Question 24075: A Declared Shifted Polynomial Reconstructs Exactly from Its Finite Jet

Original question and givens

Use shifted_coefficients=[25, 50, 75] of the explicit polynomial sum c_k*(x−a)^k, center a=12, evaluation point=14. Give (shifted_coefficients, derivatives_at_center, reconstructed_coefficients, point, original_value, reconstructed_value, equal, certificate).

• G001 — Use shifted_coefficients=[25, 50, 75] of the explicit polynomial sum c_k*(x−a)^k, center a=12, evaluation point=14. Give (shifted_coefficients, derivatives_at_center, reconstructed_coefficients, point, original_value, reconstructed_value, equal, certificate).

Definition and scope

Use the original question domain, assumptions and cited MKO definitions. This item has second-context mathematical and bilingual review, with the model, answer and every arithmetic step independently recomputed from the original parameters; the source question remains a candidate.

• mko-taylor-polynomial

Step-by-step derivation

source roles = [taylor-exact-polynomial-reconstruction]

derived = [[shifted_coefficients, derivatives_at_center, reconstructed_coefficients, point, original_value, reconstructed_value, equal, certificate]]

source roles = [12, [25, 50, 75]]

derived = [P(x)=sum c_k*(x-center)^k, 2]

source roles = [0]

derived = [1]

Taylor derivative0 from shifted coefficient := mul(25, 1)

Taylor derivative0 from shifted coefficient = 25

Taylor recover coefficient0 := div(25, 1)

Taylor recover coefficient0 = 25

Taylor k1 factorial step1 := mul(1, 1)

Taylor k1 factorial step1 = 1

Taylor derivative1 from shifted coefficient := mul(50, 1)

Taylor derivative1 from shifted coefficient = 50

Taylor recover coefficient1 := div(50, 1)

Taylor recover coefficient1 = 50

Taylor k2 factorial step1 := mul(1, 1)

Taylor k2 factorial step1 = 1

Taylor k2 factorial step2 := mul(1, 2)

Taylor k2 factorial step2 = 2

Taylor derivative2 from shifted coefficient := mul(75, 2)

Taylor derivative2 from shifted coefficient = 150

Taylor recover coefficient2 := div(150, 2)

Taylor recover coefficient2 = 75

Taylor SAME point minus declared center := sub(14, 12)

Taylor SAME point minus declared center = 2

Taylor original Horner product2 := mul(0, 2)

Taylor original Horner product2 = 0

Taylor original Horner sum2 := sum(0, 75)

Taylor original Horner sum2 = 75

Taylor original Horner product1 := mul(75, 2)

Taylor original Horner product1 = 150

Taylor original Horner sum1 := sum(150, 50)

Taylor original Horner sum1 = 200

Taylor original Horner product0 := mul(200, 2)

Taylor original Horner product0 = 400

Taylor original Horner sum0 := sum(400, 25)

Taylor original Horner sum0 = 425

Taylor reconstructed Horner product2 := mul(0, 2)

Taylor reconstructed Horner product2 = 0

Taylor reconstructed Horner sum2 := sum(0, 75)

Taylor reconstructed Horner sum2 = 75

Taylor reconstructed Horner product1 := mul(75, 2)

Taylor reconstructed Horner product1 = 150

Taylor reconstructed Horner sum1 := sum(150, 50)

Taylor reconstructed Horner sum1 = 200

Taylor reconstructed Horner product0 := mul(200, 2)

Taylor reconstructed Horner product0 = 400

Taylor reconstructed Horner sum0 := sum(400, 25)

Taylor reconstructed Horner sum0 = 425

source roles = [[25, 50, 75], [25, 50, 75], 12, 14]

derived = [Yes, 425, 425, Yes]

Reverse checks

• S026 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
• S025 · premise_and_result_audit — Recompute Taylor reconstructed Horner sum0 with exact rational arithmetic, not rounded decimals.
• S024 · premise_and_result_audit — Recompute Taylor reconstructed Horner product0 with exact rational arithmetic, not rounded decimals.
• S023 · premise_and_result_audit — Recompute Taylor reconstructed Horner sum1 with exact rational arithmetic, not rounded decimals.
• S022 · premise_and_result_audit — Recompute Taylor reconstructed Horner product1 with exact rational arithmetic, not rounded decimals.
• S021 · premise_and_result_audit — Recompute Taylor reconstructed Horner sum2 with exact rational arithmetic, not rounded decimals.
• S020 · premise_and_result_audit — Recompute Taylor reconstructed Horner product2 with exact rational arithmetic, not rounded decimals.
• S019 · premise_and_result_audit — Recompute Taylor original Horner sum0 with exact rational arithmetic, not rounded decimals.
• S018 · premise_and_result_audit — Recompute Taylor original Horner product0 with exact rational arithmetic, not rounded decimals.
• S017 · premise_and_result_audit — Recompute Taylor original Horner sum1 with exact rational arithmetic, not rounded decimals.
• S016 · premise_and_result_audit — Recompute Taylor original Horner product1 with exact rational arithmetic, not rounded decimals.
• S015 · premise_and_result_audit — Recompute Taylor original Horner sum2 with exact rational arithmetic, not rounded decimals.
• S014 · premise_and_result_audit — Recompute Taylor original Horner product2 with exact rational arithmetic, not rounded decimals.
• S013 · premise_and_result_audit — Recompute Taylor SAME point minus declared center with exact rational arithmetic, not rounded decimals.
• S012 · premise_and_result_audit — Recompute Taylor recover coefficient2 with exact rational arithmetic, not rounded decimals.
• S011 · premise_and_result_audit — Recompute Taylor derivative2 from shifted coefficient with exact rational arithmetic, not rounded decimals.
• S010 · premise_and_result_audit — Recompute Taylor k2 factorial step2 with exact rational arithmetic, not rounded decimals.
• S009 · premise_and_result_audit — Recompute Taylor k2 factorial step1 with exact rational arithmetic, not rounded decimals.
• S008 · premise_and_result_audit — Recompute Taylor recover coefficient1 with exact rational arithmetic, not rounded decimals.
• S007 · premise_and_result_audit — Recompute Taylor derivative1 from shifted coefficient with exact rational arithmetic, not rounded decimals.
• S006 · premise_and_result_audit — Recompute Taylor k1 factorial step1 with exact rational arithmetic, not rounded decimals.
• S005 · premise_and_result_audit — Recompute Taylor recover coefficient0 with exact rational arithmetic, not rounded decimals.
• S004 · premise_and_result_audit — Recompute Taylor derivative0 from shifted coefficient with exact rational arithmetic, not rounded decimals.
• S003 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
• S002 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
• S001 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.

Result

([25, 50, 75], [25, 50, 150], [25, 50, 75], 14, 425, 425, Yes, degree_at_most_n_polynomial_is_exactly_reconstructed)

The full substitutions and premise checks give the original answer; source identity,format and status are unchanged.

This question review and source binding

Review date: 2026-10-26

Original questions, answers, step expressions, numeric ASTs and historical records are retained. Source candidate labels remain historical and are not overwritten as formal proof.