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Question 23166: Complete Left Cosets Are Equal or Disjoint and Cover the Group

On this page
  1. Original question and givens
  2. Definition and scope
  3. Step-by-step derivation
  4. Reverse checks
  5. Result
  6. This question review and source binding

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R0045-23166 · q-20261014-advance-20261111-r01-lagrange-theorem-finite-groups-0041

Original question and givens

Use the complete finite Cayley table=[[3, 4, 5, 0, 1, 2], [4, 5, 0, 1, 2, 3], [5, 0, 1, 2, 3, 4], [0, 1, 2, 3, 4, 5], [1, 2, 3, 4, 5, 0], [2, 3, 4, 5, 0, 1]], identity=3 and subset=[1, 3, 5]. Row g/column h gives g*h. First certify every group axiom, then audit the entire candidate for identity, product and inverse closure; cardinality alone is not subgroup qualification. Give (representative_coset_rows, equal_sizes, flattened_elements, partition_certificate, certificate).

  • G001 — Use the complete finite Cayley table=[[3, 4, 5, 0, 1, 2], [4, 5, 0, 1, 2, 3], [5, 0, 1, 2, 3, 4], [0, 1, 2, 3, 4, 5], [1, 2, 3, 4, 5, 0], [2, 3, 4, 5, 0, 1]], identity=3 and subset=[1, 3, 5]. Row g/column h gives g*h. First certify every group axiom, then audit the entire candidate for identity, product and inverse closure; cardinality alone is not subgroup qualification. Give (representative_coset_rows, equal_sizes, flattened_elements, partition_certificate, certificate).

Definition and scope

Use the original question domain, assumptions and cited MKO definitions. This item has second-context mathematical and bilingual review, with the model, answer and every arithmetic step independently recomputed from the original parameters; the source question remains a candidate.

Step-by-step derivation

S001 · implies

Before

source operation=lagrange-left-coset-partition;original snapshot and mathematics retained

After

explicit ordered source output fields=[representative_coset_rows, equal_sizes, flattened_elements, partition_certificate, certificate]

Conditions: none

Retain the historical interface marker while listing source fields without JavaScript.Tags and No retain their claim scope;source-protocol ordering is not a mathematical proof.

Step identifiers and dependencies

Rule: source_ordered_interface_explicit_without_javascript · Uses: G001

S002 · implies

Before

ORIGINAL closed Cayley table=[[3, 4, 5, 0, 1, 2], [4, 5, 0, 1, 2, 3], [5, 0, 1, 2, 3, 4], [0, 1, 2, 3, 4, 5], [1, 2, 3, 4, 5, 0], [2, 3, 4, 5, 0, 1]];ACTUAL declared group identity=3

After

ALL [g,e*g,g*e,both_equal_g] rows=[[0, 0, 0, Yes], [1, 1, 1, Yes], [2, 2, 2, Yes], [3, 3, 3, Yes], [4, 4, 4, Yes], [5, 5, 5, Yes]];two-sided group identity=Yes

Conditions: none

Both e*g and g*e in the group table must equal g.This is not certified by an identity-action row on points.

Step identifiers and dependencies

Rule: groupaction_group_identity_both_sides_not_action_identity · Uses: G001, S001

S003 · implies

Before

ORIGINAL group pair(g,h)=[0, 0];check ALL k in Fin(6)

After

ordered [k,(g*h)*k,g*(h*k),equal] rows=[[0, 0, 0, Yes], [1, 1, 1, Yes], [2, 2, 2, Yes], [3, 3, 3, Yes], [4, 4, 4, Yes], [5, 5, 5, Yes]]

Conditions: none

Compute both parenthesizations in the complete original table without assuming cyclicity,commutativity or replacement of multiplication by integer addition.

Step identifiers and dependencies

Rule: groupaction_complete_group_associativity_not_cyclic_assumption · Uses: G001, S002

S004 · implies

Before

ORIGINAL group pair(g,h)=[0, 1];check ALL k in Fin(6)

After

ordered [k,(g*h)*k,g*(h*k),equal] rows=[[0, 1, 1, Yes], [1, 2, 2, Yes], [2, 3, 3, Yes], [3, 4, 4, Yes], [4, 5, 5, Yes], [5, 0, 0, Yes]]

Conditions: none

Compute both parenthesizations in the complete original table without assuming cyclicity,commutativity or replacement of multiplication by integer addition.

Step identifiers and dependencies

Rule: groupaction_complete_group_associativity_not_cyclic_assumption · Uses: G001, S003

S005 · implies

Before

ORIGINAL group pair(g,h)=[0, 2];check ALL k in Fin(6)

After

ordered [k,(g*h)*k,g*(h*k),equal] rows=[[0, 2, 2, Yes], [1, 3, 3, Yes], [2, 4, 4, Yes], [3, 5, 5, Yes], [4, 0, 0, Yes], [5, 1, 1, Yes]]

Conditions: none

Compute both parenthesizations in the complete original table without assuming cyclicity,commutativity or replacement of multiplication by integer addition.

Step identifiers and dependencies

Rule: groupaction_complete_group_associativity_not_cyclic_assumption · Uses: G001, S004

S006 · implies

Before

ORIGINAL group pair(g,h)=[0, 3];check ALL k in Fin(6)

After

ordered [k,(g*h)*k,g*(h*k),equal] rows=[[0, 3, 3, Yes], [1, 4, 4, Yes], [2, 5, 5, Yes], [3, 0, 0, Yes], [4, 1, 1, Yes], [5, 2, 2, Yes]]

Conditions: none

Compute both parenthesizations in the complete original table without assuming cyclicity,commutativity or replacement of multiplication by integer addition.

Step identifiers and dependencies

Rule: groupaction_complete_group_associativity_not_cyclic_assumption · Uses: G001, S005

S007 · implies

Before

ORIGINAL group pair(g,h)=[0, 4];check ALL k in Fin(6)

After

ordered [k,(g*h)*k,g*(h*k),equal] rows=[[0, 4, 4, Yes], [1, 5, 5, Yes], [2, 0, 0, Yes], [3, 1, 1, Yes], [4, 2, 2, Yes], [5, 3, 3, Yes]]

Conditions: none

Compute both parenthesizations in the complete original table without assuming cyclicity,commutativity or replacement of multiplication by integer addition.

Step identifiers and dependencies

Rule: groupaction_complete_group_associativity_not_cyclic_assumption · Uses: G001, S006

S008 · implies

Before

ORIGINAL group pair(g,h)=[0, 5];check ALL k in Fin(6)

After

ordered [k,(g*h)*k,g*(h*k),equal] rows=[[0, 5, 5, Yes], [1, 0, 0, Yes], [2, 1, 1, Yes], [3, 2, 2, Yes], [4, 3, 3, Yes], [5, 4, 4, Yes]]

Conditions: none

Compute both parenthesizations in the complete original table without assuming cyclicity,commutativity or replacement of multiplication by integer addition.

Step identifiers and dependencies

Rule: groupaction_complete_group_associativity_not_cyclic_assumption · Uses: G001, S007

S009 · implies

Before

ORIGINAL group pair(g,h)=[1, 0];check ALL k in Fin(6)

After

ordered [k,(g*h)*k,g*(h*k),equal] rows=[[0, 1, 1, Yes], [1, 2, 2, Yes], [2, 3, 3, Yes], [3, 4, 4, Yes], [4, 5, 5, Yes], [5, 0, 0, Yes]]

Conditions: none

Compute both parenthesizations in the complete original table without assuming cyclicity,commutativity or replacement of multiplication by integer addition.

Step identifiers and dependencies

Rule: groupaction_complete_group_associativity_not_cyclic_assumption · Uses: G001, S008

S010 · implies

Before

ORIGINAL group pair(g,h)=[1, 1];check ALL k in Fin(6)

After

ordered [k,(g*h)*k,g*(h*k),equal] rows=[[0, 2, 2, Yes], [1, 3, 3, Yes], [2, 4, 4, Yes], [3, 5, 5, Yes], [4, 0, 0, Yes], [5, 1, 1, Yes]]

Conditions: none

Compute both parenthesizations in the complete original table without assuming cyclicity,commutativity or replacement of multiplication by integer addition.

Step identifiers and dependencies

Rule: groupaction_complete_group_associativity_not_cyclic_assumption · Uses: G001, S009

S011 · implies

Before

ORIGINAL group pair(g,h)=[1, 2];check ALL k in Fin(6)

After

ordered [k,(g*h)*k,g*(h*k),equal] rows=[[0, 3, 3, Yes], [1, 4, 4, Yes], [2, 5, 5, Yes], [3, 0, 0, Yes], [4, 1, 1, Yes], [5, 2, 2, Yes]]

Conditions: none

Compute both parenthesizations in the complete original table without assuming cyclicity,commutativity or replacement of multiplication by integer addition.

Step identifiers and dependencies

Rule: groupaction_complete_group_associativity_not_cyclic_assumption · Uses: G001, S010

S012 · implies

Before

ORIGINAL group pair(g,h)=[1, 3];check ALL k in Fin(6)

After

ordered [k,(g*h)*k,g*(h*k),equal] rows=[[0, 4, 4, Yes], [1, 5, 5, Yes], [2, 0, 0, Yes], [3, 1, 1, Yes], [4, 2, 2, Yes], [5, 3, 3, Yes]]

Conditions: none

Compute both parenthesizations in the complete original table without assuming cyclicity,commutativity or replacement of multiplication by integer addition.

Step identifiers and dependencies

Rule: groupaction_complete_group_associativity_not_cyclic_assumption · Uses: G001, S011

S013 · implies

Before

ORIGINAL group pair(g,h)=[1, 4];check ALL k in Fin(6)

After

ordered [k,(g*h)*k,g*(h*k),equal] rows=[[0, 5, 5, Yes], [1, 0, 0, Yes], [2, 1, 1, Yes], [3, 2, 2, Yes], [4, 3, 3, Yes], [5, 4, 4, Yes]]

Conditions: none

Compute both parenthesizations in the complete original table without assuming cyclicity,commutativity or replacement of multiplication by integer addition.

Step identifiers and dependencies

Rule: groupaction_complete_group_associativity_not_cyclic_assumption · Uses: G001, S012

S014 · implies

Before

ORIGINAL group pair(g,h)=[1, 5];check ALL k in Fin(6)

After

ordered [k,(g*h)*k,g*(h*k),equal] rows=[[0, 0, 0, Yes], [1, 1, 1, Yes], [2, 2, 2, Yes], [3, 3, 3, Yes], [4, 4, 4, Yes], [5, 5, 5, Yes]]

Conditions: none

Compute both parenthesizations in the complete original table without assuming cyclicity,commutativity or replacement of multiplication by integer addition.

Step identifiers and dependencies

Rule: groupaction_complete_group_associativity_not_cyclic_assumption · Uses: G001, S013

S015 · implies

Before

ORIGINAL group pair(g,h)=[2, 0];check ALL k in Fin(6)

After

ordered [k,(g*h)*k,g*(h*k),equal] rows=[[0, 2, 2, Yes], [1, 3, 3, Yes], [2, 4, 4, Yes], [3, 5, 5, Yes], [4, 0, 0, Yes], [5, 1, 1, Yes]]

Conditions: none

Compute both parenthesizations in the complete original table without assuming cyclicity,commutativity or replacement of multiplication by integer addition.

Step identifiers and dependencies

Rule: groupaction_complete_group_associativity_not_cyclic_assumption · Uses: G001, S014

S016 · implies

Before

ORIGINAL group pair(g,h)=[2, 1];check ALL k in Fin(6)

After

ordered [k,(g*h)*k,g*(h*k),equal] rows=[[0, 3, 3, Yes], [1, 4, 4, Yes], [2, 5, 5, Yes], [3, 0, 0, Yes], [4, 1, 1, Yes], [5, 2, 2, Yes]]

Conditions: none

Compute both parenthesizations in the complete original table without assuming cyclicity,commutativity or replacement of multiplication by integer addition.

Step identifiers and dependencies

Rule: groupaction_complete_group_associativity_not_cyclic_assumption · Uses: G001, S015

S017 · implies

Before

ORIGINAL group pair(g,h)=[2, 2];check ALL k in Fin(6)

After

ordered [k,(g*h)*k,g*(h*k),equal] rows=[[0, 4, 4, Yes], [1, 5, 5, Yes], [2, 0, 0, Yes], [3, 1, 1, Yes], [4, 2, 2, Yes], [5, 3, 3, Yes]]

Conditions: none

Compute both parenthesizations in the complete original table without assuming cyclicity,commutativity or replacement of multiplication by integer addition.

Step identifiers and dependencies

Rule: groupaction_complete_group_associativity_not_cyclic_assumption · Uses: G001, S016

S018 · implies

Before

ORIGINAL group pair(g,h)=[2, 3];check ALL k in Fin(6)

After

ordered [k,(g*h)*k,g*(h*k),equal] rows=[[0, 5, 5, Yes], [1, 0, 0, Yes], [2, 1, 1, Yes], [3, 2, 2, Yes], [4, 3, 3, Yes], [5, 4, 4, Yes]]

Conditions: none

Compute both parenthesizations in the complete original table without assuming cyclicity,commutativity or replacement of multiplication by integer addition.

Step identifiers and dependencies

Rule: groupaction_complete_group_associativity_not_cyclic_assumption · Uses: G001, S017

S019 · implies

Before

ORIGINAL group pair(g,h)=[2, 4];check ALL k in Fin(6)

After

ordered [k,(g*h)*k,g*(h*k),equal] rows=[[0, 0, 0, Yes], [1, 1, 1, Yes], [2, 2, 2, Yes], [3, 3, 3, Yes], [4, 4, 4, Yes], [5, 5, 5, Yes]]

Conditions: none

Compute both parenthesizations in the complete original table without assuming cyclicity,commutativity or replacement of multiplication by integer addition.

Step identifiers and dependencies

Rule: groupaction_complete_group_associativity_not_cyclic_assumption · Uses: G001, S018

S020 · implies

Before

ORIGINAL group pair(g,h)=[2, 5];check ALL k in Fin(6)

After

ordered [k,(g*h)*k,g*(h*k),equal] rows=[[0, 1, 1, Yes], [1, 2, 2, Yes], [2, 3, 3, Yes], [3, 4, 4, Yes], [4, 5, 5, Yes], [5, 0, 0, Yes]]

Conditions: none

Compute both parenthesizations in the complete original table without assuming cyclicity,commutativity or replacement of multiplication by integer addition.

Step identifiers and dependencies

Rule: groupaction_complete_group_associativity_not_cyclic_assumption · Uses: G001, S019

S021 · implies

Before

ORIGINAL group pair(g,h)=[3, 0];check ALL k in Fin(6)

After

ordered [k,(g*h)*k,g*(h*k),equal] rows=[[0, 3, 3, Yes], [1, 4, 4, Yes], [2, 5, 5, Yes], [3, 0, 0, Yes], [4, 1, 1, Yes], [5, 2, 2, Yes]]

Conditions: none

Compute both parenthesizations in the complete original table without assuming cyclicity,commutativity or replacement of multiplication by integer addition.

Step identifiers and dependencies

Rule: groupaction_complete_group_associativity_not_cyclic_assumption · Uses: G001, S020

S022 · implies

Before

ORIGINAL group pair(g,h)=[3, 1];check ALL k in Fin(6)

After

ordered [k,(g*h)*k,g*(h*k),equal] rows=[[0, 4, 4, Yes], [1, 5, 5, Yes], [2, 0, 0, Yes], [3, 1, 1, Yes], [4, 2, 2, Yes], [5, 3, 3, Yes]]

Conditions: none

Compute both parenthesizations in the complete original table without assuming cyclicity,commutativity or replacement of multiplication by integer addition.

Step identifiers and dependencies

Rule: groupaction_complete_group_associativity_not_cyclic_assumption · Uses: G001, S021

S023 · implies

Before

ORIGINAL group pair(g,h)=[3, 2];check ALL k in Fin(6)

After

ordered [k,(g*h)*k,g*(h*k),equal] rows=[[0, 5, 5, Yes], [1, 0, 0, Yes], [2, 1, 1, Yes], [3, 2, 2, Yes], [4, 3, 3, Yes], [5, 4, 4, Yes]]

Conditions: none

Compute both parenthesizations in the complete original table without assuming cyclicity,commutativity or replacement of multiplication by integer addition.

Step identifiers and dependencies

Rule: groupaction_complete_group_associativity_not_cyclic_assumption · Uses: G001, S022

S024 · implies

Before

ORIGINAL group pair(g,h)=[3, 3];check ALL k in Fin(6)

After

ordered [k,(g*h)*k,g*(h*k),equal] rows=[[0, 0, 0, Yes], [1, 1, 1, Yes], [2, 2, 2, Yes], [3, 3, 3, Yes], [4, 4, 4, Yes], [5, 5, 5, Yes]]

Conditions: none

Compute both parenthesizations in the complete original table without assuming cyclicity,commutativity or replacement of multiplication by integer addition.

Step identifiers and dependencies

Rule: groupaction_complete_group_associativity_not_cyclic_assumption · Uses: G001, S023

S025 · implies

Before

ORIGINAL group pair(g,h)=[3, 4];check ALL k in Fin(6)

After

ordered [k,(g*h)*k,g*(h*k),equal] rows=[[0, 1, 1, Yes], [1, 2, 2, Yes], [2, 3, 3, Yes], [3, 4, 4, Yes], [4, 5, 5, Yes], [5, 0, 0, Yes]]

Conditions: none

Compute both parenthesizations in the complete original table without assuming cyclicity,commutativity or replacement of multiplication by integer addition.

Step identifiers and dependencies

Rule: groupaction_complete_group_associativity_not_cyclic_assumption · Uses: G001, S024

S026 · implies

Before

ORIGINAL group pair(g,h)=[3, 5];check ALL k in Fin(6)

After

ordered [k,(g*h)*k,g*(h*k),equal] rows=[[0, 2, 2, Yes], [1, 3, 3, Yes], [2, 4, 4, Yes], [3, 5, 5, Yes], [4, 0, 0, Yes], [5, 1, 1, Yes]]

Conditions: none

Compute both parenthesizations in the complete original table without assuming cyclicity,commutativity or replacement of multiplication by integer addition.

Step identifiers and dependencies

Rule: groupaction_complete_group_associativity_not_cyclic_assumption · Uses: G001, S025

S027 · implies

Before

ORIGINAL group pair(g,h)=[4, 0];check ALL k in Fin(6)

After

ordered [k,(g*h)*k,g*(h*k),equal] rows=[[0, 4, 4, Yes], [1, 5, 5, Yes], [2, 0, 0, Yes], [3, 1, 1, Yes], [4, 2, 2, Yes], [5, 3, 3, Yes]]

Conditions: none

Compute both parenthesizations in the complete original table without assuming cyclicity,commutativity or replacement of multiplication by integer addition.

Step identifiers and dependencies

Rule: groupaction_complete_group_associativity_not_cyclic_assumption · Uses: G001, S026

S028 · implies

Before

ORIGINAL group pair(g,h)=[4, 1];check ALL k in Fin(6)

After

ordered [k,(g*h)*k,g*(h*k),equal] rows=[[0, 5, 5, Yes], [1, 0, 0, Yes], [2, 1, 1, Yes], [3, 2, 2, Yes], [4, 3, 3, Yes], [5, 4, 4, Yes]]

Conditions: none

Compute both parenthesizations in the complete original table without assuming cyclicity,commutativity or replacement of multiplication by integer addition.

Step identifiers and dependencies

Rule: groupaction_complete_group_associativity_not_cyclic_assumption · Uses: G001, S027

S029 · implies

Before

ORIGINAL group pair(g,h)=[4, 2];check ALL k in Fin(6)

After

ordered [k,(g*h)*k,g*(h*k),equal] rows=[[0, 0, 0, Yes], [1, 1, 1, Yes], [2, 2, 2, Yes], [3, 3, 3, Yes], [4, 4, 4, Yes], [5, 5, 5, Yes]]

Conditions: none

Compute both parenthesizations in the complete original table without assuming cyclicity,commutativity or replacement of multiplication by integer addition.

Step identifiers and dependencies

Rule: groupaction_complete_group_associativity_not_cyclic_assumption · Uses: G001, S028

S030 · implies

Before

ORIGINAL group pair(g,h)=[4, 3];check ALL k in Fin(6)

After

ordered [k,(g*h)*k,g*(h*k),equal] rows=[[0, 1, 1, Yes], [1, 2, 2, Yes], [2, 3, 3, Yes], [3, 4, 4, Yes], [4, 5, 5, Yes], [5, 0, 0, Yes]]

Conditions: none

Compute both parenthesizations in the complete original table without assuming cyclicity,commutativity or replacement of multiplication by integer addition.

Step identifiers and dependencies

Rule: groupaction_complete_group_associativity_not_cyclic_assumption · Uses: G001, S029

S031 · implies

Before

ORIGINAL group pair(g,h)=[4, 4];check ALL k in Fin(6)

After

ordered [k,(g*h)*k,g*(h*k),equal] rows=[[0, 2, 2, Yes], [1, 3, 3, Yes], [2, 4, 4, Yes], [3, 5, 5, Yes], [4, 0, 0, Yes], [5, 1, 1, Yes]]

Conditions: none

Compute both parenthesizations in the complete original table without assuming cyclicity,commutativity or replacement of multiplication by integer addition.

Step identifiers and dependencies

Rule: groupaction_complete_group_associativity_not_cyclic_assumption · Uses: G001, S030

S032 · implies

Before

ORIGINAL group pair(g,h)=[4, 5];check ALL k in Fin(6)

After

ordered [k,(g*h)*k,g*(h*k),equal] rows=[[0, 3, 3, Yes], [1, 4, 4, Yes], [2, 5, 5, Yes], [3, 0, 0, Yes], [4, 1, 1, Yes], [5, 2, 2, Yes]]

Conditions: none

Compute both parenthesizations in the complete original table without assuming cyclicity,commutativity or replacement of multiplication by integer addition.

Step identifiers and dependencies

Rule: groupaction_complete_group_associativity_not_cyclic_assumption · Uses: G001, S031

S033 · implies

Before

ORIGINAL group pair(g,h)=[5, 0];check ALL k in Fin(6)

After

ordered [k,(g*h)*k,g*(h*k),equal] rows=[[0, 5, 5, Yes], [1, 0, 0, Yes], [2, 1, 1, Yes], [3, 2, 2, Yes], [4, 3, 3, Yes], [5, 4, 4, Yes]]

Conditions: none

Compute both parenthesizations in the complete original table without assuming cyclicity,commutativity or replacement of multiplication by integer addition.

Step identifiers and dependencies

Rule: groupaction_complete_group_associativity_not_cyclic_assumption · Uses: G001, S032

S034 · implies

Before

ORIGINAL group pair(g,h)=[5, 1];check ALL k in Fin(6)

After

ordered [k,(g*h)*k,g*(h*k),equal] rows=[[0, 0, 0, Yes], [1, 1, 1, Yes], [2, 2, 2, Yes], [3, 3, 3, Yes], [4, 4, 4, Yes], [5, 5, 5, Yes]]

Conditions: none

Compute both parenthesizations in the complete original table without assuming cyclicity,commutativity or replacement of multiplication by integer addition.

Step identifiers and dependencies

Rule: groupaction_complete_group_associativity_not_cyclic_assumption · Uses: G001, S033

S035 · implies

Before

ORIGINAL group pair(g,h)=[5, 2];check ALL k in Fin(6)

After

ordered [k,(g*h)*k,g*(h*k),equal] rows=[[0, 1, 1, Yes], [1, 2, 2, Yes], [2, 3, 3, Yes], [3, 4, 4, Yes], [4, 5, 5, Yes], [5, 0, 0, Yes]]

Conditions: none

Compute both parenthesizations in the complete original table without assuming cyclicity,commutativity or replacement of multiplication by integer addition.

Step identifiers and dependencies

Rule: groupaction_complete_group_associativity_not_cyclic_assumption · Uses: G001, S034

S036 · implies

Before

ORIGINAL group pair(g,h)=[5, 3];check ALL k in Fin(6)

After

ordered [k,(g*h)*k,g*(h*k),equal] rows=[[0, 2, 2, Yes], [1, 3, 3, Yes], [2, 4, 4, Yes], [3, 5, 5, Yes], [4, 0, 0, Yes], [5, 1, 1, Yes]]

Conditions: none

Compute both parenthesizations in the complete original table without assuming cyclicity,commutativity or replacement of multiplication by integer addition.

Step identifiers and dependencies

Rule: groupaction_complete_group_associativity_not_cyclic_assumption · Uses: G001, S035

S037 · implies

Before

ORIGINAL group pair(g,h)=[5, 4];check ALL k in Fin(6)

After

ordered [k,(g*h)*k,g*(h*k),equal] rows=[[0, 3, 3, Yes], [1, 4, 4, Yes], [2, 5, 5, Yes], [3, 0, 0, Yes], [4, 1, 1, Yes], [5, 2, 2, Yes]]

Conditions: none

Compute both parenthesizations in the complete original table without assuming cyclicity,commutativity or replacement of multiplication by integer addition.

Step identifiers and dependencies

Rule: groupaction_complete_group_associativity_not_cyclic_assumption · Uses: G001, S036

S038 · implies

Before

ORIGINAL group pair(g,h)=[5, 5];check ALL k in Fin(6)

After

ordered [k,(g*h)*k,g*(h*k),equal] rows=[[0, 4, 4, Yes], [1, 5, 5, Yes], [2, 0, 0, Yes], [3, 1, 1, Yes], [4, 2, 2, Yes], [5, 3, 3, Yes]]

Conditions: none

Compute both parenthesizations in the complete original table without assuming cyclicity,commutativity or replacement of multiplication by integer addition.

Step identifiers and dependencies

Rule: groupaction_complete_group_associativity_not_cyclic_assumption · Uses: G001, S037

S039 · implies

Before

ORIGINAL group element g=0;DECLARED identity=3;ALL [h,g*h,h*g,two_sided_inverse] rows=[[0, 3, 3, Yes], [1, 4, 4, No], [2, 5, 5, No], [3, 0, 0, No], [4, 1, 1, No], [5, 2, 2, No]]

After

first actual two-sided inverse witness=0;exists=Yes

Conditions: none

For each g,the same h must satisfy both inverse identities.An unqualified candidate table may have no witness;retain None rather than guessing inverses from labels.

Step identifiers and dependencies

Rule: groupaction_each_element_actual_two_sided_inverse · Uses: G001, S038

S040 · implies

Before

ORIGINAL group element g=1;DECLARED identity=3;ALL [h,g*h,h*g,two_sided_inverse] rows=[[0, 4, 4, No], [1, 5, 5, No], [2, 0, 0, No], [3, 1, 1, No], [4, 2, 2, No], [5, 3, 3, Yes]]

After

first actual two-sided inverse witness=5;exists=Yes

Conditions: none

For each g,the same h must satisfy both inverse identities.An unqualified candidate table may have no witness;retain None rather than guessing inverses from labels.

Step identifiers and dependencies

Rule: groupaction_each_element_actual_two_sided_inverse · Uses: G001, S039

S041 · implies

Before

ORIGINAL group element g=2;DECLARED identity=3;ALL [h,g*h,h*g,two_sided_inverse] rows=[[0, 5, 5, No], [1, 0, 0, No], [2, 1, 1, No], [3, 2, 2, No], [4, 3, 3, Yes], [5, 4, 4, No]]

After

first actual two-sided inverse witness=4;exists=Yes

Conditions: none

For each g,the same h must satisfy both inverse identities.An unqualified candidate table may have no witness;retain None rather than guessing inverses from labels.

Step identifiers and dependencies

Rule: groupaction_each_element_actual_two_sided_inverse · Uses: G001, S040

S042 · implies

Before

ORIGINAL group element g=3;DECLARED identity=3;ALL [h,g*h,h*g,two_sided_inverse] rows=[[0, 0, 0, No], [1, 1, 1, No], [2, 2, 2, No], [3, 3, 3, Yes], [4, 4, 4, No], [5, 5, 5, No]]

After

first actual two-sided inverse witness=3;exists=Yes

Conditions: none

For each g,the same h must satisfy both inverse identities.An unqualified candidate table may have no witness;retain None rather than guessing inverses from labels.

Step identifiers and dependencies

Rule: groupaction_each_element_actual_two_sided_inverse · Uses: G001, S041

S043 · implies

Before

ORIGINAL group element g=4;DECLARED identity=3;ALL [h,g*h,h*g,two_sided_inverse] rows=[[0, 1, 1, No], [1, 2, 2, No], [2, 3, 3, Yes], [3, 4, 4, No], [4, 5, 5, No], [5, 0, 0, No]]

After

first actual two-sided inverse witness=2;exists=Yes

Conditions: none

For each g,the same h must satisfy both inverse identities.An unqualified candidate table may have no witness;retain None rather than guessing inverses from labels.

Step identifiers and dependencies

Rule: groupaction_each_element_actual_two_sided_inverse · Uses: G001, S042

S044 · implies

Before

ORIGINAL group element g=5;DECLARED identity=3;ALL [h,g*h,h*g,two_sided_inverse] rows=[[0, 2, 2, No], [1, 3, 3, Yes], [2, 4, 4, No], [3, 5, 5, No], [4, 0, 0, No], [5, 1, 1, No]]

After

first actual two-sided inverse witness=1;exists=Yes

Conditions: none

For each g,the same h must satisfy both inverse identities.An unqualified candidate table may have no witness;retain None rather than guessing inverses from labels.

Step identifiers and dependencies

Rule: groupaction_each_element_actual_two_sided_inverse · Uses: G001, S043

S045 · implies

Before

structurally closed COMPLETE group candidate;two-sided identity=Yes;ALL-triple associativity=Yes;ALL-element inverses=Yes

After

group_valid=Yes is the CONJUNCTION;False remains a reported candidate result,not a silent repair

Conditions: none

Group qualification is the conjunction of these complete obligations.A permutation-looking action table cannot repair a bad group table;do not replace the identity or modify the table.

Step identifiers and dependencies

Rule: groupaction_group_axiom_conjunction_candidate_may_fail · Uses: G001, S044

S046 · implies

Before

CURRENT ORIGINAL complete Cayley table=[[3, 4, 5, 0, 1, 2], [4, 5, 0, 1, 2, 3], [5, 0, 1, 2, 3, 4], [0, 1, 2, 3, 4, 5], [1, 2, 3, 4, 5, 0], [2, 3, 4, 5, 0, 1]];actual identity=3;order=6

After

ALL group axioms qualified;actual inverse list=[0, 5, 4, 3, 2, 1];no point carrier or group-action assumption is used

Conditions: none

Certify closure,identity,associativity and two-sided inverses in the group table itself.Do not import an old8-element action-table limit or assume cyclicity/commutativity.The frozen pure helper receives only this question's table and trace.

Step identifiers and dependencies

Rule: group_CURRENT_complete_certified_Cayley_NOT_action_wrapper · Uses: G001, S045

S047 · implies

Before

ORIGINAL subset=[1, 3, 5];actual group identity=3

After

contains_identity=Yes;ALL [g,h,product,in_candidate] rows=[[1, 1, 5, Yes], [1, 3, 1, Yes], [1, 5, 3, Yes], [3, 1, 1, Yes], [3, 3, 3, Yes], [3, 5, 5, Yes], [5, 1, 3, Yes], [5, 3, 5, Yes], [5, 5, 1, Yes]];ALL [g,inverse,in_candidate] rows=[[1, 5, Yes], [3, 3, Yes], [5, 1, Yes]];product_closed=Yes,inverse_closed=Yes,subgroup=Yes

Conditions: none

A complete candidate may fail.Identity,product and inverse closure must all hold;divisor-sized cardinality replaces none of them.

Step identifiers and dependencies

Rule: lagrange_candidate_ALL_subgroup_obligations_not_size · Uses: G001, S046

S048 · implies

Before

ORIGINAL group representative g=0;SAME subgroup H=[1, 3, 5];inverse of g=0

After

ALL [h,g*h] rows=[[1, 4], [3, 0], [5, 2]];LEFT coset=[0, 2, 4];ALL [g*h,g_inverse*(g*h)] reverse rows=[[0, 3], [2, 5], [4, 1]];least representative for this distinct set=0

Conditions: none

Left translation h->g*h and u->g_inverse*u are inverse maps,so every left coset has H's size.Keep the first original g as its representative;do not substitute a right coset or another equally sized set.

Step identifiers and dependencies

Rule: lagrange_EVERY_actual_LEFT_translation_two_way_bijection · Uses: G001, S047

S049 · implies

Before

ORIGINAL group representative g=1;SAME subgroup H=[1, 3, 5];inverse of g=5

After

ALL [h,g*h] rows=[[1, 5], [3, 1], [5, 3]];LEFT coset=[1, 3, 5];ALL [g*h,g_inverse*(g*h)] reverse rows=[[1, 3], [3, 5], [5, 1]];least representative for this distinct set=1

Conditions: none

Left translation h->g*h and u->g_inverse*u are inverse maps,so every left coset has H's size.Keep the first original g as its representative;do not substitute a right coset or another equally sized set.

Step identifiers and dependencies

Rule: lagrange_EVERY_actual_LEFT_translation_two_way_bijection · Uses: G001, S048

S050 · implies

Before

ORIGINAL group representative g=2;SAME subgroup H=[1, 3, 5];inverse of g=4

After

ALL [h,g*h] rows=[[1, 0], [3, 2], [5, 4]];LEFT coset=[0, 2, 4];ALL [g*h,g_inverse*(g*h)] reverse rows=[[0, 1], [2, 3], [4, 5]];least representative for this distinct set=0

Conditions: none

Left translation h->g*h and u->g_inverse*u are inverse maps,so every left coset has H's size.Keep the first original g as its representative;do not substitute a right coset or another equally sized set.

Step identifiers and dependencies

Rule: lagrange_EVERY_actual_LEFT_translation_two_way_bijection · Uses: G001, S049

S051 · implies

Before

ORIGINAL group representative g=3;SAME subgroup H=[1, 3, 5];inverse of g=3

After

ALL [h,g*h] rows=[[1, 1], [3, 3], [5, 5]];LEFT coset=[1, 3, 5];ALL [g*h,g_inverse*(g*h)] reverse rows=[[1, 1], [3, 3], [5, 5]];least representative for this distinct set=1

Conditions: none

Left translation h->g*h and u->g_inverse*u are inverse maps,so every left coset has H's size.Keep the first original g as its representative;do not substitute a right coset or another equally sized set.

Step identifiers and dependencies

Rule: lagrange_EVERY_actual_LEFT_translation_two_way_bijection · Uses: G001, S050

S052 · implies

Before

ORIGINAL group representative g=4;SAME subgroup H=[1, 3, 5];inverse of g=2

After

ALL [h,g*h] rows=[[1, 2], [3, 4], [5, 0]];LEFT coset=[0, 2, 4];ALL [g*h,g_inverse*(g*h)] reverse rows=[[0, 5], [2, 1], [4, 3]];least representative for this distinct set=0

Conditions: none

Left translation h->g*h and u->g_inverse*u are inverse maps,so every left coset has H's size.Keep the first original g as its representative;do not substitute a right coset or another equally sized set.

Step identifiers and dependencies

Rule: lagrange_EVERY_actual_LEFT_translation_two_way_bijection · Uses: G001, S051

S053 · implies

Before

ORIGINAL group representative g=5;SAME subgroup H=[1, 3, 5];inverse of g=1

After

ALL [h,g*h] rows=[[1, 3], [3, 5], [5, 1]];LEFT coset=[1, 3, 5];ALL [g*h,g_inverse*(g*h)] reverse rows=[[1, 5], [3, 1], [5, 3]];least representative for this distinct set=1

Conditions: none

Left translation h->g*h and u->g_inverse*u are inverse maps,so every left coset has H's size.Keep the first original g as its representative;do not substitute a right coset or another equally sized set.

Step identifiers and dependencies

Rule: lagrange_EVERY_actual_LEFT_translation_two_way_bijection · Uses: G001, S052

S054 · implies

Before

ALL distinct LEFT cosets sorted by SOURCE English element-list order=[[0, [0, 2, 4]], [1, [1, 3, 5]]]

After

every size=3;flattened elements=[0, 1, 2, 3, 4, 5];partition covers ORIGINAL group exactly once=Yes

Conditions: none

If gh=kh1,then k_inverse*g=h1*h_inverse lies in H and the two cosets contain each other;otherwise they are disjoint.The identity puts each g in gH,so they cover G.Sort only by the coset element list,not the representative field.

Step identifiers and dependencies

Rule: lagrange_LEFT_cosets_equal_or_disjoint_cover_with_source_order · Uses: G001, S053

Reverse checks

  • S054 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
  • S053 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
  • S052 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
  • S051 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
  • S050 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
  • S049 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
  • S048 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
  • S047 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
  • S046 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
  • S045 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
  • S044 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
  • S043 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
  • S042 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
  • S041 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
  • S040 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
  • S039 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
  • S038 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
  • S037 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
  • S036 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
  • S035 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
  • S034 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
  • S033 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
  • S032 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
  • S031 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
  • S030 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
  • S029 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
  • S028 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
  • S027 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
  • S026 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
  • S025 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
  • S024 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
  • S023 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
  • S022 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
  • S021 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
  • S020 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
  • S019 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
  • S018 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
  • S017 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
  • S016 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
  • S015 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
  • S014 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
  • S013 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
  • S012 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
  • S011 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
  • S010 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
  • S009 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
  • S008 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
  • S007 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
  • S006 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
  • S005 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
  • S004 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
  • S003 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
  • S002 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
  • S001 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.

Result

([[0, [0, 2, 4]], [1, [1, 3, 5]]], Yes, [0, 1, 2, 3, 4, 5], Yes, left_cosets_equal_or_disjoint_and_cover_G)

The full substitutions and premise checks give the original answer; source identity,format and status are unchanged.

This question review and source binding

Review date: 2026-10-26

Original questions, answers, step expressions, numeric ASTs and historical records are retained. Source candidate labels remain historical and are not overwritten as formal proof.

Source hashes and review receipts
  • input commit: 0f7be61e2c22317a4075561dc822c87d881a50db
  • original question SHA-256: cee17421d7f29ebad68cca195ca2779826483c30768cb6eb5daa91244c8eebbb
  • candidate record SHA-256: d21e034b7dd9a1908b97471e1d0de418035c38d01aefa7e39d944c17f5559e2b
  • semantic review receipt SHA-256: 357d7ad7a6726b2a757558d3b9586a408ade06526cc023da093719c292704438
  • question-first witness SHA-256: 99cefe17e98c7a74321801cf72df6d02fc95b6a6b78aa335accb7e11ed467b2a
  • Lean: NOT_RUN · human review: NOT_PERFORMED
Same-source full JSON