# Question 28476: Graph Point Reflected across the Axis

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This teaching derivation has second-context AI mathematical and bilingual semantic review, limited to the model and assumptions stated in this question. It has no human review or new Lean proof and does not promote the original question or MKO to Canonical truth.

R0055-28476 · q-20261005-advance-20261006-r02-quadratic-function-0076



## Original question and givens

On the full real domain, let q:R→R be q(x)=(1)(x−(0))²+(0), with a≠0. Reflect the graph point (0,q(0)) across x=0. Give the reflected (input,output) pair.


- G001 — On the full real domain, let q:R→R be q(x)=(1)(x−(0))²+(0), with a≠0. Reflect the graph point (0,q(0)) across x=0. Give the reflected (input,output) pair.





## Definition and scope

Use the original question domain, assumptions and cited MKO definitions. This item has second-context mathematical and bilingual review, with the model, answer and every arithmetic step independently recomputed from the original parameters; the source question remains a candidate.


- [mko-quadratic-function](https://ocme.evemisslab.com/en/mko/mko-quadratic-function/)





## Step-by-step derivation

S001 · impliesBefore

source roles = [qf-quadratic-function-axis-mirror, quadratic_mirror]

After

derived = [[reflected_input_unchanged_output_graph_POINT]]

Conditions: none

List this scalar/label/set/point answer role or mode-specific ordered fields,not an imposed universal tuple.Retain legacy domain/underscore operation and integer fractions with/1;original bilingual snapshots stay unchanged.

Step identifiers and dependenciesRule: source_answer_roles_or_ordered_fields_without_JS · Uses: G001





S002 · calculationBefore

Legacy mirror ORIGINAL x minus h := sub(0, 0)

After

Legacy mirror ORIGINAL x minus h = 0

Conditions: none

Substitute original roles exactly,without floating approximation or changed operands;extra teaching identities add no source-domain restrictions.

Step identifiers and dependenciesRule: exact_rational_arithmetic · Uses: G001, S001





S003 · calculationBefore

Legacy mirror ORIGINAL squared displacement := mul(0, 0)

After

Legacy mirror ORIGINAL squared displacement = 0

Conditions: none

Substitute original roles exactly,without floating approximation or changed operands;extra teaching identities add no source-domain restrictions.

Step identifiers and dependenciesRule: exact_rational_arithmetic · Uses: G001, S002





S004 · calculationBefore

Legacy mirror ORIGINAL a times displacement square := mul(1, 0)

After

Legacy mirror ORIGINAL a times displacement square = 0

Conditions: none

Substitute original roles exactly,without floating approximation or changed operands;extra teaching identities add no source-domain restrictions.

Step identifiers and dependenciesRule: exact_rational_arithmetic · Uses: G001, S003





S005 · calculationBefore

Legacy mirror ORIGINAL graph output plus k := sum(0, 0)

After

Legacy mirror ORIGINAL graph output plus k = 0

Conditions: none

Substitute original roles exactly,without floating approximation or changed operands;extra teaching identities add no source-domain restrictions.

Step identifiers and dependenciesRule: exact_rational_arithmetic · Uses: G001, S004





S006 · calculationBefore

Legacy mirror ORIGINAL twice h := mul(2, 0)

After

Legacy mirror ORIGINAL twice h = 0

Conditions: none

Substitute original roles exactly,without floating approximation or changed operands;extra teaching identities add no source-domain restrictions.

Step identifiers and dependenciesRule: exact_rational_arithmetic · Uses: G001, S005





S007 · calculationBefore

Legacy mirror ORIGINAL reflected input := sub(0, 0)

After

Legacy mirror ORIGINAL reflected input = 0

Conditions: none

Substitute original roles exactly,without floating approximation or changed operands;extra teaching identities add no source-domain restrictions.

Step identifiers and dependenciesRule: exact_rational_arithmetic · Uses: G001, S006





S008 · calculationBefore

Legacy mirror reflected displacement := sub(0, 0)

After

Legacy mirror reflected displacement = 0

Conditions: none

Substitute original roles exactly,without floating approximation or changed operands;extra teaching identities add no source-domain restrictions.

Step identifiers and dependenciesRule: exact_rational_arithmetic · Uses: G001, S007





S009 · impliesBefore

source roles = [1, 0, 0, 0, 0]

After

derived = [0, 0, 0, 2h-(2h-x)=x]

Conditions: none

x_prime=2h-x gives x_prime-h=-(x-h),so the square and q value are unchanged.Return the FULL graph point,not the axis or vertex.A point at x=h reflects to itself;derived coordinates/values are not SAFE-clipped.

Step identifiers and dependenciesRule: Legacy_mirror_FULLreal_vertex_quadratic_involution_unchanged_output · Uses: G001, S008









## Reverse checks


- S009 · premise_and_result_audit — Reverse-check complete original data,operands and premises;finite checks,conditional reasoning,formal proof and publication authority remain distinct.
- S008 · premise_and_result_audit — Recompute Legacy mirror reflected displacement with exact rational arithmetic, not rounded decimals.
- S007 · premise_and_result_audit — Recompute Legacy mirror ORIGINAL reflected input with exact rational arithmetic, not rounded decimals.
- S006 · premise_and_result_audit — Recompute Legacy mirror ORIGINAL twice h with exact rational arithmetic, not rounded decimals.
- S005 · premise_and_result_audit — Recompute Legacy mirror ORIGINAL graph output plus k with exact rational arithmetic, not rounded decimals.
- S004 · premise_and_result_audit — Recompute Legacy mirror ORIGINAL a times displacement square with exact rational arithmetic, not rounded decimals.
- S003 · premise_and_result_audit — Recompute Legacy mirror ORIGINAL squared displacement with exact rational arithmetic, not rounded decimals.
- S002 · premise_and_result_audit — Recompute Legacy mirror ORIGINAL x minus h with exact rational arithmetic, not rounded decimals.
- S001 · premise_and_result_audit — Reverse-check complete original data,operands and premises;finite checks,conditional reasoning,formal proof and publication authority remain distinct.





## Result

(0, 0)

The full substitutions and premise checks give the original answer; source identity,format and status are unchanged.





## This question review and source binding

Review date: 2026-10-26

Original questions, answers, step expressions, numeric ASTs and historical records are retained. Source candidate labels remain historical and are not overwritten as formal proof.

Source hashes and review receipts
- input commit: 0f7be61e2c22317a4075561dc822c87d881a50db
- original question SHA-256: 99b44b21080151dfeb5b99bb6167d00a0c6d9fff3afc8ee1ee1e20d666122489
- candidate record SHA-256: fe7e03dbb84db394e0a529877d5c6659e6e917f3cdcab8a47ab6df62a962c85a
- semantic review receipt SHA-256: 6af367dae24a584f3596525c4953bbc2115343efd68cc9083693eb5c1ef2e683
- question-first witness SHA-256: 611eb69f3716404b968296a8b0d7d8c61b5ca18129d406f1ff9c7c11e10ffb4e
- Lean: NOT_RUN · human review: NOT_PERFORMED

[Same-source full JSON](https://ocme.evemisslab.com/data/question-derivations/questions/q-20261005-advance-20261006-r02-quadratic-function-0076.json)




