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Question 22077: A Compact Constant Image Does Not Make an Open-Interval Domain Compact

On this page
  1. Original question and givens
  2. Definition and scope
  3. Step-by-step derivation
  4. Reverse checks
  5. Result
  6. This question review and source binding

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R0043-22077 · q-20261014-advance-20261110-r03-continuous-image-of-compact-0077

Original question and givens

Use the ordinary real open interval (-3,3) with left<right and constant map value=1 into the real line. Give (left, right, constant_value, domain_compact, continuous, image_compact, reverse_implication_claim, boundary).

  • G001 — Use the ordinary real open interval (-3,3) with left<right and constant map value=1 into the real line. Give (left, right, constant_value, domain_compact, continuous, image_compact, reverse_implication_claim, boundary).

Definition and scope

Use the original question domain, assumptions and cited MKO definitions. This item has second-context mathematical and bilingual review, with the model, answer and every arithmetic step independently recomputed from the original parameters; the source question remains a candidate.

Step-by-step derivation

S001 · implies

Before

source operation=compactimg-reverse-implication-boundary;original snapshot and mathematics retained

After

explicit ordered source output fields=[left, right, constant_value, domain_compact, continuous, image_compact, reverse_implication_claim, boundary]

Conditions: none

Retain the historical interface marker and list ordered source fields without JavaScript.MVT fields come from the original mode,without padding or answer-shape inference.Tags and fixed No markers retain their claim scope.

Step identifiers and dependencies

Rule: source_ordered_interface_explicit_without_javascript · Uses: G001

S002 · implies

Before

ORIGINAL WHOLE real interval(-3,3);constant real image value=1

After

for integers j>=0,relative opens U_j=(L+(R-L)/(j+2),R) cover the interval;ANY finite subfamily is contained in U_max_j and misses a nonempty interval near L,so domain NOT compact

Conditions: none

For every x>L,the Archimedean property gives j whose threshold is below x,so the whole family covers.Any finite family has a largest j and misses points between L and its positive threshold.This is an actual cover argument,not finite sampling or a nonclosed slogan.

Step identifiers and dependencies

Rule: compactimg_constant_open_interval_counterexample_whole_cover · Uses: G001, S001

S003 · implies

Before

ORIGINAL noncompact domain=(-3,3);constant f(x)=1

After

preimage of ANY target open is either the whole domain or empty,so continuous;image singleton has a one-member subcover from any cover;reverse implication claim=No

Conditions: none

Both possible preimages of a constant map are open.A cover of a singleton has a member containing its point.Thus a compact image does not force a compact domain,nor general compact preimages or closed images without further hypotheses.

Step identifiers and dependencies

Rule: compactimg_constant_map_continuity_singleton_compact_no_converse · Uses: G001, S002

Reverse checks

  • S003 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
  • S002 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
  • S001 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.

Result

(-3, 3, 1, No, Yes, Yes, No, constant_continuous_map_from_noncompact_open_interval_has_compact_singleton_image)

The full substitutions and premise checks give the original answer; source identity,format and status are unchanged.

This question review and source binding

Review date: 2026-10-26

Original questions, answers, step expressions, numeric ASTs and historical records are retained. Source candidate labels remain historical and are not overwritten as formal proof.

Source hashes and review receipts
  • input commit: 0f7be61e2c22317a4075561dc822c87d881a50db
  • original question SHA-256: 3b0be56e199a50183bb781b497852c32b12a6b7a68d870da6fbbd7263afebe09
  • candidate record SHA-256: eeac7a48f03c91da256047e3e0a17ed2fda5092c91d111e1612c5b3254266719
  • semantic review receipt SHA-256: 49cf6ec60211c92d1c0c302663af4d44479635dc8181fb61a20c3374288e21c5
  • question-first witness SHA-256: 10fd25b4643e5ff12753daceaa61f9f2499bf381f65ef96e9d21185c7c0d0c5e
  • Lean: NOT_RUN · human review: NOT_PERFORMED
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