In a fixed Cartesian coordinate system, D={-4, -3, -2} and f:D→R is given by f(x)=(1)x+(-1). Does (-2, -3) belong to the declared graph?
G001 — In a fixed Cartesian coordinate system, D={-4, -3, -2} and f:D→R is given by f(x)=(1)x+(-1). Does (-2, -3) belong to the declared graph?
Definition and scope
Use the original question domain, assumptions and cited MKO definitions. This item has second-context mathematical and bilingual review, with the model, answer and every arithmetic step independently recomputed from the original parameters; the source question remains a candidate.
The domain is the declared finite integer subset,not automatically all R.The input list must already be distinct.The first coordinate is input,the second output.
candidate point=(-2, -3);x in domain=Yes;ambient formula value=-3
After
output equality=Yes;graph member=Yes
Conditions: none
The algebraic expression can have a numerical value outside D,but that is not a value of the restricted function there.Both domain membership and y=f(x) must hold.
S004 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
S003 · premise_and_result_audit — Recompute queried expression m*x+b with exact rational arithmetic, not rounded decimals.
S002 · premise_and_result_audit — Recompute queried expression m*x with exact rational arithmetic, not rounded decimals.
S001 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
Result
Yes
The full substitutions and premise checks give the original answer; source identity,format and status are unchanged.
This question review and source binding
Review date: 2026-10-26
Original questions, answers, step expressions, numeric ASTs and historical records are retained. Source candidate labels remain historical and are not overwritten as formal proof.