Question 28813: Positive Length-Scale Eligibility

Original question and givens

Use one equal-unit orthonormal Euclidean Cartesian frame. With positive denominator q=1, is k=0/1 an eligible positive length scale for nondegenerate similarity?

• G001 — Use one equal-unit orthonormal Euclidean Cartesian frame. With positive denominator q=1, is k=0/1 an eligible positive length scale for nondegenerate similarity?

Definition and scope

Use the original question domain, assumptions and cited MKO definitions. This item has second-context mathematical and bilingual review, with the model, answer and every arithmetic step independently recomputed from the original parameters; the source question remains a candidate.

• mko-similarity

Step-by-step derivation

source roles = [qf-similarity-positive-ratio, positive_scale_ratio]

derived = [positive_length_scale_eligibility]

source roles = [0, 1, euclidean_orthonormal_equal_units]

derived = [No, No]

Reverse checks

• S002 · premise_and_result_audit — Reverse-check EACH original datum and premise,retaining indices,signs and strict/non-strict boundaries.A correct final answer cannot replace the derivation obligations.This is candidate teaching/exact checking,not formal proof or publication clearance.
• S001 · premise_and_result_audit — Reverse-check EACH original datum and premise,retaining indices,signs and strict/non-strict boundaries.A correct final answer cannot replace the derivation obligations.This is candidate teaching/exact checking,not formal proof or publication clearance.

Result

No

The full substitutions and premise checks give the original answer; source identity,format and status are unchanged.

This question review and source binding

Review date: 2026-10-26

Original questions, answers, step expressions, numeric ASTs and historical records are retained. Source candidate labels remain historical and are not overwritten as formal proof.