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Question 27407: Zero, Composite Bases, Negative Inputs and Cancellation Need Distinct Conventions

On this page
  1. Original question and givens
  2. Definition and scope
  3. Step-by-step derivation
  4. Reverse checks
  5. Result
  6. This question review and source binding

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R0053-27407 · q-20261015-advance-20261118-r05-p-adic-valuation-integers-0082

Original question and givens

Use mode=negative_normalization, base p=3, integer a=-7. Give (mode, p, integer_a, absolute_a, valuation, negative_integer_valid, scope).

  • G001 — Use mode=negative_normalization, base p=3, integer a=-7. Give (mode, p, integer_a, absolute_a, valuation, negative_integer_valid, scope).

Definition and scope

Use the original question domain, assumptions and cited MKO definitions. This item has second-context mathematical and bilingual review, with the model, answer and every arithmetic step independently recomputed from the original parameters; the source question remains a candidate.

Step-by-step derivation

S001 · implies

Before

source roles = [pval-boundary]

After

derived = [[mode, p, integer_a, absolute_a, valuation, negative_integer_valid, scope]]

Conditions: none

List the complete source field order and mode-specific roles without JavaScript or answer-shape inference;No,undefined and infinity retain their distinct meanings.

Step identifiers and dependencies

Rule: source_ordered_fields_without_JS · Uses: G001

S002 · calculation

Before

Valuation boundary ORIGINAL negative terminal factorization product := mul(1, 7)

After

Valuation boundary ORIGINAL negative terminal factorization product = 7

Conditions: none

Substitute original roles and established intermediates exactly;no approximation,slot substitution or internally consistent changed operand.

Step identifiers and dependencies

Rule: exact_rational_arithmetic · Uses: G001, S001

S003 · implies

Before

source roles = [Valuation boundary ORIGINAL negative, 3, -7, 7, 0, 7, []]

After

derived = [7, 1, Yes, Yes]

Conditions: none

At termination p does not divide the unit,so p^(k+1) does not divide |a| and k is maximal.A sign does not affect divisibility;the factorization is for |a|,not negative a equalling a positive product.

Step identifiers and dependencies

Rule: Valuation_terminal_NONdivisible_unit_highest_power · Uses: G001, S002

Reverse checks

  • S003 · premise_and_result_audit — Reverse-check the complete original data,step operands and premises;finite checks,conditional named-theorem use and general formal proof remain distinct.
  • S002 · premise_and_result_audit — Recompute Valuation boundary ORIGINAL negative terminal factorization product with exact rational arithmetic, not rounded decimals.
  • S001 · premise_and_result_audit — Reverse-check the complete original data,step operands and premises;finite checks,conditional named-theorem use and general formal proof remain distinct.

Result

(negative_normalization, 3, -7, 7, 0, Yes, negative_integer_is_valid)

The full substitutions and premise checks give the original answer; source identity,format and status are unchanged.

This question review and source binding

Review date: 2026-10-26

Original questions, answers, step expressions, numeric ASTs and historical records are retained. Source candidate labels remain historical and are not overwritten as formal proof.

Source hashes and review receipts
  • input commit: 0f7be61e2c22317a4075561dc822c87d881a50db
  • original question SHA-256: cd08d58f2384aa099ce99c1de24a181692c85e867c07a83e488751f5c66f7560
  • candidate record SHA-256: 5db93bfe2032319c41bd41f5abb3bd560233652b82cc8b3f450c2e3df08378b1
  • semantic review receipt SHA-256: 1b7a62514347b82518305d5feb4369a52d7d44c442a0f2b131e9eb3cd7b45f62
  • question-first witness SHA-256: 79dc2a1077081f3ea2a03f75e32778163bf05e814cdf4c29ed86e567295f9ee1
  • Lean: NOT_RUN · human review: NOT_PERFORMED
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