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Question 27917: Regular Equality Conditions Are Necessary, Not Sufficient, and Not Inequality KKT

On this page
  1. Original question and givens
  2. Definition and scope
  3. Step-by-step derivation
  4. Reverse checks
  5. Result
  6. This question review and source binding

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← Question derivation index · Original question batch

R0054-27917 · q-20261015-pulse-20261119-r04-0092

Original question and givens

Use mode=rank_deficient, complete model={"constraint_gradients":[[1,17],[2,34]]}. Give (mode, constraint_gradient_rows, rank, constraint_count, regular_theorem_applicable, scope).

  • G001 — Use mode=rank_deficient, complete model={"constraint_gradients":[[1,17],[2,34]]}. Give (mode, constraint_gradient_rows, rank, constraint_count, regular_theorem_applicable, scope).

Definition and scope

Use the original question domain, assumptions and cited MKO definitions. This item has second-context mathematical and bilingual review, with the model, answer and every arithmetic step independently recomputed from the original parameters; the source question remains a candidate.

Step-by-step derivation

S001 · implies

Before

source roles = [lagrange-boundary]

After

derived = [[mode, constraint_gradient_rows, rank, constraint_count, regular_theorem_applicable, scope]]

Conditions: none

List the complete operation/mode field order without JavaScript or answer-shape inference;Boolean,string,null and an unclaimed result remain distinct.

Step identifiers and dependencies

Rule: source_ordered_fields_without_JS · Uses: G001

S002 · calculation

Before

Lagrange boundary ORIGINAL ORIGINAL normalize row0 col0 := div(1, 1)

After

Lagrange boundary ORIGINAL ORIGINAL normalize row0 col0 = 1

Conditions: none

Substitute original roles and established intermediates exactly,not approximations or internally consistent changed operands;extra teaching algebra adds no source-domain gate.

Step identifiers and dependencies

Rule: exact_rational_arithmetic · Uses: G001, S001

S003 · calculation

Before

Lagrange boundary ORIGINAL ORIGINAL normalize row0 col1 := div(17, 1)

After

Lagrange boundary ORIGINAL ORIGINAL normalize row0 col1 = 17

Conditions: none

Substitute original roles and established intermediates exactly,not approximations or internally consistent changed operands;extra teaching algebra adds no source-domain gate.

Step identifiers and dependencies

Rule: exact_rational_arithmetic · Uses: G001, S002

S004 · implies

Before

source roles = [Lagrange boundary ORIGINAL, 0, 0, 0, [[1, 17], [2, 34]], 1]

After

derived = [[[1, 17], [2, 34]]]

Conditions: none

Use the original first-nonzero pivot order and swap rows.Divide only by a nonzero pivot and normalize EVERY column;the inverse operation multiplies back,so row rank is preserved.All unreduced source1e8 intermediates remain qualified.

Step identifiers and dependencies

Rule: Lagrange_rank_FIRST_nonzero_pivot_full_row_normalization · Uses: G001, S003

S005 · calculation

Before

Lagrange boundary ORIGINAL ORIGINAL elimination row1 col0 factor := mul(2, 1)

After

Lagrange boundary ORIGINAL ORIGINAL elimination row1 col0 factor = 2

Conditions: none

Substitute original roles and established intermediates exactly,not approximations or internally consistent changed operands;extra teaching algebra adds no source-domain gate.

Step identifiers and dependencies

Rule: exact_rational_arithmetic · Uses: G001, S004

S006 · calculation

Before

Lagrange boundary ORIGINAL ORIGINAL elimination row1 col0 subtract := sub(2, 2)

After

Lagrange boundary ORIGINAL ORIGINAL elimination row1 col0 subtract = 0

Conditions: none

Substitute original roles and established intermediates exactly,not approximations or internally consistent changed operands;extra teaching algebra adds no source-domain gate.

Step identifiers and dependencies

Rule: exact_rational_arithmetic · Uses: G001, S005

S007 · calculation

Before

Lagrange boundary ORIGINAL ORIGINAL elimination row1 col1 factor := mul(2, 17)

After

Lagrange boundary ORIGINAL ORIGINAL elimination row1 col1 factor = 34

Conditions: none

Substitute original roles and established intermediates exactly,not approximations or internally consistent changed operands;extra teaching algebra adds no source-domain gate.

Step identifiers and dependencies

Rule: exact_rational_arithmetic · Uses: G001, S006

S008 · calculation

Before

Lagrange boundary ORIGINAL ORIGINAL elimination row1 col1 subtract := sub(34, 34)

After

Lagrange boundary ORIGINAL ORIGINAL elimination row1 col1 subtract = 0

Conditions: none

Substitute original roles and established intermediates exactly,not approximations or internally consistent changed operands;extra teaching algebra adds no source-domain gate.

Step identifiers and dependencies

Rule: exact_rational_arithmetic · Uses: G001, S007

S009 · implies

Before

source roles = [Lagrange boundary ORIGINAL, 0, 0, 1, 2, [2, 34]]

After

derived = [[[1, 17], [0, 0]]]

Conditions: none

Take the factor from the pre-update row;subtract the SAME factor times the pivot row from every column.This full-row operation is invertible.Skip zero factors as the source does;row operations do not redefine original constraint order.

Step identifiers and dependencies

Rule: Lagrange_rank_EACH_other_nonzero_factor_full_row_elimination · Uses: G001, S008

S010 · implies

Before

source roles = [Lagrange boundary ORIGINAL, 1, 1, [[1, 17], [0, 0]]]

After

derived = [null]

Conditions: none

All remaining rows are zero in this column,so it adds no rank;continue to later columns.

Step identifiers and dependencies

Rule: Lagrange_rank_no_remaining_pivot_in_column · Uses: G001, S009

S011 · implies

Before

source roles = [Lagrange boundary ORIGINAL, [[1, 17], [2, 34]]]

After

derived = [[[1, 17], [0, 0]], [[0, 0]], 1]

Conditions: none

Distinct leading1 pivots make the nonzero rows independent;remaining rows are zero and operations are invertible,so pivot count equals original row rank.Retain ORIGINAL constraint rows for J_g/lambda pairing,not RREF substitutes.

Step identifiers and dependencies

Rule: Lagrange_rank_RREF_pivots_equal_row_rank_original_rows_retained · Uses: G001, S010

S012 · implies

Before

source roles = [[[1, 17], [2, 34]], 1, 2]

After

derived = [No]

Conditions: none

Rank below the constraint count withholds regular full-row-rank qualification only;it does not imply no extrema or invalidate every multiplier concept.

Step identifiers and dependencies

Rule: Lagrange_ACTUAL_rank_deficiency_NOT_absence_of_extrema · Uses: G001, S011

Reverse checks

  • S012 · premise_and_result_audit — Reverse-check original data,operands,complete scope and premises;finite witnesses,conditional theorem use and formal proof remain distinct.
  • S011 · premise_and_result_audit — Reverse-check original data,operands,complete scope and premises;finite witnesses,conditional theorem use and formal proof remain distinct.
  • S010 · premise_and_result_audit — Reverse-check original data,operands,complete scope and premises;finite witnesses,conditional theorem use and formal proof remain distinct.
  • S009 · premise_and_result_audit — Reverse-check original data,operands,complete scope and premises;finite witnesses,conditional theorem use and formal proof remain distinct.
  • S008 · premise_and_result_audit — Recompute Lagrange boundary ORIGINAL ORIGINAL elimination row1 col1 subtract with exact rational arithmetic, not rounded decimals.
  • S007 · premise_and_result_audit — Recompute Lagrange boundary ORIGINAL ORIGINAL elimination row1 col1 factor with exact rational arithmetic, not rounded decimals.
  • S006 · premise_and_result_audit — Recompute Lagrange boundary ORIGINAL ORIGINAL elimination row1 col0 subtract with exact rational arithmetic, not rounded decimals.
  • S005 · premise_and_result_audit — Recompute Lagrange boundary ORIGINAL ORIGINAL elimination row1 col0 factor with exact rational arithmetic, not rounded decimals.
  • S004 · premise_and_result_audit — Reverse-check original data,operands,complete scope and premises;finite witnesses,conditional theorem use and formal proof remain distinct.
  • S003 · premise_and_result_audit — Recompute Lagrange boundary ORIGINAL ORIGINAL normalize row0 col1 with exact rational arithmetic, not rounded decimals.
  • S002 · premise_and_result_audit — Recompute Lagrange boundary ORIGINAL ORIGINAL normalize row0 col0 with exact rational arithmetic, not rounded decimals.
  • S001 · premise_and_result_audit — Reverse-check original data,operands,complete scope and premises;finite witnesses,conditional theorem use and formal proof remain distinct.

Result

(rank_deficient, [[1, 17], [2, 34]], 1, 2, No, regular_Lagrange_theorem_not_applicable_does_not_mean_no_extremum)

The full substitutions and premise checks give the original answer; source identity,format and status are unchanged.

This question review and source binding

Review date: 2026-10-26

Original questions, answers, step expressions, numeric ASTs and historical records are retained. Source candidate labels remain historical and are not overwritten as formal proof.

Source hashes and review receipts
  • input commit: 0f7be61e2c22317a4075561dc822c87d881a50db
  • original question SHA-256: 79592785e9c208168b2dec9017b75cf0dee1365f09422f0c9d25c69cd6bd2a5b
  • candidate record SHA-256: 4b3cb7273ac5970da78d2b04706d683c4c2f68d1975bc1b0895086aba4e0df63
  • semantic review receipt SHA-256: 0a76d8e93c08bb16998a0483f3dfc0504f269fc3e1982e6cd868cab0a2856d54
  • question-first witness SHA-256: 09127b736c225714dfa0b7ceb0e6a6e66df27438b480cad8217d3c2f99ce9437
  • Lean: NOT_RUN · human review: NOT_PERFORMED
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