The explicit finite cardinalities are |A|=7 and |B|=8, with no particular function table supplied. Does some bijection A→B exist?
G001 — The explicit finite cardinalities are |A|=7 and |B|=8, with no particular function table supplied. Does some bijection A→B exist?
Definition and scope
Use the original question domain, assumptions and cited MKO definitions. This item has second-context mathematical and bilingual review, with the model, answer and every arithmetic step independently recomputed from the original parameters; the source question remains a candidate.
A bijection between finite sets exists exactly when their cardinalities agree.A bijection pairs each A-element with a distinct B-element and misses no B-element,so the counts agree.
For equal sizes,enumerate both finite sets and pair equal indices to construct a bijection.For unequal sizes a complete one-to-one pairing is impossible.The unique empty function from0 to0 is a bijection.
S003 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
S002 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
S001 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
Result
No
The full substitutions and premise checks give the original answer; source identity,format and status are unchanged.
This question review and source binding
Review date: 2026-10-26
Original questions, answers, step expressions, numeric ASTs and historical records are retained. Source candidate labels remain historical and are not overwritten as formal proof.