Explore related knowledge and questions →
← Question derivation index · Original question batch
R0049-25326 · q-20261015-advance-20261114-r02-finite-quotient-group-0076
Use complete finite group table=[[0, 1, 2, 3, 4, 5], [1, 2, 0, 4, 5, 3], [2, 0, 1, 5, 3, 4], [3, 5, 4, 0, 2, 1], [4, 3, 5, 1, 0, 2], [5, 4, 3, 2, 1, 0]], identity=0, explicit subset=[0, 3] and the entire left-coset partition. Subgroup qualification precedes normality. Quotient elements are coset sets, not representatives; coset indices follow the source canonical element-list order. Give (subgroup, normal, cosets, representative_counterexample, well_defined, quotient_group_certificate, boundary).
G001 — Use complete finite group table=[[0, 1, 2, 3, 4, 5], [1, 2, 0, 4, 5, 3], [2, 0, 1, 5, 3, 4], [3, 5, 4, 0, 2, 1], [4, 3, 5, 1, 0, 2], [5, 4, 3, 2, 1, 0]], identity=0, explicit subset=[0, 3] and the entire left-coset partition. Subgroup qualification precedes normality. Quotient elements are coset sets, not representatives; coset indices follow the source canonical element-list order. Give (subgroup, normal, cosets, representative_counterexample, well_defined, quotient_group_certificate, boundary).Use the original question domain, assumptions and cited MKO definitions. This item has second-context mathematical and bilingual review, with the model, answer and every arithmetic step independently recomputed from the original parameters; the source question remains a candidate.
Before
source roles = [quotient-nonnormal-boundary]
After
derived = [[subgroup, normal, cosets, representative_counterexample, well_defined, quotient_group_certificate, boundary]]
Conditions: none
List the full source field order without JavaScript.LP boundary modes all have6 fields but select different roles from the original mode,not answer shape.
Rule: source_ordered_fields_without_JS · Uses: G001
Before
source roles = [[[0, 1, 2, 3, 4, 5], [1, 2, 0, 4, 5, 3], [2, 0, 1, 5, 3, 4], [3, 5, 4, 0, 2, 1], [4, 3, 5, 1, 0, 2], [5, 4, 3, 2, 1, 0]], 0]
After
derived = [6, [[0, 0, 0, 0], [1, 1, 1, 1], [2, 2, 2, 2], [3, 3, 3, 3], [4, 4, 4, 4], [5, 5, 5, 5]], Yes]
Conditions: none
Validate the complete closed Cayley table and actual identity label,without assuming0 or the old32-element cap.
Rule: Quotient_complete_group_table_actual_identity · Uses: G001, S001
Before
source roles = [6, 0]
After
derived = [[[Yes, Yes, Yes, Yes, Yes, Yes], [Yes, Yes, Yes, Yes, Yes, Yes], [Yes, Yes, Yes, Yes, Yes, Yes], [Yes, Yes, Yes, Yes, Yes, Yes], [Yes, Yes, Yes, Yes, Yes, Yes], [Yes, Yes, Yes, Yes, Yes, Yes]], 216, [0, 2, 1, 3, 4, 5]]
Conditions: none
Each pair-matrix entry checks associativity for every z,covering n^3 obligations;each inverse returns the same identity from both sides.This is exhaustive,not sampling.
Rule: Quotient_ALL_group_associativity_triples_and_two_sided_inverses · Uses: G001, S002
Before
source roles = [0, [0, 3]]
After
derived = [[[0, 0, 0, Yes], [0, 3, 3, Yes], [3, 0, 3, Yes], [3, 3, 0, Yes]], [[0, 0, Yes], [3, 3, Yes]], Yes, [[0, [0, 3]], [1, [0, 5]], [2, [0, 4]], [3, [0, 3]], [4, [0, 5]], [5, [0, 4]]], No]
Conditions: none
First qualify identity,all products and inverse closure as a genuine subgroup,then test conjugation for every g.Positive branches require normality and the boundary requires actual nonnormality,not failed subgroup qualification.
Rule: Quotient_genuine_subgroup_before_actual_normality · Uses: G001, S003
Before
source roles = [[0, 3], [0, 1, 2, 3, 4, 5]]
After
derived = [[[0, 3], [1, 4], [2, 5]], [0, 1, 2, 0, 1, 2], Yes]
Conditions: none
Every g belongs to gH.If aH meets bH,ah1=bh2 implies b^-1a in H and the complete cosets coincide.Enumerate every g,deduplicate and retain source order.Quotient elements are coset SETS,not least representatives.
Rule: Quotient_ALL_LEFT_coset_SETS_complete_disjoint_partition · Uses: G001, S004
Before
source roles = [0, 0, [0, 3], [0, 3]]
After
derived = [[[0, 0, 0, 0], [0, 3, 3, 0], [3, 0, 3, 0], [3, 3, 0, 0]], [0], Yes]
Conditions: none
For every ordered coset pair,all representative products must land in one product coset.A least-representative table alone does not establish well-definedness;retain the complete set of possible indices.
Rule: Quotient_EVERY_coset_pair_ALL_representative_products · Uses: G001, S005
Before
source roles = [0, 1, [0, 3], [1, 4]]
After
derived = [[[0, 1, 1, 1], [0, 4, 4, 1], [3, 1, 5, 2], [3, 4, 2, 2]], [1, 2], No]
Conditions: none
For every ordered coset pair,all representative products must land in one product coset.A least-representative table alone does not establish well-definedness;retain the complete set of possible indices.
Rule: Quotient_EVERY_coset_pair_ALL_representative_products · Uses: G001, S006
Before
source roles = [0, 2, [0, 3], [2, 5]]
After
derived = [[[0, 2, 2, 2], [0, 5, 5, 2], [3, 2, 4, 1], [3, 5, 1, 1]], [1, 2], No]
Conditions: none
For every ordered coset pair,all representative products must land in one product coset.A least-representative table alone does not establish well-definedness;retain the complete set of possible indices.
Rule: Quotient_EVERY_coset_pair_ALL_representative_products · Uses: G001, S007
Before
source roles = [1, 0, [1, 4], [0, 3]]
After
derived = [[[1, 0, 1, 1], [1, 3, 4, 1], [4, 0, 4, 1], [4, 3, 1, 1]], [1], Yes]
Conditions: none
For every ordered coset pair,all representative products must land in one product coset.A least-representative table alone does not establish well-definedness;retain the complete set of possible indices.
Rule: Quotient_EVERY_coset_pair_ALL_representative_products · Uses: G001, S008
Before
source roles = [1, 1, [1, 4], [1, 4]]
After
derived = [[[1, 1, 2, 2], [1, 4, 5, 2], [4, 1, 3, 0], [4, 4, 0, 0]], [0, 2], No]
Conditions: none
For every ordered coset pair,all representative products must land in one product coset.A least-representative table alone does not establish well-definedness;retain the complete set of possible indices.
Rule: Quotient_EVERY_coset_pair_ALL_representative_products · Uses: G001, S009
Before
source roles = [1, 2, [1, 4], [2, 5]]
After
derived = [[[1, 2, 0, 0], [1, 5, 3, 0], [4, 2, 5, 2], [4, 5, 2, 2]], [0, 2], No]
Conditions: none
For every ordered coset pair,all representative products must land in one product coset.A least-representative table alone does not establish well-definedness;retain the complete set of possible indices.
Rule: Quotient_EVERY_coset_pair_ALL_representative_products · Uses: G001, S010
Before
source roles = [2, 0, [2, 5], [0, 3]]
After
derived = [[[2, 0, 2, 2], [2, 3, 5, 2], [5, 0, 5, 2], [5, 3, 2, 2]], [2], Yes]
Conditions: none
For every ordered coset pair,all representative products must land in one product coset.A least-representative table alone does not establish well-definedness;retain the complete set of possible indices.
Rule: Quotient_EVERY_coset_pair_ALL_representative_products · Uses: G001, S011
Before
source roles = [2, 1, [2, 5], [1, 4]]
After
derived = [[[2, 1, 0, 0], [2, 4, 3, 0], [5, 1, 4, 1], [5, 4, 1, 1]], [0, 1], No]
Conditions: none
For every ordered coset pair,all representative products must land in one product coset.A least-representative table alone does not establish well-definedness;retain the complete set of possible indices.
Rule: Quotient_EVERY_coset_pair_ALL_representative_products · Uses: G001, S012
Before
source roles = [2, 2, [2, 5], [2, 5]]
After
derived = [[[2, 2, 1, 1], [2, 5, 4, 1], [5, 2, 3, 0], [5, 5, 0, 0]], [0, 1], No]
Conditions: none
For every ordered coset pair,all representative products must land in one product coset.A least-representative table alone does not establish well-definedness;retain the complete set of possible indices.
Rule: Quotient_EVERY_coset_pair_ALL_representative_products · Uses: G001, S013
Before
source roles = [[0, 1, [1, 2], No], [0, 3], [1, 4]]
After
derived = [[0, 1, 0, 1, 1, 3, 1, 2], No, No]
Conditions: none
Keep the source first bad ordered pair and left,left2,right,right2 search order.Different representatives of the same two cosets give different product cosets,so multiplication fails to be well-defined.The subgroup and coset partition remain valid;do not invent a quotient table.
Rule: Quotient_FIRST_bad_pair_exact_source_nested_representative_witness · Uses: G001, S014
S015 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.S014 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.S013 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.S012 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.S011 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.S010 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.S009 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.S008 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.S007 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.S006 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.S005 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.S004 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.S003 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.S002 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.S001 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.([0, 3], No, [[0, 3], [1, 4], [2, 5]], [0, 1, 0, 1, 1, 3, 1, 2], No, No, explicit_representative_dependence_blocks_quotient_group_multiplication)
The full substitutions and premise checks give the original answer; source identity,format and status are unchanged.
Review date: 2026-10-26
Original questions, answers, step expressions, numeric ASTs and historical records are retained. Source candidate labels remain historical and are not overwritten as formal proof.
input commit: 0f7be61e2c22317a4075561dc822c87d881a50dboriginal question SHA-256: 88a39acb322aefbac2c0765741b101b2caa29ce4bdbfce26cd6e5cc302349c91candidate record SHA-256: de4b34b7bb7a8ab23933f5c08113dc95049d17cc2bc8adf7962ba8f017736a87semantic review receipt SHA-256: 6212b8b0b3b273f3a514e26ebd17d7e81219c56a8f47e40047ee2b6bf01d1ba3question-first witness SHA-256: f32a23d5e1b66c7794c60def58741bcdfacff24f3cdfc9bc48109c8f71543cf3Lean: NOT_RUN · human review: NOT_PERFORMED