R0053-27304 · q-20261015-advance-20261118-r07-pumping-lemma-regular-languages-0054
Step-by-step derivation
S001 · implies
Before
source roles = [pump-anbn-all-splits]
After
derived = [[p, adversary_word, all_legal_split_rows, split_count, triangular_count, every_split_defeated, pump_down_scope]]
Conditions: none
List the complete source field order and mode-specific roles without JavaScript or answer-shape inference;No,undefined and infinity retain their distinct meanings.
Step identifiers and dependencies
Rule: source_ordered_fields_without_JS · Uses: G001
S002 · implies
Before
source roles = [4]
After
derived = [a^4b^4, 8, ALL x>=0,y>=1,x+y<=p]
Conditions: none
Under assumed regularity take its pumping length p and choose a^p b^p of length2p>=p.Any legal xy lies in the initial p a-symbols,so y consists of a symbols and is nonempty.Do not preselect a convenient split.
Step identifiers and dependencies
Rule: Pumping_adversary_word_and_ALL_legal_split_domain · Uses: G001, S001
S003 · calculation
Before
Pumping ORIGINAL remaining a after i0 split0,1 := sub(4, 1)
After
Pumping ORIGINAL remaining a after i0 split0,1 = 3
Conditions: none
Substitute original roles and established intermediates exactly;no approximation,slot substitution or internally consistent changed operand.
Step identifiers and dependencies
Rule: exact_rational_arithmetic · Uses: G001, S002
S004 · implies
Before
source roles = [4, 0, 1]
After
derived = [3, 7, [0, 1, 3, a^3b^4, No], Yes]
Conditions: none
The third field p-x-y counts only remaining a symbols in z;full |z| adds all p b-symbols.Pumping i=0 deletes nonempty y,leaving p-y<p a symbols but p b symbols,so this legal split fails membership.
Step identifiers and dependencies
Rule: Pumping_EVERY_legal_split_i0_refutation_remainingA_NOT_fullZ · Uses: G001, S003
S005 · calculation
Before
Pumping ORIGINAL remaining a after i0 split0,2 := sub(4, 2)
After
Pumping ORIGINAL remaining a after i0 split0,2 = 2
Conditions: none
Substitute original roles and established intermediates exactly;no approximation,slot substitution or internally consistent changed operand.
Step identifiers and dependencies
Rule: exact_rational_arithmetic · Uses: G001, S004
S006 · implies
Before
source roles = [4, 0, 2]
After
derived = [2, 6, [0, 2, 2, a^2b^4, No], Yes]
Conditions: none
The third field p-x-y counts only remaining a symbols in z;full |z| adds all p b-symbols.Pumping i=0 deletes nonempty y,leaving p-y<p a symbols but p b symbols,so this legal split fails membership.
Step identifiers and dependencies
Rule: Pumping_EVERY_legal_split_i0_refutation_remainingA_NOT_fullZ · Uses: G001, S005
S007 · calculation
Before
Pumping ORIGINAL remaining a after i0 split0,3 := sub(4, 3)
After
Pumping ORIGINAL remaining a after i0 split0,3 = 1
Conditions: none
Substitute original roles and established intermediates exactly;no approximation,slot substitution or internally consistent changed operand.
Step identifiers and dependencies
Rule: exact_rational_arithmetic · Uses: G001, S006
S008 · implies
Before
source roles = [4, 0, 3]
After
derived = [1, 5, [0, 3, 1, a^1b^4, No], Yes]
Conditions: none
The third field p-x-y counts only remaining a symbols in z;full |z| adds all p b-symbols.Pumping i=0 deletes nonempty y,leaving p-y<p a symbols but p b symbols,so this legal split fails membership.
Step identifiers and dependencies
Rule: Pumping_EVERY_legal_split_i0_refutation_remainingA_NOT_fullZ · Uses: G001, S007
S009 · calculation
Before
Pumping ORIGINAL remaining a after i0 split0,4 := sub(4, 4)
After
Pumping ORIGINAL remaining a after i0 split0,4 = 0
Conditions: none
Substitute original roles and established intermediates exactly;no approximation,slot substitution or internally consistent changed operand.
Step identifiers and dependencies
Rule: exact_rational_arithmetic · Uses: G001, S008
S010 · implies
Before
source roles = [4, 0, 4]
After
derived = [0, 4, [0, 4, 0, a^0b^4, No], Yes]
Conditions: none
The third field p-x-y counts only remaining a symbols in z;full |z| adds all p b-symbols.Pumping i=0 deletes nonempty y,leaving p-y<p a symbols but p b symbols,so this legal split fails membership.
Step identifiers and dependencies
Rule: Pumping_EVERY_legal_split_i0_refutation_remainingA_NOT_fullZ · Uses: G001, S009
S011 · calculation
Before
Pumping ORIGINAL remaining a after i0 split1,1 := sub(4, 1)
After
Pumping ORIGINAL remaining a after i0 split1,1 = 3
Conditions: none
Substitute original roles and established intermediates exactly;no approximation,slot substitution or internally consistent changed operand.
Step identifiers and dependencies
Rule: exact_rational_arithmetic · Uses: G001, S010
S012 · implies
Before
source roles = [4, 1, 1]
After
derived = [2, 6, [1, 1, 2, a^3b^4, No], Yes]
Conditions: none
The third field p-x-y counts only remaining a symbols in z;full |z| adds all p b-symbols.Pumping i=0 deletes nonempty y,leaving p-y<p a symbols but p b symbols,so this legal split fails membership.
Step identifiers and dependencies
Rule: Pumping_EVERY_legal_split_i0_refutation_remainingA_NOT_fullZ · Uses: G001, S011
S013 · calculation
Before
Pumping ORIGINAL remaining a after i0 split1,2 := sub(4, 2)
After
Pumping ORIGINAL remaining a after i0 split1,2 = 2
Conditions: none
Substitute original roles and established intermediates exactly;no approximation,slot substitution or internally consistent changed operand.
Step identifiers and dependencies
Rule: exact_rational_arithmetic · Uses: G001, S012
S014 · implies
Before
source roles = [4, 1, 2]
After
derived = [1, 5, [1, 2, 1, a^2b^4, No], Yes]
Conditions: none
The third field p-x-y counts only remaining a symbols in z;full |z| adds all p b-symbols.Pumping i=0 deletes nonempty y,leaving p-y<p a symbols but p b symbols,so this legal split fails membership.
Step identifiers and dependencies
Rule: Pumping_EVERY_legal_split_i0_refutation_remainingA_NOT_fullZ · Uses: G001, S013
S015 · calculation
Before
Pumping ORIGINAL remaining a after i0 split1,3 := sub(4, 3)
After
Pumping ORIGINAL remaining a after i0 split1,3 = 1
Conditions: none
Substitute original roles and established intermediates exactly;no approximation,slot substitution or internally consistent changed operand.
Step identifiers and dependencies
Rule: exact_rational_arithmetic · Uses: G001, S014
S016 · implies
Before
source roles = [4, 1, 3]
After
derived = [0, 4, [1, 3, 0, a^1b^4, No], Yes]
Conditions: none
The third field p-x-y counts only remaining a symbols in z;full |z| adds all p b-symbols.Pumping i=0 deletes nonempty y,leaving p-y<p a symbols but p b symbols,so this legal split fails membership.
Step identifiers and dependencies
Rule: Pumping_EVERY_legal_split_i0_refutation_remainingA_NOT_fullZ · Uses: G001, S015
S017 · calculation
Before
Pumping ORIGINAL remaining a after i0 split2,1 := sub(4, 1)
After
Pumping ORIGINAL remaining a after i0 split2,1 = 3
Conditions: none
Substitute original roles and established intermediates exactly;no approximation,slot substitution or internally consistent changed operand.
Step identifiers and dependencies
Rule: exact_rational_arithmetic · Uses: G001, S016
S018 · implies
Before
source roles = [4, 2, 1]
After
derived = [1, 5, [2, 1, 1, a^3b^4, No], Yes]
Conditions: none
The third field p-x-y counts only remaining a symbols in z;full |z| adds all p b-symbols.Pumping i=0 deletes nonempty y,leaving p-y<p a symbols but p b symbols,so this legal split fails membership.
Step identifiers and dependencies
Rule: Pumping_EVERY_legal_split_i0_refutation_remainingA_NOT_fullZ · Uses: G001, S017
S019 · calculation
Before
Pumping ORIGINAL remaining a after i0 split2,2 := sub(4, 2)
After
Pumping ORIGINAL remaining a after i0 split2,2 = 2
Conditions: none
Substitute original roles and established intermediates exactly;no approximation,slot substitution or internally consistent changed operand.
Step identifiers and dependencies
Rule: exact_rational_arithmetic · Uses: G001, S018
S020 · implies
Before
source roles = [4, 2, 2]
After
derived = [0, 4, [2, 2, 0, a^2b^4, No], Yes]
Conditions: none
The third field p-x-y counts only remaining a symbols in z;full |z| adds all p b-symbols.Pumping i=0 deletes nonempty y,leaving p-y<p a symbols but p b symbols,so this legal split fails membership.
Step identifiers and dependencies
Rule: Pumping_EVERY_legal_split_i0_refutation_remainingA_NOT_fullZ · Uses: G001, S019
S021 · calculation
Before
Pumping ORIGINAL remaining a after i0 split3,1 := sub(4, 1)
After
Pumping ORIGINAL remaining a after i0 split3,1 = 3
Conditions: none
Substitute original roles and established intermediates exactly;no approximation,slot substitution or internally consistent changed operand.
Step identifiers and dependencies
Rule: exact_rational_arithmetic · Uses: G001, S020
S022 · implies
Before
source roles = [4, 3, 1]
After
derived = [0, 4, [3, 1, 0, a^3b^4, No], Yes]
Conditions: none
The third field p-x-y counts only remaining a symbols in z;full |z| adds all p b-symbols.Pumping i=0 deletes nonempty y,leaving p-y<p a symbols but p b symbols,so this legal split fails membership.
Step identifiers and dependencies
Rule: Pumping_EVERY_legal_split_i0_refutation_remainingA_NOT_fullZ · Uses: G001, S021
S023 · calculation
Before
Pumping ORIGINAL triangular numerator := mul(4, 5)
After
Pumping ORIGINAL triangular numerator = 20
Conditions: none
Substitute original roles and established intermediates exactly;no approximation,slot substitution or internally consistent changed operand.
Step identifiers and dependencies
Rule: exact_rational_arithmetic · Uses: G001, S022
S024 · calculation
Before
Pumping ORIGINAL triangular all-splits count := div(20, 2)
After
Pumping ORIGINAL triangular all-splits count = 10
Conditions: none
Substitute original roles and established intermediates exactly;no approximation,slot substitution or internally consistent changed operand.
Step identifiers and dependencies
Rule: exact_rational_arithmetic · Uses: G001, S023
S025 · implies
Before
source roles = [4, [[0, 1, 3, a^3b^4, No], [0, 2, 2, a^2b^4, No], [0, 3, 1, a^1b^4, No], [0, 4, 0, a^0b^4, No], [1, 1, 2, a^3b^4, No], [1, 2, 1, a^2b^4, No], [1, 3, 0, a^1b^4, No], [2, 1, 1, a^3b^4, No], [2, 2, 0, a^2b^4, No], [3, 1, 0, a^3b^4, No]]]
After
derived = [10, 10, Yes]
Conditions: none
For each x there are p-x choices of y,total p(p+1)/2,so every legal split is included.The general argument repeats for ANY proposed p,with i=0 defeating every split.A table at one fixed p alone is not the general proof.
Step identifiers and dependencies
Rule: Pumping_ALL_splits_and_GENERAL_every_proposed_p_contradiction · Uses: G001, S024
Result
(4, a^4b^4, [[0, 1, 3, a^3b^4, No], [0, 2, 2, a^2b^4, No], [0, 3, 1, a^1b^4, No], [0, 4, 0, a^0b^4, No], [1, 1, 2, a^3b^4, No], [1, 2, 1, a^2b^4, No], [1, 3, 0, a^1b^4, No], [2, 1, 1, a^3b^4, No], [2, 2, 0, a^2b^4, No], [3, 1, 0, a^3b^4, No]], 10, 10, Yes, every_legal_split_is_defeated_by_i=0)
The full substitutions and premise checks give the original answer; source identity,format and status are unchanged.