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Question 18106: Compute an Estimator Expectation under One Fixed Parameter Law

On this page
  1. Original question and givens
  2. Definition and scope
  3. Step-by-step derivation
  4. Reverse checks
  5. Result
  6. This question review and source binding

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R0035-18106 · q-20261014-advance-20261104-r04-statistical-estimator-0056

Original question and givens

Use one common finite model with parameter indices=Fin(2)={0,…,1}, outcomes=Fin(3)={0,…,2}, complete candidate laws=[[1/9, 1/9, 7/9], [1/2, 1/3, 1/6]], and the single total statistic T=[0, 6, 12] in outcome order. Each law must be nonnegative and sum to 1 before model qualification. T depends on the observation, not the unknown parameter. An observed value is an estimate, while T is the estimator function; no prior or posterior is supplied. Qualified-model parameter index=1. Give (parameter, expectation, statistic).

  • G001 — Use one common finite model with parameter indices=Fin(2)={0,…,1}, outcomes=Fin(3)={0,…,2}, complete candidate laws=[[1/9, 1/9, 7/9], [1/2, 1/3, 1/6]], and the single total statistic T=[0, 6, 12] in outcome order. Each law must be nonnegative and sum to 1 before model qualification. T depends on the observation, not the unknown parameter. An observed value is an estimate, while T is the estimator function; no prior or posterior is supplied. Qualified-model parameter index=1. Give (parameter, expectation, statistic).

Definition and scope

Use the original question domain, assumptions and cited MKO definitions. This item has second-context mathematical and bilingual review, with the model, answer and every arithmetic step independently recomputed from the original parameters; the source question remains a candidate.

Step-by-step derivation

S001 · implies

Before

source operation=estimator-expectation-at-parameter;original snapshot and mathematics retained

After

explicit ordered source output fields=[parameter, expectation, statistic]

Conditions: none

Keep the historical interface marker in the original snapshot while giving ordered fields here,without JavaScript or an external table.Labels are not mathematical evidence,and each No marker retains the operation's claim scope.

Step identifiers and dependencies

Rule: source_ordered_interface_explicit_without_javascript · Uses: G001

S002 · calculation

Before

estimator parameter0 complete law sum := sum(1/9, 1/9, 7/9)

After

estimator parameter0 complete law sum = 1

Conditions: none

Compute exactly from original roles and established intermediates,retaining indices,denominators,signs and the relevant carrier.

Step identifiers and dependencies

Rule: exact_rational_arithmetic · Uses: G001, S001

S003 · implies

Before

original parameter=0;SAME outcome carrier Fin(3);aligned reduced candidate law=[1/9, 1/9, 7/9]

After

sum=1;nonnegative=Yes;law qualified=Yes

Conditions: none

Every model row must be nonnegative and total1.Invalid candidate rows retain false flags;a total statistic does not repair a probability model.

Step identifiers and dependencies

Rule: estimator_complete_laws_separate_from_total_statistic · Uses: G001, S002

S004 · calculation

Before

estimator parameter1 complete law sum := sum(1/2, 1/3, 1/6)

After

estimator parameter1 complete law sum = 1

Conditions: none

Compute exactly from original roles and established intermediates,retaining indices,denominators,signs and the relevant carrier.

Step identifiers and dependencies

Rule: exact_rational_arithmetic · Uses: G001, S003

S005 · implies

Before

original parameter=1;SAME outcome carrier Fin(3);aligned reduced candidate law=[1/2, 1/3, 1/6]

After

sum=1;nonnegative=Yes;law qualified=Yes

Conditions: none

Every model row must be nonnegative and total1.Invalid candidate rows retain false flags;a total statistic does not repair a probability model.

Step identifiers and dependencies

Rule: estimator_complete_laws_separate_from_total_statistic · Uses: G001, S004

S006 · implies

Before

original parameter carrier Fin(2);common outcome carrier Fin(3);ONE original statistic array=[0, 6, 12]

After

all model laws qualified=Yes;one value per outcome=Yes;SAME statistic map T(o) at EVERY parameter

Conditions: none

The statistic definition takes an observation index,not the unknown parameter.This is functional parameter-independence,not a claim that the law or expectation of T(X) is parameter-free.No estimand,prior or posterior has been supplied.

Step identifiers and dependencies

Rule: estimator_definition_parameter_independence_not_distribution_free · Uses: G001, S005

S007 · calculation

Before

estimator selected law weighted outcome0 := mul(1/2, 0)

After

estimator selected law weighted outcome0 = 0

Conditions: none

Compute exactly from original roles and established intermediates,retaining indices,denominators,signs and the relevant carrier.

Step identifiers and dependencies

Rule: exact_rational_arithmetic · Uses: G001, S006

S008 · calculation

Before

estimator selected law weighted outcome1 := mul(1/3, 6)

After

estimator selected law weighted outcome1 = 2

Conditions: none

Compute exactly from original roles and established intermediates,retaining indices,denominators,signs and the relevant carrier.

Step identifiers and dependencies

Rule: exact_rational_arithmetic · Uses: G001, S007

S009 · calculation

Before

estimator selected law weighted outcome2 := mul(1/6, 12)

After

estimator selected law weighted outcome2 = 2

Conditions: none

Compute exactly from original roles and established intermediates,retaining indices,denominators,signs and the relevant carrier.

Step identifiers and dependencies

Rule: exact_rational_arithmetic · Uses: G001, S008

S010 · calculation

Before

estimator selected parameter expectation := sum(0, 2, 2)

After

estimator selected parameter expectation = 4

Conditions: none

Compute exactly from original roles and established intermediates,retaining indices,denominators,signs and the relevant carrier.

Step identifiers and dependencies

Rule: exact_rational_arithmetic · Uses: G001, S009

S011 · implies

Before

FIXED original parameter=1;complete law=[1/2, 1/3, 1/6];SAME statistic=[0, 6, 12];weighted terms=[0, 2, 2]

After

E_parameter[T]=4;no unbiasedness or posterior conclusion

Conditions: none

Weight the same statistic by the complete law for one fixed parameter.Without a declared estimand,comparing this expectation with the parameter index does not establish bias or unbiasedness;no prior supplies a posterior.

Step identifiers and dependencies

Rule: estimator_expectation_fixed_law_no_undeclared_estimand · Uses: G001, S010

Reverse checks

  • S011 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
  • S010 · premise_and_result_audit — Recompute estimator selected parameter expectation with exact rational arithmetic, not rounded decimals.
  • S009 · premise_and_result_audit — Recompute estimator selected law weighted outcome2 with exact rational arithmetic, not rounded decimals.
  • S008 · premise_and_result_audit — Recompute estimator selected law weighted outcome1 with exact rational arithmetic, not rounded decimals.
  • S007 · premise_and_result_audit — Recompute estimator selected law weighted outcome0 with exact rational arithmetic, not rounded decimals.
  • S006 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
  • S005 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
  • S004 · premise_and_result_audit — Recompute estimator parameter1 complete law sum with exact rational arithmetic, not rounded decimals.
  • S003 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
  • S002 · premise_and_result_audit — Recompute estimator parameter0 complete law sum with exact rational arithmetic, not rounded decimals.
  • S001 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.

Result

(1, 4, [0, 6, 12])

The full substitutions and premise checks give the original answer; source identity,format and status are unchanged.

This question review and source binding

Review date: 2026-10-26

Original questions, answers, step expressions, numeric ASTs and historical records are retained. Source candidate labels remain historical and are not overwritten as formal proof.

Source hashes and review receipts
  • input commit: 0f7be61e2c22317a4075561dc822c87d881a50db
  • original question SHA-256: 5274e8666141c95738beb50f7d4f5069199ccfd11023dc46c7f7fef6bded8800
  • candidate record SHA-256: c83dc6d641b8f7121dc66620e5b99a600aff9525021ac90167f26fcd0c436758
  • semantic review receipt SHA-256: 713db6309b22bf8b31f0253d4aaa7aca9011ab908587ae0e9d4a365edce1f9bc
  • question-first witness SHA-256: 0338a3db344ab237113fc63be29153c3684da96e388109e9dcd913a0a693aed2
  • Lean: NOT_RUN · human review: NOT_PERFORMED
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