Original question and givens
Use mode=equal_valuations_cancellation, base p=3, integer a=24. Give (mode, p, a, opposite_a, valuation_a, valuation_opposite_a, valuation_sum, cancellation_scope, universal_sum_equality_claim).
G001 — Use mode=equal_valuations_cancellation, base p=3, integer a=24. Give (mode, p, a, opposite_a, valuation_a, valuation_opposite_a, valuation_sum, cancellation_scope, universal_sum_equality_claim).
Step-by-step derivation
S001 · implies
Before
source roles = [pval-boundary]
After
derived = [[mode, p, a, opposite_a, valuation_a, valuation_opposite_a, valuation_sum, cancellation_scope, universal_sum_equality_claim]]
Conditions: none
List the complete source field order and mode-specific roles without JavaScript or answer-shape inference;No,undefined and infinity retain their distinct meanings.
Step identifiers and dependencies
Rule: source_ordered_fields_without_JS · Uses: G001
S002 · calculation
Before
Valuation boundary ORIGINAL a ORIGINAL division step1 := div(24, 3)
After
Valuation boundary ORIGINAL a ORIGINAL division step1 = 8
Conditions: none
Substitute original roles and established intermediates exactly;no approximation,slot substitution or internally consistent changed operand.
Step identifiers and dependencies
Rule: exact_rational_arithmetic · Uses: G001, S001
S003 · calculation
Before
Valuation boundary ORIGINAL a dividing prime power1 := mul(1, 3)
After
Valuation boundary ORIGINAL a dividing prime power1 = 3
Conditions: none
Substitute original roles and established intermediates exactly;no approximation,slot substitution or internally consistent changed operand.
Step identifiers and dependencies
Rule: exact_rational_arithmetic · Uses: G001, S002
S004 · implies
Before
source roles = [Valuation boundary ORIGINAL a, 3, 24, 24, 1]
After
derived = [8, 3, 0, Yes]
Conditions: none
Divide only when the current unit is divisible by p.Each step preserves |a|=p^k*unit and strictly decreases the positive unit,so it terminates.Derived integers do not inherit the raw-input1e6 cap.
Step identifiers and dependencies
Rule: Valuation_EACH_division_source_remainder_and_factor_invariant · Uses: G001, S003
S005 · calculation
Before
Valuation boundary ORIGINAL a terminal factorization product := mul(3, 8)
After
Valuation boundary ORIGINAL a terminal factorization product = 24
Conditions: none
Substitute original roles and established intermediates exactly;no approximation,slot substitution or internally consistent changed operand.
Step identifiers and dependencies
Rule: exact_rational_arithmetic · Uses: G001, S004
S006 · implies
Before
source roles = [Valuation boundary ORIGINAL a, 3, 24, 24, 1, 8, [3]]
After
derived = [24, 2, Yes, Yes]
Conditions: none
At termination p does not divide the unit,so p^(k+1) does not divide |a| and k is maximal.A sign does not affect divisibility;the factorization is for |a|,not negative a equalling a positive product.
Step identifiers and dependencies
Rule: Valuation_terminal_NONdivisible_unit_highest_power · Uses: G001, S005
S007 · calculation
Before
Valuation ORIGINAL opposite cancellation sum := sum(24, -24)
After
Valuation ORIGINAL opposite cancellation sum = 0
Conditions: none
Substitute original roles and established intermediates exactly;no approximation,slot substitution or internally consistent changed operand.
Step identifiers and dependencies
Rule: exact_rational_arithmetic · Uses: G001, S006
S008 · implies
Before
source roles = [Valuation boundary ACTUAL cancellation, 3, 0]
After
derived = [infinity, 0, 0, []]
Conditions: none
Zero is divisible by every power of p,so has no highest finite exponent.Use the single serializable infinity sentinel,not numeric0 or an undefined error.
Step identifiers and dependencies
Rule: Valuation_zero_SINGLE_infinity_convention · Uses: G001, S007
S009 · implies
Before
source roles = [3, 24, -24, 1]
After
derived = [1, infinity, No]
Conditions: none
v_p(-a)=v_p(a),while the opposite sum is0 with valuation infinity,strictly above finite k.Equal summand valuations therefore do not guarantee equality with their minimum.
Step identifiers and dependencies
Rule: Valuation_equal_values_cancellation_refutes_UNIVERSAL_equality · Uses: G001, S008
Result
(equal_valuations_cancellation, 3, 24, -24, 1, 1, infinity, strict_inequality_or_infinity_can_occur_when_valuations_equal, No)
The full substitutions and premise checks give the original answer; source identity,format and status are unchanged.