 4], [1, 2, 3, 4, 0], [2, 3, 4, 0, 1], [3, 4, 0, 1, 2], [4, 0, 1, 2, 3]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=3. Give (stabilizer, identity, contains_identity, product_closed, inverse_closed, subgroup, certificate).

View answer and explanation

([0], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure)

First compute the entire stabilizer, then separately check identity membership, every product of its members and the inverse of every member using the same group table. All three obligations supply the subgroup flag. The exact result, retaining the requested order, is ([0], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-subgroup-certificate · candidate

30. Identity, Product and Inverse Closure Certify the Full Stabilizer

Use complete group table=[[0, 1, 2, 3, 4, 5], [1, 2, 3, 4, 5, 0], [2, 3, 4, 5, 0, 1], [3, 4, 5, 0, 1, 2], [4, 5, 0, 1, 2, 3], [5, 0, 1, 2, 3, 4]], identity=0, point carrier Fin(6)={0,…,5} and total action_table=[[0, 1, 2, 3, 4, 5], [1, 2, 3, 4, 5, 0], [2, 3, 4, 5, 0, 1], [3, 4, 5, 0, 1, 2], [4, 5, 0, 1, 2, 3], [5, 0, 1, 2, 3, 4]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=4. Give (stabilizer, identity, contains_identity, product_closed, inverse_closed, subgroup, certificate).

View answer and explanation

([0], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure)

First compute the entire stabilizer, then separately check identity membership, every product of its members and the inverse of every member using the same group table. All three obligations supply the subgroup flag. The exact result, retaining the requested order, is ([0], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-subgroup-certificate · candidate

31. Identity, Product and Inverse Closure Certify the Full Stabilizer

Use complete group table=[[0, 1], [1, 0]], identity=0, point carrier Fin(3)={0,…,2} and total action_table=[[0, 1, 2], [1, 0, 2]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=2. Give (stabilizer, identity, contains_identity, product_closed, inverse_closed, subgroup, certificate).

View answer and explanation

([0, 1], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure)

First compute the entire stabilizer, then separately check identity membership, every product of its members and the inverse of every member using the same group table. All three obligations supply the subgroup flag. The exact result, retaining the requested order, is ([0, 1], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-subgroup-certificate · candidate

32. Identity, Product and Inverse Closure Certify the Full Stabilizer

Use complete group table=[[0, 1, 2], [1, 2, 0], [2, 0, 1]], identity=0, point carrier Fin(4)={0,…,3} and total action_table=[[0, 1, 2, 3], [1, 2, 0, 3], [2, 0, 1, 3]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=2. Give (stabilizer, identity, contains_identity, product_closed, inverse_closed, subgroup, certificate).

View answer and explanation

([0], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure)

First compute the entire stabilizer, then separately check identity membership, every product of its members and the inverse of every member using the same group table. All three obligations supply the subgroup flag. The exact result, retaining the requested order, is ([0], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-subgroup-certificate · candidate

33. Identity, Product and Inverse Closure Certify the Full Stabilizer

Use complete group table=[[0, 1, 2, 3], [1, 2, 3, 0], [2, 3, 0, 1], [3, 0, 1, 2]], identity=0, point carrier Fin(5)={0,…,4} and total action_table=[[0, 1, 2, 3, 4], [1, 2, 3, 0, 4], [2, 3, 0, 1, 4], [3, 0, 1, 2, 4]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=2. Give (stabilizer, identity, contains_identity, product_closed, inverse_closed, subgroup, certificate).

View answer and explanation

([0], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure)

First compute the entire stabilizer, then separately check identity membership, every product of its members and the inverse of every member using the same group table. All three obligations supply the subgroup flag. The exact result, retaining the requested order, is ([0], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-subgroup-certificate · candidate

34. Identity, Product and Inverse Closure Certify the Full Stabilizer

Use complete group table=[[0, 1, 2, 3, 4], [1, 2, 3, 4, 0], [2, 3, 4, 0, 1], [3, 4, 0, 1, 2], [4, 0, 1, 2, 3]], identity=0, point carrier Fin(6)={0,…,5} and total action_table=[[0, 1, 2, 3, 4, 5], [1, 2, 3, 4, 0, 5], [2, 3, 4, 0, 1, 5], [3, 4, 0, 1, 2, 5], [4, 0, 1, 2, 3, 5]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=2. Give (stabilizer, identity, contains_identity, product_closed, inverse_closed, subgroup, certificate).

View answer and explanation

([0], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure)

First compute the entire stabilizer, then separately check identity membership, every product of its members and the inverse of every member using the same group table. All three obligations supply the subgroup flag. The exact result, retaining the requested order, is ([0], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-subgroup-certificate · candidate

35. Identity, Product and Inverse Closure Certify the Full Stabilizer

Use complete group table=[[0, 1, 2, 3, 4, 5], [1, 2, 3, 4, 5, 0], [2, 3, 4, 5, 0, 1], [3, 4, 5, 0, 1, 2], [4, 5, 0, 1, 2, 3], [5, 0, 1, 2, 3, 4]], identity=0, point carrier Fin(7)={0,…,6} and total action_table=[[0, 1, 2, 3, 4, 5, 6], [1, 2, 3, 4, 5, 0, 6], [2, 3, 4, 5, 0, 1, 6], [3, 4, 5, 0, 1, 2, 6], [4, 5, 0, 1, 2, 3, 6], [5, 0, 1, 2, 3, 4, 6]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=2. Give (stabilizer, identity, contains_identity, product_closed, inverse_closed, subgroup, certificate).

View answer and explanation

([0], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure)

First compute the entire stabilizer, then separately check identity membership, every product of its members and the inverse of every member using the same group table. All three obligations supply the subgroup flag. The exact result, retaining the requested order, is ([0], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-subgroup-certificate · candidate

36. Identity, Product and Inverse Closure Certify the Full Stabilizer

Use complete group table=[[0, 1], [1, 0]], identity=0, point carrier Fin(4)={0,…,3} and total action_table=[[0, 1, 2, 3], [1, 0, 2, 3]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=2. Give (stabilizer, identity, contains_identity, product_closed, inverse_closed, subgroup, certificate).

View answer and explanation

([0, 1], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure)

First compute the entire stabilizer, then separately check identity membership, every product of its members and the inverse of every member using the same group table. All three obligations supply the subgroup flag. The exact result, retaining the requested order, is ([0, 1], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-subgroup-certificate · candidate

37. Identity, Product and Inverse Closure Certify the Full Stabilizer

Use complete group table=[[0, 1, 2], [1, 2, 0], [2, 0, 1]], identity=0, point carrier Fin(5)={0,…,4} and total action_table=[[0, 1, 2, 3, 4], [1, 2, 0, 3, 4], [2, 0, 1, 3, 4]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=1. Give (stabilizer, identity, contains_identity, product_closed, inverse_closed, subgroup, certificate).

View answer and explanation

([0], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure)

First compute the entire stabilizer, then separately check identity membership, every product of its members and the inverse of every member using the same group table. All three obligations supply the subgroup flag. The exact result, retaining the requested order, is ([0], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-subgroup-certificate · candidate

38. Identity, Product and Inverse Closure Certify the Full Stabilizer

Use complete group table=[[0, 1, 2, 3], [1, 2, 3, 0], [2, 3, 0, 1], [3, 0, 1, 2]], identity=0, point carrier Fin(6)={0,…,5} and total action_table=[[0, 1, 2, 3, 4, 5], [1, 2, 3, 0, 4, 5], [2, 3, 0, 1, 4, 5], [3, 0, 1, 2, 4, 5]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=0. Give (stabilizer, identity, contains_identity, product_closed, inverse_closed, subgroup, certificate).

View answer and explanation

([0], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure)

First compute the entire stabilizer, then separately check identity membership, every product of its members and the inverse of every member using the same group table. All three obligations supply the subgroup flag. The exact result, retaining the requested order, is ([0], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-subgroup-certificate · candidate

39. Identity, Product and Inverse Closure Certify the Full Stabilizer

Use complete group table=[[0, 1, 2, 3, 4], [1, 2, 3, 4, 0], [2, 3, 4, 0, 1], [3, 4, 0, 1, 2], [4, 0, 1, 2, 3]], identity=0, point carrier Fin(7)={0,…,6} and total action_table=[[0, 1, 2, 3, 4, 5, 6], [1, 2, 3, 4, 0, 5, 6], [2, 3, 4, 0, 1, 5, 6], [3, 4, 0, 1, 2, 5, 6], [4, 0, 1, 2, 3, 5, 6]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=6. Give (stabilizer, identity, contains_identity, product_closed, inverse_closed, subgroup, certificate).

View answer and explanation

([0, 1, 2, 3, 4], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure)

First compute the entire stabilizer, then separately check identity membership, every product of its members and the inverse of every member using the same group table. All three obligations supply the subgroup flag. The exact result, retaining the requested order, is ([0, 1, 2, 3, 4], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-subgroup-certificate · candidate

40. Identity, Product and Inverse Closure Certify the Full Stabilizer

Use complete group table=[[0, 1, 2, 3, 4, 5], [1, 2, 3, 4, 5, 0], [2, 3, 4, 5, 0, 1], [3, 4, 5, 0, 1, 2], [4, 5, 0, 1, 2, 3], [5, 0, 1, 2, 3, 4]], identity=0, point carrier Fin(8)={0,…,7} and total action_table=[[0, 1, 2, 3, 4, 5, 6, 7], [1, 2, 3, 4, 5, 0, 6, 7], [2, 3, 4, 5, 0, 1, 6, 7], [3, 4, 5, 0, 1, 2, 6, 7], [4, 5, 0, 1, 2, 3, 6, 7], [5, 0, 1, 2, 3, 4, 6, 7]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=6. Give (stabilizer, identity, contains_identity, product_closed, inverse_closed, subgroup, certificate).

View answer and explanation

([0, 1, 2, 3, 4, 5], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure)

First compute the entire stabilizer, then separately check identity membership, every product of its members and the inverse of every member using the same group table. All three obligations supply the subgroup flag. The exact result, retaining the requested order, is ([0, 1, 2, 3, 4, 5], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-subgroup-certificate · candidate

41. Identity, Product and Inverse Closure Certify the Full Stabilizer

Use complete group table=[[0, 1], [1, 0]], identity=0, point carrier Fin(5)={0,…,4} and total action_table=[[0, 1, 2, 3, 4], [1, 0, 2, 3, 4]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=0. Give (stabilizer, identity, contains_identity, product_closed, inverse_closed, subgroup, certificate).

View answer and explanation

([0], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure)

First compute the entire stabilizer, then separately check identity membership, every product of its members and the inverse of every member using the same group table. All three obligations supply the subgroup flag. The exact result, retaining the requested order, is ([0], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-subgroup-certificate · candidate

42. Identity, Product and Inverse Closure Certify the Full Stabilizer

Use complete group table=[[0, 1, 2], [1, 2, 0], [2, 0, 1]], identity=0, point carrier Fin(6)={0,…,5} and total action_table=[[0, 1, 2, 3, 4, 5], [1, 2, 0, 3, 4, 5], [2, 0, 1, 3, 4, 5]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=4. Give (stabilizer, identity, contains_identity, product_closed, inverse_closed, subgroup, certificate).

View answer and explanation

([0, 1, 2], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure)

First compute the entire stabilizer, then separately check identity membership, every product of its members and the inverse of every member using the same group table. All three obligations supply the subgroup flag. The exact result, retaining the requested order, is ([0, 1, 2], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-subgroup-certificate · candidate

43. Identity, Product and Inverse Closure Certify the Full Stabilizer

Use complete group table=[[0, 1, 2, 3], [1, 2, 3, 0], [2, 3, 0, 1], [3, 0, 1, 2]], identity=0, point carrier Fin(7)={0,…,6} and total action_table=[[0, 1, 2, 3, 4, 5, 6], [1, 2, 3, 0, 4, 5, 6], [2, 3, 0, 1, 4, 5, 6], [3, 0, 1, 2, 4, 5, 6]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=3. Give (stabilizer, identity, contains_identity, product_closed, inverse_closed, subgroup, certificate).

View answer and explanation

([0], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure)

First compute the entire stabilizer, then separately check identity membership, every product of its members and the inverse of every member using the same group table. All three obligations supply the subgroup flag. The exact result, retaining the requested order, is ([0], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-subgroup-certificate · candidate

44. Identity, Product and Inverse Closure Certify the Full Stabilizer

Use complete group table=[[0, 1, 2, 3, 4], [1, 2, 3, 4, 0], [2, 3, 4, 0, 1], [3, 4, 0, 1, 2], [4, 0, 1, 2, 3]], identity=0, point carrier Fin(8)={0,…,7} and total action_table=[[0, 1, 2, 3, 4, 5, 6, 7], [1, 2, 3, 4, 0, 5, 6, 7], [2, 3, 4, 0, 1, 5, 6, 7], [3, 4, 0, 1, 2, 5, 6, 7], [4, 0, 1, 2, 3, 5, 6, 7]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=2. Give (stabilizer, identity, contains_identity, product_closed, inverse_closed, subgroup, certificate).

View answer and explanation

([0], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure)

First compute the entire stabilizer, then separately check identity membership, every product of its members and the inverse of every member using the same group table. All three obligations supply the subgroup flag. The exact result, retaining the requested order, is ([0], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-subgroup-certificate · candidate

45. Identity, Product and Inverse Closure Certify the Full Stabilizer

Use complete group table=[[0, 1, 2, 3, 4, 5], [1, 2, 3, 4, 5, 0], [2, 3, 4, 5, 0, 1], [3, 4, 5, 0, 1, 2], [4, 5, 0, 1, 2, 3], [5, 0, 1, 2, 3, 4]], identity=0, point carrier Fin(9)={0,…,8} and total action_table=[[0, 1, 2, 3, 4, 5, 6, 7, 8], [1, 2, 3, 4, 5, 0, 6, 7, 8], [2, 3, 4, 5, 0, 1, 6, 7, 8], [3, 4, 5, 0, 1, 2, 6, 7, 8], [4, 5, 0, 1, 2, 3, 6, 7, 8], [5, 0, 1, 2, 3, 4, 6, 7, 8]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=1. Give (stabilizer, identity, contains_identity, product_closed, inverse_closed, subgroup, certificate).

View answer and explanation

([0], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure)

First compute the entire stabilizer, then separately check identity membership, every product of its members and the inverse of every member using the same group table. All three obligations supply the subgroup flag. The exact result, retaining the requested order, is ([0], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-subgroup-certificate · candidate

46. Identity, Product and Inverse Closure Certify the Full Stabilizer

Use complete group table=[[0, 1], [1, 0]], identity=0, point carrier Fin(6)={0,…,5} and total action_table=[[0, 1, 2, 3, 4, 5], [1, 0, 2, 3, 4, 5]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=2. Give (stabilizer, identity, contains_identity, product_closed, inverse_closed, subgroup, certificate).

View answer and explanation

([0, 1], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure)

First compute the entire stabilizer, then separately check identity membership, every product of its members and the inverse of every member using the same group table. All three obligations supply the subgroup flag. The exact result, retaining the requested order, is ([0, 1], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-subgroup-certificate · candidate

47. Identity, Product and Inverse Closure Certify the Full Stabilizer

Use complete group table=[[0, 1, 2], [1, 2, 0], [2, 0, 1]], identity=0, point carrier Fin(7)={0,…,6} and total action_table=[[0, 1, 2, 3, 4, 5, 6], [1, 2, 0, 3, 4, 5, 6], [2, 0, 1, 3, 4, 5, 6]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=0. Give (stabilizer, identity, contains_identity, product_closed, inverse_closed, subgroup, certificate).

View answer and explanation

([0], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure)

First compute the entire stabilizer, then separately check identity membership, every product of its members and the inverse of every member using the same group table. All three obligations supply the subgroup flag. The exact result, retaining the requested order, is ([0], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-subgroup-certificate · candidate

48. Identity, Product and Inverse Closure Certify the Full Stabilizer

Use complete group table=[[0, 1, 2, 3], [1, 2, 3, 0], [2, 3, 0, 1], [3, 0, 1, 2]], identity=0, point carrier Fin(8)={0,…,7} and total action_table=[[0, 1, 2, 3, 4, 5, 6, 7], [1, 2, 3, 0, 4, 5, 6, 7], [2, 3, 0, 1, 4, 5, 6, 7], [3, 0, 1, 2, 4, 5, 6, 7]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=6. Give (stabilizer, identity, contains_identity, product_closed, inverse_closed, subgroup, certificate).

View answer and explanation

([0, 1, 2, 3], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure)

First compute the entire stabilizer, then separately check identity membership, every product of its members and the inverse of every member using the same group table. All three obligations supply the subgroup flag. The exact result, retaining the requested order, is ([0, 1, 2, 3], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-subgroup-certificate · candidate

49. Identity, Product and Inverse Closure Certify the Full Stabilizer

Use complete group table=[[0, 1, 2, 3, 4], [1, 2, 3, 4, 0], [2, 3, 4, 0, 1], [3, 4, 0, 1, 2], [4, 0, 1, 2, 3]], identity=0, point carrier Fin(9)={0,…,8} and total action_table=[[0, 1, 2, 3, 4, 5, 6, 7, 8], [1, 2, 3, 4, 0, 5, 6, 7, 8], [2, 3, 4, 0, 1, 5, 6, 7, 8], [3, 4, 0, 1, 2, 5, 6, 7, 8], [4, 0, 1, 2, 3, 5, 6, 7, 8]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=5. Give (stabilizer, identity, contains_identity, product_closed, inverse_closed, subgroup, certificate).

View answer and explanation

([0, 1, 2, 3, 4], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure)

First compute the entire stabilizer, then separately check identity membership, every product of its members and the inverse of every member using the same group table. All three obligations supply the subgroup flag. The exact result, retaining the requested order, is ([0, 1, 2, 3, 4], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-subgroup-certificate · candidate

50. Identity, Product and Inverse Closure Certify the Full Stabilizer

Use complete group table=[[0, 1, 2, 3, 4, 5], [1, 2, 3, 4, 5, 0], [2, 3, 4, 5, 0, 1], [3, 4, 5, 0, 1, 2], [4, 5, 0, 1, 2, 3], [5, 0, 1, 2, 3, 4]], identity=0, point carrier Fin(10)={0,…,9} and total action_table=[[0, 1, 2, 3, 4, 5, 6, 7, 8, 9], [1, 2, 3, 4, 5, 0, 6, 7, 8, 9], [2, 3, 4, 5, 0, 1, 6, 7, 8, 9], [3, 4, 5, 0, 1, 2, 6, 7, 8, 9], [4, 5, 0, 1, 2, 3, 6, 7, 8, 9], [5, 0, 1, 2, 3, 4, 6, 7, 8, 9]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=4. Give (stabilizer, identity, contains_identity, product_closed, inverse_closed, subgroup, certificate).

View answer and explanation

([0], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure)

First compute the entire stabilizer, then separately check identity membership, every product of its members and the inverse of every member using the same group table. All three obligations supply the subgroup flag. The exact result, retaining the requested order, is ([0], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-subgroup-certificate · candidate

51. Fixing This Point Is Exactly Membership in Its Stabilizer

Use complete group table=[[0, 1], [1, 0]], identity=0, point carrier Fin(2)={0,…,1} and total action_table=[[0, 1], [1, 0]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=0. Test group_element=0. Give (group_element, point, image, fixes_point, in_stabilizer).

View answer and explanation

(0, 0, 0, Yes, Yes)

Read its action image, compare with the specified point and separately report membership in the complete stabilizer. An image different from x makes both flags No. The exact result, retaining the requested order, is (0, 0, 0, Yes, Yes).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-membership-audit · candidate

52. Fixing This Point Is Exactly Membership in Its Stabilizer

Use complete group table=[[0, 1, 2], [1, 2, 0], [2, 0, 1]], identity=0, point carrier Fin(3)={0,…,2} and total action_table=[[0, 1, 2], [1, 2, 0], [2, 0, 1]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=1. Test group_element=1. Give (group_element, point, image, fixes_point, in_stabilizer).

View answer and explanation

(1, 1, 2, No, No)

Read its action image, compare with the specified point and separately report membership in the complete stabilizer. An image different from x makes both flags No. The exact result, retaining the requested order, is (1, 1, 2, No, No).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-membership-audit · candidate

53. Fixing This Point Is Exactly Membership in Its Stabilizer

Use complete group table=[[0, 1, 2, 3], [1, 2, 3, 0], [2, 3, 0, 1], [3, 0, 1, 2]], identity=0, point carrier Fin(4)={0,…,3} and total action_table=[[0, 1, 2, 3], [1, 2, 3, 0], [2, 3, 0, 1], [3, 0, 1, 2]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=2. Test group_element=2. Give (group_element, point, image, fixes_point, in_stabilizer).

View answer and explanation

(2, 2, 0, No, No)

Read its action image, compare with the specified point and separately report membership in the complete stabilizer. An image different from x makes both flags No. The exact result, retaining the requested order, is (2, 2, 0, No, No).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-membership-audit · candidate

54. Fixing This Point Is Exactly Membership in Its Stabilizer

Use complete group table=[[0, 1, 2, 3, 4], [1, 2, 3, 4, 0], [2, 3, 4, 0, 1], [3, 4, 0, 1, 2], [4, 0, 1, 2, 3]], identity=0, point carrier Fin(5)={0,…,4} and total action_table=[[0, 1, 2, 3, 4], [1, 2, 3, 4, 0], [2, 3, 4, 0, 1], [3, 4, 0, 1, 2], [4, 0, 1, 2, 3]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=3. Test group_element=3. Give (group_element, point, image, fixes_point, in_stabilizer).

View answer and explanation

(3, 3, 1, No, No)

Read its action image, compare with the specified point and separately report membership in the complete stabilizer. An image different from x makes both flags No. The exact result, retaining the requested order, is (3, 3, 1, No, No).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-membership-audit · candidate

55. Fixing This Point Is Exactly Membership in Its Stabilizer

Use complete group table=[[0, 1, 2, 3, 4, 5], [1, 2, 3, 4, 5, 0], [2, 3, 4, 5, 0, 1], [3, 4, 5, 0, 1, 2], [4, 5, 0, 1, 2, 3], [5, 0, 1, 2, 3, 4]], identity=0, point carrier Fin(6)={0,…,5} and total action_table=[[0, 1, 2, 3, 4, 5], [1, 2, 3, 4, 5, 0], [2, 3, 4, 5, 0, 1], [3, 4, 5, 0, 1, 2], [4, 5, 0, 1, 2, 3], [5, 0, 1, 2, 3, 4]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=4. Test group_element=4. Give (group_element, point, image, fixes_point, in_stabilizer).

View answer and explanation

(4, 4, 2, No, No)

Read its action image, compare with the specified point and separately report membership in the complete stabilizer. An image different from x makes both flags No. The exact result, retaining the requested order, is (4, 4, 2, No, No).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-membership-audit · candidate

56. Fixing This Point Is Exactly Membership in Its Stabilizer

Use complete group table=[[0, 1], [1, 0]], identity=0, point carrier Fin(3)={0,…,2} and total action_table=[[0, 1, 2], [1, 0, 2]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=2. Test group_element=1. Give (group_element, point, image, fixes_point, in_stabilizer).

View answer and explanation

(1, 2, 2, Yes, Yes)

Read its action image, compare with the specified point and separately report membership in the complete stabilizer. An image different from x makes both flags No. The exact result, retaining the requested order, is (1, 2, 2, Yes, Yes).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-membership-audit · candidate

57. Fixing This Point Is Exactly Membership in Its Stabilizer

Use complete group table=[[0, 1, 2], [1, 2, 0], [2, 0, 1]], identity=0, point carrier Fin(4)={0,…,3} and total action_table=[[0, 1, 2, 3], [1, 2, 0, 3], [2, 0, 1, 3]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=2. Test group_element=0. Give (group_element, point, image, fixes_point, in_stabilizer).

View answer and explanation

(0, 2, 2, Yes, Yes)

Read its action image, compare with the specified point and separately report membership in the complete stabilizer. An image different from x makes both flags No. The exact result, retaining the requested order, is (0, 2, 2, Yes, Yes).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-membership-audit · candidate

58. Fixing This Point Is Exactly Membership in Its Stabilizer

Use complete group table=[[0, 1, 2, 3], [1, 2, 3, 0], [2, 3, 0, 1], [3, 0, 1, 2]], identity=0, point carrier Fin(5)={0,…,4} and total action_table=[[0, 1, 2, 3, 4], [1, 2, 3, 0, 4], [2, 3, 0, 1, 4], [3, 0, 1, 2, 4]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=2. Test group_element=3. Give (group_element, point, image, fixes_point, in_stabilizer).

View answer and explanation

(3, 2, 1, No, No)

Read its action image, compare with the specified point and separately report membership in the complete stabilizer. An image different from x makes both flags No. The exact result, retaining the requested order, is (3, 2, 1, No, No).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-membership-audit · candidate

59. Fixing This Point Is Exactly Membership in Its Stabilizer

Use complete group table=[[0, 1, 2, 3, 4], [1, 2, 3, 4, 0], [2, 3, 4, 0, 1], [3, 4, 0, 1, 2], [4, 0, 1, 2, 3]], identity=0, point carrier Fin(6)={0,…,5} and total action_table=[[0, 1, 2, 3, 4, 5], [1, 2, 3, 4, 0, 5], [2, 3, 4, 0, 1, 5], [3, 4, 0, 1, 2, 5], [4, 0, 1, 2, 3, 5]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=2. Test group_element=3. Give (group_element, point, image, fixes_point, in_stabilizer).

View answer and explanation

(3, 2, 0, No, No)

Read its action image, compare with the specified point and separately report membership in the complete stabilizer. An image different from x makes both flags No. The exact result, retaining the requested order, is (3, 2, 0, No, No).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-membership-audit · candidate

60. Fixing This Point Is Exactly Membership in Its Stabilizer

Use complete group table=[[0, 1, 2, 3, 4, 5], [1, 2, 3, 4, 5, 0], [2, 3, 4, 5, 0, 1], [3, 4, 5, 0, 1, 2], [4, 5, 0, 1, 2, 3], [5, 0, 1, 2, 3, 4]], identity=0, point carrier Fin(7)={0,…,6} and total action_table=[[0, 1, 2, 3, 4, 5, 6], [1, 2, 3, 4, 5, 0, 6], [2, 3, 4, 5, 0, 1, 6], [3, 4, 5, 0, 1, 2, 6], [4, 5, 0, 1, 2, 3, 6], [5, 0, 1, 2, 3, 4, 6]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=2. Test group_element=3. Give (group_element, point, image, fixes_point, in_stabilizer).

View answer and explanation

(3, 2, 5, No, No)

Read its action image, compare with the specified point and separately report membership in the complete stabilizer. An image different from x makes both flags No. The exact result, retaining the requested order, is (3, 2, 5, No, No).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-membership-audit · candidate

61. Fixing This Point Is Exactly Membership in Its Stabilizer

Use complete group table=[[0, 1], [1, 0]], identity=0, point carrier Fin(4)={0,…,3} and total action_table=[[0, 1, 2, 3], [1, 0, 2, 3]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=2. Test group_element=0. Give (group_element, point, image, fixes_point, in_stabilizer).

View answer and explanation

(0, 2, 2, Yes, Yes)

Read its action image, compare with the specified point and separately report membership in the complete stabilizer. An image different from x makes both flags No. The exact result, retaining the requested order, is (0, 2, 2, Yes, Yes).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-membership-audit · candidate

62. Fixing This Point Is Exactly Membership in Its Stabilizer

Use complete group table=[[0, 1, 2], [1, 2, 0], [2, 0, 1]], identity=0, point carrier Fin(5)={0,…,4} and total action_table=[[0, 1, 2, 3, 4], [1, 2, 0, 3, 4], [2, 0, 1, 3, 4]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=1. Test group_element=2. Give (group_element, point, image, fixes_point, in_stabilizer).

View answer and explanation

(2, 1, 0, No, No)

Read its action image, compare with the specified point and separately report membership in the complete stabilizer. An image different from x makes both flags No. The exact result, retaining the requested order, is (2, 1, 0, No, No).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-membership-audit · candidate

63. Fixing This Point Is Exactly Membership in Its Stabilizer

Use complete group table=[[0, 1, 2, 3], [1, 2, 3, 0], [2, 3, 0, 1], [3, 0, 1, 2]], identity=0, point carrier Fin(6)={0,…,5} and total action_table=[[0, 1, 2, 3, 4, 5], [1, 2, 3, 0, 4, 5], [2, 3, 0, 1, 4, 5], [3, 0, 1, 2, 4, 5]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=0. Test group_element=0. Give (group_element, point, image, fixes_point, in_stabilizer).

View answer and explanation

(0, 0, 0, Yes, Yes)

Read its action image, compare with the specified point and separately report membership in the complete stabilizer. An image different from x makes both flags No. The exact result, retaining the requested order, is (0, 0, 0, Yes, Yes).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-membership-audit · candidate

64. Fixing This Point Is Exactly Membership in Its Stabilizer

Use complete group table=[[0, 1, 2, 3, 4], [1, 2, 3, 4, 0], [2, 3, 4, 0, 1], [3, 4, 0, 1, 2], [4, 0, 1, 2, 3]], identity=0, point carrier Fin(7)={0,…,6} and total action_table=[[0, 1, 2, 3, 4, 5, 6], [1, 2, 3, 4, 0, 5, 6], [2, 3, 4, 0, 1, 5, 6], [3, 4, 0, 1, 2, 5, 6], [4, 0, 1, 2, 3, 5, 6]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=6. Test group_element=3. Give (group_element, point, image, fixes_point, in_stabilizer).

View answer and explanation

(3, 6, 6, Yes, Yes)

Read its action image, compare with the specified point and separately report membership in the complete stabilizer. An image different from x makes both flags No. The exact result, retaining the requested order, is (3, 6, 6, Yes, Yes).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-membership-audit · candidate

65. Fixing This Point Is Exactly Membership in Its Stabilizer

Use complete group table=[[0, 1, 2, 3, 4, 5], [1, 2, 3, 4, 5, 0], [2, 3, 4, 5, 0, 1], [3, 4, 5, 0, 1, 2], [4, 5, 0, 1, 2, 3], [5, 0, 1, 2, 3, 4]], identity=0, point carrier Fin(8)={0,…,7} and total action_table=[[0, 1, 2, 3, 4, 5, 6, 7], [1, 2, 3, 4, 5, 0, 6, 7], [2, 3, 4, 5, 0, 1, 6, 7], [3, 4, 5, 0, 1, 2, 6, 7], [4, 5, 0, 1, 2, 3, 6, 7], [5, 0, 1, 2, 3, 4, 6, 7]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=6. Test group_element=2. Give (group_element, point, image, fixes_point, in_stabilizer).

View answer and explanation

(2, 6, 6, Yes, Yes)

Read its action image, compare with the specified point and separately report membership in the complete stabilizer. An image different from x makes both flags No. The exact result, retaining the requested order, is (2, 6, 6, Yes, Yes).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-membership-audit · candidate

66. Fixing This Point Is Exactly Membership in Its Stabilizer

Use complete group table=[[0, 1], [1, 0]], identity=0, point carrier Fin(5)={0,…,4} and total action_table=[[0, 1, 2, 3, 4], [1, 0, 2, 3, 4]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=0. Test group_element=1. Give (group_element, point, image, fixes_point, in_stabilizer).

View answer and explanation

(1, 0, 1, No, No)

Read its action image, compare with the specified point and separately report membership in the complete stabilizer. An image different from x makes both flags No. The exact result, retaining the requested order, is (1, 0, 1, No, No).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-membership-audit · candidate

67. Fixing This Point Is Exactly Membership in Its Stabilizer

Use complete group table=[[0, 1, 2], [1, 2, 0], [2, 0, 1]], identity=0, point carrier Fin(6)={0,…,5} and total action_table=[[0, 1, 2, 3, 4, 5], [1, 2, 0, 3, 4, 5], [2, 0, 1, 3, 4, 5]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=4. Test group_element=1. Give (group_element, point, image, fixes_point, in_stabilizer).

View answer and explanation

(1, 4, 4, Yes, Yes)

Read its action image, compare with the specified point and separately report membership in the complete stabilizer. An image different from x makes both flags No. The exact result, retaining the requested order, is (1, 4, 4, Yes, Yes).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-membership-audit · candidate

68. Fixing This Point Is Exactly Membership in Its Stabilizer

Use complete group table=[[0, 1, 2, 3], [1, 2, 3, 0], [2, 3, 0, 1], [3, 0, 1, 2]], identity=0, point carrier Fin(7)={0,…,6} and total action_table=[[0, 1, 2, 3, 4, 5, 6], [1, 2, 3, 0, 4, 5, 6], [2, 3, 0, 1, 4, 5, 6], [3, 0, 1, 2, 4, 5, 6]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=3. Test group_element=1. Give (group_element, point, image, fixes_point, in_stabilizer).

View answer and explanation

(1, 3, 0, No, No)

Read its action image, compare with the specified point and separately report membership in the complete stabilizer. An image different from x makes both flags No. The exact result, retaining the requested order, is (1, 3, 0, No, No).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-membership-audit · candidate

69. Fixing This Point Is Exactly Membership in Its Stabilizer

Use complete group table=[[0, 1, 2, 3, 4], [1, 2, 3, 4, 0], [2, 3, 4, 0, 1], [3, 4, 0, 1, 2], [4, 0, 1, 2, 3]], identity=0, point carrier Fin(8)={0,…,7} and total action_table=[[0, 1, 2, 3, 4, 5, 6, 7], [1, 2, 3, 4, 0, 5, 6, 7], [2, 3, 4, 0, 1, 5, 6, 7], [3, 4, 0, 1, 2, 5, 6, 7], [4, 0, 1, 2, 3, 5, 6, 7]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=2. Test group_element=3. Give (group_element, point, image, fixes_point, in_stabilizer).

View answer and explanation

(3, 2, 0, No, No)

Read its action image, compare with the specified point and separately report membership in the complete stabilizer. An image different from x makes both flags No. The exact result, retaining the requested order, is (3, 2, 0, No, No).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-membership-audit · candidate

70. Fixing This Point Is Exactly Membership in Its Stabilizer

Use complete group table=[[0, 1, 2, 3, 4, 5], [1, 2, 3, 4, 5, 0], [2, 3, 4, 5, 0, 1], [3, 4, 5, 0, 1, 2], [4, 5, 0, 1, 2, 3], [5, 0, 1, 2, 3, 4]], identity=0, point carrier Fin(9)={0,…,8} and total action_table=[[0, 1, 2, 3, 4, 5, 6, 7, 8], [1, 2, 3, 4, 5, 0, 6, 7, 8], [2, 3, 4, 5, 0, 1, 6, 7, 8], [3, 4, 5, 0, 1, 2, 6, 7, 8], [4, 5, 0, 1, 2, 3, 6, 7, 8], [5, 0, 1, 2, 3, 4, 6, 7, 8]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=1. Test group_element=1. Give (group_element, point, image, fixes_point, in_stabilizer).

View answer and explanation

(1, 1, 2, No, No)

Read its action image, compare with the specified point and separately report membership in the complete stabilizer. An image different from x makes both flags No. The exact result, retaining the requested order, is (1, 1, 2, No, No).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-membership-audit · candidate

71. Fixing This Point Is Exactly Membership in Its Stabilizer

Use complete group table=[[0, 1], [1, 0]], identity=0, point carrier Fin(6)={0,…,5} and total action_table=[[0, 1, 2, 3, 4, 5], [1, 0, 2, 3, 4, 5]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=2. Test group_element=0. Give (group_element, point, image, fixes_point, in_stabilizer).

View answer and explanation

(0, 2, 2, Yes, Yes)

Read its action image, compare with the specified point and separately report membership in the complete stabilizer. An image different from x makes both flags No. The exact result, retaining the requested order, is (0, 2, 2, Yes, Yes).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-membership-audit · candidate

72. Fixing This Point Is Exactly Membership in Its Stabilizer

Use complete group table=[[0, 1, 2], [1, 2, 0], [2, 0, 1]], identity=0, point carrier Fin(7)={0,…,6} and total action_table=[[0, 1, 2, 3, 4, 5, 6], [1, 2, 0, 3, 4, 5, 6], [2, 0, 1, 3, 4, 5, 6]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=0. Test group_element=0. Give (group_element, point, image, fixes_point, in_stabilizer).

View answer and explanation

(0, 0, 0, Yes, Yes)

Read its action image, compare with the specified point and separately report membership in the complete stabilizer. An image different from x makes both flags No. The exact result, retaining the requested order, is (0, 0, 0, Yes, Yes).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-membership-audit · candidate

73. Fixing This Point Is Exactly Membership in Its Stabilizer

Use complete group table=[[0, 1, 2, 3], [1, 2, 3, 0], [2, 3, 0, 1], [3, 0, 1, 2]], identity=0, point carrier Fin(8)={0,…,7} and total action_table=[[0, 1, 2, 3, 4, 5, 6, 7], [1, 2, 3, 0, 4, 5, 6, 7], [2, 3, 0, 1, 4, 5, 6, 7], [3, 0, 1, 2, 4, 5, 6, 7]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=6. Test group_element=2. Give (group_element, point, image, fixes_point, in_stabilizer).

View answer and explanation

(2, 6, 6, Yes, Yes)

Read its action image, compare with the specified point and separately report membership in the complete stabilizer. An image different from x makes both flags No. The exact result, retaining the requested order, is (2, 6, 6, Yes, Yes).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-membership-audit · candidate

74. Fixing This Point Is Exactly Membership in Its Stabilizer

Use complete group table=[[0, 1, 2, 3, 4], [1, 2, 3, 4, 0], [2, 3, 4, 0, 1], [3, 4, 0, 1, 2], [4, 0, 1, 2, 3]], identity=0, point carrier Fin(9)={0,…,8} and total action_table=[[0, 1, 2, 3, 4, 5, 6, 7, 8], [1, 2, 3, 4, 0, 5, 6, 7, 8], [2, 3, 4, 0, 1, 5, 6, 7, 8], [3, 4, 0, 1, 2, 5, 6, 7, 8], [4, 0, 1, 2, 3, 5, 6, 7, 8]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=5. Test group_element=3. Give (group_element, point, image, fixes_point, in_stabilizer).

View answer and explanation

(3, 5, 5, Yes, Yes)

Read its action image, compare with the specified point and separately report membership in the complete stabilizer. An image different from x makes both flags No. The exact result, retaining the requested order, is (3, 5, 5, Yes, Yes).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-membership-audit · candidate

75. Fixing This Point Is Exactly Membership in Its Stabilizer

Use complete group table=[[0, 1, 2, 3, 4, 5], [1, 2, 3, 4, 5, 0], [2, 3, 4, 5, 0, 1], [3, 4, 5, 0, 1, 2], [4, 5, 0, 1, 2, 3], [5, 0, 1, 2, 3, 4]], identity=0, point carrier Fin(10)={0,…,9} and total action_table=[[0, 1, 2, 3, 4, 5, 6, 7, 8, 9], [1, 2, 3, 4, 5, 0, 6, 7, 8, 9], [2, 3, 4, 5, 0, 1, 6, 7, 8, 9], [3, 4, 5, 0, 1, 2, 6, 7, 8, 9], [4, 5, 0, 1, 2, 3, 6, 7, 8, 9], [5, 0, 1, 2, 3, 4, 6, 7, 8, 9]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=4. Test group_element=0. Give (group_element, point, image, fixes_point, in_stabilizer).

View answer and explanation

(0, 4, 4, Yes, Yes)

Read its action image, compare with the specified point and separately report membership in the complete stabilizer. An image different from x makes both flags No. The exact result, retaining the requested order, is (0, 4, 4, Yes, Yes).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-membership-audit · candidate

76. Point Stabilizers May Agree without Becoming Orbits or Kernels

Use complete group table=[[0, 1], [1, 0]], identity=0, point carrier Fin(2)={0,…,1} and total action_table=[[0, 1], [1, 0]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=0. Compare other_point=1. Give (point, stabilizer, other_point, other_stabilizer, same_stabilizer, orbit_or_kernel_identification_claim, boundary).

The fixed No withholds identification of stabilizer, orbit and action kernel as concepts. It does not negate same_stabilizer or rule out equality of particular sets.

View answer and explanation

(0, [0], 1, [0], Yes, No, stabilizer_not_orbit_or_action_kernel)

Compute both complete stabilizers and their equality flag. The final fixed No withholds identification of stabilizer, orbit and action kernel as concepts; it does not negate equal stabilizers or rule out special set equalities. The exact result, retaining the requested order, is (0, [0], 1, [0], Yes, No, stabilizer_not_orbit_or_action_kernel).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-point-boundary · candidate

77. Point Stabilizers May Agree without Becoming Orbits or Kernels

Use complete group table=[[0, 1, 2], [1, 2, 0], [2, 0, 1]], identity=0, point carrier Fin(3)={0,…,2} and total action_table=[[0, 1, 2], [1, 2, 0], [2, 0, 1]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=1. Compare other_point=2. Give (point, stabilizer, other_point, other_stabilizer, same_stabilizer, orbit_or_kernel_identification_claim, boundary).

The fixed No withholds identification of stabilizer, orbit and action kernel as concepts. It does not negate same_stabilizer or rule out equality of particular sets.

View answer and explanation

(1, [0], 2, [0], Yes, No, stabilizer_not_orbit_or_action_kernel)

Compute both complete stabilizers and their equality flag. The final fixed No withholds identification of stabilizer, orbit and action kernel as concepts; it does not negate equal stabilizers or rule out special set equalities. The exact result, retaining the requested order, is (1, [0], 2, [0], Yes, No, stabilizer_not_orbit_or_action_kernel).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-point-boundary · candidate

78. Point Stabilizers May Agree without Becoming Orbits or Kernels

Use complete group table=[[0, 1, 2, 3], [1, 2, 3, 0], [2, 3, 0, 1], [3, 0, 1, 2]], identity=0, point carrier Fin(4)={0,…,3} and total action_table=[[0, 1, 2, 3], [1, 2, 3, 0], [2, 3, 0, 1], [3, 0, 1, 2]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=2. Compare other_point=3. Give (point, stabilizer, other_point, other_stabilizer, same_stabilizer, orbit_or_kernel_identification_claim, boundary).

The fixed No withholds identification of stabilizer, orbit and action kernel as concepts. It does not negate same_stabilizer or rule out equality of particular sets.

View answer and explanation

(2, [0], 3, [0], Yes, No, stabilizer_not_orbit_or_action_kernel)

Compute both complete stabilizers and their equality flag. The final fixed No withholds identification of stabilizer, orbit and action kernel as concepts; it does not negate equal stabilizers or rule out special set equalities. The exact result, retaining the requested order, is (2, [0], 3, [0], Yes, No, stabilizer_not_orbit_or_action_kernel).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-point-boundary · candidate

79. Point Stabilizers May Agree without Becoming Orbits or Kernels

Use complete group table=[[0, 1, 2, 3, 4], [1, 2, 3, 4, 0], [2, 3, 4, 0, 1], [3, 4, 0, 1, 2], [4, 0, 1, 2, 3]], identity=0, point carrier Fin(5)={0,…,4} and total action_table=[[0, 1, 2, 3, 4], [1, 2, 3, 4, 0], [2, 3, 4, 0, 1], [3, 4, 0, 1, 2], [4, 0, 1, 2, 3]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=3. Compare other_point=4. Give (point, stabilizer, other_point, other_stabilizer, same_stabilizer, orbit_or_kernel_identification_claim, boundary).

The fixed No withholds identification of stabilizer, orbit and action kernel as concepts. It does not negate same_stabilizer or rule out equality of particular sets.

View answer and explanation

(3, [0], 4, [0], Yes, No, stabilizer_not_orbit_or_action_kernel)

Compute both complete stabilizers and their equality flag. The final fixed No withholds identification of stabilizer, orbit and action kernel as concepts; it does not negate equal stabilizers or rule out special set equalities. The exact result, retaining the requested order, is (3, [0], 4, [0], Yes, No, stabilizer_not_orbit_or_action_kernel).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-point-boundary · candidate

80. Point Stabilizers May Agree without Becoming Orbits or Kernels

Use complete group table=[[0, 1, 2, 3, 4, 5], [1, 2, 3, 4, 5, 0], [2, 3, 4, 5, 0, 1], [3, 4, 5, 0, 1, 2], [4, 5, 0, 1, 2, 3], [5, 0, 1, 2, 3, 4]], identity=0, point carrier Fin(6)={0,…,5} and total action_table=[[0, 1, 2, 3, 4, 5], [1, 2, 3, 4, 5, 0], [2, 3, 4, 5, 0, 1], [3, 4, 5, 0, 1, 2], [4, 5, 0, 1, 2, 3], [5, 0, 1, 2, 3, 4]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=4. Compare other_point=5. Give (point, stabilizer, other_point, other_stabilizer, same_stabilizer, orbit_or_kernel_identification_claim, boundary).

The fixed No withholds identification of stabilizer, orbit and action kernel as concepts. It does not negate same_stabilizer or rule out equality of particular sets.

View answer and explanation

(4, [0], 5, [0], Yes, No, stabilizer_not_orbit_or_action_kernel)

Compute both complete stabilizers and their equality flag. The final fixed No withholds identification of stabilizer, orbit and action kernel as concepts; it does not negate equal stabilizers or rule out special set equalities. The exact result, retaining the requested order, is (4, [0], 5, [0], Yes, No, stabilizer_not_orbit_or_action_kernel).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-point-boundary · candidate

81. Point Stabilizers May Agree without Becoming Orbits or Kernels

Use complete group table=[[0, 1], [1, 0]], identity=0, point carrier Fin(3)={0,…,2} and total action_table=[[0, 1, 2], [1, 0, 2]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=2. Compare other_point=0. Give (point, stabilizer, other_point, other_stabilizer, same_stabilizer, orbit_or_kernel_identification_claim, boundary).

The fixed No withholds identification of stabilizer, orbit and action kernel as concepts. It does not negate same_stabilizer or rule out equality of particular sets.

View answer and explanation

(2, [0, 1], 0, [0], No, No, stabilizer_not_orbit_or_action_kernel)

Compute both complete stabilizers and their equality flag. The final fixed No withholds identification of stabilizer, orbit and action kernel as concepts; it does not negate equal stabilizers or rule out special set equalities. The exact result, retaining the requested order, is (2, [0, 1], 0, [0], No, No, stabilizer_not_orbit_or_action_kernel).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-point-boundary · candidate

82. Point Stabilizers May Agree without Becoming Orbits or Kernels

Use complete group table=[[0, 1, 2], [1, 2, 0], [2, 0, 1]], identity=0, point carrier Fin(4)={0,…,3} and total action_table=[[0, 1, 2, 3], [1, 2, 0, 3], [2, 0, 1, 3]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=2. Compare other_point=3. Give (point, stabilizer, other_point, other_stabilizer, same_stabilizer, orbit_or_kernel_identification_claim, boundary).

The fixed No withholds identification of stabilizer, orbit and action kernel as concepts. It does not negate same_stabilizer or rule out equality of particular sets.

View answer and explanation

(2, [0], 3, [0, 1, 2], No, No, stabilizer_not_orbit_or_action_kernel)

Compute both complete stabilizers and their equality flag. The final fixed No withholds identification of stabilizer, orbit and action kernel as concepts; it does not negate equal stabilizers or rule out special set equalities. The exact result, retaining the requested order, is (2, [0], 3, [0, 1, 2], No, No, stabilizer_not_orbit_or_action_kernel).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-point-boundary · candidate

83. Point Stabilizers May Agree without Becoming Orbits or Kernels

Use complete group table=[[0, 1, 2, 3], [1, 2, 3, 0], [2, 3, 0, 1], [3, 0, 1, 2]], identity=0, point carrier Fin(5)={0,…,4} and total action_table=[[0, 1, 2, 3, 4], [1, 2, 3, 0, 4], [2, 3, 0, 1, 4], [3, 0, 1, 2, 4]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=2. Compare other_point=3. Give (point, stabilizer, other_point, other_stabilizer, same_stabilizer, orbit_or_kernel_identification_claim, boundary).

The fixed No withholds identification of stabilizer, orbit and action kernel as concepts. It does not negate same_stabilizer or rule out equality of particular sets.

View answer and explanation

(2, [0], 3, [0], Yes, No, stabilizer_not_orbit_or_action_kernel)

Compute both complete stabilizers and their equality flag. The final fixed No withholds identification of stabilizer, orbit and action kernel as concepts; it does not negate equal stabilizers or rule out special set equalities. The exact result, retaining the requested order, is (2, [0], 3, [0], Yes, No, stabilizer_not_orbit_or_action_kernel).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-point-boundary · candidate

84. Point Stabilizers May Agree without Becoming Orbits or Kernels

Use complete group table=[[0, 1, 2, 3, 4], [1, 2, 3, 4, 0], [2, 3, 4, 0, 1], [3, 4, 0, 1, 2], [4, 0, 1, 2, 3]], identity=0, point carrier Fin(6)={0,…,5} and total action_table=[[0, 1, 2, 3, 4, 5], [1, 2, 3, 4, 0, 5], [2, 3, 4, 0, 1, 5], [3, 4, 0, 1, 2, 5], [4, 0, 1, 2, 3, 5]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=2. Compare other_point=3. Give (point, stabilizer, other_point, other_stabilizer, same_stabilizer, orbit_or_kernel_identification_claim, boundary).

The fixed No withholds identification of stabilizer, orbit and action kernel as concepts. It does not negate same_stabilizer or rule out equality of particular sets.

View answer and explanation

(2, [0], 3, [0], Yes, No, stabilizer_not_orbit_or_action_kernel)

Compute both complete stabilizers and their equality flag. The final fixed No withholds identification of stabilizer, orbit and action kernel as concepts; it does not negate equal stabilizers or rule out special set equalities. The exact result, retaining the requested order, is (2, [0], 3, [0], Yes, No, stabilizer_not_orbit_or_action_kernel).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-point-boundary · candidate

85. Point Stabilizers May Agree without Becoming Orbits or Kernels

Use complete group table=[[0, 1, 2, 3, 4, 5], [1, 2, 3, 4, 5, 0], [2, 3, 4, 5, 0, 1], [3, 4, 5, 0, 1, 2], [4, 5, 0, 1, 2, 3], [5, 0, 1, 2, 3, 4]], identity=0, point carrier Fin(7)={0,…,6} and total action_table=[[0, 1, 2, 3, 4, 5, 6], [1, 2, 3, 4, 5, 0, 6], [2, 3, 4, 5, 0, 1, 6], [3, 4, 5, 0, 1, 2, 6], [4, 5, 0, 1, 2, 3, 6], [5, 0, 1, 2, 3, 4, 6]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=2. Compare other_point=3. Give (point, stabilizer, other_point, other_stabilizer, same_stabilizer, orbit_or_kernel_identification_claim, boundary).

The fixed No withholds identification of stabilizer, orbit and action kernel as concepts. It does not negate same_stabilizer or rule out equality of particular sets.

View answer and explanation

(2, [0], 3, [0], Yes, No, stabilizer_not_orbit_or_action_kernel)

Compute both complete stabilizers and their equality flag. The final fixed No withholds identification of stabilizer, orbit and action kernel as concepts; it does not negate equal stabilizers or rule out special set equalities. The exact result, retaining the requested order, is (2, [0], 3, [0], Yes, No, stabilizer_not_orbit_or_action_kernel).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-point-boundary · candidate

86. Point Stabilizers May Agree without Becoming Orbits or Kernels

Use complete group table=[[0, 1], [1, 0]], identity=0, point carrier Fin(4)={0,…,3} and total action_table=[[0, 1, 2, 3], [1, 0, 2, 3]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=2. Compare other_point=3. Give (point, stabilizer, other_point, other_stabilizer, same_stabilizer, orbit_or_kernel_identification_claim, boundary).

The fixed No withholds identification of stabilizer, orbit and action kernel as concepts. It does not negate same_stabilizer or rule out equality of particular sets.

View answer and explanation

(2, [0, 1], 3, [0, 1], Yes, No, stabilizer_not_orbit_or_action_kernel)

Compute both complete stabilizers and their equality flag. The final fixed No withholds identification of stabilizer, orbit and action kernel as concepts; it does not negate equal stabilizers or rule out special set equalities. The exact result, retaining the requested order, is (2, [0, 1], 3, [0, 1], Yes, No, stabilizer_not_orbit_or_action_kernel).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-point-boundary · candidate

87. Point Stabilizers May Agree without Becoming Orbits or Kernels

Use complete group table=[[0, 1, 2], [1, 2, 0], [2, 0, 1]], identity=0, point carrier Fin(5)={0,…,4} and total action_table=[[0, 1, 2, 3, 4], [1, 2, 0, 3, 4], [2, 0, 1, 3, 4]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=1. Compare other_point=2. Give (point, stabilizer, other_point, other_stabilizer, same_stabilizer, orbit_or_kernel_identification_claim, boundary).

The fixed No withholds identification of stabilizer, orbit and action kernel as concepts. It does not negate same_stabilizer or rule out equality of particular sets.

View answer and explanation

(1, [0], 2, [0], Yes, No, stabilizer_not_orbit_or_action_kernel)

Compute both complete stabilizers and their equality flag. The final fixed No withholds identification of stabilizer, orbit and action kernel as concepts; it does not negate equal stabilizers or rule out special set equalities. The exact result, retaining the requested order, is (1, [0], 2, [0], Yes, No, stabilizer_not_orbit_or_action_kernel).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-point-boundary · candidate

88. Point Stabilizers May Agree without Becoming Orbits or Kernels

Use complete group table=[[0, 1, 2, 3], [1, 2, 3, 0], [2, 3, 0, 1], [3, 0, 1, 2]], identity=0, point carrier Fin(6)={0,…,5} and total action_table=[[0, 1, 2, 3, 4, 5], [1, 2, 3, 0, 4, 5], [2, 3, 0, 1, 4, 5], [3, 0, 1, 2, 4, 5]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=0. Compare other_point=1. Give (point, stabilizer, other_point, other_stabilizer, same_stabilizer, orbit_or_kernel_identification_claim, boundary).

The fixed No withholds identification of stabilizer, orbit and action kernel as concepts. It does not negate same_stabilizer or rule out equality of particular sets.

View answer and explanation

(0, [0], 1, [0], Yes, No, stabilizer_not_orbit_or_action_kernel)

Compute both complete stabilizers and their equality flag. The final fixed No withholds identification of stabilizer, orbit and action kernel as concepts; it does not negate equal stabilizers or rule out special set equalities. The exact result, retaining the requested order, is (0, [0], 1, [0], Yes, No, stabilizer_not_orbit_or_action_kernel).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-point-boundary · candidate

89. Point Stabilizers May Agree without Becoming Orbits or Kernels

Use complete group table=[[0, 1, 2, 3, 4], [1, 2, 3, 4, 0], [2, 3, 4, 0, 1], [3, 4, 0, 1, 2], [4, 0, 1, 2, 3]], identity=0, point carrier Fin(7)={0,…,6} and total action_table=[[0, 1, 2, 3, 4, 5, 6], [1, 2, 3, 4, 0, 5, 6], [2, 3, 4, 0, 1, 5, 6], [3, 4, 0, 1, 2, 5, 6], [4, 0, 1, 2, 3, 5, 6]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=6. Compare other_point=0. Give (point, stabilizer, other_point, other_stabilizer, same_stabilizer, orbit_or_kernel_identification_claim, boundary).

The fixed No withholds identification of stabilizer, orbit and action kernel as concepts. It does not negate same_stabilizer or rule out equality of particular sets.

View answer and explanation

(6, [0, 1, 2, 3, 4], 0, [0], No, No, stabilizer_not_orbit_or_action_kernel)

Compute both complete stabilizers and their equality flag. The final fixed No withholds identification of stabilizer, orbit and action kernel as concepts; it does not negate equal stabilizers or rule out special set equalities. The exact result, retaining the requested order, is (6, [0, 1, 2, 3, 4], 0, [0], No, No, stabilizer_not_orbit_or_action_kernel).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-point-boundary · candidate

90. Point Stabilizers May Agree without Becoming Orbits or Kernels

Use complete group table=[[0, 1, 2, 3, 4, 5], [1, 2, 3, 4, 5, 0], [2, 3, 4, 5, 0, 1], [3, 4, 5, 0, 1, 2], [4, 5, 0, 1, 2, 3], [5, 0, 1, 2, 3, 4]], identity=0, point carrier Fin(8)={0,…,7} and total action_table=[[0, 1, 2, 3, 4, 5, 6, 7], [1, 2, 3, 4, 5, 0, 6, 7], [2, 3, 4, 5, 0, 1, 6, 7], [3, 4, 5, 0, 1, 2, 6, 7], [4, 5, 0, 1, 2, 3, 6, 7], [5, 0, 1, 2, 3, 4, 6, 7]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=6. Compare other_point=7. Give (point, stabilizer, other_point, other_stabilizer, same_stabilizer, orbit_or_kernel_identification_claim, boundary).

The fixed No withholds identification of stabilizer, orbit and action kernel as concepts. It does not negate same_stabilizer or rule out equality of particular sets.

View answer and explanation

(6, [0, 1, 2, 3, 4, 5], 7, [0, 1, 2, 3, 4, 5], Yes, No, stabilizer_not_orbit_or_action_kernel)

Compute both complete stabilizers and their equality flag. The final fixed No withholds identification of stabilizer, orbit and action kernel as concepts; it does not negate equal stabilizers or rule out special set equalities. The exact result, retaining the requested order, is (6, [0, 1, 2, 3, 4, 5], 7, [0, 1, 2, 3, 4, 5], Yes, No, stabilizer_not_orbit_or_action_kernel).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-point-boundary · candidate

91. Point Stabilizers May Agree without Becoming Orbits or Kernels

Use complete group table=[[0, 1], [1, 0]], identity=0, point carrier Fin(5)={0,…,4} and total action_table=[[0, 1, 2, 3, 4], [1, 0, 2, 3, 4]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=0. Compare other_point=1. Give (point, stabilizer, other_point, other_stabilizer, same_stabilizer, orbit_or_kernel_identification_claim, boundary).

The fixed No withholds identification of stabilizer, orbit and action kernel as concepts. It does not negate same_stabilizer or rule out equality of particular sets.

View answer and explanation

(0, [0], 1, [0], Yes, No, stabilizer_not_orbit_or_action_kernel)

Compute both complete stabilizers and their equality flag. The final fixed No withholds identification of stabilizer, orbit and action kernel as concepts; it does not negate equal stabilizers or rule out special set equalities. The exact result, retaining the requested order, is (0, [0], 1, [0], Yes, No, stabilizer_not_orbit_or_action_kernel).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-point-boundary · candidate

92. Point Stabilizers May Agree without Becoming Orbits or Kernels

Use complete group table=[[0, 1, 2], [1, 2, 0], [2, 0, 1]], identity=0, point carrier Fin(6)={0,…,5} and total action_table=[[0, 1, 2, 3, 4, 5], [1, 2, 0, 3, 4, 5], [2, 0, 1, 3, 4, 5]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=4. Compare other_point=5. Give (point, stabilizer, other_point, other_stabilizer, same_stabilizer, orbit_or_kernel_identification_claim, boundary).

The fixed No withholds identification of stabilizer, orbit and action kernel as concepts. It does not negate same_stabilizer or rule out equality of particular sets.

View answer and explanation

(4, [0, 1, 2], 5, [0, 1, 2], Yes, No, stabilizer_not_orbit_or_action_kernel)

Compute both complete stabilizers and their equality flag. The final fixed No withholds identification of stabilizer, orbit and action kernel as concepts; it does not negate equal stabilizers or rule out special set equalities. The exact result, retaining the requested order, is (4, [0, 1, 2], 5, [0, 1, 2], Yes, No, stabilizer_not_orbit_or_action_kernel).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-point-boundary · candidate

93. Point Stabilizers May Agree without Becoming Orbits or Kernels

Use complete group table=[[0, 1, 2, 3], [1, 2, 3, 0], [2, 3, 0, 1], [3, 0, 1, 2]], identity=0, point carrier Fin(7)={0,…,6} and total action_table=[[0, 1, 2, 3, 4, 5, 6], [1, 2, 3, 0, 4, 5, 6], [2, 3, 0, 1, 4, 5, 6], [3, 0, 1, 2, 4, 5, 6]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=3. Compare other_point=4. Give (point, stabilizer, other_point, other_stabilizer, same_stabilizer, orbit_or_kernel_identification_claim, boundary).

The fixed No withholds identification of stabilizer, orbit and action kernel as concepts. It does not negate same_stabilizer or rule out equality of particular sets.

View answer and explanation

(3, [0], 4, [0, 1, 2, 3], No, No, stabilizer_not_orbit_or_action_kernel)

Compute both complete stabilizers and their equality flag. The final fixed No withholds identification of stabilizer, orbit and action kernel as concepts; it does not negate equal stabilizers or rule out special set equalities. The exact result, retaining the requested order, is (3, [0], 4, [0, 1, 2, 3], No, No, stabilizer_not_orbit_or_action_kernel).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-point-boundary · candidate

94. Point Stabilizers May Agree without Becoming Orbits or Kernels

Use complete group table=[[0, 1, 2, 3, 4], [1, 2, 3, 4, 0], [2, 3, 4, 0, 1], [3, 4, 0, 1, 2], [4, 0, 1, 2, 3]], identity=0, point carrier Fin(8)={0,…,7} and total action_table=[[0, 1, 2, 3, 4, 5, 6, 7], [1, 2, 3, 4, 0, 5, 6, 7], [2, 3, 4, 0, 1, 5, 6, 7], [3, 4, 0, 1, 2, 5, 6, 7], [4, 0, 1, 2, 3, 5, 6, 7]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=2. Compare other_point=3. Give (point, stabilizer, other_point, other_stabilizer, same_stabilizer, orbit_or_kernel_identification_claim, boundary).

The fixed No withholds identification of stabilizer, orbit and action kernel as concepts. It does not negate same_stabilizer or rule out equality of particular sets.

View answer and explanation

(2, [0], 3, [0], Yes, No, stabilizer_not_orbit_or_action_kernel)

Compute both complete stabilizers and their equality flag. The final fixed No withholds identification of stabilizer, orbit and action kernel as concepts; it does not negate equal stabilizers or rule out special set equalities. The exact result, retaining the requested order, is (2, [0], 3, [0], Yes, No, stabilizer_not_orbit_or_action_kernel).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-point-boundary · candidate

95. Point Stabilizers May Agree without Becoming Orbits or Kernels

Use complete group table=[[0, 1, 2, 3, 4, 5], [1, 2, 3, 4, 5, 0], [2, 3, 4, 5, 0, 1], [3, 4, 5, 0, 1, 2], [4, 5, 0, 1, 2, 3], [5, 0, 1, 2, 3, 4]], identity=0, point carrier Fin(9)={0,…,8} and total action_table=[[0, 1, 2, 3, 4, 5, 6, 7, 8], [1, 2, 3, 4, 5, 0, 6, 7, 8], [2, 3, 4, 5, 0, 1, 6, 7, 8], [3, 4, 5, 0, 1, 2, 6, 7, 8], [4, 5, 0, 1, 2, 3, 6, 7, 8], [5, 0, 1, 2, 3, 4, 6, 7, 8]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=1. Compare other_point=2. Give (point, stabilizer, other_point, other_stabilizer, same_stabilizer, orbit_or_kernel_identification_claim, boundary).

The fixed No withholds identification of stabilizer, orbit and action kernel as concepts. It does not negate same_stabilizer or rule out equality of particular sets.

View answer and explanation

(1, [0], 2, [0], Yes, No, stabilizer_not_orbit_or_action_kernel)

Compute both complete stabilizers and their equality flag. The final fixed No withholds identification of stabilizer, orbit and action kernel as concepts; it does not negate equal stabilizers or rule out special set equalities. The exact result, retaining the requested order, is (1, [0], 2, [0], Yes, No, stabilizer_not_orbit_or_action_kernel).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-point-boundary · candidate

96. Point Stabilizers May Agree without Becoming Orbits or Kernels

Use complete group table=[[0, 1], [1, 0]], identity=0, point carrier Fin(6)={0,…,5} and total action_table=[[0, 1, 2, 3, 4, 5], [1, 0, 2, 3, 4, 5]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=2. Compare other_point=3. Give (point, stabilizer, other_point, other_stabilizer, same_stabilizer, orbit_or_kernel_identification_claim, boundary).

The fixed No withholds identification of stabilizer, orbit and action kernel as concepts. It does not negate same_stabilizer or rule out equality of particular sets.

View answer and explanation

(2, [0, 1], 3, [0, 1], Yes, No, stabilizer_not_orbit_or_action_kernel)

Compute both complete stabilizers and their equality flag. The final fixed No withholds identification of stabilizer, orbit and action kernel as concepts; it does not negate equal stabilizers or rule out special set equalities. The exact result, retaining the requested order, is (2, [0, 1], 3, [0, 1], Yes, No, stabilizer_not_orbit_or_action_kernel).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-point-boundary · candidate

97. Point Stabilizers May Agree without Becoming Orbits or Kernels

Use complete group table=[[0, 1, 2], [1, 2, 0], [2, 0, 1]], identity=0, point carrier Fin(7)={0,…,6} and total action_table=[[0, 1, 2, 3, 4, 5, 6], [1, 2, 0, 3, 4, 5, 6], [2, 0, 1, 3, 4, 5, 6]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=0. Compare other_point=1. Give (point, stabilizer, other_point, other_stabilizer, same_stabilizer, orbit_or_kernel_identification_claim, boundary).

The fixed No withholds identification of stabilizer, orbit and action kernel as concepts. It does not negate same_stabilizer or rule out equality of particular sets.

View answer and explanation

(0, [0], 1, [0], Yes, No, stabilizer_not_orbit_or_action_kernel)

Compute both complete stabilizers and their equality flag. The final fixed No withholds identification of stabilizer, orbit and action kernel as concepts; it does not negate equal stabilizers or rule out special set equalities. The exact result, retaining the requested order, is (0, [0], 1, [0], Yes, No, stabilizer_not_orbit_or_action_kernel).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-point-boundary · candidate

98. Point Stabilizers May Agree without Becoming Orbits or Kernels

Use complete group table=[[0, 1, 2, 3], [1, 2, 3, 0], [2, 3, 0, 1], [3, 0, 1, 2]], identity=0, point carrier Fin(8)={0,…,7} and total action_table=[[0, 1, 2, 3, 4, 5, 6, 7], [1, 2, 3, 0, 4, 5, 6, 7], [2, 3, 0, 1, 4, 5, 6, 7], [3, 0, 1, 2, 4, 5, 6, 7]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=6. Compare other_point=7. Give (point, stabilizer, other_point, other_stabilizer, same_stabilizer, orbit_or_kernel_identification_claim, boundary).

The fixed No withholds identification of stabilizer, orbit and action kernel as concepts. It does not negate same_stabilizer or rule out equality of particular sets.

View answer and explanation

(6, [0, 1, 2, 3], 7, [0, 1, 2, 3], Yes, No, stabilizer_not_orbit_or_action_kernel)

Compute both complete stabilizers and their equality flag. The final fixed No withholds identification of stabilizer, orbit and action kernel as concepts; it does not negate equal stabilizers or rule out special set equalities. The exact result, retaining the requested order, is (6, [0, 1, 2, 3], 7, [0, 1, 2, 3], Yes, No, stabilizer_not_orbit_or_action_kernel).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-point-boundary · candidate

99. Point Stabilizers May Agree without Becoming Orbits or Kernels

Use complete group table=[[0, 1, 2, 3, 4], [1, 2, 3, 4, 0], [2, 3, 4, 0, 1], [3, 4, 0, 1, 2], [4, 0, 1, 2, 3]], identity=0, point carrier Fin(9)={0,…,8} and total action_table=[[0, 1, 2, 3, 4, 5, 6, 7, 8], [1, 2, 3, 4, 0, 5, 6, 7, 8], [2, 3, 4, 0, 1, 5, 6, 7, 8], [3, 4, 0, 1, 2, 5, 6, 7, 8], [4, 0, 1, 2, 3, 5, 6, 7, 8]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=5. Compare other_point=6. Give (point, stabilizer, other_point, other_stabilizer, same_stabilizer, orbit_or_kernel_identification_claim, boundary).

The fixed No withholds identification of stabilizer, orbit and action kernel as concepts. It does not negate same_stabilizer or rule out equality of particular sets.

View answer and explanation

(5, [0, 1, 2, 3, 4], 6, [0, 1, 2, 3, 4], Yes, No, stabilizer_not_orbit_or_action_kernel)

Compute both complete stabilizers and their equality flag. The final fixed No withholds identification of stabilizer, orbit and action kernel as concepts; it does not negate equal stabilizers or rule out special set equalities. The exact result, retaining the requested order, is (5, [0, 1, 2, 3, 4], 6, [0, 1, 2, 3, 4], Yes, No, stabilizer_not_orbit_or_action_kernel).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-point-boundary · candidate

100. Point Stabilizers May Agree without Becoming Orbits or Kernels

Use complete group table=[[0, 1, 2, 3, 4, 5], [1, 2, 3, 4, 5, 0], [2, 3, 4, 5, 0, 1], [3, 4, 5, 0, 1, 2], [4, 5, 0, 1, 2, 3], [5, 0, 1, 2, 3, 4]], identity=0, point carrier Fin(10)={0,…,9} and total action_table=[[0, 1, 2, 3, 4, 5, 6, 7, 8, 9], [1, 2, 3, 4, 5, 0, 6, 7, 8, 9], [2, 3, 4, 5, 0, 1, 6, 7, 8, 9], [3, 4, 5, 0, 1, 2, 6, 7, 8, 9], [4, 5, 0, 1, 2, 3, 6, 7, 8, 9], [5, 0, 1, 2, 3, 4, 6, 7, 8, 9]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=4. Compare other_point=5. Give (point, stabilizer, other_point, other_stabilizer, same_stabilizer, orbit_or_kernel_identification_claim, boundary).

The fixed No withholds identification of stabilizer, orbit and action kernel as concepts. It does not negate same_stabilizer or rule out equality of particular sets.

View answer and explanation

(4, [0], 5, [0], Yes, No, stabilizer_not_orbit_or_action_kernel)

Compute both complete stabilizers and their equality flag. The final fixed No withholds identification of stabilizer, orbit and action kernel as concepts; it does not negate equal stabilizers or rule out special set equalities. The exact result, retaining the requested order, is (4, [0], 5, [0], Yes, No, stabilizer_not_orbit_or_action_kernel).

Reviewed step-by-step derivation

Stabilizer of a finite group action · qf-mod40-stabilizer-point-boundary · candidate

Canonical question JSONL · English JSONL · Validation report