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Question 80: The Finite Expansion Includes Every k from Zero through n

On this page
  1. Original question and givens
  2. Definition and scope
  3. Step-by-step derivation
  4. Reverse checks
  5. Result
  6. This question review and source binding

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← Question derivation index · Original question batch

P250-0080 · q-20261014-advance-20261109-r05-binomial-theorem-0030

Original question and givens

Use natural exponent n=4, including0, in a commutative coefficient setting. Give (n, coefficient_exponent_rows, boundary).

  • G001 — Use natural exponent n=4, including0, in a commutative coefficient setting. Give (n, coefficient_exponent_rows, boundary).

Definition and scope

n is a nonnegative integer and x,y commute. For n=0 use the polynomial empty-product identity.

Step-by-step derivation

S001 · implies

Before

n=4≥0; x,y commute

After

(x+y)^4 is a finite product of 4 factors

Conditions: none

Choose x or y from each factor; commutativity permits grouping products by the number of y choices.

Step identifiers and dependencies

Rule: finite_product · Uses: G001

S002 · implies

Before

choose exactly 0 of 4 factors to contribute y

After

C(4,0)=24/(1·24)=1

Conditions: none

Count orderings of 4 positions and divide by reorderings within the 0 y positions and 4 x positions, giving coefficient 1.

Step identifiers and dependencies

Rule: subset_count · Uses: G001, S001

S003 · implies

Before

C(4,0)=1; choose y 0 times

After

1·x^4·y^0

Conditions: none

The x exponent is 4-0=4; the two exponents still sum to 4.

Step identifiers and dependencies

Rule: group_like_terms · Uses: G001, S002

S004 · implies

Before

choose exactly 1 of 4 factors to contribute y

After

C(4,1)=24/(1·6)=4

Conditions: none

Count orderings of 4 positions and divide by reorderings within the 1 y positions and 3 x positions, giving coefficient 4.

Step identifiers and dependencies

Rule: subset_count · Uses: G001, S003

S005 · implies

Before

C(4,1)=4; choose y 1 times

After

4·x^3·y^1

Conditions: none

The x exponent is 4-1=3; the two exponents still sum to 4.

Step identifiers and dependencies

Rule: group_like_terms · Uses: G001, S004

S006 · implies

Before

choose exactly 2 of 4 factors to contribute y

After

C(4,2)=24/(2·2)=6

Conditions: none

Count orderings of 4 positions and divide by reorderings within the 2 y positions and 2 x positions, giving coefficient 6.

Step identifiers and dependencies

Rule: subset_count · Uses: G001, S005

S007 · implies

Before

C(4,2)=6; choose y 2 times

After

6·x^2·y^2

Conditions: none

The x exponent is 4-2=2; the two exponents still sum to 4.

Step identifiers and dependencies

Rule: group_like_terms · Uses: G001, S006

S008 · implies

Before

choose exactly 3 of 4 factors to contribute y

After

C(4,3)=24/(6·1)=4

Conditions: none

Count orderings of 4 positions and divide by reorderings within the 3 y positions and 1 x positions, giving coefficient 4.

Step identifiers and dependencies

Rule: subset_count · Uses: G001, S007

S009 · implies

Before

C(4,3)=4; choose y 3 times

After

4·x^1·y^3

Conditions: none

The x exponent is 4-3=1; the two exponents still sum to 4.

Step identifiers and dependencies

Rule: group_like_terms · Uses: G001, S008

S010 · implies

Before

choose exactly 4 of 4 factors to contribute y

After

C(4,4)=24/(24·1)=1

Conditions: none

Count orderings of 4 positions and divide by reorderings within the 4 y positions and 0 x positions, giving coefficient 1.

Step identifiers and dependencies

Rule: subset_count · Uses: G001, S009

S011 · implies

Before

C(4,4)=1; choose y 4 times

After

1·x^0·y^4

Conditions: none

The x exponent is 4-4=0; the two exponents still sum to 4.

Step identifiers and dependencies

Rule: group_like_terms · Uses: G001, S010

S012 · implies

Before

all k=0 through 4 have been accounted for

After

(x+y)^4=1·x^4·y^0 + 4·x^3·y^1 + 6·x^2·y^2 + 4·x^1·y^3 + 1·x^0·y^4

Conditions: none

Every x/y choice belongs to exactly one k class, so this is the complete finite expansion, not just endpoint terms.

Step identifiers and dependencies

Rule: collect_all_terms · Uses: G001, S011

Reverse checks

  • S012 · premise_and_result_audit — There are n+1 coefficient positions, with the complete range of k retained.
  • S011 · premise_and_result_audit — The answer row is [k,coefficient,x exponent,y exponent]; do not swap the exponent columns.
  • S010 · premise_and_result_audit — Check the coefficient independently with the integer Pascal recurrence, not approximate factorials.
  • S009 · premise_and_result_audit — The answer row is [k,coefficient,x exponent,y exponent]; do not swap the exponent columns.
  • S008 · premise_and_result_audit — Check the coefficient independently with the integer Pascal recurrence, not approximate factorials.
  • S007 · premise_and_result_audit — The answer row is [k,coefficient,x exponent,y exponent]; do not swap the exponent columns.
  • S006 · premise_and_result_audit — Check the coefficient independently with the integer Pascal recurrence, not approximate factorials.
  • S005 · premise_and_result_audit — The answer row is [k,coefficient,x exponent,y exponent]; do not swap the exponent columns.
  • S004 · premise_and_result_audit — Check the coefficient independently with the integer Pascal recurrence, not approximate factorials.
  • S003 · premise_and_result_audit — The answer row is [k,coefficient,x exponent,y exponent]; do not swap the exponent columns.
  • S002 · premise_and_result_audit — Check the coefficient independently with the integer Pascal recurrence, not approximate factorials.
  • S001 · premise_and_result_audit — This is not an infinite expansion for a noninteger power or a claim for noncommuting multiplication.

Result

(4, [[0, 1, 4, 0], [1, 4, 3, 1], [2, 6, 2, 2], [3, 4, 1, 3], [4, 1, 0, 4]], complete_k_zero_through_n_coefficients)

The full expansion consists of all displayed monomials, in the same order as the answer rows.

This question review and source binding

Review date: 2026-10-24

Original questions, answers, step expressions, numeric ASTs and historical records are retained. Source candidate labels remain historical and are not overwritten as formal proof.

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