# Question 11126: A Missing Midpoint Refutes Convexity, but a Present One Does Not Prove It

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This teaching derivation has second-context AI mathematical and bilingual semantic review, limited to the model and assumptions stated in this question. It has no human review or new Lean proof and does not promote the original question or MKO to Canonical truth.

R0021-11126 · q-20261013-advance-20261024-r07-convex-set-0076



## Original question and givens

Convexity means every pair of set members and every lambda in [0,1] has lambda*left+(1−lambda)*right in the set. Positive cases use complete algebraic certificates, not sampled lambda values. One exact counterexample suffices to refute convexity; a failed counterexample does not prove convexity. Distinct finite points=[[0, 0], [2, 0], [0, 2]] retain input order; endpoints left=[2, 0], right=[0, 2] must belong to the set. Give (points,left,right,exact midpoint,midpoint present?,is this a nonconvexity witness?). Use exact rational arithmetic, reduce fractions to positive denominators and omit /1 for integer outputs.


- G001 — Convexity means every pair of set members and every lambda in [0,1] has lambda*left+(1−lambda)*right in the set. Positive cases use complete algebraic certificates, not sampled lambda values. One exact counterexample suffices to refute convexity; a failed counterexample does not prove convexity. Distinct finite points=[[0, 0], [2, 0], [0, 2]] retain input order; endpoints left=[2, 0], right=[0, 2] must belong to the set. Give (points,left,right,exact midpoint,midpoint present?,is this a nonconvexity witness?). Use exact rational arithmetic, reduce fractions to positive denominators and omit /1 for integer outputs.





## Definition and scope

Use the original question domain, assumptions and cited MKO definitions. This item has second-context mathematical and bilingual review, with the model, answer and every arithmetic step independently recomputed from the original parameters; the source question remains a candidate.


- [mko-convex-set](https://ocme.evemisslab.com/en/mko/mko-convex-set/)





## Step-by-step derivation

S001 · impliesBefore

ordered finite point set=[[0, 0], [2, 0], [0, 2]];left=[2, 0];right=[0, 2]

After

both endpoints belong;choose lambda=1/2

Conditions: none

A counterexample requires both endpoints to be members.Choose the permitted lambda1/2 and compute the exact midpoint,not a visual estimate.

Step identifiers and dependenciesRule: midpoint_member_premises · Uses: G001





S002 · calculationBefore

midpoint coordinate0 numerator := sum(2, 0)

After

midpoint coordinate0 numerator = 2

Conditions: none

Compute exactly with this step's specified roles,retaining signs,denominators and original pairings.

Step identifiers and dependenciesRule: exact_rational_arithmetic · Uses: G001, S001





S003 · calculationBefore

midpoint coordinate0 := div(2, 2)

After

midpoint coordinate0 = 1

Conditions: none

Compute exactly with this step's specified roles,retaining signs,denominators and original pairings.

Step identifiers and dependenciesRule: exact_rational_arithmetic · Uses: G001, S002





S004 · calculationBefore

midpoint coordinate1 numerator := sum(0, 2)

After

midpoint coordinate1 numerator = 2

Conditions: none

Compute exactly with this step's specified roles,retaining signs,denominators and original pairings.

Step identifiers and dependenciesRule: exact_rational_arithmetic · Uses: G001, S003





S005 · calculationBefore

midpoint coordinate1 := div(2, 2)

After

midpoint coordinate1 = 1

Conditions: none

Compute exactly with this step's specified roles,retaining signs,denominators and original pairings.

Step identifiers and dependenciesRule: exact_rational_arithmetic · Uses: G001, S004





S006 · impliesBefore

candidate point index=0;point=[0, 0];midpoint=[1, 1]

After

all coordinates equal=No

Conditions: none

Compare every set member;all coordinates must match,not merely one.

Step identifiers and dependenciesRule: midpoint_complete_set_comparison · Uses: G001, S005





S007 · impliesBefore

candidate point index=1;point=[2, 0];midpoint=[1, 1]

After

all coordinates equal=No

Conditions: none

Compare every set member;all coordinates must match,not merely one.

Step identifiers and dependenciesRule: midpoint_complete_set_comparison · Uses: G001, S006





S008 · impliesBefore

candidate point index=2;point=[0, 2];midpoint=[1, 1]

After

all coordinates equal=No

Conditions: none

Compare every set member;all coordinates must match,not merely one.

Step identifiers and dependenciesRule: midpoint_complete_set_comparison · Uses: G001, S007





S009 · impliesBefore

all point comparisons=[No, No, No]

After

midpoint present=No;this nonconvex witness=Yes

Conditions: none

An absent midpoint is one exact counterexample refuting convexity.A present midpoint only defeats this counterexample;it does not prove the set convex.

Step identifiers and dependenciesRule: midpoint_failed_counterexample_not_convexity · Uses: G001, S008









## Reverse checks


- S009 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
- S008 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
- S007 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
- S006 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
- S005 · premise_and_result_audit — Recompute midpoint coordinate1 with exact rational arithmetic, not rounded decimals.
- S004 · premise_and_result_audit — Recompute midpoint coordinate1 numerator with exact rational arithmetic, not rounded decimals.
- S003 · premise_and_result_audit — Recompute midpoint coordinate0 with exact rational arithmetic, not rounded decimals.
- S002 · premise_and_result_audit — Recompute midpoint coordinate0 numerator with exact rational arithmetic, not rounded decimals.
- S001 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.





## Result

([[0, 0], [2, 0], [0, 2]], [2, 0], [0, 2], [1, 1], No, Yes)

The full substitutions and premise checks give the original answer; source identity,format and status are unchanged.





## This question review and source binding

Review date: 2026-10-26

Original questions, answers, step expressions, numeric ASTs and historical records are retained. Source candidate labels remain historical and are not overwritten as formal proof.

Source hashes and review receipts
- input commit: 0f7be61e2c22317a4075561dc822c87d881a50db
- original question SHA-256: 077df9aab245fef266ca44c2a55d670823b5dd94019e1414d747d1ce116128a8
- candidate record SHA-256: 82b75a9933232948562e65de75ac00a8dd2334364a56a4ee5d75a3f5fdc82fe3
- semantic review receipt SHA-256: 47d23d3735987d68e27733b051bdfa80a3616d44fb223b82bf2e6c8e46d49258
- question-first witness SHA-256: a857db558000724020d2d5e815cb6bc3e2c9e2933df295bf33eb478d3c695139
- Lean: NOT_RUN · human review: NOT_PERFORMED

[Same-source full JSON](https://ocme.evemisslab.com/data/question-derivations/questions/q-20261013-advance-20261024-r07-convex-set-0076.json)




