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R0053-27474 · q-20261015-advance-20261118-r05-p-adic-valuation-integers-0049
Use prime p=13, integers a=4056, b=-25, with v_p(0)=infinity. Give (p, a, b, valuation_a, valuation_b, product, valuation_product, sum_of_valuations, additivity, infinity_convention).
G001 — Use prime p=13, integers a=4056, b=-25, with v_p(0)=infinity. Give (p, a, b, valuation_a, valuation_b, product, valuation_product, sum_of_valuations, additivity, infinity_convention).Use the original question domain, assumptions and cited MKO definitions. This item has second-context mathematical and bilingual review, with the model, answer and every arithmetic step independently recomputed from the original parameters; the source question remains a candidate.
Before
source roles = [pval-product-additivity]
After
derived = [[p, a, b, valuation_a, valuation_b, product, valuation_product, sum_of_valuations, additivity, infinity_convention]]
Conditions: none
List the complete source field order and mode-specific roles without JavaScript or answer-shape inference;No,undefined and infinity retain their distinct meanings.
Rule: source_ordered_fields_without_JS · Uses: G001
Before
Valuation ORIGINAL a ORIGINAL division step1 := div(4056, 13)
After
Valuation ORIGINAL a ORIGINAL division step1 = 312
Conditions: none
Substitute original roles and established intermediates exactly;no approximation,slot substitution or internally consistent changed operand.
Rule: exact_rational_arithmetic · Uses: G001, S001
Before
Valuation ORIGINAL a dividing prime power1 := mul(1, 13)
After
Valuation ORIGINAL a dividing prime power1 = 13
Conditions: none
Substitute original roles and established intermediates exactly;no approximation,slot substitution or internally consistent changed operand.
Rule: exact_rational_arithmetic · Uses: G001, S002
Before
source roles = [Valuation ORIGINAL a, 13, 4056, 4056, 1]
After
derived = [312, 13, 0, Yes]
Conditions: none
Divide only when the current unit is divisible by p.Each step preserves |a|=p^k*unit and strictly decreases the positive unit,so it terminates.Derived integers do not inherit the raw-input1e6 cap.
Rule: Valuation_EACH_division_source_remainder_and_factor_invariant · Uses: G001, S003
Before
Valuation ORIGINAL a ORIGINAL division step2 := div(312, 13)
After
Valuation ORIGINAL a ORIGINAL division step2 = 24
Conditions: none
Substitute original roles and established intermediates exactly;no approximation,slot substitution or internally consistent changed operand.
Rule: exact_rational_arithmetic · Uses: G001, S004
Before
Valuation ORIGINAL a dividing prime power2 := mul(13, 13)
After
Valuation ORIGINAL a dividing prime power2 = 169
Conditions: none
Substitute original roles and established intermediates exactly;no approximation,slot substitution or internally consistent changed operand.
Rule: exact_rational_arithmetic · Uses: G001, S005
Before
source roles = [Valuation ORIGINAL a, 13, 4056, 312, 2]
After
derived = [24, 169, 0, Yes]
Conditions: none
Divide only when the current unit is divisible by p.Each step preserves |a|=p^k*unit and strictly decreases the positive unit,so it terminates.Derived integers do not inherit the raw-input1e6 cap.
Rule: Valuation_EACH_division_source_remainder_and_factor_invariant · Uses: G001, S006
Before
Valuation ORIGINAL a terminal factorization product := mul(169, 24)
After
Valuation ORIGINAL a terminal factorization product = 4056
Conditions: none
Substitute original roles and established intermediates exactly;no approximation,slot substitution or internally consistent changed operand.
Rule: exact_rational_arithmetic · Uses: G001, S007
Before
source roles = [Valuation ORIGINAL a, 13, 4056, 4056, 2, 24, [13, 169]]
After
derived = [4056, 11, Yes, Yes]
Conditions: none
At termination p does not divide the unit,so p^(k+1) does not divide |a| and k is maximal.A sign does not affect divisibility;the factorization is for |a|,not negative a equalling a positive product.
Rule: Valuation_terminal_NONdivisible_unit_highest_power · Uses: G001, S008
Before
Valuation ORIGINAL b terminal factorization product := mul(1, 25)
After
Valuation ORIGINAL b terminal factorization product = 25
Conditions: none
Substitute original roles and established intermediates exactly;no approximation,slot substitution or internally consistent changed operand.
Rule: exact_rational_arithmetic · Uses: G001, S009
Before
source roles = [Valuation ORIGINAL b, 13, -25, 25, 0, 25, []]
After
derived = [25, 12, Yes, Yes]
Conditions: none
At termination p does not divide the unit,so p^(k+1) does not divide |a| and k is maximal.A sign does not affect divisibility;the factorization is for |a|,not negative a equalling a positive product.
Rule: Valuation_terminal_NONdivisible_unit_highest_power · Uses: G001, S010
Before
Valuation ORIGINAL a times b := mul(4056, -25)
After
Valuation ORIGINAL a times b = -101400
Conditions: none
Substitute original roles and established intermediates exactly;no approximation,slot substitution or internally consistent changed operand.
Rule: exact_rational_arithmetic · Uses: G001, S011
Before
Valuation ACTUAL product ORIGINAL division step1 := div(101400, 13)
After
Valuation ACTUAL product ORIGINAL division step1 = 7800
Conditions: none
Substitute original roles and established intermediates exactly;no approximation,slot substitution or internally consistent changed operand.
Rule: exact_rational_arithmetic · Uses: G001, S012
Before
Valuation ACTUAL product dividing prime power1 := mul(1, 13)
After
Valuation ACTUAL product dividing prime power1 = 13
Conditions: none
Substitute original roles and established intermediates exactly;no approximation,slot substitution or internally consistent changed operand.
Rule: exact_rational_arithmetic · Uses: G001, S013
Before
source roles = [Valuation ACTUAL product, 13, 101400, 101400, 1]
After
derived = [7800, 13, 0, Yes]
Conditions: none
Divide only when the current unit is divisible by p.Each step preserves |a|=p^k*unit and strictly decreases the positive unit,so it terminates.Derived integers do not inherit the raw-input1e6 cap.
Rule: Valuation_EACH_division_source_remainder_and_factor_invariant · Uses: G001, S014
Before
Valuation ACTUAL product ORIGINAL division step2 := div(7800, 13)
After
Valuation ACTUAL product ORIGINAL division step2 = 600
Conditions: none
Substitute original roles and established intermediates exactly;no approximation,slot substitution or internally consistent changed operand.
Rule: exact_rational_arithmetic · Uses: G001, S015
Before
Valuation ACTUAL product dividing prime power2 := mul(13, 13)
After
Valuation ACTUAL product dividing prime power2 = 169
Conditions: none
Substitute original roles and established intermediates exactly;no approximation,slot substitution or internally consistent changed operand.
Rule: exact_rational_arithmetic · Uses: G001, S016
Before
source roles = [Valuation ACTUAL product, 13, 101400, 7800, 2]
After
derived = [600, 169, 0, Yes]
Conditions: none
Divide only when the current unit is divisible by p.Each step preserves |a|=p^k*unit and strictly decreases the positive unit,so it terminates.Derived integers do not inherit the raw-input1e6 cap.
Rule: Valuation_EACH_division_source_remainder_and_factor_invariant · Uses: G001, S017
Before
Valuation ACTUAL product terminal factorization product := mul(169, 600)
After
Valuation ACTUAL product terminal factorization product = 101400
Conditions: none
Substitute original roles and established intermediates exactly;no approximation,slot substitution or internally consistent changed operand.
Rule: exact_rational_arithmetic · Uses: G001, S018
Before
source roles = [Valuation ACTUAL product, 13, -101400, 101400, 2, 600, [13, 169]]
After
derived = [101400, 2, Yes, Yes]
Conditions: none
At termination p does not divide the unit,so p^(k+1) does not divide |a| and k is maximal.A sign does not affect divisibility;the factorization is for |a|,not negative a equalling a positive product.
Rule: Valuation_terminal_NONdivisible_unit_highest_power · Uses: G001, S019
Before
Valuation ORIGINAL exponent addition := sum(2, 0)
After
Valuation ORIGINAL exponent addition = 2
Conditions: none
Substitute original roles and established intermediates exactly;no approximation,slot substitution or internally consistent changed operand.
Rule: exact_rational_arithmetic · Uses: G001, S020
Before
source roles = [13, 4056, -25, 2, 0, 24, 25]
After
derived = [-101400, 2, 2, Yes]
Conditions: none
For nonzero factors write a=±p^r*u,b=±p^s*v.Primality and Euclid lemma keep uv indivisible by p,so the exact exponent is r+s.If either factor is0,the product is0 and the same infinity convention applies.A derived product may reach1e12 while remaining SAFE;do not reapply the raw1e6 bound.
Rule: Valuation_GENERAL_product_primeness_unit_product_or_zero · Uses: G001, S021
S022 · premise_and_result_audit — Reverse-check the complete original data,step operands and premises;finite checks,conditional named-theorem use and general formal proof remain distinct.S021 · premise_and_result_audit — Recompute Valuation ORIGINAL exponent addition with exact rational arithmetic, not rounded decimals.S020 · premise_and_result_audit — Reverse-check the complete original data,step operands and premises;finite checks,conditional named-theorem use and general formal proof remain distinct.S019 · premise_and_result_audit — Recompute Valuation ACTUAL product terminal factorization product with exact rational arithmetic, not rounded decimals.S018 · premise_and_result_audit — Reverse-check the complete original data,step operands and premises;finite checks,conditional named-theorem use and general formal proof remain distinct.S017 · premise_and_result_audit — Recompute Valuation ACTUAL product dividing prime power2 with exact rational arithmetic, not rounded decimals.S016 · premise_and_result_audit — Recompute Valuation ACTUAL product ORIGINAL division step2 with exact rational arithmetic, not rounded decimals.S015 · premise_and_result_audit — Reverse-check the complete original data,step operands and premises;finite checks,conditional named-theorem use and general formal proof remain distinct.S014 · premise_and_result_audit — Recompute Valuation ACTUAL product dividing prime power1 with exact rational arithmetic, not rounded decimals.S013 · premise_and_result_audit — Recompute Valuation ACTUAL product ORIGINAL division step1 with exact rational arithmetic, not rounded decimals.S012 · premise_and_result_audit — Recompute Valuation ORIGINAL a times b with exact rational arithmetic, not rounded decimals.S011 · premise_and_result_audit — Reverse-check the complete original data,step operands and premises;finite checks,conditional named-theorem use and general formal proof remain distinct.S010 · premise_and_result_audit — Recompute Valuation ORIGINAL b terminal factorization product with exact rational arithmetic, not rounded decimals.S009 · premise_and_result_audit — Reverse-check the complete original data,step operands and premises;finite checks,conditional named-theorem use and general formal proof remain distinct.S008 · premise_and_result_audit — Recompute Valuation ORIGINAL a terminal factorization product with exact rational arithmetic, not rounded decimals.S007 · premise_and_result_audit — Reverse-check the complete original data,step operands and premises;finite checks,conditional named-theorem use and general formal proof remain distinct.S006 · premise_and_result_audit — Recompute Valuation ORIGINAL a dividing prime power2 with exact rational arithmetic, not rounded decimals.S005 · premise_and_result_audit — Recompute Valuation ORIGINAL a ORIGINAL division step2 with exact rational arithmetic, not rounded decimals.S004 · premise_and_result_audit — Reverse-check the complete original data,step operands and premises;finite checks,conditional named-theorem use and general formal proof remain distinct.S003 · premise_and_result_audit — Recompute Valuation ORIGINAL a dividing prime power1 with exact rational arithmetic, not rounded decimals.S002 · premise_and_result_audit — Recompute Valuation ORIGINAL a ORIGINAL division step1 with exact rational arithmetic, not rounded decimals.S001 · premise_and_result_audit — Reverse-check the complete original data,step operands and premises;finite checks,conditional named-theorem use and general formal proof remain distinct.(13, 4056, -25, 2, 0, -101400, 2, 2, Yes, infinity_plus_k_equals_infinity)
The full substitutions and premise checks give the original answer; source identity,format and status are unchanged.
Review date: 2026-10-26
Original questions, answers, step expressions, numeric ASTs and historical records are retained. Source candidate labels remain historical and are not overwritten as formal proof.
input commit: 0f7be61e2c22317a4075561dc822c87d881a50dboriginal question SHA-256: 0f4cead457b0be3bcd9dff24c4d0a666a0837f85ff76de6f0eb9211d3729236acandidate record SHA-256: 01345d5a40b3935622294906dcb1b1309194ad485da9cb462cb531f6569964b6semantic review receipt SHA-256: 1b7a62514347b82518305d5feb4369a52d7d44c442a0f2b131e9eb3cd7b45f62question-first witness SHA-256: 79dc2a1077081f3ea2a03f75e32778163bf05e814cdf4c29ed86e567295f9ee1Lean: NOT_RUN · human review: NOT_PERFORMED