# Question 86: The Finite Expansion Includes Every k from Zero through n

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This teaching derivation has second-context AI mathematical and bilingual semantic review, limited to the model and assumptions stated in this question. It has no human review or new Lean proof and does not promote the original question or MKO to Canonical truth.

P250-0086 · q-20261014-advance-20261109-r05-binomial-theorem-0036



## Original question and givens

Use natural exponent n=10, including0, in a commutative coefficient setting. Give (n, coefficient_exponent_rows, boundary).


- G001 — Use natural exponent n=10, including0, in a commutative coefficient setting. Give (n, coefficient_exponent_rows, boundary).





## Definition and scope

n is a nonnegative integer and x,y commute. For n=0 use the polynomial empty-product identity.


- [mko-binomial-theorem](https://ocme.evemisslab.com/en/mko/mko-binomial-theorem/)





## Step-by-step derivation

S001 · impliesBefore

n=10≥0; x,y commute

After

(x+y)^10 is a finite product of 10 factors

Conditions: none

Choose x or y from each factor; commutativity permits grouping products by the number of y choices.

Step identifiers and dependenciesRule: finite_product · Uses: G001





S002 · impliesBefore

choose exactly 0 of 10 factors to contribute y

After

C(10,0)=3628800/(1·3628800)=1

Conditions: none

Count orderings of 10 positions and divide by reorderings within the 0 y positions and 10 x positions, giving coefficient 1.

Step identifiers and dependenciesRule: subset_count · Uses: G001, S001





S003 · impliesBefore

C(10,0)=1; choose y 0 times

After

1·x^10·y^0

Conditions: none

The x exponent is 10-0=10; the two exponents still sum to 10.

Step identifiers and dependenciesRule: group_like_terms · Uses: G001, S002





S004 · impliesBefore

choose exactly 1 of 10 factors to contribute y

After

C(10,1)=3628800/(1·362880)=10

Conditions: none

Count orderings of 10 positions and divide by reorderings within the 1 y positions and 9 x positions, giving coefficient 10.

Step identifiers and dependenciesRule: subset_count · Uses: G001, S003





S005 · impliesBefore

C(10,1)=10; choose y 1 times

After

10·x^9·y^1

Conditions: none

The x exponent is 10-1=9; the two exponents still sum to 10.

Step identifiers and dependenciesRule: group_like_terms · Uses: G001, S004





S006 · impliesBefore

choose exactly 2 of 10 factors to contribute y

After

C(10,2)=3628800/(2·40320)=45

Conditions: none

Count orderings of 10 positions and divide by reorderings within the 2 y positions and 8 x positions, giving coefficient 45.

Step identifiers and dependenciesRule: subset_count · Uses: G001, S005





S007 · impliesBefore

C(10,2)=45; choose y 2 times

After

45·x^8·y^2

Conditions: none

The x exponent is 10-2=8; the two exponents still sum to 10.

Step identifiers and dependenciesRule: group_like_terms · Uses: G001, S006





S008 · impliesBefore

choose exactly 3 of 10 factors to contribute y

After

C(10,3)=3628800/(6·5040)=120

Conditions: none

Count orderings of 10 positions and divide by reorderings within the 3 y positions and 7 x positions, giving coefficient 120.

Step identifiers and dependenciesRule: subset_count · Uses: G001, S007





S009 · impliesBefore

C(10,3)=120; choose y 3 times

After

120·x^7·y^3

Conditions: none

The x exponent is 10-3=7; the two exponents still sum to 10.

Step identifiers and dependenciesRule: group_like_terms · Uses: G001, S008





S010 · impliesBefore

choose exactly 4 of 10 factors to contribute y

After

C(10,4)=3628800/(24·720)=210

Conditions: none

Count orderings of 10 positions and divide by reorderings within the 4 y positions and 6 x positions, giving coefficient 210.

Step identifiers and dependenciesRule: subset_count · Uses: G001, S009





S011 · impliesBefore

C(10,4)=210; choose y 4 times

After

210·x^6·y^4

Conditions: none

The x exponent is 10-4=6; the two exponents still sum to 10.

Step identifiers and dependenciesRule: group_like_terms · Uses: G001, S010





S012 · impliesBefore

choose exactly 5 of 10 factors to contribute y

After

C(10,5)=3628800/(120·120)=252

Conditions: none

Count orderings of 10 positions and divide by reorderings within the 5 y positions and 5 x positions, giving coefficient 252.

Step identifiers and dependenciesRule: subset_count · Uses: G001, S011





S013 · impliesBefore

C(10,5)=252; choose y 5 times

After

252·x^5·y^5

Conditions: none

The x exponent is 10-5=5; the two exponents still sum to 10.

Step identifiers and dependenciesRule: group_like_terms · Uses: G001, S012





S014 · impliesBefore

choose exactly 6 of 10 factors to contribute y

After

C(10,6)=3628800/(720·24)=210

Conditions: none

Count orderings of 10 positions and divide by reorderings within the 6 y positions and 4 x positions, giving coefficient 210.

Step identifiers and dependenciesRule: subset_count · Uses: G001, S013





S015 · impliesBefore

C(10,6)=210; choose y 6 times

After

210·x^4·y^6

Conditions: none

The x exponent is 10-6=4; the two exponents still sum to 10.

Step identifiers and dependenciesRule: group_like_terms · Uses: G001, S014





S016 · impliesBefore

choose exactly 7 of 10 factors to contribute y

After

C(10,7)=3628800/(5040·6)=120

Conditions: none

Count orderings of 10 positions and divide by reorderings within the 7 y positions and 3 x positions, giving coefficient 120.

Step identifiers and dependenciesRule: subset_count · Uses: G001, S015





S017 · impliesBefore

C(10,7)=120; choose y 7 times

After

120·x^3·y^7

Conditions: none

The x exponent is 10-7=3; the two exponents still sum to 10.

Step identifiers and dependenciesRule: group_like_terms · Uses: G001, S016





S018 · impliesBefore

choose exactly 8 of 10 factors to contribute y

After

C(10,8)=3628800/(40320·2)=45

Conditions: none

Count orderings of 10 positions and divide by reorderings within the 8 y positions and 2 x positions, giving coefficient 45.

Step identifiers and dependenciesRule: subset_count · Uses: G001, S017





S019 · impliesBefore

C(10,8)=45; choose y 8 times

After

45·x^2·y^8

Conditions: none

The x exponent is 10-8=2; the two exponents still sum to 10.

Step identifiers and dependenciesRule: group_like_terms · Uses: G001, S018





S020 · impliesBefore

choose exactly 9 of 10 factors to contribute y

After

C(10,9)=3628800/(362880·1)=10

Conditions: none

Count orderings of 10 positions and divide by reorderings within the 9 y positions and 1 x positions, giving coefficient 10.

Step identifiers and dependenciesRule: subset_count · Uses: G001, S019





S021 · impliesBefore

C(10,9)=10; choose y 9 times

After

10·x^1·y^9

Conditions: none

The x exponent is 10-9=1; the two exponents still sum to 10.

Step identifiers and dependenciesRule: group_like_terms · Uses: G001, S020





S022 · impliesBefore

choose exactly 10 of 10 factors to contribute y

After

C(10,10)=3628800/(3628800·1)=1

Conditions: none

Count orderings of 10 positions and divide by reorderings within the 10 y positions and 0 x positions, giving coefficient 1.

Step identifiers and dependenciesRule: subset_count · Uses: G001, S021





S023 · impliesBefore

C(10,10)=1; choose y 10 times

After

1·x^0·y^10

Conditions: none

The x exponent is 10-10=0; the two exponents still sum to 10.

Step identifiers and dependenciesRule: group_like_terms · Uses: G001, S022





S024 · impliesBefore

all k=0 through 10 have been accounted for

After

(x+y)^10=1·x^10·y^0 + 10·x^9·y^1 + 45·x^8·y^2 + 120·x^7·y^3 + 210·x^6·y^4 + 252·x^5·y^5 + 210·x^4·y^6 + 120·x^3·y^7 + 45·x^2·y^8 + 10·x^1·y^9 + 1·x^0·y^10

Conditions: none

Every x/y choice belongs to exactly one k class, so this is the complete finite expansion, not just endpoint terms.

Step identifiers and dependenciesRule: collect_all_terms · Uses: G001, S023









## Reverse checks


- S024 · premise_and_result_audit — There are n+1 coefficient positions, with the complete range of k retained.
- S023 · premise_and_result_audit — The answer row is [k,coefficient,x exponent,y exponent]; do not swap the exponent columns.
- S022 · premise_and_result_audit — Check the coefficient independently with the integer Pascal recurrence, not approximate factorials.
- S021 · premise_and_result_audit — The answer row is [k,coefficient,x exponent,y exponent]; do not swap the exponent columns.
- S020 · premise_and_result_audit — Check the coefficient independently with the integer Pascal recurrence, not approximate factorials.
- S019 · premise_and_result_audit — The answer row is [k,coefficient,x exponent,y exponent]; do not swap the exponent columns.
- S018 · premise_and_result_audit — Check the coefficient independently with the integer Pascal recurrence, not approximate factorials.
- S017 · premise_and_result_audit — The answer row is [k,coefficient,x exponent,y exponent]; do not swap the exponent columns.
- S016 · premise_and_result_audit — Check the coefficient independently with the integer Pascal recurrence, not approximate factorials.
- S015 · premise_and_result_audit — The answer row is [k,coefficient,x exponent,y exponent]; do not swap the exponent columns.
- S014 · premise_and_result_audit — Check the coefficient independently with the integer Pascal recurrence, not approximate factorials.
- S013 · premise_and_result_audit — The answer row is [k,coefficient,x exponent,y exponent]; do not swap the exponent columns.
- S012 · premise_and_result_audit — Check the coefficient independently with the integer Pascal recurrence, not approximate factorials.
- S011 · premise_and_result_audit — The answer row is [k,coefficient,x exponent,y exponent]; do not swap the exponent columns.
- S010 · premise_and_result_audit — Check the coefficient independently with the integer Pascal recurrence, not approximate factorials.
- S009 · premise_and_result_audit — The answer row is [k,coefficient,x exponent,y exponent]; do not swap the exponent columns.
- S008 · premise_and_result_audit — Check the coefficient independently with the integer Pascal recurrence, not approximate factorials.
- S007 · premise_and_result_audit — The answer row is [k,coefficient,x exponent,y exponent]; do not swap the exponent columns.
- S006 · premise_and_result_audit — Check the coefficient independently with the integer Pascal recurrence, not approximate factorials.
- S005 · premise_and_result_audit — The answer row is [k,coefficient,x exponent,y exponent]; do not swap the exponent columns.
- S004 · premise_and_result_audit — Check the coefficient independently with the integer Pascal recurrence, not approximate factorials.
- S003 · premise_and_result_audit — The answer row is [k,coefficient,x exponent,y exponent]; do not swap the exponent columns.
- S002 · premise_and_result_audit — Check the coefficient independently with the integer Pascal recurrence, not approximate factorials.
- S001 · premise_and_result_audit — This is not an infinite expansion for a noninteger power or a claim for noncommuting multiplication.





## Result

(10, [[0, 1, 10, 0], [1, 10, 9, 1], [2, 45, 8, 2], [3, 120, 7, 3], [4, 210, 6, 4], [5, 252, 5, 5], [6, 210, 4, 6], [7, 120, 3, 7], [8, 45, 2, 8], [9, 10, 1, 9], [10, 1, 0, 10]], complete_k_zero_through_n_coefficients)

The full expansion consists of all displayed monomials, in the same order as the answer rows.





## This question review and source binding

Review date: 2026-10-24

Original questions, answers, step expressions, numeric ASTs and historical records are retained. Source candidate labels remain historical and are not overwritten as formal proof.

Source hashes and review receipts
- input commit: 0f7be61e2c22317a4075561dc822c87d881a50db
- original question SHA-256: 9135df7c9fe9f03626f516048438cdecbfd4bf64e92f7fadcc77178f03abb65b
- candidate record SHA-256: f5e93d8c6a6c896fb910f86be8bc7549c9ecd59ad3e2145831d0c9306c84227c
- semantic review receipt SHA-256: 4727d1bd957a9b7f6cadb7972ddb5ab80a31f5259dc5394c1dff2b71944ed36b
- question-first witness SHA-256: 51e18649133238ac992229f6e16542a5f3af53ca73b2262ab0524508ea937dee
- Lean: NOT_RUN · human review: NOT_PERFORMED

[Same-source full JSON](https://ocme.evemisslab.com/data/question-derivations/questions/q-20261014-advance-20261109-r05-binomial-theorem-0036.json)




