Original question and givens
Use complete finite Cayley table=[[9, 0, 1, 2, 3, 4, 5, 6, 7, 8], [0, 1, 2, 3, 4, 5, 6, 7, 8, 9], [1, 2, 3, 4, 5, 6, 7, 8, 9, 0], [2, 3, 4, 5, 6, 7, 8, 9, 0, 1], [3, 4, 5, 6, 7, 8, 9, 0, 1, 2], [4, 5, 6, 7, 8, 9, 0, 1, 2, 3], [5, 6, 7, 8, 9, 0, 1, 2, 3, 4], [6, 7, 8, 9, 0, 1, 2, 3, 4, 5], [7, 8, 9, 0, 1, 2, 3, 4, 5, 6], [8, 9, 0, 1, 2, 3, 4, 5, 6, 7]], identity=1 and candidate subset H=[1, 6]. Row g/column h gives g*h. Validate all group axioms, then identity/product/inverse closure of the whole subset before treating it as a subgroup. Normality has a separate all-g obligation. Give (subset, contains_identity, product_closed, inverse_closed, subgroup, normal_subgroup, certificate).
G001 — Use complete finite Cayley table=[[9, 0, 1, 2, 3, 4, 5, 6, 7, 8], [0, 1, 2, 3, 4, 5, 6, 7, 8, 9], [1, 2, 3, 4, 5, 6, 7, 8, 9, 0], [2, 3, 4, 5, 6, 7, 8, 9, 0, 1], [3, 4, 5, 6, 7, 8, 9, 0, 1, 2], [4, 5, 6, 7, 8, 9, 0, 1, 2, 3], [5, 6, 7, 8, 9, 0, 1, 2, 3, 4], [6, 7, 8, 9, 0, 1, 2, 3, 4, 5], [7, 8, 9, 0, 1, 2, 3, 4, 5, 6], [8, 9, 0, 1, 2, 3, 4, 5, 6, 7]], identity=1 and candidate subset H=[1, 6]. Row g/column h gives g*h. Validate all group axioms, then identity/product/inverse closure of the whole subset before treating it as a subgroup. Normality has a separate all-g obligation. Give (subset, contains_identity, product_closed, inverse_closed, subgroup, normal_subgroup, certificate).
Step-by-step derivation
S001 · implies
Before
source roles = [normal-subgroup-qualification]
After
derived = [[subset, contains_identity, product_closed, inverse_closed, subgroup, normal_subgroup, certificate]]
Conditions: none
List the full source field order without JavaScript,keeping original data,Boolean flags,mathematical objects and nonclaims distinct.
Step identifiers and dependencies
Rule: source_ordered_fields_without_JS · Uses: G001
S002 · implies
Before
source roles = [Normality ORIGINAL group, 32, [[9, 0, 1, 2, 3, 4, 5, 6, 7, 8], [0, 1, 2, 3, 4, 5, 6, 7, 8, 9], [1, 2, 3, 4, 5, 6, 7, 8, 9, 0], [2, 3, 4, 5, 6, 7, 8, 9, 0, 1], [3, 4, 5, 6, 7, 8, 9, 0, 1, 2], [4, 5, 6, 7, 8, 9, 0, 1, 2, 3], [5, 6, 7, 8, 9, 0, 1, 2, 3, 4], [6, 7, 8, 9, 0, 1, 2, 3, 4, 5], [7, 8, 9, 0, 1, 2, 3, 4, 5, 6], [8, 9, 0, 1, 2, 3, 4, 5, 6, 7]], 1]
After
derived = [10, [[0, 0, 0, 0], [1, 1, 1, 1], [2, 2, 2, 2], [3, 3, 3, 3], [4, 4, 4, 4], [5, 5, 5, 5], [6, 6, 6, 6], [7, 7, 7, 7], [8, 8, 8, 8], [9, 9, 9, 9]], Yes]
Conditions: none
Validate the complete closed n-by-n table and actual identity label,not an assumed0.Mod44 allows32 and mod45 allows64;do not mix carriers or tables.
Step identifiers and dependencies
Rule: Group_complete_Cayley_signature_actual_identity · Uses: G001, S001
S003 · implies
Before
source roles = [Normality ORIGINAL group, 10, FOR EVERY x,y,z in0..n-1]
After
derived = [[[Yes, Yes, Yes, Yes, Yes, Yes, Yes, Yes, Yes, Yes], [Yes, Yes, Yes, Yes, Yes, Yes, Yes, Yes, Yes, Yes], [Yes, Yes, Yes, Yes, Yes, Yes, Yes, Yes, Yes, Yes], [Yes, Yes, Yes, Yes, Yes, Yes, Yes, Yes, Yes, Yes], [Yes, Yes, Yes, Yes, Yes, Yes, Yes, Yes, Yes, Yes], [Yes, Yes, Yes, Yes, Yes, Yes, Yes, Yes, Yes, Yes], [Yes, Yes, Yes, Yes, Yes, Yes, Yes, Yes, Yes, Yes], [Yes, Yes, Yes, Yes, Yes, Yes, Yes, Yes, Yes, Yes], [Yes, Yes, Yes, Yes, Yes, Yes, Yes, Yes, Yes, Yes], [Yes, Yes, Yes, Yes, Yes, Yes, Yes, Yes, Yes, Yes]], 1000, Yes]
Conditions: none
Entry(x,y) checks (xy)z=x(yz) for every z,covering all n^3 triples,not samples.The complete table is already displayed,so do not print millions of redundant lookups.
Step identifiers and dependencies
Rule: Group_ALL_associativity_triples_compact_complete_pair_matrix · Uses: G001, S002
S004 · implies
Before
source roles = [Normality ORIGINAL group, 1]
After
derived = [[2, 1, 0, 9, 8, 7, 6, 5, 4, 3], [[0, 2, 1, 1], [1, 1, 1, 1], [2, 0, 1, 1], [3, 9, 1, 1], [4, 8, 1, 1], [5, 7, 1, 1], [6, 6, 1, 1], [7, 5, 1, 1], [8, 4, 1, 1], [9, 3, 1, 1]], Yes]
Conditions: none
Every left and right inverse must return the same actual identity;associativity gives uniqueness.This completes the group premises.
Step identifiers and dependencies
Rule: Group_ALL_two_sided_inverses · Uses: G001, S003
S005 · implies
Before
source roles = [Normality ORIGINAL H, [1, 6], 1]
After
derived = [Yes, [[1, 1, 1, Yes], [1, 6, 6, Yes], [6, 1, 6, Yes], [6, 6, 1, Yes]], Yes, [[1, 1, Yes], [6, 6, Yes]], Yes, Yes]
Conditions: none
H is nonempty and unique.Check identity membership,all products and every inverse separately;their conjunction qualifies a subgroup.Size divisibility or finiteness alone is insufficient.
Step identifiers and dependencies
Rule: Subgroup_identity_ALL_products_ALL_inverses_separate · Uses: G001, S004
S006 · implies
Before
source roles = [Normality ORIGINAL H, 0, [1, 6], 2]
After
derived = [[[1, 0, 2, 1], [6, 5, 2, 6]], [1, 6], Yes]
Conditions: none
In the same table compute g*h then multiply by g inverse for every h.Check set equality for every g,not sampled elements or unproved generators.
Step identifiers and dependencies
Rule: Subgroup_EVERY_g_entire_conjugate_set · Uses: G001, S005
S007 · implies
Before
source roles = [Normality ORIGINAL H, 1, [1, 6], 1]
After
derived = [[[1, 1, 1, 1], [6, 6, 1, 6]], [1, 6], Yes]
Conditions: none
In the same table compute g*h then multiply by g inverse for every h.Check set equality for every g,not sampled elements or unproved generators.
Step identifiers and dependencies
Rule: Subgroup_EVERY_g_entire_conjugate_set · Uses: G001, S006
S008 · implies
Before
source roles = [Normality ORIGINAL H, 2, [1, 6], 0]
After
derived = [[[1, 2, 0, 1], [6, 7, 0, 6]], [1, 6], Yes]
Conditions: none
In the same table compute g*h then multiply by g inverse for every h.Check set equality for every g,not sampled elements or unproved generators.
Step identifiers and dependencies
Rule: Subgroup_EVERY_g_entire_conjugate_set · Uses: G001, S007
S009 · implies
Before
source roles = [Normality ORIGINAL H, 3, [1, 6], 9]
After
derived = [[[1, 3, 9, 1], [6, 8, 9, 6]], [1, 6], Yes]
Conditions: none
In the same table compute g*h then multiply by g inverse for every h.Check set equality for every g,not sampled elements or unproved generators.
Step identifiers and dependencies
Rule: Subgroup_EVERY_g_entire_conjugate_set · Uses: G001, S008
S010 · implies
Before
source roles = [Normality ORIGINAL H, 4, [1, 6], 8]
After
derived = [[[1, 4, 8, 1], [6, 9, 8, 6]], [1, 6], Yes]
Conditions: none
In the same table compute g*h then multiply by g inverse for every h.Check set equality for every g,not sampled elements or unproved generators.
Step identifiers and dependencies
Rule: Subgroup_EVERY_g_entire_conjugate_set · Uses: G001, S009
S011 · implies
Before
source roles = [Normality ORIGINAL H, 5, [1, 6], 7]
After
derived = [[[1, 5, 7, 1], [6, 0, 7, 6]], [1, 6], Yes]
Conditions: none
In the same table compute g*h then multiply by g inverse for every h.Check set equality for every g,not sampled elements or unproved generators.
Step identifiers and dependencies
Rule: Subgroup_EVERY_g_entire_conjugate_set · Uses: G001, S010
S012 · implies
Before
source roles = [Normality ORIGINAL H, 6, [1, 6], 6]
After
derived = [[[1, 6, 6, 1], [6, 1, 6, 6]], [1, 6], Yes]
Conditions: none
In the same table compute g*h then multiply by g inverse for every h.Check set equality for every g,not sampled elements or unproved generators.
Step identifiers and dependencies
Rule: Subgroup_EVERY_g_entire_conjugate_set · Uses: G001, S011
S013 · implies
Before
source roles = [Normality ORIGINAL H, 7, [1, 6], 5]
After
derived = [[[1, 7, 5, 1], [6, 2, 5, 6]], [1, 6], Yes]
Conditions: none
In the same table compute g*h then multiply by g inverse for every h.Check set equality for every g,not sampled elements or unproved generators.
Step identifiers and dependencies
Rule: Subgroup_EVERY_g_entire_conjugate_set · Uses: G001, S012
S014 · implies
Before
source roles = [Normality ORIGINAL H, 8, [1, 6], 4]
After
derived = [[[1, 8, 4, 1], [6, 3, 4, 6]], [1, 6], Yes]
Conditions: none
In the same table compute g*h then multiply by g inverse for every h.Check set equality for every g,not sampled elements or unproved generators.
Step identifiers and dependencies
Rule: Subgroup_EVERY_g_entire_conjugate_set · Uses: G001, S013
S015 · implies
Before
source roles = [Normality ORIGINAL H, 9, [1, 6], 3]
After
derived = [[[1, 9, 3, 1], [6, 4, 3, 6]], [1, 6], Yes]
Conditions: none
In the same table compute g*h then multiply by g inverse for every h.Check set equality for every g,not sampled elements or unproved generators.
Step identifiers and dependencies
Rule: Subgroup_EVERY_g_entire_conjugate_set · Uses: G001, S014