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Question 26626: Two Rescaled Affine Branches Meet at the Exact Middle Point

On this page
  1. Original question and givens
  2. Definition and scope
  3. Step-by-step derivation
  4. Reverse checks
  5. Result
  6. This question review and source binding

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← Question derivation index · Original question batch

R0052-26626 · q-20261015-advance-20261117-r06-path-connected-space-0051

Original question and givens

Use real interval [-3,4] and contained start=0,middle=2,end=0. Give (start, middle, end, first_branch, second_branch, join_statement, path_certificate).

  • G001 — Use real interval [-3,4] and contained start=0,middle=2,end=0. Give (start, middle, end, first_branch, second_branch, join_statement, path_certificate).

Definition and scope

Use the original question domain, assumptions and cited MKO definitions. This item has second-context mathematical and bilingual review, with the model, answer and every arithmetic step independently recomputed from the original parameters; the source question remains a candidate.

Step-by-step derivation

S001 · implies

Before

source roles = [path-concatenation]

After

derived = [[start, middle, end, first_branch, second_branch, join, continuous_path]]

Conditions: none

List this operation/mode exact source field order without JavaScript.Keep Boolean,string and null roles distinct;do not pad fields or infer the interface from answer shape.

Step identifiers and dependencies

Rule: source_ordered_fields_without_JS · Uses: G001

S002 · calculation

Before

Path first ORIGINAL middle minus start := sub(2, 0)

After

Path first ORIGINAL middle minus start = 2

Conditions: none

Substitute the original roles exactly,retaining symbolic operations;no floating approximation or extra source-domain restriction.

Step identifiers and dependencies

Rule: exact_rational_arithmetic · Uses: G001, S001

S003 · calculation

Before

Path second ORIGINAL end minus middle := sub(0, 2)

After

Path second ORIGINAL end minus middle = -2

Conditions: none

Substitute the original roles exactly,retaining symbolic operations;no floating approximation or extra source-domain restriction.

Step identifiers and dependencies

Rule: exact_rational_arithmetic · Uses: G001, S002

S004 · calculation

Before

Path first branch JOIN at half := sum(0, 2)

After

Path first branch JOIN at half = 2

Conditions: none

Substitute the original roles exactly,retaining symbolic operations;no floating approximation or extra source-domain restriction.

Step identifiers and dependencies

Rule: exact_rational_arithmetic · Uses: G001, S003

S005 · calculation

Before

Path second branch JOIN at half := sum(2, 0)

After

Path second branch JOIN at half = 2

Conditions: none

Substitute the original roles exactly,retaining symbolic operations;no floating approximation or extra source-domain restriction.

Step identifiers and dependencies

Rule: exact_rational_arithmetic · Uses: G001, S004

S006 · implies

Before

source roles = [-3, 4, 0, 2, 0, 2, -2]

After

derived = [first weight=2t in[0,1], second weight=2t-1 in[0,1], 2, 2, Yes]

Conditions: none

On the first half use weight2t from start to middle;on the second use2t-1 from middle to end.Convexity controls each entire range.Both branches are continuous and agree at t=1/2,so the pasting lemma gives continuity on the whole interval.

Step identifiers and dependencies

Rule: Path_TWO_whole_convex_branches_pasting_at_middle · Uses: G001, S005

Reverse checks

  • S006 · premise_and_result_audit — Reverse-check the complete original data,types,field order and premises;finite audits are not formal proofs of infinite theorems.
  • S005 · premise_and_result_audit — Recompute Path second branch JOIN at half with exact rational arithmetic, not rounded decimals.
  • S004 · premise_and_result_audit — Recompute Path first branch JOIN at half with exact rational arithmetic, not rounded decimals.
  • S003 · premise_and_result_audit — Recompute Path second ORIGINAL end minus middle with exact rational arithmetic, not rounded decimals.
  • S002 · premise_and_result_audit — Recompute Path first ORIGINAL middle minus start with exact rational arithmetic, not rounded decimals.
  • S001 · premise_and_result_audit — Reverse-check the complete original data,types,field order and premises;finite audits are not formal proofs of infinite theorems.

Result

(0, 2, 0, 0<=t<=1/2:0+2t(2), 1/2<=t<=1:2+(2t-1)(-2), both_branches_meet_at_middle, Yes)

The full substitutions and premise checks give the original answer; source identity,format and status are unchanged.

This question review and source binding

Review date: 2026-10-26

Original questions, answers, step expressions, numeric ASTs and historical records are retained. Source candidate labels remain historical and are not overwritten as formal proof.

Source hashes and review receipts
  • input commit: 0f7be61e2c22317a4075561dc822c87d881a50db
  • original question SHA-256: b321ca34be62760a801cd13e16ea62da67e0372afe7c2aa0c4a77083d5535b22
  • candidate record SHA-256: ea52d65595f0f0abc8a3342bd0e61a9f41328c8c6be2ccedcf6fcd7756bb06d1
  • semantic review receipt SHA-256: 729b25cbf6bf5cb1d07a21a511ae216ec5fdd54a4a7aa2f7c21156b81ff37252
  • question-first witness SHA-256: d1ab788770eaad04f986986e65afb0d55791e8a8c0d747e9a2b499f79fe78df2
  • Lean: NOT_RUN · human review: NOT_PERFORMED
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