On the full real domain, let q:R→R be q(x)=(-2)(x−(10))²+(5), with a≠0. Give the global minimum or global maximum value, according to the coefficient sign. Do not substitute a restricted interval.
G001 — On the full real domain, let q:R→R be q(x)=(-2)(x−(10))²+(5), with a≠0. Give the global minimum or global maximum value, according to the coefficient sign. Do not substitute a restricted interval.
Definition and scope
Use the original question domain, assumptions and cited MKO definitions. This item has second-context mathematical and bilingual review, with the model, answer and every arithmetic step independently recomputed from the original parameters; the source question remains a candidate.
Separate source banks:legacy RAW SAFE with unbounded derived BigInts versus BASE Number.isInteger without invented SAFE/million caps.Operations,domains and permissive/exact keys follow THIS bank.Keep ORIGINAL JSON intact.
FIRST qualify nonzero a and the FULL real domain.The ORIGINAL function is vertex form,not a*x²+h*x+k.Keep h/k roles unchanged and do not silently replace the domain by a bounded interval.
Calculate exactly from ORIGINAL ordered operands;mul/sub/div have EXPLICITLY TWO operands.Legacy derived BigInts are not recapped at RAW SAFE;check BASE Number type/representation conditions separately.Do not use floating approximations to force an answer.
Quadratic ORIGINAL displacement squared := mul(0, 0)
After
Quadratic ORIGINAL displacement squared = 0
Conditions: none
Calculate exactly from ORIGINAL ordered operands;mul/sub/div have EXPLICITLY TWO operands.Legacy derived BigInts are not recapped at RAW SAFE;check BASE Number type/representation conditions separately.Do not use floating approximations to force an answer.
Quadratic ORIGINAL a times displacement squared := mul(-2, 0)
After
Quadratic ORIGINAL a times displacement squared = 0
Conditions: none
Calculate exactly from ORIGINAL ordered operands;mul/sub/div have EXPLICITLY TWO operands.Legacy derived BigInts are not recapped at RAW SAFE;check BASE Number type/representation conditions separately.Do not use floating approximations to force an answer.
Quadratic ORIGINAL weighted square plus k := sum(0, 5)
After
Quadratic ORIGINAL weighted square plus k = 5
Conditions: none
Calculate exactly from ORIGINAL ordered operands;mul/sub/div have EXPLICITLY TWO operands.Legacy derived BigInts are not recapped at RAW SAFE;check BASE Number type/representation conditions separately.Do not use floating approximations to force an answer.
derived = [(x-h)^2>=0 for ALL real x, q(x)<=k, q(h)=k, global maximum=5]
Conditions: none
For EVERY real x,the square is nonnegative.Positive a preserves≥;negative a reverses it to≤.Adding k gives the GLOBAL bound,and x=h ATTAINS k.The other direction is unbounded as|x-h|→infinity;do not invent finite extrema in both directions.
S007 · premise_and_result_audit — Reverse-check THIS question’s ORIGINAL givens,domain and step premises.Preserve originals/English/MKOs/ASTs/status;do not reverse a one-way implication or call finite checks independent review or general formal proof.
S006 · premise_and_result_audit — Recompute Quadratic ORIGINAL weighted square plus k with exact rational arithmetic, not rounded decimals.
S005 · premise_and_result_audit — Recompute Quadratic ORIGINAL a times displacement squared with exact rational arithmetic, not rounded decimals.
S004 · premise_and_result_audit — Recompute Quadratic ORIGINAL displacement squared with exact rational arithmetic, not rounded decimals.
S003 · premise_and_result_audit — Recompute Quadratic ORIGINAL x minus h with exact rational arithmetic, not rounded decimals.
S002 · premise_and_result_audit — Reverse-check THIS question’s ORIGINAL givens,domain and step premises.Preserve originals/English/MKOs/ASTs/status;do not reverse a one-way implication or call finite checks independent review or general formal proof.
S001 · premise_and_result_audit — Reverse-check THIS question’s ORIGINAL givens,domain and step premises.Preserve originals/English/MKOs/ASTs/status;do not reverse a one-way implication or call finite checks independent review or general formal proof.
Result
global maximum=5
The full substitutions and premise checks give the original answer; source identity,format and status are unchanged.
This question review and source binding
Review date: 2026-10-26
Original questions, answers, step expressions, numeric ASTs and historical records are retained. Source candidate labels remain historical and are not overwritten as formal proof.