{"schema_version":"ocme-site-results-v1","locale":"zh-Hant","page_type":"derivations","facts":{"questions":36000,"reviewed":36000,"display_candidates":0,"knowledge":302,"guides":299,"paths":59,"batches":360,"families":1441,"atlas":302,"core":80,"evidence":9,"formal_evidence":5,"formal_subjects":4,"lean_files":6,"lean_toolchain":"leanprover/lean4:v4.30.0","question_state":"candidate","english_state":"ai_candidate","question_Lean":"NOT_RUN","canonical_truth_promotion":false},"filters":{"q":"mko-absolute-value"},"kind":"guides","total":1,"pages":1,"page":1,"entries":[{"id":"derivation-mko-absolute-value-01","title":{"zh-Hant":"絕對值：由分段定義證明非負性、零點與 |a−b|=|b−a|","en":"Absolute value: nonnegativity, the zero case and |a−b|=|b−a| from the piecewise definition"},"summary":{"zh-Hant":"只用分段定義（x≥0 時 |x|=x，x<0 時 |x|=−x）與實數的序和加法，證明對所有實數 x、a、b：(1) |x|≥0；(2) |x|=0 ⇔ x=0；(3) |−x|=|x|；(4) |a−b|=|b−a|。並計算 |−3|、|2−7|、|7−2|，說明「|x|=x 對所有 x 成立」是錯的。","en":"Using only the piecewise definition (|x|=x when x≥0, |x|=−x when x<0) together with the order and addition of the reals, prove for all reals x, a, b: (1) |x|≥0; (2) |x|=0 ⇔ x=0; (3) |−x|=|x|; (4) |a−b|=|b−a|. Then compute |−3|, |2−7| and |7−2|, and show that '|x|=x for every x' is false."},"mko_ids":["mko-absolute-value"]}],"title":"概念推導導讀"}