# Question 119: Prior and Likelihood Must Both Enter a Bayes Reversal

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This teaching derivation has second-context AI mathematical and bilingual semantic review, limited to the model and assumptions stated in this question. It has no human review or new Lean proof and does not promote the original question or MKO to Canonical truth.

P250-0119 · q-20261014-advance-20261102-r06-bayes-theorem-0019



## Original question and givens

Use the same complete finite atomic probability law with aligned nonnegative exact masses=[1/26, 1/26, 1/26, 23/26], summing to 1, and canonical event evidence=[0, 2]. Event entries are increasing distinct outcome indices from 0 through 3. Every actual conditional probability requires a strictly positive denominator; a dedicated zero-denominator audit records undefined instead of dividing. Priors, likelihoods, intersections and evidence mass all come from this one law. Keep reduced exact fractions with positive denominators, omitting /1 for integers. Bayes conditioning does not imply causation. Hypothesis=[0, 1] must have positive prior, and evidence must have positive mass. Give (prior,likelihood,evidence_mass,joint,posterior,not_causal).


- G001 — Use the same complete finite atomic probability law with aligned nonnegative exact masses=[1/26, 1/26, 1/26, 23/26], summing to 1, and canonical event evidence=[0, 2]. Event entries are increasing distinct outcome indices from 0 through 3. Every actual conditional probability requires a strictly positive denominator; a dedicated zero-denominator audit records undefined instead of dividing. Priors, likelihoods, intersections and evidence mass all come from this one law. Keep reduced exact fractions with positive denominators, omitting /1 for integers. Bayes conditioning does not imply causation. Hypothesis=[0, 1] must have positive prior, and evidence must have positive mass. Give (prior,likelihood,evidence_mass,joint,posterior,not_causal).





## Definition and scope

Use one complete finite probability law; both conditioning events have strictly positive mass.


- [mko-bayes-theorem](https://ocme.evemisslab.com/en/mko/mko-bayes-theorem/)





## Step-by-step derivation

S001 · calculationBefore

P(Ω) := sum(1/26, 1/26, 1/26, 23/26)

After

P(Ω) = 1

Conditions: none

Sum all atom masses first to verify normalization.

Step identifiers and dependenciesRule: exact_rational_arithmetic · Uses: G001





S002 · impliesBefore

H=[0, 1]; E=[0, 2]

After

H∩E=[0]

Conditions: none

Only sample points in both events contribute to their joint probability.

Step identifiers and dependenciesRule: event_intersection · Uses: G001, S001





S003 · calculationBefore

P(H) := sum(1/26, 1/26)

After

P(H) = 1/13

Conditions: none

Add the masses of the points in H.

Step identifiers and dependenciesRule: exact_rational_arithmetic · Uses: G001, S002





S004 · calculationBefore

P(E) := sum(1/26, 1/26)

After

P(E) = 1/13

Conditions: none

Add the masses in E; this is the posterior's conditioning denominator.

Step identifiers and dependenciesRule: exact_rational_arithmetic · Uses: G001, S003





S005 · calculationBefore

P(H∩E) := sum(1/26)

After

P(H∩E) = 1/26

Conditions: none

Sum the intersection once, without double-counting.

Step identifiers and dependenciesRule: exact_rational_arithmetic · Uses: G001, S004





S006 · calculationBefore

P(E|H) := div(1/26, 1/13)

After

P(E|H) = 1/2

Conditions: none

Since P(H)=1/13>0, divide the joint probability by P(H).

Step identifiers and dependenciesRule: exact_rational_arithmetic · Uses: G001, S005





S007 · calculationBefore

P(E|H)·P(H) := mul(1/2, 1/13)

After

P(E|H)·P(H) = 1/26

Conditions: none

Multiply the conditional probability by the conditioning event's probability to recover the joint.

Step identifiers and dependenciesRule: exact_rational_arithmetic · Uses: G001, S006





S008 · calculationBefore

P(H|E) := div(1/26, 1/13)

After

P(H|E) = 1/2

Conditions: none

When reversing the condition, the denominator is P(E)=1/13>0.

Step identifiers and dependenciesRule: exact_rational_arithmetic · Uses: G001, S007





S009 · impliesBefore

P(H|E)=1/2; P(H∩E)=P(E|H)P(H)

After

P(H|E)=P(E|H)P(H)/P(E)=1/2

Conditions: P(E)>0; P(H)>0

Substitute the established joint-product identity into the posterior definition to obtain Bayes' formula for this instance.

Step identifiers and dependenciesRule: bayes_substitution · Uses: G001, S008





S010 · calculationBefore

P(H|E)·P(E) := mul(1/2, 1/13)

After

P(H|E)·P(E) = 1/26

Conditions: none

Multiply back by P(E) to recover the same joint probability.

Step identifiers and dependenciesRule: exact_rational_arithmetic · Uses: G001, S009





S011 · impliesBefore

probability identity

After

no causal direction has been established

Conditions: none

This is a conditional-probability identity in one law, not evidence of a causal direction.

Step identifiers and dependenciesRule: probability_not_causality · Uses: G001, S010









## Reverse checks


- S011 · premise_and_result_audit — With zero conditioning mass the quotient is undefined, not a numerical 0/0 answer.
- S010 · premise_and_result_audit — Recompute P(H|E)·P(E) with exact rational arithmetic, not rounded decimals.
- S009 · premise_and_result_audit — Reversing a conditional does not mean swapping labels while keeping the old denominator.
- S008 · premise_and_result_audit — Recompute P(H|E) with exact rational arithmetic, not rounded decimals.
- S007 · premise_and_result_audit — Recompute P(E|H)·P(H) with exact rational arithmetic, not rounded decimals.
- S006 · premise_and_result_audit — Recompute P(E|H) with exact rational arithmetic, not rounded decimals.
- S005 · premise_and_result_audit — Recompute P(H∩E) with exact rational arithmetic, not rounded decimals.
- S004 · premise_and_result_audit — Recompute P(E) with exact rational arithmetic, not rounded decimals.
- S003 · premise_and_result_audit — Recompute P(H) with exact rational arithmetic, not rounded decimals.
- S002 · premise_and_result_audit — Do not multiply the event probabilities: independence has not been assumed.
- S001 · premise_and_result_audit — Recompute P(Ω) with exact rational arithmetic, not rounded decimals.





## Result

(1/13, 1/2, 1/13, 1/26, 1/2, not_causal)

P(H|E)=1/2; the complete answer also retains the prior, likelihood, evidence and joint.





## This question review and source binding

Review date: 2026-10-24

Original questions, answers, step expressions, numeric ASTs and historical records are retained. Source candidate labels remain historical and are not overwritten as formal proof.

Source hashes and review receipts
- input commit: 0f7be61e2c22317a4075561dc822c87d881a50db
- original question SHA-256: d96bb1f3a311d1695ba395f3f827520f93ac35e2e726700860d98c2066d26f21
- candidate record SHA-256: 2080a585408670bcd148ff9209ce22220c556c12103fe3b156cc1a84231d91b9
- semantic review receipt SHA-256: 4727d1bd957a9b7f6cadb7972ddb5ab80a31f5259dc5394c1dff2b71944ed36b
- question-first witness SHA-256: 51e18649133238ac992229f6e16542a5f3af53ca73b2262ab0524508ea937dee
- Lean: NOT_RUN · human review: NOT_PERFORMED

[Same-source full JSON](https://ocme.evemisslab.com/data/question-derivations/questions/q-20261014-advance-20261102-r06-bayes-theorem-0019.json)




