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Question 10997: Product Closure of a Nonempty Subset in a Qualified Finite Group

On this page
  1. Original question and givens
  2. Definition and scope
  3. Step-by-step derivation
  4. Reverse checks
  5. Result
  6. This question review and source binding

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R0020-10997 · q-20261013-advance-20261023-r03-subgroup-homomorphism-0022

Original question and givens

Use complete qualified finite group Cayley tables with carrier labels 0 through size−1 and the given row/column order. Every group axiom is a premise already checked on the whole table. Results concern these finite groups; a homomorphism need not be injective or an isomorphism. size=6, table=[[2, 5, 3, 0, 1, 4], [5, 3, 4, 1, 2, 0], [3, 4, 0, 2, 5, 1], [0, 1, 2, 3, 4, 5], [1, 2, 5, 4, 0, 3], [4, 0, 1, 5, 3, 2]], nonempty candidate subset=[0, 2, 3] normalized to sorted distinct labels. Give (size,subset,all products stay in the subset?).

  • G001 — Use complete qualified finite group Cayley tables with carrier labels 0 through size−1 and the given row/column order. Every group axiom is a premise already checked on the whole table. Results concern these finite groups; a homomorphism need not be injective or an isomorphism. size=6, table=[[2, 5, 3, 0, 1, 4], [5, 3, 4, 1, 2, 0], [3, 4, 0, 2, 5, 1], [0, 1, 2, 3, 4, 5], [1, 2, 5, 4, 0, 3], [4, 0, 1, 5, 3, 2]], nonempty candidate subset=[0, 2, 3] normalized to sorted distinct labels. Give (size,subset,all products stay in the subset?).

Definition and scope

Use the original question domain, assumptions and cited MKO definitions. This item has second-context mathematical and bilingual review, with the model, answer and every arithmetic step independently recomputed from the original parameters; the source question remains a candidate.

Step-by-step derivation

S001 · implies

Before

group=ambient;carrier Fin(6);complete Cayley table=[[2, 5, 3, 0, 1, 4], [5, 3, 4, 1, 2, 0], [3, 4, 0, 2, 5, 1], [0, 1, 2, 3, 4, 5], [1, 2, 5, 4, 0, 3], [4, 0, 1, 5, 3, 2]]

After

typed operation closure=Yes;all associativity failures=[]

Conditions: none

Type the complete operation table and check every associativity triple,not only cells used by a subset or map.These tasks require qualified finite groups.

Step identifiers and dependencies

Rule: complete_group_table_closure_associativity · Uses: G001

S002 · implies

Before

group=ambient;candidate identity=0;left products row=[2, 5, 3, 0, 1, 4];right products column=[2, 5, 3, 0, 1, 4]

After

both sides equal carrier labels=No

Conditions: none

Both left and right multiplication must return every x.Do not infer identity from the diagonal or assume label0.

Step identifiers and dependencies

Rule: derive_two_sided_group_identity · Uses: G001, S001

S003 · implies

Before

group=ambient;candidate identity=1;left products row=[5, 3, 4, 1, 2, 0];right products column=[5, 3, 4, 1, 2, 0]

After

both sides equal carrier labels=No

Conditions: none

Both left and right multiplication must return every x.Do not infer identity from the diagonal or assume label0.

Step identifiers and dependencies

Rule: derive_two_sided_group_identity · Uses: G001, S002

S004 · implies

Before

group=ambient;candidate identity=2;left products row=[3, 4, 0, 2, 5, 1];right products column=[3, 4, 0, 2, 5, 1]

After

both sides equal carrier labels=No

Conditions: none

Both left and right multiplication must return every x.Do not infer identity from the diagonal or assume label0.

Step identifiers and dependencies

Rule: derive_two_sided_group_identity · Uses: G001, S003

S005 · implies

Before

group=ambient;candidate identity=3;left products row=[0, 1, 2, 3, 4, 5];right products column=[0, 1, 2, 3, 4, 5]

After

both sides equal carrier labels=Yes

Conditions: none

Both left and right multiplication must return every x.Do not infer identity from the diagonal or assume label0.

Step identifiers and dependencies

Rule: derive_two_sided_group_identity · Uses: G001, S004

S006 · implies

Before

group=ambient;candidate identity=4;left products row=[1, 2, 5, 4, 0, 3];right products column=[1, 2, 5, 4, 0, 3]

After

both sides equal carrier labels=No

Conditions: none

Both left and right multiplication must return every x.Do not infer identity from the diagonal or assume label0.

Step identifiers and dependencies

Rule: derive_two_sided_group_identity · Uses: G001, S005

S007 · implies

Before

group=ambient;candidate identity=5;left products row=[4, 0, 1, 5, 3, 2];right products column=[4, 0, 1, 5, 3, 2]

After

both sides equal carrier labels=No

Conditions: none

Both left and right multiplication must return every x.Do not infer identity from the diagonal or assume label0.

Step identifiers and dependencies

Rule: derive_two_sided_group_identity · Uses: G001, S006

S008 · implies

Before

group=ambient;element=0;derived identity=3;two-sided inverse candidates=[2]

After

inverse=2

Conditions: none

Find y with xy=e and yx=e using the actual identity.The group premises ensure uniqueness;no fixed label is every element's inverse.

Step identifiers and dependencies

Rule: derive_group_inverses_from_actual_identity · Uses: G001, S007

S009 · implies

Before

group=ambient;element=1;derived identity=3;two-sided inverse candidates=[1]

After

inverse=1

Conditions: none

Find y with xy=e and yx=e using the actual identity.The group premises ensure uniqueness;no fixed label is every element's inverse.

Step identifiers and dependencies

Rule: derive_group_inverses_from_actual_identity · Uses: G001, S008

S010 · implies

Before

group=ambient;element=2;derived identity=3;two-sided inverse candidates=[0]

After

inverse=0

Conditions: none

Find y with xy=e and yx=e using the actual identity.The group premises ensure uniqueness;no fixed label is every element's inverse.

Step identifiers and dependencies

Rule: derive_group_inverses_from_actual_identity · Uses: G001, S009

S011 · implies

Before

group=ambient;element=3;derived identity=3;two-sided inverse candidates=[3]

After

inverse=3

Conditions: none

Find y with xy=e and yx=e using the actual identity.The group premises ensure uniqueness;no fixed label is every element's inverse.

Step identifiers and dependencies

Rule: derive_group_inverses_from_actual_identity · Uses: G001, S010

S012 · implies

Before

group=ambient;element=4;derived identity=3;two-sided inverse candidates=[5]

After

inverse=5

Conditions: none

Find y with xy=e and yx=e using the actual identity.The group premises ensure uniqueness;no fixed label is every element's inverse.

Step identifiers and dependencies

Rule: derive_group_inverses_from_actual_identity · Uses: G001, S011

S013 · implies

Before

group=ambient;element=5;derived identity=3;two-sided inverse candidates=[4]

After

inverse=4

Conditions: none

Find y with xy=e and yx=e using the actual identity.The group premises ensure uniqueness;no fixed label is every element's inverse.

Step identifiers and dependencies

Rule: derive_group_inverses_from_actual_identity · Uses: G001, S012

S014 · implies

Before

subset=[0, 2, 3];ordered pair=[0, 0];ambient product=2

After

product stays in subset=Yes

Conditions: none

Check every ordered subset pair using the ambient row/column roles.The group is finite and the candidate nonempty as required.

Step identifiers and dependencies

Rule: subset_every_ordered_product_closure · Uses: G001, S013

S015 · implies

Before

subset=[0, 2, 3];ordered pair=[0, 2];ambient product=3

After

product stays in subset=Yes

Conditions: none

Check every ordered subset pair using the ambient row/column roles.The group is finite and the candidate nonempty as required.

Step identifiers and dependencies

Rule: subset_every_ordered_product_closure · Uses: G001, S014

S016 · implies

Before

subset=[0, 2, 3];ordered pair=[0, 3];ambient product=0

After

product stays in subset=Yes

Conditions: none

Check every ordered subset pair using the ambient row/column roles.The group is finite and the candidate nonempty as required.

Step identifiers and dependencies

Rule: subset_every_ordered_product_closure · Uses: G001, S015

S017 · implies

Before

subset=[0, 2, 3];ordered pair=[2, 0];ambient product=3

After

product stays in subset=Yes

Conditions: none

Check every ordered subset pair using the ambient row/column roles.The group is finite and the candidate nonempty as required.

Step identifiers and dependencies

Rule: subset_every_ordered_product_closure · Uses: G001, S016

S018 · implies

Before

subset=[0, 2, 3];ordered pair=[2, 2];ambient product=0

After

product stays in subset=Yes

Conditions: none

Check every ordered subset pair using the ambient row/column roles.The group is finite and the candidate nonempty as required.

Step identifiers and dependencies

Rule: subset_every_ordered_product_closure · Uses: G001, S017

S019 · implies

Before

subset=[0, 2, 3];ordered pair=[2, 3];ambient product=2

After

product stays in subset=Yes

Conditions: none

Check every ordered subset pair using the ambient row/column roles.The group is finite and the candidate nonempty as required.

Step identifiers and dependencies

Rule: subset_every_ordered_product_closure · Uses: G001, S018

S020 · implies

Before

subset=[0, 2, 3];ordered pair=[3, 0];ambient product=0

After

product stays in subset=Yes

Conditions: none

Check every ordered subset pair using the ambient row/column roles.The group is finite and the candidate nonempty as required.

Step identifiers and dependencies

Rule: subset_every_ordered_product_closure · Uses: G001, S019

S021 · implies

Before

subset=[0, 2, 3];ordered pair=[3, 2];ambient product=2

After

product stays in subset=Yes

Conditions: none

Check every ordered subset pair using the ambient row/column roles.The group is finite and the candidate nonempty as required.

Step identifiers and dependencies

Rule: subset_every_ordered_product_closure · Uses: G001, S020

S022 · implies

Before

subset=[0, 2, 3];ordered pair=[3, 3];ambient product=3

After

product stays in subset=Yes

Conditions: none

Check every ordered subset pair using the ambient row/column roles.The group is finite and the candidate nonempty as required.

Step identifiers and dependencies

Rule: subset_every_ordered_product_closure · Uses: G001, S021

S023 · implies

Before

nonempty finite subset=[0, 2, 3];product closed=Yes

After

requested field records closure in this qualified finite group

Conditions: none

This field reports product closure.In a finite group,a nonempty closed subset does imply a subgroup:repeating powers supply identity and inverses.The separate task lists each obligation explicitly;do not falsely call closure insufficient in this finite setting.

Step identifiers and dependencies

Rule: finite_nonempty_closure_not_false_insufficiency_claim · Uses: G001, S022

Reverse checks

  • S023 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
  • S022 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
  • S021 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
  • S020 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
  • S019 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
  • S018 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
  • S017 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
  • S016 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
  • S015 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
  • S014 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
  • S013 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
  • S012 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
  • S011 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
  • S010 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
  • S009 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
  • S008 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
  • S007 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
  • S006 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
  • S005 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
  • S004 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
  • S003 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
  • S002 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
  • S001 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.

Result

(6, [0, 2, 3], Yes)

The full substitutions and premise checks give the original answer; source identity,format and status are unchanged.

This question review and source binding

Review date: 2026-10-26

Original questions, answers, step expressions, numeric ASTs and historical records are retained. Source candidate labels remain historical and are not overwritten as formal proof.

Source hashes and review receipts
  • input commit: 0f7be61e2c22317a4075561dc822c87d881a50db
  • original question SHA-256: e241d2d5dd52e27dbacaeda3927e5d79279e5cb89a845ba155540b6307ed39c8
  • candidate record SHA-256: db70aa2aa4cfac122d5c99b80a7bacabea6bb4b48ebb72cb3bad1b5f319c362b
  • semantic review receipt SHA-256: b4c47938fd38085d44967226cfa8337d61334455472e7307c60d3a488cef598f
  • question-first witness SHA-256: 3c23baa97a5933bc07b44f2257017ef4e845bf1429bd6f5381410681c43b97e4
  • Lean: NOT_RUN · human review: NOT_PERFORMED
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