On Z use f(x)=a*x+b, with nonzero slope a=4, intercept b=-9, selected left=-4, right=5. Give (slope,intercept,left,right,image_left,image_right,injective_check?,universal_nonzero_slope_injection_Z_to_Z_then_encode_N).
G001 — On Z use f(x)=a*x+b, with nonzero slope a=4, intercept b=-9, selected left=-4, right=5. Give (slope,intercept,left,right,image_left,image_right,injective_check?,universal_nonzero_slope_injection_Z_to_Z_then_encode_N).
Definition and scope
Use the original question domain, assumptions and cited MKO definitions. This item has second-context mathematical and bilingual review, with the model, answer and every arithmetic step independently recomputed from the original parameters; the source question remains a candidate.
for ANY integers x,y:f(x)=f(y) implies(4)*(x-y)=0,hence x=y
Conditions: none
Subtract the same intercept;the nonzero integer slope times(x−y) is zero.Cancellation in the integers gives x=y for every pair.The displayed left/right check is not the source of universal injectivity.
f maps Z injectively to Z;selected images=[-25, 11];selected-pair implication=Yes
After
encode integer z into N_0 by E(z)=2*z if z>=0,else -2*z-1;even/odd branches disjoint and each injective;E composed with f is injective
Conditions: none
The two branches yield nonnegative even and odd values,so cross-branch collisions are impossible;within each branch cancel±2.Composition gives an injection into the naturals.Negative slopes and equal selected inputs are allowed.
The full substitutions and premise checks give the original answer; source identity,format and status are unchanged.
This question review and source binding
Review date: 2026-10-26
Original questions, answers, step expressions, numeric ASTs and historical records are retained. Source candidate labels remain historical and are not overwritten as formal proof.