Use mode=infeasible_point, complete model={"constraint_gradient":[1,7],"constraint_rhs":6,"point":[7,0]}. Give (mode, constraint_gradient, constraint_rhs, point, constraint_value, feasible, boundary).
G001 — Use mode=infeasible_point, complete model={"constraint_gradient":[1,7],"constraint_rhs":6,"point":[7,0]}. Give (mode, constraint_gradient, constraint_rhs, point, constraint_value, feasible, boundary).
Definition and scope
Use the original question domain, assumptions and cited MKO definitions. This item has second-context mathematical and bilingual review, with the model, answer and every arithmetic step independently recomputed from the original parameters; the source question remains a candidate.
Lagrange boundary ORIGINAL constraint value ORIGINAL product0 := mul(1, 7)
After
Lagrange boundary ORIGINAL constraint value ORIGINAL product0 = 7
Conditions: none
Substitute original roles and established intermediates exactly,not approximations or internally consistent changed operands;extra teaching algebra adds no source-domain gate.
Lagrange boundary ORIGINAL constraint value ORIGINAL running sum0 := sum(0, 7)
After
Lagrange boundary ORIGINAL constraint value ORIGINAL running sum0 = 7
Conditions: none
Substitute original roles and established intermediates exactly,not approximations or internally consistent changed operands;extra teaching algebra adds no source-domain gate.
Lagrange boundary ORIGINAL constraint value ORIGINAL product1 := mul(7, 0)
After
Lagrange boundary ORIGINAL constraint value ORIGINAL product1 = 0
Conditions: none
Substitute original roles and established intermediates exactly,not approximations or internally consistent changed operands;extra teaching algebra adds no source-domain gate.
Lagrange boundary ORIGINAL constraint value ORIGINAL running sum1 := sum(7, 0)
After
Lagrange boundary ORIGINAL constraint value ORIGINAL running sum1 = 7
Conditions: none
Substitute original roles and established intermediates exactly,not approximations or internally consistent changed operands;extra teaching algebra adds no source-domain gate.
The complete dot product actually differs from rhs,hence infeasibility.This mode adds no nonzero-normal condition;a zero normal with nonzero rhs is also a witness.Stationarity cannot repair missing feasibility.
S006 · premise_and_result_audit — Reverse-check original data,operands,complete scope and premises;finite witnesses,conditional theorem use and formal proof remain distinct.
S005 · premise_and_result_audit — Recompute Lagrange boundary ORIGINAL constraint value ORIGINAL running sum1 with exact rational arithmetic, not rounded decimals.
S004 · premise_and_result_audit — Recompute Lagrange boundary ORIGINAL constraint value ORIGINAL product1 with exact rational arithmetic, not rounded decimals.
S003 · premise_and_result_audit — Recompute Lagrange boundary ORIGINAL constraint value ORIGINAL running sum0 with exact rational arithmetic, not rounded decimals.
S002 · premise_and_result_audit — Recompute Lagrange boundary ORIGINAL constraint value ORIGINAL product0 with exact rational arithmetic, not rounded decimals.
S001 · premise_and_result_audit — Reverse-check original data,operands,complete scope and premises;finite witnesses,conditional theorem use and formal proof remain distinct.
Result
(infeasible_point, [1, 7], 6, [7, 0], 7, No, stationarity_never_repairs_missing_feasibility)
The full substitutions and premise checks give the original answer; source identity,format and status are unchanged.
This question review and source binding
Review date: 2026-10-26
Original questions, answers, step expressions, numeric ASTs and historical records are retained. Source candidate labels remain historical and are not overwritten as formal proof.