Complete Point Stabilizers, Subgroup Closure and Membership Boundaries
This batch has passed Schema, deduplication, source-snapshot, and independent-answer recomputation checks; it is still not marked as human-reviewed.
This question bank has corresponding bilingual step-by-step derivations. Source candidate and English ai_candidate states are retained. AI review, finite computation and Lean formal proof are labelled separately.
batch-20261014-advance-20261109-r01-finite-group-stabilizer-foundations · 2026-10-14 · 100 questions
This English edition is an AI candidate and does not yet have an OCME Atlas (GPT-6) Twin closure receipt.
Field order uses a source-bound presentation supplement; canonical JSONL and mathematical answers are unchanged.
Field-order and source-binding data
1. The Point Stabilizer Enumerates Every Fixing Group Element
Use complete group table=[[0, 1], [1, 0]], identity=0, point carrier Fin(2)={0,…,1} and total action_table=[[0, 1], [1, 0]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=0. Give (point, stabilizer, stabilizer_order, full_enumeration_certificate, certificate).
View answer and explanation
(0, [0], 1, Yes, all_group_elements_checked)
Enumerate every g with g*x=x and retain them in group-index order. The result is a subgroup of G, not the orbit in the point carrier or merely one fixed-element witness. The exact result, retaining the requested order, is (0, [0], 1, Yes, all_group_elements_checked).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-stabilizer-of-point · candidate
2. The Point Stabilizer Enumerates Every Fixing Group Element
Use complete group table=[[0, 1, 2], [1, 2, 0], [2, 0, 1]], identity=0, point carrier Fin(3)={0,…,2} and total action_table=[[0, 1, 2], [1, 2, 0], [2, 0, 1]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=1. Give (point, stabilizer, stabilizer_order, full_enumeration_certificate, certificate).
View answer and explanation
(1, [0], 1, Yes, all_group_elements_checked)
Enumerate every g with g*x=x and retain them in group-index order. The result is a subgroup of G, not the orbit in the point carrier or merely one fixed-element witness. The exact result, retaining the requested order, is (1, [0], 1, Yes, all_group_elements_checked).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-stabilizer-of-point · candidate
3. The Point Stabilizer Enumerates Every Fixing Group Element
Use complete group table=[[0, 1, 2, 3], [1, 2, 3, 0], [2, 3, 0, 1], [3, 0, 1, 2]], identity=0, point carrier Fin(4)={0,…,3} and total action_table=[[0, 1, 2, 3], [1, 2, 3, 0], [2, 3, 0, 1], [3, 0, 1, 2]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=2. Give (point, stabilizer, stabilizer_order, full_enumeration_certificate, certificate).
View answer and explanation
(2, [0], 1, Yes, all_group_elements_checked)
Enumerate every g with g*x=x and retain them in group-index order. The result is a subgroup of G, not the orbit in the point carrier or merely one fixed-element witness. The exact result, retaining the requested order, is (2, [0], 1, Yes, all_group_elements_checked).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-stabilizer-of-point · candidate
4. The Point Stabilizer Enumerates Every Fixing Group Element
Use complete group table=[[0, 1, 2, 3, 4], [1, 2, 3, 4, 0], [2, 3, 4, 0, 1], [3, 4, 0, 1, 2], [4, 0, 1, 2, 3]], identity=0, point carrier Fin(5)={0,…,4} and total action_table=[[0, 1, 2, 3, 4], [1, 2, 3, 4, 0], [2, 3, 4, 0, 1], [3, 4, 0, 1, 2], [4, 0, 1, 2, 3]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=3. Give (point, stabilizer, stabilizer_order, full_enumeration_certificate, certificate).
View answer and explanation
(3, [0], 1, Yes, all_group_elements_checked)
Enumerate every g with g*x=x and retain them in group-index order. The result is a subgroup of G, not the orbit in the point carrier or merely one fixed-element witness. The exact result, retaining the requested order, is (3, [0], 1, Yes, all_group_elements_checked).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-stabilizer-of-point · candidate
5. The Point Stabilizer Enumerates Every Fixing Group Element
Use complete group table=[[0, 1, 2, 3, 4, 5], [1, 2, 3, 4, 5, 0], [2, 3, 4, 5, 0, 1], [3, 4, 5, 0, 1, 2], [4, 5, 0, 1, 2, 3], [5, 0, 1, 2, 3, 4]], identity=0, point carrier Fin(6)={0,…,5} and total action_table=[[0, 1, 2, 3, 4, 5], [1, 2, 3, 4, 5, 0], [2, 3, 4, 5, 0, 1], [3, 4, 5, 0, 1, 2], [4, 5, 0, 1, 2, 3], [5, 0, 1, 2, 3, 4]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=4. Give (point, stabilizer, stabilizer_order, full_enumeration_certificate, certificate).
View answer and explanation
(4, [0], 1, Yes, all_group_elements_checked)
Enumerate every g with g*x=x and retain them in group-index order. The result is a subgroup of G, not the orbit in the point carrier or merely one fixed-element witness. The exact result, retaining the requested order, is (4, [0], 1, Yes, all_group_elements_checked).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-stabilizer-of-point · candidate
6. The Point Stabilizer Enumerates Every Fixing Group Element
Use complete group table=[[0, 1], [1, 0]], identity=0, point carrier Fin(3)={0,…,2} and total action_table=[[0, 1, 2], [1, 0, 2]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=2. Give (point, stabilizer, stabilizer_order, full_enumeration_certificate, certificate).
View answer and explanation
(2, [0, 1], 2, Yes, all_group_elements_checked)
Enumerate every g with g*x=x and retain them in group-index order. The result is a subgroup of G, not the orbit in the point carrier or merely one fixed-element witness. The exact result, retaining the requested order, is (2, [0, 1], 2, Yes, all_group_elements_checked).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-stabilizer-of-point · candidate
7. The Point Stabilizer Enumerates Every Fixing Group Element
Use complete group table=[[0, 1, 2], [1, 2, 0], [2, 0, 1]], identity=0, point carrier Fin(4)={0,…,3} and total action_table=[[0, 1, 2, 3], [1, 2, 0, 3], [2, 0, 1, 3]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=2. Give (point, stabilizer, stabilizer_order, full_enumeration_certificate, certificate).
View answer and explanation
(2, [0], 1, Yes, all_group_elements_checked)
Enumerate every g with g*x=x and retain them in group-index order. The result is a subgroup of G, not the orbit in the point carrier or merely one fixed-element witness. The exact result, retaining the requested order, is (2, [0], 1, Yes, all_group_elements_checked).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-stabilizer-of-point · candidate
8. The Point Stabilizer Enumerates Every Fixing Group Element
Use complete group table=[[0, 1, 2, 3], [1, 2, 3, 0], [2, 3, 0, 1], [3, 0, 1, 2]], identity=0, point carrier Fin(5)={0,…,4} and total action_table=[[0, 1, 2, 3, 4], [1, 2, 3, 0, 4], [2, 3, 0, 1, 4], [3, 0, 1, 2, 4]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=2. Give (point, stabilizer, stabilizer_order, full_enumeration_certificate, certificate).
View answer and explanation
(2, [0], 1, Yes, all_group_elements_checked)
Enumerate every g with g*x=x and retain them in group-index order. The result is a subgroup of G, not the orbit in the point carrier or merely one fixed-element witness. The exact result, retaining the requested order, is (2, [0], 1, Yes, all_group_elements_checked).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-stabilizer-of-point · candidate
9. The Point Stabilizer Enumerates Every Fixing Group Element
Use complete group table=[[0, 1, 2, 3, 4], [1, 2, 3, 4, 0], [2, 3, 4, 0, 1], [3, 4, 0, 1, 2], [4, 0, 1, 2, 3]], identity=0, point carrier Fin(6)={0,…,5} and total action_table=[[0, 1, 2, 3, 4, 5], [1, 2, 3, 4, 0, 5], [2, 3, 4, 0, 1, 5], [3, 4, 0, 1, 2, 5], [4, 0, 1, 2, 3, 5]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=2. Give (point, stabilizer, stabilizer_order, full_enumeration_certificate, certificate).
View answer and explanation
(2, [0], 1, Yes, all_group_elements_checked)
Enumerate every g with g*x=x and retain them in group-index order. The result is a subgroup of G, not the orbit in the point carrier or merely one fixed-element witness. The exact result, retaining the requested order, is (2, [0], 1, Yes, all_group_elements_checked).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-stabilizer-of-point · candidate
10. The Point Stabilizer Enumerates Every Fixing Group Element
Use complete group table=[[0, 1, 2, 3, 4, 5], [1, 2, 3, 4, 5, 0], [2, 3, 4, 5, 0, 1], [3, 4, 5, 0, 1, 2], [4, 5, 0, 1, 2, 3], [5, 0, 1, 2, 3, 4]], identity=0, point carrier Fin(7)={0,…,6} and total action_table=[[0, 1, 2, 3, 4, 5, 6], [1, 2, 3, 4, 5, 0, 6], [2, 3, 4, 5, 0, 1, 6], [3, 4, 5, 0, 1, 2, 6], [4, 5, 0, 1, 2, 3, 6], [5, 0, 1, 2, 3, 4, 6]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=2. Give (point, stabilizer, stabilizer_order, full_enumeration_certificate, certificate).
View answer and explanation
(2, [0], 1, Yes, all_group_elements_checked)
Enumerate every g with g*x=x and retain them in group-index order. The result is a subgroup of G, not the orbit in the point carrier or merely one fixed-element witness. The exact result, retaining the requested order, is (2, [0], 1, Yes, all_group_elements_checked).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-stabilizer-of-point · candidate
11. The Point Stabilizer Enumerates Every Fixing Group Element
Use complete group table=[[0, 1], [1, 0]], identity=0, point carrier Fin(4)={0,…,3} and total action_table=[[0, 1, 2, 3], [1, 0, 2, 3]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=2. Give (point, stabilizer, stabilizer_order, full_enumeration_certificate, certificate).
View answer and explanation
(2, [0, 1], 2, Yes, all_group_elements_checked)
Enumerate every g with g*x=x and retain them in group-index order. The result is a subgroup of G, not the orbit in the point carrier or merely one fixed-element witness. The exact result, retaining the requested order, is (2, [0, 1], 2, Yes, all_group_elements_checked).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-stabilizer-of-point · candidate
12. The Point Stabilizer Enumerates Every Fixing Group Element
Use complete group table=[[0, 1, 2], [1, 2, 0], [2, 0, 1]], identity=0, point carrier Fin(5)={0,…,4} and total action_table=[[0, 1, 2, 3, 4], [1, 2, 0, 3, 4], [2, 0, 1, 3, 4]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=1. Give (point, stabilizer, stabilizer_order, full_enumeration_certificate, certificate).
View answer and explanation
(1, [0], 1, Yes, all_group_elements_checked)
Enumerate every g with g*x=x and retain them in group-index order. The result is a subgroup of G, not the orbit in the point carrier or merely one fixed-element witness. The exact result, retaining the requested order, is (1, [0], 1, Yes, all_group_elements_checked).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-stabilizer-of-point · candidate
13. The Point Stabilizer Enumerates Every Fixing Group Element
Use complete group table=[[0, 1, 2, 3], [1, 2, 3, 0], [2, 3, 0, 1], [3, 0, 1, 2]], identity=0, point carrier Fin(6)={0,…,5} and total action_table=[[0, 1, 2, 3, 4, 5], [1, 2, 3, 0, 4, 5], [2, 3, 0, 1, 4, 5], [3, 0, 1, 2, 4, 5]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=0. Give (point, stabilizer, stabilizer_order, full_enumeration_certificate, certificate).
View answer and explanation
(0, [0], 1, Yes, all_group_elements_checked)
Enumerate every g with g*x=x and retain them in group-index order. The result is a subgroup of G, not the orbit in the point carrier or merely one fixed-element witness. The exact result, retaining the requested order, is (0, [0], 1, Yes, all_group_elements_checked).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-stabilizer-of-point · candidate
14. The Point Stabilizer Enumerates Every Fixing Group Element
Use complete group table=[[0, 1, 2, 3, 4], [1, 2, 3, 4, 0], [2, 3, 4, 0, 1], [3, 4, 0, 1, 2], [4, 0, 1, 2, 3]], identity=0, point carrier Fin(7)={0,…,6} and total action_table=[[0, 1, 2, 3, 4, 5, 6], [1, 2, 3, 4, 0, 5, 6], [2, 3, 4, 0, 1, 5, 6], [3, 4, 0, 1, 2, 5, 6], [4, 0, 1, 2, 3, 5, 6]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=6. Give (point, stabilizer, stabilizer_order, full_enumeration_certificate, certificate).
View answer and explanation
(6, [0, 1, 2, 3, 4], 5, Yes, all_group_elements_checked)
Enumerate every g with g*x=x and retain them in group-index order. The result is a subgroup of G, not the orbit in the point carrier or merely one fixed-element witness. The exact result, retaining the requested order, is (6, [0, 1, 2, 3, 4], 5, Yes, all_group_elements_checked).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-stabilizer-of-point · candidate
15. The Point Stabilizer Enumerates Every Fixing Group Element
Use complete group table=[[0, 1, 2, 3, 4, 5], [1, 2, 3, 4, 5, 0], [2, 3, 4, 5, 0, 1], [3, 4, 5, 0, 1, 2], [4, 5, 0, 1, 2, 3], [5, 0, 1, 2, 3, 4]], identity=0, point carrier Fin(8)={0,…,7} and total action_table=[[0, 1, 2, 3, 4, 5, 6, 7], [1, 2, 3, 4, 5, 0, 6, 7], [2, 3, 4, 5, 0, 1, 6, 7], [3, 4, 5, 0, 1, 2, 6, 7], [4, 5, 0, 1, 2, 3, 6, 7], [5, 0, 1, 2, 3, 4, 6, 7]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=6. Give (point, stabilizer, stabilizer_order, full_enumeration_certificate, certificate).
View answer and explanation
(6, [0, 1, 2, 3, 4, 5], 6, Yes, all_group_elements_checked)
Enumerate every g with g*x=x and retain them in group-index order. The result is a subgroup of G, not the orbit in the point carrier or merely one fixed-element witness. The exact result, retaining the requested order, is (6, [0, 1, 2, 3, 4, 5], 6, Yes, all_group_elements_checked).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-stabilizer-of-point · candidate
16. The Point Stabilizer Enumerates Every Fixing Group Element
Use complete group table=[[0, 1], [1, 0]], identity=0, point carrier Fin(5)={0,…,4} and total action_table=[[0, 1, 2, 3, 4], [1, 0, 2, 3, 4]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=0. Give (point, stabilizer, stabilizer_order, full_enumeration_certificate, certificate).
View answer and explanation
(0, [0], 1, Yes, all_group_elements_checked)
Enumerate every g with g*x=x and retain them in group-index order. The result is a subgroup of G, not the orbit in the point carrier or merely one fixed-element witness. The exact result, retaining the requested order, is (0, [0], 1, Yes, all_group_elements_checked).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-stabilizer-of-point · candidate
17. The Point Stabilizer Enumerates Every Fixing Group Element
Use complete group table=[[0, 1, 2], [1, 2, 0], [2, 0, 1]], identity=0, point carrier Fin(6)={0,…,5} and total action_table=[[0, 1, 2, 3, 4, 5], [1, 2, 0, 3, 4, 5], [2, 0, 1, 3, 4, 5]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=4. Give (point, stabilizer, stabilizer_order, full_enumeration_certificate, certificate).
View answer and explanation
(4, [0, 1, 2], 3, Yes, all_group_elements_checked)
Enumerate every g with g*x=x and retain them in group-index order. The result is a subgroup of G, not the orbit in the point carrier or merely one fixed-element witness. The exact result, retaining the requested order, is (4, [0, 1, 2], 3, Yes, all_group_elements_checked).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-stabilizer-of-point · candidate
18. The Point Stabilizer Enumerates Every Fixing Group Element
Use complete group table=[[0, 1, 2, 3], [1, 2, 3, 0], [2, 3, 0, 1], [3, 0, 1, 2]], identity=0, point carrier Fin(7)={0,…,6} and total action_table=[[0, 1, 2, 3, 4, 5, 6], [1, 2, 3, 0, 4, 5, 6], [2, 3, 0, 1, 4, 5, 6], [3, 0, 1, 2, 4, 5, 6]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=3. Give (point, stabilizer, stabilizer_order, full_enumeration_certificate, certificate).
View answer and explanation
(3, [0], 1, Yes, all_group_elements_checked)
Enumerate every g with g*x=x and retain them in group-index order. The result is a subgroup of G, not the orbit in the point carrier or merely one fixed-element witness. The exact result, retaining the requested order, is (3, [0], 1, Yes, all_group_elements_checked).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-stabilizer-of-point · candidate
19. The Point Stabilizer Enumerates Every Fixing Group Element
Use complete group table=[[0, 1, 2, 3, 4], [1, 2, 3, 4, 0], [2, 3, 4, 0, 1], [3, 4, 0, 1, 2], [4, 0, 1, 2, 3]], identity=0, point carrier Fin(8)={0,…,7} and total action_table=[[0, 1, 2, 3, 4, 5, 6, 7], [1, 2, 3, 4, 0, 5, 6, 7], [2, 3, 4, 0, 1, 5, 6, 7], [3, 4, 0, 1, 2, 5, 6, 7], [4, 0, 1, 2, 3, 5, 6, 7]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=2. Give (point, stabilizer, stabilizer_order, full_enumeration_certificate, certificate).
View answer and explanation
(2, [0], 1, Yes, all_group_elements_checked)
Enumerate every g with g*x=x and retain them in group-index order. The result is a subgroup of G, not the orbit in the point carrier or merely one fixed-element witness. The exact result, retaining the requested order, is (2, [0], 1, Yes, all_group_elements_checked).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-stabilizer-of-point · candidate
20. The Point Stabilizer Enumerates Every Fixing Group Element
Use complete group table=[[0, 1, 2, 3, 4, 5], [1, 2, 3, 4, 5, 0], [2, 3, 4, 5, 0, 1], [3, 4, 5, 0, 1, 2], [4, 5, 0, 1, 2, 3], [5, 0, 1, 2, 3, 4]], identity=0, point carrier Fin(9)={0,…,8} and total action_table=[[0, 1, 2, 3, 4, 5, 6, 7, 8], [1, 2, 3, 4, 5, 0, 6, 7, 8], [2, 3, 4, 5, 0, 1, 6, 7, 8], [3, 4, 5, 0, 1, 2, 6, 7, 8], [4, 5, 0, 1, 2, 3, 6, 7, 8], [5, 0, 1, 2, 3, 4, 6, 7, 8]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=1. Give (point, stabilizer, stabilizer_order, full_enumeration_certificate, certificate).
View answer and explanation
(1, [0], 1, Yes, all_group_elements_checked)
Enumerate every g with g*x=x and retain them in group-index order. The result is a subgroup of G, not the orbit in the point carrier or merely one fixed-element witness. The exact result, retaining the requested order, is (1, [0], 1, Yes, all_group_elements_checked).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-stabilizer-of-point · candidate
21. The Point Stabilizer Enumerates Every Fixing Group Element
Use complete group table=[[0, 1], [1, 0]], identity=0, point carrier Fin(6)={0,…,5} and total action_table=[[0, 1, 2, 3, 4, 5], [1, 0, 2, 3, 4, 5]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=2. Give (point, stabilizer, stabilizer_order, full_enumeration_certificate, certificate).
View answer and explanation
(2, [0, 1], 2, Yes, all_group_elements_checked)
Enumerate every g with g*x=x and retain them in group-index order. The result is a subgroup of G, not the orbit in the point carrier or merely one fixed-element witness. The exact result, retaining the requested order, is (2, [0, 1], 2, Yes, all_group_elements_checked).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-stabilizer-of-point · candidate
22. The Point Stabilizer Enumerates Every Fixing Group Element
Use complete group table=[[0, 1, 2], [1, 2, 0], [2, 0, 1]], identity=0, point carrier Fin(7)={0,…,6} and total action_table=[[0, 1, 2, 3, 4, 5, 6], [1, 2, 0, 3, 4, 5, 6], [2, 0, 1, 3, 4, 5, 6]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=0. Give (point, stabilizer, stabilizer_order, full_enumeration_certificate, certificate).
View answer and explanation
(0, [0], 1, Yes, all_group_elements_checked)
Enumerate every g with g*x=x and retain them in group-index order. The result is a subgroup of G, not the orbit in the point carrier or merely one fixed-element witness. The exact result, retaining the requested order, is (0, [0], 1, Yes, all_group_elements_checked).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-stabilizer-of-point · candidate
23. The Point Stabilizer Enumerates Every Fixing Group Element
Use complete group table=[[0, 1, 2, 3], [1, 2, 3, 0], [2, 3, 0, 1], [3, 0, 1, 2]], identity=0, point carrier Fin(8)={0,…,7} and total action_table=[[0, 1, 2, 3, 4, 5, 6, 7], [1, 2, 3, 0, 4, 5, 6, 7], [2, 3, 0, 1, 4, 5, 6, 7], [3, 0, 1, 2, 4, 5, 6, 7]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=6. Give (point, stabilizer, stabilizer_order, full_enumeration_certificate, certificate).
View answer and explanation
(6, [0, 1, 2, 3], 4, Yes, all_group_elements_checked)
Enumerate every g with g*x=x and retain them in group-index order. The result is a subgroup of G, not the orbit in the point carrier or merely one fixed-element witness. The exact result, retaining the requested order, is (6, [0, 1, 2, 3], 4, Yes, all_group_elements_checked).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-stabilizer-of-point · candidate
24. The Point Stabilizer Enumerates Every Fixing Group Element
Use complete group table=[[0, 1, 2, 3, 4], [1, 2, 3, 4, 0], [2, 3, 4, 0, 1], [3, 4, 0, 1, 2], [4, 0, 1, 2, 3]], identity=0, point carrier Fin(9)={0,…,8} and total action_table=[[0, 1, 2, 3, 4, 5, 6, 7, 8], [1, 2, 3, 4, 0, 5, 6, 7, 8], [2, 3, 4, 0, 1, 5, 6, 7, 8], [3, 4, 0, 1, 2, 5, 6, 7, 8], [4, 0, 1, 2, 3, 5, 6, 7, 8]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=5. Give (point, stabilizer, stabilizer_order, full_enumeration_certificate, certificate).
View answer and explanation
(5, [0, 1, 2, 3, 4], 5, Yes, all_group_elements_checked)
Enumerate every g with g*x=x and retain them in group-index order. The result is a subgroup of G, not the orbit in the point carrier or merely one fixed-element witness. The exact result, retaining the requested order, is (5, [0, 1, 2, 3, 4], 5, Yes, all_group_elements_checked).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-stabilizer-of-point · candidate
25. The Point Stabilizer Enumerates Every Fixing Group Element
Use complete group table=[[0, 1, 2, 3, 4, 5], [1, 2, 3, 4, 5, 0], [2, 3, 4, 5, 0, 1], [3, 4, 5, 0, 1, 2], [4, 5, 0, 1, 2, 3], [5, 0, 1, 2, 3, 4]], identity=0, point carrier Fin(10)={0,…,9} and total action_table=[[0, 1, 2, 3, 4, 5, 6, 7, 8, 9], [1, 2, 3, 4, 5, 0, 6, 7, 8, 9], [2, 3, 4, 5, 0, 1, 6, 7, 8, 9], [3, 4, 5, 0, 1, 2, 6, 7, 8, 9], [4, 5, 0, 1, 2, 3, 6, 7, 8, 9], [5, 0, 1, 2, 3, 4, 6, 7, 8, 9]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=4. Give (point, stabilizer, stabilizer_order, full_enumeration_certificate, certificate).
View answer and explanation
(4, [0], 1, Yes, all_group_elements_checked)
Enumerate every g with g*x=x and retain them in group-index order. The result is a subgroup of G, not the orbit in the point carrier or merely one fixed-element witness. The exact result, retaining the requested order, is (4, [0], 1, Yes, all_group_elements_checked).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-stabilizer-of-point · candidate
26. Identity, Product and Inverse Closure Certify the Full Stabilizer
Use complete group table=[[0, 1], [1, 0]], identity=0, point carrier Fin(2)={0,…,1} and total action_table=[[0, 1], [1, 0]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=0. Give (stabilizer, identity, contains_identity, product_closed, inverse_closed, subgroup, certificate).
View answer and explanation
([0], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure)
First compute the entire stabilizer, then separately check identity membership, every product of its members and the inverse of every member using the same group table. All three obligations supply the subgroup flag. The exact result, retaining the requested order, is ([0], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-subgroup-certificate · candidate
27. Identity, Product and Inverse Closure Certify the Full Stabilizer
Use complete group table=[[0, 1, 2], [1, 2, 0], [2, 0, 1]], identity=0, point carrier Fin(3)={0,…,2} and total action_table=[[0, 1, 2], [1, 2, 0], [2, 0, 1]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=1. Give (stabilizer, identity, contains_identity, product_closed, inverse_closed, subgroup, certificate).
View answer and explanation
([0], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure)
First compute the entire stabilizer, then separately check identity membership, every product of its members and the inverse of every member using the same group table. All three obligations supply the subgroup flag. The exact result, retaining the requested order, is ([0], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-subgroup-certificate · candidate
28. Identity, Product and Inverse Closure Certify the Full Stabilizer
Use complete group table=[[0, 1, 2, 3], [1, 2, 3, 0], [2, 3, 0, 1], [3, 0, 1, 2]], identity=0, point carrier Fin(4)={0,…,3} and total action_table=[[0, 1, 2, 3], [1, 2, 3, 0], [2, 3, 0, 1], [3, 0, 1, 2]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=2. Give (stabilizer, identity, contains_identity, product_closed, inverse_closed, subgroup, certificate).
View answer and explanation
([0], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure)
First compute the entire stabilizer, then separately check identity membership, every product of its members and the inverse of every member using the same group table. All three obligations supply the subgroup flag. The exact result, retaining the requested order, is ([0], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-subgroup-certificate · candidate
29. Identity, Product and Inverse Closure Certify the Full Stabilizer
Use complete group table=[[0, 1, 2, 3, 4], [1, 2, 3, 4, 0], [2, 3, 4, 0, 1], [3, 4, 0, 1, 2], [4, 0, 1, 2, 3]], identity=0, point carrier Fin(5)={0,…,4} and total action_table=[[0, 1, 2, 3, 4], [1, 2, 3, 4, 0], [2, 3, 4, 0, 1], [3, 4, 0, 1, 2], [4, 0, 1, 2, 3]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=3. Give (stabilizer, identity, contains_identity, product_closed, inverse_closed, subgroup, certificate).
View answer and explanation
([0], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure)
First compute the entire stabilizer, then separately check identity membership, every product of its members and the inverse of every member using the same group table. All three obligations supply the subgroup flag. The exact result, retaining the requested order, is ([0], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-subgroup-certificate · candidate
30. Identity, Product and Inverse Closure Certify the Full Stabilizer
Use complete group table=[[0, 1, 2, 3, 4, 5], [1, 2, 3, 4, 5, 0], [2, 3, 4, 5, 0, 1], [3, 4, 5, 0, 1, 2], [4, 5, 0, 1, 2, 3], [5, 0, 1, 2, 3, 4]], identity=0, point carrier Fin(6)={0,…,5} and total action_table=[[0, 1, 2, 3, 4, 5], [1, 2, 3, 4, 5, 0], [2, 3, 4, 5, 0, 1], [3, 4, 5, 0, 1, 2], [4, 5, 0, 1, 2, 3], [5, 0, 1, 2, 3, 4]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=4. Give (stabilizer, identity, contains_identity, product_closed, inverse_closed, subgroup, certificate).
View answer and explanation
([0], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure)
First compute the entire stabilizer, then separately check identity membership, every product of its members and the inverse of every member using the same group table. All three obligations supply the subgroup flag. The exact result, retaining the requested order, is ([0], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-subgroup-certificate · candidate
31. Identity, Product and Inverse Closure Certify the Full Stabilizer
Use complete group table=[[0, 1], [1, 0]], identity=0, point carrier Fin(3)={0,…,2} and total action_table=[[0, 1, 2], [1, 0, 2]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=2. Give (stabilizer, identity, contains_identity, product_closed, inverse_closed, subgroup, certificate).
View answer and explanation
([0, 1], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure)
First compute the entire stabilizer, then separately check identity membership, every product of its members and the inverse of every member using the same group table. All three obligations supply the subgroup flag. The exact result, retaining the requested order, is ([0, 1], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-subgroup-certificate · candidate
32. Identity, Product and Inverse Closure Certify the Full Stabilizer
Use complete group table=[[0, 1, 2], [1, 2, 0], [2, 0, 1]], identity=0, point carrier Fin(4)={0,…,3} and total action_table=[[0, 1, 2, 3], [1, 2, 0, 3], [2, 0, 1, 3]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=2. Give (stabilizer, identity, contains_identity, product_closed, inverse_closed, subgroup, certificate).
View answer and explanation
([0], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure)
First compute the entire stabilizer, then separately check identity membership, every product of its members and the inverse of every member using the same group table. All three obligations supply the subgroup flag. The exact result, retaining the requested order, is ([0], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-subgroup-certificate · candidate
33. Identity, Product and Inverse Closure Certify the Full Stabilizer
Use complete group table=[[0, 1, 2, 3], [1, 2, 3, 0], [2, 3, 0, 1], [3, 0, 1, 2]], identity=0, point carrier Fin(5)={0,…,4} and total action_table=[[0, 1, 2, 3, 4], [1, 2, 3, 0, 4], [2, 3, 0, 1, 4], [3, 0, 1, 2, 4]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=2. Give (stabilizer, identity, contains_identity, product_closed, inverse_closed, subgroup, certificate).
View answer and explanation
([0], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure)
First compute the entire stabilizer, then separately check identity membership, every product of its members and the inverse of every member using the same group table. All three obligations supply the subgroup flag. The exact result, retaining the requested order, is ([0], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-subgroup-certificate · candidate
34. Identity, Product and Inverse Closure Certify the Full Stabilizer
Use complete group table=[[0, 1, 2, 3, 4], [1, 2, 3, 4, 0], [2, 3, 4, 0, 1], [3, 4, 0, 1, 2], [4, 0, 1, 2, 3]], identity=0, point carrier Fin(6)={0,…,5} and total action_table=[[0, 1, 2, 3, 4, 5], [1, 2, 3, 4, 0, 5], [2, 3, 4, 0, 1, 5], [3, 4, 0, 1, 2, 5], [4, 0, 1, 2, 3, 5]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=2. Give (stabilizer, identity, contains_identity, product_closed, inverse_closed, subgroup, certificate).
View answer and explanation
([0], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure)
First compute the entire stabilizer, then separately check identity membership, every product of its members and the inverse of every member using the same group table. All three obligations supply the subgroup flag. The exact result, retaining the requested order, is ([0], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-subgroup-certificate · candidate
35. Identity, Product and Inverse Closure Certify the Full Stabilizer
Use complete group table=[[0, 1, 2, 3, 4, 5], [1, 2, 3, 4, 5, 0], [2, 3, 4, 5, 0, 1], [3, 4, 5, 0, 1, 2], [4, 5, 0, 1, 2, 3], [5, 0, 1, 2, 3, 4]], identity=0, point carrier Fin(7)={0,…,6} and total action_table=[[0, 1, 2, 3, 4, 5, 6], [1, 2, 3, 4, 5, 0, 6], [2, 3, 4, 5, 0, 1, 6], [3, 4, 5, 0, 1, 2, 6], [4, 5, 0, 1, 2, 3, 6], [5, 0, 1, 2, 3, 4, 6]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=2. Give (stabilizer, identity, contains_identity, product_closed, inverse_closed, subgroup, certificate).
View answer and explanation
([0], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure)
First compute the entire stabilizer, then separately check identity membership, every product of its members and the inverse of every member using the same group table. All three obligations supply the subgroup flag. The exact result, retaining the requested order, is ([0], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-subgroup-certificate · candidate
36. Identity, Product and Inverse Closure Certify the Full Stabilizer
Use complete group table=[[0, 1], [1, 0]], identity=0, point carrier Fin(4)={0,…,3} and total action_table=[[0, 1, 2, 3], [1, 0, 2, 3]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=2. Give (stabilizer, identity, contains_identity, product_closed, inverse_closed, subgroup, certificate).
View answer and explanation
([0, 1], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure)
First compute the entire stabilizer, then separately check identity membership, every product of its members and the inverse of every member using the same group table. All three obligations supply the subgroup flag. The exact result, retaining the requested order, is ([0, 1], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-subgroup-certificate · candidate
37. Identity, Product and Inverse Closure Certify the Full Stabilizer
Use complete group table=[[0, 1, 2], [1, 2, 0], [2, 0, 1]], identity=0, point carrier Fin(5)={0,…,4} and total action_table=[[0, 1, 2, 3, 4], [1, 2, 0, 3, 4], [2, 0, 1, 3, 4]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=1. Give (stabilizer, identity, contains_identity, product_closed, inverse_closed, subgroup, certificate).
View answer and explanation
([0], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure)
First compute the entire stabilizer, then separately check identity membership, every product of its members and the inverse of every member using the same group table. All three obligations supply the subgroup flag. The exact result, retaining the requested order, is ([0], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-subgroup-certificate · candidate
38. Identity, Product and Inverse Closure Certify the Full Stabilizer
Use complete group table=[[0, 1, 2, 3], [1, 2, 3, 0], [2, 3, 0, 1], [3, 0, 1, 2]], identity=0, point carrier Fin(6)={0,…,5} and total action_table=[[0, 1, 2, 3, 4, 5], [1, 2, 3, 0, 4, 5], [2, 3, 0, 1, 4, 5], [3, 0, 1, 2, 4, 5]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=0. Give (stabilizer, identity, contains_identity, product_closed, inverse_closed, subgroup, certificate).
View answer and explanation
([0], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure)
First compute the entire stabilizer, then separately check identity membership, every product of its members and the inverse of every member using the same group table. All three obligations supply the subgroup flag. The exact result, retaining the requested order, is ([0], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-subgroup-certificate · candidate
39. Identity, Product and Inverse Closure Certify the Full Stabilizer
Use complete group table=[[0, 1, 2, 3, 4], [1, 2, 3, 4, 0], [2, 3, 4, 0, 1], [3, 4, 0, 1, 2], [4, 0, 1, 2, 3]], identity=0, point carrier Fin(7)={0,…,6} and total action_table=[[0, 1, 2, 3, 4, 5, 6], [1, 2, 3, 4, 0, 5, 6], [2, 3, 4, 0, 1, 5, 6], [3, 4, 0, 1, 2, 5, 6], [4, 0, 1, 2, 3, 5, 6]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=6. Give (stabilizer, identity, contains_identity, product_closed, inverse_closed, subgroup, certificate).
View answer and explanation
([0, 1, 2, 3, 4], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure)
First compute the entire stabilizer, then separately check identity membership, every product of its members and the inverse of every member using the same group table. All three obligations supply the subgroup flag. The exact result, retaining the requested order, is ([0, 1, 2, 3, 4], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-subgroup-certificate · candidate
40. Identity, Product and Inverse Closure Certify the Full Stabilizer
Use complete group table=[[0, 1, 2, 3, 4, 5], [1, 2, 3, 4, 5, 0], [2, 3, 4, 5, 0, 1], [3, 4, 5, 0, 1, 2], [4, 5, 0, 1, 2, 3], [5, 0, 1, 2, 3, 4]], identity=0, point carrier Fin(8)={0,…,7} and total action_table=[[0, 1, 2, 3, 4, 5, 6, 7], [1, 2, 3, 4, 5, 0, 6, 7], [2, 3, 4, 5, 0, 1, 6, 7], [3, 4, 5, 0, 1, 2, 6, 7], [4, 5, 0, 1, 2, 3, 6, 7], [5, 0, 1, 2, 3, 4, 6, 7]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=6. Give (stabilizer, identity, contains_identity, product_closed, inverse_closed, subgroup, certificate).
View answer and explanation
([0, 1, 2, 3, 4, 5], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure)
First compute the entire stabilizer, then separately check identity membership, every product of its members and the inverse of every member using the same group table. All three obligations supply the subgroup flag. The exact result, retaining the requested order, is ([0, 1, 2, 3, 4, 5], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-subgroup-certificate · candidate
41. Identity, Product and Inverse Closure Certify the Full Stabilizer
Use complete group table=[[0, 1], [1, 0]], identity=0, point carrier Fin(5)={0,…,4} and total action_table=[[0, 1, 2, 3, 4], [1, 0, 2, 3, 4]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=0. Give (stabilizer, identity, contains_identity, product_closed, inverse_closed, subgroup, certificate).
View answer and explanation
([0], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure)
First compute the entire stabilizer, then separately check identity membership, every product of its members and the inverse of every member using the same group table. All three obligations supply the subgroup flag. The exact result, retaining the requested order, is ([0], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-subgroup-certificate · candidate
42. Identity, Product and Inverse Closure Certify the Full Stabilizer
Use complete group table=[[0, 1, 2], [1, 2, 0], [2, 0, 1]], identity=0, point carrier Fin(6)={0,…,5} and total action_table=[[0, 1, 2, 3, 4, 5], [1, 2, 0, 3, 4, 5], [2, 0, 1, 3, 4, 5]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=4. Give (stabilizer, identity, contains_identity, product_closed, inverse_closed, subgroup, certificate).
View answer and explanation
([0, 1, 2], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure)
First compute the entire stabilizer, then separately check identity membership, every product of its members and the inverse of every member using the same group table. All three obligations supply the subgroup flag. The exact result, retaining the requested order, is ([0, 1, 2], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-subgroup-certificate · candidate
43. Identity, Product and Inverse Closure Certify the Full Stabilizer
Use complete group table=[[0, 1, 2, 3], [1, 2, 3, 0], [2, 3, 0, 1], [3, 0, 1, 2]], identity=0, point carrier Fin(7)={0,…,6} and total action_table=[[0, 1, 2, 3, 4, 5, 6], [1, 2, 3, 0, 4, 5, 6], [2, 3, 0, 1, 4, 5, 6], [3, 0, 1, 2, 4, 5, 6]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=3. Give (stabilizer, identity, contains_identity, product_closed, inverse_closed, subgroup, certificate).
View answer and explanation
([0], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure)
First compute the entire stabilizer, then separately check identity membership, every product of its members and the inverse of every member using the same group table. All three obligations supply the subgroup flag. The exact result, retaining the requested order, is ([0], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-subgroup-certificate · candidate
44. Identity, Product and Inverse Closure Certify the Full Stabilizer
Use complete group table=[[0, 1, 2, 3, 4], [1, 2, 3, 4, 0], [2, 3, 4, 0, 1], [3, 4, 0, 1, 2], [4, 0, 1, 2, 3]], identity=0, point carrier Fin(8)={0,…,7} and total action_table=[[0, 1, 2, 3, 4, 5, 6, 7], [1, 2, 3, 4, 0, 5, 6, 7], [2, 3, 4, 0, 1, 5, 6, 7], [3, 4, 0, 1, 2, 5, 6, 7], [4, 0, 1, 2, 3, 5, 6, 7]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=2. Give (stabilizer, identity, contains_identity, product_closed, inverse_closed, subgroup, certificate).
View answer and explanation
([0], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure)
First compute the entire stabilizer, then separately check identity membership, every product of its members and the inverse of every member using the same group table. All three obligations supply the subgroup flag. The exact result, retaining the requested order, is ([0], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-subgroup-certificate · candidate
45. Identity, Product and Inverse Closure Certify the Full Stabilizer
Use complete group table=[[0, 1, 2, 3, 4, 5], [1, 2, 3, 4, 5, 0], [2, 3, 4, 5, 0, 1], [3, 4, 5, 0, 1, 2], [4, 5, 0, 1, 2, 3], [5, 0, 1, 2, 3, 4]], identity=0, point carrier Fin(9)={0,…,8} and total action_table=[[0, 1, 2, 3, 4, 5, 6, 7, 8], [1, 2, 3, 4, 5, 0, 6, 7, 8], [2, 3, 4, 5, 0, 1, 6, 7, 8], [3, 4, 5, 0, 1, 2, 6, 7, 8], [4, 5, 0, 1, 2, 3, 6, 7, 8], [5, 0, 1, 2, 3, 4, 6, 7, 8]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=1. Give (stabilizer, identity, contains_identity, product_closed, inverse_closed, subgroup, certificate).
View answer and explanation
([0], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure)
First compute the entire stabilizer, then separately check identity membership, every product of its members and the inverse of every member using the same group table. All three obligations supply the subgroup flag. The exact result, retaining the requested order, is ([0], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-subgroup-certificate · candidate
46. Identity, Product and Inverse Closure Certify the Full Stabilizer
Use complete group table=[[0, 1], [1, 0]], identity=0, point carrier Fin(6)={0,…,5} and total action_table=[[0, 1, 2, 3, 4, 5], [1, 0, 2, 3, 4, 5]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=2. Give (stabilizer, identity, contains_identity, product_closed, inverse_closed, subgroup, certificate).
View answer and explanation
([0, 1], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure)
First compute the entire stabilizer, then separately check identity membership, every product of its members and the inverse of every member using the same group table. All three obligations supply the subgroup flag. The exact result, retaining the requested order, is ([0, 1], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-subgroup-certificate · candidate
47. Identity, Product and Inverse Closure Certify the Full Stabilizer
Use complete group table=[[0, 1, 2], [1, 2, 0], [2, 0, 1]], identity=0, point carrier Fin(7)={0,…,6} and total action_table=[[0, 1, 2, 3, 4, 5, 6], [1, 2, 0, 3, 4, 5, 6], [2, 0, 1, 3, 4, 5, 6]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=0. Give (stabilizer, identity, contains_identity, product_closed, inverse_closed, subgroup, certificate).
View answer and explanation
([0], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure)
First compute the entire stabilizer, then separately check identity membership, every product of its members and the inverse of every member using the same group table. All three obligations supply the subgroup flag. The exact result, retaining the requested order, is ([0], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-subgroup-certificate · candidate
48. Identity, Product and Inverse Closure Certify the Full Stabilizer
Use complete group table=[[0, 1, 2, 3], [1, 2, 3, 0], [2, 3, 0, 1], [3, 0, 1, 2]], identity=0, point carrier Fin(8)={0,…,7} and total action_table=[[0, 1, 2, 3, 4, 5, 6, 7], [1, 2, 3, 0, 4, 5, 6, 7], [2, 3, 0, 1, 4, 5, 6, 7], [3, 0, 1, 2, 4, 5, 6, 7]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=6. Give (stabilizer, identity, contains_identity, product_closed, inverse_closed, subgroup, certificate).
View answer and explanation
([0, 1, 2, 3], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure)
First compute the entire stabilizer, then separately check identity membership, every product of its members and the inverse of every member using the same group table. All three obligations supply the subgroup flag. The exact result, retaining the requested order, is ([0, 1, 2, 3], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-subgroup-certificate · candidate
49. Identity, Product and Inverse Closure Certify the Full Stabilizer
Use complete group table=[[0, 1, 2, 3, 4], [1, 2, 3, 4, 0], [2, 3, 4, 0, 1], [3, 4, 0, 1, 2], [4, 0, 1, 2, 3]], identity=0, point carrier Fin(9)={0,…,8} and total action_table=[[0, 1, 2, 3, 4, 5, 6, 7, 8], [1, 2, 3, 4, 0, 5, 6, 7, 8], [2, 3, 4, 0, 1, 5, 6, 7, 8], [3, 4, 0, 1, 2, 5, 6, 7, 8], [4, 0, 1, 2, 3, 5, 6, 7, 8]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=5. Give (stabilizer, identity, contains_identity, product_closed, inverse_closed, subgroup, certificate).
View answer and explanation
([0, 1, 2, 3, 4], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure)
First compute the entire stabilizer, then separately check identity membership, every product of its members and the inverse of every member using the same group table. All three obligations supply the subgroup flag. The exact result, retaining the requested order, is ([0, 1, 2, 3, 4], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-subgroup-certificate · candidate
50. Identity, Product and Inverse Closure Certify the Full Stabilizer
Use complete group table=[[0, 1, 2, 3, 4, 5], [1, 2, 3, 4, 5, 0], [2, 3, 4, 5, 0, 1], [3, 4, 5, 0, 1, 2], [4, 5, 0, 1, 2, 3], [5, 0, 1, 2, 3, 4]], identity=0, point carrier Fin(10)={0,…,9} and total action_table=[[0, 1, 2, 3, 4, 5, 6, 7, 8, 9], [1, 2, 3, 4, 5, 0, 6, 7, 8, 9], [2, 3, 4, 5, 0, 1, 6, 7, 8, 9], [3, 4, 5, 0, 1, 2, 6, 7, 8, 9], [4, 5, 0, 1, 2, 3, 6, 7, 8, 9], [5, 0, 1, 2, 3, 4, 6, 7, 8, 9]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=4. Give (stabilizer, identity, contains_identity, product_closed, inverse_closed, subgroup, certificate).
View answer and explanation
([0], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure)
First compute the entire stabilizer, then separately check identity membership, every product of its members and the inverse of every member using the same group table. All three obligations supply the subgroup flag. The exact result, retaining the requested order, is ([0], 0, Yes, Yes, Yes, Yes, identity_product_inverse_closure).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-subgroup-certificate · candidate
51. Fixing This Point Is Exactly Membership in Its Stabilizer
Use complete group table=[[0, 1], [1, 0]], identity=0, point carrier Fin(2)={0,…,1} and total action_table=[[0, 1], [1, 0]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=0. Test group_element=0. Give (group_element, point, image, fixes_point, in_stabilizer).
View answer and explanation
(0, 0, 0, Yes, Yes)
Read its action image, compare with the specified point and separately report membership in the complete stabilizer. An image different from x makes both flags No. The exact result, retaining the requested order, is (0, 0, 0, Yes, Yes).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-membership-audit · candidate
52. Fixing This Point Is Exactly Membership in Its Stabilizer
Use complete group table=[[0, 1, 2], [1, 2, 0], [2, 0, 1]], identity=0, point carrier Fin(3)={0,…,2} and total action_table=[[0, 1, 2], [1, 2, 0], [2, 0, 1]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=1. Test group_element=1. Give (group_element, point, image, fixes_point, in_stabilizer).
View answer and explanation
(1, 1, 2, No, No)
Read its action image, compare with the specified point and separately report membership in the complete stabilizer. An image different from x makes both flags No. The exact result, retaining the requested order, is (1, 1, 2, No, No).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-membership-audit · candidate
53. Fixing This Point Is Exactly Membership in Its Stabilizer
Use complete group table=[[0, 1, 2, 3], [1, 2, 3, 0], [2, 3, 0, 1], [3, 0, 1, 2]], identity=0, point carrier Fin(4)={0,…,3} and total action_table=[[0, 1, 2, 3], [1, 2, 3, 0], [2, 3, 0, 1], [3, 0, 1, 2]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=2. Test group_element=2. Give (group_element, point, image, fixes_point, in_stabilizer).
View answer and explanation
(2, 2, 0, No, No)
Read its action image, compare with the specified point and separately report membership in the complete stabilizer. An image different from x makes both flags No. The exact result, retaining the requested order, is (2, 2, 0, No, No).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-membership-audit · candidate
54. Fixing This Point Is Exactly Membership in Its Stabilizer
Use complete group table=[[0, 1, 2, 3, 4], [1, 2, 3, 4, 0], [2, 3, 4, 0, 1], [3, 4, 0, 1, 2], [4, 0, 1, 2, 3]], identity=0, point carrier Fin(5)={0,…,4} and total action_table=[[0, 1, 2, 3, 4], [1, 2, 3, 4, 0], [2, 3, 4, 0, 1], [3, 4, 0, 1, 2], [4, 0, 1, 2, 3]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=3. Test group_element=3. Give (group_element, point, image, fixes_point, in_stabilizer).
View answer and explanation
(3, 3, 1, No, No)
Read its action image, compare with the specified point and separately report membership in the complete stabilizer. An image different from x makes both flags No. The exact result, retaining the requested order, is (3, 3, 1, No, No).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-membership-audit · candidate
55. Fixing This Point Is Exactly Membership in Its Stabilizer
Use complete group table=[[0, 1, 2, 3, 4, 5], [1, 2, 3, 4, 5, 0], [2, 3, 4, 5, 0, 1], [3, 4, 5, 0, 1, 2], [4, 5, 0, 1, 2, 3], [5, 0, 1, 2, 3, 4]], identity=0, point carrier Fin(6)={0,…,5} and total action_table=[[0, 1, 2, 3, 4, 5], [1, 2, 3, 4, 5, 0], [2, 3, 4, 5, 0, 1], [3, 4, 5, 0, 1, 2], [4, 5, 0, 1, 2, 3], [5, 0, 1, 2, 3, 4]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=4. Test group_element=4. Give (group_element, point, image, fixes_point, in_stabilizer).
View answer and explanation
(4, 4, 2, No, No)
Read its action image, compare with the specified point and separately report membership in the complete stabilizer. An image different from x makes both flags No. The exact result, retaining the requested order, is (4, 4, 2, No, No).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-membership-audit · candidate
56. Fixing This Point Is Exactly Membership in Its Stabilizer
Use complete group table=[[0, 1], [1, 0]], identity=0, point carrier Fin(3)={0,…,2} and total action_table=[[0, 1, 2], [1, 0, 2]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=2. Test group_element=1. Give (group_element, point, image, fixes_point, in_stabilizer).
View answer and explanation
(1, 2, 2, Yes, Yes)
Read its action image, compare with the specified point and separately report membership in the complete stabilizer. An image different from x makes both flags No. The exact result, retaining the requested order, is (1, 2, 2, Yes, Yes).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-membership-audit · candidate
57. Fixing This Point Is Exactly Membership in Its Stabilizer
Use complete group table=[[0, 1, 2], [1, 2, 0], [2, 0, 1]], identity=0, point carrier Fin(4)={0,…,3} and total action_table=[[0, 1, 2, 3], [1, 2, 0, 3], [2, 0, 1, 3]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=2. Test group_element=0. Give (group_element, point, image, fixes_point, in_stabilizer).
View answer and explanation
(0, 2, 2, Yes, Yes)
Read its action image, compare with the specified point and separately report membership in the complete stabilizer. An image different from x makes both flags No. The exact result, retaining the requested order, is (0, 2, 2, Yes, Yes).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-membership-audit · candidate
58. Fixing This Point Is Exactly Membership in Its Stabilizer
Use complete group table=[[0, 1, 2, 3], [1, 2, 3, 0], [2, 3, 0, 1], [3, 0, 1, 2]], identity=0, point carrier Fin(5)={0,…,4} and total action_table=[[0, 1, 2, 3, 4], [1, 2, 3, 0, 4], [2, 3, 0, 1, 4], [3, 0, 1, 2, 4]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=2. Test group_element=3. Give (group_element, point, image, fixes_point, in_stabilizer).
View answer and explanation
(3, 2, 1, No, No)
Read its action image, compare with the specified point and separately report membership in the complete stabilizer. An image different from x makes both flags No. The exact result, retaining the requested order, is (3, 2, 1, No, No).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-membership-audit · candidate
59. Fixing This Point Is Exactly Membership in Its Stabilizer
Use complete group table=[[0, 1, 2, 3, 4], [1, 2, 3, 4, 0], [2, 3, 4, 0, 1], [3, 4, 0, 1, 2], [4, 0, 1, 2, 3]], identity=0, point carrier Fin(6)={0,…,5} and total action_table=[[0, 1, 2, 3, 4, 5], [1, 2, 3, 4, 0, 5], [2, 3, 4, 0, 1, 5], [3, 4, 0, 1, 2, 5], [4, 0, 1, 2, 3, 5]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=2. Test group_element=3. Give (group_element, point, image, fixes_point, in_stabilizer).
View answer and explanation
(3, 2, 0, No, No)
Read its action image, compare with the specified point and separately report membership in the complete stabilizer. An image different from x makes both flags No. The exact result, retaining the requested order, is (3, 2, 0, No, No).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-membership-audit · candidate
60. Fixing This Point Is Exactly Membership in Its Stabilizer
Use complete group table=[[0, 1, 2, 3, 4, 5], [1, 2, 3, 4, 5, 0], [2, 3, 4, 5, 0, 1], [3, 4, 5, 0, 1, 2], [4, 5, 0, 1, 2, 3], [5, 0, 1, 2, 3, 4]], identity=0, point carrier Fin(7)={0,…,6} and total action_table=[[0, 1, 2, 3, 4, 5, 6], [1, 2, 3, 4, 5, 0, 6], [2, 3, 4, 5, 0, 1, 6], [3, 4, 5, 0, 1, 2, 6], [4, 5, 0, 1, 2, 3, 6], [5, 0, 1, 2, 3, 4, 6]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=2. Test group_element=3. Give (group_element, point, image, fixes_point, in_stabilizer).
View answer and explanation
(3, 2, 5, No, No)
Read its action image, compare with the specified point and separately report membership in the complete stabilizer. An image different from x makes both flags No. The exact result, retaining the requested order, is (3, 2, 5, No, No).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-membership-audit · candidate
61. Fixing This Point Is Exactly Membership in Its Stabilizer
Use complete group table=[[0, 1], [1, 0]], identity=0, point carrier Fin(4)={0,…,3} and total action_table=[[0, 1, 2, 3], [1, 0, 2, 3]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=2. Test group_element=0. Give (group_element, point, image, fixes_point, in_stabilizer).
View answer and explanation
(0, 2, 2, Yes, Yes)
Read its action image, compare with the specified point and separately report membership in the complete stabilizer. An image different from x makes both flags No. The exact result, retaining the requested order, is (0, 2, 2, Yes, Yes).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-membership-audit · candidate
62. Fixing This Point Is Exactly Membership in Its Stabilizer
Use complete group table=[[0, 1, 2], [1, 2, 0], [2, 0, 1]], identity=0, point carrier Fin(5)={0,…,4} and total action_table=[[0, 1, 2, 3, 4], [1, 2, 0, 3, 4], [2, 0, 1, 3, 4]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=1. Test group_element=2. Give (group_element, point, image, fixes_point, in_stabilizer).
View answer and explanation
(2, 1, 0, No, No)
Read its action image, compare with the specified point and separately report membership in the complete stabilizer. An image different from x makes both flags No. The exact result, retaining the requested order, is (2, 1, 0, No, No).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-membership-audit · candidate
63. Fixing This Point Is Exactly Membership in Its Stabilizer
Use complete group table=[[0, 1, 2, 3], [1, 2, 3, 0], [2, 3, 0, 1], [3, 0, 1, 2]], identity=0, point carrier Fin(6)={0,…,5} and total action_table=[[0, 1, 2, 3, 4, 5], [1, 2, 3, 0, 4, 5], [2, 3, 0, 1, 4, 5], [3, 0, 1, 2, 4, 5]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=0. Test group_element=0. Give (group_element, point, image, fixes_point, in_stabilizer).
View answer and explanation
(0, 0, 0, Yes, Yes)
Read its action image, compare with the specified point and separately report membership in the complete stabilizer. An image different from x makes both flags No. The exact result, retaining the requested order, is (0, 0, 0, Yes, Yes).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-membership-audit · candidate
64. Fixing This Point Is Exactly Membership in Its Stabilizer
Use complete group table=[[0, 1, 2, 3, 4], [1, 2, 3, 4, 0], [2, 3, 4, 0, 1], [3, 4, 0, 1, 2], [4, 0, 1, 2, 3]], identity=0, point carrier Fin(7)={0,…,6} and total action_table=[[0, 1, 2, 3, 4, 5, 6], [1, 2, 3, 4, 0, 5, 6], [2, 3, 4, 0, 1, 5, 6], [3, 4, 0, 1, 2, 5, 6], [4, 0, 1, 2, 3, 5, 6]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=6. Test group_element=3. Give (group_element, point, image, fixes_point, in_stabilizer).
View answer and explanation
(3, 6, 6, Yes, Yes)
Read its action image, compare with the specified point and separately report membership in the complete stabilizer. An image different from x makes both flags No. The exact result, retaining the requested order, is (3, 6, 6, Yes, Yes).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-membership-audit · candidate
65. Fixing This Point Is Exactly Membership in Its Stabilizer
Use complete group table=[[0, 1, 2, 3, 4, 5], [1, 2, 3, 4, 5, 0], [2, 3, 4, 5, 0, 1], [3, 4, 5, 0, 1, 2], [4, 5, 0, 1, 2, 3], [5, 0, 1, 2, 3, 4]], identity=0, point carrier Fin(8)={0,…,7} and total action_table=[[0, 1, 2, 3, 4, 5, 6, 7], [1, 2, 3, 4, 5, 0, 6, 7], [2, 3, 4, 5, 0, 1, 6, 7], [3, 4, 5, 0, 1, 2, 6, 7], [4, 5, 0, 1, 2, 3, 6, 7], [5, 0, 1, 2, 3, 4, 6, 7]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=6. Test group_element=2. Give (group_element, point, image, fixes_point, in_stabilizer).
View answer and explanation
(2, 6, 6, Yes, Yes)
Read its action image, compare with the specified point and separately report membership in the complete stabilizer. An image different from x makes both flags No. The exact result, retaining the requested order, is (2, 6, 6, Yes, Yes).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-membership-audit · candidate
66. Fixing This Point Is Exactly Membership in Its Stabilizer
Use complete group table=[[0, 1], [1, 0]], identity=0, point carrier Fin(5)={0,…,4} and total action_table=[[0, 1, 2, 3, 4], [1, 0, 2, 3, 4]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=0. Test group_element=1. Give (group_element, point, image, fixes_point, in_stabilizer).
View answer and explanation
(1, 0, 1, No, No)
Read its action image, compare with the specified point and separately report membership in the complete stabilizer. An image different from x makes both flags No. The exact result, retaining the requested order, is (1, 0, 1, No, No).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-membership-audit · candidate
67. Fixing This Point Is Exactly Membership in Its Stabilizer
Use complete group table=[[0, 1, 2], [1, 2, 0], [2, 0, 1]], identity=0, point carrier Fin(6)={0,…,5} and total action_table=[[0, 1, 2, 3, 4, 5], [1, 2, 0, 3, 4, 5], [2, 0, 1, 3, 4, 5]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=4. Test group_element=1. Give (group_element, point, image, fixes_point, in_stabilizer).
View answer and explanation
(1, 4, 4, Yes, Yes)
Read its action image, compare with the specified point and separately report membership in the complete stabilizer. An image different from x makes both flags No. The exact result, retaining the requested order, is (1, 4, 4, Yes, Yes).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-membership-audit · candidate
68. Fixing This Point Is Exactly Membership in Its Stabilizer
Use complete group table=[[0, 1, 2, 3], [1, 2, 3, 0], [2, 3, 0, 1], [3, 0, 1, 2]], identity=0, point carrier Fin(7)={0,…,6} and total action_table=[[0, 1, 2, 3, 4, 5, 6], [1, 2, 3, 0, 4, 5, 6], [2, 3, 0, 1, 4, 5, 6], [3, 0, 1, 2, 4, 5, 6]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=3. Test group_element=1. Give (group_element, point, image, fixes_point, in_stabilizer).
View answer and explanation
(1, 3, 0, No, No)
Read its action image, compare with the specified point and separately report membership in the complete stabilizer. An image different from x makes both flags No. The exact result, retaining the requested order, is (1, 3, 0, No, No).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-membership-audit · candidate
69. Fixing This Point Is Exactly Membership in Its Stabilizer
Use complete group table=[[0, 1, 2, 3, 4], [1, 2, 3, 4, 0], [2, 3, 4, 0, 1], [3, 4, 0, 1, 2], [4, 0, 1, 2, 3]], identity=0, point carrier Fin(8)={0,…,7} and total action_table=[[0, 1, 2, 3, 4, 5, 6, 7], [1, 2, 3, 4, 0, 5, 6, 7], [2, 3, 4, 0, 1, 5, 6, 7], [3, 4, 0, 1, 2, 5, 6, 7], [4, 0, 1, 2, 3, 5, 6, 7]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=2. Test group_element=3. Give (group_element, point, image, fixes_point, in_stabilizer).
View answer and explanation
(3, 2, 0, No, No)
Read its action image, compare with the specified point and separately report membership in the complete stabilizer. An image different from x makes both flags No. The exact result, retaining the requested order, is (3, 2, 0, No, No).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-membership-audit · candidate
70. Fixing This Point Is Exactly Membership in Its Stabilizer
Use complete group table=[[0, 1, 2, 3, 4, 5], [1, 2, 3, 4, 5, 0], [2, 3, 4, 5, 0, 1], [3, 4, 5, 0, 1, 2], [4, 5, 0, 1, 2, 3], [5, 0, 1, 2, 3, 4]], identity=0, point carrier Fin(9)={0,…,8} and total action_table=[[0, 1, 2, 3, 4, 5, 6, 7, 8], [1, 2, 3, 4, 5, 0, 6, 7, 8], [2, 3, 4, 5, 0, 1, 6, 7, 8], [3, 4, 5, 0, 1, 2, 6, 7, 8], [4, 5, 0, 1, 2, 3, 6, 7, 8], [5, 0, 1, 2, 3, 4, 6, 7, 8]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=1. Test group_element=1. Give (group_element, point, image, fixes_point, in_stabilizer).
View answer and explanation
(1, 1, 2, No, No)
Read its action image, compare with the specified point and separately report membership in the complete stabilizer. An image different from x makes both flags No. The exact result, retaining the requested order, is (1, 1, 2, No, No).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-membership-audit · candidate
71. Fixing This Point Is Exactly Membership in Its Stabilizer
Use complete group table=[[0, 1], [1, 0]], identity=0, point carrier Fin(6)={0,…,5} and total action_table=[[0, 1, 2, 3, 4, 5], [1, 0, 2, 3, 4, 5]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=2. Test group_element=0. Give (group_element, point, image, fixes_point, in_stabilizer).
View answer and explanation
(0, 2, 2, Yes, Yes)
Read its action image, compare with the specified point and separately report membership in the complete stabilizer. An image different from x makes both flags No. The exact result, retaining the requested order, is (0, 2, 2, Yes, Yes).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-membership-audit · candidate
72. Fixing This Point Is Exactly Membership in Its Stabilizer
Use complete group table=[[0, 1, 2], [1, 2, 0], [2, 0, 1]], identity=0, point carrier Fin(7)={0,…,6} and total action_table=[[0, 1, 2, 3, 4, 5, 6], [1, 2, 0, 3, 4, 5, 6], [2, 0, 1, 3, 4, 5, 6]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=0. Test group_element=0. Give (group_element, point, image, fixes_point, in_stabilizer).
View answer and explanation
(0, 0, 0, Yes, Yes)
Read its action image, compare with the specified point and separately report membership in the complete stabilizer. An image different from x makes both flags No. The exact result, retaining the requested order, is (0, 0, 0, Yes, Yes).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-membership-audit · candidate
73. Fixing This Point Is Exactly Membership in Its Stabilizer
Use complete group table=[[0, 1, 2, 3], [1, 2, 3, 0], [2, 3, 0, 1], [3, 0, 1, 2]], identity=0, point carrier Fin(8)={0,…,7} and total action_table=[[0, 1, 2, 3, 4, 5, 6, 7], [1, 2, 3, 0, 4, 5, 6, 7], [2, 3, 0, 1, 4, 5, 6, 7], [3, 0, 1, 2, 4, 5, 6, 7]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=6. Test group_element=2. Give (group_element, point, image, fixes_point, in_stabilizer).
View answer and explanation
(2, 6, 6, Yes, Yes)
Read its action image, compare with the specified point and separately report membership in the complete stabilizer. An image different from x makes both flags No. The exact result, retaining the requested order, is (2, 6, 6, Yes, Yes).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-membership-audit · candidate
74. Fixing This Point Is Exactly Membership in Its Stabilizer
Use complete group table=[[0, 1, 2, 3, 4], [1, 2, 3, 4, 0], [2, 3, 4, 0, 1], [3, 4, 0, 1, 2], [4, 0, 1, 2, 3]], identity=0, point carrier Fin(9)={0,…,8} and total action_table=[[0, 1, 2, 3, 4, 5, 6, 7, 8], [1, 2, 3, 4, 0, 5, 6, 7, 8], [2, 3, 4, 0, 1, 5, 6, 7, 8], [3, 4, 0, 1, 2, 5, 6, 7, 8], [4, 0, 1, 2, 3, 5, 6, 7, 8]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=5. Test group_element=3. Give (group_element, point, image, fixes_point, in_stabilizer).
View answer and explanation
(3, 5, 5, Yes, Yes)
Read its action image, compare with the specified point and separately report membership in the complete stabilizer. An image different from x makes both flags No. The exact result, retaining the requested order, is (3, 5, 5, Yes, Yes).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-membership-audit · candidate
75. Fixing This Point Is Exactly Membership in Its Stabilizer
Use complete group table=[[0, 1, 2, 3, 4, 5], [1, 2, 3, 4, 5, 0], [2, 3, 4, 5, 0, 1], [3, 4, 5, 0, 1, 2], [4, 5, 0, 1, 2, 3], [5, 0, 1, 2, 3, 4]], identity=0, point carrier Fin(10)={0,…,9} and total action_table=[[0, 1, 2, 3, 4, 5, 6, 7, 8, 9], [1, 2, 3, 4, 5, 0, 6, 7, 8, 9], [2, 3, 4, 5, 0, 1, 6, 7, 8, 9], [3, 4, 5, 0, 1, 2, 6, 7, 8, 9], [4, 5, 0, 1, 2, 3, 6, 7, 8, 9], [5, 0, 1, 2, 3, 4, 6, 7, 8, 9]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=4. Test group_element=0. Give (group_element, point, image, fixes_point, in_stabilizer).
View answer and explanation
(0, 4, 4, Yes, Yes)
Read its action image, compare with the specified point and separately report membership in the complete stabilizer. An image different from x makes both flags No. The exact result, retaining the requested order, is (0, 4, 4, Yes, Yes).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-membership-audit · candidate
76. Point Stabilizers May Agree without Becoming Orbits or Kernels
Use complete group table=[[0, 1], [1, 0]], identity=0, point carrier Fin(2)={0,…,1} and total action_table=[[0, 1], [1, 0]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=0. Compare other_point=1. Give (point, stabilizer, other_point, other_stabilizer, same_stabilizer, orbit_or_kernel_identification_claim, boundary).
The fixed No withholds identification of stabilizer, orbit and action kernel as concepts. It does not negate same_stabilizer or rule out equality of particular sets.
View answer and explanation
(0, [0], 1, [0], Yes, No, stabilizer_not_orbit_or_action_kernel)
Compute both complete stabilizers and their equality flag. The final fixed No withholds identification of stabilizer, orbit and action kernel as concepts; it does not negate equal stabilizers or rule out special set equalities. The exact result, retaining the requested order, is (0, [0], 1, [0], Yes, No, stabilizer_not_orbit_or_action_kernel).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-point-boundary · candidate
77. Point Stabilizers May Agree without Becoming Orbits or Kernels
Use complete group table=[[0, 1, 2], [1, 2, 0], [2, 0, 1]], identity=0, point carrier Fin(3)={0,…,2} and total action_table=[[0, 1, 2], [1, 2, 0], [2, 0, 1]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=1. Compare other_point=2. Give (point, stabilizer, other_point, other_stabilizer, same_stabilizer, orbit_or_kernel_identification_claim, boundary).
The fixed No withholds identification of stabilizer, orbit and action kernel as concepts. It does not negate same_stabilizer or rule out equality of particular sets.
View answer and explanation
(1, [0], 2, [0], Yes, No, stabilizer_not_orbit_or_action_kernel)
Compute both complete stabilizers and their equality flag. The final fixed No withholds identification of stabilizer, orbit and action kernel as concepts; it does not negate equal stabilizers or rule out special set equalities. The exact result, retaining the requested order, is (1, [0], 2, [0], Yes, No, stabilizer_not_orbit_or_action_kernel).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-point-boundary · candidate
78. Point Stabilizers May Agree without Becoming Orbits or Kernels
Use complete group table=[[0, 1, 2, 3], [1, 2, 3, 0], [2, 3, 0, 1], [3, 0, 1, 2]], identity=0, point carrier Fin(4)={0,…,3} and total action_table=[[0, 1, 2, 3], [1, 2, 3, 0], [2, 3, 0, 1], [3, 0, 1, 2]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=2. Compare other_point=3. Give (point, stabilizer, other_point, other_stabilizer, same_stabilizer, orbit_or_kernel_identification_claim, boundary).
The fixed No withholds identification of stabilizer, orbit and action kernel as concepts. It does not negate same_stabilizer or rule out equality of particular sets.
View answer and explanation
(2, [0], 3, [0], Yes, No, stabilizer_not_orbit_or_action_kernel)
Compute both complete stabilizers and their equality flag. The final fixed No withholds identification of stabilizer, orbit and action kernel as concepts; it does not negate equal stabilizers or rule out special set equalities. The exact result, retaining the requested order, is (2, [0], 3, [0], Yes, No, stabilizer_not_orbit_or_action_kernel).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-point-boundary · candidate
79. Point Stabilizers May Agree without Becoming Orbits or Kernels
Use complete group table=[[0, 1, 2, 3, 4], [1, 2, 3, 4, 0], [2, 3, 4, 0, 1], [3, 4, 0, 1, 2], [4, 0, 1, 2, 3]], identity=0, point carrier Fin(5)={0,…,4} and total action_table=[[0, 1, 2, 3, 4], [1, 2, 3, 4, 0], [2, 3, 4, 0, 1], [3, 4, 0, 1, 2], [4, 0, 1, 2, 3]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=3. Compare other_point=4. Give (point, stabilizer, other_point, other_stabilizer, same_stabilizer, orbit_or_kernel_identification_claim, boundary).
The fixed No withholds identification of stabilizer, orbit and action kernel as concepts. It does not negate same_stabilizer or rule out equality of particular sets.
View answer and explanation
(3, [0], 4, [0], Yes, No, stabilizer_not_orbit_or_action_kernel)
Compute both complete stabilizers and their equality flag. The final fixed No withholds identification of stabilizer, orbit and action kernel as concepts; it does not negate equal stabilizers or rule out special set equalities. The exact result, retaining the requested order, is (3, [0], 4, [0], Yes, No, stabilizer_not_orbit_or_action_kernel).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-point-boundary · candidate
80. Point Stabilizers May Agree without Becoming Orbits or Kernels
Use complete group table=[[0, 1, 2, 3, 4, 5], [1, 2, 3, 4, 5, 0], [2, 3, 4, 5, 0, 1], [3, 4, 5, 0, 1, 2], [4, 5, 0, 1, 2, 3], [5, 0, 1, 2, 3, 4]], identity=0, point carrier Fin(6)={0,…,5} and total action_table=[[0, 1, 2, 3, 4, 5], [1, 2, 3, 4, 5, 0], [2, 3, 4, 5, 0, 1], [3, 4, 5, 0, 1, 2], [4, 5, 0, 1, 2, 3], [5, 0, 1, 2, 3, 4]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=4. Compare other_point=5. Give (point, stabilizer, other_point, other_stabilizer, same_stabilizer, orbit_or_kernel_identification_claim, boundary).
The fixed No withholds identification of stabilizer, orbit and action kernel as concepts. It does not negate same_stabilizer or rule out equality of particular sets.
View answer and explanation
(4, [0], 5, [0], Yes, No, stabilizer_not_orbit_or_action_kernel)
Compute both complete stabilizers and their equality flag. The final fixed No withholds identification of stabilizer, orbit and action kernel as concepts; it does not negate equal stabilizers or rule out special set equalities. The exact result, retaining the requested order, is (4, [0], 5, [0], Yes, No, stabilizer_not_orbit_or_action_kernel).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-point-boundary · candidate
81. Point Stabilizers May Agree without Becoming Orbits or Kernels
Use complete group table=[[0, 1], [1, 0]], identity=0, point carrier Fin(3)={0,…,2} and total action_table=[[0, 1, 2], [1, 0, 2]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=2. Compare other_point=0. Give (point, stabilizer, other_point, other_stabilizer, same_stabilizer, orbit_or_kernel_identification_claim, boundary).
The fixed No withholds identification of stabilizer, orbit and action kernel as concepts. It does not negate same_stabilizer or rule out equality of particular sets.
View answer and explanation
(2, [0, 1], 0, [0], No, No, stabilizer_not_orbit_or_action_kernel)
Compute both complete stabilizers and their equality flag. The final fixed No withholds identification of stabilizer, orbit and action kernel as concepts; it does not negate equal stabilizers or rule out special set equalities. The exact result, retaining the requested order, is (2, [0, 1], 0, [0], No, No, stabilizer_not_orbit_or_action_kernel).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-point-boundary · candidate
82. Point Stabilizers May Agree without Becoming Orbits or Kernels
Use complete group table=[[0, 1, 2], [1, 2, 0], [2, 0, 1]], identity=0, point carrier Fin(4)={0,…,3} and total action_table=[[0, 1, 2, 3], [1, 2, 0, 3], [2, 0, 1, 3]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=2. Compare other_point=3. Give (point, stabilizer, other_point, other_stabilizer, same_stabilizer, orbit_or_kernel_identification_claim, boundary).
The fixed No withholds identification of stabilizer, orbit and action kernel as concepts. It does not negate same_stabilizer or rule out equality of particular sets.
View answer and explanation
(2, [0], 3, [0, 1, 2], No, No, stabilizer_not_orbit_or_action_kernel)
Compute both complete stabilizers and their equality flag. The final fixed No withholds identification of stabilizer, orbit and action kernel as concepts; it does not negate equal stabilizers or rule out special set equalities. The exact result, retaining the requested order, is (2, [0], 3, [0, 1, 2], No, No, stabilizer_not_orbit_or_action_kernel).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-point-boundary · candidate
83. Point Stabilizers May Agree without Becoming Orbits or Kernels
Use complete group table=[[0, 1, 2, 3], [1, 2, 3, 0], [2, 3, 0, 1], [3, 0, 1, 2]], identity=0, point carrier Fin(5)={0,…,4} and total action_table=[[0, 1, 2, 3, 4], [1, 2, 3, 0, 4], [2, 3, 0, 1, 4], [3, 0, 1, 2, 4]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=2. Compare other_point=3. Give (point, stabilizer, other_point, other_stabilizer, same_stabilizer, orbit_or_kernel_identification_claim, boundary).
The fixed No withholds identification of stabilizer, orbit and action kernel as concepts. It does not negate same_stabilizer or rule out equality of particular sets.
View answer and explanation
(2, [0], 3, [0], Yes, No, stabilizer_not_orbit_or_action_kernel)
Compute both complete stabilizers and their equality flag. The final fixed No withholds identification of stabilizer, orbit and action kernel as concepts; it does not negate equal stabilizers or rule out special set equalities. The exact result, retaining the requested order, is (2, [0], 3, [0], Yes, No, stabilizer_not_orbit_or_action_kernel).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-point-boundary · candidate
84. Point Stabilizers May Agree without Becoming Orbits or Kernels
Use complete group table=[[0, 1, 2, 3, 4], [1, 2, 3, 4, 0], [2, 3, 4, 0, 1], [3, 4, 0, 1, 2], [4, 0, 1, 2, 3]], identity=0, point carrier Fin(6)={0,…,5} and total action_table=[[0, 1, 2, 3, 4, 5], [1, 2, 3, 4, 0, 5], [2, 3, 4, 0, 1, 5], [3, 4, 0, 1, 2, 5], [4, 0, 1, 2, 3, 5]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=2. Compare other_point=3. Give (point, stabilizer, other_point, other_stabilizer, same_stabilizer, orbit_or_kernel_identification_claim, boundary).
The fixed No withholds identification of stabilizer, orbit and action kernel as concepts. It does not negate same_stabilizer or rule out equality of particular sets.
View answer and explanation
(2, [0], 3, [0], Yes, No, stabilizer_not_orbit_or_action_kernel)
Compute both complete stabilizers and their equality flag. The final fixed No withholds identification of stabilizer, orbit and action kernel as concepts; it does not negate equal stabilizers or rule out special set equalities. The exact result, retaining the requested order, is (2, [0], 3, [0], Yes, No, stabilizer_not_orbit_or_action_kernel).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-point-boundary · candidate
85. Point Stabilizers May Agree without Becoming Orbits or Kernels
Use complete group table=[[0, 1, 2, 3, 4, 5], [1, 2, 3, 4, 5, 0], [2, 3, 4, 5, 0, 1], [3, 4, 5, 0, 1, 2], [4, 5, 0, 1, 2, 3], [5, 0, 1, 2, 3, 4]], identity=0, point carrier Fin(7)={0,…,6} and total action_table=[[0, 1, 2, 3, 4, 5, 6], [1, 2, 3, 4, 5, 0, 6], [2, 3, 4, 5, 0, 1, 6], [3, 4, 5, 0, 1, 2, 6], [4, 5, 0, 1, 2, 3, 6], [5, 0, 1, 2, 3, 4, 6]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=2. Compare other_point=3. Give (point, stabilizer, other_point, other_stabilizer, same_stabilizer, orbit_or_kernel_identification_claim, boundary).
The fixed No withholds identification of stabilizer, orbit and action kernel as concepts. It does not negate same_stabilizer or rule out equality of particular sets.
View answer and explanation
(2, [0], 3, [0], Yes, No, stabilizer_not_orbit_or_action_kernel)
Compute both complete stabilizers and their equality flag. The final fixed No withholds identification of stabilizer, orbit and action kernel as concepts; it does not negate equal stabilizers or rule out special set equalities. The exact result, retaining the requested order, is (2, [0], 3, [0], Yes, No, stabilizer_not_orbit_or_action_kernel).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-point-boundary · candidate
86. Point Stabilizers May Agree without Becoming Orbits or Kernels
Use complete group table=[[0, 1], [1, 0]], identity=0, point carrier Fin(4)={0,…,3} and total action_table=[[0, 1, 2, 3], [1, 0, 2, 3]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=2. Compare other_point=3. Give (point, stabilizer, other_point, other_stabilizer, same_stabilizer, orbit_or_kernel_identification_claim, boundary).
The fixed No withholds identification of stabilizer, orbit and action kernel as concepts. It does not negate same_stabilizer or rule out equality of particular sets.
View answer and explanation
(2, [0, 1], 3, [0, 1], Yes, No, stabilizer_not_orbit_or_action_kernel)
Compute both complete stabilizers and their equality flag. The final fixed No withholds identification of stabilizer, orbit and action kernel as concepts; it does not negate equal stabilizers or rule out special set equalities. The exact result, retaining the requested order, is (2, [0, 1], 3, [0, 1], Yes, No, stabilizer_not_orbit_or_action_kernel).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-point-boundary · candidate
87. Point Stabilizers May Agree without Becoming Orbits or Kernels
Use complete group table=[[0, 1, 2], [1, 2, 0], [2, 0, 1]], identity=0, point carrier Fin(5)={0,…,4} and total action_table=[[0, 1, 2, 3, 4], [1, 2, 0, 3, 4], [2, 0, 1, 3, 4]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=1. Compare other_point=2. Give (point, stabilizer, other_point, other_stabilizer, same_stabilizer, orbit_or_kernel_identification_claim, boundary).
The fixed No withholds identification of stabilizer, orbit and action kernel as concepts. It does not negate same_stabilizer or rule out equality of particular sets.
View answer and explanation
(1, [0], 2, [0], Yes, No, stabilizer_not_orbit_or_action_kernel)
Compute both complete stabilizers and their equality flag. The final fixed No withholds identification of stabilizer, orbit and action kernel as concepts; it does not negate equal stabilizers or rule out special set equalities. The exact result, retaining the requested order, is (1, [0], 2, [0], Yes, No, stabilizer_not_orbit_or_action_kernel).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-point-boundary · candidate
88. Point Stabilizers May Agree without Becoming Orbits or Kernels
Use complete group table=[[0, 1, 2, 3], [1, 2, 3, 0], [2, 3, 0, 1], [3, 0, 1, 2]], identity=0, point carrier Fin(6)={0,…,5} and total action_table=[[0, 1, 2, 3, 4, 5], [1, 2, 3, 0, 4, 5], [2, 3, 0, 1, 4, 5], [3, 0, 1, 2, 4, 5]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=0. Compare other_point=1. Give (point, stabilizer, other_point, other_stabilizer, same_stabilizer, orbit_or_kernel_identification_claim, boundary).
The fixed No withholds identification of stabilizer, orbit and action kernel as concepts. It does not negate same_stabilizer or rule out equality of particular sets.
View answer and explanation
(0, [0], 1, [0], Yes, No, stabilizer_not_orbit_or_action_kernel)
Compute both complete stabilizers and their equality flag. The final fixed No withholds identification of stabilizer, orbit and action kernel as concepts; it does not negate equal stabilizers or rule out special set equalities. The exact result, retaining the requested order, is (0, [0], 1, [0], Yes, No, stabilizer_not_orbit_or_action_kernel).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-point-boundary · candidate
89. Point Stabilizers May Agree without Becoming Orbits or Kernels
Use complete group table=[[0, 1, 2, 3, 4], [1, 2, 3, 4, 0], [2, 3, 4, 0, 1], [3, 4, 0, 1, 2], [4, 0, 1, 2, 3]], identity=0, point carrier Fin(7)={0,…,6} and total action_table=[[0, 1, 2, 3, 4, 5, 6], [1, 2, 3, 4, 0, 5, 6], [2, 3, 4, 0, 1, 5, 6], [3, 4, 0, 1, 2, 5, 6], [4, 0, 1, 2, 3, 5, 6]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=6. Compare other_point=0. Give (point, stabilizer, other_point, other_stabilizer, same_stabilizer, orbit_or_kernel_identification_claim, boundary).
The fixed No withholds identification of stabilizer, orbit and action kernel as concepts. It does not negate same_stabilizer or rule out equality of particular sets.
View answer and explanation
(6, [0, 1, 2, 3, 4], 0, [0], No, No, stabilizer_not_orbit_or_action_kernel)
Compute both complete stabilizers and their equality flag. The final fixed No withholds identification of stabilizer, orbit and action kernel as concepts; it does not negate equal stabilizers or rule out special set equalities. The exact result, retaining the requested order, is (6, [0, 1, 2, 3, 4], 0, [0], No, No, stabilizer_not_orbit_or_action_kernel).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-point-boundary · candidate
90. Point Stabilizers May Agree without Becoming Orbits or Kernels
Use complete group table=[[0, 1, 2, 3, 4, 5], [1, 2, 3, 4, 5, 0], [2, 3, 4, 5, 0, 1], [3, 4, 5, 0, 1, 2], [4, 5, 0, 1, 2, 3], [5, 0, 1, 2, 3, 4]], identity=0, point carrier Fin(8)={0,…,7} and total action_table=[[0, 1, 2, 3, 4, 5, 6, 7], [1, 2, 3, 4, 5, 0, 6, 7], [2, 3, 4, 5, 0, 1, 6, 7], [3, 4, 5, 0, 1, 2, 6, 7], [4, 5, 0, 1, 2, 3, 6, 7], [5, 0, 1, 2, 3, 4, 6, 7]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=6. Compare other_point=7. Give (point, stabilizer, other_point, other_stabilizer, same_stabilizer, orbit_or_kernel_identification_claim, boundary).
The fixed No withholds identification of stabilizer, orbit and action kernel as concepts. It does not negate same_stabilizer or rule out equality of particular sets.
View answer and explanation
(6, [0, 1, 2, 3, 4, 5], 7, [0, 1, 2, 3, 4, 5], Yes, No, stabilizer_not_orbit_or_action_kernel)
Compute both complete stabilizers and their equality flag. The final fixed No withholds identification of stabilizer, orbit and action kernel as concepts; it does not negate equal stabilizers or rule out special set equalities. The exact result, retaining the requested order, is (6, [0, 1, 2, 3, 4, 5], 7, [0, 1, 2, 3, 4, 5], Yes, No, stabilizer_not_orbit_or_action_kernel).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-point-boundary · candidate
91. Point Stabilizers May Agree without Becoming Orbits or Kernels
Use complete group table=[[0, 1], [1, 0]], identity=0, point carrier Fin(5)={0,…,4} and total action_table=[[0, 1, 2, 3, 4], [1, 0, 2, 3, 4]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=0. Compare other_point=1. Give (point, stabilizer, other_point, other_stabilizer, same_stabilizer, orbit_or_kernel_identification_claim, boundary).
The fixed No withholds identification of stabilizer, orbit and action kernel as concepts. It does not negate same_stabilizer or rule out equality of particular sets.
View answer and explanation
(0, [0], 1, [0], Yes, No, stabilizer_not_orbit_or_action_kernel)
Compute both complete stabilizers and their equality flag. The final fixed No withholds identification of stabilizer, orbit and action kernel as concepts; it does not negate equal stabilizers or rule out special set equalities. The exact result, retaining the requested order, is (0, [0], 1, [0], Yes, No, stabilizer_not_orbit_or_action_kernel).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-point-boundary · candidate
92. Point Stabilizers May Agree without Becoming Orbits or Kernels
Use complete group table=[[0, 1, 2], [1, 2, 0], [2, 0, 1]], identity=0, point carrier Fin(6)={0,…,5} and total action_table=[[0, 1, 2, 3, 4, 5], [1, 2, 0, 3, 4, 5], [2, 0, 1, 3, 4, 5]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=4. Compare other_point=5. Give (point, stabilizer, other_point, other_stabilizer, same_stabilizer, orbit_or_kernel_identification_claim, boundary).
The fixed No withholds identification of stabilizer, orbit and action kernel as concepts. It does not negate same_stabilizer or rule out equality of particular sets.
View answer and explanation
(4, [0, 1, 2], 5, [0, 1, 2], Yes, No, stabilizer_not_orbit_or_action_kernel)
Compute both complete stabilizers and their equality flag. The final fixed No withholds identification of stabilizer, orbit and action kernel as concepts; it does not negate equal stabilizers or rule out special set equalities. The exact result, retaining the requested order, is (4, [0, 1, 2], 5, [0, 1, 2], Yes, No, stabilizer_not_orbit_or_action_kernel).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-point-boundary · candidate
93. Point Stabilizers May Agree without Becoming Orbits or Kernels
Use complete group table=[[0, 1, 2, 3], [1, 2, 3, 0], [2, 3, 0, 1], [3, 0, 1, 2]], identity=0, point carrier Fin(7)={0,…,6} and total action_table=[[0, 1, 2, 3, 4, 5, 6], [1, 2, 3, 0, 4, 5, 6], [2, 3, 0, 1, 4, 5, 6], [3, 0, 1, 2, 4, 5, 6]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=3. Compare other_point=4. Give (point, stabilizer, other_point, other_stabilizer, same_stabilizer, orbit_or_kernel_identification_claim, boundary).
The fixed No withholds identification of stabilizer, orbit and action kernel as concepts. It does not negate same_stabilizer or rule out equality of particular sets.
View answer and explanation
(3, [0], 4, [0, 1, 2, 3], No, No, stabilizer_not_orbit_or_action_kernel)
Compute both complete stabilizers and their equality flag. The final fixed No withholds identification of stabilizer, orbit and action kernel as concepts; it does not negate equal stabilizers or rule out special set equalities. The exact result, retaining the requested order, is (3, [0], 4, [0, 1, 2, 3], No, No, stabilizer_not_orbit_or_action_kernel).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-point-boundary · candidate
94. Point Stabilizers May Agree without Becoming Orbits or Kernels
Use complete group table=[[0, 1, 2, 3, 4], [1, 2, 3, 4, 0], [2, 3, 4, 0, 1], [3, 4, 0, 1, 2], [4, 0, 1, 2, 3]], identity=0, point carrier Fin(8)={0,…,7} and total action_table=[[0, 1, 2, 3, 4, 5, 6, 7], [1, 2, 3, 4, 0, 5, 6, 7], [2, 3, 4, 0, 1, 5, 6, 7], [3, 4, 0, 1, 2, 5, 6, 7], [4, 0, 1, 2, 3, 5, 6, 7]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=2. Compare other_point=3. Give (point, stabilizer, other_point, other_stabilizer, same_stabilizer, orbit_or_kernel_identification_claim, boundary).
The fixed No withholds identification of stabilizer, orbit and action kernel as concepts. It does not negate same_stabilizer or rule out equality of particular sets.
View answer and explanation
(2, [0], 3, [0], Yes, No, stabilizer_not_orbit_or_action_kernel)
Compute both complete stabilizers and their equality flag. The final fixed No withholds identification of stabilizer, orbit and action kernel as concepts; it does not negate equal stabilizers or rule out special set equalities. The exact result, retaining the requested order, is (2, [0], 3, [0], Yes, No, stabilizer_not_orbit_or_action_kernel).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-point-boundary · candidate
95. Point Stabilizers May Agree without Becoming Orbits or Kernels
Use complete group table=[[0, 1, 2, 3, 4, 5], [1, 2, 3, 4, 5, 0], [2, 3, 4, 5, 0, 1], [3, 4, 5, 0, 1, 2], [4, 5, 0, 1, 2, 3], [5, 0, 1, 2, 3, 4]], identity=0, point carrier Fin(9)={0,…,8} and total action_table=[[0, 1, 2, 3, 4, 5, 6, 7, 8], [1, 2, 3, 4, 5, 0, 6, 7, 8], [2, 3, 4, 5, 0, 1, 6, 7, 8], [3, 4, 5, 0, 1, 2, 6, 7, 8], [4, 5, 0, 1, 2, 3, 6, 7, 8], [5, 0, 1, 2, 3, 4, 6, 7, 8]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=1. Compare other_point=2. Give (point, stabilizer, other_point, other_stabilizer, same_stabilizer, orbit_or_kernel_identification_claim, boundary).
The fixed No withholds identification of stabilizer, orbit and action kernel as concepts. It does not negate same_stabilizer or rule out equality of particular sets.
View answer and explanation
(1, [0], 2, [0], Yes, No, stabilizer_not_orbit_or_action_kernel)
Compute both complete stabilizers and their equality flag. The final fixed No withholds identification of stabilizer, orbit and action kernel as concepts; it does not negate equal stabilizers or rule out special set equalities. The exact result, retaining the requested order, is (1, [0], 2, [0], Yes, No, stabilizer_not_orbit_or_action_kernel).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-point-boundary · candidate
96. Point Stabilizers May Agree without Becoming Orbits or Kernels
Use complete group table=[[0, 1], [1, 0]], identity=0, point carrier Fin(6)={0,…,5} and total action_table=[[0, 1, 2, 3, 4, 5], [1, 0, 2, 3, 4, 5]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=2. Compare other_point=3. Give (point, stabilizer, other_point, other_stabilizer, same_stabilizer, orbit_or_kernel_identification_claim, boundary).
The fixed No withholds identification of stabilizer, orbit and action kernel as concepts. It does not negate same_stabilizer or rule out equality of particular sets.
View answer and explanation
(2, [0, 1], 3, [0, 1], Yes, No, stabilizer_not_orbit_or_action_kernel)
Compute both complete stabilizers and their equality flag. The final fixed No withholds identification of stabilizer, orbit and action kernel as concepts; it does not negate equal stabilizers or rule out special set equalities. The exact result, retaining the requested order, is (2, [0, 1], 3, [0, 1], Yes, No, stabilizer_not_orbit_or_action_kernel).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-point-boundary · candidate
97. Point Stabilizers May Agree without Becoming Orbits or Kernels
Use complete group table=[[0, 1, 2], [1, 2, 0], [2, 0, 1]], identity=0, point carrier Fin(7)={0,…,6} and total action_table=[[0, 1, 2, 3, 4, 5, 6], [1, 2, 0, 3, 4, 5, 6], [2, 0, 1, 3, 4, 5, 6]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=0. Compare other_point=1. Give (point, stabilizer, other_point, other_stabilizer, same_stabilizer, orbit_or_kernel_identification_claim, boundary).
The fixed No withholds identification of stabilizer, orbit and action kernel as concepts. It does not negate same_stabilizer or rule out equality of particular sets.
View answer and explanation
(0, [0], 1, [0], Yes, No, stabilizer_not_orbit_or_action_kernel)
Compute both complete stabilizers and their equality flag. The final fixed No withholds identification of stabilizer, orbit and action kernel as concepts; it does not negate equal stabilizers or rule out special set equalities. The exact result, retaining the requested order, is (0, [0], 1, [0], Yes, No, stabilizer_not_orbit_or_action_kernel).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-point-boundary · candidate
98. Point Stabilizers May Agree without Becoming Orbits or Kernels
Use complete group table=[[0, 1, 2, 3], [1, 2, 3, 0], [2, 3, 0, 1], [3, 0, 1, 2]], identity=0, point carrier Fin(8)={0,…,7} and total action_table=[[0, 1, 2, 3, 4, 5, 6, 7], [1, 2, 3, 0, 4, 5, 6, 7], [2, 3, 0, 1, 4, 5, 6, 7], [3, 0, 1, 2, 4, 5, 6, 7]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=6. Compare other_point=7. Give (point, stabilizer, other_point, other_stabilizer, same_stabilizer, orbit_or_kernel_identification_claim, boundary).
The fixed No withholds identification of stabilizer, orbit and action kernel as concepts. It does not negate same_stabilizer or rule out equality of particular sets.
View answer and explanation
(6, [0, 1, 2, 3], 7, [0, 1, 2, 3], Yes, No, stabilizer_not_orbit_or_action_kernel)
Compute both complete stabilizers and their equality flag. The final fixed No withholds identification of stabilizer, orbit and action kernel as concepts; it does not negate equal stabilizers or rule out special set equalities. The exact result, retaining the requested order, is (6, [0, 1, 2, 3], 7, [0, 1, 2, 3], Yes, No, stabilizer_not_orbit_or_action_kernel).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-point-boundary · candidate
99. Point Stabilizers May Agree without Becoming Orbits or Kernels
Use complete group table=[[0, 1, 2, 3, 4], [1, 2, 3, 4, 0], [2, 3, 4, 0, 1], [3, 4, 0, 1, 2], [4, 0, 1, 2, 3]], identity=0, point carrier Fin(9)={0,…,8} and total action_table=[[0, 1, 2, 3, 4, 5, 6, 7, 8], [1, 2, 3, 4, 0, 5, 6, 7, 8], [2, 3, 4, 0, 1, 5, 6, 7, 8], [3, 4, 0, 1, 2, 5, 6, 7, 8], [4, 0, 1, 2, 3, 5, 6, 7, 8]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=5. Compare other_point=6. Give (point, stabilizer, other_point, other_stabilizer, same_stabilizer, orbit_or_kernel_identification_claim, boundary).
The fixed No withholds identification of stabilizer, orbit and action kernel as concepts. It does not negate same_stabilizer or rule out equality of particular sets.
View answer and explanation
(5, [0, 1, 2, 3, 4], 6, [0, 1, 2, 3, 4], Yes, No, stabilizer_not_orbit_or_action_kernel)
Compute both complete stabilizers and their equality flag. The final fixed No withholds identification of stabilizer, orbit and action kernel as concepts; it does not negate equal stabilizers or rule out special set equalities. The exact result, retaining the requested order, is (5, [0, 1, 2, 3, 4], 6, [0, 1, 2, 3, 4], Yes, No, stabilizer_not_orbit_or_action_kernel).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-point-boundary · candidate
100. Point Stabilizers May Agree without Becoming Orbits or Kernels
Use complete group table=[[0, 1, 2, 3, 4, 5], [1, 2, 3, 4, 5, 0], [2, 3, 4, 5, 0, 1], [3, 4, 5, 0, 1, 2], [4, 5, 0, 1, 2, 3], [5, 0, 1, 2, 3, 4]], identity=0, point carrier Fin(10)={0,…,9} and total action_table=[[0, 1, 2, 3, 4, 5, 6, 7, 8, 9], [1, 2, 3, 4, 5, 0, 6, 7, 8, 9], [2, 3, 4, 5, 0, 1, 6, 7, 8, 9], [3, 4, 5, 0, 1, 2, 6, 7, 8, 9], [4, 5, 0, 1, 2, 3, 6, 7, 8, 9], [5, 0, 1, 2, 3, 4, 6, 7, 8, 9]]. Group row g/column h gives g*h; action row g/column x gives g*x. Every group and action axiom must qualify before the stabilizer is computed. Specified point=4. Compare other_point=5. Give (point, stabilizer, other_point, other_stabilizer, same_stabilizer, orbit_or_kernel_identification_claim, boundary).
The fixed No withholds identification of stabilizer, orbit and action kernel as concepts. It does not negate same_stabilizer or rule out equality of particular sets.
View answer and explanation
(4, [0], 5, [0], Yes, No, stabilizer_not_orbit_or_action_kernel)
Compute both complete stabilizers and their equality flag. The final fixed No withholds identification of stabilizer, orbit and action kernel as concepts; it does not negate equal stabilizers or rule out special set equalities. The exact result, retaining the requested order, is (4, [0], 5, [0], Yes, No, stabilizer_not_orbit_or_action_kernel).
Reviewed step-by-step derivation
Stabilizer of a finite group action · qf-mod40-stabilizer-point-boundary · candidate
Canonical question JSONL · English JSONL · Validation report