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Question 15930: Build the Quotient from Full Additive Cosets

On this page
  1. Original question and givens
  2. Definition and scope
  3. Step-by-step derivation
  4. Reverse checks
  5. Result
  6. This question review and source binding

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R0030-15930 · q-20261014-advance-20261031-r04-finite-quotient-ring-0005

Original question and givens

Use the parent ring Z_12 with residues 0 through 11 and the proper two-sided ideal I of multiples of d=6, where 2≤d≤n and d divides n. Its cosets are residue classes modulo d, ordered by representatives 0 through d−1 with increasing members. The d=n zero ideal is allowed; d=1 gives I=R and is excluded by the project's 1≠0 convention. Retain parent arithmetic modulo n separately from the quotient class label modulo d. No field conclusion follows. Give (ideal,cosets,quotient_size,proper_two_sided_ideal_in_commutative_Zn).

  • G001 — Use the parent ring Z_12 with residues 0 through 11 and the proper two-sided ideal I of multiples of d=6, where 2≤d≤n and d divides n. Its cosets are residue classes modulo d, ordered by representatives 0 through d−1 with increasing members. The d=n zero ideal is allowed; d=1 gives I=R and is excluded by the project's 1≠0 convention. Retain parent arithmetic modulo n separately from the quotient class label modulo d. No field conclusion follows. Give (ideal,cosets,quotient_size,proper_two_sided_ideal_in_commutative_Zn).

Definition and scope

Use the original question domain, assumptions and cited MKO definitions. This item has second-context mathematical and bilingual review, with the model, answer and every arithmetic step independently recomputed from the original parameters; the source question remains a candidate.

Step-by-step derivation

S001 · calculation

Before

quotient ring parent modulus divided by ideal generator := div(12, 6)

After

quotient ring parent modulus divided by ideal generator = 2

Conditions: none

Compute exactly from original roles and established intermediates,retaining indices,signs,denominators and the operation's carrier.

Step identifiers and dependencies

Rule: exact_rational_arithmetic · Uses: G001

S002 · implies

Before

same declared parent Z_12;generator d=6;n/d=2;ideal multiples=[0, 6]

After

I=kernel of residue map Z_12 to Z_6;proper two-sided ideal=Yes;zero ideal allowed when d=n

Conditions: none

Since d divides n,changing an integer representative by n does not change mod d.The map π:Z_n→Z_d is well-defined and preserves addition and multiplication.Its kernel consists of multiples of d,closed under differences and multiplication on either side by parent elements.With d≥2 it excludes1 and is proper;d=n gives the allowed zero ideal.

Step identifiers and dependencies

Rule: quotient_ring_actual_parent_proper_two_sided_ideal · Uses: G001, S001

S003 · implies

Before

complete parent residues=[0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11];same ideal I=[0, 6]

After

all additive cosets in representative order0..d-1=[[0, 6], [1, 7], [2, 8], [3, 9], [4, 10], [5, 11]];quotient size=6;no field conclusion

Conditions: none

List every parent element congruent mod d in each additive coset,ordered by representatives0 through d−1.They are disjoint and cover Z_n.Quotient elements are whole cosets;class labels are indices only,and a finite quotient ring is not automatically a field.

Step identifiers and dependencies

Rule: quotient_ring_full_cosets_not_representative_carrier · Uses: G001, S002

Reverse checks

  • S003 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
  • S002 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
  • S001 · premise_and_result_audit — Recompute quotient ring parent modulus divided by ideal generator with exact rational arithmetic, not rounded decimals.

Result

([0, 6], [[0, 6], [1, 7], [2, 8], [3, 9], [4, 10], [5, 11]], 6, proper_two_sided_ideal_in_commutative_Zn)

The full substitutions and premise checks give the original answer; source identity,format and status are unchanged.

This question review and source binding

Review date: 2026-10-26

Original questions, answers, step expressions, numeric ASTs and historical records are retained. Source candidate labels remain historical and are not overwritten as formal proof.

Source hashes and review receipts
  • input commit: 0f7be61e2c22317a4075561dc822c87d881a50db
  • original question SHA-256: f69a02485005503358c839b77d922fcbd12aba0fcbe2f1778002515c25a8682b
  • candidate record SHA-256: 6813c349fbd075a73af092cf7cedd95ed6c5e90d3f2cad7e8a5d2f4b9c13639d
  • semantic review receipt SHA-256: 73bc08066ffb1a81eacb2d4e288d03f522aeefd3949fa0d97da41b484ed737bc
  • question-first witness SHA-256: ac120452a208b257b8270f38351a09dcd832cdbc8d9db6b69933f83e43cc9336
  • Lean: NOT_RUN · human review: NOT_PERFORMED
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