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Question 17753: Retain Both the Telescoping Remainder and the Source Ratio Text

On this page
  1. Original question and givens
  2. Definition and scope
  3. Step-by-step derivation
  4. Reverse checks
  5. Result
  6. This question review and source binding

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R0034-17753 · q-20261014-advance-20261103-r03-infinite-series-0053

Original question and givens

Use c=3, positive shift s=2, and n=3 terms c/(s+k)−c/(s+k+1) for k=0 through n−1. Give (c,shift,n,partial_sum,remainder,infinite_sum,exact_telescoping_remainder). The source directly formats remainder=c/(s+n) and infinite_sum=c/s and may leave those two ratios unreduced; retain that exact text.

  • G001 — Use c=3, positive shift s=2, and n=3 terms c/(s+k)−c/(s+k+1) for k=0 through n−1. Give (c,shift,n,partial_sum,remainder,infinite_sum,exact_telescoping_remainder). The source directly formats remainder=c/(s+n) and infinite_sum=c/s and may leave those two ratios unreduced; retain that exact text.

Definition and scope

Use the original question domain, assumptions and cited MKO definitions. This item has second-context mathematical and bilingual review, with the model, answer and every arithmetic step independently recomputed from the original parameters; the source question remains a candidate.

Step-by-step derivation

S001 · calculation

Before

telescoping final remainder denominator := sum(2, 3)

After

telescoping final remainder denominator = 5

Conditions: none

Compute exactly from original roles and established intermediates,retaining denominators,signs,indices and strict conditions.

Step identifiers and dependencies

Rule: exact_rational_arithmetic · Uses: G001

S002 · calculation

Before

telescoping first endpoint numeric value := div(3, 2)

After

telescoping first endpoint numeric value = 3/2

Conditions: none

Compute exactly from original roles and established intermediates,retaining denominators,signs,indices and strict conditions.

Step identifiers and dependencies

Rule: exact_rational_arithmetic · Uses: G001, S001

S003 · calculation

Before

telescoping signed remainder numeric value := div(3, 5)

After

telescoping signed remainder numeric value = 3/5

Conditions: none

Compute exactly from original roles and established intermediates,retaining denominators,signs,indices and strict conditions.

Step identifiers and dependencies

Rule: exact_rational_arithmetic · Uses: G001, S002

S004 · calculation

Before

telescoping reduced partial sum := sub(3/2, 3/5)

After

telescoping reduced partial sum = 9/10

Conditions: none

Compute exactly from original roles and established intermediates,retaining denominators,signs,indices and strict conditions.

Step identifiers and dependencies

Rule: exact_rational_arithmetic · Uses: G001, S003

S005 · calculation

Before

telescoping partial plus signed remainder := sum(9/10, 3/5)

After

telescoping partial plus signed remainder = 3/2

Conditions: none

Compute exactly from original roles and established intermediates,retaining denominators,signs,indices and strict conditions.

Step identifiers and dependencies

Rule: exact_rational_arithmetic · Uses: G001, S004

S006 · implies

Before

original c=3;shift=2;n=3;terms c/(shift+k)-c/(shift+k+1),k0..n-1

After

ALL interior terms cancel;S_n=c/shift-c/(shift+n)=9/10;signed remainder=3/5;reverse sum=3/2

Conditions: none

Every interior positive endpoint cancels its preceding negative occurrence,leaving the first endpoint and final negative one.Add the signed remainder back to reverse-check;do not replace a negative-c remainder by its absolute value.

Step identifiers and dependencies

Rule: series_telescoping_all_interior_cancellation_and_reverse_check · Uses: G001, S005

S007 · implies

Before

same source formatting c=3;source remainder ratio text=3/5;source infinite-sum ratio text=3/2

After

computed partial sum REDUCED=9/10;remainder/infinite fields retain DIRECT UNREDUCED source text;numeric equivalents=[3/5, 3/2]

Conditions: none

The source reduces the computed partial sum but directly formats the other two ratio fields,which can remain2/4 or0/den.Preserve those answer bytes and verify their numerical values separately;mathematical equivalence does not authorize rewriting the source output.

Step identifiers and dependencies

Rule: series_telescoping_source_ratio_bytes_not_silent_reduction · Uses: G001, S006

S008 · implies

Before

DECLARED whole telescoping tail;remainder at general n is(3)/(n+2)

After

signed remainder tends to0;full partial-sum limit=c/shift under the given index convention

Conditions: none

The fixed coefficient and positive shift give an explicit remainder for every n.Its limit proves the full sum,not success of the single supplied endpoint check.

Step identifiers and dependencies

Rule: series_telescoping_full_remainder_limit_not_one_n · Uses: G001, S007

Reverse checks

  • S008 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
  • S007 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
  • S006 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
  • S005 · premise_and_result_audit — Recompute telescoping partial plus signed remainder with exact rational arithmetic, not rounded decimals.
  • S004 · premise_and_result_audit — Recompute telescoping reduced partial sum with exact rational arithmetic, not rounded decimals.
  • S003 · premise_and_result_audit — Recompute telescoping signed remainder numeric value with exact rational arithmetic, not rounded decimals.
  • S002 · premise_and_result_audit — Recompute telescoping first endpoint numeric value with exact rational arithmetic, not rounded decimals.
  • S001 · premise_and_result_audit — Recompute telescoping final remainder denominator with exact rational arithmetic, not rounded decimals.

Result

(3, 2, 3, 9/10, 3/5, 3/2, exact_telescoping_remainder)

The full substitutions and premise checks give the original answer; source identity,format and status are unchanged.

This question review and source binding

Review date: 2026-10-26

Original questions, answers, step expressions, numeric ASTs and historical records are retained. Source candidate labels remain historical and are not overwritten as formal proof.

Source hashes and review receipts
  • input commit: 0f7be61e2c22317a4075561dc822c87d881a50db
  • original question SHA-256: 646226343a3328a5cf4d9b277b5e248b5130ec5f1c080928ba3a173c8466de71
  • candidate record SHA-256: 67849eca53ba467fa732f8865f0ec9da42739d52c27782eff46798419c8f6bd1
  • semantic review receipt SHA-256: f73d099ebe3ff1c69a5d96f08c75b11b9e5b05120af40cf3ef388fce3b5c5336
  • question-first witness SHA-256: 22675ffb6209b4fea076032b29b96e3dc19aad4244c54493f5f65f5e5d875699
  • Lean: NOT_RUN · human review: NOT_PERFORMED
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