Explore related knowledge and questions →

Question 10102: Point Derivative of a Continuous Accumulating Integral

On this page
  1. Original question and givens
  2. Definition and scope
  3. Step-by-step derivation
  4. Reverse checks
  5. Result
  6. This question review and source binding

Return to catalogue page 51

← Question derivation index · Original question batch

R0019-10102 · q-20261007-advance-20261009-r01-fundamental-theorem-calculus-0002

Original question and givens

On all R, the polynomial f is continuous and f has ascending coefficients [3], constant term first. Let G(x)=∫_0^x f(t)dt with oriented endpoints. Find G′(-1). Use reduced positive-denominator fractions, retaining /1 for integers.

  • G001 — On all R, the polynomial f is continuous and f has ascending coefficients [3], constant term first. Let G(x)=∫_0^x f(t)dt with oriented endpoints. Find G′(-1). Use reduced positive-denominator fractions, retaining /1 for integers.

Definition and scope

Use the original question domain, assumptions and cited MKO definitions. This item has second-context mathematical and bilingual review, with the model, answer and every arithmetic step independently recomputed from the original parameters; the source question remains a candidate.

Step-by-step derivation

S001 · implies

Before

raw integrand f=[3];ascending powers on all R

After

normalized coefficients=[3/1];declared continuous real polynomial

Conditions: none

The declared integrand is a continuous real polynomial on all R,and endpoints are oriented.Use FTC only under these supplied sufficient hypotheses;finite checks are not a new general formal FTC proof.

Step identifiers and dependencies

Rule: declared_FTC_continuity_hypothesis · Uses: G001

S002 · calculation

Before

zero primitive coefficient1 := div(3, 1)

After

zero primitive coefficient1 = 3

Conditions: none

Compute exactly from this step's original operands in the specified order,retaining signs and denominator conditions.

Step identifiers and dependencies

Rule: exact_rational_arithmetic · Uses: G001, S001

S003 · implies

Before

integrand power=0;coefficient=3/1

After

primitive power=1;coefficient=3/1

Conditions: none

For c*x^k place c/(k+1) at x^(k+1),with positive denominator k+1.Differentiating recovers c*x^k.Any additive constant gives another primitive.

Step identifiers and dependencies

Rule: polynomial_primitive_coefficient_rule · Uses: G001, S002

S004 · implies

Before

original integrand coefficients=[3/1]

After

zero-constant primitive coefficients=[0/1, 3/1]

Conditions: none

This is one convenient representative,not a claim that the primitive is unique without its constant family.

Step identifiers and dependencies

Rule: zero_constant_polynomial_primitive · Uses: G001, S003

S005 · calculation

Before

constructed P0 derivative coefficient0 := mul(1, 3)

After

constructed P0 derivative coefficient0 = 3

Conditions: none

Compute exactly from this step's original operands in the specified order,retaining signs and denominator conditions.

Step identifiers and dependencies

Rule: exact_rational_arithmetic · Uses: G001, S004

S006 · implies

Before

constructed P0:source power=1;coefficient=3/1

After

derivative power=0;coefficient=3/1

Conditions: none

Multiply the coefficient by k and lower its power by1.The constant contributes nothing;retain every higher nonzero term.

Step identifiers and dependencies

Rule: polynomial_derivative_coefficient_rule · Uses: G001, S005

S007 · implies

Before

P0 derivative coefficients=[3/1];f=[3/1]

After

P0'=f on all R in this declared polynomial model

Conditions: none

The full coefficient identity establishes the primitive relation in the declared model.With the supplied continuity premise use the FTC endpoint difference,not a function guessed from sample points.

Step identifiers and dependencies

Rule: constructed_primitive_coefficient_identity · Uses: G001, S006

S008 · calculation

Before

P0 at anchor Horner multiply1 := mul(0, 0)

After

P0 at anchor Horner multiply1 = 0

Conditions: none

Compute exactly from this step's original operands in the specified order,retaining signs and denominator conditions.

Step identifiers and dependencies

Rule: exact_rational_arithmetic · Uses: G001, S007

S009 · calculation

Before

P0 at anchor Horner add1 := sum(0, 3)

After

P0 at anchor Horner add1 = 3

Conditions: none

Compute exactly from this step's original operands in the specified order,retaining signs and denominator conditions.

Step identifiers and dependencies

Rule: exact_rational_arithmetic · Uses: G001, S008

S010 · calculation

Before

P0 at anchor Horner multiply0 := mul(3, 0)

After

P0 at anchor Horner multiply0 = 0

Conditions: none

Compute exactly from this step's original operands in the specified order,retaining signs and denominator conditions.

Step identifiers and dependencies

Rule: exact_rational_arithmetic · Uses: G001, S009

S011 · calculation

Before

P0 at anchor Horner add0 := sum(0, 0)

After

P0 at anchor Horner add0 = 0

Conditions: none

Compute exactly from this step's original operands in the specified order,retaining signs and denominator conditions.

Step identifiers and dependencies

Rule: exact_rational_arithmetic · Uses: G001, S010

S012 · implies

Before

anchor a=0;P0(a)=0/1

After

G(t)=P0(t)-(0/1);G'(t)=f(t)

Conditions: none

The anchor contributes the t-independent constant P0(a),which vanishes under differentiation.Do not use G's zero anchor value as its derivative.

Step identifiers and dependencies

Rule: FTC_accumulation_anchor_constant · Uses: G001, S011

S013 · calculation

Before

f at derivative point Horner multiply0 := mul(0, -1)

After

f at derivative point Horner multiply0 = 0

Conditions: none

Compute exactly from this step's original operands in the specified order,retaining signs and denominator conditions.

Step identifiers and dependencies

Rule: exact_rational_arithmetic · Uses: G001, S012

S014 · calculation

Before

f at derivative point Horner add0 := sum(0, 3)

After

f at derivative point Horner add0 = 3

Conditions: none

Compute exactly from this step's original operands in the specified order,retaining signs and denominator conditions.

Step identifiers and dependencies

Rule: exact_rational_arithmetic · Uses: G001, S013

Reverse checks

  • S014 · premise_and_result_audit — Recompute f at derivative point Horner add0 with exact rational arithmetic, not rounded decimals.
  • S013 · premise_and_result_audit — Recompute f at derivative point Horner multiply0 with exact rational arithmetic, not rounded decimals.
  • S012 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
  • S011 · premise_and_result_audit — Recompute P0 at anchor Horner add0 with exact rational arithmetic, not rounded decimals.
  • S010 · premise_and_result_audit — Recompute P0 at anchor Horner multiply0 with exact rational arithmetic, not rounded decimals.
  • S009 · premise_and_result_audit — Recompute P0 at anchor Horner add1 with exact rational arithmetic, not rounded decimals.
  • S008 · premise_and_result_audit — Recompute P0 at anchor Horner multiply1 with exact rational arithmetic, not rounded decimals.
  • S007 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
  • S006 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
  • S005 · premise_and_result_audit — Recompute constructed P0 derivative coefficient0 with exact rational arithmetic, not rounded decimals.
  • S004 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
  • S003 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
  • S002 · premise_and_result_audit — Recompute zero primitive coefficient1 with exact rational arithmetic, not rounded decimals.
  • S001 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.

Result

3/1

The full substitutions and premise checks give the original answer; source identity,format and status are unchanged.

This question review and source binding

Review date: 2026-10-26

Original questions, answers, step expressions, numeric ASTs and historical records are retained. Source candidate labels remain historical and are not overwritten as formal proof.

Source hashes and review receipts
  • input commit: 0f7be61e2c22317a4075561dc822c87d881a50db
  • original question SHA-256: 1ab9776ee7ec830917fa2b19c33ebd59097253dbf5bee19ae14c34e35e2ce03d
  • candidate record SHA-256: 22d2f70ed7126ca0638e8eb182a86a09039c5732f7d6fdeb090a82ccef750090
  • semantic review receipt SHA-256: eeb35dc5daab92234bf72827627392b47f38ead4cfb574d4373bebc43c09fbf5
  • question-first witness SHA-256: 3cf8e0d3a00b0df1994db2bfde81f4a31b382e170bdda83ea3d0b68da64e8419
  • Lean: NOT_RUN · human review: NOT_PERFORMED
Same-source full JSON