Step-by-step derivation
S001 · implies
Before
source roles = [normal-left-right-coset-audit]
After
derived = [[subgroup, coset_rows, all_left_right_equal, certificate]]
Conditions: none
List the full source field order without JavaScript,keeping original data,Boolean flags,mathematical objects and nonclaims distinct.
Step identifiers and dependencies
Rule: source_ordered_fields_without_JS · Uses: G001
S002 · implies
Before
source roles = [Normality ORIGINAL group, 32, [[2, 3, 4, 5, 0, 1], [3, 4, 5, 0, 1, 2], [4, 5, 0, 1, 2, 3], [5, 0, 1, 2, 3, 4], [0, 1, 2, 3, 4, 5], [1, 2, 3, 4, 5, 0]], 4]
After
derived = [6, [[0, 0, 0, 0], [1, 1, 1, 1], [2, 2, 2, 2], [3, 3, 3, 3], [4, 4, 4, 4], [5, 5, 5, 5]], Yes]
Conditions: none
Validate the complete closed n-by-n table and actual identity label,not an assumed0.Mod44 allows32 and mod45 allows64;do not mix carriers or tables.
Step identifiers and dependencies
Rule: Group_complete_Cayley_signature_actual_identity · Uses: G001, S001
S003 · implies
Before
source roles = [Normality ORIGINAL group, 6, FOR EVERY x,y,z in0..n-1]
After
derived = [[[Yes, Yes, Yes, Yes, Yes, Yes], [Yes, Yes, Yes, Yes, Yes, Yes], [Yes, Yes, Yes, Yes, Yes, Yes], [Yes, Yes, Yes, Yes, Yes, Yes], [Yes, Yes, Yes, Yes, Yes, Yes], [Yes, Yes, Yes, Yes, Yes, Yes]], 216, Yes]
Conditions: none
Entry(x,y) checks (xy)z=x(yz) for every z,covering all n^3 triples,not samples.The complete table is already displayed,so do not print millions of redundant lookups.
Step identifiers and dependencies
Rule: Group_ALL_associativity_triples_compact_complete_pair_matrix · Uses: G001, S002
S004 · implies
Before
source roles = [Normality ORIGINAL group, 4]
After
derived = [[2, 1, 0, 5, 4, 3], [[0, 2, 4, 4], [1, 1, 4, 4], [2, 0, 4, 4], [3, 5, 4, 4], [4, 4, 4, 4], [5, 3, 4, 4]], Yes]
Conditions: none
Every left and right inverse must return the same actual identity;associativity gives uniqueness.This completes the group premises.
Step identifiers and dependencies
Rule: Group_ALL_two_sided_inverses · Uses: G001, S003
S005 · implies
Before
source roles = [Normality ORIGINAL H, [0, 1, 2, 3, 4, 5], 4]
After
derived = [Yes, [[0, 0, 2, Yes], [0, 1, 3, Yes], [0, 2, 4, Yes], [0, 3, 5, Yes], [0, 4, 0, Yes], [0, 5, 1, Yes], [1, 0, 3, Yes], [1, 1, 4, Yes], [1, 2, 5, Yes], [1, 3, 0, Yes], [1, 4, 1, Yes], [1, 5, 2, Yes], [2, 0, 4, Yes], [2, 1, 5, Yes], [2, 2, 0, Yes], [2, 3, 1, Yes], [2, 4, 2, Yes], [2, 5, 3, Yes], [3, 0, 5, Yes], [3, 1, 0, Yes], [3, 2, 1, Yes], [3, 3, 2, Yes], [3, 4, 3, Yes], [3, 5, 4, Yes], [4, 0, 0, Yes], [4, 1, 1, Yes], [4, 2, 2, Yes], [4, 3, 3, Yes], [4, 4, 4, Yes], [4, 5, 5, Yes], [5, 0, 1, Yes], [5, 1, 2, Yes], [5, 2, 3, Yes], [5, 3, 4, Yes], [5, 4, 5, Yes], [5, 5, 0, Yes]], Yes, [[0, 2, Yes], [1, 1, Yes], [2, 0, Yes], [3, 5, Yes], [4, 4, Yes], [5, 3, Yes]], Yes, Yes]
Conditions: none
H is nonempty and unique.Check identity membership,all products and every inverse separately;their conjunction qualifies a subgroup.Size divisibility or finiteness alone is insufficient.
Step identifiers and dependencies
Rule: Subgroup_identity_ALL_products_ALL_inverses_separate · Uses: G001, S004
S006 · implies
Before
source roles = [Normality ORIGINAL H, 0, [0, 1, 2, 3, 4, 5], 2]
After
derived = [[[0, 2, 2, 0], [1, 3, 2, 1], [2, 4, 2, 2], [3, 5, 2, 3], [4, 0, 2, 4], [5, 1, 2, 5]], [0, 1, 2, 3, 4, 5], Yes]
Conditions: none
In the same table compute g*h then multiply by g inverse for every h.Check set equality for every g,not sampled elements or unproved generators.
Step identifiers and dependencies
Rule: Subgroup_EVERY_g_entire_conjugate_set · Uses: G001, S005
S007 · implies
Before
source roles = [Normality ORIGINAL H, 1, [0, 1, 2, 3, 4, 5], 1]
After
derived = [[[0, 3, 1, 0], [1, 4, 1, 1], [2, 5, 1, 2], [3, 0, 1, 3], [4, 1, 1, 4], [5, 2, 1, 5]], [0, 1, 2, 3, 4, 5], Yes]
Conditions: none
In the same table compute g*h then multiply by g inverse for every h.Check set equality for every g,not sampled elements or unproved generators.
Step identifiers and dependencies
Rule: Subgroup_EVERY_g_entire_conjugate_set · Uses: G001, S006
S008 · implies
Before
source roles = [Normality ORIGINAL H, 2, [0, 1, 2, 3, 4, 5], 0]
After
derived = [[[0, 4, 0, 0], [1, 5, 0, 1], [2, 0, 0, 2], [3, 1, 0, 3], [4, 2, 0, 4], [5, 3, 0, 5]], [0, 1, 2, 3, 4, 5], Yes]
Conditions: none
In the same table compute g*h then multiply by g inverse for every h.Check set equality for every g,not sampled elements or unproved generators.
Step identifiers and dependencies
Rule: Subgroup_EVERY_g_entire_conjugate_set · Uses: G001, S007
S009 · implies
Before
source roles = [Normality ORIGINAL H, 3, [0, 1, 2, 3, 4, 5], 5]
After
derived = [[[0, 5, 5, 0], [1, 0, 5, 1], [2, 1, 5, 2], [3, 2, 5, 3], [4, 3, 5, 4], [5, 4, 5, 5]], [0, 1, 2, 3, 4, 5], Yes]
Conditions: none
In the same table compute g*h then multiply by g inverse for every h.Check set equality for every g,not sampled elements or unproved generators.
Step identifiers and dependencies
Rule: Subgroup_EVERY_g_entire_conjugate_set · Uses: G001, S008
S010 · implies
Before
source roles = [Normality ORIGINAL H, 4, [0, 1, 2, 3, 4, 5], 4]
After
derived = [[[0, 0, 4, 0], [1, 1, 4, 1], [2, 2, 4, 2], [3, 3, 4, 3], [4, 4, 4, 4], [5, 5, 4, 5]], [0, 1, 2, 3, 4, 5], Yes]
Conditions: none
In the same table compute g*h then multiply by g inverse for every h.Check set equality for every g,not sampled elements or unproved generators.
Step identifiers and dependencies
Rule: Subgroup_EVERY_g_entire_conjugate_set · Uses: G001, S009
S011 · implies
Before
source roles = [Normality ORIGINAL H, 5, [0, 1, 2, 3, 4, 5], 3]
After
derived = [[[0, 1, 3, 0], [1, 2, 3, 1], [2, 3, 3, 2], [3, 4, 3, 3], [4, 5, 3, 4], [5, 0, 3, 5]], [0, 1, 2, 3, 4, 5], Yes]
Conditions: none
In the same table compute g*h then multiply by g inverse for every h.Check set equality for every g,not sampled elements or unproved generators.
Step identifiers and dependencies
Rule: Subgroup_EVERY_g_entire_conjugate_set · Uses: G001, S010
S012 · implies
Before
source roles = [0, [0, 1, 2, 3, 4, 5]]
After
derived = [[0, 1, 2, 3, 4, 5], [0, 1, 2, 3, 4, 5], Yes]
Conditions: none
These are complete left and right cosets for the same g.Do not reverse multiplication in a nonabelian group.
Step identifiers and dependencies
Rule: Normality_ALL_g_LEFT_RIGHT_cosets · Uses: G001, S011
S013 · implies
Before
source roles = [1, [0, 1, 2, 3, 4, 5]]
After
derived = [[0, 1, 2, 3, 4, 5], [0, 1, 2, 3, 4, 5], Yes]
Conditions: none
These are complete left and right cosets for the same g.Do not reverse multiplication in a nonabelian group.
Step identifiers and dependencies
Rule: Normality_ALL_g_LEFT_RIGHT_cosets · Uses: G001, S012
S014 · implies
Before
source roles = [2, [0, 1, 2, 3, 4, 5]]
After
derived = [[0, 1, 2, 3, 4, 5], [0, 1, 2, 3, 4, 5], Yes]
Conditions: none
These are complete left and right cosets for the same g.Do not reverse multiplication in a nonabelian group.
Step identifiers and dependencies
Rule: Normality_ALL_g_LEFT_RIGHT_cosets · Uses: G001, S013
S015 · implies
Before
source roles = [3, [0, 1, 2, 3, 4, 5]]
After
derived = [[0, 1, 2, 3, 4, 5], [0, 1, 2, 3, 4, 5], Yes]
Conditions: none
These are complete left and right cosets for the same g.Do not reverse multiplication in a nonabelian group.
Step identifiers and dependencies
Rule: Normality_ALL_g_LEFT_RIGHT_cosets · Uses: G001, S014
S016 · implies
Before
source roles = [4, [0, 1, 2, 3, 4, 5]]
After
derived = [[0, 1, 2, 3, 4, 5], [0, 1, 2, 3, 4, 5], Yes]
Conditions: none
These are complete left and right cosets for the same g.Do not reverse multiplication in a nonabelian group.
Step identifiers and dependencies
Rule: Normality_ALL_g_LEFT_RIGHT_cosets · Uses: G001, S015
S017 · implies
Before
source roles = [5, [0, 1, 2, 3, 4, 5]]
After
derived = [[0, 1, 2, 3, 4, 5], [0, 1, 2, 3, 4, 5], Yes]
Conditions: none
These are complete left and right cosets for the same g.Do not reverse multiplication in a nonabelian group.
Step identifiers and dependencies
Rule: Normality_ALL_g_LEFT_RIGHT_cosets · Uses: G001, S016
S018 · implies
Before
source roles = [[0, 1, 2, 3, 4, 5], Yes, Yes, Yes]
After
derived = [gHg^-1=H iff gH=Hg for EVERY g]
Conditions: none
Right multiplication by g is a bijection,turning gHg^-1=H into gH=Hg;right multiply by g inverse for the converse.No quotient multiplication is claimed here.
Step identifiers and dependencies
Rule: Normality_GENERAL_conjugates_iff_left_right_cosets · Uses: G001, S017
Result
([0, 1, 2, 3, 4, 5], [[0, [0, 1, 2, 3, 4, 5], [0, 1, 2, 3, 4, 5], Yes], [1, [0, 1, 2, 3, 4, 5], [0, 1, 2, 3, 4, 5], Yes], [2, [0, 1, 2, 3, 4, 5], [0, 1, 2, 3, 4, 5], Yes], [3, [0, 1, 2, 3, 4, 5], [0, 1, 2, 3, 4, 5], Yes], [4, [0, 1, 2, 3, 4, 5], [0, 1, 2, 3, 4, 5], Yes], [5, [0, 1, 2, 3, 4, 5], [0, 1, 2, 3, 4, 5], Yes]], Yes, left_and_right_cosets_agree_for_every_g_exactly_when_H_is_normal)
The full substitutions and premise checks give the original answer; source identity,format and status are unchanged.